Theorem sdc 38787

Description: Strong dependent choice. Suppose we may choose an element of 𝐴 such that property 𝜓 holds, and suppose that if we have already chosen the first 𝑘 elements (represented here by a function from 1...𝑘 to 𝐴), we may choose another element so that all 𝑘 + 1 elements taken together have property 𝜓. Then there exists an infinite sequence of elements of 𝐴 such that the first 𝑛 terms of this sequence satisfy 𝜓 for all 𝑛. This theorem allows to construct infinite sequences where each term depends on all the previous terms in the sequence. (Contributed by Jeff Madsen, 2-Sep-2009.) (Proof shortened by Mario Carneiro, 3-Jun-2014.)

Hypotheses

Ref	Expression
sdc.1	⊢ 𝑍 = (ℤ≥‘𝑀)
sdc.2	⊢ (𝑔 = (𝑓 ↾ (𝑀...𝑛)) → (𝜓 ↔ 𝜒))
sdc.3	⊢ (𝑛 = 𝑀 → (𝜓 ↔ 𝜏))
sdc.4	⊢ (𝑛 = 𝑘 → (𝜓 ↔ 𝜃))
sdc.5	⊢ ((𝑔 = ℎ ∧ 𝑛 = (𝑘 + 1)) → (𝜓 ↔ 𝜎))
sdc.6	⊢ (𝜑 → 𝐴 ∈ 𝑉)
sdc.7	⊢ (𝜑 → 𝑀 ∈ ℤ)
sdc.8	⊢ (𝜑 → ∃𝑔(𝑔:{𝑀}⟶𝐴 ∧ 𝜏))
sdc.9	⊢ ((𝜑 ∧ 𝑘 ∈ 𝑍) → ((𝑔:(𝑀...𝑘)⟶𝐴 ∧ 𝜃) → ∃ℎ(ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑔 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)))

Assertion

Ref	Expression
sdc	⊢ (𝜑 → ∃𝑓(𝑓:𝑍⟶𝐴 ∧ ∀𝑛 ∈ 𝑍 𝜒))

Distinct variable groups:   𝑓,𝑔,ℎ,𝑘,𝑛,𝐴   𝑓,𝑀,𝑔,ℎ,𝑘,𝑛   𝜒,𝑔   𝜓,𝑓,ℎ,𝑘   𝜎,𝑓,𝑔,𝑛   𝜑,𝑛   𝜃,𝑛   ℎ,𝑉   𝜏,ℎ,𝑘,𝑛   𝑓,𝑍,𝑔,ℎ,𝑘,𝑛   𝜑,𝑔,ℎ,𝑘

Allowed substitution hints:   𝜑(𝑓)   𝜓(𝑔, 𝑛)   𝜒(𝑓, ℎ, 𝑘, 𝑛)   𝜃(𝑓, 𝑔, ℎ, 𝑘)   𝜏(𝑓, 𝑔)   𝜎(ℎ, 𝑘)   𝑉(𝑓, 𝑔, 𝑘, 𝑛)

Proof of Theorem sdc

Dummy variables 𝑗 𝑥 𝑦 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		sdc.1	. 2 ⊢ 𝑍 = (ℤ≥‘𝑀)
2		sdc.2	. 2 ⊢ (𝑔 = (𝑓 ↾ (𝑀...𝑛)) → (𝜓 ↔ 𝜒))
3		sdc.3	. 2 ⊢ (𝑛 = 𝑀 → (𝜓 ↔ 𝜏))
4		sdc.4	. 2 ⊢ (𝑛 = 𝑘 → (𝜓 ↔ 𝜃))
5		sdc.5	. 2 ⊢ ((𝑔 = ℎ ∧ 𝑛 = (𝑘 + 1)) → (𝜓 ↔ 𝜎))
6		sdc.6	. 2 ⊢ (𝜑 → 𝐴 ∈ 𝑉)
7		sdc.7	. 2 ⊢ (𝜑 → 𝑀 ∈ ℤ)
8		sdc.8	. 2 ⊢ (𝜑 → ∃𝑔(𝑔:{𝑀}⟶𝐴 ∧ 𝜏))
9		sdc.9	. 2 ⊢ ((𝜑 ∧ 𝑘 ∈ 𝑍) → ((𝑔:(𝑀...𝑘)⟶𝐴 ∧ 𝜃) → ∃ℎ(ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑔 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)))
10		eqid 2760	. 2 ⊢ {𝑔 ∣ ∃𝑛 ∈ 𝑍 (𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓)} = {𝑔 ∣ ∃𝑛 ∈ 𝑍 (𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓)}
11		eqid 2760	. . . 4 ⊢ 𝑍 = 𝑍
12		oveq2 7432	. . . . . . . 8 ⊢ (𝑛 = 𝑘 → (𝑀...𝑛) = (𝑀...𝑘))
13	12	feq2d 6698	. . . . . . 7 ⊢ (𝑛 = 𝑘 → (𝑔:(𝑀...𝑛)⟶𝐴 ↔ 𝑔:(𝑀...𝑘)⟶𝐴))
14	13, 4	anbi12d 644	. . . . . 6 ⊢ (𝑛 = 𝑘 → ((𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓) ↔ (𝑔:(𝑀...𝑘)⟶𝐴 ∧ 𝜃)))
15	14	cbvrexvw 3241	. . . . 5 ⊢ (∃𝑛 ∈ 𝑍 (𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓) ↔ ∃𝑘 ∈ 𝑍 (𝑔:(𝑀...𝑘)⟶𝐴 ∧ 𝜃))
16	15	abbii 2827	. . . 4 ⊢ {𝑔 ∣ ∃𝑛 ∈ 𝑍 (𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓)} = {𝑔 ∣ ∃𝑘 ∈ 𝑍 (𝑔:(𝑀...𝑘)⟶𝐴 ∧ 𝜃)}
17		eqid 2760	. . . 4 ⊢ {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)} = {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)}
18	11, 16, 17	mpoeq123i 7500	. . 3 ⊢ (𝑗 ∈ 𝑍, 𝑓 ∈ {𝑔 ∣ ∃𝑛 ∈ 𝑍 (𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓)} ↦ {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)}) = (𝑗 ∈ 𝑍, 𝑓 ∈ {𝑔 ∣ ∃𝑘 ∈ 𝑍 (𝑔:(𝑀...𝑘)⟶𝐴 ∧ 𝜃)} ↦ {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)})
19		eqidd 2761	. . . 4 ⊢ (𝑗 = 𝑦 → {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)} = {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)})
20		eqeq1 2764	. . . . . . 7 ⊢ (𝑓 = 𝑥 → (𝑓 = (ℎ ↾ (𝑀...𝑘)) ↔ 𝑥 = (ℎ ↾ (𝑀...𝑘))))
21	20	3anbi2d 1469	. . . . . 6 ⊢ (𝑓 = 𝑥 → ((ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎) ↔ (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑥 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)))
22	21	rexbidv 3186	. . . . 5 ⊢ (𝑓 = 𝑥 → (∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎) ↔ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑥 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)))
23	22	abbidv 2826	. . . 4 ⊢ (𝑓 = 𝑥 → {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)} = {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑥 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)})
24	19, 23	cbvmpov 7519	. . 3 ⊢ (𝑗 ∈ 𝑍, 𝑓 ∈ {𝑔 ∣ ∃𝑛 ∈ 𝑍 (𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓)} ↦ {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)}) = (𝑦 ∈ 𝑍, 𝑥 ∈ {𝑔 ∣ ∃𝑛 ∈ 𝑍 (𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓)} ↦ {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑥 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)})
25	18, 24	eqtr3i 2785	. 2 ⊢ (𝑗 ∈ 𝑍, 𝑓 ∈ {𝑔 ∣ ∃𝑘 ∈ 𝑍 (𝑔:(𝑀...𝑘)⟶𝐴 ∧ 𝜃)} ↦ {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑓 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)}) = (𝑦 ∈ 𝑍, 𝑥 ∈ {𝑔 ∣ ∃𝑛 ∈ 𝑍 (𝑔:(𝑀...𝑛)⟶𝐴 ∧ 𝜓)} ↦ {ℎ ∣ ∃𝑘 ∈ 𝑍 (ℎ:(𝑀...(𝑘 + 1))⟶𝐴 ∧ 𝑥 = (ℎ ↾ (𝑀...𝑘)) ∧ 𝜎)})
26	1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 25	sdclem1 38786	1 ⊢ (𝜑 → ∃𝑓(𝑓:𝑍⟶𝐴 ∧ ∀𝑛 ∈ 𝑍 𝜒))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   ∧ w3a 1103   = wceq 1569  ∃wex 1811   ∈ wcel 2144  {cab 2738  ∀wral 3076  ∃wrex 3086  {csn 4584   ↾ cres 5653  ⟶wf 6539  ‘cfv 6543  (class class class)co 7424   ∈ cmpo 7426  1c1 11208   + caddc 11210  ℤcz 12700  ℤ_≥cuz 12972  ...cfz 13646

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732  ax-rep 5231  ax-sep 5248  ax-nul 5259  ax-pow 5327  ax-pr 5391  ax-un 7755  ax-inf2 9649  ax-dc 10531  ax-cnex 11263  ax-resscn 11264  ax-1cn 11265  ax-icn 11266  ax-addcl 11267  ax-addrcl 11268  ax-mulcl 11269  ax-mulrcl 11270  ax-mulcom 11271  ax-addass 11272  ax-mulass 11273  ax-distr 11274  ax-i2m1 11275  ax-1ne0 11276  ax-1rid 11277  ax-rnegex 11278  ax-rrecex 11279  ax-cnre 11280  ax-pre-lttri 11281  ax-pre-lttrn 11282  ax-pre-ltadd 11283  ax-pre-mulgt0 11284

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2099  df-mo 2564  df-eu 2594  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ne 2956  df-nel 3062  df-ral 3077  df-rex 3087  df-reu 3366  df-rab 3413  df-v 3452  df-sbc 3739  df-csb 3848  df-ss 3897  df-pss 4013  df-dif 4046  df-in 4090  df-un 4150  df-nul 4278  df-if 4482  df-pw 4558  df-sn 4585  df-pr 4587  df-op 4835  df-uni 4867  df-iun 4952  df-br 5103  df-opab 5167  df-mpt 5186  df-tr 5212  df-id 5546  df-eprel 5551  df-po 5559  df-so 5560  df-fr 5604  df-we 5606  df-xp 5657  df-rel 5658  df-cnv 5659  df-co 5660  df-dm 5661  df-rn 5662  df-res 5663  df-ima 5664  df-pred 6307  df-ord 6368  df-on 6369  df-lim 6370  df-suc 6371  df-iota 6497  df-fun 6545  df-fn 6546  df-f 6547  df-f1 6548  df-fo 6549  df-f1o 6550  df-fv 6551  df-riota 7381  df-ov 7427  df-oprab 7428  df-mpo 7429  df-om 7882  df-1st 8005  df-2nd 8006  df-frecs 8306  df-wrecs 8337  df-recs 8386  df-rdg 8425  df-1o 8483  df-er 8724  df-map 8856  df-en 8981  df-dom 8982  df-sdom 8983  df-pnf 11352  df-mnf 11353  df-xr 11354  df-ltxr 11355  df-le 11356  df-sub 11550  df-neg 11551  df-nn 12343  df-n0 12614  df-z 12701  df-uz 12973  df-fz 13647

This theorem is used by: (None)