Users' Mathboxes Mathbox for BTernaryTau < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  rankscottu Structured version   Visualization version   GIF version

Theorem rankscottu 35456
Description: An upper bound on the rank of a Scott's trick set. (Contributed by BTernaryTau, 4-Jul-2026.)
Assertion
Ref Expression
rankscottu (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))

Proof of Theorem rankscottu
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 id 23 . . . . . . 7 (𝑥 ∈ Scott 𝐵𝑥 ∈ Scott 𝐵)
21scottrankd 9874 . . . . . 6 (𝑥 ∈ Scott 𝐵 → (rank‘Scott 𝐵) = suc (rank‘𝑥))
32adantr 485 . . . . 5 ((𝑥 ∈ Scott 𝐵𝐴𝐵) → (rank‘Scott 𝐵) = suc (rank‘𝑥))
4 elscottrankss 35452 . . . . . 6 ((𝑥 ∈ Scott 𝐵𝐴𝐵) → (rank‘𝑥) ⊆ (rank‘𝐴))
5 rankon 9767 . . . . . . . 8 (rank‘𝑥) ∈ On
65onordi 6475 . . . . . . 7 Ord (rank‘𝑥)
7 rankon 9767 . . . . . . . 8 (rank‘𝐴) ∈ On
87onordi 6475 . . . . . . 7 Ord (rank‘𝐴)
9 ordsucsssuc 7819 . . . . . . 7 ((Ord (rank‘𝑥) ∧ Ord (rank‘𝐴)) → ((rank‘𝑥) ⊆ (rank‘𝐴) ↔ suc (rank‘𝑥) ⊆ suc (rank‘𝐴)))
106, 8, 9mp2an 704 . . . . . 6 ((rank‘𝑥) ⊆ (rank‘𝐴) ↔ suc (rank‘𝑥) ⊆ suc (rank‘𝐴))
114, 10sylib 221 . . . . 5 ((𝑥 ∈ Scott 𝐵𝐴𝐵) → suc (rank‘𝑥) ⊆ suc (rank‘𝐴))
123, 11eqsstrd 3979 . . . 4 ((𝑥 ∈ Scott 𝐵𝐴𝐵) → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
1312ex 417 . . 3 (𝑥 ∈ Scott 𝐵 → (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴)))
1413exlimiv 1957 . 2 (∃𝑥 𝑥 ∈ Scott 𝐵 → (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴)))
15 neq0 4314 . . . . 5 (¬ Scott 𝐵 = ∅ ↔ ∃𝑥 𝑥 ∈ Scott 𝐵)
1615con1bii 359 . . . 4 (¬ ∃𝑥 𝑥 ∈ Scott 𝐵 ↔ Scott 𝐵 = ∅)
17 scottex2 9871 . . . . . 6 Scott 𝐵 ∈ V
1817rankeq0 9833 . . . . 5 (Scott 𝐵 = ∅ ↔ (rank‘Scott 𝐵) = ∅)
19 0ss 4364 . . . . . 6 ∅ ⊆ suc (rank‘𝐴)
20 sseq1 3970 . . . . . 6 ((rank‘Scott 𝐵) = ∅ → ((rank‘Scott 𝐵) ⊆ suc (rank‘𝐴) ↔ ∅ ⊆ suc (rank‘𝐴)))
2119, 20mpbiri 261 . . . . 5 ((rank‘Scott 𝐵) = ∅ → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
2218, 21sylbi 220 . . . 4 (Scott 𝐵 = ∅ → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
2316, 22sylbi 220 . . 3 (¬ ∃𝑥 𝑥 ∈ Scott 𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
2423a1d 26 . 2 (¬ ∃𝑥 𝑥 ∈ Scott 𝐵 → (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴)))
2514, 24pm2.61i 184 1 (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 209  wa 400   = wceq 1567  wex 1806  wcel 2149  wss 3913  c0 4294  Ord word 6360  suc csuc 6363  cfv 6537  rankcrnk 9735  Scott cscott 9857
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1822  ax-4 1836  ax-5 1937  ax-6 1994  ax-7 2035  ax-8 2151  ax-9 2159  ax-10 2182  ax-11 2198  ax-12 2219  ax-ext 2741  ax-rep 5242  ax-sep 5261  ax-nul 5271  ax-pow 5337  ax-pr 5405  ax-un 7733  ax-reg 9554  ax-inf2 9610
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3or 1102  df-3an 1103  df-tru 1570  df-fal 1580  df-ex 1807  df-nf 1811  df-sb 2098  df-mo 2573  df-eu 2603  df-clab 2748  df-cleq 2761  df-clel 2844  df-nfc 2918  df-ne 2965  df-ral 3086  df-rex 3096  df-reu 3377  df-rab 3424  df-v 3465  df-sbc 3754  df-csb 3862  df-dif 3916  df-un 3918  df-in 3920  df-ss 3930  df-pss 3933  df-nul 4295  df-if 4493  df-pw 4569  df-sn 4595  df-pr 4597  df-op 4601  df-uni 4877  df-int 4917  df-iun 4962  df-br 5114  df-opab 5178  df-mpt 5197  df-tr 5223  df-id 5557  df-eprel 5562  df-po 5570  df-so 5571  df-fr 5615  df-we 5617  df-xp 5668  df-rel 5669  df-cnv 5670  df-co 5671  df-dm 5672  df-rn 5673  df-res 5674  df-ima 5675  df-pred 6303  df-ord 6364  df-on 6365  df-lim 6366  df-suc 6367  df-iota 6493  df-fun 6539  df-fn 6540  df-f 6541  df-f1 6542  df-fo 6543  df-f1o 6544  df-fv 6545  df-ov 7414  df-om 7863  df-2nd 7987  df-frecs 8278  df-wrecs 8309  df-recs 8358  df-rdg 8397  df-r1 9736  df-rank 9737  df-scott 9858
This theorem is referenced by:  scottssr1  35457  rankkardu  35517
  Copyright terms: Public domain W3C validator