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| Mirrors > Home > ILE Home > Th. List > qusecsub | GIF version | ||
| Description: Two subgroup cosets are equal if and only if the difference of their representatives is a member of the subgroup. (Contributed by AV, 7-Mar-2025.) |
| Ref | Expression |
|---|---|
| qusecsub.x | ⊢ 𝐵 = (Base‘𝐺) |
| qusecsub.n | ⊢ − = (-g‘𝐺) |
| qusecsub.r | ⊢ ∼ = (𝐺 ~QG 𝑆) |
| Ref | Expression |
|---|---|
| qusecsub | ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ([𝑋] ∼ = [𝑌] ∼ ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | qusecsub.x | . . . . . 6 ⊢ 𝐵 = (Base‘𝐺) | |
| 2 | 1 | subgss 13779 | . . . . 5 ⊢ (𝑆 ∈ (SubGrp‘𝐺) → 𝑆 ⊆ 𝐵) |
| 3 | 2 | anim2i 342 | . . . 4 ⊢ ((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) → (𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵)) |
| 4 | 3 | adantr 276 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵)) |
| 5 | qusecsub.n | . . . 4 ⊢ − = (-g‘𝐺) | |
| 6 | qusecsub.r | . . . 4 ⊢ ∼ = (𝐺 ~QG 𝑆) | |
| 7 | 1, 5, 6 | eqgabl 13935 | . . 3 ⊢ ((𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵) → (𝑋 ∼ 𝑌 ↔ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 8 | 4, 7 | syl 14 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝑋 ∼ 𝑌 ↔ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 9 | 1, 6 | eqger 13829 | . . . 4 ⊢ (𝑆 ∈ (SubGrp‘𝐺) → ∼ Er 𝐵) |
| 10 | 9 | ad2antlr 489 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ∼ Er 𝐵) |
| 11 | simprl 531 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → 𝑋 ∈ 𝐵) | |
| 12 | 10, 11 | erth 6748 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝑋 ∼ 𝑌 ↔ [𝑋] ∼ = [𝑌] ∼ )) |
| 13 | df-3an 1006 | . . 3 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆) ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆)) | |
| 14 | ibar 301 | . . . 4 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) → ((𝑌 − 𝑋) ∈ 𝑆 ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆))) | |
| 15 | 14 | adantl 277 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ((𝑌 − 𝑋) ∈ 𝑆 ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 16 | 13, 15 | bitr4id 199 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆) ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| 17 | 8, 12, 16 | 3bitr3d 218 | 1 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ([𝑋] ∼ = [𝑌] ∼ ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 ∧ wa 104 ↔ wb 105 ∧ w3a 1004 = wceq 1397 ∈ wcel 2202 ⊆ wss 3200 class class class wbr 4088 ‘cfv 5326 (class class class)co 6018 Er wer 6699 [cec 6700 Basecbs 13100 -gcsg 13603 SubGrpcsubg 13772 ~QG cqg 13774 Abelcabl 13890 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 619 ax-in2 620 ax-io 716 ax-5 1495 ax-7 1496 ax-gen 1497 ax-ie1 1541 ax-ie2 1542 ax-8 1552 ax-10 1553 ax-11 1554 ax-i12 1555 ax-bndl 1557 ax-4 1558 ax-17 1574 ax-i9 1578 ax-ial 1582 ax-i5r 1583 ax-13 2204 ax-14 2205 ax-ext 2213 ax-coll 4204 ax-sep 4207 ax-pow 4264 ax-pr 4299 ax-un 4530 ax-setind 4635 ax-cnex 8123 ax-resscn 8124 ax-1cn 8125 ax-1re 8126 ax-icn 8127 ax-addcl 8128 ax-addrcl 8129 ax-mulcl 8130 ax-addcom 8132 ax-addass 8134 ax-i2m1 8137 ax-0lt1 8138 ax-0id 8140 ax-rnegex 8141 ax-pre-ltirr 8144 ax-pre-ltadd 8148 |
| This theorem depends on definitions: df-bi 117 df-3an 1006 df-tru 1400 df-fal 1403 df-nf 1509 df-sb 1811 df-eu 2082 df-mo 2083 df-clab 2218 df-cleq 2224 df-clel 2227 df-nfc 2363 df-ne 2403 df-nel 2498 df-ral 2515 df-rex 2516 df-reu 2517 df-rmo 2518 df-rab 2519 df-v 2804 df-sbc 3032 df-csb 3128 df-dif 3202 df-un 3204 df-in 3206 df-ss 3213 df-nul 3495 df-pw 3654 df-sn 3675 df-pr 3676 df-op 3678 df-uni 3894 df-int 3929 df-iun 3972 df-br 4089 df-opab 4151 df-mpt 4152 df-id 4390 df-xp 4731 df-rel 4732 df-cnv 4733 df-co 4734 df-dm 4735 df-rn 4736 df-res 4737 df-ima 4738 df-iota 5286 df-fun 5328 df-fn 5329 df-f 5330 df-f1 5331 df-fo 5332 df-f1o 5333 df-fv 5334 df-riota 5971 df-ov 6021 df-oprab 6022 df-mpo 6023 df-1st 6303 df-2nd 6304 df-er 6702 df-ec 6704 df-pnf 8216 df-mnf 8217 df-ltxr 8219 df-inn 9144 df-2 9202 df-ndx 13103 df-slot 13104 df-base 13106 df-sets 13107 df-iress 13108 df-plusg 13191 df-0g 13359 df-mgm 13457 df-sgrp 13503 df-mnd 13518 df-grp 13604 df-minusg 13605 df-sbg 13606 df-subg 13775 df-eqg 13777 df-cmn 13891 df-abl 13892 |
| This theorem is referenced by: (None) |
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