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| Mirrors > Home > MPE Home > Th. List > dfttrcl2 | Structured version Visualization version GIF version | ||
| Description: When 𝑅 is a set and a relation, then its transitive closure can be defined by an intersection. (Contributed by Scott Fenton, 26-Oct-2024.) |
| Ref | Expression |
|---|---|
| dfttrcl2 | ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ssintab 4924 | . . . 4 ⊢ (t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ↔ ∀𝑧((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) → t++𝑅 ⊆ 𝑧)) | |
| 2 | ttrclss 9724 | . . . 4 ⊢ ((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) → t++𝑅 ⊆ 𝑧) | |
| 3 | 1, 2 | mpgbir 1831 | . . 3 ⊢ t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} |
| 4 | 3 | a1i 11 | . 2 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| 5 | rabab 3480 | . . . 4 ⊢ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} = {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} | |
| 6 | 5 | inteqi 4910 | . . 3 ⊢ ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} |
| 7 | ttrclexg 9727 | . . . 4 ⊢ (𝑅 ∈ 𝑉 → t++𝑅 ∈ V) | |
| 8 | ssttrcl 9719 | . . . . 5 ⊢ (Rel 𝑅 → 𝑅 ⊆ t++𝑅) | |
| 9 | ttrcltr 9720 | . . . . 5 ⊢ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅 | |
| 10 | 8, 9 | jctir 530 | . . . 4 ⊢ (Rel 𝑅 → (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) |
| 11 | sseq2 3934 | . . . . . 6 ⊢ (𝑧 = t++𝑅 → (𝑅 ⊆ 𝑧 ↔ 𝑅 ⊆ t++𝑅)) | |
| 12 | coeq1 5834 | . . . . . . . 8 ⊢ (𝑧 = t++𝑅 → (𝑧 ∘ 𝑧) = (t++𝑅 ∘ 𝑧)) | |
| 13 | coeq2 5835 | . . . . . . . 8 ⊢ (𝑧 = t++𝑅 → (t++𝑅 ∘ 𝑧) = (t++𝑅 ∘ t++𝑅)) | |
| 14 | 12, 13 | eqtrd 2795 | . . . . . . 7 ⊢ (𝑧 = t++𝑅 → (𝑧 ∘ 𝑧) = (t++𝑅 ∘ t++𝑅)) |
| 15 | id 23 | . . . . . . 7 ⊢ (𝑧 = t++𝑅 → 𝑧 = t++𝑅) | |
| 16 | 14, 15 | sseq12d 3941 | . . . . . 6 ⊢ (𝑧 = t++𝑅 → ((𝑧 ∘ 𝑧) ⊆ 𝑧 ↔ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) |
| 17 | 11, 16 | anbi12d 644 | . . . . 5 ⊢ (𝑧 = t++𝑅 → ((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) ↔ (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅))) |
| 18 | 17 | intminss 4933 | . . . 4 ⊢ ((t++𝑅 ∈ V ∧ (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) → ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 19 | 7, 10, 18 | syl2an 608 | . . 3 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 20 | 6, 19 | eqsstrrid 3947 | . 2 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 21 | 4, 20 | eqssd 3925 | 1 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 401 = wceq 1569 ∈ wcel 2144 {cab 2738 {crab 3412 Vcvv 3450 ⊆ wss 3895 ∩ cint 4906 ∘ ccom 5654 Rel wrel 5655 t++cttrcl 9711 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1827 ax-4 1841 ax-5 1942 ax-6 1999 ax-7 2040 ax-8 2146 ax-9 2154 ax-10 2177 ax-11 2193 ax-12 2212 ax-ext 2732 ax-rep 5231 ax-sep 5248 ax-nul 5259 ax-pow 5326 ax-pr 5390 ax-un 7751 |
| This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3or 1104 df-3an 1105 df-tru 1572 df-fal 1582 df-ex 1812 df-nf 1816 df-sb 2099 df-mo 2564 df-eu 2594 df-clab 2739 df-cleq 2752 df-clel 2835 df-nfc 2909 df-ne 2956 df-ral 3077 df-rex 3087 df-rmo 3365 df-reu 3366 df-rab 3413 df-v 3452 df-sbc 3739 df-csb 3847 df-ss 3896 df-pss 4014 df-dif 4047 df-in 4091 df-un 4151 df-nul 4279 df-if 4482 df-pw 4558 df-sn 4585 df-pr 4587 df-op 4835 df-uni 4867 df-int 4907 df-iun 4952 df-br 5103 df-opab 5167 df-mpt 5186 df-tr 5212 df-id 5545 df-eprel 5550 df-po 5558 df-so 5559 df-fr 5603 df-we 5605 df-xp 5656 df-rel 5657 df-cnv 5658 df-co 5659 df-dm 5660 df-rn 5661 df-res 5662 df-ima 5663 df-pred 6304 df-ord 6365 df-on 6366 df-lim 6367 df-suc 6368 df-iota 6494 df-fun 6540 df-fn 6541 df-f 6542 df-f1 6543 df-fo 6544 df-f1o 6545 df-fv 6546 df-riota 7377 df-ov 7423 df-oprab 7424 df-mpo 7425 df-om 7878 df-2nd 8002 df-frecs 8302 df-wrecs 8333 df-recs 8382 df-rdg 8421 df-1o 8479 df-oadd 8483 df-ttrcl 9712 |
| This theorem is used by: (None) |
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