Step | Hyp | Ref
| Expression |
1 | | sn-negex 39881 |
. . 3
⊢ (𝐴 ∈ ℂ →
∃𝑦 ∈ ℂ
(𝐴 + 𝑦) = 0) |
2 | 1 | adantr 485 |
. 2
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) →
∃𝑦 ∈ ℂ
(𝐴 + 𝑦) = 0) |
3 | | simprl 771 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) → 𝑦 ∈ ℂ) |
4 | | simplr 769 |
. . . 4
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) → 𝐵 ∈ ℂ) |
5 | 3, 4 | addcld 10683 |
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) → (𝑦 + 𝐵) ∈ ℂ) |
6 | | simplrr 778 |
. . . . . . . 8
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → (𝐴 + 𝑦) = 0) |
7 | 6 | oveq1d 7158 |
. . . . . . 7
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → ((𝐴 + 𝑦) + 𝐵) = (0 + 𝐵)) |
8 | | simplll 775 |
. . . . . . . 8
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → 𝐴 ∈ ℂ) |
9 | | simplrl 777 |
. . . . . . . 8
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → 𝑦 ∈ ℂ) |
10 | | simpllr 776 |
. . . . . . . 8
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → 𝐵 ∈ ℂ) |
11 | 8, 9, 10 | addassd 10686 |
. . . . . . 7
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → ((𝐴 + 𝑦) + 𝐵) = (𝐴 + (𝑦 + 𝐵))) |
12 | | sn-addid2 39869 |
. . . . . . . 8
⊢ (𝐵 ∈ ℂ → (0 +
𝐵) = 𝐵) |
13 | 10, 12 | syl 17 |
. . . . . . 7
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → (0 + 𝐵) = 𝐵) |
14 | 7, 11, 13 | 3eqtr3rd 2803 |
. . . . . 6
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → 𝐵 = (𝐴 + (𝑦 + 𝐵))) |
15 | 14 | eqeq2d 2770 |
. . . . 5
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → ((𝐴 + 𝑥) = 𝐵 ↔ (𝐴 + 𝑥) = (𝐴 + (𝑦 + 𝐵)))) |
16 | | simpr 489 |
. . . . . 6
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → 𝑥 ∈ ℂ) |
17 | 9, 10 | addcld 10683 |
. . . . . 6
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → (𝑦 + 𝐵) ∈ ℂ) |
18 | 8, 16, 17 | sn-addcand 39883 |
. . . . 5
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → ((𝐴 + 𝑥) = (𝐴 + (𝑦 + 𝐵)) ↔ 𝑥 = (𝑦 + 𝐵))) |
19 | 15, 18 | bitrd 282 |
. . . 4
⊢ ((((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) ∧ 𝑥 ∈ ℂ) → ((𝐴 + 𝑥) = 𝐵 ↔ 𝑥 = (𝑦 + 𝐵))) |
20 | 19 | ralrimiva 3111 |
. . 3
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) → ∀𝑥 ∈ ℂ ((𝐴 + 𝑥) = 𝐵 ↔ 𝑥 = (𝑦 + 𝐵))) |
21 | | reu6i 3639 |
. . 3
⊢ (((𝑦 + 𝐵) ∈ ℂ ∧ ∀𝑥 ∈ ℂ ((𝐴 + 𝑥) = 𝐵 ↔ 𝑥 = (𝑦 + 𝐵))) → ∃!𝑥 ∈ ℂ (𝐴 + 𝑥) = 𝐵) |
22 | 5, 20, 21 | syl2anc 588 |
. 2
⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝑦 ∈ ℂ ∧ (𝐴 + 𝑦) = 0)) → ∃!𝑥 ∈ ℂ (𝐴 + 𝑥) = 𝐵) |
23 | 2, 22 | rexlimddv 3213 |
1
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) →
∃!𝑥 ∈ ℂ
(𝐴 + 𝑥) = 𝐵) |