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Theorem ordtri3or 6355
Description: A trichotomy law for ordinals. Proposition 7.10 of [TakeutiZaring] p. 38. Theorem 1.9(iii) of [Schloeder] p. 1. (Contributed by NM, 10-May-1994.) (Proof shortened by Andrew Salmon, 25-Jul-2011.)
Assertion
Ref Expression
ordtri3or ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴𝐵𝐴 = 𝐵𝐵𝐴))

Proof of Theorem ordtri3or
StepHypRef Expression
1 ordin 6353 . . . . . 6 ((Ord 𝐴 ∧ Ord 𝐵) → Ord (𝐴𝐵))
2 ordirr 6341 . . . . . 6 (Ord (𝐴𝐵) → ¬ (𝐴𝐵) ∈ (𝐴𝐵))
31, 2syl 17 . . . . 5 ((Ord 𝐴 ∧ Ord 𝐵) → ¬ (𝐴𝐵) ∈ (𝐴𝐵))
4 ianor 984 . . . . . 6 (¬ ((𝐴𝐵) ∈ 𝐴 ∧ (𝐵𝐴) ∈ 𝐵) ↔ (¬ (𝐴𝐵) ∈ 𝐴 ∨ ¬ (𝐵𝐴) ∈ 𝐵))
5 elin 3905 . . . . . . 7 ((𝐴𝐵) ∈ (𝐴𝐵) ↔ ((𝐴𝐵) ∈ 𝐴 ∧ (𝐴𝐵) ∈ 𝐵))
6 incom 4149 . . . . . . . . 9 (𝐴𝐵) = (𝐵𝐴)
76eleq1i 2827 . . . . . . . 8 ((𝐴𝐵) ∈ 𝐵 ↔ (𝐵𝐴) ∈ 𝐵)
87anbi2i 624 . . . . . . 7 (((𝐴𝐵) ∈ 𝐴 ∧ (𝐴𝐵) ∈ 𝐵) ↔ ((𝐴𝐵) ∈ 𝐴 ∧ (𝐵𝐴) ∈ 𝐵))
95, 8bitri 275 . . . . . 6 ((𝐴𝐵) ∈ (𝐴𝐵) ↔ ((𝐴𝐵) ∈ 𝐴 ∧ (𝐵𝐴) ∈ 𝐵))
104, 9xchnxbir 333 . . . . 5 (¬ (𝐴𝐵) ∈ (𝐴𝐵) ↔ (¬ (𝐴𝐵) ∈ 𝐴 ∨ ¬ (𝐵𝐴) ∈ 𝐵))
113, 10sylib 218 . . . 4 ((Ord 𝐴 ∧ Ord 𝐵) → (¬ (𝐴𝐵) ∈ 𝐴 ∨ ¬ (𝐵𝐴) ∈ 𝐵))
12 inss1 4177 . . . . . . . . . 10 (𝐴𝐵) ⊆ 𝐴
13 ordsseleq 6352 . . . . . . . . . 10 ((Ord (𝐴𝐵) ∧ Ord 𝐴) → ((𝐴𝐵) ⊆ 𝐴 ↔ ((𝐴𝐵) ∈ 𝐴 ∨ (𝐴𝐵) = 𝐴)))
1412, 13mpbii 233 . . . . . . . . 9 ((Ord (𝐴𝐵) ∧ Ord 𝐴) → ((𝐴𝐵) ∈ 𝐴 ∨ (𝐴𝐵) = 𝐴))
151, 14sylan 581 . . . . . . . 8 (((Ord 𝐴 ∧ Ord 𝐵) ∧ Ord 𝐴) → ((𝐴𝐵) ∈ 𝐴 ∨ (𝐴𝐵) = 𝐴))
1615anabss1 667 . . . . . . 7 ((Ord 𝐴 ∧ Ord 𝐵) → ((𝐴𝐵) ∈ 𝐴 ∨ (𝐴𝐵) = 𝐴))
1716ord 865 . . . . . 6 ((Ord 𝐴 ∧ Ord 𝐵) → (¬ (𝐴𝐵) ∈ 𝐴 → (𝐴𝐵) = 𝐴))
18 dfss2 3907 . . . . . 6 (𝐴𝐵 ↔ (𝐴𝐵) = 𝐴)
1917, 18imbitrrdi 252 . . . . 5 ((Ord 𝐴 ∧ Ord 𝐵) → (¬ (𝐴𝐵) ∈ 𝐴𝐴𝐵))
20 ordin 6353 . . . . . . . . 9 ((Ord 𝐵 ∧ Ord 𝐴) → Ord (𝐵𝐴))
21 inss1 4177 . . . . . . . . . 10 (𝐵𝐴) ⊆ 𝐵
22 ordsseleq 6352 . . . . . . . . . 10 ((Ord (𝐵𝐴) ∧ Ord 𝐵) → ((𝐵𝐴) ⊆ 𝐵 ↔ ((𝐵𝐴) ∈ 𝐵 ∨ (𝐵𝐴) = 𝐵)))
2321, 22mpbii 233 . . . . . . . . 9 ((Ord (𝐵𝐴) ∧ Ord 𝐵) → ((𝐵𝐴) ∈ 𝐵 ∨ (𝐵𝐴) = 𝐵))
2420, 23sylan 581 . . . . . . . 8 (((Ord 𝐵 ∧ Ord 𝐴) ∧ Ord 𝐵) → ((𝐵𝐴) ∈ 𝐵 ∨ (𝐵𝐴) = 𝐵))
2524anabss4 668 . . . . . . 7 ((Ord 𝐴 ∧ Ord 𝐵) → ((𝐵𝐴) ∈ 𝐵 ∨ (𝐵𝐴) = 𝐵))
2625ord 865 . . . . . 6 ((Ord 𝐴 ∧ Ord 𝐵) → (¬ (𝐵𝐴) ∈ 𝐵 → (𝐵𝐴) = 𝐵))
27 dfss2 3907 . . . . . 6 (𝐵𝐴 ↔ (𝐵𝐴) = 𝐵)
2826, 27imbitrrdi 252 . . . . 5 ((Ord 𝐴 ∧ Ord 𝐵) → (¬ (𝐵𝐴) ∈ 𝐵𝐵𝐴))
2919, 28orim12d 967 . . . 4 ((Ord 𝐴 ∧ Ord 𝐵) → ((¬ (𝐴𝐵) ∈ 𝐴 ∨ ¬ (𝐵𝐴) ∈ 𝐵) → (𝐴𝐵𝐵𝐴)))
3011, 29mpd 15 . . 3 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴𝐵𝐵𝐴))
31 sspsstri 4045 . . 3 ((𝐴𝐵𝐵𝐴) ↔ (𝐴𝐵𝐴 = 𝐵𝐵𝐴))
3230, 31sylib 218 . 2 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴𝐵𝐴 = 𝐵𝐵𝐴))
33 ordelpss 6351 . . 3 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴𝐵𝐴𝐵))
34 biidd 262 . . 3 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴 = 𝐵𝐴 = 𝐵))
35 ordelpss 6351 . . . 4 ((Ord 𝐵 ∧ Ord 𝐴) → (𝐵𝐴𝐵𝐴))
3635ancoms 458 . . 3 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐵𝐴𝐵𝐴))
3733, 34, 363orbi123d 1438 . 2 ((Ord 𝐴 ∧ Ord 𝐵) → ((𝐴𝐵𝐴 = 𝐵𝐵𝐴) ↔ (𝐴𝐵𝐴 = 𝐵𝐵𝐴)))
3832, 37mpbird 257 1 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴𝐵𝐴 = 𝐵𝐵𝐴))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 206  wa 395  wo 848  w3o 1086   = wceq 1542  wcel 2114  cin 3888  wss 3889  wpss 3890  Ord word 6322
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-ext 2708  ax-sep 5231  ax-pr 5375
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3or 1088  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-sb 2069  df-clab 2715  df-cleq 2728  df-clel 2811  df-ne 2933  df-ral 3052  df-rex 3062  df-rab 3390  df-v 3431  df-dif 3892  df-un 3894  df-in 3896  df-ss 3906  df-pss 3909  df-nul 4274  df-if 4467  df-pw 4543  df-sn 4568  df-pr 4570  df-op 4574  df-uni 4851  df-br 5086  df-opab 5148  df-tr 5193  df-eprel 5531  df-po 5539  df-so 5540  df-fr 5584  df-we 5586  df-ord 6326
This theorem is referenced by:  ordtri1  6356  oneltri  6366  epweon  7729  epweonALT  7730  ordeleqon  7736  poseq  8108  soseq  8109  smo11  8304  smoord  8305  omopth2  8519  ttrcltr  9637  r111  9699  tcrank  9808  domtriomlem  10364  axdc3lem2  10373  zorn2lem6  10423  grur1  10743  nosepon  27629  addsproplem7  27967  negsproplem7  28026  mulsproplem13  28120  mulsproplem14  28121
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