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| Mirrors > Home > ILE Home > Th. List > qusecsub | GIF version | ||
| Description: Two subgroup cosets are equal if and only if the difference of their representatives is a member of the subgroup. (Contributed by AV, 7-Mar-2025.) |
| Ref | Expression |
|---|---|
| qusecsub.x | ⊢ 𝐵 = (Base‘𝐺) |
| qusecsub.n | ⊢ − = (-g‘𝐺) |
| qusecsub.r | ⊢ ∼ = (𝐺 ~QG 𝑆) |
| Ref | Expression |
|---|---|
| qusecsub | ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ([𝑋] ∼ = [𝑌] ∼ ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | qusecsub.x | . . . . . 6 ⊢ 𝐵 = (Base‘𝐺) | |
| 2 | 1 | subgss 13726 | . . . . 5 ⊢ (𝑆 ∈ (SubGrp‘𝐺) → 𝑆 ⊆ 𝐵) |
| 3 | 2 | anim2i 342 | . . . 4 ⊢ ((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) → (𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵)) |
| 4 | 3 | adantr 276 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵)) |
| 5 | qusecsub.n | . . . 4 ⊢ − = (-g‘𝐺) | |
| 6 | qusecsub.r | . . . 4 ⊢ ∼ = (𝐺 ~QG 𝑆) | |
| 7 | 1, 5, 6 | eqgabl 13882 | . . 3 ⊢ ((𝐺 ∈ Abel ∧ 𝑆 ⊆ 𝐵) → (𝑋 ∼ 𝑌 ↔ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 8 | 4, 7 | syl 14 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝑋 ∼ 𝑌 ↔ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 9 | 1, 6 | eqger 13776 | . . . 4 ⊢ (𝑆 ∈ (SubGrp‘𝐺) → ∼ Er 𝐵) |
| 10 | 9 | ad2antlr 489 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ∼ Er 𝐵) |
| 11 | simprl 529 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → 𝑋 ∈ 𝐵) | |
| 12 | 10, 11 | erth 6734 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → (𝑋 ∼ 𝑌 ↔ [𝑋] ∼ = [𝑌] ∼ )) |
| 13 | df-3an 1004 | . . 3 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆) ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆)) | |
| 14 | ibar 301 | . . . 4 ⊢ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) → ((𝑌 − 𝑋) ∈ 𝑆 ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆))) | |
| 15 | 14 | adantl 277 | . . 3 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ((𝑌 − 𝑋) ∈ 𝑆 ↔ ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑌 − 𝑋) ∈ 𝑆))) |
| 16 | 13, 15 | bitr4id 199 | . 2 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ((𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ (𝑌 − 𝑋) ∈ 𝑆) ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| 17 | 8, 12, 16 | 3bitr3d 218 | 1 ⊢ (((𝐺 ∈ Abel ∧ 𝑆 ∈ (SubGrp‘𝐺)) ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵)) → ([𝑋] ∼ = [𝑌] ∼ ↔ (𝑌 − 𝑋) ∈ 𝑆)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 ∧ wa 104 ↔ wb 105 ∧ w3a 1002 = wceq 1395 ∈ wcel 2200 ⊆ wss 3197 class class class wbr 4083 ‘cfv 5318 (class class class)co 6007 Er wer 6685 [cec 6686 Basecbs 13047 -gcsg 13550 SubGrpcsubg 13719 ~QG cqg 13721 Abelcabl 13837 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 617 ax-in2 618 ax-io 714 ax-5 1493 ax-7 1494 ax-gen 1495 ax-ie1 1539 ax-ie2 1540 ax-8 1550 ax-10 1551 ax-11 1552 ax-i12 1553 ax-bndl 1555 ax-4 1556 ax-17 1572 ax-i9 1576 ax-ial 1580 ax-i5r 1581 ax-13 2202 ax-14 2203 ax-ext 2211 ax-coll 4199 ax-sep 4202 ax-pow 4258 ax-pr 4293 ax-un 4524 ax-setind 4629 ax-cnex 8101 ax-resscn 8102 ax-1cn 8103 ax-1re 8104 ax-icn 8105 ax-addcl 8106 ax-addrcl 8107 ax-mulcl 8108 ax-addcom 8110 ax-addass 8112 ax-i2m1 8115 ax-0lt1 8116 ax-0id 8118 ax-rnegex 8119 ax-pre-ltirr 8122 ax-pre-ltadd 8126 |
| This theorem depends on definitions: df-bi 117 df-3an 1004 df-tru 1398 df-fal 1401 df-nf 1507 df-sb 1809 df-eu 2080 df-mo 2081 df-clab 2216 df-cleq 2222 df-clel 2225 df-nfc 2361 df-ne 2401 df-nel 2496 df-ral 2513 df-rex 2514 df-reu 2515 df-rmo 2516 df-rab 2517 df-v 2801 df-sbc 3029 df-csb 3125 df-dif 3199 df-un 3201 df-in 3203 df-ss 3210 df-nul 3492 df-pw 3651 df-sn 3672 df-pr 3673 df-op 3675 df-uni 3889 df-int 3924 df-iun 3967 df-br 4084 df-opab 4146 df-mpt 4147 df-id 4384 df-xp 4725 df-rel 4726 df-cnv 4727 df-co 4728 df-dm 4729 df-rn 4730 df-res 4731 df-ima 4732 df-iota 5278 df-fun 5320 df-fn 5321 df-f 5322 df-f1 5323 df-fo 5324 df-f1o 5325 df-fv 5326 df-riota 5960 df-ov 6010 df-oprab 6011 df-mpo 6012 df-1st 6292 df-2nd 6293 df-er 6688 df-ec 6690 df-pnf 8194 df-mnf 8195 df-ltxr 8197 df-inn 9122 df-2 9180 df-ndx 13050 df-slot 13051 df-base 13053 df-sets 13054 df-iress 13055 df-plusg 13138 df-0g 13306 df-mgm 13404 df-sgrp 13450 df-mnd 13465 df-grp 13551 df-minusg 13552 df-sbg 13553 df-subg 13722 df-eqg 13724 df-cmn 13838 df-abl 13839 |
| This theorem is referenced by: (None) |
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