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| Mirrors > Home > ILE Home > Th. List > Mathboxes > trirec0xor | GIF version | ||
| Description: Version of trirec0 16756 with exclusive-or.
The definition of a discrete field is sometimes stated in terms of exclusive-or but as proved here, this is equivalent to inclusive-or because the two disjuncts cannot be simultaneously true. (Contributed by Jim Kingdon, 10-Jun-2024.) |
| Ref | Expression |
|---|---|
| trirec0xor | ⊢ (∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | trirec0 16756 | . 2 ⊢ (∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0)) | |
| 2 | 1ne0 9254 | . . . . . . . 8 ⊢ 1 ≠ 0 | |
| 3 | 2 | nesymi 2449 | . . . . . . 7 ⊢ ¬ 0 = 1 |
| 4 | simpr 110 | . . . . . . . . . . 11 ⊢ (((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) → 𝑥 = 0) | |
| 5 | 4 | oveq1d 6043 | . . . . . . . . . 10 ⊢ (((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) → (𝑥 · 𝑧) = (0 · 𝑧)) |
| 6 | mul02lem2 8610 | . . . . . . . . . 10 ⊢ (𝑧 ∈ ℝ → (0 · 𝑧) = 0) | |
| 7 | 5, 6 | sylan9eqr 2286 | . . . . . . . . 9 ⊢ ((𝑧 ∈ ℝ ∧ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)) → (𝑥 · 𝑧) = 0) |
| 8 | simprl 531 | . . . . . . . . 9 ⊢ ((𝑧 ∈ ℝ ∧ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)) → (𝑥 · 𝑧) = 1) | |
| 9 | 7, 8 | eqtr3d 2266 | . . . . . . . 8 ⊢ ((𝑧 ∈ ℝ ∧ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)) → 0 = 1) |
| 10 | 9 | rexlimiva 2646 | . . . . . . 7 ⊢ (∃𝑧 ∈ ℝ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) → 0 = 1) |
| 11 | 3, 10 | mto 668 | . . . . . 6 ⊢ ¬ ∃𝑧 ∈ ℝ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) |
| 12 | r19.41v 2690 | . . . . . 6 ⊢ (∃𝑧 ∈ ℝ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) ↔ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)) | |
| 13 | 11, 12 | mtbi 677 | . . . . 5 ⊢ ¬ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) |
| 14 | 13 | biantru 302 | . . . 4 ⊢ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ↔ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ∧ ¬ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∧ 𝑥 = 0))) |
| 15 | df-xor 1421 | . . . 4 ⊢ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0) ↔ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ∧ ¬ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∧ 𝑥 = 0))) | |
| 16 | 14, 15 | bitr4i 187 | . . 3 ⊢ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ↔ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0)) |
| 17 | 16 | ralbii 2539 | . 2 ⊢ (∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0)) |
| 18 | 1, 17 | bitri 184 | 1 ⊢ (∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 ∧ wa 104 ↔ wb 105 ∨ wo 716 ∨ w3o 1004 = wceq 1398 ⊻ wxo 1420 ∈ wcel 2202 ∀wral 2511 ∃wrex 2512 class class class wbr 4093 (class class class)co 6028 ℝcr 8074 0cc0 8075 1c1 8076 · cmul 8080 < clt 8257 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 619 ax-in2 620 ax-io 717 ax-5 1496 ax-7 1497 ax-gen 1498 ax-ie1 1542 ax-ie2 1543 ax-8 1553 ax-10 1554 ax-11 1555 ax-i12 1556 ax-bndl 1558 ax-4 1559 ax-17 1575 ax-i9 1579 ax-ial 1583 ax-i5r 1584 ax-13 2204 ax-14 2205 ax-ext 2213 ax-sep 4212 ax-pow 4270 ax-pr 4305 ax-un 4536 ax-setind 4641 ax-cnex 8166 ax-resscn 8167 ax-1cn 8168 ax-1re 8169 ax-icn 8170 ax-addcl 8171 ax-addrcl 8172 ax-mulcl 8173 ax-mulrcl 8174 ax-addcom 8175 ax-mulcom 8176 ax-addass 8177 ax-mulass 8178 ax-distr 8179 ax-i2m1 8180 ax-0lt1 8181 ax-1rid 8182 ax-0id 8183 ax-rnegex 8184 ax-precex 8185 ax-cnre 8186 ax-pre-ltirr 8187 ax-pre-ltwlin 8188 ax-pre-lttrn 8189 ax-pre-apti 8190 ax-pre-ltadd 8191 ax-pre-mulgt0 8192 ax-pre-mulext 8193 |
| This theorem depends on definitions: df-bi 117 df-3or 1006 df-3an 1007 df-tru 1401 df-fal 1404 df-xor 1421 df-nf 1510 df-sb 1811 df-eu 2082 df-mo 2083 df-clab 2218 df-cleq 2224 df-clel 2227 df-nfc 2364 df-ne 2404 df-nel 2499 df-ral 2516 df-rex 2517 df-reu 2518 df-rmo 2519 df-rab 2520 df-v 2805 df-sbc 3033 df-dif 3203 df-un 3205 df-in 3207 df-ss 3214 df-pw 3658 df-sn 3679 df-pr 3680 df-op 3682 df-uni 3899 df-br 4094 df-opab 4156 df-id 4396 df-po 4399 df-iso 4400 df-xp 4737 df-rel 4738 df-cnv 4739 df-co 4740 df-dm 4741 df-iota 5293 df-fun 5335 df-fv 5341 df-riota 5981 df-ov 6031 df-oprab 6032 df-mpo 6033 df-pnf 8259 df-mnf 8260 df-xr 8261 df-ltxr 8262 df-le 8263 df-sub 8395 df-neg 8396 df-reap 8798 df-ap 8805 df-div 8896 |
| This theorem is referenced by: (None) |
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