Proof of Theorem nmulss1
| Step | Hyp | Ref
| Expression |
| 1 | | simpl3 1210 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → 𝐶 ∈ On) |
| 2 | | simpl2 1209 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → 𝐵 ∈ On) |
| 3 | | 0elon 6416 |
. . . 4
⊢ ∅
∈ On |
| 4 | 3 | a1i 11 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → ∅ ∈ On) |
| 5 | | simpl1 1208 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → 𝐴 ∈ On) |
| 6 | | 0ss 4356 |
. . . 4
⊢ ∅
⊆ 𝐶 |
| 7 | 6 | a1i 11 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → ∅ ⊆ 𝐶) |
| 8 | | simpr 489 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → 𝐴 ⊆ 𝐵) |
| 9 | | nmuladdss 36656 |
. . 3
⊢ (((𝐶 ∈ On ∧ 𝐵 ∈ On) ∧ (∅
∈ On ∧ 𝐴 ∈
On) ∧ (∅ ⊆ 𝐶 ∧ 𝐴 ⊆ 𝐵)) → ((∅ ·no
𝐵) +no (𝐶 ·no 𝐴)) ⊆ ((𝐶 ·no 𝐵) +no (∅ ·no 𝐴))) |
| 10 | 1, 2, 4, 5, 7, 8, 9 | syl222anc 1411 |
. 2
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → ((∅ ·no
𝐵) +no (𝐶 ·no 𝐴)) ⊆ ((𝐶 ·no 𝐵) +no (∅ ·no 𝐴))) |
| 11 | | nmull0 36654 |
. . . . 5
⊢ (𝐵 ∈ On → (∅
·no 𝐵) =
∅) |
| 12 | 2, 11 | syl 18 |
. . . 4
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → (∅ ·no
𝐵) =
∅) |
| 13 | 12 | oveq1d 7425 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → ((∅ ·no
𝐵) +no (𝐶 ·no 𝐴)) = (∅ +no (𝐶 ·no 𝐴))) |
| 14 | 1, 5 | nmulcld 36651 |
. . . 4
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → (𝐶 ·no 𝐴) ∈ On) |
| 15 | | naddlid 8670 |
. . . 4
⊢ ((𝐶 ·no 𝐴) ∈ On → (∅ +no
(𝐶 ·no
𝐴)) = (𝐶 ·no 𝐴)) |
| 16 | 14, 15 | syl 18 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → (∅ +no (𝐶 ·no 𝐴)) = (𝐶 ·no 𝐴)) |
| 17 | 13, 16 | eqtr2d 2797 |
. 2
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → (𝐶 ·no 𝐴) = ((∅ ·no 𝐵) +no (𝐶 ·no 𝐴))) |
| 18 | | nmull0 36654 |
. . . . 5
⊢ (𝐴 ∈ On → (∅
·no 𝐴) =
∅) |
| 19 | 5, 18 | syl 18 |
. . . 4
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → (∅ ·no
𝐴) =
∅) |
| 20 | 19 | oveq2d 7426 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → ((𝐶 ·no 𝐵) +no (∅ ·no 𝐴)) = ((𝐶 ·no 𝐵) +no ∅)) |
| 21 | 1, 2 | nmulcld 36651 |
. . . 4
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → (𝐶 ·no 𝐵) ∈ On) |
| 22 | | naddrid 8669 |
. . . 4
⊢ ((𝐶 ·no 𝐵) ∈ On → ((𝐶 ·no 𝐵) +no ∅) = (𝐶 ·no 𝐵)) |
| 23 | 21, 22 | syl 18 |
. . 3
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → ((𝐶 ·no 𝐵) +no ∅) = (𝐶 ·no 𝐵)) |
| 24 | 20, 23 | eqtr2d 2797 |
. 2
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → (𝐶 ·no 𝐵) = ((𝐶 ·no 𝐵) +no (∅ ·no 𝐴))) |
| 25 | 10, 17, 24 | 3sstr4d 3991 |
1
⊢ (((𝐴 ∈ On ∧ 𝐵 ∈ On ∧ 𝐶 ∈ On) ∧ 𝐴 ⊆ 𝐵) → (𝐶 ·no 𝐴) ⊆ (𝐶 ·no 𝐵)) |