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Theorem shftfib 11501
Description: Value of a fiber of the relation 𝐹. (Contributed by Mario Carneiro, 4-Nov-2013.)
Hypothesis
Ref Expression
shftfval.1 𝐹 ∈ V
Assertion
Ref Expression
shftfib ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐹 shift 𝐴) “ {𝐵}) = (𝐹 “ {(𝐵𝐴)}))

Proof of Theorem shftfib
Dummy variables 𝑥 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 shftfval.1 . . . . . . 7 𝐹 ∈ V
21shftfval 11499 . . . . . 6 (𝐴 ∈ ℂ → (𝐹 shift 𝐴) = {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)})
32breqd 4119 . . . . 5 (𝐴 ∈ ℂ → (𝐵(𝐹 shift 𝐴)𝑧𝐵{⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)}𝑧))
4 vex 2815 . . . . . 6 𝑧 ∈ V
5 eleq1 2295 . . . . . . . 8 (𝑥 = 𝐵 → (𝑥 ∈ ℂ ↔ 𝐵 ∈ ℂ))
6 oveq1 6056 . . . . . . . . 9 (𝑥 = 𝐵 → (𝑥𝐴) = (𝐵𝐴))
76breq1d 4118 . . . . . . . 8 (𝑥 = 𝐵 → ((𝑥𝐴)𝐹𝑦 ↔ (𝐵𝐴)𝐹𝑦))
85, 7anbi12d 473 . . . . . . 7 (𝑥 = 𝐵 → ((𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦) ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑦)))
9 breq2 4112 . . . . . . . 8 (𝑦 = 𝑧 → ((𝐵𝐴)𝐹𝑦 ↔ (𝐵𝐴)𝐹𝑧))
109anbi2d 464 . . . . . . 7 (𝑦 = 𝑧 → ((𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑦) ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
11 eqid 2232 . . . . . . 7 {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)} = {⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)}
128, 10, 11brabg 4386 . . . . . 6 ((𝐵 ∈ ℂ ∧ 𝑧 ∈ V) → (𝐵{⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)}𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
134, 12mpan2 425 . . . . 5 (𝐵 ∈ ℂ → (𝐵{⟨𝑥, 𝑦⟩ ∣ (𝑥 ∈ ℂ ∧ (𝑥𝐴)𝐹𝑦)}𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
143, 13sylan9bb 462 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐵(𝐹 shift 𝐴)𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
15 ibar 301 . . . . 5 (𝐵 ∈ ℂ → ((𝐵𝐴)𝐹𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
1615adantl 277 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐵𝐴)𝐹𝑧 ↔ (𝐵 ∈ ℂ ∧ (𝐵𝐴)𝐹𝑧)))
1714, 16bitr4d 191 . . 3 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐵(𝐹 shift 𝐴)𝑧 ↔ (𝐵𝐴)𝐹𝑧))
1817abbidv 2352 . 2 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → {𝑧𝐵(𝐹 shift 𝐴)𝑧} = {𝑧 ∣ (𝐵𝐴)𝐹𝑧})
19 imasng 5126 . . 3 (𝐵 ∈ ℂ → ((𝐹 shift 𝐴) “ {𝐵}) = {𝑧𝐵(𝐹 shift 𝐴)𝑧})
2019adantl 277 . 2 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐹 shift 𝐴) “ {𝐵}) = {𝑧𝐵(𝐹 shift 𝐴)𝑧})
21 simpr 110 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → 𝐵 ∈ ℂ)
22 simpl 109 . . . 4 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → 𝐴 ∈ ℂ)
2321, 22subcld 8580 . . 3 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐵𝐴) ∈ ℂ)
24 imasng 5126 . . 3 ((𝐵𝐴) ∈ ℂ → (𝐹 “ {(𝐵𝐴)}) = {𝑧 ∣ (𝐵𝐴)𝐹𝑧})
2523, 24syl 14 . 2 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐹 “ {(𝐵𝐴)}) = {𝑧 ∣ (𝐵𝐴)𝐹𝑧})
2618, 20, 253eqtr4d 2275 1 ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐹 shift 𝐴) “ {𝐵}) = (𝐹 “ {(𝐵𝐴)}))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104  wb 105   = wceq 1398  wcel 2203  {cab 2218  Vcvv 2812  {csn 3688   class class class wbr 4108  {copab 4169  cima 4751  (class class class)co 6049  cc 8121  cmin 8440   shift cshi 11492
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-13 2205  ax-14 2206  ax-ext 2214  ax-coll 4224  ax-sep 4227  ax-pow 4286  ax-pr 4321  ax-un 4553  ax-setind 4658  ax-resscn 8215  ax-1cn 8216  ax-icn 8218  ax-addcl 8219  ax-addrcl 8220  ax-mulcl 8221  ax-addcom 8223  ax-addass 8225  ax-distr 8227  ax-i2m1 8228  ax-0id 8231  ax-rnegex 8232  ax-cnre 8234
This theorem depends on definitions:  df-bi 117  df-3an 1007  df-tru 1401  df-fal 1404  df-nf 1510  df-sb 1812  df-eu 2083  df-mo 2084  df-clab 2219  df-cleq 2225  df-clel 2228  df-nfc 2373  df-ne 2413  df-ral 2525  df-rex 2526  df-reu 2527  df-rab 2529  df-v 2814  df-sbc 3042  df-csb 3138  df-dif 3212  df-un 3214  df-in 3216  df-ss 3223  df-pw 3670  df-sn 3694  df-pr 3695  df-op 3697  df-uni 3914  df-iun 3992  df-br 4109  df-opab 4171  df-mpt 4172  df-id 4413  df-xp 4754  df-rel 4755  df-cnv 4756  df-co 4757  df-dm 4758  df-rn 4759  df-res 4760  df-ima 4761  df-iota 5311  df-fun 5353  df-fn 5354  df-f 5355  df-f1 5356  df-fo 5357  df-f1o 5358  df-fv 5359  df-riota 6002  df-ov 6052  df-oprab 6053  df-mpo 6054  df-sub 8442  df-shft 11493
This theorem is referenced by:  shftval  11503
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