Theorem nqereq 11059

Description: The function [Q] acts as a substitute for equivalence classes, and it satisfies the fundamental requirement for equivalence representatives: the representatives are equal iff the members are equivalent. (Contributed by Mario Carneiro, 6-May-2013.) (Revised by Mario Carneiro, 12-Aug-2015.) (New usage is discouraged.)

Assertion

Ref	Expression
nqereq	⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N)) → (𝐴 ~Q 𝐵 ↔ ([Q]‘𝐴) = ([Q]‘𝐵)))

Proof of Theorem nqereq

Step	Hyp	Ref	Expression
1		nqercl 11055	. . . . 5 ⊢ (𝐴 ∈ (N × N) → ([Q]‘𝐴) ∈ Q)
2	1	3ad2ant1 1151	. . . 4 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐴) ∈ Q)
3		nqercl 11055	. . . . 5 ⊢ (𝐵 ∈ (N × N) → ([Q]‘𝐵) ∈ Q)
4	3	3ad2ant2 1152	. . . 4 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐵) ∈ Q)
5		enqer 11045	. . . . . 6 ⊢ ~Q Er (N × N)
6	5	a1i 11	. . . . 5 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ~Q Er (N × N))
7		nqerrel 11056	. . . . . . 7 ⊢ (𝐴 ∈ (N × N) → 𝐴 ~Q ([Q]‘𝐴))
8	7	3ad2ant1 1151	. . . . . 6 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → 𝐴 ~Q ([Q]‘𝐴))
9		simp3 1156	. . . . . 6 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → 𝐴 ~Q 𝐵)
10	6, 8, 9	ertr3d 8774	. . . . 5 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐴) ~Q 𝐵)
11		nqerrel 11056	. . . . . 6 ⊢ (𝐵 ∈ (N × N) → 𝐵 ~Q ([Q]‘𝐵))
12	11	3ad2ant2 1152	. . . . 5 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → 𝐵 ~Q ([Q]‘𝐵))
13	6, 10, 12	ertrd 8772	. . . 4 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐴) ~Q ([Q]‘𝐵))
14		enqeq 11058	. . . 4 ⊢ ((([Q]‘𝐴) ∈ Q ∧ ([Q]‘𝐵) ∈ Q ∧ ([Q]‘𝐴) ~Q ([Q]‘𝐵)) → ([Q]‘𝐴) = ([Q]‘𝐵))
15	2, 4, 13, 14	syl3anc 1399	. . 3 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N) ∧ 𝐴 ~Q 𝐵) → ([Q]‘𝐴) = ([Q]‘𝐵))
16	15	3expia 1139	. 2 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N)) → (𝐴 ~Q 𝐵 → ([Q]‘𝐴) = ([Q]‘𝐵)))
17	5	a1i 11	. . . 4 ⊢ ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → ~Q Er (N × N))
18	7	adantr 486	. . . . 5 ⊢ ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → 𝐴 ~Q ([Q]‘𝐴))
19		simprr 785	. . . . 5 ⊢ ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → ([Q]‘𝐴) = ([Q]‘𝐵))
20	18, 19	breqtrd 5137	. . . 4 ⊢ ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → 𝐴 ~Q ([Q]‘𝐵))
21	11	ad2antrl 741	. . . 4 ⊢ ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → 𝐵 ~Q ([Q]‘𝐵))
22	17, 20, 21	ertr4d 8775	. . 3 ⊢ ((𝐴 ∈ (N × N) ∧ (𝐵 ∈ (N × N) ∧ ([Q]‘𝐴) = ([Q]‘𝐵))) → 𝐴 ~Q 𝐵)
23	22	expr 462	. 2 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N)) → (([Q]‘𝐴) = ([Q]‘𝐵) → 𝐴 ~Q 𝐵))
24	16, 23	impbid 215	1 ⊢ ((𝐴 ∈ (N × N) ∧ 𝐵 ∈ (N × N)) → (𝐴 ~Q 𝐵 ↔ ([Q]‘𝐴) = ([Q]‘𝐵)))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   ∧ w3a 1103   = wceq 1570   ∈ wcel 2147   class class class wbr 5108   × cxp 5656  ‘cfv 6566   Er wer 8752  Ncnpi 10968   ~_Q ceq 10975  Qcnq 10976  [Q]cerq 10978

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-10 2180  ax-11 2197  ax-12 2216  ax-ext 2735  ax-sep 5255  ax-nul 5266  ax-pr 5398  ax-un 7783

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2102  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2839  df-nfc 2913  df-ne 2960  df-ral 3081  df-rex 3091  df-rmo 3369  df-reu 3370  df-rab 3417  df-v 3456  df-sbc 3743  df-csb 3852  df-ss 3901  df-pss 4017  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-pw 4562  df-sn 4589  df-pr 4591  df-op 4841  df-uni 4873  df-iun 4958  df-br 5109  df-opab 5174  df-mpt 5193  df-tr 5219  df-id 5553  df-eprel 5558  df-po 5566  df-so 5567  df-fr 5611  df-we 5613  df-xp 5664  df-rel 5665  df-cnv 5666  df-co 5667  df-dm 5668  df-rn 5669  df-res 5670  df-ima 5671  df-pred 6330  df-ord 6391  df-on 6392  df-lim 6393  df-suc 6394  df-iota 6520  df-fun 6568  df-fn 6569  df-f 6570  df-f1 6571  df-fo 6572  df-f1o 6573  df-fv 6574  df-ov 7454  df-oprab 7455  df-mpo 7456  df-om 7912  df-1st 8035  df-2nd 8036  df-frecs 8337  df-wrecs 8368  df-recs 8417  df-rdg 8456  df-1o 8514  df-oadd 8518  df-omul 8519  df-er 8755  df-ni 10996  df-mi 10998  df-lti 10999  df-enq 11035  df-nq 11036  df-erq 11037  df-1nq 11040

This theorem is used by:  adderpq  11080  mulerpq  11081  distrnq  11085  recmulnq  11088  ltexnq  11099