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| Mirrors > Home > MPE Home > Th. List > dfttrcl2 | Structured version Visualization version GIF version | ||
| Description: When 𝑅 is a set and a relation, then its transitive closure can be defined by an intersection. (Contributed by Scott Fenton, 26-Oct-2024.) |
| Ref | Expression |
|---|---|
| dfttrcl2 | ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ssintab 4928 | . . . 4 ⊢ (t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ↔ ∀𝑧((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) → t++𝑅 ⊆ 𝑧)) | |
| 2 | ttrclss 9703 | . . . 4 ⊢ ((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) → t++𝑅 ⊆ 𝑧) | |
| 3 | 1, 2 | mpgbir 1832 | . . 3 ⊢ t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} |
| 4 | 3 | a1i 11 | . 2 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| 5 | rabab 3483 | . . . 4 ⊢ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} = {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} | |
| 6 | 5 | inteqi 4914 | . . 3 ⊢ ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} |
| 7 | ttrclexg 9706 | . . . 4 ⊢ (𝑅 ∈ 𝑉 → t++𝑅 ∈ V) | |
| 8 | ssttrcl 9698 | . . . . 5 ⊢ (Rel 𝑅 → 𝑅 ⊆ t++𝑅) | |
| 9 | ttrcltr 9699 | . . . . 5 ⊢ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅 | |
| 10 | 8, 9 | jctir 530 | . . . 4 ⊢ (Rel 𝑅 → (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) |
| 11 | sseq2 3960 | . . . . . 6 ⊢ (𝑧 = t++𝑅 → (𝑅 ⊆ 𝑧 ↔ 𝑅 ⊆ t++𝑅)) | |
| 12 | coeq1 5841 | . . . . . . . 8 ⊢ (𝑧 = t++𝑅 → (𝑧 ∘ 𝑧) = (t++𝑅 ∘ 𝑧)) | |
| 13 | coeq2 5842 | . . . . . . . 8 ⊢ (𝑧 = t++𝑅 → (t++𝑅 ∘ 𝑧) = (t++𝑅 ∘ t++𝑅)) | |
| 14 | 12, 13 | eqtrd 2797 | . . . . . . 7 ⊢ (𝑧 = t++𝑅 → (𝑧 ∘ 𝑧) = (t++𝑅 ∘ t++𝑅)) |
| 15 | id 23 | . . . . . . 7 ⊢ (𝑧 = t++𝑅 → 𝑧 = t++𝑅) | |
| 16 | 14, 15 | sseq12d 3967 | . . . . . 6 ⊢ (𝑧 = t++𝑅 → ((𝑧 ∘ 𝑧) ⊆ 𝑧 ↔ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) |
| 17 | 11, 16 | anbi12d 644 | . . . . 5 ⊢ (𝑧 = t++𝑅 → ((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) ↔ (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅))) |
| 18 | 17 | intminss 4937 | . . . 4 ⊢ ((t++𝑅 ∈ V ∧ (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) → ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 19 | 7, 10, 18 | syl2an 608 | . . 3 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 20 | 6, 19 | eqsstrrid 3973 | . 2 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 21 | 4, 20 | eqssd 3951 | 1 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 401 = wceq 1570 ∈ wcel 2145 {cab 2740 {crab 3414 Vcvv 3453 ⊆ wss 3902 ∩ cint 4910 ∘ ccom 5663 Rel wrel 5664 t++cttrcl 9690 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-8 2147 ax-9 2155 ax-10 2178 ax-11 2194 ax-12 2215 ax-ext 2734 ax-rep 5236 ax-sep 5255 ax-nul 5267 ax-pow 5334 ax-pr 5402 ax-un 7740 |
| This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3or 1104 df-3an 1105 df-tru 1573 df-fal 1583 df-ex 1813 df-nf 1817 df-sb 2100 df-mo 2566 df-eu 2596 df-clab 2741 df-cleq 2754 df-clel 2837 df-nfc 2911 df-ne 2958 df-ral 3079 df-rex 3089 df-rmo 3367 df-reu 3368 df-rab 3415 df-v 3455 df-sbc 3743 df-csb 3851 df-dif 3905 df-un 3907 df-in 3909 df-ss 3919 df-pss 3922 df-nul 4283 df-if 4486 df-pw 4562 df-sn 4588 df-pr 4590 df-op 4594 df-uni 4871 df-int 4911 df-iun 4956 df-br 5108 df-opab 5172 df-mpt 5191 df-tr 5217 df-id 5554 df-eprel 5559 df-po 5567 df-so 5568 df-fr 5612 df-we 5614 df-xp 5665 df-rel 5666 df-cnv 5667 df-co 5668 df-dm 5669 df-rn 5670 df-res 5671 df-ima 5672 df-pred 6303 df-ord 6364 df-on 6365 df-lim 6366 df-suc 6367 df-iota 6493 df-fun 6539 df-fn 6540 df-f 6541 df-f1 6542 df-fo 6543 df-f1o 6544 df-fv 6545 df-riota 7374 df-ov 7420 df-oprab 7421 df-mpo 7422 df-om 7867 df-2nd 7991 df-frecs 8284 df-wrecs 8315 df-recs 8364 df-rdg 8403 df-1o 8459 df-oadd 8463 df-ttrcl 9691 |
| This theorem is used by: (None) |
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