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Theorem shftfib 11516
Description: Value of a fiber of the relation 𝐹. (Contributed by Mario Carneiro, 4-Nov-2013.)
Hypothesis
Ref Expression
shftfval.1 𝐹 ∈ V
Assertion
Ref Expression
shftfib ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐹 shift 𝐴) “ {𝐵}) = (𝐹 “ {(𝐵𝐴)}))

Proof of Theorem shftfib
Dummy variables 𝑥 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 shftfval.1 . . . . . . 7 𝐹 ∈ V
21shftfval 11514 . . . . . 6 (𝐴 ∈ ℂ → (𝐹 shift 𝐴) = {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)})
32breqd 4122 . . . . 5 (𝐴 ∈ ℂ → (𝐵(𝐹 shift 𝐴)𝑧𝐵{⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)}𝑧))
4 vex 2818 . . . . . 6 𝑧 ∈ V
5 eleq1 2297 . . . . . . . 8 (𝑥 = 𝐵 → (𝑥 ∈ ℂ ↔ 𝐵 ∈ ℂ))
6 oveq1 6059 . . . . . . . . 9 (𝑥 = 𝐵 → (𝑥𝐴) = (𝐵𝐴))
76breq1d 4121 . . . . . . . 8 (𝑥 = 𝐵 → ((𝑥𝐴)𝐹𝑦 ↔ (𝐵𝐴)𝐹𝑦))
85, 7anbi12d 473 . . . . . . 7 (𝑥 = 𝐵 → ((𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦) ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑦)))
9 breq2 4115 . . . . . . . 8 (𝑦 = 𝑧 → ((𝐵𝐴)𝐹𝑦 ↔ (𝐵𝐴)𝐹𝑧))
109anbi2d 464 . . . . . . 7 (𝑦 = 𝑧 → ((𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑦) ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
11 eqid 2234 . . . . . . 7 {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)} = {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)}
128, 10, 11brabg 4389 . . . . . 6 ((𝐵 ∈ ℂ ∧ 𝑧 ∈ V) → (𝐵{⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)}𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
134, 12mpan2 425 . . . . 5 (𝐵 ∈ ℂ → (𝐵{⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)}𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
143, 13sylan9bb 462 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐵(𝐹 shift 𝐴)𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
15 ibar 301 . . . . 5 (𝐵 ∈ ℂ → ((𝐵𝐴)𝐹𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
1615adantl 277 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐵𝐴)𝐹𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
1714, 16bitr4d 191 . . 3 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐵(𝐹 shift 𝐴)𝑧 ↔ (𝐵𝐴)𝐹𝑧))
1817abbidv 2354 . 2 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → {𝑧𝐵(𝐹 shift 𝐴)𝑧} = {𝑧 ∣ (𝐵𝐴)𝐹𝑧})
19 imasng 5129 . . 3 (𝐵 ∈ ℂ → ((𝐹 shift 𝐴) “ {𝐵}) = {𝑧𝐵(𝐹 shift 𝐴)𝑧})
2019adantl 277 . 2 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐹 shift 𝐴) “ {𝐵}) = {𝑧𝐵(𝐹 shift 𝐴)𝑧})
21 simpr 110 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → 𝐵 ∈ ℂ)
22 simpl 109 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → 𝐴 ∈ ℂ)
2321, 22subcld 8589 . . 3 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐵𝐴) ∈ ℂ)
24 imasng 5129 . . 3 ((𝐵𝐴) ∈ ℂ → (𝐹 “ {(𝐵𝐴)}) = {𝑧 ∣ (𝐵𝐴)𝐹𝑧})
2523, 24syl 14 . 2 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐹 “ {(𝐵𝐴)}) = {𝑧 ∣ (𝐵𝐴)𝐹𝑧})
2618, 20, 253eqtr4d 2277 1 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐹 shift 𝐴) “ {𝐵}) = (𝐹 “ {(𝐵𝐴)}))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104  wb 105   = wceq 1398  wcel 2205  {cab 2220  Vcvv 2815  {csn 3691   class class class wbr 4111  {copab 4172  cima 4754  (class class class)co 6052  cc 8130  cmin 8449   shift cshi 11507
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-13 2207  ax-14 2208  ax-ext 2216  ax-coll 4227  ax-sep 4230  ax-pow 4289  ax-pr 4324  ax-un 4556  ax-setind 4661  ax-resscn 8224  ax-1cn 8225  ax-icn 8227  ax-addcl 8228  ax-addrcl 8229  ax-mulcl 8230  ax-addcom 8232  ax-addass 8234  ax-distr 8236  ax-i2m1 8237  ax-0id 8240  ax-rnegex 8241  ax-cnre 8243
This theorem depends on definitions:  df-bi 117  df-3an 1007  df-tru 1401  df-fal 1404  df-nf 1510  df-sb 1812  df-eu 2085  df-mo 2086  df-clab 2221  df-cleq 2227  df-clel 2230  df-nfc 2375  df-ne 2415  df-ral 2527  df-rex 2528  df-reu 2529  df-rab 2531  df-v 2817  df-sbc 3045  df-csb 3141  df-dif 3215  df-un 3217  df-in 3219  df-ss 3226  df-pw 3673  df-sn 3697  df-pr 3698  df-op 3700  df-uni 3917  df-iun 3995  df-br 4112  df-opab 4174  df-mpt 4175  df-id 4416  df-xp 4757  df-rel 4758  df-cnv 4759  df-co 4760  df-dm 4761  df-rn 4762  df-res 4763  df-ima 4764  df-iota 5314  df-fun 5356  df-fn 5357  df-f 5358  df-f1 5359  df-fo 5360  df-f1o 5361  df-fv 5362  df-riota 6005  df-ov 6055  df-oprab 6056  df-mpo 6057  df-sub 8451  df-shft 11508
This theorem is referenced by:  shftval  11518
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