Theorem ogrpsub 20351

Description: In an ordered group, the ordering is compatible with group subtraction. (Contributed by Thierry Arnoux, 30-Jan-2018.)

Hypotheses

Ref	Expression
ogrpsub.0	⊢ 𝐵 = (Base‘𝐺)
ogrpsub.1	⊢ ≤ = (le‘𝐺)
ogrpsub.2	⊢ − = (-g‘𝐺)

Assertion

Ref	Expression
ogrpsub	⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) ≤ (𝑌 − 𝑍))

Proof of Theorem ogrpsub

Step	Hyp	Ref	Expression
1		isogrp 20338	. . . . 5 ⊢ (𝐺 ∈ oGrp ↔ (𝐺 ∈ Grp ∧ 𝐺 ∈ oMnd))
2	1	simprbi 503	. . . 4 ⊢ (𝐺 ∈ oGrp → 𝐺 ∈ oMnd)
3	2	3ad2ant1 1151	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝐺 ∈ oMnd)
4		simp21 1225	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑋 ∈ 𝐵)
5		simp22 1226	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑌 ∈ 𝐵)
6		ogrpgrp 20339	. . . . 5 ⊢ (𝐺 ∈ oGrp → 𝐺 ∈ Grp)
7	6	3ad2ant1 1151	. . . 4 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝐺 ∈ Grp)
8		simp23 1227	. . . 4 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑍 ∈ 𝐵)
9		ogrpsub.0	. . . . 5 ⊢ 𝐵 = (Base‘𝐺)
10		eqid 2760	. . . . 5 ⊢ (invg‘𝐺) = (invg‘𝐺)
11	9, 10	grpinvcl 19198	. . . 4 ⊢ ((𝐺 ∈ Grp ∧ 𝑍 ∈ 𝐵) → ((invg‘𝐺)‘𝑍) ∈ 𝐵)
12	7, 8, 11	syl2anc 596	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → ((invg‘𝐺)‘𝑍) ∈ 𝐵)
13		simp3 1156	. . 3 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → 𝑋 ≤ 𝑌)
14		ogrpsub.1	. . . 4 ⊢ ≤ = (le‘𝐺)
15		eqid 2760	. . . 4 ⊢ (+g‘𝐺) = (+g‘𝐺)
16	9, 14, 15	omndadd 20342	. . 3 ⊢ ((𝐺 ∈ oMnd ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ ((invg‘𝐺)‘𝑍) ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)) ≤ (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
17	3, 4, 5, 12, 13, 16	syl131anc 1410	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)) ≤ (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
18		ogrpsub.2	. . . 4 ⊢ − = (-g‘𝐺)
19	9, 15, 10, 18	grpsubval 19196	. . 3 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) → (𝑋 − 𝑍) = (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)))
20	4, 8, 19	syl2anc 596	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) = (𝑋(+g‘𝐺)((invg‘𝐺)‘𝑍)))
21	9, 15, 10, 18	grpsubval 19196	. . 3 ⊢ ((𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) → (𝑌 − 𝑍) = (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
22	5, 8, 21	syl2anc 596	. 2 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑌 − 𝑍) = (𝑌(+g‘𝐺)((invg‘𝐺)‘𝑍)))
23	17, 20, 22	3brtr4d 5136	1 ⊢ ((𝐺 ∈ oGrp ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵) ∧ 𝑋 ≤ 𝑌) → (𝑋 − 𝑍) ≤ (𝑌 − 𝑍))

This proof depends on syntax axioms:   → wi 4   ∧ w3a 1103   = wceq 1569   ∈ wcel 2144   class class class wbr 5102  ‘cfv 6538  (class class class)co 7420  Basecbs 17387  +_gcplusg 17428  lecple 17435  Grpcgrp 19144  inv_gcminusg 19145  -_gcsg 19146  oMndcomnd 20333  oGrpcogrp 20334

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732  ax-sep 5248  ax-nul 5259  ax-pow 5326  ax-pr 5390  ax-un 7751

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2099  df-mo 2564  df-eu 2594  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ne 2956  df-ral 3077  df-rex 3087  df-rmo 3365  df-reu 3366  df-rab 3413  df-v 3452  df-sbc 3739  df-csb 3847  df-ss 3896  df-dif 4047  df-in 4091  df-un 4151  df-nul 4279  df-if 4482  df-pw 4558  df-sn 4584  df-pr 4586  df-op 4590  df-uni 4867  df-iun 4952  df-br 5103  df-opab 5167  df-mpt 5186  df-id 5545  df-xp 5656  df-rel 5657  df-cnv 5658  df-co 5659  df-dm 5660  df-rn 5661  df-res 5662  df-ima 5663  df-iota 6494  df-fun 6540  df-fn 6541  df-f 6542  df-fv 6546  df-riota 7377  df-ov 7423  df-oprab 7424  df-mpo 7425  df-1st 8001  df-2nd 8002  df-0g 17612  df-mgm 18816  df-sgrp 18908  df-mnd 18924  df-grp 19147  df-minusg 19148  df-sbg 19149  df-omnd 20335  df-ogrp 20336

This theorem is used by:  ogrpsublt  20356  ornglmulle  21124  orngrmulle  21125  archiabllem1a  33752  archiabllem2c  33756