| Step | Hyp | Ref
| Expression |
| 1 | | simp1 1137 |
. . 3
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → 𝑃 ∈ ℙ) |
| 2 | | simp2l 1200 |
. . . 4
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → 𝐴 ∈ ℤ) |
| 3 | | simp3 1139 |
. . . 4
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → 𝐵 ∈ ℕ) |
| 4 | | znq 12994 |
. . . 4
⊢ ((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℕ) → (𝐴 / 𝐵) ∈ ℚ) |
| 5 | 2, 3, 4 | syl2anc 584 |
. . 3
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → (𝐴 / 𝐵) ∈ ℚ) |
| 6 | 2 | zcnd 12723 |
. . . 4
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → 𝐴 ∈ ℂ) |
| 7 | 3 | nncnd 12282 |
. . . 4
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → 𝐵 ∈ ℂ) |
| 8 | | simp2r 1201 |
. . . 4
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → 𝐴 ≠ 0) |
| 9 | 3 | nnne0d 12316 |
. . . 4
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → 𝐵 ≠ 0) |
| 10 | 6, 7, 8, 9 | divne0d 12059 |
. . 3
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → (𝐴 / 𝐵) ≠ 0) |
| 11 | | eqid 2737 |
. . . 4
⊢
sup({𝑛 ∈
ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) |
| 12 | | eqid 2737 |
. . . 4
⊢
sup({𝑛 ∈
ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ) |
| 13 | 11, 12 | pcval 16882 |
. . 3
⊢ ((𝑃 ∈ ℙ ∧ ((𝐴 / 𝐵) ∈ ℚ ∧ (𝐴 / 𝐵) ≠ 0)) → (𝑃 pCnt (𝐴 / 𝐵)) = (℩𝑧∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))))) |
| 14 | 1, 5, 10, 13 | syl12anc 837 |
. 2
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → (𝑃 pCnt (𝐴 / 𝐵)) = (℩𝑧∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))))) |
| 15 | | eqid 2737 |
. . . . . . . 8
⊢
sup({𝑛 ∈
ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) |
| 16 | 15 | pczpre 16885 |
. . . . . . 7
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0)) → (𝑃 pCnt 𝐴) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < )) |
| 17 | 16 | 3adant3 1133 |
. . . . . 6
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → (𝑃 pCnt 𝐴) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < )) |
| 18 | | nnz 12634 |
. . . . . . . . 9
⊢ (𝐵 ∈ ℕ → 𝐵 ∈
ℤ) |
| 19 | | nnne0 12300 |
. . . . . . . . 9
⊢ (𝐵 ∈ ℕ → 𝐵 ≠ 0) |
| 20 | 18, 19 | jca 511 |
. . . . . . . 8
⊢ (𝐵 ∈ ℕ → (𝐵 ∈ ℤ ∧ 𝐵 ≠ 0)) |
| 21 | | eqid 2737 |
. . . . . . . . 9
⊢
sup({𝑛 ∈
ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < ) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < ) |
| 22 | 21 | pczpre 16885 |
. . . . . . . 8
⊢ ((𝑃 ∈ ℙ ∧ (𝐵 ∈ ℤ ∧ 𝐵 ≠ 0)) → (𝑃 pCnt 𝐵) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < )) |
| 23 | 20, 22 | sylan2 593 |
. . . . . . 7
⊢ ((𝑃 ∈ ℙ ∧ 𝐵 ∈ ℕ) → (𝑃 pCnt 𝐵) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < )) |
| 24 | 23 | 3adant2 1132 |
. . . . . 6
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → (𝑃 pCnt 𝐵) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < )) |
| 25 | 17, 24 | oveq12d 7449 |
. . . . 5
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < ))) |
| 26 | | eqid 2737 |
. . . . 5
⊢ (𝐴 / 𝐵) = (𝐴 / 𝐵) |
| 27 | 25, 26 | jctil 519 |
. . . 4
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → ((𝐴 / 𝐵) = (𝐴 / 𝐵) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < )))) |
| 28 | | oveq1 7438 |
. . . . . . 7
⊢ (𝑥 = 𝐴 → (𝑥 / 𝑦) = (𝐴 / 𝑦)) |
| 29 | 28 | eqeq2d 2748 |
. . . . . 6
⊢ (𝑥 = 𝐴 → ((𝐴 / 𝐵) = (𝑥 / 𝑦) ↔ (𝐴 / 𝐵) = (𝐴 / 𝑦))) |
| 30 | | breq2 5147 |
. . . . . . . . . 10
⊢ (𝑥 = 𝐴 → ((𝑃↑𝑛) ∥ 𝑥 ↔ (𝑃↑𝑛) ∥ 𝐴)) |
| 31 | 30 | rabbidv 3444 |
. . . . . . . . 9
⊢ (𝑥 = 𝐴 → {𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥} = {𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}) |
| 32 | 31 | supeq1d 9486 |
. . . . . . . 8
⊢ (𝑥 = 𝐴 → sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < )) |
| 33 | 32 | oveq1d 7446 |
. . . . . . 7
⊢ (𝑥 = 𝐴 → (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )) = (sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))) |
| 34 | 33 | eqeq2d 2748 |
. . . . . 6
⊢ (𝑥 = 𝐴 → (((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )) ↔ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) |
| 35 | 29, 34 | anbi12d 632 |
. . . . 5
⊢ (𝑥 = 𝐴 → (((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))) ↔ ((𝐴 / 𝐵) = (𝐴 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))))) |
| 36 | | oveq2 7439 |
. . . . . . 7
⊢ (𝑦 = 𝐵 → (𝐴 / 𝑦) = (𝐴 / 𝐵)) |
| 37 | 36 | eqeq2d 2748 |
. . . . . 6
⊢ (𝑦 = 𝐵 → ((𝐴 / 𝐵) = (𝐴 / 𝑦) ↔ (𝐴 / 𝐵) = (𝐴 / 𝐵))) |
| 38 | | breq2 5147 |
. . . . . . . . . 10
⊢ (𝑦 = 𝐵 → ((𝑃↑𝑛) ∥ 𝑦 ↔ (𝑃↑𝑛) ∥ 𝐵)) |
| 39 | 38 | rabbidv 3444 |
. . . . . . . . 9
⊢ (𝑦 = 𝐵 → {𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑦} = {𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐵}) |
| 40 | 39 | supeq1d 9486 |
. . . . . . . 8
⊢ (𝑦 = 𝐵 → sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ) = sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < )) |
| 41 | 40 | oveq2d 7447 |
. . . . . . 7
⊢ (𝑦 = 𝐵 → (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )) = (sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < ))) |
| 42 | 41 | eqeq2d 2748 |
. . . . . 6
⊢ (𝑦 = 𝐵 → (((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )) ↔ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < )))) |
| 43 | 37, 42 | anbi12d 632 |
. . . . 5
⊢ (𝑦 = 𝐵 → (((𝐴 / 𝐵) = (𝐴 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))) ↔ ((𝐴 / 𝐵) = (𝐴 / 𝐵) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < ))))) |
| 44 | 35, 43 | rspc2ev 3635 |
. . . 4
⊢ ((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℕ ∧ ((𝐴 / 𝐵) = (𝐴 / 𝐵) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝐴}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝐵}, ℝ, < )))) → ∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) |
| 45 | 2, 3, 27, 44 | syl3anc 1373 |
. . 3
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → ∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) |
| 46 | | ovex 7464 |
. . . 4
⊢ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) ∈ V |
| 47 | 11, 12 | pceu 16884 |
. . . . 5
⊢ ((𝑃 ∈ ℙ ∧ ((𝐴 / 𝐵) ∈ ℚ ∧ (𝐴 / 𝐵) ≠ 0)) → ∃!𝑧∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) |
| 48 | 1, 5, 10, 47 | syl12anc 837 |
. . . 4
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → ∃!𝑧∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) |
| 49 | | eqeq1 2741 |
. . . . . . 7
⊢ (𝑧 = ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) → (𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )) ↔ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) |
| 50 | 49 | anbi2d 630 |
. . . . . 6
⊢ (𝑧 = ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) → (((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))) ↔ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))))) |
| 51 | 50 | 2rexbidv 3222 |
. . . . 5
⊢ (𝑧 = ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) → (∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))) ↔ ∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))))) |
| 52 | 51 | iota2 6550 |
. . . 4
⊢ ((((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) ∈ V ∧ ∃!𝑧∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) → (∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))) ↔ (℩𝑧∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) = ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)))) |
| 53 | 46, 48, 52 | sylancr 587 |
. . 3
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → (∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)) = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < ))) ↔ (℩𝑧∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) = ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵)))) |
| 54 | 45, 53 | mpbid 232 |
. 2
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → (℩𝑧∃𝑥 ∈ ℤ ∃𝑦 ∈ ℕ ((𝐴 / 𝐵) = (𝑥 / 𝑦) ∧ 𝑧 = (sup({𝑛 ∈ ℕ0 ∣ (𝑃↑𝑛) ∥ 𝑥}, ℝ, < ) − sup({𝑛 ∈ ℕ0
∣ (𝑃↑𝑛) ∥ 𝑦}, ℝ, < )))) = ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵))) |
| 55 | 14, 54 | eqtrd 2777 |
1
⊢ ((𝑃 ∈ ℙ ∧ (𝐴 ∈ ℤ ∧ 𝐴 ≠ 0) ∧ 𝐵 ∈ ℕ) → (𝑃 pCnt (𝐴 / 𝐵)) = ((𝑃 pCnt 𝐴) − (𝑃 pCnt 𝐵))) |