Proof of Theorem rngonegrmul
Step | Hyp | Ref
| Expression |
1 | | ringnegmul.3 |
. . . . . . 7
⊢ 𝑋 = ran 𝐺 |
2 | | ringnegmul.1 |
. . . . . . . 8
⊢ 𝐺 = (1st ‘𝑅) |
3 | 2 | rneqi 5846 |
. . . . . . 7
⊢ ran 𝐺 = ran (1st
‘𝑅) |
4 | 1, 3 | eqtri 2766 |
. . . . . 6
⊢ 𝑋 = ran (1st
‘𝑅) |
5 | | ringnegmul.2 |
. . . . . 6
⊢ 𝐻 = (2nd ‘𝑅) |
6 | | eqid 2738 |
. . . . . 6
⊢
(GId‘𝐻) =
(GId‘𝐻) |
7 | 4, 5, 6 | rngo1cl 36097 |
. . . . 5
⊢ (𝑅 ∈ RingOps →
(GId‘𝐻) ∈ 𝑋) |
8 | | ringnegmul.4 |
. . . . . 6
⊢ 𝑁 = (inv‘𝐺) |
9 | 2, 1, 8 | rngonegcl 36085 |
. . . . 5
⊢ ((𝑅 ∈ RingOps ∧
(GId‘𝐻) ∈ 𝑋) → (𝑁‘(GId‘𝐻)) ∈ 𝑋) |
10 | 7, 9 | mpdan 684 |
. . . 4
⊢ (𝑅 ∈ RingOps → (𝑁‘(GId‘𝐻)) ∈ 𝑋) |
11 | 2, 5, 1 | rngoass 36064 |
. . . . . . 7
⊢ ((𝑅 ∈ RingOps ∧ (𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ∧ (𝑁‘(GId‘𝐻)) ∈ 𝑋)) → ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻))) = (𝐴𝐻(𝐵𝐻(𝑁‘(GId‘𝐻))))) |
12 | 11 | 3exp2 1353 |
. . . . . 6
⊢ (𝑅 ∈ RingOps → (𝐴 ∈ 𝑋 → (𝐵 ∈ 𝑋 → ((𝑁‘(GId‘𝐻)) ∈ 𝑋 → ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻))) = (𝐴𝐻(𝐵𝐻(𝑁‘(GId‘𝐻)))))))) |
13 | 12 | com24 95 |
. . . . 5
⊢ (𝑅 ∈ RingOps → ((𝑁‘(GId‘𝐻)) ∈ 𝑋 → (𝐵 ∈ 𝑋 → (𝐴 ∈ 𝑋 → ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻))) = (𝐴𝐻(𝐵𝐻(𝑁‘(GId‘𝐻)))))))) |
14 | 13 | com34 91 |
. . . 4
⊢ (𝑅 ∈ RingOps → ((𝑁‘(GId‘𝐻)) ∈ 𝑋 → (𝐴 ∈ 𝑋 → (𝐵 ∈ 𝑋 → ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻))) = (𝐴𝐻(𝐵𝐻(𝑁‘(GId‘𝐻)))))))) |
15 | 10, 14 | mpd 15 |
. . 3
⊢ (𝑅 ∈ RingOps → (𝐴 ∈ 𝑋 → (𝐵 ∈ 𝑋 → ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻))) = (𝐴𝐻(𝐵𝐻(𝑁‘(GId‘𝐻))))))) |
16 | 15 | 3imp 1110 |
. 2
⊢ ((𝑅 ∈ RingOps ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋) → ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻))) = (𝐴𝐻(𝐵𝐻(𝑁‘(GId‘𝐻))))) |
17 | 2, 5, 1 | rngocl 36059 |
. . . . 5
⊢ ((𝑅 ∈ RingOps ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋) → (𝐴𝐻𝐵) ∈ 𝑋) |
18 | 17 | 3expb 1119 |
. . . 4
⊢ ((𝑅 ∈ RingOps ∧ (𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋)) → (𝐴𝐻𝐵) ∈ 𝑋) |
19 | 2, 5, 1, 8, 6 | rngonegmn1r 36100 |
. . . 4
⊢ ((𝑅 ∈ RingOps ∧ (𝐴𝐻𝐵) ∈ 𝑋) → (𝑁‘(𝐴𝐻𝐵)) = ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻)))) |
20 | 18, 19 | syldan 591 |
. . 3
⊢ ((𝑅 ∈ RingOps ∧ (𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋)) → (𝑁‘(𝐴𝐻𝐵)) = ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻)))) |
21 | 20 | 3impb 1114 |
. 2
⊢ ((𝑅 ∈ RingOps ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋) → (𝑁‘(𝐴𝐻𝐵)) = ((𝐴𝐻𝐵)𝐻(𝑁‘(GId‘𝐻)))) |
22 | 2, 5, 1, 8, 6 | rngonegmn1r 36100 |
. . . 4
⊢ ((𝑅 ∈ RingOps ∧ 𝐵 ∈ 𝑋) → (𝑁‘𝐵) = (𝐵𝐻(𝑁‘(GId‘𝐻)))) |
23 | 22 | 3adant2 1130 |
. . 3
⊢ ((𝑅 ∈ RingOps ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋) → (𝑁‘𝐵) = (𝐵𝐻(𝑁‘(GId‘𝐻)))) |
24 | 23 | oveq2d 7291 |
. 2
⊢ ((𝑅 ∈ RingOps ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋) → (𝐴𝐻(𝑁‘𝐵)) = (𝐴𝐻(𝐵𝐻(𝑁‘(GId‘𝐻))))) |
25 | 16, 21, 24 | 3eqtr4d 2788 |
1
⊢ ((𝑅 ∈ RingOps ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋) → (𝑁‘(𝐴𝐻𝐵)) = (𝐴𝐻(𝑁‘𝐵))) |