Proof of Theorem cdleme2
| Step | Hyp | Ref
| Expression |
| 1 | | cdleme1.l |
. . . 4
⊢ ≤ =
(le‘𝐾) |
| 2 | | cdleme1.j |
. . . 4
⊢ ∨ =
(join‘𝐾) |
| 3 | | cdleme1.m |
. . . 4
⊢ ∧ =
(meet‘𝐾) |
| 4 | | cdleme1.a |
. . . 4
⊢ 𝐴 = (Atoms‘𝐾) |
| 5 | | cdleme1.h |
. . . 4
⊢ 𝐻 = (LHyp‘𝐾) |
| 6 | | cdleme1.u |
. . . 4
⊢ 𝑈 = ((𝑃 ∨ 𝑄) ∧ 𝑊) |
| 7 | | cdleme1.f |
. . . 4
⊢ 𝐹 = ((𝑅 ∨ 𝑈) ∧ (𝑄 ∨ ((𝑃 ∨ 𝑅) ∧ 𝑊))) |
| 8 | 1, 2, 3, 4, 5, 6, 7 | cdleme1 40229 |
. . 3
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → (𝑅 ∨ 𝐹) = (𝑅 ∨ 𝑈)) |
| 9 | 8 | oveq1d 7446 |
. 2
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → ((𝑅 ∨ 𝐹) ∧ 𝑊) = ((𝑅 ∨ 𝑈) ∧ 𝑊)) |
| 10 | | simpll 767 |
. . 3
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝐾 ∈ HL) |
| 11 | | simpr3l 1235 |
. . 3
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝑅 ∈ 𝐴) |
| 12 | | hllat 39364 |
. . . . . 6
⊢ (𝐾 ∈ HL → 𝐾 ∈ Lat) |
| 13 | 12 | ad2antrr 726 |
. . . . 5
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝐾 ∈ Lat) |
| 14 | | simpr1 1195 |
. . . . . . 7
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝑃 ∈ 𝐴) |
| 15 | | eqid 2737 |
. . . . . . . 8
⊢
(Base‘𝐾) =
(Base‘𝐾) |
| 16 | 15, 4 | atbase 39290 |
. . . . . . 7
⊢ (𝑃 ∈ 𝐴 → 𝑃 ∈ (Base‘𝐾)) |
| 17 | 14, 16 | syl 17 |
. . . . . 6
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝑃 ∈ (Base‘𝐾)) |
| 18 | | simpr2 1196 |
. . . . . . 7
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝑄 ∈ 𝐴) |
| 19 | 15, 4 | atbase 39290 |
. . . . . . 7
⊢ (𝑄 ∈ 𝐴 → 𝑄 ∈ (Base‘𝐾)) |
| 20 | 18, 19 | syl 17 |
. . . . . 6
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝑄 ∈ (Base‘𝐾)) |
| 21 | 15, 2 | latjcl 18484 |
. . . . . 6
⊢ ((𝐾 ∈ Lat ∧ 𝑃 ∈ (Base‘𝐾) ∧ 𝑄 ∈ (Base‘𝐾)) → (𝑃 ∨ 𝑄) ∈ (Base‘𝐾)) |
| 22 | 13, 17, 20, 21 | syl3anc 1373 |
. . . . 5
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → (𝑃 ∨ 𝑄) ∈ (Base‘𝐾)) |
| 23 | 15, 5 | lhpbase 40000 |
. . . . . 6
⊢ (𝑊 ∈ 𝐻 → 𝑊 ∈ (Base‘𝐾)) |
| 24 | 23 | ad2antlr 727 |
. . . . 5
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝑊 ∈ (Base‘𝐾)) |
| 25 | 15, 3 | latmcl 18485 |
. . . . 5
⊢ ((𝐾 ∈ Lat ∧ (𝑃 ∨ 𝑄) ∈ (Base‘𝐾) ∧ 𝑊 ∈ (Base‘𝐾)) → ((𝑃 ∨ 𝑄) ∧ 𝑊) ∈ (Base‘𝐾)) |
| 26 | 13, 22, 24, 25 | syl3anc 1373 |
. . . 4
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → ((𝑃 ∨ 𝑄) ∧ 𝑊) ∈ (Base‘𝐾)) |
| 27 | 6, 26 | eqeltrid 2845 |
. . 3
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝑈 ∈ (Base‘𝐾)) |
| 28 | 15, 1, 3 | latmle2 18510 |
. . . . 5
⊢ ((𝐾 ∈ Lat ∧ (𝑃 ∨ 𝑄) ∈ (Base‘𝐾) ∧ 𝑊 ∈ (Base‘𝐾)) → ((𝑃 ∨ 𝑄) ∧ 𝑊) ≤ 𝑊) |
| 29 | 13, 22, 24, 28 | syl3anc 1373 |
. . . 4
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → ((𝑃 ∨ 𝑄) ∧ 𝑊) ≤ 𝑊) |
| 30 | 6, 29 | eqbrtrid 5178 |
. . 3
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝑈 ≤ 𝑊) |
| 31 | 15, 1, 2, 3, 4 | atmod4i2 39869 |
. . 3
⊢ ((𝐾 ∈ HL ∧ (𝑅 ∈ 𝐴 ∧ 𝑈 ∈ (Base‘𝐾) ∧ 𝑊 ∈ (Base‘𝐾)) ∧ 𝑈 ≤ 𝑊) → ((𝑅 ∧ 𝑊) ∨ 𝑈) = ((𝑅 ∨ 𝑈) ∧ 𝑊)) |
| 32 | 10, 11, 27, 24, 30, 31 | syl131anc 1385 |
. 2
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → ((𝑅 ∧ 𝑊) ∨ 𝑈) = ((𝑅 ∨ 𝑈) ∧ 𝑊)) |
| 33 | | eqid 2737 |
. . . . . 6
⊢
(0.‘𝐾) =
(0.‘𝐾) |
| 34 | 1, 3, 33, 4, 5 | lhpmat 40032 |
. . . . 5
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊)) → (𝑅 ∧ 𝑊) = (0.‘𝐾)) |
| 35 | 34 | 3ad2antr3 1191 |
. . . 4
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → (𝑅 ∧ 𝑊) = (0.‘𝐾)) |
| 36 | 35 | oveq1d 7446 |
. . 3
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → ((𝑅 ∧ 𝑊) ∨ 𝑈) = ((0.‘𝐾) ∨ 𝑈)) |
| 37 | | hlol 39362 |
. . . . 5
⊢ (𝐾 ∈ HL → 𝐾 ∈ OL) |
| 38 | 37 | ad2antrr 726 |
. . . 4
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → 𝐾 ∈ OL) |
| 39 | 15, 2, 33 | olj02 39227 |
. . . 4
⊢ ((𝐾 ∈ OL ∧ 𝑈 ∈ (Base‘𝐾)) → ((0.‘𝐾) ∨ 𝑈) = 𝑈) |
| 40 | 38, 27, 39 | syl2anc 584 |
. . 3
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → ((0.‘𝐾) ∨ 𝑈) = 𝑈) |
| 41 | 36, 40 | eqtrd 2777 |
. 2
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → ((𝑅 ∧ 𝑊) ∨ 𝑈) = 𝑈) |
| 42 | 9, 32, 41 | 3eqtr2d 2783 |
1
⊢ (((𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻) ∧ (𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ (𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊))) → ((𝑅 ∨ 𝐹) ∧ 𝑊) = 𝑈) |