Proof of Theorem itgreval
| Step | Hyp | Ref
| Expression |
| 1 | | iblrelem.1 |
. . 3
⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → 𝐵 ∈ ℝ) |
| 2 | | itgreval.2 |
. . 3
⊢ (𝜑 → (𝑥 ∈ 𝐴 ↦ 𝐵) ∈
𝐿1) |
| 3 | 1, 2 | itgrevallem1 25753 |
. 2
⊢ (𝜑 → ∫𝐴𝐵 d𝑥 = ((∫2‘(𝑥 ∈ ℝ ↦
if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0))) −
(∫2‘(𝑥
∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0))))) |
| 4 | | 0re 11242 |
. . . . . 6
⊢ 0 ∈
ℝ |
| 5 | | ifcl 4551 |
. . . . . 6
⊢ ((𝐵 ∈ ℝ ∧ 0 ∈
ℝ) → if(0 ≤ 𝐵, 𝐵, 0) ∈ ℝ) |
| 6 | 1, 4, 5 | sylancl 586 |
. . . . 5
⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → if(0 ≤ 𝐵, 𝐵, 0) ∈ ℝ) |
| 7 | 1 | iblrelem 25749 |
. . . . . . . . 9
⊢ (𝜑 → ((𝑥 ∈ 𝐴 ↦ 𝐵) ∈ 𝐿1 ↔
((𝑥 ∈ 𝐴 ↦ 𝐵) ∈ MblFn ∧
(∫2‘(𝑥
∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0))) ∈ ℝ ∧
(∫2‘(𝑥
∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0))) ∈ ℝ))) |
| 8 | 2, 7 | mpbid 232 |
. . . . . . . 8
⊢ (𝜑 → ((𝑥 ∈ 𝐴 ↦ 𝐵) ∈ MblFn ∧
(∫2‘(𝑥
∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0))) ∈ ℝ ∧
(∫2‘(𝑥
∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0))) ∈ ℝ)) |
| 9 | 8 | simp1d 1142 |
. . . . . . 7
⊢ (𝜑 → (𝑥 ∈ 𝐴 ↦ 𝐵) ∈ MblFn) |
| 10 | 1, 9 | mbfpos 25609 |
. . . . . 6
⊢ (𝜑 → (𝑥 ∈ 𝐴 ↦ if(0 ≤ 𝐵, 𝐵, 0)) ∈ MblFn) |
| 11 | | ifan 4559 |
. . . . . . . . 9
⊢ if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0) = if(𝑥 ∈ 𝐴, if(0 ≤ 𝐵, 𝐵, 0), 0) |
| 12 | 11 | mpteq2i 5222 |
. . . . . . . 8
⊢ (𝑥 ∈ ℝ ↦
if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0)) = (𝑥 ∈ ℝ ↦ if(𝑥 ∈ 𝐴, if(0 ≤ 𝐵, 𝐵, 0), 0)) |
| 13 | 12 | fveq2i 6884 |
. . . . . . 7
⊢
(∫2‘(𝑥 ∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0))) = (∫2‘(𝑥 ∈ ℝ ↦ if(𝑥 ∈ 𝐴, if(0 ≤ 𝐵, 𝐵, 0), 0))) |
| 14 | 8 | simp2d 1143 |
. . . . . . 7
⊢ (𝜑 →
(∫2‘(𝑥
∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0))) ∈ ℝ) |
| 15 | 13, 14 | eqeltrrid 2840 |
. . . . . 6
⊢ (𝜑 →
(∫2‘(𝑥
∈ ℝ ↦ if(𝑥
∈ 𝐴, if(0 ≤ 𝐵, 𝐵, 0), 0))) ∈ ℝ) |
| 16 | | max1 13206 |
. . . . . . . 8
⊢ ((0
∈ ℝ ∧ 𝐵
∈ ℝ) → 0 ≤ if(0 ≤ 𝐵, 𝐵, 0)) |
| 17 | 4, 1, 16 | sylancr 587 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → 0 ≤ if(0 ≤ 𝐵, 𝐵, 0)) |
| 18 | 6, 17 | iblpos 25751 |
. . . . . 6
⊢ (𝜑 → ((𝑥 ∈ 𝐴 ↦ if(0 ≤ 𝐵, 𝐵, 0)) ∈ 𝐿1 ↔
((𝑥 ∈ 𝐴 ↦ if(0 ≤ 𝐵, 𝐵, 0)) ∈ MblFn ∧
(∫2‘(𝑥
∈ ℝ ↦ if(𝑥
∈ 𝐴, if(0 ≤ 𝐵, 𝐵, 0), 0))) ∈
ℝ))) |
| 19 | 10, 15, 18 | mpbir2and 713 |
. . . . 5
⊢ (𝜑 → (𝑥 ∈ 𝐴 ↦ if(0 ≤ 𝐵, 𝐵, 0)) ∈
𝐿1) |
| 20 | 6, 19, 17 | itgposval 25754 |
. . . 4
⊢ (𝜑 → ∫𝐴if(0 ≤ 𝐵, 𝐵, 0) d𝑥 = (∫2‘(𝑥 ∈ ℝ ↦ if(𝑥 ∈ 𝐴, if(0 ≤ 𝐵, 𝐵, 0), 0)))) |
| 21 | 20, 13 | eqtr4di 2789 |
. . 3
⊢ (𝜑 → ∫𝐴if(0 ≤ 𝐵, 𝐵, 0) d𝑥 = (∫2‘(𝑥 ∈ ℝ ↦
if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0)))) |
| 22 | 1 | renegcld 11669 |
. . . . . 6
⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → -𝐵 ∈ ℝ) |
| 23 | | ifcl 4551 |
. . . . . 6
⊢ ((-𝐵 ∈ ℝ ∧ 0 ∈
ℝ) → if(0 ≤ -𝐵, -𝐵, 0) ∈ ℝ) |
| 24 | 22, 4, 23 | sylancl 586 |
. . . . 5
⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → if(0 ≤ -𝐵, -𝐵, 0) ∈ ℝ) |
| 25 | 1, 9 | mbfneg 25608 |
. . . . . . 7
⊢ (𝜑 → (𝑥 ∈ 𝐴 ↦ -𝐵) ∈ MblFn) |
| 26 | 22, 25 | mbfpos 25609 |
. . . . . 6
⊢ (𝜑 → (𝑥 ∈ 𝐴 ↦ if(0 ≤ -𝐵, -𝐵, 0)) ∈ MblFn) |
| 27 | | ifan 4559 |
. . . . . . . . 9
⊢ if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0) = if(𝑥 ∈ 𝐴, if(0 ≤ -𝐵, -𝐵, 0), 0) |
| 28 | 27 | mpteq2i 5222 |
. . . . . . . 8
⊢ (𝑥 ∈ ℝ ↦
if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0)) = (𝑥 ∈ ℝ ↦ if(𝑥 ∈ 𝐴, if(0 ≤ -𝐵, -𝐵, 0), 0)) |
| 29 | 28 | fveq2i 6884 |
. . . . . . 7
⊢
(∫2‘(𝑥 ∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0))) = (∫2‘(𝑥 ∈ ℝ ↦ if(𝑥 ∈ 𝐴, if(0 ≤ -𝐵, -𝐵, 0), 0))) |
| 30 | 8 | simp3d 1144 |
. . . . . . 7
⊢ (𝜑 →
(∫2‘(𝑥
∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0))) ∈ ℝ) |
| 31 | 29, 30 | eqeltrrid 2840 |
. . . . . 6
⊢ (𝜑 →
(∫2‘(𝑥
∈ ℝ ↦ if(𝑥
∈ 𝐴, if(0 ≤ -𝐵, -𝐵, 0), 0))) ∈ ℝ) |
| 32 | | max1 13206 |
. . . . . . . 8
⊢ ((0
∈ ℝ ∧ -𝐵
∈ ℝ) → 0 ≤ if(0 ≤ -𝐵, -𝐵, 0)) |
| 33 | 4, 22, 32 | sylancr 587 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → 0 ≤ if(0 ≤ -𝐵, -𝐵, 0)) |
| 34 | 24, 33 | iblpos 25751 |
. . . . . 6
⊢ (𝜑 → ((𝑥 ∈ 𝐴 ↦ if(0 ≤ -𝐵, -𝐵, 0)) ∈ 𝐿1 ↔
((𝑥 ∈ 𝐴 ↦ if(0 ≤ -𝐵, -𝐵, 0)) ∈ MblFn ∧
(∫2‘(𝑥
∈ ℝ ↦ if(𝑥
∈ 𝐴, if(0 ≤ -𝐵, -𝐵, 0), 0))) ∈
ℝ))) |
| 35 | 26, 31, 34 | mpbir2and 713 |
. . . . 5
⊢ (𝜑 → (𝑥 ∈ 𝐴 ↦ if(0 ≤ -𝐵, -𝐵, 0)) ∈
𝐿1) |
| 36 | 24, 35, 33 | itgposval 25754 |
. . . 4
⊢ (𝜑 → ∫𝐴if(0 ≤ -𝐵, -𝐵, 0) d𝑥 = (∫2‘(𝑥 ∈ ℝ ↦ if(𝑥 ∈ 𝐴, if(0 ≤ -𝐵, -𝐵, 0), 0)))) |
| 37 | 36, 29 | eqtr4di 2789 |
. . 3
⊢ (𝜑 → ∫𝐴if(0 ≤ -𝐵, -𝐵, 0) d𝑥 = (∫2‘(𝑥 ∈ ℝ ↦
if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0)))) |
| 38 | 21, 37 | oveq12d 7428 |
. 2
⊢ (𝜑 → (∫𝐴if(0 ≤ 𝐵, 𝐵, 0) d𝑥 − ∫𝐴if(0 ≤ -𝐵, -𝐵, 0) d𝑥) = ((∫2‘(𝑥 ∈ ℝ ↦
if((𝑥 ∈ 𝐴 ∧ 0 ≤ 𝐵), 𝐵, 0))) −
(∫2‘(𝑥
∈ ℝ ↦ if((𝑥 ∈ 𝐴 ∧ 0 ≤ -𝐵), -𝐵, 0))))) |
| 39 | 3, 38 | eqtr4d 2774 |
1
⊢ (𝜑 → ∫𝐴𝐵 d𝑥 = (∫𝐴if(0 ≤ 𝐵, 𝐵, 0) d𝑥 − ∫𝐴if(0 ≤ -𝐵, -𝐵, 0) d𝑥)) |