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| Mirrors > Home > MPE Home > Th. List > dfttrcl2 | Structured version Visualization version GIF version | ||
| Description: When 𝑅 is a set and a relation, then its transitive closure can be defined by an intersection. (Contributed by Scott Fenton, 26-Oct-2024.) |
| Ref | Expression |
|---|---|
| dfttrcl2 | ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ssintab 4935 | . . . 4 ⊢ (t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ↔ ∀𝑧((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) → t++𝑅 ⊆ 𝑧)) | |
| 2 | ttrclss 9699 | . . . 4 ⊢ ((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) → t++𝑅 ⊆ 𝑧) | |
| 3 | 1, 2 | mpgbir 1832 | . . 3 ⊢ t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} |
| 4 | 3 | a1i 11 | . 2 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 ⊆ ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| 5 | rabab 3488 | . . . 4 ⊢ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} = {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} | |
| 6 | 5 | inteqi 4921 | . . 3 ⊢ ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} |
| 7 | ttrclexg 9702 | . . . 4 ⊢ (𝑅 ∈ 𝑉 → t++𝑅 ∈ V) | |
| 8 | ssttrcl 9694 | . . . . 5 ⊢ (Rel 𝑅 → 𝑅 ⊆ t++𝑅) | |
| 9 | ttrcltr 9695 | . . . . 5 ⊢ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅 | |
| 10 | 8, 9 | jctir 530 | . . . 4 ⊢ (Rel 𝑅 → (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) |
| 11 | sseq2 3966 | . . . . . 6 ⊢ (𝑧 = t++𝑅 → (𝑅 ⊆ 𝑧 ↔ 𝑅 ⊆ t++𝑅)) | |
| 12 | coeq1 5848 | . . . . . . . 8 ⊢ (𝑧 = t++𝑅 → (𝑧 ∘ 𝑧) = (t++𝑅 ∘ 𝑧)) | |
| 13 | coeq2 5849 | . . . . . . . 8 ⊢ (𝑧 = t++𝑅 → (t++𝑅 ∘ 𝑧) = (t++𝑅 ∘ t++𝑅)) | |
| 14 | 12, 13 | eqtrd 2801 | . . . . . . 7 ⊢ (𝑧 = t++𝑅 → (𝑧 ∘ 𝑧) = (t++𝑅 ∘ t++𝑅)) |
| 15 | id 23 | . . . . . . 7 ⊢ (𝑧 = t++𝑅 → 𝑧 = t++𝑅) | |
| 16 | 14, 15 | sseq12d 3973 | . . . . . 6 ⊢ (𝑧 = t++𝑅 → ((𝑧 ∘ 𝑧) ⊆ 𝑧 ↔ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) |
| 17 | 11, 16 | anbi12d 644 | . . . . 5 ⊢ (𝑧 = t++𝑅 → ((𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧) ↔ (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅))) |
| 18 | 17 | intminss 4944 | . . . 4 ⊢ ((t++𝑅 ∈ V ∧ (𝑅 ⊆ t++𝑅 ∧ (t++𝑅 ∘ t++𝑅) ⊆ t++𝑅)) → ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 19 | 7, 10, 18 | syl2an 608 | . . 3 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → ∩ {𝑧 ∈ V ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 20 | 6, 19 | eqsstrrid 3979 | . 2 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)} ⊆ t++𝑅) |
| 21 | 4, 20 | eqssd 3957 | 1 ⊢ ((𝑅 ∈ 𝑉 ∧ Rel 𝑅) → t++𝑅 = ∩ {𝑧 ∣ (𝑅 ⊆ 𝑧 ∧ (𝑧 ∘ 𝑧) ⊆ 𝑧)}) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 401 = wceq 1570 ∈ wcel 2146 {cab 2744 {crab 3419 Vcvv 3458 ⊆ wss 3908 ∩ cint 4917 ∘ ccom 5670 Rel wrel 5671 t++cttrcl 9686 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-8 2148 ax-9 2156 ax-10 2179 ax-11 2195 ax-12 2216 ax-ext 2738 ax-rep 5243 ax-sep 5262 ax-nul 5274 ax-pow 5341 ax-pr 5409 ax-un 7745 |
| This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3or 1104 df-3an 1105 df-tru 1573 df-fal 1583 df-ex 1813 df-nf 1817 df-sb 2100 df-mo 2570 df-eu 2600 df-clab 2745 df-cleq 2758 df-clel 2841 df-nfc 2915 df-ne 2962 df-ral 3083 df-rex 3093 df-rmo 3372 df-reu 3373 df-rab 3420 df-v 3460 df-sbc 3748 df-csb 3857 df-dif 3911 df-un 3913 df-in 3915 df-ss 3925 df-pss 3928 df-nul 4290 df-if 4493 df-pw 4569 df-sn 4595 df-pr 4597 df-op 4601 df-uni 4878 df-int 4918 df-iun 4963 df-br 5115 df-opab 5179 df-mpt 5198 df-tr 5224 df-id 5561 df-eprel 5566 df-po 5574 df-so 5575 df-fr 5619 df-we 5621 df-xp 5672 df-rel 5673 df-cnv 5674 df-co 5675 df-dm 5676 df-rn 5677 df-res 5678 df-ima 5679 df-pred 6309 df-ord 6370 df-on 6371 df-lim 6372 df-suc 6373 df-iota 6499 df-fun 6545 df-fn 6546 df-f 6547 df-f1 6548 df-fo 6549 df-f1o 6550 df-fv 6551 df-riota 7380 df-ov 7426 df-oprab 7427 df-mpo 7428 df-om 7872 df-2nd 7996 df-frecs 8287 df-wrecs 8318 df-recs 8367 df-rdg 8406 df-1o 8462 df-oadd 8466 df-ttrcl 9687 |
| This theorem is used by: (None) |
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