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Mirrors > Home > ILE Home > Th. List > mpjaod | GIF version |
Description: Eliminate a disjunction in a deduction. (Contributed by Mario Carneiro, 29-May-2016.) |
Ref | Expression |
---|---|
jaod.1 | ⊢ (𝜑 → (𝜓 → 𝜒)) |
jaod.2 | ⊢ (𝜑 → (𝜃 → 𝜒)) |
jaod.3 | ⊢ (𝜑 → (𝜓 ∨ 𝜃)) |
Ref | Expression |
---|---|
mpjaod | ⊢ (𝜑 → 𝜒) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | jaod.3 | . 2 ⊢ (𝜑 → (𝜓 ∨ 𝜃)) | |
2 | jaod.1 | . . 3 ⊢ (𝜑 → (𝜓 → 𝜒)) | |
3 | jaod.2 | . . 3 ⊢ (𝜑 → (𝜃 → 𝜒)) | |
4 | 2, 3 | jaod 706 | . 2 ⊢ (𝜑 → ((𝜓 ∨ 𝜃) → 𝜒)) |
5 | 1, 4 | mpd 13 | 1 ⊢ (𝜑 → 𝜒) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ∨ wo 697 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 ax-io 698 |
This theorem depends on definitions: df-bi 116 |
This theorem is referenced by: ifbothdc 3504 opth1 4158 onsucelsucexmidlem 4444 reldmtpos 6150 dftpos4 6160 nnm00 6425 xpfi 6818 omp1eomlem 6979 ctmlemr 6993 ctssdclemn0 6995 finomni 7012 indpi 7150 enq0tr 7242 prarloclem3step 7304 distrlem4prl 7392 distrlem4pru 7393 lelttr 7852 nn1suc 8739 nnsub 8759 nn0lt2 9132 uzin 9358 xrlelttr 9589 xlesubadd 9666 fzfig 10203 seq3id 10281 seq3z 10284 faclbnd 10487 facavg 10492 bcval5 10509 hashfzo 10568 iserex 11108 fsum3cvg 11147 fsumf1o 11159 fisumss 11161 fsumcl2lem 11167 fsumadd 11175 fsummulc2 11217 isumsplit 11260 absdvdsb 11511 dvdsabsb 11512 dvdsabseq 11545 m1exp1 11598 flodddiv4 11631 gcdaddm 11672 gcdabs1 11677 lcmdvds 11760 prmind2 11801 rpexp 11831 trilpolemcl 13230 trilpolemlt1 13234 |
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