Proof of Theorem halfaddsub
| Step | Hyp | Ref
| Expression |
| 1 | | ppncan 11530 |
. . . . . 6
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐴 ∈ ℂ) → ((𝐴 + 𝐵) + (𝐴 − 𝐵)) = (𝐴 + 𝐴)) |
| 2 | 1 | 3anidm13 1422 |
. . . . 5
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐴 + 𝐵) + (𝐴 − 𝐵)) = (𝐴 + 𝐴)) |
| 3 | | 2times 12381 |
. . . . . 6
⊢ (𝐴 ∈ ℂ → (2
· 𝐴) = (𝐴 + 𝐴)) |
| 4 | 3 | adantr 480 |
. . . . 5
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (2
· 𝐴) = (𝐴 + 𝐴)) |
| 5 | 2, 4 | eqtr4d 2774 |
. . . 4
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐴 + 𝐵) + (𝐴 − 𝐵)) = (2 · 𝐴)) |
| 6 | 5 | oveq1d 7425 |
. . 3
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (((𝐴 + 𝐵) + (𝐴 − 𝐵)) / 2) = ((2 · 𝐴) / 2)) |
| 7 | | addcl 11216 |
. . . 4
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐴 + 𝐵) ∈ ℂ) |
| 8 | | subcl 11486 |
. . . 4
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (𝐴 − 𝐵) ∈ ℂ) |
| 9 | | 2cnne0 12455 |
. . . . 5
⊢ (2 ∈
ℂ ∧ 2 ≠ 0) |
| 10 | | divdir 11926 |
. . . . 5
⊢ (((𝐴 + 𝐵) ∈ ℂ ∧ (𝐴 − 𝐵) ∈ ℂ ∧ (2 ∈ ℂ
∧ 2 ≠ 0)) → (((𝐴 + 𝐵) + (𝐴 − 𝐵)) / 2) = (((𝐴 + 𝐵) / 2) + ((𝐴 − 𝐵) / 2))) |
| 11 | 9, 10 | mp3an3 1452 |
. . . 4
⊢ (((𝐴 + 𝐵) ∈ ℂ ∧ (𝐴 − 𝐵) ∈ ℂ) → (((𝐴 + 𝐵) + (𝐴 − 𝐵)) / 2) = (((𝐴 + 𝐵) / 2) + ((𝐴 − 𝐵) / 2))) |
| 12 | 7, 8, 11 | syl2anc 584 |
. . 3
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (((𝐴 + 𝐵) + (𝐴 − 𝐵)) / 2) = (((𝐴 + 𝐵) / 2) + ((𝐴 − 𝐵) / 2))) |
| 13 | | 2cn 12320 |
. . . . 5
⊢ 2 ∈
ℂ |
| 14 | | 2ne0 12349 |
. . . . 5
⊢ 2 ≠
0 |
| 15 | | divcan3 11927 |
. . . . 5
⊢ ((𝐴 ∈ ℂ ∧ 2 ∈
ℂ ∧ 2 ≠ 0) → ((2 · 𝐴) / 2) = 𝐴) |
| 16 | 13, 14, 15 | mp3an23 1455 |
. . . 4
⊢ (𝐴 ∈ ℂ → ((2
· 𝐴) / 2) = 𝐴) |
| 17 | 16 | adantr 480 |
. . 3
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((2
· 𝐴) / 2) = 𝐴) |
| 18 | 6, 12, 17 | 3eqtr3d 2779 |
. 2
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (((𝐴 + 𝐵) / 2) + ((𝐴 − 𝐵) / 2)) = 𝐴) |
| 19 | | pnncan 11529 |
. . . . . 6
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐴 + 𝐵) − (𝐴 − 𝐵)) = (𝐵 + 𝐵)) |
| 20 | 19 | 3anidm23 1423 |
. . . . 5
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐴 + 𝐵) − (𝐴 − 𝐵)) = (𝐵 + 𝐵)) |
| 21 | | 2times 12381 |
. . . . . 6
⊢ (𝐵 ∈ ℂ → (2
· 𝐵) = (𝐵 + 𝐵)) |
| 22 | 21 | adantl 481 |
. . . . 5
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (2
· 𝐵) = (𝐵 + 𝐵)) |
| 23 | 20, 22 | eqtr4d 2774 |
. . . 4
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((𝐴 + 𝐵) − (𝐴 − 𝐵)) = (2 · 𝐵)) |
| 24 | 23 | oveq1d 7425 |
. . 3
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (((𝐴 + 𝐵) − (𝐴 − 𝐵)) / 2) = ((2 · 𝐵) / 2)) |
| 25 | | divsubdir 11940 |
. . . . 5
⊢ (((𝐴 + 𝐵) ∈ ℂ ∧ (𝐴 − 𝐵) ∈ ℂ ∧ (2 ∈ ℂ
∧ 2 ≠ 0)) → (((𝐴 + 𝐵) − (𝐴 − 𝐵)) / 2) = (((𝐴 + 𝐵) / 2) − ((𝐴 − 𝐵) / 2))) |
| 26 | 9, 25 | mp3an3 1452 |
. . . 4
⊢ (((𝐴 + 𝐵) ∈ ℂ ∧ (𝐴 − 𝐵) ∈ ℂ) → (((𝐴 + 𝐵) − (𝐴 − 𝐵)) / 2) = (((𝐴 + 𝐵) / 2) − ((𝐴 − 𝐵) / 2))) |
| 27 | 7, 8, 26 | syl2anc 584 |
. . 3
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (((𝐴 + 𝐵) − (𝐴 − 𝐵)) / 2) = (((𝐴 + 𝐵) / 2) − ((𝐴 − 𝐵) / 2))) |
| 28 | | divcan3 11927 |
. . . . 5
⊢ ((𝐵 ∈ ℂ ∧ 2 ∈
ℂ ∧ 2 ≠ 0) → ((2 · 𝐵) / 2) = 𝐵) |
| 29 | 13, 14, 28 | mp3an23 1455 |
. . . 4
⊢ (𝐵 ∈ ℂ → ((2
· 𝐵) / 2) = 𝐵) |
| 30 | 29 | adantl 481 |
. . 3
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((2
· 𝐵) / 2) = 𝐵) |
| 31 | 24, 27, 30 | 3eqtr3d 2779 |
. 2
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → (((𝐴 + 𝐵) / 2) − ((𝐴 − 𝐵) / 2)) = 𝐵) |
| 32 | 18, 31 | jca 511 |
1
⊢ ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) →
((((𝐴 + 𝐵) / 2) + ((𝐴 − 𝐵) / 2)) = 𝐴 ∧ (((𝐴 + 𝐵) / 2) − ((𝐴 − 𝐵) / 2)) = 𝐵)) |