Theorem ogrpsub 20378

Description: In an ordered group, the ordering is compatible with group subtraction. (Contributed by Thierry Arnoux, 30-Jan-2018.)

Hypotheses

Ref	Expression
ogrpsub.0	⊢ 𝐵 = (Base‘𝐺)
ogrpsub.1	⊢ ≤ = (le‘𝐺)
ogrpsub.2	⊢ − = (-g‘𝐺)

Assertion

Ref	Expression
ogrpsub	⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) ≤ (𝑌 − 𝑍))

Proof of Theorem ogrpsub

Step	Hyp	Ref	Expression
1		isogrp 20365	. . . . 5 ⊢ (𝐺 ∈ oGrp ↔ (𝐺 ∈ Grp ∧ 𝐺 ∈ oMnd))
2	1	simprbi 503	. . . 4 ⊢ (𝐺 ∈ oGrp → 𝐺 ∈ oMnd)
3	2	3ad2ant1 1151	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝐺 ∈ oMnd)
4		simp21 1225	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑋 ∈ 𝐵)
5		simp22 1226	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑌 ∈ 𝐵)
6		ogrpgrp 20366	. . . . 5 ⊢ (𝐺 ∈ oGrp → 𝐺 ∈ Grp)
7	6	3ad2ant1 1151	. . . 4 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝐺 ∈ Grp)
8		simp23 1227	. . . 4 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑍 ∈ 𝐵)
9		ogrpsub.0	. . . . 5 ⊢ 𝐵 = (Base‘𝐺)
10		eqid 2763	. . . . 5 ⊢ (invg‘𝐺) = (invg‘𝐺)
11	9, 10	grpinvcl 19224	. . . 4 ⊢ ((𝐺 ∈ Grp ∧ 𝑍 ∈ 𝐵) → ((invg‘𝐺)‘𝑍) ∈ 𝐵)
12	7, 8, 11	syl2anc 596	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → ((invg‘𝐺)‘𝑍) ∈ 𝐵)
13		simp3 1156	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑋 ≤ 𝑌)
14		ogrpsub.1	. . . 4 ⊢ ≤ = (le‘𝐺)
15		eqid 2763	. . . 4 ⊢ (+g‘𝐺) = (+g‘𝐺)
16	9, 14, 15	omndadd 20369	. . 3 ⊢ ((𝐺 ∈ oMnd ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ ((invg‘𝐺)‘𝑍) ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)) ≤ (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
17	3, 4, 5, 12, 13, 16	syl131anc 1411	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)) ≤ (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
18		ogrpsub.2	. . . 4 ⊢ − = (-g‘𝐺)
19	9, 15, 10, 18	grpsubval 19222	. . 3 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) → (𝑋 − 𝑍) = (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)))
20	4, 8, 19	syl2anc 596	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) = (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)))
21	9, 15, 10, 18	grpsubval 19222	. . 3 ⊢ ((𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) → (𝑌 − 𝑍) = (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
22	5, 8, 21	syl2anc 596	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑌 − 𝑍) = (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
23	17, 20, 22	3brtr4d 5140	1 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) ≤ (𝑌 − 𝑍))

This proof depends on syntax axioms:   → wi 4   ∧ w3a 1103   = wceq 1570   ∈ wcel 2147   class class class wbr 5106  ‘cfv 6555  (class class class)co 7440  Basecbs 17413  +_gcplusg 17454  lecple 17461  Grpcgrp 19170  inv_gcminusg 19171  -_gcsg 19172  oMndcomnd 20360  oGrpcogrp 20361

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-10 2180  ax-11 2197  ax-12 2216  ax-ext 2735  ax-sep 5252  ax-nul 5263  ax-pow 5331  ax-pr 5395  ax-un 7772

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2102  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2839  df-nfc 2913  df-ne 2960  df-ral 3081  df-rex 3091  df-rmo 3369  df-reu 3370  df-rab 3417  df-v 3456  df-sbc 3743  df-csb 3852  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-pw 4562  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-iun 4956  df-br 5107  df-opab 5171  df-mpt 5190  df-id 5550  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-res 5667  df-ima 5668  df-iota 6509  df-fun 6557  df-fn 6558  df-f 6559  df-fv 6563  df-riota 7397  df-ov 7443  df-oprab 7444  df-mpo 7445  df-1st 8022  df-2nd 8023  df-0g 17638  df-mgm 18842  df-sgrp 18934  df-mnd 18950  df-grp 19173  df-minusg 19174  df-sbg 19175  df-omnd 20362  df-ogrp 20363

This theorem is used by:  ogrpsublt  20383  ornglmulle  21151  orngrmulle  21152  archiabllem1a  33819  archiabllem2c  33823