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Theorem shftlem 11497
Description: Two ways to write a shifted set (𝐵 + 𝐴). (Contributed by Mario Carneiro, 3-Nov-2013.)
Assertion
Ref Expression
shftlem ((𝐴 ∈ ℂ ∧ 𝐵 ⊆ ℂ) → {𝑥 ∈ ℂ ∣ (𝑥𝐴) ∈ 𝐵} = {𝑥 ∣ ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴)})
Distinct variable groups:   𝑥,𝑦,𝐴   𝑥,𝐵,𝑦

Proof of Theorem shftlem
StepHypRef Expression
1 df-rab 2529 . 2 {𝑥 ∈ ℂ ∣ (𝑥𝐴) ∈ 𝐵} = {𝑥 ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴) ∈ 𝐵)}
2 npcan 8481 . . . . . . . . 9 ((𝑥 ∈ ℂ ∧ 𝐴 ∈ ℂ) → ((𝑥𝐴) + 𝐴) = 𝑥)
32ancoms 268 . . . . . . . 8 ((𝐴 ∈ ℂ ∧ 𝑥 ∈ ℂ) → ((𝑥𝐴) + 𝐴) = 𝑥)
43eqcomd 2238 . . . . . . 7 ((𝐴 ∈ ℂ ∧ 𝑥 ∈ ℂ) → 𝑥 = ((𝑥𝐴) + 𝐴))
5 oveq1 6056 . . . . . . . . . 10 (𝑦 = (𝑥𝐴) → (𝑦 + 𝐴) = ((𝑥𝐴) + 𝐴))
65eqeq2d 2244 . . . . . . . . 9 (𝑦 = (𝑥𝐴) → (𝑥 = (𝑦 + 𝐴) ↔ 𝑥 = ((𝑥𝐴) + 𝐴)))
76rspcev 2920 . . . . . . . 8 (((𝑥𝐴) ∈ 𝐵𝑥 = ((𝑥𝐴) + 𝐴)) → ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴))
87expcom 116 . . . . . . 7 (𝑥 = ((𝑥𝐴) + 𝐴) → ((𝑥𝐴) ∈ 𝐵 → ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴)))
94, 8syl 14 . . . . . 6 ((𝐴 ∈ ℂ ∧ 𝑥 ∈ ℂ) → ((𝑥𝐴) ∈ 𝐵 → ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴)))
109expimpd 363 . . . . 5 (𝐴 ∈ ℂ → ((𝑥 ∈ ℂ ∧ (𝑥𝐴) ∈ 𝐵) → ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴)))
1110adantr 276 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ⊆ ℂ) → ((𝑥 ∈ ℂ ∧ (𝑥𝐴) ∈ 𝐵) → ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴)))
12 ssel2 3232 . . . . . . . . . 10 ((𝐵 ⊆ ℂ ∧ 𝑦𝐵) → 𝑦 ∈ ℂ)
13 addcl 8251 . . . . . . . . . 10 ((𝑦 ∈ ℂ ∧ 𝐴 ∈ ℂ) → (𝑦 + 𝐴) ∈ ℂ)
1412, 13sylan 283 . . . . . . . . 9 (((𝐵 ⊆ ℂ ∧ 𝑦𝐵) ∧ 𝐴 ∈ ℂ) → (𝑦 + 𝐴) ∈ ℂ)
15 pncan 8478 . . . . . . . . . . 11 ((𝑦 ∈ ℂ ∧ 𝐴 ∈ ℂ) → ((𝑦 + 𝐴) − 𝐴) = 𝑦)
1612, 15sylan 283 . . . . . . . . . 10 (((𝐵 ⊆ ℂ ∧ 𝑦𝐵) ∧ 𝐴 ∈ ℂ) → ((𝑦 + 𝐴) − 𝐴) = 𝑦)
17 simplr 529 . . . . . . . . . 10 (((𝐵 ⊆ ℂ ∧ 𝑦𝐵) ∧ 𝐴 ∈ ℂ) → 𝑦𝐵)
1816, 17eqeltrd 2309 . . . . . . . . 9 (((𝐵 ⊆ ℂ ∧ 𝑦𝐵) ∧ 𝐴 ∈ ℂ) → ((𝑦 + 𝐴) − 𝐴) ∈ 𝐵)
1914, 18jca 306 . . . . . . . 8 (((𝐵 ⊆ ℂ ∧ 𝑦𝐵) ∧ 𝐴 ∈ ℂ) → ((𝑦 + 𝐴) ∈ ℂ ∧ ((𝑦 + 𝐴) − 𝐴) ∈ 𝐵))
2019ancoms 268 . . . . . . 7 ((𝐴 ∈ ℂ ∧ (𝐵 ⊆ ℂ ∧ 𝑦𝐵)) → ((𝑦 + 𝐴) ∈ ℂ ∧ ((𝑦 + 𝐴) − 𝐴) ∈ 𝐵))
2120anassrs 400 . . . . . 6 (((𝐴 ∈ ℂ ∧ 𝐵 ⊆ ℂ) ∧ 𝑦𝐵) → ((𝑦 + 𝐴) ∈ ℂ ∧ ((𝑦 + 𝐴) − 𝐴) ∈ 𝐵))
22 eleq1 2295 . . . . . . 7 (𝑥 = (𝑦 + 𝐴) → (𝑥 ∈ ℂ ↔ (𝑦 + 𝐴) ∈ ℂ))
23 oveq1 6056 . . . . . . . 8 (𝑥 = (𝑦 + 𝐴) → (𝑥𝐴) = ((𝑦 + 𝐴) − 𝐴))
2423eleq1d 2301 . . . . . . 7 (𝑥 = (𝑦 + 𝐴) → ((𝑥𝐴) ∈ 𝐵 ↔ ((𝑦 + 𝐴) − 𝐴) ∈ 𝐵))
2522, 24anbi12d 473 . . . . . 6 (𝑥 = (𝑦 + 𝐴) → ((𝑥 ∈ ℂ ∧ (𝑥𝐴) ∈ 𝐵) ↔ ((𝑦 + 𝐴) ∈ ℂ ∧ ((𝑦 + 𝐴) − 𝐴) ∈ 𝐵)))
2621, 25syl5ibrcom 157 . . . . 5 (((𝐴 ∈ ℂ ∧ 𝐵 ⊆ ℂ) ∧ 𝑦𝐵) → (𝑥 = (𝑦 + 𝐴) → (𝑥 ∈ ℂ ∧ (𝑥𝐴) ∈ 𝐵)))
2726rexlimdva 2660 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ⊆ ℂ) → (∃𝑦𝐵 𝑥 = (𝑦 + 𝐴) → (𝑥 ∈ ℂ ∧ (𝑥𝐴) ∈ 𝐵)))
2811, 27impbid 129 . . 3 ((𝐴 ∈ ℂ ∧ 𝐵 ⊆ ℂ) → ((𝑥 ∈ ℂ ∧ (𝑥𝐴) ∈ 𝐵) ↔ ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴)))
2928abbidv 2352 . 2 ((𝐴 ∈ ℂ ∧ 𝐵 ⊆ ℂ) → {𝑥 ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴) ∈ 𝐵)} = {𝑥 ∣ ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴)})
301, 29eqtrid 2277 1 ((𝐴 ∈ ℂ ∧ 𝐵 ⊆ ℂ) → {𝑥 ∈ ℂ ∣ (𝑥𝐴) ∈ 𝐵} = {𝑥 ∣ ∃𝑦𝐵 𝑥 = (𝑦 + 𝐴)})
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104   = wceq 1398  wcel 2203  {cab 2218  wrex 2521  {crab 2524  wss 3210  (class class class)co 6049  cc 8124   + caddc 8129  cmin 8443
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-14 2206  ax-ext 2214  ax-sep 4227  ax-pow 4286  ax-pr 4321  ax-setind 4658  ax-resscn 8218  ax-1cn 8219  ax-icn 8221  ax-addcl 8222  ax-addrcl 8223  ax-mulcl 8224  ax-addcom 8226  ax-addass 8228  ax-distr 8230  ax-i2m1 8231  ax-0id 8234  ax-rnegex 8235  ax-cnre 8237
This theorem depends on definitions:  df-bi 117  df-3an 1007  df-tru 1401  df-fal 1404  df-nf 1510  df-sb 1812  df-eu 2083  df-mo 2084  df-clab 2219  df-cleq 2225  df-clel 2228  df-nfc 2373  df-ne 2413  df-ral 2525  df-rex 2526  df-reu 2527  df-rab 2529  df-v 2814  df-sbc 3042  df-dif 3212  df-un 3214  df-in 3216  df-ss 3223  df-pw 3670  df-sn 3694  df-pr 3695  df-op 3697  df-uni 3914  df-br 4109  df-opab 4171  df-id 4413  df-xp 4754  df-rel 4755  df-cnv 4756  df-co 4757  df-dm 4758  df-iota 5311  df-fun 5353  df-fv 5359  df-riota 6002  df-ov 6052  df-oprab 6053  df-mpo 6054  df-sub 8445
This theorem is referenced by: (None)
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