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Theorem rankscottu 35582
Description: An upper bound on the rank of a Scott's trick set. (Contributed by BTernaryTau, 4-Jul-2026.)
Assertion
Ref Expression
rankscottu (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))

Proof of Theorem rankscottu
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 id 23 . . . . . . 7 (𝑥 ∈ Scott 𝐵𝑥 ∈ Scott 𝐵)
21scottrankd 9885 . . . . . 6 (𝑥 ∈ Scott 𝐵 → (rank‘Scott 𝐵) = suc (rank‘𝑥))
32adantr 486 . . . . 5 ((𝑥 ∈ Scott 𝐵𝐴𝐵) → (rank‘Scott 𝐵) = suc (rank‘𝑥))
4 elscottrankss 35576 . . . . . 6 ((𝑥 ∈ Scott 𝐵𝐴𝐵) → (rank‘𝑥) ⊆ (rank‘𝐴))
5 rankon 9774 . . . . . . . 8 (rank‘𝑥) ∈ On
65onordi 6478 . . . . . . 7 Ord (rank‘𝑥)
7 rankon 9774 . . . . . . . 8 (rank‘𝐴) ∈ On
87onordi 6478 . . . . . . 7 Ord (rank‘𝐴)
9 ordsucsssuc 7825 . . . . . . 7 ((Ord (rank‘𝑥) ∧ Ord (rank‘𝐴)) → ((rank‘𝑥) ⊆ (rank‘𝐴) ↔ suc (rank‘𝑥) ⊆ suc (rank‘𝐴)))
106, 8, 9mp2an 705 . . . . . 6 ((rank‘𝑥) ⊆ (rank‘𝐴) ↔ suc (rank‘𝑥) ⊆ suc (rank‘𝐴))
114, 10sylib 221 . . . . 5 ((𝑥 ∈ Scott 𝐵𝐴𝐵) → suc (rank‘𝑥) ⊆ suc (rank‘𝐴))
123, 11eqsstrd 3972 . . . 4 ((𝑥 ∈ Scott 𝐵𝐴𝐵) → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
1312ex 418 . . 3 (𝑥 ∈ Scott 𝐵 → (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴)))
1413exlimiv 1963 . 2 (∃𝑥 𝑥 ∈ Scott 𝐵 → (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴)))
15 neq0 4306 . . . . 5 (¬ Scott 𝐵 = ∅ ↔ ∃𝑥 𝑥 ∈ Scott 𝐵)
1615con1bii 359 . . . 4 (¬ ∃𝑥 𝑥 ∈ Scott 𝐵 ↔ Scott 𝐵 = ∅)
17 scottex 9869 . . . . . 6 Scott 𝐵 ∈ V
1817rankeq0 9840 . . . . 5 (Scott 𝐵 = ∅ ↔ (rank‘Scott 𝐵) = ∅)
19 0ss 4357 . . . . . 6 ∅ ⊆ suc (rank‘𝐴)
20 sseq1 3963 . . . . . 6 ((rank‘Scott 𝐵) = ∅ → ((rank‘Scott 𝐵) ⊆ suc (rank‘𝐴) ↔ ∅ ⊆ suc (rank‘𝐴)))
2119, 20mpbiri 261 . . . . 5 ((rank‘Scott 𝐵) = ∅ → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
2218, 21sylbi 220 . . . 4 (Scott 𝐵 = ∅ → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
2316, 22sylbi 220 . . 3 (¬ ∃𝑥 𝑥 ∈ Scott 𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
2423a1d 26 . 2 (¬ ∃𝑥 𝑥 ∈ Scott 𝐵 → (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴)))
2514, 24pm2.61i 184 1 (𝐴𝐵 → (rank‘Scott 𝐵) ⊆ suc (rank‘𝐴))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3  wi 4  wb 209  wa 401   = wceq 1570  wex 1812  wcel 2146  wss 3906  c0 4286  Ord word 6363  suc csuc 6366  cfv 6540  rankcrnk 9742  Scott cscott 9864
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2195  ax-12 2216  ax-ext 2737  ax-rep 5240  ax-sep 5259  ax-nul 5271  ax-pow 5338  ax-pr 5406  ax-un 7742  ax-reg 9561  ax-inf2 9617
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2569  df-eu 2599  df-clab 2744  df-cleq 2757  df-clel 2840  df-nfc 2914  df-ne 2961  df-ral 3082  df-rex 3092  df-reu 3372  df-rab 3419  df-v 3459  df-sbc 3747  df-csb 3855  df-dif 3909  df-un 3911  df-in 3913  df-ss 3923  df-pss 3926  df-nul 4287  df-if 4490  df-pw 4566  df-sn 4592  df-pr 4594  df-op 4598  df-uni 4875  df-int 4915  df-iun 4960  df-br 5112  df-opab 5176  df-mpt 5195  df-tr 5221  df-id 5558  df-eprel 5563  df-po 5571  df-so 5572  df-fr 5616  df-we 5618  df-xp 5669  df-rel 5670  df-cnv 5671  df-co 5672  df-dm 5673  df-rn 5674  df-res 5675  df-ima 5676  df-pred 6306  df-ord 6367  df-on 6368  df-lim 6369  df-suc 6370  df-iota 6496  df-fun 6542  df-fn 6543  df-f 6544  df-f1 6545  df-fo 6546  df-f1o 6547  df-fv 6548  df-ov 7422  df-om 7869  df-2nd 7993  df-frecs 8284  df-wrecs 8315  df-recs 8364  df-rdg 8403  df-r1 9743  df-rank 9744  df-scott 9865
This theorem is used by:  scottssr1  35583  rankkardu  35643
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