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Theorem i2linesd 50408
Description: Solve for the intersection of two lines expressed in Y = MX+B form (note that the lines cannot be vertical). Here we use deduction form. We just solve for X, since Y can be trivially found by using X. This is an example of how to use the algebra helpers. Notice that because this proof uses algebra helpers, the main steps of the proof are higher level and easier to follow by a human reader. (Contributed by David A. Wheeler, 15-Oct-2018.)
Hypotheses
Ref Expression
i2linesd.1 (𝜑𝐴 ∈ ℂ)
i2linesd.2 (𝜑𝐵 ∈ ℂ)
i2linesd.3 (𝜑𝐶 ∈ ℂ)
i2linesd.4 (𝜑𝐷 ∈ ℂ)
i2linesd.5 (𝜑𝑋 ∈ ℂ)
i2linesd.6 (𝜑𝑌 = ((𝐴 · 𝑋) + 𝐵))
i2linesd.7 (𝜑𝑌 = ((𝐶 · 𝑋) + 𝐷))
i2linesd.8 (𝜑 → (𝐴𝐶) ≠ 0)
Assertion
Ref Expression
i2linesd (𝜑𝑋 = ((𝐷𝐵) / (𝐴𝐶)))

Proof of Theorem i2linesd
StepHypRef Expression
1 i2linesd.1 . . 3 (𝜑𝐴 ∈ ℂ)
2 i2linesd.3 . . 3 (𝜑𝐶 ∈ ℂ)
31, 2subcld 11557 . 2 (𝜑 → (𝐴𝐶) ∈ ℂ)
4 i2linesd.5 . 2 (𝜑𝑋 ∈ ℂ)
5 i2linesd.8 . 2 (𝜑 → (𝐴𝐶) ≠ 0)
62, 4mulcld 11217 . . . 4 (𝜑 → (𝐶 · 𝑋) ∈ ℂ)
7 i2linesd.4 . . . . 5 (𝜑𝐷 ∈ ℂ)
8 i2linesd.2 . . . . 5 (𝜑𝐵 ∈ ℂ)
97, 8subcld 11557 . . . 4 (𝜑 → (𝐷𝐵) ∈ ℂ)
101, 4mulcld 11217 . . . . . 6 (𝜑 → (𝐴 · 𝑋) ∈ ℂ)
11 i2linesd.6 . . . . . . 7 (𝜑𝑌 = ((𝐴 · 𝑋) + 𝐵))
12 i2linesd.7 . . . . . . 7 (𝜑𝑌 = ((𝐶 · 𝑋) + 𝐷))
1311, 12eqtr3d 2802 . . . . . 6 (𝜑 → ((𝐴 · 𝑋) + 𝐵) = ((𝐶 · 𝑋) + 𝐷))
1410, 8, 13mvlraddd 11612 . . . . 5 (𝜑 → (𝐴 · 𝑋) = (((𝐶 · 𝑋) + 𝐷) − 𝐵))
156, 7, 8, 14assraddsubd 11616 . . . 4 (𝜑 → (𝐴 · 𝑋) = ((𝐶 · 𝑋) + (𝐷𝐵)))
166, 9, 15mvrladdd 11615 . . 3 (𝜑 → ((𝐴 · 𝑋) − (𝐶 · 𝑋)) = (𝐷𝐵))
171, 4, 2, 16joinlmulsubmuld 50403 . 2 (𝜑 → ((𝐴𝐶) · 𝑋) = (𝐷𝐵))
183, 4, 5, 17mvllmuld 12038 1 (𝜑𝑋 = ((𝐷𝐵) / (𝐴𝐶)))
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1563  wcel 2145  wne 2960  (class class class)co 7400  cc 11086  0cc0 11088   + caddc 11091   · cmul 11093  cmin 11429   / cdiv 11859
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1818  ax-4 1832  ax-5 1933  ax-6 1990  ax-7 2031  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2215  ax-ext 2737  ax-sep 5251  ax-nul 5261  ax-pow 5327  ax-pr 5395  ax-un 7722  ax-resscn 11145  ax-1cn 11146  ax-icn 11147  ax-addcl 11148  ax-addrcl 11149  ax-mulcl 11150  ax-mulrcl 11151  ax-mulcom 11152  ax-addass 11153  ax-mulass 11154  ax-distr 11155  ax-i2m1 11156  ax-1ne0 11157  ax-1rid 11158  ax-rnegex 11159  ax-rrecex 11160  ax-cnre 11161  ax-pre-lttri 11162  ax-pre-lttrn 11163  ax-pre-ltadd 11164  ax-pre-mulgt0 11165
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3or 1102  df-3an 1103  df-tru 1566  df-fal 1576  df-ex 1803  df-nf 1807  df-sb 2094  df-mo 2569  df-eu 2599  df-clab 2744  df-cleq 2757  df-clel 2840  df-nfc 2914  df-ne 2961  df-nel 3065  df-ral 3080  df-rex 3090  df-rmo 3370  df-reu 3371  df-rab 3418  df-v 3459  df-sbc 3748  df-csb 3856  df-dif 3910  df-un 3912  df-in 3914  df-ss 3924  df-nul 4289  df-if 4484  df-pw 4560  df-sn 4586  df-pr 4588  df-op 4592  df-uni 4869  df-br 5106  df-opab 5168  df-mpt 5187  df-id 5547  df-po 5560  df-so 5561  df-xp 5658  df-rel 5659  df-cnv 5660  df-co 5661  df-dm 5662  df-rn 5663  df-res 5664  df-ima 5665  df-iota 6481  df-fun 6527  df-fn 6528  df-f 6529  df-f1 6530  df-fo 6531  df-f1o 6532  df-fv 6533  df-riota 7357  df-ov 7403  df-oprab 7404  df-mpo 7405  df-er 8682  df-en 8932  df-dom 8933  df-sdom 8934  df-pnf 11233  df-mnf 11234  df-xr 11235  df-ltxr 11236  df-le 11237  df-sub 11431  df-neg 11432  df-div 11860
This theorem is referenced by: (None)
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