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| Mirrors > Home > MPE Home > Th. List > dfttrcl2 | Structured version Visualization version GIF version | ||
| Description: When 𝑅 is a set and a relation, then its transitive closure can be defined by an intersection. (Contributed by Scott Fenton, 26-Oct-2024.) |
| Ref | Expression |
|---|---|
| dfttrcl2 | ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ssintab 4928 | . . . 4 ⊢ (t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ↔ ∀𝑧((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) → t++𝑅 ⊆ 𝑧)) | |
| 2 | ttrclss 9748 | . . . 4 ⊢ ((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) → t++𝑅 ⊆ 𝑧) | |
| 3 | 1, 2 | mpgbir 1832 | . . 3 ⊢ t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} |
| 4 | 3 | a1i 11 | . 2 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| 5 | rabab 3484 | . . . 4 ⊢ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} = {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} | |
| 6 | 5 | inteqi 4914 | . . 3 ⊢ ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} |
| 7 | ttrclexg 9751 | . . . 4 ⊢ (𝑅 ∈ 𝑉 → t++𝑅 ∈ V) | |
| 8 | ssttrcl 9743 | . . . . 5 ⊢ (Rel 𝑅 → 𝑅 ⊆ t++𝑅) | |
| 9 | ttrcltr 9744 | . . . . 5 ⊢ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅 | |
| 10 | 8, 9 | jctir 530 | . . . 4 ⊢ (Rel 𝑅 → (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) |
| 11 | sseq2 3939 | . . . . . 6 ⊢ (𝑧 = t++𝑅 → (𝑅 ⊆ 𝑧 ↔ 𝑅 ⊆ t++𝑅)) | |
| 12 | coeq1 5841 | . . . . . . . 8 ⊢ (𝑧 = t++𝑅 → (𝑧 ∘ 𝑧) = (t++𝑅 ∘ 𝑧)) | |
| 13 | coeq2 5842 | . . . . . . . 8 ⊢ (𝑧 = t++𝑅 → (t++𝑅 ∘ 𝑧) = (t++𝑅 ∘ t++𝑅)) | |
| 14 | 12, 13 | eqtrd 2798 | . . . . . . 7 ⊢ (𝑧 = t++𝑅 → (𝑧 ∘ 𝑧) = (t++𝑅 ∘ t++𝑅)) |
| 15 | id 23 | . . . . . . 7 ⊢ (𝑧 = t++𝑅 → 𝑧 = t++𝑅) | |
| 16 | 14, 15 | sseq12d 3946 | . . . . . 6 ⊢ (𝑧 = t++𝑅 → ((𝑧 ∘ 𝑧) ⊆ 𝑧 ↔ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) |
| 17 | 11, 16 | anbi12d 644 | . . . . 5 ⊢ (𝑧 = t++𝑅 → ((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) ↔ (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅))) |
| 18 | 17 | intminss 4937 | . . . 4 ⊢ ((t++𝑅 ∈ V ∧ (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) → ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 19 | 7, 10, 18 | syl2an 608 | . . 3 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 20 | 6, 19 | eqsstrrid 3952 | . 2 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 21 | 4, 20 | eqssd 3930 | 1 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 401 = wceq 1570 ∈ wcel 2147 {cab 2741 {crab 3416 Vcvv 3454 ⊆ wss 3900 ∩ cint 4910 ∘ ccom 5659 Rel wrel 5660 t++cttrcl 9735 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1945 ax-6 2002 ax-7 2043 ax-8 2149 ax-9 2157 ax-10 2180 ax-11 2197 ax-12 2216 ax-ext 2735 ax-rep 5235 ax-sep 5252 ax-nul 5263 ax-pow 5331 ax-pr 5395 ax-un 7775 |
| This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3or 1104 df-3an 1105 df-tru 1573 df-fal 1583 df-ex 1813 df-nf 1817 df-sb 2102 df-mo 2567 df-eu 2597 df-clab 2742 df-cleq 2755 df-clel 2839 df-nfc 2913 df-ne 2960 df-ral 3081 df-rex 3091 df-rmo 3369 df-reu 3370 df-rab 3417 df-v 3456 df-sbc 3743 df-csb 3852 df-ss 3901 df-pss 4017 df-dif 4050 df-in 4094 df-un 4154 df-nul 4282 df-if 4486 df-pw 4562 df-sn 4589 df-pr 4591 df-op 4839 df-uni 4871 df-int 4911 df-iun 4956 df-br 5107 df-opab 5171 df-mpt 5190 df-tr 5216 df-id 5550 df-eprel 5555 df-po 5563 df-so 5564 df-fr 5608 df-we 5610 df-xp 5661 df-rel 5662 df-cnv 5663 df-co 5664 df-dm 5665 df-rn 5666 df-res 5667 df-ima 5668 df-pred 6322 df-ord 6383 df-on 6384 df-lim 6385 df-suc 6386 df-iota 6512 df-fun 6560 df-fn 6561 df-f 6562 df-f1 6563 df-fo 6564 df-f1o 6565 df-fv 6566 df-riota 7400 df-ov 7446 df-oprab 7447 df-mpo 7448 df-om 7902 df-2nd 8026 df-frecs 8327 df-wrecs 8358 df-recs 8407 df-rdg 8446 df-1o 8504 df-oadd 8508 df-ttrcl 9736 |
| This theorem is used by: (None) |
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