Theorem trirec0xor 17106

Description: Version of trirec0 17105 with exclusive-or.

The definition of a discrete field is sometimes stated in terms of exclusive-or but as proved here, this is equivalent to inclusive-or because the two disjuncts cannot be simultaneously true. (Contributed by Jim Kingdon, 10-Jun-2024.)

Assertion

Ref	Expression
trirec0xor	⊢ (∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0))

Distinct variable group:   𝑥,𝑦,𝑧

Proof of Theorem trirec0xor

Step	Hyp	Ref	Expression
1		trirec0 17105	. 2 ⊢ (∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0))
2		1ne0 9373	. . . . . . . 8 ⊢ 1 ≠ 0
3	2	nesymi 2466	. . . . . . 7 ⊢ ¬ 0 = 1
4		simpr 110	. . . . . . . . . . 11 ⊢ (((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) → 𝑥 = 0)
5	4	oveq1d 6100	. . . . . . . . . 10 ⊢ (((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) → (𝑥 · 𝑧) = (0 · 𝑧))
6		mul02lem2 8715	. . . . . . . . . 10 ⊢ (𝑧 ∈ ℝ → (0 · 𝑧) = 0)
7	5, 6	sylan9eqr 2293	. . . . . . . . 9 ⊢ ((𝑧 ∈ ℝ ∧ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)) → (𝑥 · 𝑧) = 0)
8		simprl 535	. . . . . . . . 9 ⊢ ((𝑧 ∈ ℝ ∧ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)) → (𝑥 · 𝑧) = 1)
9	7, 8	eqtr3d 2273	. . . . . . . 8 ⊢ ((𝑧 ∈ ℝ ∧ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)) → 0 = 1)
10	9	rexlimiva 2663	. . . . . . 7 ⊢ (∃𝑧 ∈ ℝ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) → 0 = 1)
11	3, 10	mto 672	. . . . . 6 ⊢ ¬ ∃𝑧 ∈ ℝ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)
12		r19.41v 2707	. . . . . 6 ⊢ (∃𝑧 ∈ ℝ ((𝑥 · 𝑧) = 1 ∧ 𝑥 = 0) ↔ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∧ 𝑥 = 0))
13	11, 12	mtbi 681	. . . . 5 ⊢ ¬ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)
14	13	biantru 302	. . . 4 ⊢ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ↔ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ∧ ¬ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)))
15		df-xor 1425	. . . 4 ⊢ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0) ↔ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ∧ ¬ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∧ 𝑥 = 0)))
16	14, 15	bitr4i 187	. . 3 ⊢ ((∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ↔ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0))
17	16	ralbii 2556	. 2 ⊢ (∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0))
18	1, 17	bitri 184	1 ⊢ (∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦 < 𝑥) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0))

This proof depends on syntax axioms:  ¬ wn 3   ∧ wa 104   ↔ wb 105   ∨ wo 720   ∨ w3o 1008   = wceq 1402   ⊻ wxo 1424   ∈ wcel 2209  ∀wral 2528  ∃wrex 2529   class class class wbr 4130  (class class class)co 6085  ℝcr 8178  0cc0 8179  1c1 8180   · cmul 8184   < clt 8360

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 623  ax-in2 624  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-14 2212  ax-ext 2220  ax-sep 4249  ax-pow 4311  ax-pr 4346  ax-un 4578  ax-setind 4684  ax-cnex 8270  ax-resscn 8271  ax-1cn 8272  ax-1re 8273  ax-icn 8274  ax-addcl 8275  ax-addrcl 8276  ax-mulcl 8277  ax-mulrcl 8278  ax-addcom 8279  ax-mulcom 8280  ax-addass 8281  ax-mulass 8282  ax-distr 8283  ax-i2m1 8284  ax-0lt1 8285  ax-1rid 8286  ax-0id 8287  ax-rnegex 8288  ax-precex 8289  ax-cnre 8290  ax-pre-ltirr 8291  ax-pre-ltwlin 8292  ax-pre-lttrn 8293  ax-pre-apti 8294  ax-pre-ltadd 8295  ax-pre-mulgt0 8296  ax-pre-mulext 8297

This proof depends on definitions:  df-bi 117  df-3or 1010  df-3an 1011  df-tru 1405  df-fal 1408  df-xor 1425  df-nf 1514  df-sb 1816  df-eu 2089  df-mo 2090  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-ne 2421  df-nel 2516  df-ral 2533  df-rex 2534  df-reu 2535  df-rmo 2536  df-rab 2537  df-v 2823  df-sbc 3052  df-dif 3222  df-un 3224  df-in 3226  df-ss 3233  df-pw 3690  df-sn 3715  df-pr 3716  df-op 3718  df-uni 3936  df-br 4131  df-opab 4193  df-id 4438  df-po 4441  df-iso 4442  df-xp 4780  df-rel 4781  df-cnv 4782  df-co 4783  df-dm 4784  df-iota 5337  df-fun 5379  df-fv 5385  df-riota 6038  df-ov 6088  df-oprab 6089  df-mpo 6090  df-pnf 8362  df-mnf 8363  df-xr 8364  df-ltxr 8365  df-le 8366  df-sub 8499  df-neg 8500  df-reap 8904  df-ap 8911  df-div 9004

This theorem is used by: (None)