Proof of Theorem divmuleqap
Step | Hyp | Ref
| Expression |
1 | | divclap 8588 |
. . . . 5
⊢ ((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) → (𝐴 / 𝐶) ∈ ℂ) |
2 | 1 | 3expb 1199 |
. . . 4
⊢ ((𝐴 ∈ ℂ ∧ (𝐶 ∈ ℂ ∧ 𝐶 # 0)) → (𝐴 / 𝐶) ∈ ℂ) |
3 | 2 | ad2ant2r 506 |
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (𝐴 / 𝐶) ∈ ℂ) |
4 | | divclap 8588 |
. . . . 5
⊢ ((𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0) → (𝐵 / 𝐷) ∈ ℂ) |
5 | 4 | 3expb 1199 |
. . . 4
⊢ ((𝐵 ∈ ℂ ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐵 / 𝐷) ∈ ℂ) |
6 | 5 | ad2ant2l 505 |
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (𝐵 / 𝐷) ∈ ℂ) |
7 | | mulcl 7894 |
. . . . . 6
⊢ ((𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ) → (𝐶 · 𝐷) ∈ ℂ) |
8 | 7 | ad2ant2r 506 |
. . . . 5
⊢ (((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐶 · 𝐷) ∈ ℂ) |
9 | | mulap0 8565 |
. . . . 5
⊢ (((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐶 · 𝐷) # 0) |
10 | 8, 9 | jca 304 |
. . . 4
⊢ (((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0)) → ((𝐶 · 𝐷) ∈ ℂ ∧ (𝐶 · 𝐷) # 0)) |
11 | 10 | adantl 275 |
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐶 · 𝐷) ∈ ℂ ∧ (𝐶 · 𝐷) # 0)) |
12 | | mulcanap2 8577 |
. . 3
⊢ (((𝐴 / 𝐶) ∈ ℂ ∧ (𝐵 / 𝐷) ∈ ℂ ∧ ((𝐶 · 𝐷) ∈ ℂ ∧ (𝐶 · 𝐷) # 0)) → (((𝐴 / 𝐶) · (𝐶 · 𝐷)) = ((𝐵 / 𝐷) · (𝐶 · 𝐷)) ↔ (𝐴 / 𝐶) = (𝐵 / 𝐷))) |
13 | 3, 6, 11, 12 | syl3anc 1233 |
. 2
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (((𝐴 / 𝐶) · (𝐶 · 𝐷)) = ((𝐵 / 𝐷) · (𝐶 · 𝐷)) ↔ (𝐴 / 𝐶) = (𝐵 / 𝐷))) |
14 | | simprll 532 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → 𝐶 ∈ ℂ) |
15 | | simprrl 534 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → 𝐷 ∈ ℂ) |
16 | 3, 14, 15 | mulassd 7936 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (((𝐴 / 𝐶) · 𝐶) · 𝐷) = ((𝐴 / 𝐶) · (𝐶 · 𝐷))) |
17 | | divcanap1 8591 |
. . . . . . 7
⊢ ((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) → ((𝐴 / 𝐶) · 𝐶) = 𝐴) |
18 | 17 | 3expb 1199 |
. . . . . 6
⊢ ((𝐴 ∈ ℂ ∧ (𝐶 ∈ ℂ ∧ 𝐶 # 0)) → ((𝐴 / 𝐶) · 𝐶) = 𝐴) |
19 | 18 | ad2ant2r 506 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐴 / 𝐶) · 𝐶) = 𝐴) |
20 | 19 | oveq1d 5866 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (((𝐴 / 𝐶) · 𝐶) · 𝐷) = (𝐴 · 𝐷)) |
21 | 16, 20 | eqtr3d 2205 |
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐴 / 𝐶) · (𝐶 · 𝐷)) = (𝐴 · 𝐷)) |
22 | 14, 15 | mulcomd 7934 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (𝐶 · 𝐷) = (𝐷 · 𝐶)) |
23 | 22 | oveq2d 5867 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐵 / 𝐷) · (𝐶 · 𝐷)) = ((𝐵 / 𝐷) · (𝐷 · 𝐶))) |
24 | 6, 15, 14 | mulassd 7936 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (((𝐵 / 𝐷) · 𝐷) · 𝐶) = ((𝐵 / 𝐷) · (𝐷 · 𝐶))) |
25 | | divcanap1 8591 |
. . . . . . 7
⊢ ((𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0) → ((𝐵 / 𝐷) · 𝐷) = 𝐵) |
26 | 25 | 3expb 1199 |
. . . . . 6
⊢ ((𝐵 ∈ ℂ ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0)) → ((𝐵 / 𝐷) · 𝐷) = 𝐵) |
27 | 26 | ad2ant2l 505 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐵 / 𝐷) · 𝐷) = 𝐵) |
28 | 27 | oveq1d 5866 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (((𝐵 / 𝐷) · 𝐷) · 𝐶) = (𝐵 · 𝐶)) |
29 | 23, 24, 28 | 3eqtr2d 2209 |
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐵 / 𝐷) · (𝐶 · 𝐷)) = (𝐵 · 𝐶)) |
30 | 21, 29 | eqeq12d 2185 |
. 2
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → (((𝐴 / 𝐶) · (𝐶 · 𝐷)) = ((𝐵 / 𝐷) · (𝐶 · 𝐷)) ↔ (𝐴 · 𝐷) = (𝐵 · 𝐶))) |
31 | 13, 30 | bitr3d 189 |
1
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐴 / 𝐶) = (𝐵 / 𝐷) ↔ (𝐴 · 𝐷) = (𝐵 · 𝐶))) |