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Theorem issubrng 46711
Description: The subring of non-unital ring predicate. (Contributed by AV, 14-Feb-2025.)
Hypothesis
Ref Expression
issubrng.b 𝐵 = (Base‘𝑅)
Assertion
Ref Expression
issubrng (𝐴 ∈ (SubRng‘𝑅) ↔ (𝑅 ∈ Rng ∧ (𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵))

Proof of Theorem issubrng
Dummy variables 𝑤 𝑠 𝑟 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 df-subrng 46710 . . 3 SubRng = (𝑤 ∈ Rng ↦ {𝑠 ∈ 𝒫 (Base‘𝑤) ∣ (𝑤s 𝑠) ∈ Rng})
21mptrcl 7005 . 2 (𝐴 ∈ (SubRng‘𝑅) → 𝑅 ∈ Rng)
3 simp1 1137 . 2 ((𝑅 ∈ Rng ∧ (𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵) → 𝑅 ∈ Rng)
4 fveq2 6889 . . . . . . 7 (𝑟 = 𝑅 → (Base‘𝑟) = (Base‘𝑅))
54pweqd 4619 . . . . . 6 (𝑟 = 𝑅 → 𝒫 (Base‘𝑟) = 𝒫 (Base‘𝑅))
6 oveq1 7413 . . . . . . 7 (𝑟 = 𝑅 → (𝑟s 𝑠) = (𝑅s 𝑠))
76eleq1d 2819 . . . . . 6 (𝑟 = 𝑅 → ((𝑟s 𝑠) ∈ Rng ↔ (𝑅s 𝑠) ∈ Rng))
85, 7rabeqbidv 3450 . . . . 5 (𝑟 = 𝑅 → {𝑠 ∈ 𝒫 (Base‘𝑟) ∣ (𝑟s 𝑠) ∈ Rng} = {𝑠 ∈ 𝒫 (Base‘𝑅) ∣ (𝑅s 𝑠) ∈ Rng})
9 df-subrng 46710 . . . . 5 SubRng = (𝑟 ∈ Rng ↦ {𝑠 ∈ 𝒫 (Base‘𝑟) ∣ (𝑟s 𝑠) ∈ Rng})
10 fvex 6902 . . . . . . 7 (Base‘𝑅) ∈ V
1110pwex 5378 . . . . . 6 𝒫 (Base‘𝑅) ∈ V
1211rabex 5332 . . . . 5 {𝑠 ∈ 𝒫 (Base‘𝑅) ∣ (𝑅s 𝑠) ∈ Rng} ∈ V
138, 9, 12fvmpt 6996 . . . 4 (𝑅 ∈ Rng → (SubRng‘𝑅) = {𝑠 ∈ 𝒫 (Base‘𝑅) ∣ (𝑅s 𝑠) ∈ Rng})
1413eleq2d 2820 . . 3 (𝑅 ∈ Rng → (𝐴 ∈ (SubRng‘𝑅) ↔ 𝐴 ∈ {𝑠 ∈ 𝒫 (Base‘𝑅) ∣ (𝑅s 𝑠) ∈ Rng}))
15 oveq2 7414 . . . . . 6 (𝑠 = 𝐴 → (𝑅s 𝑠) = (𝑅s 𝐴))
1615eleq1d 2819 . . . . 5 (𝑠 = 𝐴 → ((𝑅s 𝑠) ∈ Rng ↔ (𝑅s 𝐴) ∈ Rng))
1716elrab 3683 . . . 4 (𝐴 ∈ {𝑠 ∈ 𝒫 (Base‘𝑅) ∣ (𝑅s 𝑠) ∈ Rng} ↔ (𝐴 ∈ 𝒫 (Base‘𝑅) ∧ (𝑅s 𝐴) ∈ Rng))
18 issubrng.b . . . . . . . . 9 𝐵 = (Base‘𝑅)
1918eqcomi 2742 . . . . . . . 8 (Base‘𝑅) = 𝐵
2019sseq2i 4011 . . . . . . 7 (𝐴 ⊆ (Base‘𝑅) ↔ 𝐴𝐵)
2120anbi2i 624 . . . . . 6 (((𝑅s 𝐴) ∈ Rng ∧ 𝐴 ⊆ (Base‘𝑅)) ↔ ((𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵))
22 ibar 530 . . . . . 6 (𝑅 ∈ Rng → (((𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵) ↔ (𝑅 ∈ Rng ∧ ((𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵))))
2321, 22bitrid 283 . . . . 5 (𝑅 ∈ Rng → (((𝑅s 𝐴) ∈ Rng ∧ 𝐴 ⊆ (Base‘𝑅)) ↔ (𝑅 ∈ Rng ∧ ((𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵))))
2410elpw2 5345 . . . . . 6 (𝐴 ∈ 𝒫 (Base‘𝑅) ↔ 𝐴 ⊆ (Base‘𝑅))
2524anbi2ci 626 . . . . 5 ((𝐴 ∈ 𝒫 (Base‘𝑅) ∧ (𝑅s 𝐴) ∈ Rng) ↔ ((𝑅s 𝐴) ∈ Rng ∧ 𝐴 ⊆ (Base‘𝑅)))
26 3anass 1096 . . . . 5 ((𝑅 ∈ Rng ∧ (𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵) ↔ (𝑅 ∈ Rng ∧ ((𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵)))
2723, 25, 263bitr4g 314 . . . 4 (𝑅 ∈ Rng → ((𝐴 ∈ 𝒫 (Base‘𝑅) ∧ (𝑅s 𝐴) ∈ Rng) ↔ (𝑅 ∈ Rng ∧ (𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵)))
2817, 27bitrid 283 . . 3 (𝑅 ∈ Rng → (𝐴 ∈ {𝑠 ∈ 𝒫 (Base‘𝑅) ∣ (𝑅s 𝑠) ∈ Rng} ↔ (𝑅 ∈ Rng ∧ (𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵)))
2914, 28bitrd 279 . 2 (𝑅 ∈ Rng → (𝐴 ∈ (SubRng‘𝑅) ↔ (𝑅 ∈ Rng ∧ (𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵)))
302, 3, 29pm5.21nii 380 1 (𝐴 ∈ (SubRng‘𝑅) ↔ (𝑅 ∈ Rng ∧ (𝑅s 𝐴) ∈ Rng ∧ 𝐴𝐵))
Colors of variables: wff setvar class
Syntax hints:  wb 205  wa 397  w3a 1088   = wceq 1542  wcel 2107  {crab 3433  wss 3948  𝒫 cpw 4602  cfv 6541  (class class class)co 7406  Basecbs 17141  s cress 17170  Rngcrng 46635  SubRngcsubrng 46709
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1798  ax-4 1812  ax-5 1914  ax-6 1972  ax-7 2012  ax-8 2109  ax-9 2117  ax-10 2138  ax-11 2155  ax-12 2172  ax-ext 2704  ax-sep 5299  ax-nul 5306  ax-pow 5363  ax-pr 5427
This theorem depends on definitions:  df-bi 206  df-an 398  df-or 847  df-3an 1090  df-tru 1545  df-fal 1555  df-ex 1783  df-nf 1787  df-sb 2069  df-mo 2535  df-eu 2564  df-clab 2711  df-cleq 2725  df-clel 2811  df-nfc 2886  df-ne 2942  df-ral 3063  df-rex 3072  df-rab 3434  df-v 3477  df-dif 3951  df-un 3953  df-in 3955  df-ss 3965  df-nul 4323  df-if 4529  df-pw 4604  df-sn 4629  df-pr 4631  df-op 4635  df-uni 4909  df-br 5149  df-opab 5211  df-mpt 5232  df-id 5574  df-xp 5682  df-rel 5683  df-cnv 5684  df-co 5685  df-dm 5686  df-rn 5687  df-res 5688  df-ima 5689  df-iota 6493  df-fun 6543  df-fv 6549  df-ov 7409  df-subrng 46710
This theorem is referenced by:  subrngss  46712  subrngid  46713  subrngrng  46714  subrngrcl  46715  issubrng2  46722  subsubrng  46727  subrngpropd  46732  rng2idlsubrng  46742
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