Proof of Theorem eloppf
| Step | Hyp | Ref
| Expression |
| 1 | | eloppf.x |
. . . . 5
⊢ (𝜑 → 𝑋 ∈ 𝐺) |
| 2 | | eloppf.g |
. . . . 5
⊢ 𝐺 = ( oppFunc ‘𝐹) |
| 3 | 1, 2 | eleqtrdi 2838 |
. . . 4
⊢ (𝜑 → 𝑋 ∈ ( oppFunc ‘𝐹)) |
| 4 | | elfvdm 6877 |
. . . . 5
⊢ (𝑋 ∈ ( oppFunc ‘𝐹) → 𝐹 ∈ dom oppFunc ) |
| 5 | | oppffn 49086 |
. . . . . 6
⊢ oppFunc
Fn (V × V) |
| 6 | 5 | fndmi 6604 |
. . . . 5
⊢ dom
oppFunc = (V × V) |
| 7 | 4, 6 | eleqtrdi 2838 |
. . . 4
⊢ (𝑋 ∈ ( oppFunc ‘𝐹) → 𝐹 ∈ (V × V)) |
| 8 | 3, 7 | syl 17 |
. . 3
⊢ (𝜑 → 𝐹 ∈ (V × V)) |
| 9 | | 0nelxp 5665 |
. . 3
⊢ ¬
∅ ∈ (V × V) |
| 10 | | nelne2 3023 |
. . 3
⊢ ((𝐹 ∈ (V × V) ∧
¬ ∅ ∈ (V × V)) → 𝐹 ≠ ∅) |
| 11 | 8, 9, 10 | sylancl 586 |
. 2
⊢ (𝜑 → 𝐹 ≠ ∅) |
| 12 | | 1st2nd2 7986 |
. . . . . . . 8
⊢ (𝐹 ∈ (V × V) →
𝐹 = 〈(1st
‘𝐹), (2nd
‘𝐹)〉) |
| 13 | 3, 7, 12 | 3syl 18 |
. . . . . . 7
⊢ (𝜑 → 𝐹 = 〈(1st ‘𝐹), (2nd ‘𝐹)〉) |
| 14 | 13 | fveq2d 6844 |
. . . . . 6
⊢ (𝜑 → ( oppFunc ‘𝐹) = ( oppFunc
‘〈(1st ‘𝐹), (2nd ‘𝐹)〉)) |
| 15 | | df-ov 7372 |
. . . . . . 7
⊢
((1st ‘𝐹) oppFunc (2nd ‘𝐹)) = ( oppFunc
‘〈(1st ‘𝐹), (2nd ‘𝐹)〉) |
| 16 | | fvex 6853 |
. . . . . . . 8
⊢
(1st ‘𝐹) ∈ V |
| 17 | | fvex 6853 |
. . . . . . . 8
⊢
(2nd ‘𝐹) ∈ V |
| 18 | | oppfvalg 49088 |
. . . . . . . 8
⊢
(((1st ‘𝐹) ∈ V ∧ (2nd
‘𝐹) ∈ V) →
((1st ‘𝐹)
oppFunc (2nd ‘𝐹)) = if((Rel (2nd ‘𝐹) ∧ Rel dom (2nd
‘𝐹)),
〈(1st ‘𝐹), tpos (2nd ‘𝐹)〉,
∅)) |
| 19 | 16, 17, 18 | mp2an 692 |
. . . . . . 7
⊢
((1st ‘𝐹) oppFunc (2nd ‘𝐹)) = if((Rel (2nd
‘𝐹) ∧ Rel dom
(2nd ‘𝐹)),
〈(1st ‘𝐹), tpos (2nd ‘𝐹)〉,
∅) |
| 20 | 15, 19 | eqtr3i 2754 |
. . . . . 6
⊢ ( oppFunc
‘〈(1st ‘𝐹), (2nd ‘𝐹)〉) = if((Rel (2nd
‘𝐹) ∧ Rel dom
(2nd ‘𝐹)),
〈(1st ‘𝐹), tpos (2nd ‘𝐹)〉,
∅) |
| 21 | 14, 20 | eqtrdi 2780 |
. . . . 5
⊢ (𝜑 → ( oppFunc ‘𝐹) = if((Rel (2nd
‘𝐹) ∧ Rel dom
(2nd ‘𝐹)),
〈(1st ‘𝐹), tpos (2nd ‘𝐹)〉,
∅)) |
| 22 | 3, 21 | eleqtrd 2830 |
. . . 4
⊢ (𝜑 → 𝑋 ∈ if((Rel (2nd ‘𝐹) ∧ Rel dom (2nd
‘𝐹)),
〈(1st ‘𝐹), tpos (2nd ‘𝐹)〉,
∅)) |
| 23 | 22 | ne0d 4301 |
. . 3
⊢ (𝜑 → if((Rel (2nd
‘𝐹) ∧ Rel dom
(2nd ‘𝐹)),
〈(1st ‘𝐹), tpos (2nd ‘𝐹)〉, ∅) ≠
∅) |
| 24 | | iffalse 4493 |
. . . 4
⊢ (¬
(Rel (2nd ‘𝐹) ∧ Rel dom (2nd ‘𝐹)) → if((Rel
(2nd ‘𝐹)
∧ Rel dom (2nd ‘𝐹)), 〈(1st ‘𝐹), tpos (2nd
‘𝐹)〉, ∅) =
∅) |
| 25 | 24 | necon1ai 2952 |
. . 3
⊢ (if((Rel
(2nd ‘𝐹)
∧ Rel dom (2nd ‘𝐹)), 〈(1st ‘𝐹), tpos (2nd
‘𝐹)〉, ∅)
≠ ∅ → (Rel (2nd ‘𝐹) ∧ Rel dom (2nd ‘𝐹))) |
| 26 | 23, 25 | syl 17 |
. 2
⊢ (𝜑 → (Rel (2nd
‘𝐹) ∧ Rel dom
(2nd ‘𝐹))) |
| 27 | 11, 26 | jca 511 |
1
⊢ (𝜑 → (𝐹 ≠ ∅ ∧ (Rel (2nd
‘𝐹) ∧ Rel dom
(2nd ‘𝐹)))) |