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Theorem infeq5 9616
Description: The statement "there exists a set that is a proper subset of its union" is equivalent to the Axiom of Infinity (shown on the right-hand side in the form of omex 9622.) The left-hand side provides us with a very short way to express the Axiom of Infinity using only elementary symbols. This proof of equivalence does not depend on the Axiom of Infinity. (Contributed by NM, 23-Mar-2004.) (Revised by Mario Carneiro, 16-Nov-2014.)
Assertion
Ref Expression
infeq5 (∃𝑥 𝑥 𝑥 ↔ ω ∈ V)

Proof of Theorem infeq5
Dummy variables 𝑦 𝑤 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 df-pss 3918 . . . . 5 (𝑥 𝑥 ↔ (𝑥 𝑥𝑥 𝑥))
2 unieq 4877 . . . . . . . . . 10 (𝑥 = ∅ → 𝑥 = ∅)
3 uni0 4895 . . . . . . . . . 10 ∅ = ∅
42, 3eqtr2di 2812 . . . . . . . . 9 (𝑥 = ∅ → ∅ = 𝑥)
5 eqtr 2780 . . . . . . . . 9 ((𝑥 = ∅ ∧ ∅ = 𝑥) → 𝑥 = 𝑥)
64, 5mpdan 700 . . . . . . . 8 (𝑥 = ∅ → 𝑥 = 𝑥)
76necon3i 2987 . . . . . . 7 (𝑥 𝑥𝑥 ≠ ∅)
87anim1i 627 . . . . . 6 ((𝑥 𝑥𝑥 𝑥) → (𝑥 ≠ ∅ ∧ 𝑥 𝑥))
98ancoms 464 . . . . 5 ((𝑥 𝑥𝑥 𝑥) → (𝑥 ≠ ∅ ∧ 𝑥 𝑥))
101, 9sylbi 220 . . . 4 (𝑥 𝑥 → (𝑥 ≠ ∅ ∧ 𝑥 𝑥))
1110eximi 1868 . . 3 (∃𝑥 𝑥 𝑥 → ∃𝑥(𝑥 ≠ ∅ ∧ 𝑥 𝑥))
12 eqid 2760 . . . . 5 (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦}) = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})
13 eqid 2760 . . . . 5 (rec((𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦}), ∅) ↾ ω) = (rec((𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦}), ∅) ↾ ω)
14 vex 3454 . . . . 5 𝑥 ∈ V
1512, 13, 14, 14inf3lem7 9613 . . . 4 ((𝑥 ≠ ∅ ∧ 𝑥 𝑥) → ω ∈ V)
1615exlimiv 1963 . . 3 (∃𝑥(𝑥 ≠ ∅ ∧ 𝑥 𝑥) → ω ∈ V)
1711, 16syl 18 . 2 (∃𝑥 𝑥 𝑥 → ω ∈ V)
18 infeq5i 9615 . 2 (ω ∈ V → ∃𝑥 𝑥 𝑥)
1917, 18impbii 212 1 (∃𝑥 𝑥 𝑥 ↔ ω ∈ V)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wa 401   = wceq 1570  wex 1812  wcel 2145  wne 2955  {crab 3412  Vcvv 3450  cin 3897  wss 3898  wpss 3899  c0 4278   cuni 4866  cmpt 5185  cres 5649  ωcom 7860  reccrdg 8395
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2213  ax-ext 2732  ax-rep 5231  ax-sep 5248  ax-nul 5259  ax-pow 5326  ax-pr 5390  ax-un 7734  ax-reg 9564
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2564  df-eu 2594  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ne 2956  df-ral 3077  df-rex 3087  df-reu 3366  df-rab 3413  df-v 3452  df-sbc 3739  df-csb 3847  df-dif 3901  df-un 3903  df-in 3905  df-ss 3915  df-pss 3918  df-nul 4279  df-if 4482  df-pw 4558  df-sn 4584  df-pr 4586  df-op 4590  df-uni 4867  df-iun 4952  df-br 5103  df-opab 5167  df-mpt 5186  df-tr 5212  df-id 5542  df-eprel 5547  df-po 5555  df-so 5556  df-fr 5600  df-we 5602  df-xp 5653  df-rel 5654  df-cnv 5655  df-co 5656  df-dm 5657  df-rn 5658  df-res 5659  df-ima 5660  df-pred 6293  df-ord 6354  df-on 6355  df-lim 6356  df-suc 6357  df-iota 6483  df-fun 6529  df-fn 6530  df-f 6531  df-f1 6532  df-fo 6533  df-f1o 6534  df-fv 6535  df-ov 7411  df-om 7861  df-2nd 7985  df-frecs 8277  df-wrecs 8308  df-recs 8357  df-rdg 8396
This theorem is used by: (None)
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