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Most recent proofs    These are the 100 (Unicode, GIF) or 1000 (Unicode, GIF) most recent proofs in the iset.mm database for the Intuitionistic Logic Explorer. The iset.mm database is maintained on GitHub with master (stable) and develop (development) versions. This page was created from the commit given on the MPE Most Recent Proofs page. The database from that commit is also available here: iset.mm.

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Last updated on 19-Oct-2026 at 7:11 AM ET.
Recent Additions to the Intuitionistic Logic Explorer
DateLabelDescription
Theorem
 
13-Oct-2026mapm 6974 Set exponentiation is inhabited if the base is inhabited. (Contributed by Jim Kingdon, 13-Oct-2026.)
((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐶 ∈ 𝐴) → ∃𝑥 𝑥 ∈ (𝐴 ↑𝑚 𝐵))
 
11-Oct-2026psrbagdceq 15169 Finite bags have decidable equality. (Contributed by Jim Kingdon, 11-Oct-2026.)
𝐷 = {𝑓 ∈ (ℕ0 ↑𝑚 𝐼) ∣ (◡𝑓 “ ℕ) ∈ Fin}    ⇒   ((𝐼 ∈ Fin ∧ 𝐴 ∈ 𝐷 ∧ 𝐵 ∈ 𝐷) → DECID 𝐴 = 𝐵)
 
9-Oct-2026ofovex 6311 Applying a function operation to two functions which are sets yields a set. (Contributed by Jim Kingdon, 9-Oct-2026.)
((𝐹 ∈ 𝑉 ∧ 𝐺 ∈ 𝑊) → (𝐹 ∘𝑓 𝑅𝐺) ∈ V)
 
8-Oct-2026idjufi 14270 A finite indexed disjoint union of finite sets is finite. (Contributed by Jim Kingdon, 8-Oct-2026.)
(𝜑 → 𝐴 ∈ Fin)    &   ((𝜑 ∧ 𝑗 ∈ 𝐴) → 𝐶 ∈ Fin)    ⇒   (𝜑 → ∪ 𝑗 ∈ 𝐴 ({𝑗} × 𝐶) ∈ Fin)
 
8-Oct-2026sn0disj 4127 A collection, each of whose elements is empty or a singleton of the index, is disjoint. (Contributed by Jim Kingdon, 8-Oct-2026.)
((𝜑 ∧ 𝑥 ∈ 𝐴) → (𝐵 = ∅ ∨ 𝐵 = {𝑥}))    ⇒   (𝜑 → Disj 𝑥 ∈ 𝐴 𝐵)
 
6-Oct-2026gsum2dfi 14274 Write a sum over a two-dimensional region as a double sum. (Contributed by Mario Carneiro, 28-Dec-2014.) (Revised by AV, 8-Jun-2019.) (Revised by Jim Kingdon, 6-Oct-2026.)
𝐵 = (Base‘𝐺)    &    0 = (0g‘𝐺)    &   (𝜑 → 𝐺 ∈ CMnd)    &   (𝜑 → 𝐴 ∈ Fin)    &   (𝜑 → Rel 𝐴)    &   (𝜑 → 𝐷 ∈ Fin)    &   (𝜑 → dom 𝐴 ⊆ 𝐷)    &   (𝜑 → dom 𝐴 ∈ Fin)    &   (𝜑 → 𝐹:𝐴⟶𝐵)    &   ((𝜑 ∧ 𝑗 ∈ 𝐷) → (𝐴 “ {𝑗}) ∈ Fin)    ⇒   (𝜑 → (𝐺 Σg 𝐹) = (𝐺 Σg (𝑗 ∈ 𝐷 ↦ (𝐺 Σg (𝑘 ∈ (𝐴 “ {𝑗}) ↦ (𝑗𝐹𝑘))))))
 
6-Oct-2026relresfin 7269 Restricting to a subset of a finite relation's domain gives a finite set. (Contributed by Jim Kingdon, 6-Oct-2026.)
(𝜑 → 𝐸 ∈ Fin)    &   (𝜑 → Rel 𝐸)    &   (𝜑 → dom 𝐸 ∈ Fin)    &   (𝜑 → 𝐵 ⊆ dom 𝐸)    &   (𝜑 → 𝐵 ∈ Fin)    ⇒   (𝜑 → (𝐸 ↾ 𝐵) ∈ Fin)
 
4-Oct-2026gsum2dfilem2 14273 Lemma for gsum2dfi 14274. (Contributed by Mario Carneiro, 28-Dec-2014.) (Revised by AV, 8-Jun-2019.) (Revised by Jim Kingdon, 4-Oct-2026.)
𝐵 = (Base‘𝐺)    &    0 = (0g‘𝐺)    &   (𝜑 → 𝐺 ∈ CMnd)    &   (𝜑 → 𝐴 ∈ Fin)    &   (𝜑 → Rel 𝐴)    &   (𝜑 → 𝐷 ∈ Fin)    &   (𝜑 → dom 𝐴 ⊆ 𝐷)    &   (𝜑 → dom 𝐴 ∈ Fin)    &   (𝜑 → 𝐹:𝐴⟶𝐵)    &   ((𝜑 ∧ 𝑗 ∈ 𝐷) → (𝐴 “ {𝑗}) ∈ Fin)    ⇒   (𝜑 → (𝐺 Σg 𝐹) = (𝐺 Σg (𝑗 ∈ dom 𝐴 ↦ (𝐺 Σg (𝑘 ∈ (𝐴 “ {𝑗}) ↦ (𝑗𝐹𝑘))))))
 
2-Oct-2026idjudju 17264 An indexed disjoint union over two sets equals the disjoint union of those two sets. This connects our notation for an indexed disjoint union, ∪ 𝑥 ∈ 𝐶({𝑥} × 𝐹) which uses df-iun 4014, with our notation for the disjoint union of two sets (df-dju 7385). (Contributed by Jim Kingdon, 2-Oct-2026.)
𝐹 = if(𝑥 = ∅, 𝐴, 𝐵)    ⇒   ∪ 𝑥 ∈ 2o ({𝑥} × 𝐹) = (𝐴 ⊔ 𝐵)
 
2-Oct-2026gsum2dfilem1 14272 Lemma 1 for gsum2dfi 14274. (Contributed by Mario Carneiro, 28-Dec-2014.) (Revised by AV, 8-Jun-2019.) (Revised by Jim Kingdon, 2-Oct-2026.)
𝐵 = (Base‘𝐺)    &    0 = (0g‘𝐺)    &   (𝜑 → 𝐺 ∈ CMnd)    &   (𝜑 → 𝐹:𝐴⟶𝐵)    &   ((𝜑 ∧ 𝑗 ∈ 𝐷) → (𝐴 “ {𝑗}) ∈ Fin)    ⇒   ((𝜑 ∧ 𝑗 ∈ 𝐷) → (𝐺 Σg (𝑘 ∈ (𝐴 “ {𝑗}) ↦ (𝑗𝐹𝑘))) ∈ 𝐵)
 
2-Oct-2026idjusnfi 14271 The image of a singleton through an indexed disjoint union, where it is of finite sets. (Contributed by Jim Kingdon, 2-Oct-2026.)
(𝜑 → 𝐴 ∈ 𝑉)    &   ((𝜑 ∧ 𝑗 ∈ 𝐴) → 𝐶 ∈ Fin)    &   𝑈 = ∪ 𝑗 ∈ 𝐴 ({𝑗} × 𝐶)    ⇒   ((𝜑 ∧ 𝐾 ∈ 𝐴) → (𝑈 “ {𝐾}) ∈ Fin)
 
24-Sep-2026gsumresfi 14264 Extend a finite group sum by padding outside with zeroes. (Contributed by Mario Carneiro, 15-Dec-2014.) (Revised by Mario Carneiro, 24-Apr-2016.) (Revised by AV, 3-Jun-2019.) (Revised by Jim Kingdon, 24-Sep-2026.)
𝐵 = (Base‘𝐺)    &    0 = (0g‘𝐺)    &   (𝜑 → 𝐺 ∈ CMnd)    &   (𝜑 → 𝐴 ∈ Fin)    &   (𝜑 → 𝐹:𝐴⟶𝐵)    &   (𝜑 → ∀𝑥 ∈ (𝐴 ∖ 𝑊)(𝐹‘𝑥) = 0 )    &   (𝜑 → 𝑊 ∈ Fin)    &   (𝜑 → 𝑊 ⊆ 𝐴)    ⇒   (𝜑 → (𝐺 Σg (𝐹 ↾ 𝑊)) = (𝐺 Σg 𝐹))
 
23-Sep-2026sineq0re 16088 A complex number whose sine is zero is real. (Contributed by NM, 17-Aug-2008.) (Revised by Mario Carneiro, 10-May-2014.) (Revised by Jim Kingdon, 23-Sep-2026.)
((𝐴 ∈ ℂ ∧ (sin‘𝐴) = 0) → 𝐴 ∈ ℝ)
 
18-Sep-2026rirrdisj 17303 The rational and irrational numbers are disjoint. Here irrational means apart from any rational number. (Contributed by Jim Kingdon, 18-Sep-2026.)
(ℚ ∩ {𝑥 ∈ ℝ ∣ ∀𝑞 ∈ ℚ 𝑥 # 𝑞}) = ∅
 
18-Sep-2026efnthr 16188 An equation involving an 𝑁-th power. The expression exp(2πi / 𝑁) is a way to write the primitive 𝑁-th root of unity with the smallest positive argument. We could write it as -1↑𝑐(2 / 𝑁) except that we only support positive real numbers as the base for ↑𝑐. The converse is presumably also provable but we do not have a proof yet. (Contributed by Mario Carneiro, 23-Apr-2015.) (Revised by Jim Kingdon, 18-Sep-2026.)
((𝐴 ∈ ℂ ∧ 𝑁 ∈ ℕ ∧ 𝐵 ∈ ℝ+) → (∃𝑛 ∈ (0...(𝑁 − 1))𝐴 = ((𝐵↑𝑐(1 / 𝑁)) · ((exp‘((i · (2 · π)) / 𝑁))↑𝑛)) → (𝐴↑𝑁) = 𝐵))
 
16-Sep-2026cntzm 14162 If the centralizer of a subset of a magma has an element, the magma is inhabited. (Contributed by Jim Kingdon, 16-Sep-2026.)
𝑍 = (Cntz‘𝑀)    ⇒   (𝑋 ∈ (𝑍‘𝑆) → ∃𝑤 𝑤 ∈ 𝑀)
 
16-Sep-2026ressmex 13479 If a structure restriction is inhabited, the structure is a set and so is the class it is restricted to. (Contributed by Jim Kingdon, 16-Sep-2026.)
𝑅 = (𝑊 ↾s 𝐴)    ⇒   (𝑋 ∈ 𝑅 → (𝑊 ∈ V ∧ 𝐴 ∈ V))
 
15-Sep-2026cntzex 14151 Set existence of the centralizer. (Contributed by Jim Kingdon, 15-Sep-2026.)
𝑍 = (Cntz‘𝑀)    ⇒   (𝑀 ∈ 𝑉 → 𝑍 ∈ V)
 
9-Sep-2026flaplt 10740 The floor function value is less than the next integer. (Contributed by NM, 24-Feb-2005.) (Revised by Jim Kingdon, 9-Sep-2026.)
(((𝐴 ∈ ℚ ∨ (𝐴 ∈ ℝ ∧ ∀𝑞 ∈ ℚ 𝐴 # 𝑞)) ∧ 𝐵 ∈ ℤ) → (𝐴 < 𝐵 ↔ (⌊‘𝐴) < 𝐵))
 
8-Sep-2026fiidxsupcl 12019 A set of integers indexed by a finite set has an upper bound. (Contributed by Jim Kingdon, 8-Sep-2026.)
(𝜑 → 𝐹:𝐴⟶ℤ)    &   (𝜑 → 𝐴 ∈ Fin)    ⇒   (𝜑 → ∃𝑥 ∈ ℤ ∀𝑦 ∈ 𝐴 (𝐹‘𝑦) ≤ 𝑥)
 
6-Sep-2026ofrfidc 7324 Decidability of a relation applied to two functions. (Contributed by Jim Kingdon, 6-Sep-2026.)
(𝜑 → 𝐹 Fn 𝐴)    &   (𝜑 → 𝐺 Fn 𝐴)    &   (𝜑 → ∀𝑥 ∈ 𝐴 DECID (𝐹‘𝑥)𝑅(𝐺‘𝑥))    &   (𝜑 → 𝐴 ∈ Fin)    ⇒   (𝜑 → DECID 𝐹 ∘𝑟 𝑅𝐺)
 
27-Aug-2026prmdcz 12935 Primality is decidable. (Contributed by Jim Kingdon, 27-Aug-2026.)
(𝑁 ∈ ℤ → DECID 𝑁 ∈ ℙ)
 
27-Aug-2026zmincl 12030 The minumum of two integers is an integer. (Contributed by Jim Kingdon, 27-Aug-2026.)
((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ) → inf({𝐴, 𝐵}, ℝ, < ) ∈ ℤ)
 
25-Aug-2026nn0sqdcq 13014 A nonnegative integer is a perfect square or not. This is similar to nn0sqdc 11169 but expresses the idea of being a perfect square as having a rational number which, when squared, gives the original number. (Contributed by Jim Kingdon, 25-Aug-2026.)
(𝑁 ∈ ℕ0 → DECID ∃𝑞 ∈ ℚ 𝑁 = (𝑞↑2))
 
25-Aug-2026qabscl 11866 The absolute value of a rational number is a rational number. (Contributed by Jim Kingdon, 25-Aug-2026.)
(𝐴 ∈ ℚ → (abs‘𝐴) ∈ ℚ)
 
25-Aug-2026nn0sqdc 11169 A nonnegative integer is a perfect square or not. (Contributed by Jim Kingdon, 25-Aug-2026.)
(𝑁 ∈ ℕ0 → DECID ∃𝑞 ∈ ℕ0 𝑁 = (𝑞↑2))
 
24-Aug-2026sqrtrirr 13015 The square root of a nonnegative integer is either rational or irrational. (Contributed by Jim Kingdon, 24-Aug-2026.)
(𝐴 ∈ ℕ0 → ((√‘𝐴) ∈ ℚ ∨ ((√‘𝐴) ∈ ℝ ∧ ∀𝑞 ∈ ℚ (√‘𝐴) # 𝑞)))
 
21-Aug-2026prmefexple 16320 Convert a bound on a power of a prime to a bound on the exponent. (Contributed by Mario Carneiro, 11-Mar-2014.) (Revised by Jim Kingdon, 21-Aug-2026.)
((𝐴 ∈ ℙ ∧ 𝑁 ∈ ℤ ∧ 𝐵 ∈ ℕ) → ((𝐴↑𝑁) ≤ 𝐵 ↔ 𝑁 ≤ (⌊‘((log‘𝐵) / (log‘𝐴)))))
 
20-Aug-2026zprmlogbap 16230 The logarithm of a natural number to a prime base is either rational or irrational.

The proof decomposes 𝑋 into 𝑚 ∈ ℕ and 𝑎 ∈ ℕ0 such that 𝑋 = ((𝐵↑𝑎) · 𝑚) (using nnmaxpw 12979). If 𝑚 = 1 the logarithm is 𝑎, which is rational. If 1 < 𝑚 then we can apply logbgcd1irrap 16218 to show that the logarithm is irrational. (Contributed by Jim Kingdon and Taylor Barrella, 20-Aug-2026.)

((𝑋 ∈ ℕ ∧ 𝐵 ∈ ℙ) → ((𝐵 logb 𝑋) ∈ ℚ ∨ ((𝐵 logb 𝑋) ∈ ℝ ∧ ∀𝑞 ∈ ℚ (𝐵 logb 𝑋) # 𝑞)))
 
20-Aug-2026zprmlogbaplem3 16229 Lemma for zprmlogbap 16230. Decomposing a natural number into a power of a prime base and a factor not divisible by that prime. (Contributed by Jim Kingdon, 20-Aug-2026.)
𝐽 = {𝑧 ∈ ℕ ∣ ¬ 𝐵 ∥ 𝑧}    &   𝐹 = (𝑥 ∈ 𝐽, 𝑦 ∈ ℕ0 ↦ ((𝐵↑𝑦) · 𝑥))    ⇒   ((𝑋 ∈ ℕ ∧ 𝐵 ∈ ℙ) → ∃𝑚 ∈ ℕ ∃𝑎 ∈ ℕ0 (¬ 𝐵 ∥ 𝑚 ∧ 𝑋 = ((𝐵↑𝑎) · 𝑚)))
 
20-Aug-2026zprmlogbaplem2 16228 Lemma for zprmlogbap 16230. The logarithm is either rational or irrational. (Contributed by Jim Kingdon, 20-Aug-2026.)
(𝜑 → 𝐵 ∈ ℙ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → ¬ 𝐵 ∥ 𝑀)    &   (𝜑 → 𝐴 ∈ ℕ0)    &   𝑋 = ((𝐵↑𝐴) · 𝑀)    ⇒   (𝜑 → ((𝐵 logb 𝑋) ∈ ℚ ∨ ((𝐵 logb 𝑋) ∈ ℝ ∧ ∀𝑞 ∈ ℚ (𝐵 logb 𝑋) # 𝑞)))
 
20-Aug-2026zprmlogbaplem1 16227 Lemma for zprmlogbap 16230. Rearranging an expression involving logarithms. (Contributed by Jim Kingdon, 20-Aug-2026.)
(𝜑 → 𝐵 ∈ ℙ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → ¬ 𝐵 ∥ 𝑀)    &   (𝜑 → 𝐴 ∈ ℕ0)    ⇒   (𝜑 → (𝐵 logb ((𝐵↑𝐴) · 𝑀)) = (𝐴 + (𝐵 logb 𝑀)))
 
20-Aug-2026flaplelt 10731 A basic property of the floor (greatest integer) function. (Contributed by Jim Kingdon, 20-Aug-2026.)
((𝐴 ∈ ℚ ∨ (𝐴 ∈ ℝ ∧ ∀𝑞 ∈ ℚ 𝐴 # 𝑞)) → ((⌊‘𝐴) ≤ 𝐴 ∧ 𝐴 < ((⌊‘𝐴) + 1)))
 
20-Aug-2026flapcl 10729 The floor (greatest integer) function yields an integer when applied to a number which is either rational or irrational. (Contributed by Jim Kingdon, 20-Aug-2026.)
((𝐴 ∈ ℚ ∨ (𝐴 ∈ ℝ ∧ ∀𝑞 ∈ ℚ 𝐴 # 𝑞)) → (⌊‘𝐴) ∈ ℤ)
 
20-Aug-2026irraddap 10064 The sum of an irrational number and a rational number is irrational. (Contributed by Jim Kingdon, 20-Aug-2026.)
(((𝐴 ∈ ℝ ∧ ∀𝑞 ∈ ℚ 𝐴 # 𝑞) ∧ 𝐵 ∈ ℚ) → ((𝐴 + 𝐵) ∈ ℝ ∧ ∀𝑞 ∈ ℚ (𝐴 + 𝐵) # 𝑞))
 
19-Aug-2026nnmaxpw 12979 The function 𝐹 that decomposes a number into its "odd" and "even" parts, which is to say the largest power of a base and largest divisor of the number not divisible by that base, is a bijection from pairs of a nonnegative integer and a number not divisible by that base to positive integers. (Contributed by Thierry Arnoux, 15-Aug-2017.) (Revised by Jim Kingdon, 19-Aug-2026.)
𝐽 = {𝑧 ∈ ℕ ∣ ¬ 𝐵 ∥ 𝑧}    &   𝐹 = (𝑥 ∈ 𝐽, 𝑦 ∈ ℕ0 ↦ ((𝐵↑𝑦) · 𝑥))    ⇒   (𝐵 ∈ (ℤ≥‘2) → 𝐹:(𝐽 × ℕ0)–1-1-onto→ℕ)
 
19-Aug-2026nnmaxpwlemparts 12978 Lemma for nnmaxpw 12979. Decomposing a number into parts. (Contributed by Jim Kingdon, 16-Nov-2021.) (Revised by Jim Kingdon, 19-Aug-2026.)
(𝐵 ∈ (ℤ≥‘2) → ((((𝑋 ∈ ℕ ∧ ¬ 𝐵 ∥ 𝑋) ∧ 𝑌 ∈ ℕ0) ∧ 𝐴 = ((𝐵↑𝑌) · 𝑋)) ↔ (𝐴 ∈ ℕ ∧ (𝑋 = (𝐴 / (𝐵↑(℩𝑧 ∈ ℕ0 ((𝐵↑𝑧) ∥ 𝐴 ∧ ¬ (𝐵↑(𝑧 + 1)) ∥ 𝐴)))) ∧ 𝑌 = (℩𝑧 ∈ ℕ0 ((𝐵↑𝑧) ∥ 𝐴 ∧ ¬ (𝐵↑(𝑧 + 1)) ∥ 𝐴))))))
 
19-Aug-2026nnmaxpwlemnfac 12977 Lemma for nnmaxpw 12979. Removing the powers of a base from a natural number produces a number not divisible by that base. (Contributed by Jim Kingdon, 16-Nov-2021.) (Revised by Jim Kingdon, 19-Aug-2026.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ (ℤ≥‘2)) → ¬ 𝐵 ∥ (𝐴 / (𝐵↑(℩𝑧 ∈ ℕ0 ((𝐵↑𝑧) ∥ 𝐴 ∧ ¬ (𝐵↑(𝑧 + 1)) ∥ 𝐴)))))
 
19-Aug-2026nnmaxpwlemndvds 12976 Lemma for nnmaxpw 12979. A natural number is not divisible by one more than the highest power of a base which divides it. (Contributed by Jim Kingdon, 17-Nov-2021.) (Revised by Jim Kingdon, 19-Aug-2026.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ (ℤ≥‘2)) → ¬ (𝐵↑((℩𝑧 ∈ ℕ0 ((𝐵↑𝑧) ∥ 𝐴 ∧ ¬ (𝐵↑(𝑧 + 1)) ∥ 𝐴)) + 1)) ∥ 𝐴)
 
19-Aug-2026nnmaxpwlemdvds 12975 Lemma for nnmaxpw 12979. A natural number is divisible by the highest power of a base which divides it. (Contributed by Jim Kingdon, 17-Nov-2021.) (Revised by Jim Kingdon, 19-Aug-2026.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ (ℤ≥‘2)) → (𝐵↑(℩𝑧 ∈ ℕ0 ((𝐵↑𝑧) ∥ 𝐴 ∧ ¬ (𝐵↑(𝑧 + 1)) ∥ 𝐴))) ∥ 𝐴)
 
18-Aug-2026nnmaxpwlemxy 12974 Lemma for nnmaxpw 12979. Another way of stating that decomposing a natural number into a power of a base and a number not divisible by that base is unique. (Contributed by Jim Kingdon, 16-Nov-2021.) (Revised by Jim Kingdon, 18-Aug-2026.)
(𝜑 → 𝑋 ∈ ℕ)    &   (𝜑 → 𝐵 ∈ (ℤ≥‘2))    &   (𝜑 → ¬ 𝐵 ∥ 𝑋)    &   (𝜑 → 𝑌 ∈ ℕ0)    &   (𝜑 → 𝐴 = ((𝐵↑𝑌) · 𝑋))    ⇒   (𝜑 → (𝑋 = (𝐴 / (𝐵↑(℩𝑧 ∈ ℕ0 ((𝐵↑𝑧) ∥ 𝐴 ∧ ¬ (𝐵↑(𝑧 + 1)) ∥ 𝐴)))) ∧ 𝑌 = (℩𝑧 ∈ ℕ0 ((𝐵↑𝑧) ∥ 𝐴 ∧ ¬ (𝐵↑(𝑧 + 1)) ∥ 𝐴))))
 
18-Aug-2026pwbdvdseu 12973 A natural number has a unique highest power of a base which divides it. (Contributed by Jim Kingdon, 16-Nov-2021.) (Revised by Jim Kingdon, 18-Aug-2026.)
((𝑁 ∈ ℕ ∧ 𝐵 ∈ (ℤ≥‘2)) → ∃!𝑚 ∈ ℕ0 ((𝐵↑𝑚) ∥ 𝑁 ∧ ¬ (𝐵↑(𝑚 + 1)) ∥ 𝑁))
 
18-Aug-2026pwbdvdseulemle 12972 Lemma for pwbdvdseu 12973. Powers of a base which do and do not divide a natural number. (Contributed by Jim Kingdon, 17-Nov-2021.) (Revised by Jim Kingdon, 18-Aug-2026.)
(𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝐴 ∈ ℕ0)    &   (𝜑 → 𝐵 ∈ ℕ0)    &   (𝜑 → 𝑃 ∈ ℕ)    &   (𝜑 → (𝑃↑𝐴) ∥ 𝑁)    &   (𝜑 → ¬ (𝑃↑(𝐵 + 1)) ∥ 𝑁)    ⇒   (𝜑 → 𝐴 ≤ 𝐵)
 
18-Aug-2026pwbdvds 12971 A natural number has a highest power of a base which divides it. (Contributed by Jim Kingdon, 16-Nov-2021.) (Revised by Jim Kingdon, 18-Aug-2026.)
((𝑁 ∈ ℕ ∧ 𝐵 ∈ (ℤ≥‘2)) → ∃𝑚 ∈ ℕ0 ((𝐵↑𝑚) ∥ 𝑁 ∧ ¬ (𝐵↑(𝑚 + 1)) ∥ 𝑁))
 
17-Aug-2026pwbdvdslemn 12970 Lemma for pwbdvds 12971. If a natural number has some power of a base which does not divide it, there is a highest power of the base which does divide it. (Contributed by Jim Kingdon, 14-Nov-2021.) (Revised by Jim Kingdon, 17-Aug-2026.)
(𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝐴 ∈ ℕ)    &   (𝜑 → 𝐵 ∈ ℕ)    &   (𝜑 → ¬ (𝐵↑𝐴) ∥ 𝑁)    ⇒   (𝜑 → ∃𝑚 ∈ ℕ0 ((𝐵↑𝑚) ∥ 𝑁 ∧ ¬ (𝐵↑(𝑚 + 1)) ∥ 𝑁))
 
14-Aug-2026reaplog 16109 Apartness and the real natural logarithm. (Contributed by Jim Kingdon, 14-Aug-2026.)
((𝐴 ∈ ℝ+ ∧ 𝐵 ∈ ℝ+) → (𝐴 # 𝐵 ↔ (log‘𝐴) # (log‘𝐵)))
 
13-Aug-2026efap1p 16017 If the exponential of a number is apart from one plus that number, the number is apart from zero. To some extent can be thought of as the converse of efgt1p 12489. (Contributed by Jim Kingdon, 13-Aug-2026.)
((𝐴 ∈ ℝ ∧ (1 + 𝐴) # (exp‘𝐴)) → 𝐴 # 0)
 
6-Aug-2026relndmfv 5731 The value of a relation outside its domain is the empty set. (Contributed by Jim Kingdon, 6-Aug-2026.)
((Rel 𝐹 ∧ ¬ 𝐴 ∈ dom 𝐹) → (𝐹‘𝐴) = ∅)
 
1-Aug-2026wexmiddifxy 17263 Being able to subtract an arbitrary finite set from a finite set and get a finite set is equivalent to weak excluded middle. By adding additional conditions we can get a theorem which does not need weak excluded middle, at diffifi 7203. (Contributed by Jim Kingdon, 1-Aug-2026.)
(WEXMID ↔ ∀𝑥∀𝑦((𝑥 ∈ Fin ∧ 𝑦 ∈ Fin) → (𝑥 ∖ 𝑦) ∈ Fin))
 
1-Aug-2026wexmiddifxylem 17262 Lemma for wexmiddifxylem 17262. Showing weak excluded middle given a suitable finite set. (Contributed by Jim Kingdon, 1-Aug-2026.)
(({1o} ∖ {{𝑥 ∈ 1o ∣ 𝜑}}) ∈ Fin → DECID ¬ 𝜑)
 
31-Jul-2026rabid1o 17251 Converting between propositions and corresponding subsets of a singleton. (Contributed by Jim Kingdon, 31-Jul-2026.)
({𝑥 ∈ 1o ∣ 𝜑} = 1o ↔ 𝜑)
 
30-Jul-2026wexmiddc 17259 Weak excluded middle expressed using WEXMID implies decidability of a negated proposition. (Contributed by Jim Kingdon, 30-Jul-2026.)
(WEXMID → DECID ¬ 𝜑)
 
30-Jul-2026df-wexmid 17258 Weak excluded middle is the principle that any negated proposition is decidable. (Contributed by Jim Kingdon, 30-Jul-2026.)
(WEXMID ↔ ∀𝑝 ∈ 𝒫 1o(¬ 𝑝 = 1o ∨ ¬ ¬ 𝑝 = 1o))
 
29-Jul-2026wexmiddiffi 17261 Being able to subtract an arbitrary set from a finite set and get a finite set is equivalent to weak excluded middle. By adding additional conditions we can get a theorem which does not need weak excluded middle, at diffifi 7203. (Contributed by Jim Kingdon, 29-Jul-2026.)
(WEXMID ↔ ∀𝑥∀𝑦(𝑥 ∈ Fin → (𝑥 ∖ 𝑦) ∈ Fin))
 
29-Jul-2026wexmiddiffilem 17260 Lemma for wexmiddiffi 17261. The reverse direction, using different notation. (Contributed by Jim Kingdon, 29-Jul-2026.)
(∀𝑥∀𝑦(𝑥 ∈ Fin → (𝑥 ∖ 𝑦) ∈ Fin) → (¬ 𝜑 ∨ ¬ ¬ 𝜑))
 
28-Jul-2026psrbaglefifi 15177 There are finitely many bags dominated by a given bag. (Contributed by Mario Carneiro, 29-Dec-2014.) (Revised by Mario Carneiro, 25-Jan-2015.) (Revised by Jim Kingdon, 28-Jul-2026.)
𝐷 = {𝑓 ∈ (ℕ0 ↑𝑚 𝐼) ∣ (◡𝑓 “ ℕ) ∈ Fin}    ⇒   ((𝐹 ∈ 𝐷 ∧ 𝐼 ∈ Fin) → {𝑦 ∈ 𝐷 ∣ 𝑦 ∘𝑟 ≤ 𝐹} ∈ Fin)
 
24-Jul-2026stnot 17256 A proposition is double negation stable if and only if it is equivalent to a negated proposition. Here by "proposition" we mean a subset of a singleton (which is a choice which allows us to quantify over them). Posed as an exercise online by Yannick Forster. (Contributed by Jim Kingdon, 24-Jul-2026.)
(𝐴 ∈ 𝒫 1o → ((¬ ¬ 𝐴 = 1o → 𝐴 = 1o) ↔ ∃𝑦 ∈ 𝒫 1o(𝐴 = 1o ↔ ¬ 𝑦 = 1o)))
 
24-Jul-2026slotm 13474 A structure with an inhabited slot is inhabited. (Contributed by Jim Kingdon, 24-Jul-2026.)
(𝐸 = Slot (𝐸‘ndx) ∧ (𝐸‘ndx) ∈ ℕ)    ⇒   (𝐴 ∈ (𝐸‘𝐺) → ∃𝑗 𝑗 ∈ 𝐺)
 
22-Jul-2026alseu-no-surprise 17398 Demonstrate that there is never a "surprise" when using the "all some one" quantifier, that is, it is never possible for the consequent to be both always true and always false. This follows from als-no-surprise 17366 by alseuals 17384. See als-no-surprise 17366 for why ordinary "for all" with implication has no such property. (Contributed by David A. Wheeler, 22-Jul-2026.)
¬ (∀∃!𝑥(𝜑 → 𝜓) ∧ ∀∃!𝑥(𝜑 → ¬ 𝜓))
 
22-Jul-2026alseueu 17397 "The 𝜑 is 𝜓 " implies that exactly one thing is both 𝜑 and 𝜓. This is the half of dfalseu2 17396 that drops the universal conjunct; it does not reverse, so ∃!𝑥(𝜑 ∧ 𝜓) cannot be used in place of an "all some one" statement. (Contributed by David A. Wheeler, 22-Jul-2026.)
(∀∃!𝑥(𝜑 → 𝜓) → ∃!𝑥(𝜑 ∧ 𝜓))
 
22-Jul-2026dfalseu2 17396 An "all some one" statement is equivalent to its universal part conjoined with the claim that exactly one 𝑥 satisfies both 𝜑 and 𝜓. In other words, given ∀𝑥(𝜑 → 𝜓), requiring exactly one 𝑥 to satisfy 𝜑, which is what df-alseu 17381 requires, and requiring exactly one 𝑥 to satisfy (𝜑 ∧ 𝜓) come to the same thing. Read 𝜑 as "is a king" and 𝜓 as "is hungry": if every king is hungry, then "there is exactly one king" and "there is exactly one hungry king" say the same thing, so either of them, together with "every king is hungry", gives "the king is hungry".

The universal conjunct is what makes that work, and it cannot be dropped. ∃!𝑥(𝜑 ∧ 𝜓) on its own is strictly weaker than ∀∃!𝑥(𝜑 → 𝜓), since it is satisfied when many things are 𝜑 and just one of those is 𝜓, as in a region with five kings exactly one of whom is hungry; see alseueu 17397 for the one direction that does hold without it. Uniqueness attaches to the antecedent, not to the conjunction. Russell's analysis of a definite description is built the same way: its uniqueness clause constrains the description predicate alone, while the predication is a separate conjunct. See his worked example of "the father of Charles II was executed", [Russell1905] p. 482. (Contributed by David A. Wheeler, 22-Jul-2026.)

(∀∃!𝑥(𝜑 → 𝜓) ↔ (∀𝑥(𝜑 → 𝜓) ∧ ∃!𝑥(𝜑 ∧ 𝜓)))
 
22-Jul-2026nfralseu 17395 Bound-variable hypothesis builder for "all some one" restricted to a class. This is the "all some one" counterpart of nfrals 17364. (Contributed by David A. Wheeler, 22-Jul-2026.)
Ⅎ𝑥𝐴    &   Ⅎ𝑥𝜑    &   Ⅎ𝑥𝜓    ⇒   Ⅎ𝑥∀∃!𝑦 ∈ 𝐴(𝜑 → 𝜓)
 
22-Jul-2026nfalseu 17394 Bound-variable hypothesis builder for "all some one". This is the "all some one" counterpart of nfals 17363. Unlike the set.mm version of this theorem, no disjoint variable condition is needed, because nfeu 2105 here does not require one. (Contributed by David A. Wheeler, 22-Jul-2026.)
Ⅎ𝑥𝜑    &   Ⅎ𝑥𝜓    ⇒   Ⅎ𝑥∀∃!𝑦(𝜑 → 𝜓)
 
22-Jul-2026ralseubii 17393 Congruence for "all some one" restricted to a class. This is the "all some one" counterpart of ralsbii 17361. (Contributed by David A. Wheeler, 22-Jul-2026.)
(𝜑 ↔ 𝜒)    &   (𝜓 ↔ 𝜃)    ⇒   (∀∃!𝑥 ∈ 𝐴(𝜑 → 𝜓) ↔ ∀∃!𝑥 ∈ 𝐴(𝜒 → 𝜃))
 
22-Jul-2026alseubii 17392 Congruence: equivalents may be substituted inside an "all some one". This is the "all some one" counterpart of alsbii 17360. (Contributed by David A. Wheeler, 22-Jul-2026.)
(𝜑 ↔ 𝜒)    &   (𝜓 ↔ 𝜃)    ⇒   (∀∃!𝑥(𝜑 → 𝜓) ↔ ∀∃!𝑥(𝜒 → 𝜃))
 
22-Jul-2026ralseu2d 17391 Deduction rule: Given "all some one" applied to a class, you can extract the "exactly one" part. Note that the witness must satisfy the antecedent 𝜓, not merely be a member of 𝐴. (Contributed by David A. Wheeler, 22-Jul-2026.)
(𝜑 → ∀∃!𝑥 ∈ 𝐴(𝜓 → 𝜒))    ⇒   (𝜑 → ∃!𝑥 ∈ 𝐴 𝜓)
 
22-Jul-2026ralseu1d 17390 Deduction rule: Given "all some one" applied to a class, you can extract the "for all" part. (Contributed by David A. Wheeler, 22-Jul-2026.)
(𝜑 → ∀∃!𝑥 ∈ 𝐴(𝜓 → 𝜒))    ⇒   (𝜑 → ∀𝑥 ∈ 𝐴 (𝜓 → 𝜒))
 
22-Jul-2026alseu2d 17389 Deduction rule: Given "all some one" applied to a top-level inference, you can extract the "exactly one" part. (Contributed by David A. Wheeler, 22-Jul-2026.)
(𝜑 → ∀∃!𝑥(𝜓 → 𝜒))    ⇒   (𝜑 → ∃!𝑥𝜓)
 
22-Jul-2026alseu1d 17388 Deduction rule: Given "all some one" applied to a top-level inference, you can extract the "for all" part. (Contributed by David A. Wheeler, 22-Jul-2026.)
(𝜑 → ∀∃!𝑥(𝜓 → 𝜒))    ⇒   (𝜑 → ∀𝑥(𝜓 → 𝜒))
 
22-Jul-2026ralseud 17387 Introduction rule for "all some one" restricted to a class. This is the converse of ralseu1d 17390 and ralseu2d 17391 taken together. (Contributed by David A. Wheeler, 22-Jul-2026.)
(𝜑 → ∀𝑥 ∈ 𝐴 (𝜓 → 𝜒))    &   (𝜑 → ∃!𝑥 ∈ 𝐴 𝜓)    ⇒   (𝜑 → ∀∃!𝑥 ∈ 𝐴(𝜓 → 𝜒))
 
22-Jul-2026alseud 17386 Introduction rule: "all some one" holds if the "for all" part holds and the antecedent has exactly one witness. This is the converse of alseu1d 17388 and alseu2d 17389 taken together. (Contributed by David A. Wheeler, 22-Jul-2026.)
(𝜑 → ∀𝑥(𝜓 → 𝜒))    &   (𝜑 → ∃!𝑥𝜓)    ⇒   (𝜑 → ∀∃!𝑥(𝜓 → 𝜒))
 
22-Jul-2026ralseurals 17385 "All some one" restricted to a class implies "all some" restricted to that class. Restricted counterpart of alseuals 17384. (Contributed by David A. Wheeler, 22-Jul-2026.)
(∀∃!𝑥 ∈ 𝐴(𝜑 → 𝜓) → ∀∃𝑥 ∈ 𝐴(𝜑 → 𝜓))
 
22-Jul-2026alseuals 17384 "All some one" implies "all some": requiring exactly one witness is stronger than requiring at least one. Any consequence of an allsome statement is therefore a consequence of the corresponding "all some one" statement, which is how alseu-no-surprise 17398 is proved. (Contributed by David A. Wheeler, 22-Jul-2026.)
(∀∃!𝑥(𝜑 → 𝜓) → ∀∃𝑥(𝜑 → 𝜓))
 
22-Jul-2026dfralseu2 17383 The bounded "all some one" form is the general form with the class membership folded into the antecedent. This is the "all some one" counterpart of dfrals2 17349. (Contributed by David A. Wheeler, 22-Jul-2026.)
(∀∃!𝑥 ∈ 𝐴(𝜑 → 𝜓) ↔ ∀∃!𝑥((𝑥 ∈ 𝐴 ∧ 𝜑) → 𝜓))
 
22-Jul-2026df-ralseu 17382 Define "all some one" applied to a class, which means 𝜓 is true whenever 𝜑 is true for 𝑥 in 𝐴, and exactly one 𝑥 in 𝐴 satisfies 𝜑. (Contributed by David A. Wheeler, 22-Jul-2026.)
(∀∃!𝑥 ∈ 𝐴(𝜑 → 𝜓) ↔ (∀𝑥 ∈ 𝐴 (𝜑 → 𝜓) ∧ ∃!𝑥 ∈ 𝐴 𝜑))
 
22-Jul-2026df-alseu 17381 Define "all some one" applied to a top-level implication, which means 𝜓 is true whenever 𝜑 is true and exactly one 𝑥 satisfies 𝜑. (Contributed by David A. Wheeler, 22-Jul-2026.)
(∀∃!𝑥(𝜑 → 𝜓) ↔ (∀𝑥(𝜑 → 𝜓) ∧ ∃!𝑥𝜑))
 
22-Jul-2026wralseu 17380 Extend wff definition to include "all some one" applied to a class, which means 𝜓 is true whenever 𝜑 is true for 𝑥 in 𝐴, and exactly one 𝑥 in 𝐴 satisfies 𝜑. (Contributed by David A. Wheeler, 22-Jul-2026.)
wff ∀∃!𝑥 ∈ 𝐴(𝜑 → 𝜓)
 
22-Jul-2026walseu 17379 Extend wff definition to include "all some one" applied to a top-level implication, which means 𝜓 is true whenever 𝜑 is true, and exactly one 𝑥 satisfies 𝜑. (Contributed by David A. Wheeler, 22-Jul-2026.)
wff ∀∃!𝑥(𝜑 → 𝜓)
 
22-Jul-2026mptmex 5948 If a function given by maps-to notation is inhabited, then the class it is defined on is inhabited. (Contributed by Jim Kingdon, 22-Jul-2026.)
(𝐶 ∈ (𝑥 ∈ 𝐴 ↦ 𝐵) → ∃𝑦 𝑦 ∈ 𝐴)
 
20-Jul-20262alsraln0idm 17378 Nested general "all some" quantifiers with class membership as their antecedents, for the same class 𝐴: 𝜑 holds for every 𝑥 and every 𝑦 in 𝐴, and 𝐴 is inhabited. (Contributed by Peter Mazsa, 28-May-2019.) (Revised by David A. Wheeler, 20-Jul-2026.)
(∀∃𝑥(𝑥 ∈ 𝐴 → ∀∃𝑦(𝑦 ∈ 𝐴 → 𝜑)) ↔ (∀𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 𝜑 ∧ ∃𝑥 𝑥 ∈ 𝐴))
 
20-Jul-20262alsraln0m 17377 Nested general "all some" quantifiers with class membership as their antecedents: 𝜑 holds for every 𝑥 in 𝐴 and every 𝑦 in 𝐵, and both 𝐴 and 𝐵 are inhabited. (Contributed by Peter Mazsa, 28-May-2019.) (Revised by David A. Wheeler, 20-Jul-2026.)
(∀∃𝑥(𝑥 ∈ 𝐴 → ∀∃𝑦(𝑦 ∈ 𝐵 → 𝜑)) ↔ (∀𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐵 𝜑 ∧ (∃𝑥 𝑥 ∈ 𝐴 ∧ ∃𝑦 𝑦 ∈ 𝐵)))
 
20-Jul-2026n0alsm 17376 If 𝐴 is inhabited, then the general "all some" quantifier with class membership as its antecedent reduces to the assertion that 𝜑 holds for every 𝑥 in 𝐴. (Contributed by Peter Mazsa, 19-Dec-2018.) (Revised by David A. Wheeler, 20-Jul-2026.)
(∃𝑥 𝑥 ∈ 𝐴 → (∀∃𝑥(𝑥 ∈ 𝐴 → 𝜑) ↔ ∀𝑥 ∈ 𝐴 𝜑))
 
20-Jul-2026alsraln0m 17373 The general "all some" quantifier with class membership as its antecedent holds if and only if 𝜑 holds for every 𝑥 in 𝐴 and 𝐴 is inhabited. This is the intuitionistic form of what set.mm states using 𝐴 ≠ ∅; see the section comment. (Contributed by Peter Mazsa, 28-Nov-2018.) (Revised by David A. Wheeler, 20-Jul-2026.)
(∀∃𝑥(𝑥 ∈ 𝐴 → 𝜑) ↔ (∀𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑥 𝑥 ∈ 𝐴))
 
20-Jul-2026alsralrex 17372 The general "all some" quantifier with class membership as its antecedent holds if and only if 𝜑 holds for every 𝑥 in 𝐴 and some 𝑥 in 𝐴 satisfies 𝜑. (Contributed by Peter Mazsa, 27-Nov-2018.) (Revised by David A. Wheeler, 20-Jul-2026.)
(∀∃𝑥(𝑥 ∈ 𝐴 → 𝜑) ↔ (∀𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑥 ∈ 𝐴 𝜑))
 
20-Jul-2026ralsanmo 17371 An "all some" statement restricted to a class, conjoined with the claim that at most one 𝑥 in 𝐴 satisfies its antecedent, is equivalent to the universal part conjoined with the claim that exactly one 𝑥 in 𝐴 satisfies the antecedent. This is the restricted counterpart of alsanmo 17370. (Contributed by Peter Mazsa and David A. Wheeler, 20-Jul-2026.)
((∀∃𝑥 ∈ 𝐴(𝜑 → 𝜓) ∧ ∃*𝑥 ∈ 𝐴 𝜑) ↔ (∀𝑥 ∈ 𝐴 (𝜑 → 𝜓) ∧ ∃!𝑥 ∈ 𝐴 𝜑))
 
20-Jul-2026alsanmo 17370 An "all some" statement conjoined with the claim that at most one 𝑥 satisfies its antecedent is equivalent to the universal part conjoined with the claim that exactly one 𝑥 satisfies the antecedent. The "all some" quantifier supplies the existence of such an 𝑥 and ∃*𝑥𝜑 supplies the at-most-one part, so together they yield ∃!𝑥𝜑. (Contributed by Peter Mazsa and David A. Wheeler, 20-Jul-2026.)
((∀∃𝑥(𝜑 → 𝜓) ∧ ∃*𝑥𝜑) ↔ (∀𝑥(𝜑 → 𝜓) ∧ ∃!𝑥𝜑))
 
20-Jul-2026rexrals 17369 If a member of 𝐴 satisfying the antecedent exists, then a restricted "all some" statement reduces to its universal part. This is the restricted counterpart of rexals 17375. (Contributed by Peter Mazsa and David A. Wheeler, 20-Jul-2026.)
(∃𝑥 ∈ 𝐴 𝜑 → (∀∃𝑥 ∈ 𝐴(𝜑 → 𝜓) ↔ ∀𝑥 ∈ 𝐴 (𝜑 → 𝜓)))
 
20-Jul-2026ralrals 17368 If the universal part of a restricted "all some" statement holds, then the statement reduces to the existence of a member of 𝐴 satisfying its antecedent. This is the restricted counterpart of ralals 17374. (Contributed by Peter Mazsa and David A. Wheeler, 20-Jul-2026.)
(∀𝑥 ∈ 𝐴 (𝜑 → 𝜓) → (∀∃𝑥 ∈ 𝐴(𝜑 → 𝜓) ↔ ∃𝑥 ∈ 𝐴 𝜑))
 
20-Jul-2026als-no-surprise 17366 Demonstrate that there is never a "surprise" when using the allsome quantifier, that is, it is never possible for the consequent to be both always true and always false. This uses the definition of df-als 17347: the universal parts give ∀𝑥¬ 𝜑, which contradicts the witness that the allsome quantifier supplies. Ordinary "for all" with implication has no such property, since ∀𝑥(𝜑 → 𝜓) and ∀𝑥(𝜑 → ¬ 𝜓) can both hold when nothing satisfies 𝜑. (Contributed by David A. Wheeler, 27-Oct-2018.) (Revised by David A. Wheeler, 20-Jul-2026.)
¬ (∀∃𝑥(𝜑 → 𝜓) ∧ ∀∃𝑥(𝜑 → ¬ 𝜓))
 
20-Jul-2026ralsmd 17357 Deduction rule: Given "all some" applied to a class, the class is inhabited. This is stronger than ralsn0d 17356, which only concludes that the class is nonempty; see n0r 3535. (Contributed by David A. Wheeler, 20-Jul-2026.)
(𝜑 → ∀∃𝑥 ∈ 𝐴(𝜓 → 𝜒))    ⇒   (𝜑 → ∃𝑥 𝑥 ∈ 𝐴)
 
19-Jul-2026disjdifg 3598 A class and its relative complement are disjoint. (Contributed by NM, 24-Mar-1998.) Generalize from disjdif 3599. (Revised by BJ, 19-Jul-2026.)
(𝐴 ⊆ 𝐵 → (𝐴 ∩ (𝐶 ∖ 𝐵)) = ∅)
 
19-Jul-2026sseq0b 3564 The only subclass of the empty class is itself. (Contributed by NM, 7-Mar-2007.) (Proof shortened by Andrew Salmon, 26-Jun-2011.) Strengthen sseq0 3565 to a biconditional. (Revised by BJ, 19-Jul-2026.)
(𝐴 = ∅ → (𝐵 ⊆ 𝐴 ↔ 𝐵 = ∅))
 
18-Jul-2026sepab 4280 Separation Scheme (Aussonderung) in terms of a class abstraction. Prefer using the more natural statement rabexg 4281. (Contributed by NM, 8-Jun-1994.) Put in closed form. (Revised by BJ, 18-Jul-2026.)
(𝐴 ∈ 𝑉 → {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ∈ V)
 
18-Jul-2026inssdif0im 3592 Intersection, subclass, and difference relationship. The converse holds in classical logic but not in intuitionistic logic. (Contributed by Jim Kingdon, 3-Aug-2018.) (Proof shortened by BJ, 18-Jul-2026.)
((𝐴 ∩ 𝐵) ⊆ 𝐶 → (𝐴 ∩ (𝐵 ∖ 𝐶)) = ∅)
 
15-Jul-2026rexals 17375 If some 𝑥 in 𝐴 satisfies 𝜑, then the general "all some" quantifier with class membership as its antecedent reduces to the assertion that 𝜑 holds for every 𝑥 in 𝐴. See rexrals 17369 for the restricted counterpart. (Contributed by Peter Mazsa, 19-Dec-2018.) (Revised by David A. Wheeler, 15-Jul-2026.)
(∃𝑥 ∈ 𝐴 𝜑 → (∀∃𝑥(𝑥 ∈ 𝐴 → 𝜑) ↔ ∀𝑥 ∈ 𝐴 𝜑))
 
15-Jul-2026ralals 17374 If 𝜑 holds for every 𝑥 in 𝐴, then the general "all some" quantifier with class membership as its antecedent reduces to the assertion that some 𝑥 in 𝐴 satisfies 𝜑. See ralrals 17368 for the restricted counterpart. (Contributed by Peter Mazsa, 19-Dec-2018.) (Revised by David A. Wheeler, 15-Jul-2026.)
(∀𝑥 ∈ 𝐴 𝜑 → (∀∃𝑥(𝑥 ∈ 𝐴 → 𝜑) ↔ ∃𝑥 ∈ 𝐴 𝜑))
 
14-Jul-2026uniex2 4583 The Axiom of Union using the standard abbreviation for union. Given any set 𝑥, its union 𝑦 exists. (Contributed by NM, 4-Jun-2006.) (Proof shortened by BJ, 14-Jul-2026.)
∃𝑦 𝑦 = ∪ 𝑥
 
14-Jul-2026sepgi 4254 Inference associated with sepg 4253. (Contributed by NM, 21-Jun-1993.) (Revised by BJ, 14-Jul-2026.)
𝐴 ∈ V    ⇒   ∃𝑦∀𝑥(𝑥 ∈ 𝑦 ↔ (𝑥 ∈ 𝐴 ∧ 𝜑))
 
13-Jul-2026f1setfi 7323 The set of injections between two finite sets is finite. (Contributed by Jim Kingdon, 13-Jul-2026.)
((𝐴 ∈ Fin ∧ 𝐵 ∈ Fin) → {𝑓 ∣ 𝑓:𝐴–1-1→𝐵} ∈ Fin)
 
13-Jul-2026fdcf1 7322 It is decidable whether a function from a finite set into another finite set is one-to-one. (Contributed by Jim Kingdon, 13-Jul-2026.)
((𝐴 ∈ Fin ∧ 𝐵 ∈ Fin ∧ 𝐹:𝐴⟶𝐵) → DECID 𝐹:𝐴–1-1→𝐵)
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