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Theorem gblacfnacd 35609
Description: If 𝐺 is a global choice function, then the Axiom of Choice (in the form of the right-hand side of dfac4 10125) holds. Note that 𝐺 must be a proper class by fndmexb 7912. This means we cannot show that the existence of a class that behaves as a global choice function is sufficient because we only have existential quantifiers for sets, not (proper) classes. However, if a class variant of exlimiv 1963 were available, then it could be used alongside the closed form of this theorem to prove that result. (Contributed by BTernaryTau, 12-Dec-2024.)
Hypotheses
Ref Expression
gblacfnacd.1 (𝜑𝐺 Fn V)
gblacfnacd.2 (𝜑 → ∀𝑧(𝑧 ≠ ∅ → (𝐺𝑧) ∈ 𝑧))
Assertion
Ref Expression
gblacfnacd (𝜑 → ∀𝑥𝑓(𝑓 Fn 𝑥 ∧ ∀𝑧𝑥 (𝑧 ≠ ∅ → (𝑓𝑧) ∈ 𝑧)))
Distinct variable groups:   𝑥,𝑓   𝜑,𝑥,𝑧   𝑓,𝐺,𝑧
Allowed substitution hints:   𝜑(𝑓)   𝐺(𝑥)

Proof of Theorem gblacfnacd
StepHypRef Expression
1 gblacfnacd.1 . . . 4 (𝜑𝐺 Fn V)
2 fnfun 6642 . . . 4 (𝐺 Fn V → Fun 𝐺)
3 resfunexg 7220 . . . . 5 ((Fun 𝐺𝑥 ∈ V) → (𝐺𝑥) ∈ V)
43elvd 3464 . . . 4 (Fun 𝐺 → (𝐺𝑥) ∈ V)
51, 2, 43syl 19 . . 3 (𝜑 → (𝐺𝑥) ∈ V)
6 ssv 3964 . . . . 5 𝑥 ⊆ V
7 fnssres 6665 . . . . 5 ((𝐺 Fn V ∧ 𝑥 ⊆ V) → (𝐺𝑥) Fn 𝑥)
81, 6, 7sylancl 598 . . . 4 (𝜑 → (𝐺𝑥) Fn 𝑥)
9 gblacfnacd.2 . . . . . . 7 (𝜑 → ∀𝑧(𝑧 ≠ ∅ → (𝐺𝑧) ∈ 𝑧))
10919.21bi 2228 . . . . . 6 (𝜑 → (𝑧 ≠ ∅ → (𝐺𝑧) ∈ 𝑧))
11 fvres 6907 . . . . . . . 8 (𝑧𝑥 → ((𝐺𝑥)‘𝑧) = (𝐺𝑧))
1211eleq1d 2851 . . . . . . 7 (𝑧𝑥 → (((𝐺𝑥)‘𝑧) ∈ 𝑧 ↔ (𝐺𝑧) ∈ 𝑧))
1312imbi2d 343 . . . . . 6 (𝑧𝑥 → ((𝑧 ≠ ∅ → ((𝐺𝑥)‘𝑧) ∈ 𝑧) ↔ (𝑧 ≠ ∅ → (𝐺𝑧) ∈ 𝑧)))
1410, 13syl5ibrcom 250 . . . . 5 (𝜑 → (𝑧𝑥 → (𝑧 ≠ ∅ → ((𝐺𝑥)‘𝑧) ∈ 𝑧)))
1514ralrimiv 3159 . . . 4 (𝜑 → ∀𝑧𝑥 (𝑧 ≠ ∅ → ((𝐺𝑥)‘𝑧) ∈ 𝑧))
168, 15jca 521 . . 3 (𝜑 → ((𝐺𝑥) Fn 𝑥 ∧ ∀𝑧𝑥 (𝑧 ≠ ∅ → ((𝐺𝑥)‘𝑧) ∈ 𝑧)))
17 fneq1 6633 . . . 4 (𝑓 = (𝐺𝑥) → (𝑓 Fn 𝑥 ↔ (𝐺𝑥) Fn 𝑥))
18 fveq1 6887 . . . . . . 7 (𝑓 = (𝐺𝑥) → (𝑓𝑧) = ((𝐺𝑥)‘𝑧))
1918eleq1d 2851 . . . . . 6 (𝑓 = (𝐺𝑥) → ((𝑓𝑧) ∈ 𝑧 ↔ ((𝐺𝑥)‘𝑧) ∈ 𝑧))
2019imbi2d 343 . . . . 5 (𝑓 = (𝐺𝑥) → ((𝑧 ≠ ∅ → (𝑓𝑧) ∈ 𝑧) ↔ (𝑧 ≠ ∅ → ((𝐺𝑥)‘𝑧) ∈ 𝑧)))
2120ralbidv 3191 . . . 4 (𝑓 = (𝐺𝑥) → (∀𝑧𝑥 (𝑧 ≠ ∅ → (𝑓𝑧) ∈ 𝑧) ↔ ∀𝑧𝑥 (𝑧 ≠ ∅ → ((𝐺𝑥)‘𝑧) ∈ 𝑧)))
2217, 21anbi12d 644 . . 3 (𝑓 = (𝐺𝑥) → ((𝑓 Fn 𝑥 ∧ ∀𝑧𝑥 (𝑧 ≠ ∅ → (𝑓𝑧) ∈ 𝑧)) ↔ ((𝐺𝑥) Fn 𝑥 ∧ ∀𝑧𝑥 (𝑧 ≠ ∅ → ((𝐺𝑥)‘𝑧) ∈ 𝑧))))
235, 16, 22spcedv 3560 . 2 (𝜑 → ∃𝑓(𝑓 Fn 𝑥 ∧ ∀𝑧𝑥 (𝑧 ≠ ∅ → (𝑓𝑧) ∈ 𝑧)))
2423alrimiv 1960 1 (𝜑 → ∀𝑥𝑓(𝑓 Fn 𝑥 ∧ ∀𝑧𝑥 (𝑧 ≠ ∅ → (𝑓𝑧) ∈ 𝑧)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wa 401  wal 1568   = wceq 1570  wex 1812  wcel 2146  wne 2961  wral 3082  Vcvv 3458  wss 3908  c0 4289  cres 5668  Fun wfun 6537   Fn wfn 6538  cfv 6543
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2195  ax-12 2216  ax-ext 2738  ax-rep 5243  ax-sep 5262  ax-nul 5274  ax-pr 5409
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2570  df-eu 2600  df-clab 2745  df-cleq 2758  df-clel 2841  df-nfc 2915  df-ne 2962  df-ral 3083  df-rex 3093  df-reu 3373  df-rab 3420  df-v 3460  df-sbc 3748  df-csb 3857  df-dif 3911  df-un 3913  df-in 3915  df-ss 3925  df-nul 4290  df-if 4493  df-sn 4595  df-pr 4597  df-op 4601  df-uni 4878  df-iun 4963  df-br 5115  df-opab 5179  df-mpt 5198  df-id 5561  df-xp 5672  df-rel 5673  df-cnv 5674  df-co 5675  df-dm 5676  df-rn 5677  df-res 5678  df-ima 5679  df-iota 6499  df-fun 6545  df-fn 6546  df-f 6547  df-f1 6548  df-fo 6549  df-f1o 6550  df-fv 6551
This theorem is used by: (None)
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