Theorem ogrpsub 20265

Description: In an ordered group, the ordering is compatible with group subtraction. (Contributed by Thierry Arnoux, 30-Jan-2018.)

Hypotheses

Ref	Expression
ogrpsub.0	⊢ 𝐵 = (Base‘𝐺)
ogrpsub.1	⊢ ≤ = (le‘𝐺)
ogrpsub.2	⊢ − = (-g‘𝐺)

Assertion

Ref	Expression
ogrpsub	⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) ≤ (𝑌 − 𝑍))

Proof of Theorem ogrpsub

Step	Hyp	Ref	Expression
1		isogrp 20252	. . . . 5 ⊢ (𝐺 ∈ oGrp ↔ (𝐺 ∈ Grp ∧ 𝐺 ∈ oMnd))
2	1	simprbi 503	. . . 4 ⊢ (𝐺 ∈ oGrp → 𝐺 ∈ oMnd)
3	2	3ad2ant1 1151	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝐺 ∈ oMnd)
4		simp21 1225	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑋 ∈ 𝐵)
5		simp22 1226	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑌 ∈ 𝐵)
6		ogrpgrp 20253	. . . . 5 ⊢ (𝐺 ∈ oGrp → 𝐺 ∈ Grp)
7	6	3ad2ant1 1151	. . . 4 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝐺 ∈ Grp)
8		simp23 1227	. . . 4 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑍 ∈ 𝐵)
9		ogrpsub.0	. . . . 5 ⊢ 𝐵 = (Base‘𝐺)
10		eqid 2762	. . . . 5 ⊢ (invg‘𝐺) = (invg‘𝐺)
11	9, 10	grpinvcl 19112	. . . 4 ⊢ ((𝐺 ∈ Grp ∧ 𝑍 ∈ 𝐵) → ((invg‘𝐺)‘𝑍) ∈ 𝐵)
12	7, 8, 11	syl2anc 596	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → ((invg‘𝐺)‘𝑍) ∈ 𝐵)
13		simp3 1156	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑋 ≤ 𝑌)
14		ogrpsub.1	. . . 4 ⊢ ≤ = (le‘𝐺)
15		eqid 2762	. . . 4 ⊢ (+g‘𝐺) = (+g‘𝐺)
16	9, 14, 15	omndadd 20256	. . 3 ⊢ ((𝐺 ∈ oMnd ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ ((invg‘𝐺)‘𝑍) ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)) ≤ (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
17	3, 4, 5, 12, 13, 16	syl131anc 1410	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)) ≤ (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
18		ogrpsub.2	. . . 4 ⊢ − = (-g‘𝐺)
19	9, 15, 10, 18	grpsubval 19110	. . 3 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) → (𝑋 − 𝑍) = (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)))
20	4, 8, 19	syl2anc 596	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) = (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)))
21	9, 15, 10, 18	grpsubval 19110	. . 3 ⊢ ((𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) → (𝑌 − 𝑍) = (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
22	5, 8, 21	syl2anc 596	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑌 − 𝑍) = (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
23	17, 20, 22	3brtr4d 5141	1 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) ≤ (𝑌 − 𝑍))

This proof depends on syntax axioms:   → wi 4   ∧ w3a 1103   = wceq 1570   ∈ wcel 2145   class class class wbr 5107  ‘cfv 6537  (class class class)co 7416  Basecbs 17305  +_gcplusg 17346  lecple 17353  Grpcgrp 19058  inv_gcminusg 19059  -_gcsg 19060  oMndcomnd 20247  oGrpcogrp 20248

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2215  ax-ext 2734  ax-sep 5255  ax-nul 5267  ax-pow 5334  ax-pr 5402  ax-un 7739

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2566  df-eu 2596  df-clab 2741  df-cleq 2754  df-clel 2837  df-nfc 2911  df-ne 2958  df-ral 3079  df-rex 3089  df-rmo 3367  df-reu 3368  df-rab 3415  df-v 3455  df-sbc 3743  df-csb 3851  df-dif 3905  df-un 3907  df-in 3909  df-ss 3919  df-nul 4283  df-if 4486  df-pw 4562  df-sn 4588  df-pr 4590  df-op 4594  df-uni 4871  df-iun 4956  df-br 5108  df-opab 5172  df-mpt 5191  df-id 5554  df-xp 5665  df-rel 5666  df-cnv 5667  df-co 5668  df-dm 5669  df-rn 5670  df-res 5671  df-ima 5672  df-iota 6493  df-fun 6539  df-fn 6540  df-f 6541  df-fv 6545  df-riota 7373  df-ov 7419  df-oprab 7420  df-mpo 7421  df-1st 7989  df-2nd 7990  df-0g 17530  df-mgm 18734  df-sgrp 18823  df-mnd 18839  df-grp 19061  df-minusg 19062  df-sbg 19063  df-omnd 20249  df-ogrp 20250

This theorem is used by:  ogrpsublt  20270  ornglmulle  21034  orngrmulle  21035  archiabllem1a  33618  archiabllem2c  33622