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Theorem nqereq 10346
Description: The function [Q] acts as a substitute for equivalence classes, and it satisfies the fundamental requirement for equivalence representatives: the representatives are equal iff the members are equivalent. (Contributed by Mario Carneiro, 6-May-2013.) (Revised by Mario Carneiro, 12-Aug-2015.) (New usage is discouraged.)
Assertion
Ref Expression
nqereq ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N)) → (𝐴 ~Q 𝐵 ↔ ([Q]‘𝐴) = ([Q]‘𝐵)))

Proof of Theorem nqereq
StepHypRef Expression
1 nqercl 10342 . . . . 5 (𝐴 ∈ (N × N) → ([Q]‘𝐴) ∈ Q)
213ad2ant1 1130 . . . 4 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐴) ∈ Q)
3 nqercl 10342 . . . . 5 (𝐵 ∈ (N × N) → ([Q]‘𝐵) ∈ Q)
433ad2ant2 1131 . . . 4 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐵) ∈ Q)
5 enqer 10332 . . . . . 6 ~Q Er (N × N)
65a1i 11 . . . . 5 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ~Q Er (N × N))
7 nqerrel 10343 . . . . . . 7 (𝐴 ∈ (N × N) → 𝐴 ~Q ([Q]‘𝐴))
873ad2ant1 1130 . . . . . 6 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → 𝐴 ~Q ([Q]‘𝐴))
9 simp3 1135 . . . . . 6 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → 𝐴 ~Q 𝐵)
106, 8, 9ertr3d 8290 . . . . 5 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐴) ~Q 𝐵)
11 nqerrel 10343 . . . . . 6 (𝐵 ∈ (N × N) → 𝐵 ~Q ([Q]‘𝐵))
12113ad2ant2 1131 . . . . 5 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → 𝐵 ~Q ([Q]‘𝐵))
136, 10, 12ertrd 8288 . . . 4 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐴) ~Q ([Q]‘𝐵))
14 enqeq 10345 . . . 4 ((([Q]‘𝐴) ∈ Q ∧ ([Q]‘𝐵) ∈ Q ∧ ([Q]‘𝐴) ~Q ([Q]‘𝐵)) → ([Q]‘𝐴) = ([Q]‘𝐵))
152, 4, 13, 14syl3anc 1368 . . 3 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐴) = ([Q]‘𝐵))
16153expia 1118 . 2 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N)) → (𝐴 ~Q 𝐵 → ([Q]‘𝐴) = ([Q]‘𝐵)))
175a1i 11 . . . 4 ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → ~Q Er (N × N))
187adantr 484 . . . . 5 ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → 𝐴 ~Q ([Q]‘𝐴))
19 simprr 772 . . . . 5 ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → ([Q]‘𝐴) = ([Q]‘𝐵))
2018, 19breqtrd 5056 . . . 4 ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → 𝐴 ~Q ([Q]‘𝐵))
2111ad2antrl 727 . . . 4 ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → 𝐵 ~Q ([Q]‘𝐵))
2217, 20, 21ertr4d 8291 . . 3 ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → 𝐴 ~Q 𝐵)
2322expr 460 . 2 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N)) → (([Q]‘𝐴) = ([Q]‘𝐵) → 𝐴 ~Q 𝐵))
2416, 23impbid 215 1 ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N)) → (𝐴 ~Q 𝐵 ↔ ([Q]‘𝐴) = ([Q]‘𝐵)))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 209  wa 399  w3a 1084   = wceq 1538  wcel 2111   class class class wbr 5030   × cxp 5517  cfv 6324   Er wer 8269  Ncnpi 10255   ~Q ceq 10262  Qcnq 10263  [Q]cerq 10265
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2113  ax-9 2121  ax-10 2142  ax-11 2158  ax-12 2175  ax-ext 2770  ax-sep 5167  ax-nul 5174  ax-pow 5231  ax-pr 5295  ax-un 7441
This theorem depends on definitions:  df-bi 210  df-an 400  df-or 845  df-3or 1085  df-3an 1086  df-tru 1541  df-ex 1782  df-nf 1786  df-sb 2070  df-mo 2598  df-eu 2629  df-clab 2777  df-cleq 2791  df-clel 2870  df-nfc 2938  df-ne 2988  df-ral 3111  df-rex 3112  df-reu 3113  df-rmo 3114  df-rab 3115  df-v 3443  df-sbc 3721  df-csb 3829  df-dif 3884  df-un 3886  df-in 3888  df-ss 3898  df-pss 3900  df-nul 4244  df-if 4426  df-pw 4499  df-sn 4526  df-pr 4528  df-tp 4530  df-op 4532  df-uni 4801  df-iun 4883  df-br 5031  df-opab 5093  df-mpt 5111  df-tr 5137  df-id 5425  df-eprel 5430  df-po 5438  df-so 5439  df-fr 5478  df-we 5480  df-xp 5525  df-rel 5526  df-cnv 5527  df-co 5528  df-dm 5529  df-rn 5530  df-res 5531  df-ima 5532  df-pred 6116  df-ord 6162  df-on 6163  df-lim 6164  df-suc 6165  df-iota 6283  df-fun 6326  df-fn 6327  df-f 6328  df-f1 6329  df-fo 6330  df-f1o 6331  df-fv 6332  df-ov 7138  df-oprab 7139  df-mpo 7140  df-om 7561  df-1st 7671  df-2nd 7672  df-wrecs 7930  df-recs 7991  df-rdg 8029  df-1o 8085  df-oadd 8089  df-omul 8090  df-er 8272  df-ni 10283  df-mi 10285  df-lti 10286  df-enq 10322  df-nq 10323  df-erq 10324  df-1nq 10327
This theorem is referenced by:  adderpq  10367  mulerpq  10368  distrnq  10372  recmulnq  10375  ltexnq  10386
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