Theorem List for Intuitionistic Logic Explorer - 1001-1100 *Has distinct variable
group(s)
| Type | Label | Description |
| Statement |
| |
| Theorem | ifpnst 1001 |
Conditional operator for the negation of a proposition. (Contributed by
BJ, 30-Sep-2019.) (Proof shortened by Wolf Lammen, 5-May-2024.)
|
| ⊢ (STAB 𝜑 → (if-(𝜑, 𝜓, 𝜒) ↔ if-(¬ 𝜑, 𝜒, 𝜓))) |
| |
| Theorem | ifptru 1002 |
Value of the conditional operator for propositions when its first argument
is true. Analogue for propositions of iftrue 3645. This is essentially
dedlema 982. (Contributed by BJ, 20-Sep-2019.) (Proof
shortened by Wolf
Lammen, 10-Jul-2020.)
|
| ⊢ (𝜑 → (if-(𝜑, 𝜓, 𝜒) ↔ 𝜓)) |
| |
| Theorem | ifpfal 1003 |
Value of the conditional operator for propositions when its first argument
is false. Analogue for propositions of iffalse 3648. This is essentially
dedlemb 983. (Contributed by BJ, 20-Sep-2019.) (Proof
shortened by Wolf
Lammen, 25-Jun-2020.)
|
| ⊢ (¬ 𝜑 → (if-(𝜑, 𝜓, 𝜒) ↔ 𝜒)) |
| |
| Theorem | ifpiddc 1004 |
Value of the conditional operator for propositions when the same
proposition is returned in either case. Analogue for propositions of
ifiddc 3676. (Contributed by BJ, 20-Sep-2019.)
|
| ⊢ (DECID 𝜑 → (if-(𝜑, 𝜓, 𝜓) ↔ 𝜓)) |
| |
| Theorem | ifpbi123d 1005 |
Equivalence deduction for conditional operator for propositions.
(Contributed by AV, 30-Dec-2020.) (Proof shortened by Wolf Lammen,
17-Apr-2024.)
|
| ⊢ (𝜑 → (𝜓 ↔ 𝜏)) & ⊢ (𝜑 → (𝜒 ↔ 𝜂)) & ⊢ (𝜑 → (𝜃 ↔ 𝜁)) ⇒ ⊢ (𝜑 → (if-(𝜓, 𝜒, 𝜃) ↔ if-(𝜏, 𝜂, 𝜁))) |
| |
| Theorem | ifpbi23d 1006 |
Equivalence deduction for conditional operator for propositions.
Convenience theorem for a frequent case. (Contributed by Wolf Lammen,
28-Apr-2024.)
|
| ⊢ (𝜑 → (𝜒 ↔ 𝜂)) & ⊢ (𝜑 → (𝜃 ↔ 𝜁)) ⇒ ⊢ (𝜑 → (if-(𝜓, 𝜒, 𝜃) ↔ if-(𝜓, 𝜂, 𝜁))) |
| |
| Theorem | 1fpid3 1007 |
The value of the conditional operator for propositions is its third
argument if the first and second argument imply the third argument.
(Contributed by AV, 4-Apr-2021.)
|
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (if-(𝜑, 𝜓, 𝜒) → 𝜒) |
| |
| 1.2.12 Abbreviated conjunction and disjunction
of three wff's
|
| |
| Syntax | w3o 1008 |
Extend wff definition to include 3-way disjunction ('or').
|
| wff (𝜑 ∨ 𝜓 ∨ 𝜒) |
| |
| Syntax | w3a 1009 |
Extend wff definition to include 3-way conjunction ('and').
|
| wff (𝜑 ∧ 𝜓 ∧ 𝜒) |
| |
| Definition | df-3or 1010 |
Define disjunction ('or') of 3 wff's. Definition *2.33 of
[WhiteheadRussell] p. 105. This
abbreviation reduces the number of
parentheses and emphasizes that the order of bracketing is not important
by virtue of the associative law orass 779. (Contributed by NM,
8-Apr-1994.)
|
| ⊢ ((𝜑 ∨ 𝜓 ∨ 𝜒) ↔ ((𝜑 ∨ 𝜓) ∨ 𝜒)) |
| |
| Definition | df-3an 1011 |
Define conjunction ('and') of 3 wff.s. Definition *4.34 of
[WhiteheadRussell] p. 118. This
abbreviation reduces the number of
parentheses and emphasizes that the order of bracketing is not important
by virtue of the associative law anass 405. (Contributed by NM,
8-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ((𝜑 ∧ 𝜓) ∧ 𝜒)) |
| |
| Theorem | 3orass 1012 |
Associative law for triple disjunction. (Contributed by NM,
8-Apr-1994.)
|
| ⊢ ((𝜑 ∨ 𝜓 ∨ 𝜒) ↔ (𝜑 ∨ (𝜓 ∨ 𝜒))) |
| |
| Theorem | 3anass 1013 |
Associative law for triple conjunction. (Contributed by NM,
8-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜑 ∧ (𝜓 ∧ 𝜒))) |
| |
| Theorem | 3anrot 1014 |
Rotation law for triple conjunction. (Contributed by NM, 8-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜓 ∧ 𝜒 ∧ 𝜑)) |
| |
| Theorem | 3orrot 1015 |
Rotation law for triple disjunction. (Contributed by NM, 4-Apr-1995.)
|
| ⊢ ((𝜑 ∨ 𝜓 ∨ 𝜒) ↔ (𝜓 ∨ 𝜒 ∨ 𝜑)) |
| |
| Theorem | 3ancoma 1016 |
Commutation law for triple conjunction. (Contributed by NM,
21-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜓 ∧ 𝜑 ∧ 𝜒)) |
| |
| Theorem | 3ancomb 1017 |
Commutation law for triple conjunction. (Contributed by NM,
21-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜑 ∧ 𝜒 ∧ 𝜓)) |
| |
| Theorem | 3orcomb 1018 |
Commutation law for triple disjunction. (Contributed by Scott Fenton,
20-Apr-2011.)
|
| ⊢ ((𝜑 ∨ 𝜓 ∨ 𝜒) ↔ (𝜑 ∨ 𝜒 ∨ 𝜓)) |
| |
| Theorem | 3anrev 1019 |
Reversal law for triple conjunction. (Contributed by NM, 21-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜒 ∧ 𝜓 ∧ 𝜑)) |
| |
| Theorem | 3anan32 1020 |
Convert triple conjunction to conjunction, then commute. (Contributed by
Jonathan Ben-Naim, 3-Jun-2011.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ((𝜑 ∧ 𝜒) ∧ 𝜓)) |
| |
| Theorem | 3anan12 1021 |
Convert triple conjunction to conjunction, then commute. (Contributed by
Jonathan Ben-Naim, 3-Jun-2011.) (Proof shortened by Andrew Salmon,
14-Jun-2011.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒))) |
| |
| Theorem | anandi3 1022 |
Distribution of triple conjunction over conjunction. (Contributed by
David A. Wheeler, 4-Nov-2018.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒))) |
| |
| Theorem | anandi3r 1023 |
Distribution of triple conjunction over conjunction. (Contributed by
David A. Wheeler, 4-Nov-2018.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ ((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜓))) |
| |
| Theorem | 3ioran 1024 |
Negated triple disjunction as triple conjunction. (Contributed by Scott
Fenton, 19-Apr-2011.)
|
| ⊢ (¬ (𝜑 ∨ 𝜓 ∨ 𝜒) ↔ (¬ 𝜑 ∧ ¬ 𝜓 ∧ ¬ 𝜒)) |
| |
| Theorem | 3simpa 1025 |
Simplification of triple conjunction. (Contributed by NM,
21-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → (𝜑 ∧ 𝜓)) |
| |
| Theorem | 3simpb 1026 |
Simplification of triple conjunction. (Contributed by NM,
21-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → (𝜑 ∧ 𝜒)) |
| |
| Theorem | 3simpc 1027 |
Simplification of triple conjunction. (Contributed by NM, 21-Apr-1994.)
(Proof shortened by Andrew Salmon, 13-May-2011.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → (𝜓 ∧ 𝜒)) |
| |
| Theorem | simp1 1028 |
Simplification of triple conjunction. (Contributed by NM,
21-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜑) |
| |
| Theorem | simp2 1029 |
Simplification of triple conjunction. (Contributed by NM,
21-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜓) |
| |
| Theorem | simp3 1030 |
Simplification of triple conjunction. (Contributed by NM,
21-Apr-1994.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜒) |
| |
| Theorem | simpl1 1031 |
Simplification rule. (Contributed by Jeff Hankins, 17-Nov-2009.)
|
| ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜑) |
| |
| Theorem | simpl2 1032 |
Simplification rule. (Contributed by Jeff Hankins, 17-Nov-2009.)
|
| ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜓) |
| |
| Theorem | simpl3 1033 |
Simplification rule. (Contributed by Jeff Hankins, 17-Nov-2009.)
|
| ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜒) |
| |
| Theorem | simpr1 1034 |
Simplification rule. (Contributed by Jeff Hankins, 17-Nov-2009.)
|
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃)) → 𝜓) |
| |
| Theorem | simpr2 1035 |
Simplification rule. (Contributed by Jeff Hankins, 17-Nov-2009.)
|
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃)) → 𝜒) |
| |
| Theorem | simpr3 1036 |
Simplification rule. (Contributed by Jeff Hankins, 17-Nov-2009.)
|
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃)) → 𝜃) |
| |
| Theorem | simp1i 1037 |
Infer a conjunct from a triple conjunction. (Contributed by NM,
19-Apr-2005.)
|
| ⊢ (𝜑 ∧ 𝜓 ∧ 𝜒) ⇒ ⊢ 𝜑 |
| |
| Theorem | simp2i 1038 |
Infer a conjunct from a triple conjunction. (Contributed by NM,
19-Apr-2005.)
|
| ⊢ (𝜑 ∧ 𝜓 ∧ 𝜒) ⇒ ⊢ 𝜓 |
| |
| Theorem | simp3i 1039 |
Infer a conjunct from a triple conjunction. (Contributed by NM,
19-Apr-2005.)
|
| ⊢ (𝜑 ∧ 𝜓 ∧ 𝜒) ⇒ ⊢ 𝜒 |
| |
| Theorem | simp1d 1040 |
Deduce a conjunct from a triple conjunction. (Contributed by NM,
4-Sep-2005.)
|
| ⊢ (𝜑 → (𝜓 ∧ 𝜒 ∧ 𝜃)) ⇒ ⊢ (𝜑 → 𝜓) |
| |
| Theorem | simp2d 1041 |
Deduce a conjunct from a triple conjunction. (Contributed by NM,
4-Sep-2005.)
|
| ⊢ (𝜑 → (𝜓 ∧ 𝜒 ∧ 𝜃)) ⇒ ⊢ (𝜑 → 𝜒) |
| |
| Theorem | simp3d 1042 |
Deduce a conjunct from a triple conjunction. (Contributed by NM,
4-Sep-2005.)
|
| ⊢ (𝜑 → (𝜓 ∧ 𝜒 ∧ 𝜃)) ⇒ ⊢ (𝜑 → 𝜃) |
| |
| Theorem | simp1bi 1043 |
Deduce a conjunct from a triple conjunction. (Contributed by Jonathan
Ben-Naim, 3-Jun-2011.)
|
| ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒 ∧ 𝜃)) ⇒ ⊢ (𝜑 → 𝜓) |
| |
| Theorem | simp2bi 1044 |
Deduce a conjunct from a triple conjunction. (Contributed by Jonathan
Ben-Naim, 3-Jun-2011.)
|
| ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒 ∧ 𝜃)) ⇒ ⊢ (𝜑 → 𝜒) |
| |
| Theorem | simp3bi 1045 |
Deduce a conjunct from a triple conjunction. (Contributed by Jonathan
Ben-Naim, 3-Jun-2011.)
|
| ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒 ∧ 𝜃)) ⇒ ⊢ (𝜑 → 𝜃) |
| |
| Theorem | 3adant1 1046 |
Deduction adding a conjunct to antecedent. (Contributed by NM,
16-Jul-1995.)
|
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜃 ∧ 𝜑 ∧ 𝜓) → 𝜒) |
| |
| Theorem | 3adant2 1047 |
Deduction adding a conjunct to antecedent. (Contributed by NM,
16-Jul-1995.)
|
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜃 ∧ 𝜓) → 𝜒) |
| |
| Theorem | 3adant3 1048 |
Deduction adding a conjunct to antecedent. (Contributed by NM,
16-Jul-1995.)
|
| ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜒) |
| |
| Theorem | 3ad2ant1 1049 |
Deduction adding conjuncts to an antecedent. (Contributed by NM,
21-Apr-2005.)
|
| ⊢ (𝜑 → 𝜒) ⇒ ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜃) → 𝜒) |
| |
| Theorem | 3ad2ant2 1050 |
Deduction adding conjuncts to an antecedent. (Contributed by NM,
21-Apr-2005.)
|
| ⊢ (𝜑 → 𝜒) ⇒ ⊢ ((𝜓 ∧ 𝜑 ∧ 𝜃) → 𝜒) |
| |
| Theorem | 3ad2ant3 1051 |
Deduction adding conjuncts to an antecedent. (Contributed by NM,
21-Apr-2005.)
|
| ⊢ (𝜑 → 𝜒) ⇒ ⊢ ((𝜓 ∧ 𝜃 ∧ 𝜑) → 𝜒) |
| |
| Theorem | simp1l 1052 |
Simplification of triple conjunction. (Contributed by NM, 9-Nov-2011.)
|
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃) → 𝜑) |
| |
| Theorem | simp1r 1053 |
Simplification of triple conjunction. (Contributed by NM, 9-Nov-2011.)
|
| ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃) → 𝜓) |
| |
| Theorem | simp2l 1054 |
Simplification of triple conjunction. (Contributed by NM, 9-Nov-2011.)
|
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜓) |
| |
| Theorem | simp2r 1055 |
Simplification of triple conjunction. (Contributed by NM, 9-Nov-2011.)
|
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜒) |
| |
| Theorem | simp3l 1056 |
Simplification of triple conjunction. (Contributed by NM, 9-Nov-2011.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ (𝜒 ∧ 𝜃)) → 𝜒) |
| |
| Theorem | simp3r 1057 |
Simplification of triple conjunction. (Contributed by NM, 9-Nov-2011.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ (𝜒 ∧ 𝜃)) → 𝜃) |
| |
| Theorem | simp11 1058 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃 ∧ 𝜏) → 𝜑) |
| |
| Theorem | simp12 1059 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃 ∧ 𝜏) → 𝜓) |
| |
| Theorem | simp13 1060 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃 ∧ 𝜏) → 𝜒) |
| |
| Theorem | simp21 1061 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜓) |
| |
| Theorem | simp22 1062 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜒) |
| |
| Theorem | simp23 1063 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜃) |
| |
| Theorem | simp31 1064 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ (𝜒 ∧ 𝜃 ∧ 𝜏)) → 𝜒) |
| |
| Theorem | simp32 1065 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ (𝜒 ∧ 𝜃 ∧ 𝜏)) → 𝜃) |
| |
| Theorem | simp33 1066 |
Simplification of doubly triple conjunction. (Contributed by NM,
17-Nov-2011.)
|
| ⊢ ((𝜑 ∧ 𝜓 ∧ (𝜒 ∧ 𝜃 ∧ 𝜏)) → 𝜏) |
| |
| Theorem | simpll1 1067 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) → 𝜑) |
| |
| Theorem | simpll2 1068 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) → 𝜓) |
| |
| Theorem | simpll3 1069 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) → 𝜒) |
| |
| Theorem | simplr1 1070 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜃 ∧ (𝜑 ∧ 𝜓 ∧ 𝜒)) ∧ 𝜏) → 𝜑) |
| |
| Theorem | simplr2 1071 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜃 ∧ (𝜑 ∧ 𝜓 ∧ 𝜒)) ∧ 𝜏) → 𝜓) |
| |
| Theorem | simplr3 1072 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜃 ∧ (𝜑 ∧ 𝜓 ∧ 𝜒)) ∧ 𝜏) → 𝜒) |
| |
| Theorem | simprl1 1073 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ ((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃)) → 𝜑) |
| |
| Theorem | simprl2 1074 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ ((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃)) → 𝜓) |
| |
| Theorem | simprl3 1075 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ ((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃)) → 𝜒) |
| |
| Theorem | simprr1 1076 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ (𝜃 ∧ (𝜑 ∧ 𝜓 ∧ 𝜒))) → 𝜑) |
| |
| Theorem | simprr2 1077 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ (𝜃 ∧ (𝜑 ∧ 𝜓 ∧ 𝜒))) → 𝜓) |
| |
| Theorem | simprr3 1078 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ (𝜃 ∧ (𝜑 ∧ 𝜓 ∧ 𝜒))) → 𝜒) |
| |
| Theorem | simpl1l 1079 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜑) |
| |
| Theorem | simpl1r 1080 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃) ∧ 𝜏) → 𝜓) |
| |
| Theorem | simpl2l 1081 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜒 ∧ (𝜑 ∧ 𝜓) ∧ 𝜃) ∧ 𝜏) → 𝜑) |
| |
| Theorem | simpl2r 1082 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜒 ∧ (𝜑 ∧ 𝜓) ∧ 𝜃) ∧ 𝜏) → 𝜓) |
| |
| Theorem | simpl3l 1083 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜒 ∧ 𝜃 ∧ (𝜑 ∧ 𝜓)) ∧ 𝜏) → 𝜑) |
| |
| Theorem | simpl3r 1084 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜒 ∧ 𝜃 ∧ (𝜑 ∧ 𝜓)) ∧ 𝜏) → 𝜓) |
| |
| Theorem | simpr1l 1085 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ ((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃)) → 𝜑) |
| |
| Theorem | simpr1r 1086 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ ((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃)) → 𝜓) |
| |
| Theorem | simpr2l 1087 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ (𝜒 ∧ (𝜑 ∧ 𝜓) ∧ 𝜃)) → 𝜑) |
| |
| Theorem | simpr2r 1088 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ (𝜒 ∧ (𝜑 ∧ 𝜓) ∧ 𝜃)) → 𝜓) |
| |
| Theorem | simpr3l 1089 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ (𝜒 ∧ 𝜃 ∧ (𝜑 ∧ 𝜓))) → 𝜑) |
| |
| Theorem | simpr3r 1090 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜏 ∧ (𝜒 ∧ 𝜃 ∧ (𝜑 ∧ 𝜓))) → 𝜓) |
| |
| Theorem | simp1ll 1091 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ 𝜃 ∧ 𝜏) → 𝜑) |
| |
| Theorem | simp1lr 1092 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ 𝜃 ∧ 𝜏) → 𝜓) |
| |
| Theorem | simp1rl 1093 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜒 ∧ (𝜑 ∧ 𝜓)) ∧ 𝜃 ∧ 𝜏) → 𝜑) |
| |
| Theorem | simp1rr 1094 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ (((𝜒 ∧ (𝜑 ∧ 𝜓)) ∧ 𝜃 ∧ 𝜏) → 𝜓) |
| |
| Theorem | simp2ll 1095 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜃 ∧ ((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ 𝜏) → 𝜑) |
| |
| Theorem | simp2lr 1096 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜃 ∧ ((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ 𝜏) → 𝜓) |
| |
| Theorem | simp2rl 1097 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜃 ∧ (𝜒 ∧ (𝜑 ∧ 𝜓)) ∧ 𝜏) → 𝜑) |
| |
| Theorem | simp2rr 1098 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜃 ∧ (𝜒 ∧ (𝜑 ∧ 𝜓)) ∧ 𝜏) → 𝜓) |
| |
| Theorem | simp3ll 1099 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜃 ∧ 𝜏 ∧ ((𝜑 ∧ 𝜓) ∧ 𝜒)) → 𝜑) |
| |
| Theorem | simp3lr 1100 |
Simplification of conjunction. (Contributed by NM, 9-Mar-2012.)
|
| ⊢ ((𝜃 ∧ 𝜏 ∧ ((𝜑 ∧ 𝜓) ∧ 𝜒)) → 𝜓) |