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Statement List for Metamath Proof Explorer - 6901-7000 - Page 70 of 107
TypeLabelDescription
Statement
 
Theoremfaclbnd4lem1 6901 Lemma for faclbnd4 6905. Prepare the induction step. Warning: The HTML proof page is 0.6 megabyte in size.
 
Theoremfaclbnd4lem2 6902 Lemma for faclbnd4 6905. Use the weak deduction theorem to convert the hypotheses of faclbnd4lem1 6901 to antecedents.
 
Theoremfaclbnd4lem3 6903 Lemma for faclbnd4 6905. The N = 0 case.
 
Theoremfaclbnd4lem4 6904 Lemma for faclbnd4 6905. Prove the 0 < N case by induction on K.
 
Theoremfaclbnd4 6905 Variant of faclbnd5 6906 providing a non-strict lower bound.
((N ∈ ℕ0K ∈ ℕ0M ∈ ℕ0) → ((NK) · (MN)) ≤ (((2↑(K↑2)) · (M↑(M + K))) · (! ‘N)))
 
Theoremfaclbnd5 6906 The factorial function grows faster than powers and exponentiations. If we consider K and M to be constants, the right-hand side of the inequality is a constant times N -factorial.
((N ∈ ℕ0K ∈ ℕ0M ∈ ℕ) → ((NK) · (MN)) < ((2 · ((2↑(K↑2)) · (M↑(M + K)))) · (! ‘N)))
 
Theoremfaclbnd6 6907 Geometric lower bound for the factorial function, where N is usually held constant. (Contributed by Paul Chapman, 28-Dec-2007.)
((N ∈ ℕ0M ∈ ℕ0) → ((! ‘N) · ((N + 1)↑M)) ≤ (! ‘(N + M)))
 
Theoremfacavgt 6908 The product of two factorials is greater than or equal to the factorial of (the floor of) their average.
((M ∈ ℕ0N ∈ ℕ0) → (! ‘(⌊ ‘((M + N) / 2))) ≤ ((! ‘M) · (! ‘N)))
 
The binomial coefficient operation
 
Syntaxcbc 6909 Extend class notation to include the binomial coefficient operation (combinatorial choose operation).
class C
 
Definitiondf-bc 6910 Define the binomial coefficient operation. In the literature, this function is often written as a column vector of the two arguments, or with the arguments as subscripts before and after the letter "C". (NCK) is read "N choose K." Definition of binomial coefficient in [Gleason] p. 295. As suggested by Gleason, we define it to be 0 when 0 ≤ kn does not hold.
C = {⟨⟨n, k⟩, m⟩∣((n ∈ ℕ0k ∈ ℤ) ⋀ m = if((0 ≤ kkn), ((! ‘n) / ((! ‘(nk)) · (! ‘k))), 0))}
 
Theorembcvalt 6911 Value of the binomial coefficient, N choose K. Definition of binomial coefficient in [Gleason] p. 295. As suggested by Gleason, we define it to be 0 when 0 ≤ KN does not hold. See bcval2t 6913 for the value in the standard domain.
((N ∈ ℕ0K ∈ ℤ) → (NCK) = if((0 ≤ KKN), ((! ‘N) / ((! ‘(NK)) · (! ‘K))), 0))
 
Theorembcval3tOLD 6912 Value of the binomial coefficient, N choose K, in its standard domain.
(((N ∈ ℕ0K ∈ ℤ) ⋀ (0 ≤ KKN)) → (NCK) = ((! ‘N) / ((! ‘(NK)) · (! ‘K))))
 
Theorembcval2t 6913 Value of the binomial coefficient, N choose K, in its standard domain.
((N ∈ ℕ0K ∈ ℕ0KN) → (NCK) = ((! ‘N) / ((! ‘(NK)) · (! ‘K))))
 
Theorembcval3t 6914 Value of the binomial coefficient, N choose K, in its standard domain.
((N ∈ ℕ0K ∈ (0...N)) → (NCK) = ((! ‘N) / ((! ‘(NK)) · (! ‘K))))
 
Theorembcval4t 6915 Value of the binomial coefficient, N choose K, outside of its standard domain. Remark in [Gleason] p. 295.
((N ∈ ℕ0K ∈ ℤ ⋀ (K < 0 ⋁ N < K)) → (NCK) = 0)
 
Theorembccmplt 6916 "Complementing" its second argument doesn't change a binary coefficient.
((N ∈ ℕ0K ∈ ℕ0KN) → (NCK) = (NC(NK)))
 
Theorembcn0t 6917 N choose 0 is 1. Remark in [Gleason] p. 296.
(N ∈ ℕ0 → (NC0) = 1)
 
Theorembcnnt 6918 N choose N is 1. Remark in [Gleason] p. 296.
(N ∈ ℕ0 → (NCN) = 1)
 
Theorembcnp11t 6919 Binomial coefficient: N + 1 choose 1.
(N ∈ ℕ0 → ((N + 1)C1) = (N + 1))
 
Theorembcnp1nt 6920 Binomial coefficient: N + 1 choose N.
(N ∈ ℕ0 → ((N + 1)CN) = (N + 1))
 
Theorembcpasc2 6921 Pascal's rule for the binomial coefficient. Equation 2 of [Gleason] p. 295.
N ∈ ℕ    &   K ∈ ℕ    &   KN    ⇒   ((NCK) + (NC(K − 1))) = ((N + 1)CK)
 
Theorembcpasc2t 6922 Pascal's rule for the binomial coefficient. Equation 2 of [Gleason] p. 295.
((N ∈ ℕ ⋀ K ∈ ℕ ⋀ KN) → ((NCK) + (NC(K − 1))) = ((N + 1)CK))
 
Theorembcpasc 6923 Pascal's rule for the binomial coefficient, generalized to all integers K. Equation 2 of [Gleason] p. 295.
N ∈ ℕ0    &   K ∈ ℤ    ⇒   ((NCK) + (NC(K − 1))) = ((N + 1)CK)
 
Theorembcpasct 6924 Pascal's rule for the binomial coefficient, generalized to all integers K. Equation 2 of [Gleason] p. 295.
((N ∈ ℕ0K ∈ ℤ) → ((NCK) + (NC(K − 1))) = ((N + 1)CK))
 
Theorembccl2t 6925 A binomial coefficient, in its standard domain, is a natural number.
((N ∈ ℕ0K ∈ (0...N)) → (NCK) ∈ ℕ)
 
Theorembcclt 6926 A binomial coefficient, in its extended domain, is a nonnegative integer.
((N ∈ ℕ0K ∈ ℤ) → (NCK) ∈ ℕ0)
 
Theorempermnnt 6927 The number of permutations of NR objects from a collection of N objects is a natural number. (Contributed by Jason Orendorff, 24-Jan-2007.)
((N ∈ ℕ0R ∈ (0...N)) → ((! ‘N) / (! ‘R)) ∈ ℕ)
 
Limits
 
Syntaxcli 6928 Extend class notation with convergence relation for limits.
class
 
Definitiondf-clim 6929 Define the limit relation for complex number sequences. See clim 6931 for its relational expression.
⇝ = {⟨f, y⟩∣(y ∈ ℂ ⋀ ∀x ∈ ℝ (0 < x → ∃j ∈ ℤ ∀k ∈ ℤ (jk → ((fk) ∈ ℂ ⋀ (abs ‘((fk) − y)) < x))))}
 
Theoremclimrel 6930 The limit relation is a relation.
Rel ⇝
 
Theoremclim 6931 Express the predicate: The limit of complex number sequence F is A, or F converges to A. This means that for any real x, no matter how small, there always exists an integer j such that the absolute difference of any later complex number in the sequence and the limit is less than x.
((FCAD) → (FA ↔ (A ∈ ℂ ⋀ ∀x ∈ ℝ (0 < x → ∃j ∈ ℤ ∀k ∈ ℤ (jk → ((Fk) ∈ ℂ ⋀ (abs ‘((Fk) − A)) < x))))))
 
Theoremclimcl 6932 Closure of the limit of a sequence of complex numbers.
((ACFA) → A ∈ ℂ)
 
Finite and infinite sums
 
Syntaxcsu 6933 Extend class notation to include finite summations. (An underscore was added the ASCII token in order to facilitate text searches, since "sum" is is a commonly used word in comments.)
class ΣkA B
 
Definitiondf-sum 6934 Define the sum of a series with an index set of integers A. k is normally a free variable in B, i.e. B can be thought of as B(k). The definition is meaningful when A is a finite set of sequential integers (representing a finite sum over them) or a set of upper integers (representing an infinite sum, when the sum converges). The left-hand side of the union expresses the finite sum case, and the right-hand side expresses the infinite sum case. In either case, the other side of the union equals the empty set. Examples: Σk ∈ (2...4) k means 2 + 3 + 4 = 9, and Σk ∈ ℕ (1 / (2↑k)) means 1/2 + 1/4 + 1/8 + ... = 1. Note: The restrictions to ℤ force the class abstractions to be sets.
ΣkA B = ({x∣∃mn ∈ (ℤm)(A = (m...n) ⋀ x ∈ ((⟨m, + ⟩seq({⟨k, y⟩∣y = B} ↾ ℤ)) ‘n))} ∪ {x∣∃m ∈ ℤ (A = (ℤm) ⋀ (⟨m, + ⟩seq({⟨k, y⟩∣y = B} ↾ ℤ)) ⇝ x)})
 
Theoremsumex 6935 A sum is a set.
ΣkA BV
 
Theoremsumeq1 6936 Equality theorem for a sum.
(A = B → ΣkA C = ΣkB C)
 
Theoremhbsum1 6937 Bound-variable hypothesis builder for sum.
(xA → ∀k xA)    ⇒   (x ∈ ΣkA B → ∀k x ∈ ΣkA B)
 
Theoremhbsum 6938 Bound-variable hypothesis builder for sum: if x is (effectively) not free in A and B, it is not free in ΣkAB.
(yA → ∀x yA)    &   (yB → ∀x yB)    ⇒   (y ∈ ΣkA B → ∀x y ∈ ΣkA B)
 
Theoremsumeq2 6939 Equality theorem for sum.
(∀kA B = C → ΣkA B = ΣkA C)
 
Theoremcbvsum 6940 Change bound variable in a sum.
(xB → ∀k xB)    &   (xC → ∀j xC)    &   (j = kB = C)    ⇒   ΣjA B = ΣkA C
 
Theoremsumeq1i 6941 Equality inference for sum.
A = B    ⇒   ΣkA C = ΣkB C
 
Theoremsumeq2i 6942 Equality inference for sum.
(kAB = C)    ⇒   ΣkA B = ΣkA C
 
Theoremsumeq12i 6943 Equality inference for sum. (Contributed by FL, 10-Dec-2006.)
A = B    &   (kAC = D)    ⇒   ΣkA C = ΣkB D
 
Theoremsumeq1d 6944 Equality deduction for sum.
(φA = B)    ⇒   (φ → ΣkA C = ΣkB C)
 
Theoremsumeq2d 6945 Equality deduction for sum. Note that unlike sumeq2dv 6946, k may occur in φ.
(φ → ∀kA B = C)    ⇒   (φ → ΣkA B = ΣkA C)
 
Theoremsumeq2dv 6946 Equality deduction for sum.
((φkA) → B = C)    ⇒   (φ → ΣkA B = ΣkA C)
 
Theoremsumeq2sdv 6947 Equality deduction for sum.
(φB = C)    ⇒   (φ → ΣkA B = ΣkA C)
 
Theorem2sumeq2dv 6948 Equality deduction for double sum.
((φjAkB) → C = D)    ⇒   (φ → ΣjA ΣkB C = ΣjA ΣkB D)
 
Theoremsumeq12dv 6949 Equality deduction for sum.
(φA = B)    &   ((φkA) → C = D)    ⇒   (φ → ΣkA C = ΣkB D)
 
Theoremsumeq12rdv 6950 Equality deduction for sum.
(φA = B)    &   ((φkB) → C = D)    ⇒   (φ → ΣkA C = ΣkB D)
 
Theoremsumeqfv 6951 Convert a sum of function values to a sum of classes A(k).
AV    &   F = {⟨k, y⟩∣(kBy = A)}    ⇒   (CB → ΣkC (Fk) = ΣkC A)
 
Finite sums (cont.)
 
Theoremdffsum 6952 Special case of series sum over a finite index set.
(N ∈ (ℤM) → Σk ∈ (M...N)A = ((⟨M, + ⟩seq({⟨k, y⟩∣y = A} ↾ ℤ)) ‘N))
 
Theoremfsumserz 6953 A finite sum expressed in terms of a partial sum of an infinite series. The recursive definition of follows as fsum1 6959 and fsump1 6960, which should make our notation clear and from which, along with closure fsumclt 6969, we will derive the basic properties of finite sums.
FV    ⇒   (N ∈ (ℤM) → Σk ∈ (M...N)(Fk) = ((⟨M, + ⟩seqF) ‘N))
 
Theoremfsumserzf 6954 Version of fsumserz 6953 with a bound-variable hypothesis instead of a distinct variable condition.
FV    &   (xF → ∀k xF)    ⇒   (N ∈ (ℤM) → Σk ∈ (M...N)(Fk) = ((⟨M, + ⟩seqF) ‘N))
 
Theoremfsumser0f 6955 A finite sum expressed in terms of a partial sum of an infinite 0-based series.
FV    &   (xF → ∀k xF)    ⇒   (N ∈ ℕ0 → Σk ∈ (0...N)(Fk) = (( + seq0F) ‘N))
 
Theoremfsumser1f 6956 A finite sum expressed in terms of a partial sum of an infinite 1-based series.
FV    &   (xF → ∀k xF)    ⇒   (N ∈ ℕ → Σk ∈ (1...N)(Fk) = (( + seq1F) ‘N))
 
Theoremfsumserz2 6957 A finite sum expressed in terms of a partial sum of an infinite series.
AV    &   F = {⟨k, y⟩∣(k ∈ (ℤM) ⋀ y = A)}    ⇒   (N ∈ (ℤM) → Σk ∈ (M...N)A = ((⟨M, + ⟩seqF) ‘N))
 
Theoremserzfsum 6958 An infinite series in terms of finite partial sums of A(k).
AV    &   F = {⟨k, y⟩∣(k ∈ (ℤM) ⋀ y = A)}    &   G = {⟨n, z⟩∣(n ∈ (ℤM) ⋀ z = Σk ∈ (M...n)A)}    ⇒   (M ∈ ℤ → (⟨M, + ⟩seqF) = G)
 
Theoremfsum1 6959 The finite sum of A(k) from k = M to M (i.e. a sum with only one term) is B i.e. A(M).
(k = MA = B)    ⇒   ((BCM ∈ ℤ) → Σk ∈ (M...M)A = B)
 
Theoremfsump1 6960 The addition of the next term in a finite sum of A(k) is the current term plus B i.e. A(N + 1).
AV    &   BV    &   (k = (N + 1) → A = B)    ⇒   (N ∈ (ℤM) → Σk ∈ (M...(N + 1))A = (Σk ∈ (M...N)A + B))
 
Theoremfsum1f 6961 The finite sum of a term A(k) from M to M (i.e. a sum with only one term) is A(M) = B, where k is effectively not free in B.
(xB → ∀k xB)    &   (k = MA = B)    ⇒   ((BCM ∈ ℤ) → Σk ∈ (M...M)A = B)
 
Theoremfsum1slem 6962 Lemma for fsum1s 6963.
 
Theoremfsum1s 6963 The finite sum of a sequence A(k) from M to M (i.e. a sum with only one term) is A(M).
((M ∈ ℤ ⋀ ∀k ∈ (M...M)AB) → Σk ∈ (M...M)A = [M / k]A)
 
Theoremfsum1s2 6964 The finite sum of a sequence A(k) from M to M (i.e. a sum with only one term) is A(M).
((M ∈ ℤ ⋀ [M / k]AB) → Σk ∈ (M...M)A = [M / k]A)
 
Theoremfsump1f 6965 The addition of the next term in a finite sum of A(k) is the previous term plus A(N + 1) = B.
AV    &   BV    &   (xB → ∀k xB)    &   (k = (N + 1) → A = B)    ⇒   (N ∈ (ℤM) → Σk ∈ (M...(N + 1))A = (Σk ∈ (M...N)A + B))
 
Theoremfsump1slem 6966 Lemma for fsump1s 6967.
 
Theoremfsump1s 6967 The addition of the next term in a finite sum of A(k) is the previous term plus A(N + 1).
((N ∈ (ℤM) ⋀ ∀k ∈ (M...(N + 1))AB) → Σk ∈ (M...(N + 1))A = (Σk ∈ (M...N)A + [(N + 1) / k]A))
 
Theoremfsumcllem 6968 - Lemma for finite sum closures. (The "-" before "Lemma" forces the math content to be displayed in the Statement List - NM 11-Feb-2008.)
((xCyC) → (x + y) ∈ C)    ⇒   ((N ∈ (ℤM) ⋀ ∀k ∈ (M...N)AC) → Σk ∈ (M...N)AC)
 
Theoremfsumclt 6969 Closure of a finite sum of complex numbers A(k).
((N ∈ (ℤM) ⋀ ∀k ∈ (M...N)A ∈ ℂ) → Σk ∈ (M...N)A ∈ ℂ)
 
Theoremfsum0clt 6970 Closure of a finite sum of complex numbers A(k), starting at index zero.
((N ∈ ℕ0 ⋀ ∀k ∈ (0...N)A ∈ ℂ) → Σk ∈ (0...N)A ∈ ℂ)
 
Theoremfsumreclt 6971 Closure of a finite sum of reals.
((N ∈ (ℤM) ⋀ ∀k ∈ (M...N)A ∈ ℝ) → Σk ∈ (M...N)A ∈ ℝ)
 
Theoremfsum1ps 6972 Separate out the first term in a finite sum.
((N ∈ (ℤM) ⋀ M < N ⋀ ∀k ∈ (M...N)A ∈ ℂ) → Σk ∈ (M...N)A = ([M / k]A + Σk ∈ ((M + 1)...N)A))
 
Theoremfsum1p 6973 Separate out the first term in a finite sum.
(k = MA = B)    ⇒   ((N ∈ (ℤM) ⋀ M < N ⋀ ∀k ∈ (M...N)A ∈ ℂ) → Σk ∈ (M...N)A = (B + Σk ∈ ((M + 1)...N)A))
 
Theoremfsumsplit 6974 Split a finite sum into two parts. Warning: The HTML proof page is 0.6 megabyte in size.
((N ∈ ℤ ⋀ K ∈ (M...(N − 1)) ⋀ ∀k ∈ (M...N)A ∈ ℂ) → Σk ∈ (M...N)A = (Σk ∈ (M...K)A + Σk ∈ ((K + 1)...N)A))
 
Theoremfsum0split 6975 Split a finite sum into two parts.
((N ∈ ℤ ⋀ K ∈ (1...N) ⋀ ∀k ∈ (0...N)A ∈ ℂ) → Σk ∈ (0...N)A = (Σk ∈ (0...(NK))A + Σk ∈ (((NK) + 1)...N)A))
 
Theoremfsumadd 6976 The sum of two finite sums.
((N ∈ (ℤM) ⋀ ∀k ∈ (M...N)(A ∈ ℂ ⋀ B ∈ ℂ)) → Σk ∈ (M...N)(A + B) = (Σk ∈ (M...N)A + Σk ∈ (M...N)B))
 
Theoremfsum2 6977 The sum of two terms.
AV    ⇒   (M ∈ ℤ → Σk ∈ (M...(M + 1))A = ([M / k]A + [(M + 1) / k]A))
 
Theoremfsum3 6978 The sum of three terms.
AV    ⇒   (M ∈ ℤ → Σk ∈ (M...(M + 2))A = (([M / k]A + [(M + 1) / k]A) + [(M + 2) / k]A))
 
Theoremfsum4 6979 The sum of four terms.
AV    ⇒   (M ∈ ℤ → Σk ∈ (M...(M + 3))A = ((([M / k]A + [(M + 1) / k]A) + [(M + 2) / k]A) + [(M + 3) / k]A))
 
Theoremcsbfsumlem 6980 Lemma for csbfsum 6981.
 
Theoremcsbfsum 6981 Distribute substitution for classes over a finite sum.
((ACN ∈ (ℤM) ⋀ ∀k ∈ (M...N)[A / x]B ∈ ℂ) → [A / x]Σk ∈ (M...N)B = Σk ∈ (M...N)[A / x]B)
 
Theoremfsumcom 6982 Interchange order of summation. Warning: The HTML proof page is 0.6MB in size.
((K ∈ (ℤJ) ⋀ N ∈ (ℤM) ⋀ ∀j ∈ (J...K)∀m ∈ (M...N)A ∈ ℂ) → Σj ∈ (J...Km ∈ (M...N)A = Σm ∈ (M...Nj ∈ (J...K)A)
 
Theoremfsumrev 6983 Reversal of a finite sum. Warning: The HTML proof page is 0.6 MB in size.
((N ∈ (ℤM) ⋀ K ∈ ℤ ⋀ ∀j ∈ (M...N)A ∈ ℂ) → Σj ∈ (M...N)A = Σk ∈ ((KN)...(KM))[(Kk) / j]A)
 
Theoremfsumrev2 6984 Reversal of a finite sum.
((N ∈ (ℤM) ⋀ ∀j ∈ (M...N)A ∈ ℂ) → Σj ∈ (M...N)A = Σk ∈ (M...N)[((M + N) − k) / j]A)
 
Theoremfsumshft 6985 Index shift of a finite sum.
((N ∈ (ℤM) ⋀ K ∈ ℤ ⋀ ∀j ∈ (M...N)A ∈ ℂ) → Σj ∈ (M...N)A = Σk ∈ ((M + K)...(N + K))[(kK) / j]A)
 
Theoremfsumshftm 6986 Negative index shift of a finite sum.
((N ∈ (ℤM) ⋀ K ∈ ℤ ⋀ ∀j ∈ (M...N)A ∈ ℂ) → Σj ∈ (M...N)A = Σk ∈ ((MK)...(NK))[(k + K) / j]A)
 
Theoremfsummulc1 6987 A finite sum multiplied by a constant.
((N ∈ (ℤM) ⋀ C ∈ ℂ ⋀ ∀k ∈ (M...N)A ∈ ℂ) → (C · Σk ∈ (M...N)A) = Σk ∈ (M...N)(C · A))
 
Theoremfsummulc2 6988 A finite sum multiplied by a constant.
((N ∈ (ℤM) ⋀ C ∈ ℂ ⋀ ∀k ∈ (M...N)A ∈ ℂ) → (Σk ∈ (M...N)A · C) = Σk ∈ (M...N)(A · C))
 
Theoremfsumdivc 6989 A finite sum divided by a constant.
(((N ∈ (ℤM) ⋀ C ∈ ℂ) ⋀ (C ≠ 0 ⋀ ∀k ∈ (M...N)A ∈ ℂ)) → (Σk ∈ (M...N)A / C) = Σk ∈ (M...N)(A / C))
 
TheoremfsumdivcALT 6990 A finite sum divided by a constant. (An experiment: this version of fsumdivc 6989 adds 5 bytes and 233 bytes to the compressed and uncompressed proofs, but saves 540 bytes on the HTML page.)
(((N ∈ (ℤM) ⋀ C ∈ ℂ) ⋀ (C ≠ 0 ⋀ ∀k ∈ (M...N)A ∈ ℂ)) → (Σk ∈ (M...N)A / C) = Σk ∈ (M...N)(A / C))
 
Theoremfsum2mul 6991 Separate the nested sum of the product A(j) · B(m).
(((K ∈ (ℤJ) ⋀ ∀j ∈ (J...K)A ∈ ℂ) ⋀ (N ∈ (ℤM) ⋀ ∀m ∈ (M...N)B ∈ ℂ)) → Σj ∈ (J...Km ∈ (M...N)(A · B) = (Σj ∈ (J...K)A · Σm ∈ (M...N)B))
 
Theoremfsumconst 6992 The sum of constant terms (k is not free in A).
((N ∈ (ℤM) ⋀ A ∈ ℂ) → Σk ∈ (M...N)A = (((NM) + 1) · A))
 
Theoremfsum0 6993 If all of the terms of a finite sum are zero, so is the sum.
(N ∈ (ℤM) → Σk ∈ (M...N)0 = 0)
 
Theoremfsumcmp 6994 If all of the terms of finite sums compare, so do the sums.
((N ∈ (ℤM) ⋀ ∀k ∈ (M...N)(A ∈ ℝ ⋀ B ∈ ℝ ⋀ AB)) → Σk ∈ (M...N)A ≤ Σk ∈ (M...N)B)
 
Theoremfsumcmp0 6995 If all of the terms of a finite sum are nonnegative, so is the sum.
((N ∈ (ℤM) ⋀ ∀k ∈ (M...N)(A ∈ ℝ ⋀ 0 ≤ A)) → 0 ≤ Σk ∈ (M...N)A)
 
Theoremfsumcmpndx2 6996 A shorter sum of nonnegative terms is smaller than a longer one.
(((J ∈ (ℤM) ⋀ K ∈ (ℤM)) ⋀ (∀k ∈ (M...K)(A ∈ ℝ ⋀ 0 ≤ A) ⋀ JK)) → Σk ∈ (M...J)A ≤ Σk ∈ (M...K)A)
 
Theoremfsumabs 6997 Generalized triangle inequality: the absolute value of a finite sum is less than or equal to the sum of absolute values.
((N ∈ (ℤM) ⋀ ∀k ∈ (M...N)A ∈ ℂ) → (abs ‘Σk ∈ (M...N)A) ≤ Σk ∈ (M...N)(abs ‘A))
 
Theoremfsumabs2mul 6998 The sum of absolute values of the product A(j) · B(m) is less than or equal to the product of the two sums of absolute values.
(((K ∈ (ℤJ) ⋀ ∀j ∈ (J...K)A ∈ ℂ) ⋀ (N ∈ (ℤM) ⋀ ∀m ∈ (M...N)B ∈ ℂ)) → (abs ‘Σj ∈ (J...Km ∈ (M...N)(A · B)) ≤ (Σj ∈ (J...K)(abs ‘A) · Σm ∈ (M...N)(abs ‘B)))
 
Theoremserzclt 6999 Closure of partial sums of an infinite series.
FV    ⇒   ((N ∈ (ℤM) ⋀ ∀k ∈ (M...N)(Fk) ∈ ℂ) → ((⟨M, + ⟩seqF) ‘N) ∈ ℂ)
 
Theoremser0clt 7000 Closure of partial sums of a 0-based infinite series.
FV    ⇒   ((N ∈ ℕ0 ⋀ ∀k ∈ (0...N)(Fk) ∈ ℂ) → (( + seq0F) ‘N) ∈ ℂ)

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