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Theorem List for Metamath Proof Explorer - 35401-35500   *Has distinct variable group(s)
TypeLabelDescription
Statement

Theoremcdleme18d 35401* Part of proof of Lemma E in [Crawley] p. 114, 4th sentence of 4th paragraph. 𝐹, 𝐺, 𝐷, 𝐸 represent f(s), fs(r), f(t), ft(r) respectively. We show fs(r)=ft(r) for all possible r (which must equal p or q in the case of exactly 3 atoms in p q/0 i.e. when ¬ ∃𝑟𝐴...). (Contributed by NM, 12-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑆) 𝑊)))    &   𝐷 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐸 = ((𝑃 𝑄) (𝐷 ((𝑅 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (𝑃𝑄 ∧ (𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ ¬ ∃𝑟𝐴𝑟 𝑊 ∧ (𝑃 𝑟) = (𝑄 𝑟)))) → 𝐺 = 𝐸)

Theoremcdlemesner 35402 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴) ∧ (𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝑆𝑅)

Theoremcdlemedb 35403 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. 𝐷 represents s2. (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝐵 = (Base‘𝐾)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐴𝑆𝐴)) → 𝐷𝐵)

Theoremcdlemeda 35404 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. 𝐷 represents s2. (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑅𝐴𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐷𝐴)

Theoremcdlemednpq 35405 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. 𝐷 represents s2. (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴𝑄𝐴 ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → ¬ 𝐷 (𝑃 𝑄))

TheoremcdlemednuN 35406 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. 𝐷 represents s2. (Contributed by NM, 18-Nov-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑈 = ((𝑃 𝑄) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴𝑄𝐴 ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐷𝑈)

Theoremcdleme20zN 35407 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. (Contributed by NM, 17-Nov-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴𝑇𝐴) ∧ (𝑆𝑇 ∧ ¬ 𝑅 (𝑆 𝑇))) → ((𝑆 𝑅) 𝑇) = (0.‘𝐾))

Theoremcdleme20y 35408 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. (Contributed by NM, 17-Nov-2012.) (Proof shortened by OpenAI, 25-Mar-2020.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴𝑇𝐴) ∧ (𝑆𝑇 ∧ ¬ 𝑅 (𝑆 𝑇))) → ((𝑆 𝑅) (𝑇 𝑅)) = 𝑅)

Theoremcdleme20yOLD 35409 Part of proof of Lemma E in [Crawley] p. 113. Utility lemma. (Contributed by NM, 17-Nov-2012.) Obsolete version of cdleme20y 35408 as of 25-Mar-2020. (New usage is discouraged.) (Proof modification is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴𝑇𝐴) ∧ (𝑆𝑇 ∧ ¬ 𝑅 (𝑆 𝑇))) → ((𝑆 𝑅) (𝑇 𝑅)) = 𝑅)

Theoremcdleme19a 35410 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, 1st line. 𝐷 represents s2. In their notation, we prove that if r s t, then s2=(s t) w. (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       ((𝐾 ∈ HL ∧ (𝑅𝐴𝑆𝐴𝑇𝐴) ∧ (𝑅 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇))) → 𝐷 = ((𝑆 𝑇) 𝑊))

Theoremcdleme19b 35411 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, 1st line. 𝐷, 𝐹, 𝐺 represent s2, f(s), f(t). In their notation, we prove that if r s t, then s2 f(s) f(t). (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ 𝑅𝐴) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇)))) → 𝐷 (𝐹 𝐺))

Theoremcdleme19c 35412 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, 1st line. 𝐷, 𝐹 represent s2, f(s). We prove f(s) s2. (Contributed by NM, 13-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑅𝐴𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄))) → 𝐹𝐷)

Theoremcdleme19d 35413 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114. 𝐷, 𝐹, 𝐺 represent s2, f(s), f(t). We prove f(s) s2 = f(s) f(t). (Contributed by NM, 14-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ 𝑅𝐴) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇)))) → (𝐹 𝐷) = (𝐹 𝐺))

Theoremcdleme19e 35414 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, line 2. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We prove f(s) s2=f(t) t2. (Contributed by NM, 14-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ 𝑅𝐴) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇)))) → (𝐹 𝐷) = (𝐺 𝑌))

Theoremcdleme19f 35415 Part of proof of Lemma E in [Crawley] p. 113, 5th paragraph on p. 114, line 3. 𝐷, 𝐹, 𝑁, 𝑌, 𝐺, 𝑂 represent s2, f(s), fs(r), t2, f(t), ft(r). We prove that if r s t, then ft(r) = ft(r). (Contributed by NM, 14-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ 𝑅𝐴) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑅 (𝑆 𝑇)))) → 𝑁 = 𝑂)

Theoremcdleme20aN 35416 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 14-Nov-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐴𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝑉 𝐷) = (((𝑆 𝑅) 𝑇) 𝑊))

Theoremcdleme20bN 35417 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, second line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show v s2 = v t2. (Contributed by NM, 15-Nov-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐴 ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝑉 𝐷) = (𝑉 𝑌))

Theoremcdleme20c 35418 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, second line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 15-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝐷 𝑌) = (((𝑅 𝑆) 𝑇) 𝑊))

Theoremcdleme20d 35419 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, second line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 17-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ 𝑅 (𝑃 𝑄))) → ((𝐹 𝐺) (𝐷 𝑌)) = 𝑉)

Theoremcdleme20e 35420 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, 4th line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show <f(s),s2,s> and <f(t),t2,t> are centrally perspective. (Contributed by NM, 17-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ 𝑅 (𝑃 𝑄))) → ((𝐹 𝐺) (𝐷 𝑌)) (𝑆 𝑇))

Theoremcdleme20f 35421 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, 4th line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show <f(s),s2,s> and <f(t),t2,t> are axially perspective. (Contributed by NM, 17-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ 𝑅 (𝑃 𝑄))) → ((𝐹 𝐷) (𝐺 𝑌)) (((𝐷 𝑆) (𝑌 𝑇)) ((𝑆 𝐹) (𝑇 𝐺))))

Theoremcdleme20g 35422 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, antepenultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄)) ∧ 𝑅 (𝑃 𝑄))) → (((𝐷 𝑆) (𝑌 𝑇)) ((𝑆 𝐹) (𝑇 𝐺))) = (((𝑆 𝑅) (𝑇 𝑅)) ((𝑆 𝑈) (𝑇 𝑈))))

Theoremcdleme20h 35423 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, antepenultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → (((𝑆 𝑅) (𝑇 𝑅)) ((𝑆 𝑈) (𝑇 𝑈))) = (𝑅 𝑈))

Theoremcdleme20i 35424 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, antepenultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show (f(s) s2) (f(t) t2) p q. (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → ((𝐹 𝐷) (𝐺 𝑌)) (𝑃 𝑄))

Theoremcdleme20j 35425 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). We show s2 t2. (Contributed by NM, 18-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ ¬ 𝑅 (𝑆 𝑇))) → 𝐷𝑌)

Theoremcdleme20k 35426 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, antepenultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t). (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝑃𝐴𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊)) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝐹 𝐷) ≠ (𝑃 𝑄))

Theoremcdleme20l1 35427 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, penultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t) respectively. (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑅𝐴𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄))) → (𝐹 𝐷) ∈ (LLines‘𝐾))

Theoremcdleme20l2 35428 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, penultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t) respectively. (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → ((𝐹 𝐷) (𝐺 𝑌)) ∈ 𝐴)

Theoremcdleme20l 35429 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, penultimate line. 𝐷, 𝐹, 𝑌, 𝐺 represent s2, f(s), t2, f(t) respectively. (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → ((𝐹 𝐷) (𝐺 𝑌)) = ((𝑃 𝑄) (𝐹 𝐷)))

Theoremcdleme20m 35430 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 114, penultimate line. 𝐷, 𝐹, 𝑁, 𝑌, 𝐺, 𝑂 represent s2, f(s), fs(r), t2, f(t), ft(r) respectively. We prove that if ¬ r s t and ¬ u s t, then fs(r) = ft(r). (Contributed by NM, 20-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ (¬ 𝑅 (𝑆 𝑇) ∧ ¬ 𝑈 (𝑆 𝑇)))) → 𝑁 = 𝑂)

Theoremcdleme20 35431 Combine cdleme19f 35415 and cdleme20m 35430 to eliminate ¬ 𝑅 (𝑆 𝑇) condition. (Contributed by NM, 28-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑉 = ((𝑆 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ ¬ 𝑈 (𝑆 𝑇))) → 𝑁 = 𝑂)

Theoremcdleme21a 35432 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 28-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &   𝐴 = (Atoms‘𝐾)       (((𝐾 ∈ HL ∧ 𝑃𝐴𝑄𝐴) ∧ (𝑆𝐴 ∧ ¬ 𝑆 (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ (𝑃 𝑧) = (𝑆 𝑧))) → 𝑆𝑧)

Theoremcdleme21b 35433 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 28-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &   𝐴 = (Atoms‘𝐾)       (((𝐾 ∈ HL ∧ 𝑃𝐴𝑄𝐴) ∧ (𝑆𝐴𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ (𝑃 𝑧) = (𝑆 𝑧))) → ¬ 𝑧 (𝑃 𝑄))

Theoremcdleme21c 35434 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 28-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ (𝑆𝐴𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ (𝑃 𝑧) = (𝑆 𝑧))) → ¬ 𝑈 (𝑆 𝑧))

Theoremcdleme21at 35435 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄)) ∧ 𝑈 (𝑆 𝑇)) ∧ (𝑧𝐴 ∧ (𝑃 𝑧) = (𝑆 𝑧))) → 𝑇𝑧)

Theoremcdleme21ct 35436 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇))) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧))) → ¬ 𝑈 (𝑇 𝑧))

Theoremcdleme21d 35437 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 115, 3rd line. 𝐷, 𝐹, 𝑁, 𝐸, 𝐵, 𝑍 represent s2, f(s), fs(r), z2, f(z), fz(r) respectively. We prove fs(r) = fz(r). (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐵 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝐸 = ((𝑅 𝑧) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑍 = ((𝑃 𝑄) (𝐵 𝐸))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (𝑃𝑄 ∧ (¬ 𝑆 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧)))) → 𝑁 = 𝑍)

Theoremcdleme21e 35438 Part of proof of Lemma E in [Crawley] p. 113, last paragraph on p. 115, 3rd line. 𝑌, 𝐺, 𝑂, 𝐸, 𝐵, 𝑍 represent s2, f(s), fs(r), z2, f(z), fz(r) respectively. We prove that if u s z, then ft(r) = fz(r). (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐵 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝐸 = ((𝑅 𝑧) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑍 = ((𝑃 𝑄) (𝐵 𝐸))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧)))) → 𝑂 = 𝑍)

Theoremcdleme21f 35439 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐵 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝐸 = ((𝑅 𝑧) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑍 = ((𝑃 𝑄) (𝐵 𝐸))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧)))) → 𝑁 = 𝑂)

Theoremcdleme21g 35440 Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)) ∧ ((𝑧𝐴 ∧ ¬ 𝑧 𝑊) ∧ (𝑃 𝑧) = (𝑆 𝑧)))) → 𝑁 = 𝑂)

Theoremcdleme21h 35441* Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)))) → (∃𝑧𝐴𝑧 𝑊 ∧ (𝑃 𝑧) = (𝑆 𝑧)) → 𝑁 = 𝑂))

Theoremcdleme21i 35442* Part of proof of Lemma E in [Crawley] p. 115. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑃𝑄 ∧ ¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄))) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑅 (𝑃 𝑄) ∧ 𝑈 (𝑆 𝑇)))) → (∃𝑟𝐴𝑟 𝑊 ∧ (𝑃 𝑟) = (𝑄 𝑟)) → 𝑁 = 𝑂))

Theoremcdleme21j 35443* Combine cdleme20 35431 and cdleme21i 35442 to eliminate 𝑈 (𝑆 𝑇) condition. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)) ∧ ∃𝑟𝐴𝑟 𝑊 ∧ (𝑃 𝑟) = (𝑄 𝑟)))) → 𝑁 = 𝑂)

Theoremcdleme21 35444 Part of proof of Lemma E in [Crawley] p. 113, 3rd line on p. 115. 𝐷, 𝐹, 𝑁, 𝑌, 𝐺, 𝑂 represent s2, f(s), fs(r), t2, f(t), ft(r) respectively. Combine cdleme18d 35401 and cdleme21j 35443 to eliminate existence condition, proving fs(r) = ft(r) with fewer conditions. (Contributed by NM, 29-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)))) → 𝑁 = 𝑂)

Theoremcdleme21k 35445 Eliminate 𝑆𝑇 condition in cdleme21 35444. (Contributed by NM, 26-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝐷 = ((𝑅 𝑆) 𝑊)    &   𝑌 = ((𝑅 𝑇) 𝑊)    &   𝑁 = ((𝑃 𝑄) (𝐹 𝐷))    &   𝑂 = ((𝑃 𝑄) (𝐺 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (𝑃𝑄 ∧ (¬ 𝑆 (𝑃 𝑄) ∧ ¬ 𝑇 (𝑃 𝑄) ∧ 𝑅 (𝑃 𝑄)))) → 𝑁 = 𝑂)

Theoremcdleme22aa 35446 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 3rd line on p. 115. Show that t v = p q implies v = u. (Contributed by NM, 2-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴𝑃𝑄) ∧ (𝑉𝐴𝑉 𝑊𝑉 (𝑃 𝑄))) → 𝑉 = 𝑈)

Theoremcdleme22a 35447 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 3rd line on p. 115. Show that t v = p q implies v = u. (Contributed by NM, 30-Nov-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴𝑇𝐴) ∧ ((𝑉𝐴𝑉 𝑊) ∧ 𝑃𝑄 ∧ (𝑇 𝑉) = (𝑃 𝑄))) → 𝑉 = 𝑈)

Theoremcdleme22b 35448 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 5th line on p. 115. Show that t v =/= p q and s p q implies ¬ t p q. (Contributed by NM, 2-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       (((𝐾 ∈ HL ∧ (𝑆𝐴𝑇𝐴𝑆𝑇)) ∧ (𝑃𝐴𝑄𝐴𝑃𝑄) ∧ (𝑉𝐴 ∧ ((𝑇 𝑉) ≠ (𝑃 𝑄) ∧ 𝑆 (𝑇 𝑉) ∧ 𝑆 (𝑃 𝑄)))) → ¬ 𝑇 (𝑃 𝑄))

Theoremcdleme22cN 35449 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 5th line on p. 115. Show that t v =/= p q and s p q implies ¬ v p q. (Contributed by NM, 3-Dec-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝑄𝐴) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴 ∧ (𝑉𝐴𝑉 𝑊)) ∧ ((𝑃𝑄𝑆𝑇) ∧ (𝑆 (𝑇 𝑉) ∧ 𝑆 (𝑃 𝑄)) ∧ (𝑇 𝑉) ≠ (𝑃 𝑄))) → ¬ 𝑉 (𝑃 𝑄))

Theoremcdleme22d 35450 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 9th line on p. 115. (Contributed by NM, 4-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑉𝐴𝑉 𝑊)) ∧ (𝑆𝑇𝑆 (𝑇 𝑉))) → 𝑉 = ((𝑆 𝑇) 𝑊))

Theoremcdleme22e 35451 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 4th line on p. 115. 𝐹, 𝑁, 𝑂 represent f(z), fz(s), fz(t) respectively. When t v = p q, fz(s) fz(t) v. (Contributed by NM, 6-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑧) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐹 ((𝑇 𝑧) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴𝑇𝐴)) ∧ ((𝑉𝐴𝑉 𝑊) ∧ (𝑃𝑄 ∧ (𝑇 𝑉) = (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ ¬ 𝑧 𝑊))) → 𝑁 (𝑂 𝑉))

Theoremcdleme22eALTN 35452 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 4th line on p. 115. 𝐹, 𝑁, 𝑂 represent f(z), fz(s), fz(t) respectively. When t v = p q, fz(s) fz(t) v. (Contributed by NM, 6-Dec-2012.) (New usage is discouraged.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑦 𝑈) (𝑄 ((𝑃 𝑦) 𝑊)))    &   𝐺 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑦) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐺 ((𝑇 𝑧) 𝑊)))       (((𝐾 ∈ HL ∧ 𝑊𝐻𝑇𝐴) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ 𝑃𝑄) ∧ (𝑆𝐴 ∧ (𝑉𝐴𝑉 𝑊 ∧ (𝑇 𝑉) = (𝑃 𝑄)) ∧ ((𝑦𝐴 ∧ ¬ 𝑦 𝑊) ∧ (𝑧𝐴 ∧ ¬ 𝑧 𝑊)))) → 𝑁 (𝑂 𝑉))

Theoremcdleme22f 35453 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 6th and 7th lines on p. 115. 𝐹, 𝑁 represent f(t), ft(s) respectively. If s t v, then ft(s) f(t) v. (Contributed by NM, 6-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ 𝑇𝐴 ∧ (𝑉𝐴𝑉 𝑊)) ∧ (𝑆𝑇𝑆 (𝑇 𝑉))) → 𝑁 (𝐹 𝑉))

Theoremcdleme22f2 35454 Part of proof of Lemma E in [Crawley] p. 113. cdleme22f 35453 with s and t swapped (this case is not mentioned by them). If s t v, then f(s) fs(t) v. (Contributed by NM, 7-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑇 𝑆) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (¬ 𝑆 (𝑃 𝑄) ∧ 𝑇 (𝑃 𝑄) ∧ 𝑃𝑄)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑆𝑇𝑆 (𝑇 𝑉)) ∧ (𝑉𝐴𝑉 𝑊))) → 𝐹 (𝑁 𝑉))

Theoremcdleme22g 35455 Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 6th and 7th lines on p. 115. 𝐹, 𝐺 represent f(s), f(t) respectively. If s t v and ¬ s p q, then f(s) f(t) v. (Contributed by NM, 6-Dec-2012.)
= (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝐺 = ((𝑇 𝑈) (𝑄 ((𝑃 𝑇) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (¬ 𝑇 (𝑃 𝑄) ∧ ¬ 𝑆 (𝑃 𝑄) ∧ 𝑃𝑄)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑆𝑇𝑆 (𝑇 𝑉)) ∧ (𝑉𝐴𝑉 𝑊))) → 𝐹 (𝐺 𝑉))

Theoremcdleme23a 35456 Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 8-Dec-2012.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑉 = ((𝑆 𝑇) (𝑋 𝑊))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊) ∧ (𝑆𝑇 ∧ (𝑆 (𝑋 𝑊)) = 𝑋 ∧ (𝑇 (𝑋 𝑊)) = 𝑋)) → 𝑉 𝑊)

Theoremcdleme23b 35457 Part of proof of Lemma E in [Crawley] p. 113, 4th paragraph, 6th line on p. 115. (Contributed by NM, 8-Dec-2012.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑉 = ((𝑆 𝑇) (𝑋 𝑊))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊) ∧ (𝑆𝑇 ∧ (𝑆 (𝑋 𝑊)) = 𝑋 ∧ (𝑇 (𝑋 𝑊)) = 𝑋)) → 𝑉𝐴)

Theoremcdleme23c 35458 Part of proof of Lemma E in [Crawley] p. 113, 4th paragraph, 6th line on p. 115. (Contributed by NM, 8-Dec-2012.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑉 = ((𝑆 𝑇) (𝑋 𝑊))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊) ∧ (𝑆𝑇 ∧ (𝑆 (𝑋 𝑊)) = 𝑋 ∧ (𝑇 (𝑋 𝑊)) = 𝑋)) → 𝑆 (𝑇 𝑉))

Theoremcdleme24 35459* Quantified version of cdleme21k 35445. (Contributed by NM, 26-Dec-2012.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑠) 𝑊)))    &   𝐺 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐺 ((𝑅 𝑡) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑃𝑄𝑅 (𝑃 𝑄))) → ∀𝑠𝐴𝑡𝐴 (((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) ∧ (¬ 𝑡 𝑊 ∧ ¬ 𝑡 (𝑃 𝑄))) → 𝑁 = 𝑂))

Theoremcdleme25a 35460* Lemma for cdleme25b 35461. (Contributed by NM, 1-Jan-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑠) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑃𝑄𝑅 (𝑃 𝑄))) → ∃𝑠𝐴 ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) ∧ 𝑁𝐵))

Theoremcdleme25b 35461* Transform cdleme24 35459. TODO get rid of \$d's on 𝑈, 𝑁 (Contributed by NM, 1-Jan-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑠) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑃𝑄𝑅 (𝑃 𝑄))) → ∃𝑢𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) → 𝑢 = 𝑁))

Theoremcdleme25c 35462* Transform cdleme25b 35461. (Contributed by NM, 1-Jan-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑠) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑃𝑄𝑅 (𝑃 𝑄))) → ∃!𝑢𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) → 𝑢 = 𝑁))

Theoremcdleme25dN 35463* Transform cdleme25c 35462. (Contributed by NM, 19-Jan-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑠) 𝑊)))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑃𝑄𝑅 (𝑃 𝑄))) → ∃!𝑢𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) ∧ 𝑢 = 𝑁))

Theoremcdleme25cl 35464* Show closure of the unique element in cdleme25c 35462. (Contributed by NM, 2-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑠) 𝑊)))    &   𝐼 = (𝑢𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) → 𝑢 = 𝑁))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑅𝐴 ∧ ¬ 𝑅 𝑊) ∧ (𝑃𝑄𝑅 (𝑃 𝑄))) → 𝐼𝐵)

Theoremcdleme25cv 35465* Change bound variables in cdleme25c 35462. (Contributed by NM, 2-Feb-2013.)
𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑅 𝑠) 𝑊)))    &   𝐺 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐺 ((𝑅 𝑧) 𝑊)))    &   𝐼 = (𝑢𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))       𝐼 = 𝐸

Theoremcdleme26e 35466* Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 4th line on p. 115. 𝐹, 𝑁, 𝑂 represent f(z), fz(s), fz(t) respectively. When t v = p q, fz(s) fz(t) v. TODO: FIX COMMENT. (Contributed by NM, 2-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑧) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐹 ((𝑇 𝑧) 𝑊)))    &   𝐼 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑉𝐴𝑉 𝑊)) ∧ ((𝑃𝑄𝑆 (𝑃 𝑄) ∧ 𝑇 (𝑃 𝑄)) ∧ ((𝑇 𝑉) = (𝑃 𝑄) ∧ ¬ 𝑧 (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ ¬ 𝑧 𝑊))) → 𝐼 (𝐸 𝑉))

Theoremcdleme26ee 35467* Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 4th line on p. 115. 𝐹, 𝑁, 𝑂 represent f(z), fz(s), fz(t) respectively. When t v = p q, fz(s) fz(t) v. TODO: FIX COMMENT. (Contributed by NM, 2-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑧) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐹 ((𝑇 𝑧) 𝑊)))    &   𝐼 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑆𝐴 ∧ ¬ 𝑆 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊) ∧ (𝑉𝐴𝑉 𝑊)) ∧ ((𝑃𝑄𝑆 (𝑃 𝑄) ∧ 𝑇 (𝑃 𝑄)) ∧ (𝑇 𝑉) = (𝑃 𝑄))) → 𝐼 (𝐸 𝑉))

Theoremcdleme26eALTN 35468* Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 4th line on p. 115. 𝐹, 𝑁, 𝑂 represent f(z), fz(s), fz(t) respectively. When t v = p q, fz(s) fz(t) v. TODO: FIX COMMENT. (Contributed by NM, 1-Feb-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑦 𝑈) (𝑄 ((𝑃 𝑦) 𝑊)))    &   𝐺 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑦) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐺 ((𝑇 𝑧) 𝑊)))    &   𝐼 = (𝑢𝐵𝑦𝐴 ((¬ 𝑦 𝑊 ∧ ¬ 𝑦 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑃𝑄 ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊𝑆 (𝑃 𝑄)) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊𝑇 (𝑃 𝑄))) ∧ ((𝑉𝐴𝑉 𝑊 ∧ (𝑇 𝑉) = (𝑃 𝑄)) ∧ (𝑦𝐴 ∧ ¬ 𝑦 𝑊 ∧ ¬ 𝑦 (𝑃 𝑄)) ∧ (𝑧𝐴 ∧ ¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)))) → 𝐼 (𝐸 𝑉))

Theoremcdleme26fALTN 35469* Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 6th and 7th lines on p. 115. 𝐹, 𝑁 represent f(t), ft(s) respectively. If t t v, then ft(s) f(t) v. TODO: FIX COMMENT. (Contributed by NM, 1-Feb-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑡) 𝑊)))    &   𝐼 = (𝑢𝐵𝑡𝐴 ((¬ 𝑡 𝑊 ∧ ¬ 𝑡 (𝑃 𝑄)) → 𝑢 = 𝑁))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝑄𝑆 (𝑃 𝑄)) ∧ (𝑡𝐴 ∧ ¬ 𝑡 𝑊)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ ((¬ 𝑡 𝑊 ∧ ¬ 𝑡 (𝑃 𝑄)) ∧ (𝑆𝑡𝑆 (𝑡 𝑉)) ∧ (𝑉𝐴𝑉 𝑊))) → 𝐼 (𝐹 𝑉))

Theoremcdleme26f 35470* Part of proof of Lemma E in [Crawley] p. 113, 3rd paragraph, 6th and 7th lines on p. 115. 𝐹, 𝑁 represent f(t), ft(s) respectively. If t t v, then ft(s) f(t) v. TODO: FIX COMMENT. (Contributed by NM, 1-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝐹 ((𝑆 𝑡) 𝑊)))    &   𝐼 = (𝑢𝐵𝑡𝐴 ((¬ 𝑡 𝑊 ∧ ¬ 𝑡 (𝑃 𝑄)) → 𝑢 = 𝑁))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝑄𝑆 (𝑃 𝑄)) ∧ (𝑡𝐴 ∧ ¬ 𝑡 𝑊)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑆𝐴 ∧ ¬ 𝑆 𝑊)) ∧ (¬ 𝑡 (𝑃 𝑄) ∧ (𝑆𝑡𝑆 (𝑡 𝑉)) ∧ (𝑉𝐴𝑉 𝑊))) → 𝐼 (𝐹 𝑉))

Theoremcdleme26f2ALTN 35471* Part of proof of Lemma E in [Crawley] p. 113. cdleme26fALTN 35469 with s and t swapped (this case is not mentioned by them). If s t v, then f(s) fs(t) v. TODO: FIX COMMENT. (Contributed by NM, 1-Feb-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐺 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐺 ((𝑇 𝑠) 𝑊)))    &   𝐸 = (𝑢𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) → 𝑢 = 𝑂))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝑄𝑇 (𝑃 𝑄)) ∧ (𝑠𝐴 ∧ ¬ 𝑠 𝑊)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) ∧ (𝑠𝑇𝑠 (𝑇 𝑉)) ∧ (𝑉𝐴𝑉 𝑊))) → 𝐺 (𝐸 𝑉))

Theoremcdleme26f2 35472* Part of proof of Lemma E in [Crawley] p. 113. cdleme26fALTN 35469 with s and t swapped (this case is not mentioned by them). If s t v, then f(s) fs(t) v. TODO: FIX COMMENT. (Contributed by NM, 1-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐺 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝐺 ((𝑇 𝑠) 𝑊)))    &   𝐸 = (𝑢𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ ¬ 𝑠 (𝑃 𝑄)) → 𝑢 = 𝑂))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝑄𝑇 (𝑃 𝑄)) ∧ (𝑠𝐴 ∧ ¬ 𝑠 𝑊)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑇𝐴 ∧ ¬ 𝑇 𝑊)) ∧ (¬ 𝑠 (𝑃 𝑄) ∧ (𝑠𝑇𝑠 (𝑇 𝑉)) ∧ (𝑉𝐴𝑉 𝑊))) → 𝐺 (𝐸 𝑉))

Theoremcdleme27cl 35473* Part of proof of Lemma E in [Crawley] p. 113. Closure of 𝐶. (Contributed by NM, 6-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ ((𝑠𝐴 ∧ ¬ 𝑠 𝑊) ∧ 𝑃𝑄)) → 𝐶𝐵)

Theoremcdleme27a 35474* Part of proof of Lemma E in [Crawley] p. 113. cdleme26f 35470 with s and t swapped (this case is not mentioned by them). If s t v, then f(s) fs(t) v. TODO: FIX COMMENT. (Contributed by NM, 3-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)    &   𝐺 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝑍 ((𝑡 𝑧) 𝑊)))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))    &   𝑌 = if(𝑡 (𝑃 𝑄), 𝐸, 𝐺)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝑃𝑄 ∧ (𝑠𝐴 ∧ ¬ 𝑠 𝑊)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑡𝐴 ∧ ¬ 𝑡 𝑊)) ∧ ((𝑠𝑡𝑠 (𝑡 𝑉)) ∧ (𝑉𝐴𝑉 𝑊))) → 𝐶 (𝑌 𝑉))

Theoremcdleme27b 35475* Lemma for cdleme27N 35476. (Contributed by NM, 3-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)    &   𝐺 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝑍 ((𝑡 𝑧) 𝑊)))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))    &   𝑌 = if(𝑡 (𝑃 𝑄), 𝐸, 𝐺)       (𝑠 = 𝑡𝐶 = 𝑌)

Theoremcdleme27N 35476* Part of proof of Lemma E in [Crawley] p. 113. Eliminate the 𝑠𝑡 antecedent in cdleme27a 35474. (Contributed by NM, 3-Feb-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)    &   𝐺 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝑍 ((𝑡 𝑧) 𝑊)))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))    &   𝑌 = if(𝑡 (𝑃 𝑄), 𝐸, 𝐺)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝑃𝑄 ∧ (𝑠𝐴 ∧ ¬ 𝑠 𝑊)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊) ∧ (𝑡𝐴 ∧ ¬ 𝑡 𝑊)) ∧ (𝑠 (𝑡 𝑉) ∧ (𝑉𝐴𝑉 𝑊))) → 𝐶 (𝑌 𝑉))

Theoremcdleme28a 35477* Lemma for cdleme25b 35461. TODO: FIX COMMENT. (Contributed by NM, 4-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)    &   𝐺 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝑍 ((𝑡 𝑧) 𝑊)))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))    &   𝑌 = if(𝑡 (𝑃 𝑄), 𝐸, 𝐺)    &   𝑉 = ((𝑠 𝑡) (𝑋 𝑊))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑃𝑄 ∧ (𝑠𝐴 ∧ ¬ 𝑠 𝑊) ∧ (𝑡𝐴 ∧ ¬ 𝑡 𝑊)) ∧ (𝑠𝑡 ∧ ((𝑠 (𝑋 𝑊)) = 𝑋 ∧ (𝑡 (𝑋 𝑊)) = 𝑋) ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊))) → (𝐶 (𝑋 𝑊)) (𝑌 (𝑋 𝑊)))

Theoremcdleme28b 35478* Lemma for cdleme25b 35461. TODO: FIX COMMENT. (Contributed by NM, 6-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)    &   𝐺 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝑍 ((𝑡 𝑧) 𝑊)))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))    &   𝑌 = if(𝑡 (𝑃 𝑄), 𝐸, 𝐺)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑃𝑄 ∧ (𝑠𝐴 ∧ ¬ 𝑠 𝑊) ∧ (𝑡𝐴 ∧ ¬ 𝑡 𝑊)) ∧ (𝑠𝑡 ∧ ((𝑠 (𝑋 𝑊)) = 𝑋 ∧ (𝑡 (𝑋 𝑊)) = 𝑋) ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊))) → (𝐶 (𝑋 𝑊)) = (𝑌 (𝑋 𝑊)))

Theoremcdleme28c 35479* Part of proof of Lemma E in [Crawley] p. 113. Eliminate the 𝑠𝑡 antecedent in cdleme28b 35478. TODO: FIX COMMENT. (Contributed by NM, 6-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)    &   𝐺 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝑍 ((𝑡 𝑧) 𝑊)))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))    &   𝑌 = if(𝑡 (𝑃 𝑄), 𝐸, 𝐺)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ (𝑃𝑄 ∧ (𝑠𝐴 ∧ ¬ 𝑠 𝑊) ∧ (𝑡𝐴 ∧ ¬ 𝑡 𝑊)) ∧ ((𝑠 (𝑋 𝑊)) = 𝑋 ∧ (𝑡 (𝑋 𝑊)) = 𝑋 ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊))) → (𝐶 (𝑋 𝑊)) = (𝑌 (𝑋 𝑊)))

Theoremcdleme28 35480* Quantified version of cdleme28c 35479. (Compare cdleme24 35459.) (Contributed by NM, 7-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)    &   𝐺 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑂 = ((𝑃 𝑄) (𝑍 ((𝑡 𝑧) 𝑊)))    &   𝐸 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑂))    &   𝑌 = if(𝑡 (𝑃 𝑄), 𝐸, 𝐺)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ 𝑃𝑄 ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊)) → ∀𝑠𝐴𝑡𝐴 (((¬ 𝑠 𝑊 ∧ (𝑠 (𝑋 𝑊)) = 𝑋) ∧ (¬ 𝑡 𝑊 ∧ (𝑡 (𝑋 𝑊)) = 𝑋)) → (𝐶 (𝑋 𝑊)) = (𝑌 (𝑋 𝑊))))

Theoremcdleme29ex 35481* Lemma for cdleme29b 35482. (Compare cdleme25a 35460.) TODO: FIX COMMENT. (Contributed by NM, 7-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ 𝑃𝑄 ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊)) → ∃𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑋 𝑊)) = 𝑋) ∧ (𝐶 (𝑋 𝑊)) ∈ 𝐵))

Theoremcdleme29b 35482* Transform cdleme28 35480. (Compare cdleme25b 35461.) TODO: FIX COMMENT. (Contributed by NM, 7-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ 𝑃𝑄 ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊)) → ∃𝑣𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑋 𝑊)) = 𝑋) → 𝑣 = (𝐶 (𝑋 𝑊))))

Theoremcdleme29c 35483* Transform cdleme28b 35478. (Compare cdleme25c 35462.) TODO: FIX COMMENT. (Contributed by NM, 8-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ 𝑃𝑄 ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊)) → ∃!𝑣𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑋 𝑊)) = 𝑋) → 𝑣 = (𝐶 (𝑋 𝑊))))

Theoremcdleme29cl 35484* Show closure of the unique element in cdleme28c 35479. (Contributed by NM, 8-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑈 = ((𝑃 𝑄) 𝑊)    &   𝐹 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑍 = ((𝑧 𝑈) (𝑄 ((𝑃 𝑧) 𝑊)))    &   𝑁 = ((𝑃 𝑄) (𝑍 ((𝑠 𝑧) 𝑊)))    &   𝐷 = (𝑢𝐵𝑧𝐴 ((¬ 𝑧 𝑊 ∧ ¬ 𝑧 (𝑃 𝑄)) → 𝑢 = 𝑁))    &   𝐶 = if(𝑠 (𝑃 𝑄), 𝐷, 𝐹)    &   𝐼 = (𝑣𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑋 𝑊)) = 𝑋) → 𝑣 = (𝐶 (𝑋 𝑊))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑄𝐴 ∧ ¬ 𝑄 𝑊)) ∧ 𝑃𝑄 ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊)) → 𝐼𝐵)

Theoremcdleme30a 35485 Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 9-Feb-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑠𝐴 ∧ (𝑋𝐵 ∧ ¬ 𝑋 𝑊) ∧ 𝑌𝐵) ∧ ((𝑠 (𝑋 𝑊)) = 𝑋𝑋 𝑌)) → (𝑠 (𝑌 𝑊)) = 𝑌)

Theoremcdleme31so 35486* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 25-Feb-2013.)
𝑂 = (𝑧𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑥 𝑊)) = 𝑥) → 𝑧 = (𝑁 (𝑥 𝑊))))    &   𝐶 = (𝑧𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑋 𝑊)) = 𝑋) → 𝑧 = (𝑁 (𝑋 𝑊))))       (𝑋𝐵𝑋 / 𝑥𝑂 = 𝐶)

Theoremcdleme31sn 35487* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 26-Feb-2013.)
𝑁 = if(𝑠 (𝑃 𝑄), 𝐼, 𝐷)    &   𝐶 = if(𝑅 (𝑃 𝑄), 𝑅 / 𝑠𝐼, 𝑅 / 𝑠𝐷)       (𝑅𝐴𝑅 / 𝑠𝑁 = 𝐶)

Theoremcdleme31sn1 35488* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 26-Feb-2013.)
𝐼 = (𝑦𝐵𝑡𝐴 ((¬ 𝑡 𝑊 ∧ ¬ 𝑡 (𝑃 𝑄)) → 𝑦 = 𝐺))    &   𝑁 = if(𝑠 (𝑃 𝑄), 𝐼, 𝐷)    &   𝐶 = (𝑦𝐵𝑡𝐴 ((¬ 𝑡 𝑊 ∧ ¬ 𝑡 (𝑃 𝑄)) → 𝑦 = 𝑅 / 𝑠𝐺))       ((𝑅𝐴𝑅 (𝑃 𝑄)) → 𝑅 / 𝑠𝑁 = 𝐶)

Theoremcdleme31se 35489* Part of proof of Lemma D in [Crawley] p. 113. (Contributed by NM, 26-Feb-2013.)
𝐸 = ((𝑃 𝑄) (𝐷 ((𝑠 𝑇) 𝑊)))    &   𝑌 = ((𝑃 𝑄) (𝐷 ((𝑅 𝑇) 𝑊)))       (𝑅𝐴𝑅 / 𝑠𝐸 = 𝑌)

Theoremcdleme31se2 35490* Part of proof of Lemma D in [Crawley] p. 113. (Contributed by NM, 3-Apr-2013.)
𝐸 = ((𝑃 𝑄) (𝐷 ((𝑅 𝑡) 𝑊)))    &   𝑌 = ((𝑃 𝑄) (𝑆 / 𝑡𝐷 ((𝑅 𝑆) 𝑊)))       (𝑆𝐴𝑆 / 𝑡𝐸 = 𝑌)

Theoremcdleme31sc 35491* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 31-Mar-2013.)
𝐶 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑋 = ((𝑅 𝑈) (𝑄 ((𝑃 𝑅) 𝑊)))       (𝑅𝐴𝑅 / 𝑠𝐶 = 𝑋)

Theoremcdleme31sde 35492* Part of proof of Lemma D in [Crawley] p. 113. (Contributed by NM, 31-Mar-2013.)
𝐷 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝐸 = ((𝑃 𝑄) (𝐷 ((𝑠 𝑡) 𝑊)))    &   𝑌 = ((𝑆 𝑈) (𝑄 ((𝑃 𝑆) 𝑊)))    &   𝑍 = ((𝑃 𝑄) (𝑌 ((𝑅 𝑆) 𝑊)))       ((𝑅𝐴𝑆𝐴) → 𝑅 / 𝑠𝑆 / 𝑡𝐸 = 𝑍)

Theoremcdleme31snd 35493* Part of proof of Lemma D in [Crawley] p. 113. (Contributed by NM, 1-Apr-2013.)
𝐷 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑁 = ((𝑣 𝑉) (𝑃 ((𝑄 𝑣) 𝑊)))    &   𝐸 = ((𝑂 𝑈) (𝑄 ((𝑃 𝑂) 𝑊)))    &   𝑂 = ((𝑆 𝑉) (𝑃 ((𝑄 𝑆) 𝑊)))       (𝑆𝐴𝑆 / 𝑣𝑁 / 𝑡𝐷 = 𝐸)

Theoremcdleme31sdnN 35494* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 31-Mar-2013.) (New usage is discouraged.)
𝐶 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝐷 = ((𝑡 𝑈) (𝑄 ((𝑃 𝑡) 𝑊)))    &   𝑁 = if(𝑠 (𝑃 𝑄), 𝐼, 𝐶)       𝑁 = if(𝑠 (𝑃 𝑄), 𝐼, 𝑠 / 𝑡𝐷)

Theoremcdleme31sn1c 35495* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 1-Mar-2013.)
𝐺 = ((𝑃 𝑄) (𝐸 ((𝑠 𝑡) 𝑊)))    &   𝐼 = (𝑦𝐵𝑡𝐴 ((¬ 𝑡 𝑊 ∧ ¬ 𝑡 (𝑃 𝑄)) → 𝑦 = 𝐺))    &   𝑁 = if(𝑠 (𝑃 𝑄), 𝐼, 𝐷)    &   𝑌 = ((𝑃 𝑄) (𝐸 ((𝑅 𝑡) 𝑊)))    &   𝐶 = (𝑦𝐵𝑡𝐴 ((¬ 𝑡 𝑊 ∧ ¬ 𝑡 (𝑃 𝑄)) → 𝑦 = 𝑌))       ((𝑅𝐴𝑅 (𝑃 𝑄)) → 𝑅 / 𝑠𝑁 = 𝐶)

Theoremcdleme31sn2 35496* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 26-Feb-2013.)
𝐷 = ((𝑠 𝑈) (𝑄 ((𝑃 𝑠) 𝑊)))    &   𝑁 = if(𝑠 (𝑃 𝑄), 𝐼, 𝐷)    &   𝐶 = ((𝑅 𝑈) (𝑄 ((𝑃 𝑅) 𝑊)))       ((𝑅𝐴 ∧ ¬ 𝑅 (𝑃 𝑄)) → 𝑅 / 𝑠𝑁 = 𝐶)

Theoremcdleme31fv 35497* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 10-Feb-2013.)
𝑂 = (𝑧𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑥 𝑊)) = 𝑥) → 𝑧 = (𝑁 (𝑥 𝑊))))    &   𝐹 = (𝑥𝐵 ↦ if((𝑃𝑄 ∧ ¬ 𝑥 𝑊), 𝑂, 𝑥))    &   𝐶 = (𝑧𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑋 𝑊)) = 𝑋) → 𝑧 = (𝑁 (𝑋 𝑊))))       (𝑋𝐵 → (𝐹𝑋) = if((𝑃𝑄 ∧ ¬ 𝑋 𝑊), 𝐶, 𝑋))

Theoremcdleme31fv1 35498* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 10-Feb-2013.)
𝑂 = (𝑧𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑥 𝑊)) = 𝑥) → 𝑧 = (𝑁 (𝑥 𝑊))))    &   𝐹 = (𝑥𝐵 ↦ if((𝑃𝑄 ∧ ¬ 𝑥 𝑊), 𝑂, 𝑥))    &   𝐶 = (𝑧𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑋 𝑊)) = 𝑋) → 𝑧 = (𝑁 (𝑋 𝑊))))       ((𝑋𝐵 ∧ (𝑃𝑄 ∧ ¬ 𝑋 𝑊)) → (𝐹𝑋) = 𝐶)

Theoremcdleme31fv1s 35499* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 25-Feb-2013.)
𝑂 = (𝑧𝐵𝑠𝐴 ((¬ 𝑠 𝑊 ∧ (𝑠 (𝑥 𝑊)) = 𝑥) → 𝑧 = (𝑁 (𝑥 𝑊))))    &   𝐹 = (𝑥𝐵 ↦ if((𝑃𝑄 ∧ ¬ 𝑥 𝑊), 𝑂, 𝑥))       ((𝑋𝐵 ∧ (𝑃𝑄 ∧ ¬ 𝑋 𝑊)) → (𝐹𝑋) = 𝑋 / 𝑥𝑂)

Theoremcdleme31fv2 35500* Part of proof of Lemma E in [Crawley] p. 113. (Contributed by NM, 23-Feb-2013.)
𝐹 = (𝑥𝐵 ↦ if((𝑃𝑄 ∧ ¬ 𝑥 𝑊), 𝑂, 𝑥))       ((𝑋𝐵 ∧ ¬ (𝑃𝑄 ∧ ¬ 𝑋 𝑊)) → (𝐹𝑋) = 𝑋)

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