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Theorem naddwordnexlem0 44103
Description: When 𝐴 is the sum of a limit ordinal (or zero) and a natural number and 𝐵 is the sum of a larger limit ordinal and a smaller natural number, (ω ·o suc 𝐶) lies between 𝐴 and 𝐵. (Contributed by RP, 14-Feb-2025.)
Hypotheses
Ref Expression
naddwordnex.a (𝜑𝐴 = ((ω ·o 𝐶) +o 𝑀))
naddwordnex.b (𝜑𝐵 = ((ω ·o 𝐷) +o 𝑁))
naddwordnex.c (𝜑𝐶𝐷)
naddwordnex.d (𝜑𝐷 ∈ On)
naddwordnex.m (𝜑𝑀 ∈ ω)
naddwordnex.n (𝜑𝑁𝑀)
Assertion
Ref Expression
naddwordnexlem0 (𝜑 → (𝐴 ∈ (ω ·o suc 𝐶) ∧ (ω ·o suc 𝐶) ⊆ 𝐵))

Proof of Theorem naddwordnexlem0
StepHypRef Expression
1 omelon 9616 . . . . . 6 ω ∈ On
21a1i 11 . . . . 5 (𝜑 → ω ∈ On)
3 naddwordnex.d . . . . . . 7 (𝜑𝐷 ∈ On)
4 naddwordnex.c . . . . . . 7 (𝜑𝐶𝐷)
5 onelon 6387 . . . . . . 7 ((𝐷 ∈ On ∧ 𝐶𝐷) → 𝐶 ∈ On)
63, 4, 5syl2anc 595 . . . . . 6 (𝜑𝐶 ∈ On)
7 omcl 8522 . . . . . 6 ((ω ∈ On ∧ 𝐶 ∈ On) → (ω ·o 𝐶) ∈ On)
82, 6, 7syl2anc 595 . . . . 5 (𝜑 → (ω ·o 𝐶) ∈ On)
92, 8jca 520 . . . 4 (𝜑 → (ω ∈ On ∧ (ω ·o 𝐶) ∈ On))
10 naddwordnex.m . . . 4 (𝜑𝑀 ∈ ω)
11 oaordi 8532 . . . 4 ((ω ∈ On ∧ (ω ·o 𝐶) ∈ On) → (𝑀 ∈ ω → ((ω ·o 𝐶) +o 𝑀) ∈ ((ω ·o 𝐶) +o ω)))
129, 10, 11sylc 66 . . 3 (𝜑 → ((ω ·o 𝐶) +o 𝑀) ∈ ((ω ·o 𝐶) +o ω))
13 naddwordnex.a . . 3 (𝜑𝐴 = ((ω ·o 𝐶) +o 𝑀))
14 omsuc 8512 . . . 4 ((ω ∈ On ∧ 𝐶 ∈ On) → (ω ·o suc 𝐶) = ((ω ·o 𝐶) +o ω))
152, 6, 14syl2anc 595 . . 3 (𝜑 → (ω ·o suc 𝐶) = ((ω ·o 𝐶) +o ω))
1612, 13, 153eltr4d 2878 . 2 (𝜑𝐴 ∈ (ω ·o suc 𝐶))
17 onsuc 7810 . . . . . . 7 (𝐶 ∈ On → suc 𝐶 ∈ On)
186, 17syl 18 . . . . . 6 (𝜑 → suc 𝐶 ∈ On)
1918, 3, 23jca 1146 . . . . 5 (𝜑 → (suc 𝐶 ∈ On ∧ 𝐷 ∈ On ∧ ω ∈ On))
20 onsucss 43973 . . . . . 6 (𝐷 ∈ On → (𝐶𝐷 → suc 𝐶𝐷))
213, 4, 20sylc 66 . . . . 5 (𝜑 → suc 𝐶𝐷)
22 omwordi 8557 . . . . 5 ((suc 𝐶 ∈ On ∧ 𝐷 ∈ On ∧ ω ∈ On) → (suc 𝐶𝐷 → (ω ·o suc 𝐶) ⊆ (ω ·o 𝐷)))
2319, 21, 22sylc 66 . . . 4 (𝜑 → (ω ·o suc 𝐶) ⊆ (ω ·o 𝐷))
24 omcl 8522 . . . . . 6 ((ω ∈ On ∧ 𝐷 ∈ On) → (ω ·o 𝐷) ∈ On)
252, 3, 24syl2anc 595 . . . . 5 (𝜑 → (ω ·o 𝐷) ∈ On)
26 naddwordnex.n . . . . . . . 8 (𝜑𝑁𝑀)
2726, 10jca 520 . . . . . . 7 (𝜑 → (𝑁𝑀𝑀 ∈ ω))
28 ontr1 6410 . . . . . . 7 (ω ∈ On → ((𝑁𝑀𝑀 ∈ ω) → 𝑁 ∈ ω))
292, 27, 28sylc 66 . . . . . 6 (𝜑𝑁 ∈ ω)
30 nnon 7869 . . . . . 6 (𝑁 ∈ ω → 𝑁 ∈ On)
3129, 30syl 18 . . . . 5 (𝜑𝑁 ∈ On)
32 oaword1 8538 . . . . 5 (((ω ·o 𝐷) ∈ On ∧ 𝑁 ∈ On) → (ω ·o 𝐷) ⊆ ((ω ·o 𝐷) +o 𝑁))
3325, 31, 32syl2anc 595 . . . 4 (𝜑 → (ω ·o 𝐷) ⊆ ((ω ·o 𝐷) +o 𝑁))
3423, 33sstrd 3948 . . 3 (𝜑 → (ω ·o suc 𝐶) ⊆ ((ω ·o 𝐷) +o 𝑁))
35 naddwordnex.b . . 3 (𝜑𝐵 = ((ω ·o 𝐷) +o 𝑁))
3634, 35sseqtrrd 3975 . 2 (𝜑 → (ω ·o suc 𝐶) ⊆ 𝐵)
3716, 36jca 520 1 (𝜑 → (𝐴 ∈ (ω ·o suc 𝐶) ∧ (ω ·o suc 𝐶) ⊆ 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 400  w3a 1103   = wceq 1570  wcel 2143  wss 3906  Oncon0 6362  suc csuc 6364  (class class class)co 7412  ωcom 7863   +o coa 8451   ·o comu 8452
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-10 2176  ax-11 2192  ax-12 2213  ax-ext 2735  ax-rep 5239  ax-sep 5258  ax-nul 5270  ax-pr 5406  ax-un 7734  ax-inf2 9611
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1810  df-nf 1814  df-sb 2097  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2838  df-nfc 2912  df-ne 2959  df-ral 3080  df-rex 3090  df-reu 3370  df-rab 3417  df-v 3457  df-sbc 3746  df-csb 3855  df-dif 3909  df-un 3911  df-in 3913  df-ss 3923  df-pss 3926  df-nul 4288  df-if 4489  df-pw 4565  df-sn 4591  df-pr 4593  df-op 4597  df-uni 4874  df-iun 4959  df-br 5111  df-opab 5175  df-mpt 5194  df-tr 5220  df-id 5558  df-eprel 5563  df-po 5571  df-so 5572  df-fr 5616  df-we 5618  df-xp 5669  df-rel 5670  df-cnv 5671  df-co 5672  df-dm 5673  df-rn 5674  df-res 5675  df-ima 5676  df-pred 6304  df-ord 6365  df-on 6366  df-lim 6367  df-suc 6368  df-iota 6494  df-fun 6540  df-fn 6541  df-f 6542  df-f1 6543  df-fo 6544  df-f1o 6545  df-fv 6546  df-ov 7415  df-oprab 7416  df-mpo 7417  df-om 7864  df-2nd 7988  df-frecs 8279  df-wrecs 8310  df-recs 8359  df-rdg 8398  df-oadd 8458  df-omul 8459
This theorem is referenced by:  naddwordnexlem1  44104  naddwordnexlem2  44105  naddwordnexlem3  44106
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