Proof of Theorem divmuldivap
| Step | Hyp | Ref
| Expression |
| 1 | | 3anass 984 |
. . 3
⊢ ((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ↔ (𝐴 ∈ ℂ ∧ (𝐶 ∈ ℂ ∧ 𝐶 # 0))) |
| 2 | | 3anass 984 |
. . 3
⊢ ((𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0) ↔ (𝐵 ∈ ℂ ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) |
| 3 | | divclap 8705 |
. . . . . 6
⊢ ((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) → (𝐴 / 𝐶) ∈ ℂ) |
| 4 | | divclap 8705 |
. . . . . 6
⊢ ((𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0) → (𝐵 / 𝐷) ∈ ℂ) |
| 5 | | mulcl 8006 |
. . . . . 6
⊢ (((𝐴 / 𝐶) ∈ ℂ ∧ (𝐵 / 𝐷) ∈ ℂ) → ((𝐴 / 𝐶) · (𝐵 / 𝐷)) ∈ ℂ) |
| 6 | 3, 4, 5 | syl2an 289 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → ((𝐴 / 𝐶) · (𝐵 / 𝐷)) ∈ ℂ) |
| 7 | | mulcl 8006 |
. . . . . . . 8
⊢ ((𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ) → (𝐶 · 𝐷) ∈ ℂ) |
| 8 | 7 | ad2ant2r 509 |
. . . . . . 7
⊢ (((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐶 · 𝐷) ∈ ℂ) |
| 9 | 8 | 3adantr1 1158 |
. . . . . 6
⊢ (((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐶 · 𝐷) ∈ ℂ) |
| 10 | 9 | 3adantl1 1155 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐶 · 𝐷) ∈ ℂ) |
| 11 | | mulap0 8681 |
. . . . . . 7
⊢ (((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐶 · 𝐷) # 0) |
| 12 | 11 | 3adantr1 1158 |
. . . . . 6
⊢ (((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐶 · 𝐷) # 0) |
| 13 | 12 | 3adantl1 1155 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (𝐶 · 𝐷) # 0) |
| 14 | | divcanap3 8725 |
. . . . 5
⊢ ((((𝐴 / 𝐶) · (𝐵 / 𝐷)) ∈ ℂ ∧ (𝐶 · 𝐷) ∈ ℂ ∧ (𝐶 · 𝐷) # 0) → (((𝐶 · 𝐷) · ((𝐴 / 𝐶) · (𝐵 / 𝐷))) / (𝐶 · 𝐷)) = ((𝐴 / 𝐶) · (𝐵 / 𝐷))) |
| 15 | 6, 10, 13, 14 | syl3anc 1249 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (((𝐶 · 𝐷) · ((𝐴 / 𝐶) · (𝐵 / 𝐷))) / (𝐶 · 𝐷)) = ((𝐴 / 𝐶) · (𝐵 / 𝐷))) |
| 16 | | simp2 1000 |
. . . . . . . 8
⊢ ((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) → 𝐶 ∈ ℂ) |
| 17 | 16, 3 | jca 306 |
. . . . . . 7
⊢ ((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) → (𝐶 ∈ ℂ ∧ (𝐴 / 𝐶) ∈ ℂ)) |
| 18 | | simp2 1000 |
. . . . . . . 8
⊢ ((𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0) → 𝐷 ∈ ℂ) |
| 19 | 18, 4 | jca 306 |
. . . . . . 7
⊢ ((𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0) → (𝐷 ∈ ℂ ∧ (𝐵 / 𝐷) ∈ ℂ)) |
| 20 | | mul4 8158 |
. . . . . . 7
⊢ (((𝐶 ∈ ℂ ∧ (𝐴 / 𝐶) ∈ ℂ) ∧ (𝐷 ∈ ℂ ∧ (𝐵 / 𝐷) ∈ ℂ)) → ((𝐶 · (𝐴 / 𝐶)) · (𝐷 · (𝐵 / 𝐷))) = ((𝐶 · 𝐷) · ((𝐴 / 𝐶) · (𝐵 / 𝐷)))) |
| 21 | 17, 19, 20 | syl2an 289 |
. . . . . 6
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → ((𝐶 · (𝐴 / 𝐶)) · (𝐷 · (𝐵 / 𝐷))) = ((𝐶 · 𝐷) · ((𝐴 / 𝐶) · (𝐵 / 𝐷)))) |
| 22 | | divcanap2 8707 |
. . . . . . 7
⊢ ((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) → (𝐶 · (𝐴 / 𝐶)) = 𝐴) |
| 23 | | divcanap2 8707 |
. . . . . . 7
⊢ ((𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0) → (𝐷 · (𝐵 / 𝐷)) = 𝐵) |
| 24 | 22, 23 | oveqan12d 5941 |
. . . . . 6
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → ((𝐶 · (𝐴 / 𝐶)) · (𝐷 · (𝐵 / 𝐷))) = (𝐴 · 𝐵)) |
| 25 | 21, 24 | eqtr3d 2231 |
. . . . 5
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → ((𝐶 · 𝐷) · ((𝐴 / 𝐶) · (𝐵 / 𝐷))) = (𝐴 · 𝐵)) |
| 26 | 25 | oveq1d 5937 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → (((𝐶 · 𝐷) · ((𝐴 / 𝐶) · (𝐵 / 𝐷))) / (𝐶 · 𝐷)) = ((𝐴 · 𝐵) / (𝐶 · 𝐷))) |
| 27 | 15, 26 | eqtr3d 2231 |
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐵 ∈ ℂ ∧ 𝐷 ∈ ℂ ∧ 𝐷 # 0)) → ((𝐴 / 𝐶) · (𝐵 / 𝐷)) = ((𝐴 · 𝐵) / (𝐶 · 𝐷))) |
| 28 | 1, 2, 27 | syl2anbr 292 |
. 2
⊢ (((𝐴 ∈ ℂ ∧ (𝐶 ∈ ℂ ∧ 𝐶 # 0)) ∧ (𝐵 ∈ ℂ ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐴 / 𝐶) · (𝐵 / 𝐷)) = ((𝐴 · 𝐵) / (𝐶 · 𝐷))) |
| 29 | 28 | an4s 588 |
1
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ ((𝐶 ∈ ℂ ∧ 𝐶 # 0) ∧ (𝐷 ∈ ℂ ∧ 𝐷 # 0))) → ((𝐴 / 𝐶) · (𝐵 / 𝐷)) = ((𝐴 · 𝐵) / (𝐶 · 𝐷))) |