4sqlem6 - Metamath Proof Explorer

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Theorem 4sqlem6 16881

Description: Lemma for 4sq 16902. (Contributed by Mario Carneiro, 15-Jul-2014.)

**Hypotheses**
Ref	Expression
4sqlem5.2	⊢ (𝜑 → 𝐴 ∈ ℤ)
4sqlem5.3	⊢ (𝜑 → 𝑀 ∈ ℕ)
4sqlem5.4	⊢ 𝐵 = (((𝐴 + (𝑀 / 2)) mod 𝑀) − (𝑀 / 2))

**Assertion**
Ref	Expression
4sqlem6	⊢ (𝜑 → (-(𝑀 / 2) ≤ 𝐵 ∧ 𝐵 < (𝑀 / 2)))

**Proof of Theorem 4sqlem6**
Step	Hyp	Ref	Expression
1		0red 11222	. . . 4 ⊢ (𝜑 → 0 ∈ ℝ)
2		4sqlem5.2	. . . . . . 7 ⊢ (𝜑 → 𝐴 ∈ ℤ)
3	2	zred 12671	. . . . . 6 ⊢ (𝜑 → 𝐴 ∈ ℝ)
4		4sqlem5.3	. . . . . . . 8 ⊢ (𝜑 → 𝑀 ∈ ℕ)
5	4	nnred 12232	. . . . . . 7 ⊢ (𝜑 → 𝑀 ∈ ℝ)
6	5	rehalfcld 12464	. . . . . 6 ⊢ (𝜑 → (𝑀 / 2) ∈ ℝ)
7	3, 6	readdcld 11248	. . . . 5 ⊢ (𝜑 → (𝐴 + (𝑀 / 2)) ∈ ℝ)
8	4	nnrpd 13019	. . . . 5 ⊢ (𝜑 → 𝑀 ∈ ℝ⁺)
9	7, 8	modcld 13845	. . . 4 ⊢ (𝜑 → ((𝐴 + (𝑀 / 2)) mod 𝑀) ∈ ℝ)
10		modge0 13849	. . . . 5 ⊢ (((𝐴 + (𝑀 / 2)) ∈ ℝ ∧ 𝑀 ∈ ℝ⁺) → 0 ≤ ((𝐴 + (𝑀 / 2)) mod 𝑀))
11	7, 8, 10	syl2anc 583	. . . 4 ⊢ (𝜑 → 0 ≤ ((𝐴 + (𝑀 / 2)) mod 𝑀))
12	1, 9, 6, 11	lesub1dd 11835	. . 3 ⊢ (𝜑 → (0 − (𝑀 / 2)) ≤ (((𝐴 + (𝑀 / 2)) mod 𝑀) − (𝑀 / 2)))
13		df-neg 11452	. . 3 ⊢ -(𝑀 / 2) = (0 − (𝑀 / 2))
14		4sqlem5.4	. . 3 ⊢ 𝐵 = (((𝐴 + (𝑀 / 2)) mod 𝑀) − (𝑀 / 2))
15	12, 13, 14	3brtr4g 5182	. 2 ⊢ (𝜑 → -(𝑀 / 2) ≤ 𝐵)
16		modlt 13850	. . . . . 6 ⊢ (((𝐴 + (𝑀 / 2)) ∈ ℝ ∧ 𝑀 ∈ ℝ⁺) → ((𝐴 + (𝑀 / 2)) mod 𝑀) < 𝑀)
17	7, 8, 16	syl2anc 583	. . . . 5 ⊢ (𝜑 → ((𝐴 + (𝑀 / 2)) mod 𝑀) < 𝑀)
18	4	nncnd 12233	. . . . . 6 ⊢ (𝜑 → 𝑀 ∈ ℂ)
19	18	2halvesd 12463	. . . . 5 ⊢ (𝜑 → ((𝑀 / 2) + (𝑀 / 2)) = 𝑀)
20	17, 19	breqtrrd 5176	. . . 4 ⊢ (𝜑 → ((𝐴 + (𝑀 / 2)) mod 𝑀) < ((𝑀 / 2) + (𝑀 / 2)))
21	9, 6, 6	ltsubaddd 11815	. . . 4 ⊢ (𝜑 → ((((𝐴 + (𝑀 / 2)) mod 𝑀) − (𝑀 / 2)) < (𝑀 / 2) ↔ ((𝐴 + (𝑀 / 2)) mod 𝑀) < ((𝑀 / 2) + (𝑀 / 2))))
22	20, 21	mpbird 257	. . 3 ⊢ (𝜑 → (((𝐴 + (𝑀 / 2)) mod 𝑀) − (𝑀 / 2)) < (𝑀 / 2))
23	14, 22	eqbrtrid 5183	. 2 ⊢ (𝜑 → 𝐵 < (𝑀 / 2))
24	15, 23	jca 511	1 ⊢ (𝜑 → (-(𝑀 / 2) ≤ 𝐵 ∧ 𝐵 < (𝑀 / 2)))

Colors of variables: wff setvar class

Syntax hints: → wi 4 ∧ wa 395 = wceq 1540 ∈ wcel 2105 class class class wbr 5148 (class class class)co 7412 ℝcr 11112 0cc0 11113 + caddc 11116 < clt 11253 ≤ cle 11254 − cmin 11449 -cneg 11450 / cdiv 11876 ℕcn 12217 2c2 12272 ℤcz 12563 ℝ⁺crp 12979 mod cmo 13839

This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-5 1912 ax-6 1970 ax-7 2010 ax-8 2107 ax-9 2115 ax-10 2136 ax-11 2153 ax-12 2170 ax-ext 2702 ax-sep 5299 ax-nul 5306 ax-pow 5363 ax-pr 5427 ax-un 7728 ax-cnex 11169 ax-resscn 11170 ax-1cn 11171 ax-icn 11172 ax-addcl 11173 ax-addrcl 11174 ax-mulcl 11175 ax-mulrcl 11176 ax-mulcom 11177 ax-addass 11178 ax-mulass 11179 ax-distr 11180 ax-i2m1 11181 ax-1ne0 11182 ax-1rid 11183 ax-rnegex 11184 ax-rrecex 11185 ax-cnre 11186 ax-pre-lttri 11187 ax-pre-lttrn 11188 ax-pre-ltadd 11189 ax-pre-mulgt0 11190 ax-pre-sup 11191

This theorem depends on definitions: df-bi 206 df-an 396 df-or 845 df-3or 1087 df-3an 1088 df-tru 1543 df-fal 1553 df-ex 1781 df-nf 1785 df-sb 2067 df-mo 2533 df-eu 2562 df-clab 2709 df-cleq 2723 df-clel 2809 df-nfc 2884 df-ne 2940 df-nel 3046 df-ral 3061 df-rex 3070 df-rmo 3375 df-reu 3376 df-rab 3432 df-v 3475 df-sbc 3778 df-csb 3894 df-dif 3951 df-un 3953 df-in 3955 df-ss 3965 df-pss 3967 df-nul 4323 df-if 4529 df-pw 4604 df-sn 4629 df-pr 4631 df-op 4635 df-uni 4909 df-iun 4999 df-br 5149 df-opab 5211 df-mpt 5232 df-tr 5266 df-id 5574 df-eprel 5580 df-po 5588 df-so 5589 df-fr 5631 df-we 5633 df-xp 5682 df-rel 5683 df-cnv 5684 df-co 5685 df-dm 5686 df-rn 5687 df-res 5688 df-ima 5689 df-pred 6300 df-ord 6367 df-on 6368 df-lim 6369 df-suc 6370 df-iota 6495 df-fun 6545 df-fn 6546 df-f 6547 df-f1 6548 df-fo 6549 df-f1o 6550 df-fv 6551 df-riota 7368 df-ov 7415 df-oprab 7416 df-mpo 7417 df-om 7859 df-2nd 7979 df-frecs 8269 df-wrecs 8300 df-recs 8374 df-rdg 8413 df-er 8706 df-en 8943 df-dom 8944 df-sdom 8945 df-sup 9440 df-inf 9441 df-pnf 11255 df-mnf 11256 df-xr 11257 df-ltxr 11258 df-le 11259 df-sub 11451 df-neg 11452 df-div 11877 df-nn 12218 df-2 12280 df-n0 12478 df-z 12564 df-uz 12828 df-rp 12980 df-fl 13762 df-mod 13840

This theorem is referenced by: 4sqlem7 16882 4sqlem10 16885

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