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| Mirrors > Home > ILE Home > Th. List > qusecsub | GIF version | ||
| Description: Two subgroup cosets are equal if and only if the difference of their representatives is a member of the subgroup. (Contributed by AV, 7-Mar-2025.) |
| Ref | Expression |
|---|---|
| qusecsub.x | ⊢ 𝐵 = (Base‘𝐺) |
| qusecsub.n | ⊢ − = (-g‘𝐺) |
| qusecsub.r | ⊢ ∼ = (𝐺 ~QG 𝑆) |
| Ref | Expression |
|---|---|
| qusecsub | ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ([𝑋] ∼ = [𝑌] ∼ ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | qusecsub.x | . . . . . 6 ⊢ 𝐵 = (Base‘𝐺) | |
| 2 | 1 | subgss 13891 | . . . . 5 ⊢ (𝑆 ∈ (SubGrp‘𝐺) → 𝑆 ⊆ 𝐵) |
| 3 | 2 | anim2i 342 | . . . 4 ⊢ ((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) → (𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵)) |
| 4 | 3 | adantr 276 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵)) |
| 5 | qusecsub.n | . . . 4 ⊢ − = (-g‘𝐺) | |
| 6 | qusecsub.r | . . . 4 ⊢ ∼ = (𝐺 ~QG 𝑆) | |
| 7 | 1, 5, 6 | eqgabl 14047 | . . 3 ⊢ ((𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵) → (𝑋 ∼ 𝑌 ↔ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 8 | 4, 7 | syl 14 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝑋 ∼ 𝑌 ↔ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 9 | 1, 6 | eqger 13941 | . . . 4 ⊢ (𝑆 ∈ (SubGrp‘𝐺) → ∼ Er 𝐵) |
| 10 | 9 | ad2antlr 489 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ∼ Er 𝐵) |
| 11 | simprl 531 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → 𝑋 ∈ 𝐵) | |
| 12 | 10, 11 | erth 6813 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝑋 ∼ 𝑌 ↔ [𝑋] ∼ = [𝑌] ∼ )) |
| 13 | df-3an 1007 | . . 3 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆) ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆)) | |
| 14 | ibar 301 | . . . 4 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) → ((𝑌 − 𝑋) ∈ 𝑆 ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆))) | |
| 15 | 14 | adantl 277 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ((𝑌 − 𝑋) ∈ 𝑆 ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 16 | 13, 15 | bitr4id 199 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆) ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| 17 | 8, 12, 16 | 3bitr3d 218 | 1 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ([𝑋] ∼ = [𝑌] ∼ ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 ∧ wa 104 ↔ wb 105 ∧ w3a 1005 = wceq 1398 ∈ wcel 2203 ⊆ wss 3211 class class class wbr 4109 ‘cfv 5352 (class class class)co 6050 Er wer 6764 [cec 6765 Basecbs 13212 -gcsg 13715 SubGrpcsubg 13884 ~QG cqg 13886 Abelcabl 14002 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 619 ax-in2 620 ax-io 717 ax-5 1496 ax-7 1497 ax-gen 1498 ax-ie1 1542 ax-ie2 1543 ax-8 1553 ax-10 1554 ax-11 1555 ax-i12 1556 ax-bndl 1558 ax-4 1559 ax-17 1575 ax-i9 1579 ax-ial 1583 ax-i5r 1584 ax-13 2205 ax-14 2206 ax-ext 2214 ax-coll 4225 ax-sep 4228 ax-pow 4287 ax-pr 4322 ax-un 4554 ax-setind 4659 ax-cnex 8218 ax-resscn 8219 ax-1cn 8220 ax-1re 8221 ax-icn 8222 ax-addcl 8223 ax-addrcl 8224 ax-mulcl 8225 ax-addcom 8227 ax-addass 8229 ax-i2m1 8232 ax-0lt1 8233 ax-0id 8235 ax-rnegex 8236 ax-pre-ltirr 8239 ax-pre-ltadd 8243 |
| This theorem depends on definitions: df-bi 117 df-3an 1007 df-tru 1401 df-fal 1404 df-nf 1510 df-sb 1812 df-eu 2083 df-mo 2084 df-clab 2219 df-cleq 2225 df-clel 2228 df-nfc 2373 df-ne 2413 df-nel 2508 df-ral 2525 df-rex 2526 df-reu 2527 df-rmo 2528 df-rab 2529 df-v 2815 df-sbc 3043 df-csb 3139 df-dif 3213 df-un 3215 df-in 3217 df-ss 3224 df-nul 3509 df-pw 3671 df-sn 3695 df-pr 3696 df-op 3698 df-uni 3915 df-int 3950 df-iun 3993 df-br 4110 df-opab 4172 df-mpt 4173 df-id 4414 df-xp 4755 df-rel 4756 df-cnv 4757 df-co 4758 df-dm 4759 df-rn 4760 df-res 4761 df-ima 4762 df-iota 5312 df-fun 5354 df-fn 5355 df-f 5356 df-f1 5357 df-fo 5358 df-f1o 5359 df-fv 5360 df-riota 6003 df-ov 6053 df-oprab 6054 df-mpo 6055 df-1st 6334 df-2nd 6335 df-er 6767 df-ec 6769 df-pnf 8310 df-mnf 8311 df-ltxr 8313 df-inn 9238 df-2 9296 df-ndx 13215 df-slot 13216 df-base 13218 df-sets 13219 df-iress 13220 df-plusg 13303 df-0g 13471 df-mgm 13569 df-sgrp 13615 df-mnd 13630 df-grp 13716 df-minusg 13717 df-sbg 13718 df-subg 13887 df-eqg 13889 df-cmn 14003 df-abl 14004 |
| This theorem is referenced by: (None) |
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