| Step | Hyp | Ref
| Expression |
| 1 | | depind.p |
. . 3
⊢ (𝜑 → 𝑃:ℕ0⟶V) |
| 2 | | depind.0 |
. . 3
⊢ (𝜑 → 𝐴 ∈ (𝑃‘0)) |
| 3 | | depind.h |
. . 3
⊢ (𝜑 → ∀𝑛 ∈ ℕ0 (𝐻‘𝑛):(𝑃‘𝑛)⟶(𝑃‘(𝑛 + 1))) |
| 4 | | eqid 2231 |
. . 3
⊢
seq0((𝑥 ∈ V,
ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) |
| 5 | 1, 2, 3, 4 | depindlem2 16347 |
. 2
⊢ (𝜑 → seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) ∈ X𝑛 ∈
ℕ0 (𝑃‘𝑛)) |
| 6 | 1, 2, 3, 4 | depindlem1 16346 |
. . 3
⊢ (𝜑 → (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))):ℕ0⟶V
∧ (seq0((𝑥 ∈ V,
ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘0) = 𝐴 ∧ ∀𝑛 ∈ ℕ0 (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘𝑛)))) |
| 7 | 6 | simp2d 1036 |
. 2
⊢ (𝜑 → (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘0) = 𝐴) |
| 8 | 6 | simp3d 1037 |
. 2
⊢ (𝜑 → ∀𝑛 ∈ ℕ0 (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘𝑛))) |
| 9 | 1, 2, 3, 4 | depindlem3 16348 |
. 2
⊢ (𝜑 → ∀𝑓 ∈ X 𝑛 ∈ ℕ0
(𝑃‘𝑛)(((𝑓‘0) = 𝐴 ∧ ∀𝑛 ∈ ℕ0 (𝑓‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(𝑓‘𝑛))) → 𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))))) |
| 10 | | fveq1 5638 |
. . . . 5
⊢ (𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) → (𝑓‘0) = (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘0)) |
| 11 | 10 | eqeq1d 2240 |
. . . 4
⊢ (𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) → ((𝑓‘0) = 𝐴 ↔ (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘0) = 𝐴)) |
| 12 | | fveq1 5638 |
. . . . . 6
⊢ (𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) → (𝑓‘(𝑛 + 1)) = (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘(𝑛 + 1))) |
| 13 | | fveq1 5638 |
. . . . . . 7
⊢ (𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) → (𝑓‘𝑛) = (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘𝑛)) |
| 14 | 13 | fveq2d 5643 |
. . . . . 6
⊢ (𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) → ((𝐻‘𝑛)‘(𝑓‘𝑛)) = ((𝐻‘𝑛)‘(seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘𝑛))) |
| 15 | 12, 14 | eqeq12d 2246 |
. . . . 5
⊢ (𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) → ((𝑓‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(𝑓‘𝑛)) ↔ (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘𝑛)))) |
| 16 | 15 | ralbidv 2532 |
. . . 4
⊢ (𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) → (∀𝑛 ∈ ℕ0
(𝑓‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(𝑓‘𝑛)) ↔ ∀𝑛 ∈ ℕ0 (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘𝑛)))) |
| 17 | 11, 16 | anbi12d 473 |
. . 3
⊢ (𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) → (((𝑓‘0) = 𝐴 ∧ ∀𝑛 ∈ ℕ0 (𝑓‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(𝑓‘𝑛))) ↔ ((seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘0) = 𝐴 ∧ ∀𝑛 ∈ ℕ0 (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘𝑛))))) |
| 18 | 17 | eqreu 2998 |
. 2
⊢
((seq0((𝑥 ∈ V,
ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))) ∈ X𝑛 ∈
ℕ0 (𝑃‘𝑛) ∧ ((seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘0) = 𝐴 ∧ ∀𝑛 ∈ ℕ0 (seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1)))))‘𝑛))) ∧ ∀𝑓 ∈ X 𝑛 ∈ ℕ0
(𝑃‘𝑛)(((𝑓‘0) = 𝐴 ∧ ∀𝑛 ∈ ℕ0 (𝑓‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(𝑓‘𝑛))) → 𝑓 = seq0((𝑥 ∈ V, ℎ ∈ V ↦ (ℎ‘𝑥)), (𝑚 ∈ ℕ0 ↦ if(𝑚 = 0, 𝐴, (𝐻‘(𝑚 − 1))))))) → ∃!𝑓 ∈ X
𝑛 ∈
ℕ0 (𝑃‘𝑛)((𝑓‘0) = 𝐴 ∧ ∀𝑛 ∈ ℕ0 (𝑓‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(𝑓‘𝑛)))) |
| 19 | 5, 7, 8, 9, 18 | syl121anc 1278 |
1
⊢ (𝜑 → ∃!𝑓 ∈ X 𝑛 ∈ ℕ0
(𝑃‘𝑛)((𝑓‘0) = 𝐴 ∧ ∀𝑛 ∈ ℕ0 (𝑓‘(𝑛 + 1)) = ((𝐻‘𝑛)‘(𝑓‘𝑛)))) |