Theorem List for Intuitionistic Logic Explorer - 11101-11200 *Has distinct variable
group(s)
| Type | Label | Description |
| Statement |
| |
| Definition | df-word 11101* |
Define the class of words over a set. A word (sometimes also called a
string) is a finite sequence of symbols from a set (alphabet)
𝑆.
Definition in Section 9.1 of [AhoHopUll] p. 318. The domain is forced
to be an initial segment of ℕ0
so that two words with the same
symbols in the same order be equal. The set Word 𝑆 is sometimes
denoted by S*, using the Kleene star, although the Kleene star, or
Kleene closure, is sometimes reserved to denote an operation on
languages. The set Word 𝑆 equipped with concatenation is the
free
monoid over 𝑆, and the monoid unit is the empty
word. (Contributed
by FL, 14-Jan-2014.) (Revised by Stefan O'Rear, 14-Aug-2015.) (Revised
by Mario Carneiro, 26-Feb-2016.)
|
| ⊢ Word 𝑆 = {𝑤 ∣ ∃𝑙 ∈ ℕ0 𝑤:(0..^𝑙)⟶𝑆} |
| |
| Theorem | iswrd 11102* |
Property of being a word over a set with an existential quantifier over
the length. (Contributed by Stefan O'Rear, 15-Aug-2015.) (Revised by
Mario Carneiro, 26-Feb-2016.) (Proof shortened by AV, 13-May-2020.)
|
| ⊢ (𝑊 ∈ Word 𝑆 ↔ ∃𝑙 ∈ ℕ0 𝑊:(0..^𝑙)⟶𝑆) |
| |
| Theorem | wrdval 11103* |
Value of the set of words over a set. (Contributed by Stefan O'Rear,
10-Aug-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
|
| ⊢ (𝑆 ∈ 𝑉 → Word 𝑆 = ∪
𝑙 ∈
ℕ0 (𝑆
↑𝑚 (0..^𝑙))) |
| |
| Theorem | lencl 11104 |
The length of a word is a nonnegative integer. This corresponds to the
definition in Section 9.1 of [AhoHopUll] p. 318. (Contributed by Stefan
O'Rear, 27-Aug-2015.)
|
| ⊢ (𝑊 ∈ Word 𝑆 → (♯‘𝑊) ∈
ℕ0) |
| |
| Theorem | iswrdinn0 11105 |
A zero-based sequence is a word. (Contributed by Stefan O'Rear,
15-Aug-2015.) (Revised by Mario Carneiro, 26-Feb-2016.) (Revised by
Jim Kingdon, 16-Aug-2025.)
|
| ⊢ ((𝑊:(0..^𝐿)⟶𝑆 ∧ 𝐿 ∈ ℕ0) → 𝑊 ∈ Word 𝑆) |
| |
| Theorem | wrdf 11106 |
A word is a zero-based sequence with a recoverable upper limit.
(Contributed by Stefan O'Rear, 15-Aug-2015.)
|
| ⊢ (𝑊 ∈ Word 𝑆 → 𝑊:(0..^(♯‘𝑊))⟶𝑆) |
| |
| Theorem | iswrdiz 11107 |
A zero-based sequence is a word. In iswrdinn0 11105 we can specify a length
as an nonnegative integer. However, it will occasionally be helpful to
allow a negative length, as well as zero, to specify an empty sequence.
(Contributed by Jim Kingdon, 18-Aug-2025.)
|
| ⊢ ((𝑊:(0..^𝐿)⟶𝑆 ∧ 𝐿 ∈ ℤ) → 𝑊 ∈ Word 𝑆) |
| |
| Theorem | wrddm 11108 |
The indices of a word (i.e. its domain regarded as function) are elements
of an open range of nonnegative integers (of length equal to the length of
the word). (Contributed by AV, 2-May-2020.)
|
| ⊢ (𝑊 ∈ Word 𝑆 → dom 𝑊 = (0..^(♯‘𝑊))) |
| |
| Theorem | sswrd 11109 |
The set of words respects ordering on the base set. (Contributed by
Stefan O'Rear, 15-Aug-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
(Proof shortened by AV, 13-May-2020.)
|
| ⊢ (𝑆 ⊆ 𝑇 → Word 𝑆 ⊆ Word 𝑇) |
| |
| Theorem | snopiswrd 11110 |
A singleton of an ordered pair (with 0 as first component) is a word.
(Contributed by AV, 23-Nov-2018.) (Proof shortened by AV,
18-Apr-2021.)
|
| ⊢ (𝑆 ∈ 𝑉 → {〈0, 𝑆〉} ∈ Word 𝑉) |
| |
| Theorem | wrdexg 11111 |
The set of words over a set is a set. (Contributed by Mario Carneiro,
26-Feb-2016.) (Proof shortened by JJ, 18-Nov-2022.)
|
| ⊢ (𝑆 ∈ 𝑉 → Word 𝑆 ∈ V) |
| |
| Theorem | wrdexb 11112 |
The set of words over a set is a set, bidirectional version.
(Contributed by Mario Carneiro, 26-Feb-2016.) (Proof shortened by AV,
23-Nov-2018.)
|
| ⊢ (𝑆 ∈ V ↔ Word 𝑆 ∈ V) |
| |
| Theorem | wrdexi 11113 |
The set of words over a set is a set, inference form. (Contributed by
AV, 23-May-2021.)
|
| ⊢ 𝑆 ∈ V ⇒ ⊢ Word 𝑆 ∈ V |
| |
| Theorem | wrdsymbcl 11114 |
A symbol within a word over an alphabet belongs to the alphabet.
(Contributed by Alexander van der Vekens, 28-Jun-2018.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 𝐼 ∈ (0..^(♯‘𝑊))) → (𝑊‘𝐼) ∈ 𝑉) |
| |
| Theorem | wrdfn 11115 |
A word is a function with a zero-based sequence of integers as domain.
(Contributed by Alexander van der Vekens, 13-Apr-2018.)
|
| ⊢ (𝑊 ∈ Word 𝑆 → 𝑊 Fn (0..^(♯‘𝑊))) |
| |
| Theorem | wrdv 11116 |
A word over an alphabet is a word over the universal class. (Contributed
by AV, 8-Feb-2021.) (Proof shortened by JJ, 18-Nov-2022.)
|
| ⊢ (𝑊 ∈ Word 𝑉 → 𝑊 ∈ Word V) |
| |
| Theorem | wrdlndm 11117 |
The length of a word is not in the domain of the word (regarded as a
function). (Contributed by AV, 3-Mar-2021.) (Proof shortened by JJ,
18-Nov-2022.)
|
| ⊢ (𝑊 ∈ Word 𝑉 → (♯‘𝑊) ∉ dom 𝑊) |
| |
| Theorem | iswrdsymb 11118* |
An arbitrary word is a word over an alphabet if all of its symbols
belong to the alphabet. (Contributed by AV, 23-Jan-2021.)
|
| ⊢ ((𝑊 ∈ Word V ∧ ∀𝑖 ∈
(0..^(♯‘𝑊))(𝑊‘𝑖) ∈ 𝑉) → 𝑊 ∈ Word 𝑉) |
| |
| Theorem | wrdfin 11119 |
A word is a finite set. (Contributed by Stefan O'Rear, 2-Nov-2015.)
(Proof shortened by AV, 18-Nov-2018.)
|
| ⊢ (𝑊 ∈ Word 𝑆 → 𝑊 ∈ Fin) |
| |
| Theorem | lennncl 11120 |
The length of a nonempty word is a positive integer. (Contributed by
Mario Carneiro, 1-Oct-2015.)
|
| ⊢ ((𝑊 ∈ Word 𝑆 ∧ 𝑊 ≠ ∅) → (♯‘𝑊) ∈
ℕ) |
| |
| Theorem | wrdffz 11121 |
A word is a function from a finite interval of integers. (Contributed by
AV, 10-Feb-2021.)
|
| ⊢ (𝑊 ∈ Word 𝑆 → 𝑊:(0...((♯‘𝑊) − 1))⟶𝑆) |
| |
| Theorem | wrdeq 11122 |
Equality theorem for the set of words. (Contributed by Mario Carneiro,
26-Feb-2016.)
|
| ⊢ (𝑆 = 𝑇 → Word 𝑆 = Word 𝑇) |
| |
| Theorem | wrdeqi 11123 |
Equality theorem for the set of words, inference form. (Contributed by
AV, 23-May-2021.)
|
| ⊢ 𝑆 = 𝑇 ⇒ ⊢ Word 𝑆 = Word 𝑇 |
| |
| Theorem | iswrddm0 11124 |
A function with empty domain is a word. (Contributed by AV,
13-Oct-2018.)
|
| ⊢ (𝑊:∅⟶𝑆 → 𝑊 ∈ Word 𝑆) |
| |
| Theorem | wrd0 11125 |
The empty set is a word (the empty word, frequently denoted ε in
this context). This corresponds to the definition in Section 9.1 of
[AhoHopUll] p. 318. (Contributed by
Stefan O'Rear, 15-Aug-2015.) (Proof
shortened by AV, 13-May-2020.)
|
| ⊢ ∅ ∈ Word 𝑆 |
| |
| Theorem | 0wrd0 11126 |
The empty word is the only word over an empty alphabet. (Contributed by
AV, 25-Oct-2018.)
|
| ⊢ (𝑊 ∈ Word ∅ ↔ 𝑊 = ∅) |
| |
| Theorem | ffz0iswrdnn0 11127 |
A sequence with zero-based indices is a word. (Contributed by AV,
31-Jan-2018.) (Proof shortened by AV, 13-Oct-2018.) (Proof shortened by
JJ, 18-Nov-2022.)
|
| ⊢ ((𝑊:(0...𝐿)⟶𝑆 ∧ 𝐿 ∈ ℕ0) → 𝑊 ∈ Word 𝑆) |
| |
| Theorem | wrdsymb 11128 |
A word is a word over the symbols it consists of. (Contributed by AV,
1-Dec-2022.)
|
| ⊢ (𝑆 ∈ Word 𝐴 → 𝑆 ∈ Word (𝑆 “ (0..^(♯‘𝑆)))) |
| |
| Theorem | nfwrd 11129 |
Hypothesis builder for Word 𝑆. (Contributed by Mario Carneiro,
26-Feb-2016.)
|
| ⊢ Ⅎ𝑥𝑆 ⇒ ⊢ Ⅎ𝑥Word 𝑆 |
| |
| Theorem | csbwrdg 11130* |
Class substitution for the symbols of a word. (Contributed by Alexander
van der Vekens, 15-Jul-2018.)
|
| ⊢ (𝑆 ∈ 𝑉 → ⦋𝑆 / 𝑥⦌Word 𝑥 = Word 𝑆) |
| |
| Theorem | wrdnval 11131* |
Words of a fixed length are mappings from a fixed half-open integer
interval. (Contributed by Alexander van der Vekens, 25-Mar-2018.)
(Proof shortened by AV, 13-May-2020.)
|
| ⊢ ((𝑉 ∈ 𝑋 ∧ 𝑁 ∈ ℕ0) → {𝑤 ∈ Word 𝑉 ∣ (♯‘𝑤) = 𝑁} = (𝑉 ↑𝑚 (0..^𝑁))) |
| |
| Theorem | wrdmap 11132 |
Words as a mapping. (Contributed by Thierry Arnoux, 4-Mar-2020.)
|
| ⊢ ((𝑉 ∈ 𝑋 ∧ 𝑁 ∈ ℕ0) → ((𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) = 𝑁) ↔ 𝑊 ∈ (𝑉 ↑𝑚 (0..^𝑁)))) |
| |
| Theorem | wrdsymb0 11133 |
A symbol at a position "outside" of a word. (Contributed by
Alexander van
der Vekens, 26-May-2018.) (Proof shortened by AV, 2-May-2020.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 𝐼 ∈ ℤ) → ((𝐼 < 0 ∨ (♯‘𝑊) ≤ 𝐼) → (𝑊‘𝐼) = ∅)) |
| |
| Theorem | wrdlenge1n0 11134 |
A word with length at least 1 is not empty. (Contributed by AV,
14-Oct-2018.)
|
| ⊢ (𝑊 ∈ Word 𝑉 → (𝑊 ≠ ∅ ↔ 1 ≤
(♯‘𝑊))) |
| |
| Theorem | len0nnbi 11135 |
The length of a word is a positive integer iff the word is not empty.
(Contributed by AV, 22-Mar-2022.)
|
| ⊢ (𝑊 ∈ Word 𝑆 → (𝑊 ≠ ∅ ↔ (♯‘𝑊) ∈
ℕ)) |
| |
| Theorem | wrdlenge2n0 11136 |
A word with length at least 2 is not empty. (Contributed by AV,
18-Jun-2018.) (Proof shortened by AV, 14-Oct-2018.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 2 ≤ (♯‘𝑊)) → 𝑊 ≠ ∅) |
| |
| Theorem | wrdsymb1 11137 |
The first symbol of a nonempty word over an alphabet belongs to the
alphabet. (Contributed by Alexander van der Vekens, 28-Jun-2018.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 1 ≤ (♯‘𝑊)) → (𝑊‘0) ∈ 𝑉) |
| |
| Theorem | wrdlen1 11138* |
A word of length 1 starts with a symbol. (Contributed by AV,
20-Jul-2018.) (Proof shortened by AV, 19-Oct-2018.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) = 1) → ∃𝑣 ∈ 𝑉 (𝑊‘0) = 𝑣) |
| |
| Theorem | fstwrdne 11139 |
The first symbol of a nonempty word is element of the alphabet for the
word. (Contributed by AV, 28-Sep-2018.) (Proof shortened by AV,
14-Oct-2018.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 𝑊 ≠ ∅) → (𝑊‘0) ∈ 𝑉) |
| |
| Theorem | fstwrdne0 11140 |
The first symbol of a nonempty word is element of the alphabet for the
word. (Contributed by AV, 29-Sep-2018.) (Proof shortened by AV,
14-Oct-2018.)
|
| ⊢ ((𝑁 ∈ ℕ ∧ (𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) = 𝑁)) → (𝑊‘0) ∈ 𝑉) |
| |
| Theorem | eqwrd 11141* |
Two words are equal iff they have the same length and the same symbol at
each position. (Contributed by AV, 13-Apr-2018.) (Revised by JJ,
30-Dec-2023.)
|
| ⊢ ((𝑈 ∈ Word 𝑆 ∧ 𝑊 ∈ Word 𝑇) → (𝑈 = 𝑊 ↔ ((♯‘𝑈) = (♯‘𝑊) ∧ ∀𝑖 ∈ (0..^(♯‘𝑈))(𝑈‘𝑖) = (𝑊‘𝑖)))) |
| |
| Theorem | elovmpowrd 11142* |
Implications for the value of an operation defined by the maps-to
notation with a class abstraction of words as a result having an
element. Note that 𝜑 may depend on 𝑧 as well as on 𝑣 and
𝑦. (Contributed by Alexander van der
Vekens, 15-Jul-2018.)
|
| ⊢ 𝑂 = (𝑣 ∈ V, 𝑦 ∈ V ↦ {𝑧 ∈ Word 𝑣 ∣ 𝜑}) ⇒ ⊢ (𝑍 ∈ (𝑉𝑂𝑌) → (𝑉 ∈ V ∧ 𝑌 ∈ V ∧ 𝑍 ∈ Word 𝑉)) |
| |
| Theorem | wrdred1 11143 |
A word truncated by a symbol is a word. (Contributed by AV,
29-Jan-2021.)
|
| ⊢ (𝐹 ∈ Word 𝑆 → (𝐹 ↾ (0..^((♯‘𝐹) − 1))) ∈ Word
𝑆) |
| |
| Theorem | wrdred1hash 11144 |
The length of a word truncated by a symbol. (Contributed by Alexander van
der Vekens, 1-Nov-2017.) (Revised by AV, 29-Jan-2021.)
|
| ⊢ ((𝐹 ∈ Word 𝑆 ∧ 1 ≤ (♯‘𝐹)) → (♯‘(𝐹 ↾
(0..^((♯‘𝐹)
− 1)))) = ((♯‘𝐹) − 1)) |
| |
| 4.7.2 Last symbol of a word
|
| |
| Syntax | clsw 11145 |
Extend class notation with the Last Symbol of a word.
|
| class lastS |
| |
| Definition | df-lsw 11146 |
Extract the last symbol of a word. May be not meaningful for other sets
which are not words. The name lastS (as
abbreviation of "lastSymbol")
is a compromise between usually used names for corresponding functions in
computer programs (as last() or lastChar()), the terminology used for
words in set.mm ("symbol" instead of "character") and
brevity ("lastS" is
shorter than "lastChar" and "lastSymbol"). Labels of
theorems about last
symbols of a word will contain the abbreviation "lsw" (Last
Symbol of a
Word). (Contributed by Alexander van der Vekens, 18-Mar-2018.)
|
| ⊢ lastS = (𝑤 ∈ V ↦ (𝑤‘((♯‘𝑤) − 1))) |
| |
| Theorem | lswwrd 11147 |
Extract the last symbol of a word. (Contributed by Alexander van der
Vekens, 18-Mar-2018.) (Revised by Jim Kingdon, 18-Dec-2025.)
|
| ⊢ (𝑊 ∈ Word 𝑉 → (lastS‘𝑊) = (𝑊‘((♯‘𝑊) − 1))) |
| |
| Theorem | lsw0 11148 |
The last symbol of an empty word does not exist. (Contributed by
Alexander van der Vekens, 19-Mar-2018.) (Proof shortened by AV,
2-May-2020.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) = 0) → (lastS‘𝑊) = ∅) |
| |
| Theorem | lsw0g 11149 |
The last symbol of an empty word does not exist. (Contributed by
Alexander van der Vekens, 11-Nov-2018.)
|
| ⊢ (lastS‘∅) =
∅ |
| |
| Theorem | lsw1 11150 |
The last symbol of a word of length 1 is the first symbol of this word.
(Contributed by Alexander van der Vekens, 19-Mar-2018.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) = 1) → (lastS‘𝑊) = (𝑊‘0)) |
| |
| Theorem | lswcl 11151 |
Closure of the last symbol: the last symbol of a nonempty word belongs to
the alphabet for the word. (Contributed by AV, 2-Aug-2018.) (Proof
shortened by AV, 29-Apr-2020.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 𝑊 ≠ ∅) → (lastS‘𝑊) ∈ 𝑉) |
| |
| Theorem | lswex 11152 |
Existence of the last symbol. The last symbol of a word is a set. See
lsw0g 11149 or lswcl 11151 if you want more specific results
for empty or
nonempty words, respectively. (Contributed by Jim Kingdon,
27-Dec-2025.)
|
| ⊢ (𝑊 ∈ Word 𝑉 → (lastS‘𝑊) ∈ V) |
| |
| Theorem | lswlgt0cl 11153 |
The last symbol of a nonempty word is an element of the alphabet for the
word. (Contributed by Alexander van der Vekens, 1-Oct-2018.) (Proof
shortened by AV, 29-Apr-2020.)
|
| ⊢ ((𝑁 ∈ ℕ ∧ (𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) = 𝑁)) → (lastS‘𝑊) ∈ 𝑉) |
| |
| 4.7.3 Concatenations of words
|
| |
| Syntax | cconcat 11154 |
Syntax for the concatenation operator.
|
| class ++ |
| |
| Definition | df-concat 11155* |
Define the concatenation operator which combines two words. Definition
in Section 9.1 of [AhoHopUll] p. 318.
(Contributed by FL, 14-Jan-2014.)
(Revised by Stefan O'Rear, 15-Aug-2015.)
|
| ⊢ ++ = (𝑠 ∈ V, 𝑡 ∈ V ↦ (𝑥 ∈ (0..^((♯‘𝑠) + (♯‘𝑡))) ↦ if(𝑥 ∈
(0..^(♯‘𝑠)),
(𝑠‘𝑥), (𝑡‘(𝑥 − (♯‘𝑠)))))) |
| |
| Theorem | ccatfvalfi 11156* |
Value of the concatenation operator. (Contributed by Stefan O'Rear,
15-Aug-2015.)
|
| ⊢ ((𝑆 ∈ Fin ∧ 𝑇 ∈ Fin) → (𝑆 ++ 𝑇) = (𝑥 ∈ (0..^((♯‘𝑆) + (♯‘𝑇))) ↦ if(𝑥 ∈
(0..^(♯‘𝑆)),
(𝑆‘𝑥), (𝑇‘(𝑥 − (♯‘𝑆)))))) |
| |
| Theorem | ccatcl 11157 |
The concatenation of two words is a word. (Contributed by FL,
2-Feb-2014.) (Proof shortened by Stefan O'Rear, 15-Aug-2015.) (Proof
shortened by AV, 29-Apr-2020.)
|
| ⊢ ((𝑆 ∈ Word 𝐵 ∧ 𝑇 ∈ Word 𝐵) → (𝑆 ++ 𝑇) ∈ Word 𝐵) |
| |
| Theorem | ccatclab 11158 |
The concatenation of words over two sets is a word over the union of
those sets. (Contributed by Jim Kingdon, 19-Dec-2025.)
|
| ⊢ ((𝑆 ∈ Word 𝐴 ∧ 𝑇 ∈ Word 𝐵) → (𝑆 ++ 𝑇) ∈ Word (𝐴 ∪ 𝐵)) |
| |
| Theorem | ccatlen 11159 |
The length of a concatenated word. (Contributed by Stefan O'Rear,
15-Aug-2015.) (Revised by JJ, 1-Jan-2024.)
|
| ⊢ ((𝑆 ∈ Word 𝐴 ∧ 𝑇 ∈ Word 𝐵) → (♯‘(𝑆 ++ 𝑇)) = ((♯‘𝑆) + (♯‘𝑇))) |
| |
| Theorem | ccat0 11160 |
The concatenation of two words is empty iff the two words are empty.
(Contributed by AV, 4-Mar-2022.) (Revised by JJ, 18-Jan-2024.)
|
| ⊢ ((𝑆 ∈ Word 𝐴 ∧ 𝑇 ∈ Word 𝐵) → ((𝑆 ++ 𝑇) = ∅ ↔ (𝑆 = ∅ ∧ 𝑇 = ∅))) |
| |
| Theorem | ccatval1 11161 |
Value of a symbol in the left half of a concatenated word. (Contributed
by Stefan O'Rear, 15-Aug-2015.) (Revised by Mario Carneiro,
22-Sep-2015.) (Proof shortened by AV, 30-Apr-2020.) (Revised by JJ,
18-Jan-2024.)
|
| ⊢ ((𝑆 ∈ Word 𝐴 ∧ 𝑇 ∈ Word 𝐵 ∧ 𝐼 ∈ (0..^(♯‘𝑆))) → ((𝑆 ++ 𝑇)‘𝐼) = (𝑆‘𝐼)) |
| |
| Theorem | ccatval2 11162 |
Value of a symbol in the right half of a concatenated word.
(Contributed by Stefan O'Rear, 15-Aug-2015.) (Revised by Mario
Carneiro, 22-Sep-2015.)
|
| ⊢ ((𝑆 ∈ Word 𝐵 ∧ 𝑇 ∈ Word 𝐵 ∧ 𝐼 ∈ ((♯‘𝑆)..^((♯‘𝑆) + (♯‘𝑇)))) → ((𝑆 ++ 𝑇)‘𝐼) = (𝑇‘(𝐼 − (♯‘𝑆)))) |
| |
| Theorem | ccatval3 11163 |
Value of a symbol in the right half of a concatenated word, using an
index relative to the subword. (Contributed by Stefan O'Rear,
16-Aug-2015.) (Proof shortened by AV, 30-Apr-2020.)
|
| ⊢ ((𝑆 ∈ Word 𝐵 ∧ 𝑇 ∈ Word 𝐵 ∧ 𝐼 ∈ (0..^(♯‘𝑇))) → ((𝑆 ++ 𝑇)‘(𝐼 + (♯‘𝑆))) = (𝑇‘𝐼)) |
| |
| Theorem | elfzelfzccat 11164 |
An element of a finite set of sequential integers up to the length of a
word is an element of an extended finite set of sequential integers up to
the length of a concatenation of this word with another word.
(Contributed by Alexander van der Vekens, 28-Mar-2018.)
|
| ⊢ ((𝐴 ∈ Word 𝑉 ∧ 𝐵 ∈ Word 𝑉) → (𝑁 ∈ (0...(♯‘𝐴)) → 𝑁 ∈ (0...(♯‘(𝐴 ++ 𝐵))))) |
| |
| Theorem | ccatvalfn 11165 |
The concatenation of two words is a function over the half-open integer
range having the sum of the lengths of the word as length. (Contributed
by Alexander van der Vekens, 30-Mar-2018.)
|
| ⊢ ((𝐴 ∈ Word 𝑉 ∧ 𝐵 ∈ Word 𝑉) → (𝐴 ++ 𝐵) Fn (0..^((♯‘𝐴) + (♯‘𝐵)))) |
| |
| Theorem | ccatsymb 11166 |
The symbol at a given position in a concatenated word. (Contributed by
AV, 26-May-2018.) (Proof shortened by AV, 24-Nov-2018.)
|
| ⊢ ((𝐴 ∈ Word 𝑉 ∧ 𝐵 ∈ Word 𝑉 ∧ 𝐼 ∈ ℤ) → ((𝐴 ++ 𝐵)‘𝐼) = if(𝐼 < (♯‘𝐴), (𝐴‘𝐼), (𝐵‘(𝐼 − (♯‘𝐴))))) |
| |
| Theorem | ccatfv0 11167 |
The first symbol of a concatenation of two words is the first symbol of
the first word if the first word is not empty. (Contributed by Alexander
van der Vekens, 22-Sep-2018.)
|
| ⊢ ((𝐴 ∈ Word 𝑉 ∧ 𝐵 ∈ Word 𝑉 ∧ 0 < (♯‘𝐴)) → ((𝐴 ++ 𝐵)‘0) = (𝐴‘0)) |
| |
| Theorem | ccatval1lsw 11168 |
The last symbol of the left (nonempty) half of a concatenated word.
(Contributed by Alexander van der Vekens, 3-Oct-2018.) (Proof shortened
by AV, 1-May-2020.)
|
| ⊢ ((𝐴 ∈ Word 𝑉 ∧ 𝐵 ∈ Word 𝑉 ∧ 𝐴 ≠ ∅) → ((𝐴 ++ 𝐵)‘((♯‘𝐴) − 1)) = (lastS‘𝐴)) |
| |
| Theorem | ccatval21sw 11169 |
The first symbol of the right (nonempty) half of a concatenated word.
(Contributed by AV, 23-Apr-2022.)
|
| ⊢ ((𝐴 ∈ Word 𝑉 ∧ 𝐵 ∈ Word 𝑉 ∧ 𝐵 ≠ ∅) → ((𝐴 ++ 𝐵)‘(♯‘𝐴)) = (𝐵‘0)) |
| |
| Theorem | ccatlid 11170 |
Concatenation of a word by the empty word on the left. (Contributed by
Stefan O'Rear, 15-Aug-2015.) (Proof shortened by AV, 1-May-2020.)
|
| ⊢ (𝑆 ∈ Word 𝐵 → (∅ ++ 𝑆) = 𝑆) |
| |
| Theorem | ccatrid 11171 |
Concatenation of a word by the empty word on the right. (Contributed by
Stefan O'Rear, 15-Aug-2015.) (Proof shortened by AV, 1-May-2020.)
|
| ⊢ (𝑆 ∈ Word 𝐵 → (𝑆 ++ ∅) = 𝑆) |
| |
| Theorem | ccatass 11172 |
Associative law for concatenation of words. (Contributed by Stefan
O'Rear, 15-Aug-2015.)
|
| ⊢ ((𝑆 ∈ Word 𝐵 ∧ 𝑇 ∈ Word 𝐵 ∧ 𝑈 ∈ Word 𝐵) → ((𝑆 ++ 𝑇) ++ 𝑈) = (𝑆 ++ (𝑇 ++ 𝑈))) |
| |
| Theorem | ccatrn 11173 |
The range of a concatenated word. (Contributed by Stefan O'Rear,
15-Aug-2015.)
|
| ⊢ ((𝑆 ∈ Word 𝐵 ∧ 𝑇 ∈ Word 𝐵) → ran (𝑆 ++ 𝑇) = (ran 𝑆 ∪ ran 𝑇)) |
| |
| Theorem | ccatidid 11174 |
Concatenation of the empty word by the empty word. (Contributed by AV,
26-Mar-2022.)
|
| ⊢ (∅ ++ ∅) =
∅ |
| |
| Theorem | lswccatn0lsw 11175 |
The last symbol of a word concatenated with a nonempty word is the last
symbol of the nonempty word. (Contributed by AV, 22-Oct-2018.) (Proof
shortened by AV, 1-May-2020.)
|
| ⊢ ((𝐴 ∈ Word 𝑉 ∧ 𝐵 ∈ Word 𝑉 ∧ 𝐵 ≠ ∅) → (lastS‘(𝐴 ++ 𝐵)) = (lastS‘𝐵)) |
| |
| Theorem | lswccat0lsw 11176 |
The last symbol of a word concatenated with the empty word is the last
symbol of the word. (Contributed by AV, 22-Oct-2018.) (Proof shortened
by AV, 1-May-2020.)
|
| ⊢ (𝑊 ∈ Word 𝑉 → (lastS‘(𝑊 ++ ∅)) = (lastS‘𝑊)) |
| |
| Theorem | ccatalpha 11177 |
A concatenation of two arbitrary words is a word over an alphabet iff
the symbols of both words belong to the alphabet. (Contributed by AV,
28-Feb-2021.)
|
| ⊢ ((𝐴 ∈ Word V ∧ 𝐵 ∈ Word V) → ((𝐴 ++ 𝐵) ∈ Word 𝑆 ↔ (𝐴 ∈ Word 𝑆 ∧ 𝐵 ∈ Word 𝑆))) |
| |
| Theorem | ccatrcl1 11178 |
Reverse closure of a concatenation: If the concatenation of two arbitrary
words is a word over an alphabet then the symbols of the first word belong
to the alphabet. (Contributed by AV, 3-Mar-2021.)
|
| ⊢ ((𝐴 ∈ Word 𝑋 ∧ 𝐵 ∈ Word 𝑌 ∧ (𝑊 = (𝐴 ++ 𝐵) ∧ 𝑊 ∈ Word 𝑆)) → 𝐴 ∈ Word 𝑆) |
| |
| 4.7.4 Singleton words
|
| |
| Syntax | cs1 11179 |
Syntax for the singleton word constructor.
|
| class 〈“𝐴”〉 |
| |
| Definition | df-s1 11180 |
Define the canonical injection from symbols to words. Although not
required, 𝐴 should usually be a set. Otherwise,
the singleton word
〈“𝐴”〉 would be the singleton
word consisting of the empty set, see
s1prc 11187, and not, as maybe expected, the empty word.
(Contributed by
Stefan O'Rear, 15-Aug-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
|
| ⊢ 〈“𝐴”〉 = {〈0, ( I ‘𝐴)〉} |
| |
| Theorem | s1val 11181 |
Value of a singleton word. (Contributed by Stefan O'Rear, 15-Aug-2015.)
(Revised by Mario Carneiro, 26-Feb-2016.)
|
| ⊢ (𝐴 ∈ 𝑉 → 〈“𝐴”〉 = {〈0, 𝐴〉}) |
| |
| Theorem | s1rn 11182 |
The range of a singleton word. (Contributed by Mario Carneiro,
18-Jul-2016.)
|
| ⊢ (𝐴 ∈ 𝑉 → ran 〈“𝐴”〉 = {𝐴}) |
| |
| Theorem | s1eq 11183 |
Equality theorem for a singleton word. (Contributed by Mario Carneiro,
26-Feb-2016.)
|
| ⊢ (𝐴 = 𝐵 → 〈“𝐴”〉 = 〈“𝐵”〉) |
| |
| Theorem | s1eqd 11184 |
Equality theorem for a singleton word. (Contributed by Mario Carneiro,
26-Feb-2016.)
|
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → 〈“𝐴”〉 = 〈“𝐵”〉) |
| |
| Theorem | s1cl 11185 |
A singleton word is a word. (Contributed by Stefan O'Rear, 15-Aug-2015.)
(Revised by Mario Carneiro, 26-Feb-2016.) (Proof shortened by AV,
23-Nov-2018.)
|
| ⊢ (𝐴 ∈ 𝐵 → 〈“𝐴”〉 ∈ Word 𝐵) |
| |
| Theorem | s1cld 11186 |
A singleton word is a word. (Contributed by Mario Carneiro,
26-Feb-2016.)
|
| ⊢ (𝜑 → 𝐴 ∈ 𝐵) ⇒ ⊢ (𝜑 → 〈“𝐴”〉 ∈ Word 𝐵) |
| |
| Theorem | s1prc 11187 |
Value of a singleton word if the symbol is a proper class. (Contributed
by AV, 26-Mar-2022.)
|
| ⊢ (¬ 𝐴 ∈ V → 〈“𝐴”〉 =
〈“∅”〉) |
| |
| Theorem | s1leng 11188 |
Length of a singleton word. (Contributed by Stefan O'Rear, 15-Aug-2015.)
(Revised by Mario Carneiro, 26-Feb-2016.)
|
| ⊢ (𝐴 ∈ 𝑉 → (♯‘〈“𝐴”〉) =
1) |
| |
| Theorem | s1dmg 11189 |
The domain of a singleton word is a singleton. (Contributed by AV,
9-Jan-2020.)
|
| ⊢ (𝐴 ∈ 𝑆 → dom 〈“𝐴”〉 = {0}) |
| |
| Theorem | s1fv 11190 |
Sole symbol of a singleton word. (Contributed by Stefan O'Rear,
15-Aug-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
|
| ⊢ (𝐴 ∈ 𝐵 → (〈“𝐴”〉‘0) = 𝐴) |
| |
| Theorem | lsws1 11191 |
The last symbol of a singleton word is its symbol. (Contributed by AV,
22-Oct-2018.)
|
| ⊢ (𝐴 ∈ 𝑉 → (lastS‘〈“𝐴”〉) = 𝐴) |
| |
| Theorem | eqs1 11192 |
A word of length 1 is a singleton word. (Contributed by Stefan O'Rear,
23-Aug-2015.) (Proof shortened by AV, 1-May-2020.)
|
| ⊢ ((𝑊 ∈ Word 𝐴 ∧ (♯‘𝑊) = 1) → 𝑊 = 〈“(𝑊‘0)”〉) |
| |
| Theorem | wrdl1exs1 11193* |
A word of length 1 is a singleton word. (Contributed by AV,
24-Jan-2021.)
|
| ⊢ ((𝑊 ∈ Word 𝑆 ∧ (♯‘𝑊) = 1) → ∃𝑠 ∈ 𝑆 𝑊 = 〈“𝑠”〉) |
| |
| Theorem | wrdl1s1 11194 |
A word of length 1 is a singleton word consisting of the first symbol of
the word. (Contributed by AV, 22-Jul-2018.) (Proof shortened by AV,
14-Oct-2018.)
|
| ⊢ (𝑆 ∈ 𝑉 → (𝑊 = 〈“𝑆”〉 ↔ (𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) = 1 ∧ (𝑊‘0) = 𝑆))) |
| |
| Theorem | s111 11195 |
The singleton word function is injective. (Contributed by Mario Carneiro,
1-Oct-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
|
| ⊢ ((𝑆 ∈ 𝐴 ∧ 𝑇 ∈ 𝐴) → (〈“𝑆”〉 = 〈“𝑇”〉 ↔ 𝑆 = 𝑇)) |
| |
| 4.7.5 Concatenations with singleton
words
|
| |
| Theorem | ccatws1cl 11196 |
The concatenation of a word with a singleton word is a word. (Contributed
by Alexander van der Vekens, 22-Sep-2018.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 𝑋 ∈ 𝑉) → (𝑊 ++ 〈“𝑋”〉) ∈ Word 𝑉) |
| |
| Theorem | ccat2s1cl 11197 |
The concatenation of two singleton words is a word. (Contributed by
Alexander van der Vekens, 22-Sep-2018.)
|
| ⊢ ((𝑋 ∈ 𝑉 ∧ 𝑌 ∈ 𝑉) → (〈“𝑋”〉 ++ 〈“𝑌”〉) ∈ Word
𝑉) |
| |
| Theorem | ccatws1leng 11198 |
The length of the concatenation of a word with a singleton word.
(Contributed by Alexander van der Vekens, 22-Sep-2018.) (Revised by AV,
4-Mar-2022.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 𝑋 ∈ 𝑌) → (♯‘(𝑊 ++ 〈“𝑋”〉)) = ((♯‘𝑊) + 1)) |
| |
| Theorem | ccatws1lenp1bg 11199 |
The length of a word is 𝑁 iff the length of the concatenation
of the
word with a singleton word is 𝑁 + 1. (Contributed by AV,
4-Mar-2022.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 𝑋 ∈ 𝑌 ∧ 𝑁 ∈ ℕ0) →
((♯‘(𝑊 ++
〈“𝑋”〉)) = (𝑁 + 1) ↔ (♯‘𝑊) = 𝑁)) |
| |
| Theorem | wrdlenccats1lenm1g 11200 |
The length of a word is the length of the word concatenated with a
singleton word minus 1. (Contributed by AV, 28-Jun-2018.) (Revised by
AV, 5-Mar-2022.)
|
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ 𝑆 ∈ 𝐵) → ((♯‘(𝑊 ++ 〈“𝑆”〉)) − 1) =
(♯‘𝑊)) |