Theorem List for Intuitionistic Logic Explorer - 7001-7100 *Has distinct variable
group(s)
| Type | Label | Description |
| Statement |
| |
| Theorem | rex2dom 7001* |
A set that has at least 2 different members dominates ordinal 2.
(Contributed by BTernaryTau, 30-Dec-2024.)
|
| ⊢ ((𝐴 ∈ 𝑉 ∧ ∃𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐴 𝑥 ≠ 𝑦) → 2o ≼ 𝐴) |
| |
| Theorem | enpr2d 7002 |
A pair with distinct elements is equinumerous to ordinal two.
(Contributed by Rohan Ridenour, 3-Aug-2023.)
|
| ⊢ (𝜑 → 𝐴 ∈ 𝐶)
& ⊢ (𝜑 → 𝐵 ∈ 𝐷)
& ⊢ (𝜑 → ¬ 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → {𝐴, 𝐵} ≈ 2o) |
| |
| Theorem | en2 7003* |
A set equinumerous to ordinal 2 is an unordered pair. (Contributed by
Mario Carneiro, 5-Jan-2016.)
|
| ⊢ (𝐴 ≈ 2o → ∃𝑥∃𝑦 𝐴 = {𝑥, 𝑦}) |
| |
| Theorem | en2m 7004* |
A set with two elements is inhabited. (Contributed by Jim Kingdon,
3-Jan-2026.)
|
| ⊢ (𝐴 ≈ 2o → ∃𝑥 𝑥 ∈ 𝐴) |
| |
| Theorem | ssct 7005 |
A subset of a set dominated by ω is dominated by
ω.
(Contributed by Thierry Arnoux, 31-Jan-2017.)
|
| ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ≼ ω) → 𝐴 ≼ ω) |
| |
| Theorem | 1domsn 7006 |
A singleton (whether of a set or a proper class) is dominated by one.
(Contributed by Jim Kingdon, 1-Mar-2022.)
|
| ⊢ {𝐴} ≼ 1o |
| |
| Theorem | dom1o 7007* |
Two ways of saying that a set is inhabited. (Contributed by Jim
Kingdon, 3-Jan-2026.)
|
| ⊢ (𝐴 ∈ 𝑉 → (1o ≼ 𝐴 ↔ ∃𝑗 𝑗 ∈ 𝐴)) |
| |
| Theorem | dom1oi 7008 |
A set with an element dominates one. (Contributed by Jim Kingdon,
3-Feb-2026.)
|
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝐴) → 1o ≼ 𝐴) |
| |
| Theorem | enm 7009* |
A set equinumerous to an inhabited set is inhabited. (Contributed by
Jim Kingdon, 19-May-2020.)
|
| ⊢ ((𝐴 ≈ 𝐵 ∧ ∃𝑥 𝑥 ∈ 𝐴) → ∃𝑦 𝑦 ∈ 𝐵) |
| |
| Theorem | xpsnen 7010 |
A set is equinumerous to its Cartesian product with a singleton.
Proposition 4.22(c) of [Mendelson] p.
254. (Contributed by NM,
4-Jan-2004.) (Revised by Mario Carneiro, 15-Nov-2014.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ (𝐴 × {𝐵}) ≈ 𝐴 |
| |
| Theorem | xpsneng 7011 |
A set is equinumerous to its Cartesian product with a singleton.
Proposition 4.22(c) of [Mendelson] p.
254. (Contributed by NM,
22-Oct-2004.)
|
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → (𝐴 × {𝐵}) ≈ 𝐴) |
| |
| Theorem | xp1en 7012 |
One times a cardinal number. (Contributed by NM, 27-Sep-2004.) (Revised
by Mario Carneiro, 29-Apr-2015.)
|
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 × 1o) ≈ 𝐴) |
| |
| Theorem | endisj 7013* |
Any two sets are equinumerous to disjoint sets. Exercise 4.39 of
[Mendelson] p. 255. (Contributed by
NM, 16-Apr-2004.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ ∃𝑥∃𝑦((𝑥 ≈ 𝐴 ∧ 𝑦 ≈ 𝐵) ∧ (𝑥 ∩ 𝑦) = ∅) |
| |
| Theorem | xpcomf1o 7014* |
The canonical bijection from (𝐴 × 𝐵) to (𝐵 × 𝐴).
(Contributed by Mario Carneiro, 23-Apr-2014.)
|
| ⊢ 𝐹 = (𝑥 ∈ (𝐴 × 𝐵) ↦ ∪
◡{𝑥}) ⇒ ⊢ 𝐹:(𝐴 × 𝐵)–1-1-onto→(𝐵 × 𝐴) |
| |
| Theorem | xpcomco 7015* |
Composition with the bijection of xpcomf1o 7014 swaps the arguments to a
mapping. (Contributed by Mario Carneiro, 30-May-2015.)
|
| ⊢ 𝐹 = (𝑥 ∈ (𝐴 × 𝐵) ↦ ∪
◡{𝑥})
& ⊢ 𝐺 = (𝑦 ∈ 𝐵, 𝑧 ∈ 𝐴 ↦ 𝐶) ⇒ ⊢ (𝐺 ∘ 𝐹) = (𝑧 ∈ 𝐴, 𝑦 ∈ 𝐵 ↦ 𝐶) |
| |
| Theorem | xpcomen 7016 |
Commutative law for equinumerosity of Cartesian product. Proposition
4.22(d) of [Mendelson] p. 254.
(Contributed by NM, 5-Jan-2004.)
(Revised by Mario Carneiro, 15-Nov-2014.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ (𝐴 × 𝐵) ≈ (𝐵 × 𝐴) |
| |
| Theorem | xpcomeng 7017 |
Commutative law for equinumerosity of Cartesian product. Proposition
4.22(d) of [Mendelson] p. 254.
(Contributed by NM, 27-Mar-2006.)
|
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → (𝐴 × 𝐵) ≈ (𝐵 × 𝐴)) |
| |
| Theorem | xpsnen2g 7018 |
A set is equinumerous to its Cartesian product with a singleton on the
left. (Contributed by Stefan O'Rear, 21-Nov-2014.)
|
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → ({𝐴} × 𝐵) ≈ 𝐵) |
| |
| Theorem | xpassen 7019 |
Associative law for equinumerosity of Cartesian product. Proposition
4.22(e) of [Mendelson] p. 254.
(Contributed by NM, 22-Jan-2004.)
(Revised by Mario Carneiro, 15-Nov-2014.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V & ⊢ 𝐶 ∈
V ⇒ ⊢ ((𝐴 × 𝐵) × 𝐶) ≈ (𝐴 × (𝐵 × 𝐶)) |
| |
| Theorem | xpdom2 7020 |
Dominance law for Cartesian product. Proposition 10.33(2) of
[TakeutiZaring] p. 92.
(Contributed by NM, 24-Jul-2004.) (Revised by
Mario Carneiro, 15-Nov-2014.)
|
| ⊢ 𝐶 ∈ V ⇒ ⊢ (𝐴 ≼ 𝐵 → (𝐶 × 𝐴) ≼ (𝐶 × 𝐵)) |
| |
| Theorem | xpdom2g 7021 |
Dominance law for Cartesian product. Theorem 6L(c) of [Enderton]
p. 149. (Contributed by Mario Carneiro, 26-Apr-2015.)
|
| ⊢ ((𝐶 ∈ 𝑉 ∧ 𝐴 ≼ 𝐵) → (𝐶 × 𝐴) ≼ (𝐶 × 𝐵)) |
| |
| Theorem | xpdom1g 7022 |
Dominance law for Cartesian product. Theorem 6L(c) of [Enderton]
p. 149. (Contributed by NM, 25-Mar-2006.) (Revised by Mario Carneiro,
26-Apr-2015.)
|
| ⊢ ((𝐶 ∈ 𝑉 ∧ 𝐴 ≼ 𝐵) → (𝐴 × 𝐶) ≼ (𝐵 × 𝐶)) |
| |
| Theorem | xpdom3m 7023* |
A set is dominated by its Cartesian product with an inhabited set.
Exercise 6 of [Suppes] p. 98.
(Contributed by Jim Kingdon,
15-Apr-2020.)
|
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ ∃𝑥 𝑥 ∈ 𝐵) → 𝐴 ≼ (𝐴 × 𝐵)) |
| |
| Theorem | xpdom1 7024 |
Dominance law for Cartesian product. Theorem 6L(c) of [Enderton]
p. 149. (Contributed by NM, 28-Sep-2004.) (Revised by NM,
29-Mar-2006.) (Revised by Mario Carneiro, 7-May-2015.)
|
| ⊢ 𝐶 ∈ V ⇒ ⊢ (𝐴 ≼ 𝐵 → (𝐴 × 𝐶) ≼ (𝐵 × 𝐶)) |
| |
| Theorem | pw2f1odclem 7025* |
Lemma for pw2f1odc 7026. (Contributed by Mario Carneiro,
6-Oct-2014.)
|
| ⊢ (𝜑 → 𝐴 ∈ 𝑉)
& ⊢ (𝜑 → 𝐵 ∈ 𝑊)
& ⊢ (𝜑 → 𝐶 ∈ 𝑊)
& ⊢ (𝜑 → 𝐵 ≠ 𝐶)
& ⊢ (𝜑 → ∀𝑝 ∈ 𝐴 ∀𝑞 ∈ 𝒫 𝐴DECID 𝑝 ∈ 𝑞) ⇒ ⊢ (𝜑 → ((𝑆 ∈ 𝒫 𝐴 ∧ 𝐺 = (𝑧 ∈ 𝐴 ↦ if(𝑧 ∈ 𝑆, 𝐶, 𝐵))) ↔ (𝐺 ∈ ({𝐵, 𝐶} ↑𝑚 𝐴) ∧ 𝑆 = (◡𝐺 “ {𝐶})))) |
| |
| Theorem | pw2f1odc 7026* |
The power set of a set is equinumerous to set exponentiation with an
unordered pair base of ordinal 2. Generalized from Proposition 10.44 of
[TakeutiZaring] p. 96.
(Contributed by Mario Carneiro, 6-Oct-2014.)
|
| ⊢ (𝜑 → 𝐴 ∈ 𝑉)
& ⊢ (𝜑 → 𝐵 ∈ 𝑊)
& ⊢ (𝜑 → 𝐶 ∈ 𝑊)
& ⊢ (𝜑 → 𝐵 ≠ 𝐶)
& ⊢ (𝜑 → ∀𝑝 ∈ 𝐴 ∀𝑞 ∈ 𝒫 𝐴DECID 𝑝 ∈ 𝑞)
& ⊢ 𝐹 = (𝑥 ∈ 𝒫 𝐴 ↦ (𝑧 ∈ 𝐴 ↦ if(𝑧 ∈ 𝑥, 𝐶, 𝐵))) ⇒ ⊢ (𝜑 → 𝐹:𝒫 𝐴–1-1-onto→({𝐵, 𝐶} ↑𝑚 𝐴)) |
| |
| Theorem | fopwdom 7027 |
Covering implies injection on power sets. (Contributed by Stefan
O'Rear, 6-Nov-2014.) (Revised by Mario Carneiro, 24-Jun-2015.)
|
| ⊢ ((𝐹 ∈ V ∧ 𝐹:𝐴–onto→𝐵) → 𝒫 𝐵 ≼ 𝒫 𝐴) |
| |
| Theorem | 0domg 7028 |
Any set dominates the empty set. (Contributed by NM, 26-Oct-2003.)
(Revised by Mario Carneiro, 26-Apr-2015.)
|
| ⊢ (𝐴 ∈ 𝑉 → ∅ ≼ 𝐴) |
| |
| Theorem | dom0 7029 |
A set dominated by the empty set is empty. (Contributed by NM,
22-Nov-2004.)
|
| ⊢ (𝐴 ≼ ∅ ↔ 𝐴 = ∅) |
| |
| Theorem | 0dom 7030 |
Any set dominates the empty set. (Contributed by NM, 26-Oct-2003.)
(Revised by Mario Carneiro, 26-Apr-2015.)
|
| ⊢ 𝐴 ∈ V ⇒ ⊢ ∅ ≼ 𝐴 |
| |
| Theorem | enen1 7031 |
Equality-like theorem for equinumerosity. (Contributed by NM,
18-Dec-2003.)
|
| ⊢ (𝐴 ≈ 𝐵 → (𝐴 ≈ 𝐶 ↔ 𝐵 ≈ 𝐶)) |
| |
| Theorem | enen2 7032 |
Equality-like theorem for equinumerosity. (Contributed by NM,
18-Dec-2003.)
|
| ⊢ (𝐴 ≈ 𝐵 → (𝐶 ≈ 𝐴 ↔ 𝐶 ≈ 𝐵)) |
| |
| Theorem | domen1 7033 |
Equality-like theorem for equinumerosity and dominance. (Contributed by
NM, 8-Nov-2003.)
|
| ⊢ (𝐴 ≈ 𝐵 → (𝐴 ≼ 𝐶 ↔ 𝐵 ≼ 𝐶)) |
| |
| Theorem | domen2 7034 |
Equality-like theorem for equinumerosity and dominance. (Contributed by
NM, 8-Nov-2003.)
|
| ⊢ (𝐴 ≈ 𝐵 → (𝐶 ≼ 𝐴 ↔ 𝐶 ≼ 𝐵)) |
| |
| 2.6.29 Equinumerosity (cont.)
|
| |
| Theorem | xpf1o 7035* |
Construct a bijection on a Cartesian product given bijections on the
factors. (Contributed by Mario Carneiro, 30-May-2015.)
|
| ⊢ (𝜑 → (𝑥 ∈ 𝐴 ↦ 𝑋):𝐴–1-1-onto→𝐵)
& ⊢ (𝜑 → (𝑦 ∈ 𝐶 ↦ 𝑌):𝐶–1-1-onto→𝐷) ⇒ ⊢ (𝜑 → (𝑥 ∈ 𝐴, 𝑦 ∈ 𝐶 ↦ 〈𝑋, 𝑌〉):(𝐴 × 𝐶)–1-1-onto→(𝐵 × 𝐷)) |
| |
| Theorem | xpen 7036 |
Equinumerosity law for Cartesian product. Proposition 4.22(b) of
[Mendelson] p. 254. (Contributed by
NM, 24-Jul-2004.)
|
| ⊢ ((𝐴 ≈ 𝐵 ∧ 𝐶 ≈ 𝐷) → (𝐴 × 𝐶) ≈ (𝐵 × 𝐷)) |
| |
| Theorem | mapen 7037 |
Two set exponentiations are equinumerous when their bases and exponents
are equinumerous. Theorem 6H(c) of [Enderton] p. 139. (Contributed by
NM, 16-Dec-2003.) (Proof shortened by Mario Carneiro, 26-Apr-2015.)
|
| ⊢ ((𝐴 ≈ 𝐵 ∧ 𝐶 ≈ 𝐷) → (𝐴 ↑𝑚 𝐶) ≈ (𝐵 ↑𝑚 𝐷)) |
| |
| Theorem | mapdom1g 7038 |
Order-preserving property of set exponentiation. (Contributed by Jim
Kingdon, 15-Jul-2022.)
|
| ⊢ ((𝐴 ≼ 𝐵 ∧ 𝐶 ∈ 𝑉) → (𝐴 ↑𝑚 𝐶) ≼ (𝐵 ↑𝑚 𝐶)) |
| |
| Theorem | mapxpen 7039 |
Equinumerosity law for double set exponentiation. Proposition 10.45 of
[TakeutiZaring] p. 96.
(Contributed by NM, 21-Feb-2004.) (Revised by
Mario Carneiro, 24-Jun-2015.)
|
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐶 ∈ 𝑋) → ((𝐴 ↑𝑚 𝐵) ↑𝑚
𝐶) ≈ (𝐴 ↑𝑚
(𝐵 × 𝐶))) |
| |
| Theorem | xpmapenlem 7040* |
Lemma for xpmapen 7041. (Contributed by NM, 1-May-2004.) (Revised
by
Mario Carneiro, 16-Nov-2014.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V & ⊢ 𝐶 ∈ V & ⊢ 𝐷 = (𝑧 ∈ 𝐶 ↦ (1st ‘(𝑥‘𝑧))) & ⊢ 𝑅 = (𝑧 ∈ 𝐶 ↦ (2nd ‘(𝑥‘𝑧))) & ⊢ 𝑆 = (𝑧 ∈ 𝐶 ↦ 〈((1st
‘𝑦)‘𝑧), ((2nd
‘𝑦)‘𝑧)〉) ⇒ ⊢ ((𝐴 × 𝐵) ↑𝑚 𝐶) ≈ ((𝐴 ↑𝑚 𝐶) × (𝐵 ↑𝑚 𝐶)) |
| |
| Theorem | xpmapen 7041 |
Equinumerosity law for set exponentiation of a Cartesian product.
Exercise 4.47 of [Mendelson] p. 255.
(Contributed by NM, 23-Feb-2004.)
(Proof shortened by Mario Carneiro, 16-Nov-2014.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V & ⊢ 𝐶 ∈
V ⇒ ⊢ ((𝐴 × 𝐵) ↑𝑚 𝐶) ≈ ((𝐴 ↑𝑚 𝐶) × (𝐵 ↑𝑚 𝐶)) |
| |
| Theorem | ssenen 7042* |
Equinumerosity of equinumerous subsets of a set. (Contributed by NM,
30-Sep-2004.) (Revised by Mario Carneiro, 16-Nov-2014.)
|
| ⊢ (𝐴 ≈ 𝐵 → {𝑥 ∣ (𝑥 ⊆ 𝐴 ∧ 𝑥 ≈ 𝐶)} ≈ {𝑥 ∣ (𝑥 ⊆ 𝐵 ∧ 𝑥 ≈ 𝐶)}) |
| |
| 2.6.30 Pigeonhole Principle
|
| |
| Theorem | phplem1 7043 |
Lemma for Pigeonhole Principle. If we join a natural number to itself
minus an element, we end up with its successor minus the same element.
(Contributed by NM, 25-May-1998.)
|
| ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ 𝐴) → ({𝐴} ∪ (𝐴 ∖ {𝐵})) = (suc 𝐴 ∖ {𝐵})) |
| |
| Theorem | phplem2 7044 |
Lemma for Pigeonhole Principle. A natural number is equinumerous to its
successor minus one of its elements. (Contributed by NM, 11-Jun-1998.)
(Revised by Mario Carneiro, 16-Nov-2014.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ 𝐴) → 𝐴 ≈ (suc 𝐴 ∖ {𝐵})) |
| |
| Theorem | phplem3 7045 |
Lemma for Pigeonhole Principle. A natural number is equinumerous to its
successor minus any element of the successor. For a version without the
redundant hypotheses, see phplem3g 7047. (Contributed by NM,
26-May-1998.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ suc 𝐴) → 𝐴 ≈ (suc 𝐴 ∖ {𝐵})) |
| |
| Theorem | phplem4 7046 |
Lemma for Pigeonhole Principle. Equinumerosity of successors implies
equinumerosity of the original natural numbers. (Contributed by NM,
28-May-1998.) (Revised by Mario Carneiro, 24-Jun-2015.)
|
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ ω) → (suc 𝐴 ≈ suc 𝐵 → 𝐴 ≈ 𝐵)) |
| |
| Theorem | phplem3g 7047 |
A natural number is equinumerous to its successor minus any element of
the successor. Version of phplem3 7045 with unnecessary hypotheses
removed. (Contributed by Jim Kingdon, 1-Sep-2021.)
|
| ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ suc 𝐴) → 𝐴 ≈ (suc 𝐴 ∖ {𝐵})) |
| |
| Theorem | nneneq 7048 |
Two equinumerous natural numbers are equal. Proposition 10.20 of
[TakeutiZaring] p. 90 and its
converse. Also compare Corollary 6E of
[Enderton] p. 136. (Contributed by NM,
28-May-1998.)
|
| ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ ω) → (𝐴 ≈ 𝐵 ↔ 𝐴 = 𝐵)) |
| |
| Theorem | php5 7049 |
A natural number is not equinumerous to its successor. Corollary
10.21(1) of [TakeutiZaring] p. 90.
(Contributed by NM, 26-Jul-2004.)
|
| ⊢ (𝐴 ∈ ω → ¬ 𝐴 ≈ suc 𝐴) |
| |
| Theorem | snnen2og 7050 |
A singleton {𝐴} is never equinumerous with the
ordinal number 2. If
𝐴 is a proper class, see snnen2oprc 7051. (Contributed by Jim Kingdon,
1-Sep-2021.)
|
| ⊢ (𝐴 ∈ 𝑉 → ¬ {𝐴} ≈ 2o) |
| |
| Theorem | snnen2oprc 7051 |
A singleton {𝐴} is never equinumerous with the
ordinal number 2. If
𝐴 is a set, see snnen2og 7050. (Contributed by Jim Kingdon,
1-Sep-2021.)
|
| ⊢ (¬ 𝐴 ∈ V → ¬ {𝐴} ≈ 2o) |
| |
| Theorem | 1nen2 7052 |
One and two are not equinumerous. (Contributed by Jim Kingdon,
25-Jan-2022.)
|
| ⊢ ¬ 1o ≈
2o |
| |
| Theorem | phplem4dom 7053 |
Dominance of successors implies dominance of the original natural
numbers. (Contributed by Jim Kingdon, 1-Sep-2021.)
|
| ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ ω) → (suc 𝐴 ≼ suc 𝐵 → 𝐴 ≼ 𝐵)) |
| |
| Theorem | php5dom 7054 |
A natural number does not dominate its successor. (Contributed by Jim
Kingdon, 1-Sep-2021.)
|
| ⊢ (𝐴 ∈ ω → ¬ suc 𝐴 ≼ 𝐴) |
| |
| Theorem | nndomo 7055 |
Cardinal ordering agrees with natural number ordering. Example 3 of
[Enderton] p. 146. (Contributed by NM,
17-Jun-1998.)
|
| ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ ω) → (𝐴 ≼ 𝐵 ↔ 𝐴 ⊆ 𝐵)) |
| |
| Theorem | 1ndom2 7056 |
Two is not dominated by one. (Contributed by Jim Kingdon,
10-Jan-2026.)
|
| ⊢ ¬ 2o ≼
1o |
| |
| Theorem | phpm 7057* |
Pigeonhole Principle. A natural number is not equinumerous to a proper
subset of itself. By "proper subset" here we mean that there
is an
element which is in the natural number and not in the subset, or in
symbols ∃𝑥𝑥 ∈ (𝐴 ∖ 𝐵) (which is stronger than not being
equal
in the absence of excluded middle). Theorem (Pigeonhole Principle) of
[Enderton] p. 134. The theorem is
so-called because you can't put n +
1 pigeons into n holes (if each hole holds only one pigeon). The
proof consists of lemmas phplem1 7043 through phplem4 7046, nneneq 7048, and
this final piece of the proof. (Contributed by NM, 29-May-1998.)
|
| ⊢ ((𝐴 ∈ ω ∧ 𝐵 ⊆ 𝐴 ∧ ∃𝑥 𝑥 ∈ (𝐴 ∖ 𝐵)) → ¬ 𝐴 ≈ 𝐵) |
| |
| Theorem | phpelm 7058 |
Pigeonhole Principle. A natural number is not equinumerous to an
element of itself. (Contributed by Jim Kingdon, 6-Sep-2021.)
|
| ⊢ ((𝐴 ∈ ω ∧ 𝐵 ∈ 𝐴) → ¬ 𝐴 ≈ 𝐵) |
| |
| Theorem | phplem4on 7059 |
Equinumerosity of successors of an ordinal and a natural number implies
equinumerosity of the originals. (Contributed by Jim Kingdon,
5-Sep-2021.)
|
| ⊢ ((𝐴 ∈ On ∧ 𝐵 ∈ ω) → (suc 𝐴 ≈ suc 𝐵 → 𝐴 ≈ 𝐵)) |
| |
| 2.6.31 Finite sets
|
| |
| Theorem | fict 7060 |
A finite set is dominated by ω. Also see finct 7320. (Contributed
by Thierry Arnoux, 27-Mar-2018.)
|
| ⊢ (𝐴 ∈ Fin → 𝐴 ≼ ω) |
| |
| Theorem | fidceq 7061 |
Equality of members of a finite set is decidable. This may be
counterintuitive: cannot any two sets be elements of a finite set?
Well, to show, for example, that {𝐵, 𝐶} is finite would require
showing it is equinumerous to 1o or
to 2o but to show that you'd
need to know 𝐵 = 𝐶 or ¬ 𝐵 = 𝐶, respectively. (Contributed by
Jim Kingdon, 5-Sep-2021.)
|
| ⊢ ((𝐴 ∈ Fin ∧ 𝐵 ∈ 𝐴 ∧ 𝐶 ∈ 𝐴) → DECID 𝐵 = 𝐶) |
| |
| Theorem | fidifsnen 7062 |
All decrements of a finite set are equinumerous. (Contributed by Jim
Kingdon, 9-Sep-2021.)
|
| ⊢ ((𝑋 ∈ Fin ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋) → (𝑋 ∖ {𝐴}) ≈ (𝑋 ∖ {𝐵})) |
| |
| Theorem | fidifsnid 7063 |
If we remove a single element from a finite set then put it back in, we
end up with the original finite set. This strengthens difsnss 3820 from
subset to equality when the set is finite. (Contributed by Jim Kingdon,
9-Sep-2021.)
|
| ⊢ ((𝐴 ∈ Fin ∧ 𝐵 ∈ 𝐴) → ((𝐴 ∖ {𝐵}) ∪ {𝐵}) = 𝐴) |
| |
| Theorem | nnfi 7064 |
Natural numbers are finite sets. (Contributed by Stefan O'Rear,
21-Mar-2015.)
|
| ⊢ (𝐴 ∈ ω → 𝐴 ∈ Fin) |
| |
| Theorem | enfi 7065 |
Equinumerous sets have the same finiteness. (Contributed by NM,
22-Aug-2008.)
|
| ⊢ (𝐴 ≈ 𝐵 → (𝐴 ∈ Fin ↔ 𝐵 ∈ Fin)) |
| |
| Theorem | enfii 7066 |
A set equinumerous to a finite set is finite. (Contributed by Mario
Carneiro, 12-Mar-2015.)
|
| ⊢ ((𝐵 ∈ Fin ∧ 𝐴 ≈ 𝐵) → 𝐴 ∈ Fin) |
| |
| Theorem | ssfilem 7067* |
Lemma for ssfiexmid 7068. (Contributed by Jim Kingdon, 3-Feb-2022.)
|
| ⊢ {𝑧 ∈ {∅} ∣ 𝜑} ∈ Fin ⇒ ⊢ (𝜑 ∨ ¬ 𝜑) |
| |
| Theorem | ssfiexmid 7068* |
If any subset of a finite set is finite, excluded middle follows. One
direction of Theorem 2.1 of [Bauer], p.
485. (Contributed by Jim
Kingdon, 19-May-2020.)
|
| ⊢ ∀𝑥∀𝑦((𝑥 ∈ Fin ∧ 𝑦 ⊆ 𝑥) → 𝑦 ∈ Fin) ⇒ ⊢ (𝜑 ∨ ¬ 𝜑) |
| |
| Theorem | ssfilemd 7069* |
Lemma for ssfiexmidt 7070. (Contributed by Jim Kingdon, 3-Feb-2022.)
|
| ⊢ (𝜑 → {𝑧 ∈ {∅} ∣ 𝜓} ∈ Fin)
⇒ ⊢ (𝜑 → (𝜓 ∨ ¬ 𝜓)) |
| |
| Theorem | ssfiexmidt 7070* |
If any subset of a finite set is finite, excluded middle follows. One
direction of Theorem 2.1 of [Bauer], p.
485. (Contributed by Jim
Kingdon, 19-May-2020.)
|
| ⊢ (∀𝑥∀𝑦((𝑥 ∈ Fin ∧ 𝑦 ⊆ 𝑥) → 𝑦 ∈ Fin) → (𝜑 ∨ ¬ 𝜑)) |
| |
| Theorem | infiexmid 7071* |
If the intersection of any finite set and any other set is finite,
excluded middle follows. (Contributed by Jim Kingdon, 5-Feb-2022.)
|
| ⊢ (𝑥 ∈ Fin → (𝑥 ∩ 𝑦) ∈ Fin) ⇒ ⊢ (𝜑 ∨ ¬ 𝜑) |
| |
| Theorem | domfiexmid 7072* |
If any set dominated by a finite set is finite, excluded middle follows.
(Contributed by Jim Kingdon, 3-Feb-2022.)
|
| ⊢ ((𝑥 ∈ Fin ∧ 𝑦 ≼ 𝑥) → 𝑦 ∈ Fin) ⇒ ⊢ (𝜑 ∨ ¬ 𝜑) |
| |
| Theorem | dif1en 7073 |
If a set 𝐴 is equinumerous to the successor of
a natural number
𝑀, then 𝐴 with an element removed
is equinumerous to 𝑀.
(Contributed by Jeff Madsen, 2-Sep-2009.) (Revised by Stefan O'Rear,
16-Aug-2015.)
|
| ⊢ ((𝑀 ∈ ω ∧ 𝐴 ≈ suc 𝑀 ∧ 𝑋 ∈ 𝐴) → (𝐴 ∖ {𝑋}) ≈ 𝑀) |
| |
| Theorem | dif1enen 7074 |
Subtracting one element from each of two equinumerous finite sets.
(Contributed by Jim Kingdon, 5-Jun-2022.)
|
| ⊢ (𝜑 → 𝐴 ∈ Fin) & ⊢ (𝜑 → 𝐴 ≈ 𝐵)
& ⊢ (𝜑 → 𝐶 ∈ 𝐴)
& ⊢ (𝜑 → 𝐷 ∈ 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∖ {𝐶}) ≈ (𝐵 ∖ {𝐷})) |
| |
| Theorem | fiunsnnn 7075 |
Adding one element to a finite set which is equinumerous to a natural
number. (Contributed by Jim Kingdon, 13-Sep-2021.)
|
| ⊢ (((𝐴 ∈ Fin ∧ 𝐵 ∈ (V ∖ 𝐴)) ∧ (𝑁 ∈ ω ∧ 𝐴 ≈ 𝑁)) → (𝐴 ∪ {𝐵}) ≈ suc 𝑁) |
| |
| Theorem | php5fin 7076 |
A finite set is not equinumerous to a set which adds one element.
(Contributed by Jim Kingdon, 13-Sep-2021.)
|
| ⊢ ((𝐴 ∈ Fin ∧ 𝐵 ∈ (V ∖ 𝐴)) → ¬ 𝐴 ≈ (𝐴 ∪ {𝐵})) |
| |
| Theorem | fisbth 7077 |
Schroeder-Bernstein Theorem for finite sets. (Contributed by Jim
Kingdon, 12-Sep-2021.)
|
| ⊢ (((𝐴 ∈ Fin ∧ 𝐵 ∈ Fin) ∧ (𝐴 ≼ 𝐵 ∧ 𝐵 ≼ 𝐴)) → 𝐴 ≈ 𝐵) |
| |
| Theorem | 0fi 7078 |
The empty set is finite. (Contributed by FL, 14-Jul-2008.)
|
| ⊢ ∅ ∈ Fin |
| |
| Theorem | fin0 7079* |
A nonempty finite set has at least one element. (Contributed by Jim
Kingdon, 10-Sep-2021.)
|
| ⊢ (𝐴 ∈ Fin → (𝐴 ≠ ∅ ↔ ∃𝑥 𝑥 ∈ 𝐴)) |
| |
| Theorem | fin0or 7080* |
A finite set is either empty or inhabited. (Contributed by Jim Kingdon,
30-Sep-2021.)
|
| ⊢ (𝐴 ∈ Fin → (𝐴 = ∅ ∨ ∃𝑥 𝑥 ∈ 𝐴)) |
| |
| Theorem | diffitest 7081* |
If subtracting any set from a finite set gives a finite set, any
proposition of the form ¬ 𝜑 is decidable. This is not a proof
of
full excluded middle, but it is close enough to show we won't be able to
prove 𝐴 ∈ Fin → (𝐴 ∖ 𝐵) ∈ Fin. (Contributed by Jim
Kingdon,
8-Sep-2021.)
|
| ⊢ ∀𝑎 ∈ Fin ∀𝑏(𝑎 ∖ 𝑏) ∈ Fin ⇒ ⊢ (¬ 𝜑 ∨ ¬ ¬ 𝜑) |
| |
| Theorem | findcard 7082* |
Schema for induction on the cardinality of a finite set. The inductive
hypothesis is that the result is true on the given set with any one
element removed. The result is then proven to be true for all finite
sets. (Contributed by Jeff Madsen, 2-Sep-2009.)
|
| ⊢ (𝑥 = ∅ → (𝜑 ↔ 𝜓)) & ⊢ (𝑥 = (𝑦 ∖ {𝑧}) → (𝜑 ↔ 𝜒)) & ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜃)) & ⊢ (𝑥 = 𝐴 → (𝜑 ↔ 𝜏)) & ⊢ 𝜓 & ⊢ (𝑦 ∈ Fin →
(∀𝑧 ∈ 𝑦 𝜒 → 𝜃)) ⇒ ⊢ (𝐴 ∈ Fin → 𝜏) |
| |
| Theorem | findcard2 7083* |
Schema for induction on the cardinality of a finite set. The inductive
step shows that the result is true if one more element is added to the
set. The result is then proven to be true for all finite sets.
(Contributed by Jeff Madsen, 8-Jul-2010.)
|
| ⊢ (𝑥 = ∅ → (𝜑 ↔ 𝜓)) & ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜒)) & ⊢ (𝑥 = (𝑦 ∪ {𝑧}) → (𝜑 ↔ 𝜃)) & ⊢ (𝑥 = 𝐴 → (𝜑 ↔ 𝜏)) & ⊢ 𝜓 & ⊢ (𝑦 ∈ Fin → (𝜒 → 𝜃)) ⇒ ⊢ (𝐴 ∈ Fin → 𝜏) |
| |
| Theorem | findcard2s 7084* |
Variation of findcard2 7083 requiring that the element added in the
induction step not be a member of the original set. (Contributed by
Paul Chapman, 30-Nov-2012.)
|
| ⊢ (𝑥 = ∅ → (𝜑 ↔ 𝜓)) & ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜒)) & ⊢ (𝑥 = (𝑦 ∪ {𝑧}) → (𝜑 ↔ 𝜃)) & ⊢ (𝑥 = 𝐴 → (𝜑 ↔ 𝜏)) & ⊢ 𝜓 & ⊢ ((𝑦 ∈ Fin ∧ ¬ 𝑧 ∈ 𝑦) → (𝜒 → 𝜃)) ⇒ ⊢ (𝐴 ∈ Fin → 𝜏) |
| |
| Theorem | findcard2d 7085* |
Deduction version of findcard2 7083. If you also need 𝑦 ∈ Fin (which
doesn't come for free due to ssfiexmid 7068), use findcard2sd 7086 instead.
(Contributed by SO, 16-Jul-2018.)
|
| ⊢ (𝑥 = ∅ → (𝜓 ↔ 𝜒)) & ⊢ (𝑥 = 𝑦 → (𝜓 ↔ 𝜃)) & ⊢ (𝑥 = (𝑦 ∪ {𝑧}) → (𝜓 ↔ 𝜏)) & ⊢ (𝑥 = 𝐴 → (𝜓 ↔ 𝜂)) & ⊢ (𝜑 → 𝜒)
& ⊢ ((𝜑 ∧ (𝑦 ⊆ 𝐴 ∧ 𝑧 ∈ (𝐴 ∖ 𝑦))) → (𝜃 → 𝜏)) & ⊢ (𝜑 → 𝐴 ∈ Fin) ⇒ ⊢ (𝜑 → 𝜂) |
| |
| Theorem | findcard2sd 7086* |
Deduction form of finite set induction . (Contributed by Jim Kingdon,
14-Sep-2021.)
|
| ⊢ (𝑥 = ∅ → (𝜓 ↔ 𝜒)) & ⊢ (𝑥 = 𝑦 → (𝜓 ↔ 𝜃)) & ⊢ (𝑥 = (𝑦 ∪ {𝑧}) → (𝜓 ↔ 𝜏)) & ⊢ (𝑥 = 𝐴 → (𝜓 ↔ 𝜂)) & ⊢ (𝜑 → 𝜒)
& ⊢ (((𝜑 ∧ 𝑦 ∈ Fin) ∧ (𝑦 ⊆ 𝐴 ∧ 𝑧 ∈ (𝐴 ∖ 𝑦))) → (𝜃 → 𝜏)) & ⊢ (𝜑 → 𝐴 ∈ Fin) ⇒ ⊢ (𝜑 → 𝜂) |
| |
| Theorem | diffisn 7087 |
Subtracting a singleton from a finite set produces a finite set.
(Contributed by Jim Kingdon, 11-Sep-2021.)
|
| ⊢ ((𝐴 ∈ Fin ∧ 𝐵 ∈ 𝐴) → (𝐴 ∖ {𝐵}) ∈ Fin) |
| |
| Theorem | diffifi 7088 |
Subtracting one finite set from another produces a finite set.
(Contributed by Jim Kingdon, 8-Sep-2021.)
|
| ⊢ ((𝐴 ∈ Fin ∧ 𝐵 ∈ Fin ∧ 𝐵 ⊆ 𝐴) → (𝐴 ∖ 𝐵) ∈ Fin) |
| |
| Theorem | infnfi 7089 |
An infinite set is not finite. (Contributed by Jim Kingdon,
20-Feb-2022.)
|
| ⊢ (ω ≼ 𝐴 → ¬ 𝐴 ∈ Fin) |
| |
| Theorem | ominf 7090 |
The set of natural numbers is not finite. Although we supply this theorem
because we can, the more natural way to express "ω is infinite" is
ω ≼ ω which is an instance of domrefg 6945. (Contributed by NM,
2-Jun-1998.)
|
| ⊢ ¬ ω ∈ Fin |
| |
| Theorem | isinfinf 7091* |
An infinite set contains subsets of arbitrarily large finite
cardinality. (Contributed by Jim Kingdon, 15-Jun-2022.)
|
| ⊢ (ω ≼ 𝐴 → ∀𝑛 ∈ ω ∃𝑥(𝑥 ⊆ 𝐴 ∧ 𝑥 ≈ 𝑛)) |
| |
| Theorem | ac6sfi 7092* |
Existence of a choice function for finite sets. (Contributed by Jeff
Hankins, 26-Jun-2009.) (Proof shortened by Mario Carneiro,
29-Jan-2014.)
|
| ⊢ (𝑦 = (𝑓‘𝑥) → (𝜑 ↔ 𝜓)) ⇒ ⊢ ((𝐴 ∈ Fin ∧ ∀𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐵 𝜑) → ∃𝑓(𝑓:𝐴⟶𝐵 ∧ ∀𝑥 ∈ 𝐴 𝜓)) |
| |
| Theorem | fidcen 7093 |
Equinumerosity of finite sets is decidable. (Contributed by Jim
Kingdon, 10-Feb-2026.)
|
| ⊢ ((𝐴 ∈ Fin ∧ 𝐵 ∈ Fin) → DECID
𝐴 ≈ 𝐵) |
| |
| Theorem | tridc 7094* |
A trichotomous order is decidable. (Contributed by Jim Kingdon,
5-Sep-2022.)
|
| ⊢ (𝜑 → 𝑅 Po 𝐴)
& ⊢ (𝜑 → ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 (𝑥𝑅𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦𝑅𝑥))
& ⊢ (𝜑 → 𝐵 ∈ 𝐴)
& ⊢ (𝜑 → 𝐶 ∈ 𝐴) ⇒ ⊢ (𝜑 → DECID 𝐵𝑅𝐶) |
| |
| Theorem | fimax2gtrilemstep 7095* |
Lemma for fimax2gtri 7096. The induction step. (Contributed by Jim
Kingdon, 5-Sep-2022.)
|
| ⊢ (𝜑 → 𝑅 Po 𝐴)
& ⊢ (𝜑 → ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 (𝑥𝑅𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦𝑅𝑥))
& ⊢ (𝜑 → 𝐴 ∈ Fin) & ⊢ (𝜑 → 𝐴 ≠ ∅) & ⊢ (𝜑 → 𝑈 ∈ Fin) & ⊢ (𝜑 → 𝑈 ⊆ 𝐴)
& ⊢ (𝜑 → 𝑍 ∈ 𝐴)
& ⊢ (𝜑 → 𝑉 ∈ 𝐴)
& ⊢ (𝜑 → ¬ 𝑉 ∈ 𝑈)
& ⊢ (𝜑 → ∀𝑦 ∈ 𝑈 ¬ 𝑍𝑅𝑦) ⇒ ⊢ (𝜑 → ∃𝑥 ∈ 𝐴 ∀𝑦 ∈ (𝑈 ∪ {𝑉}) ¬ 𝑥𝑅𝑦) |
| |
| Theorem | fimax2gtri 7096* |
A finite set has a maximum under a trichotomous order. (Contributed
by Jim Kingdon, 5-Sep-2022.)
|
| ⊢ (𝜑 → 𝑅 Po 𝐴)
& ⊢ (𝜑 → ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 (𝑥𝑅𝑦 ∨ 𝑥 = 𝑦 ∨ 𝑦𝑅𝑥))
& ⊢ (𝜑 → 𝐴 ∈ Fin) & ⊢ (𝜑 → 𝐴 ≠ ∅)
⇒ ⊢ (𝜑 → ∃𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 ¬ 𝑥𝑅𝑦) |
| |
| Theorem | finexdc 7097* |
Decidability of existence, over a finite set and defined by a decidable
proposition. (Contributed by Jim Kingdon, 12-Jul-2022.)
|
| ⊢ ((𝐴 ∈ Fin ∧ ∀𝑥 ∈ 𝐴 DECID 𝜑) → DECID ∃𝑥 ∈ 𝐴 𝜑) |
| |
| Theorem | dfrex2fin 7098* |
Relationship between universal and existential quantifiers over a finite
set. Remark in Section 2.2.1 of [Pierik], p. 8. Although Pierik does
not mention the decidability condition explicitly, it does say
"only
finitely many x to check" which means there must be some way of
checking
each value of x. (Contributed by Jim Kingdon, 11-Jul-2022.)
|
| ⊢ ((𝐴 ∈ Fin ∧ ∀𝑥 ∈ 𝐴 DECID 𝜑) → (∃𝑥 ∈ 𝐴 𝜑 ↔ ¬ ∀𝑥 ∈ 𝐴 ¬ 𝜑)) |
| |
| Theorem | elssdc 7099* |
Membership in a finite subset of a set with decidable equality is
decidable. (Contributed by Jim Kingdon, 11-Feb-2026.)
|
| ⊢ (𝜑 → ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐵 DECID 𝑥 = 𝑦)
& ⊢ (𝜑 → 𝑋 ∈ 𝐵)
& ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
& ⊢ (𝜑 → 𝐴 ∈ Fin) ⇒ ⊢ (𝜑 → DECID 𝑋 ∈ 𝐴) |
| |
| Theorem | eqsndc 7100* |
Decidability of equality between a finite subset of a set with
decidable equality, and a singleton whose element is an element of the
larger set. (Contributed by Jim Kingdon, 15-Feb-2026.)
|
| ⊢ (𝜑 → ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐵 DECID 𝑥 = 𝑦)
& ⊢ (𝜑 → 𝑋 ∈ 𝐵)
& ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
& ⊢ (𝜑 → 𝐴 ∈ Fin) ⇒ ⊢ (𝜑 → DECID 𝐴 = {𝑋}) |