Theorem List for Intuitionistic Logic Explorer - 11201-11300 *Has distinct variable
group(s)
| Type | Label | Description |
| Statement |
| |
| Theorem | fstwrdne 11201 |
The first symbol of a nonempty word is element of the alphabet for the
word. (Contributed by AV, 28-Sep-2018.) (Proof shortened by AV,
14-Oct-2018.)
|
  Word        |
| |
| Theorem | fstwrdne0 11202 |
The first symbol of a nonempty word is element of the alphabet for the
word. (Contributed by AV, 29-Sep-2018.) (Proof shortened by AV,
14-Oct-2018.)
|
   Word ♯          |
| |
| Theorem | eqwrd 11203* |
Two words are equal iff they have the same length and the same symbol at
each position. (Contributed by AV, 13-Apr-2018.) (Revised by JJ,
30-Dec-2023.)
|
  Word Word    ♯ 
♯    ..^ ♯                |
| |
| Theorem | elovmpowrd 11204* |
Implications for the value of an operation defined by the maps-to
notation with a class abstraction of words as a result having an
element. Note that may depend on as well as on and
. (Contributed
by Alexander van der Vekens, 15-Jul-2018.)
|
   Word        
Word    |
| |
| Theorem | wrdred1 11205 |
A word truncated by a symbol is a word. (Contributed by AV,
29-Jan-2021.)
|
 Word   ..^ ♯     Word
  |
| |
| Theorem | wrdred1hash 11206 |
The length of a word truncated by a symbol. (Contributed by Alexander van
der Vekens, 1-Nov-2017.) (Revised by AV, 29-Jan-2021.)
|
  Word ♯   ♯   ..^ ♯       ♯     |
| |
| 4.7.2 Last symbol of a word
|
| |
| Syntax | clsw 11207 |
Extend class notation with the Last Symbol of a word.
|
lastS |
| |
| Definition | df-lsw 11208 |
Extract the last symbol of a word. May be not meaningful for other sets
which are not words. The name lastS (as abbreviation of
"lastSymbol")
is a compromise between usually used names for corresponding functions in
computer programs (as last() or lastChar()), the terminology used for
words in set.mm ("symbol" instead of "character") and
brevity ("lastS" is
shorter than "lastChar" and "lastSymbol"). Labels of
theorems about last
symbols of a word will contain the abbreviation "lsw" (Last
Symbol of a
Word). (Contributed by Alexander van der Vekens, 18-Mar-2018.)
|
lastS      ♯      |
| |
| Theorem | lswwrd 11209 |
Extract the last symbol of a word. (Contributed by Alexander van der
Vekens, 18-Mar-2018.) (Revised by Jim Kingdon, 18-Dec-2025.)
|
 Word lastS      ♯      |
| |
| Theorem | lsw0 11210 |
The last symbol of an empty word does not exist. (Contributed by
Alexander van der Vekens, 19-Mar-2018.) (Proof shortened by AV,
2-May-2020.)
|
  Word ♯   lastS    |
| |
| Theorem | lsw0g 11211 |
The last symbol of an empty word does not exist. (Contributed by
Alexander van der Vekens, 11-Nov-2018.)
|
lastS   |
| |
| Theorem | lsw1 11212 |
The last symbol of a word of length 1 is the first symbol of this word.
(Contributed by Alexander van der Vekens, 19-Mar-2018.)
|
  Word ♯   lastS        |
| |
| Theorem | lswcl 11213 |
Closure of the last symbol: the last symbol of a nonempty word belongs to
the alphabet for the word. (Contributed by AV, 2-Aug-2018.) (Proof
shortened by AV, 29-Apr-2020.)
|
  Word  lastS    |
| |
| Theorem | lswex 11214 |
Existence of the last symbol. The last symbol of a word is a set. See
lsw0g 11211 or lswcl 11213 if you want more specific results
for empty or
nonempty words, respectively. (Contributed by Jim Kingdon,
27-Dec-2025.)
|
 Word lastS    |
| |
| Theorem | lswlgt0cl 11215 |
The last symbol of a nonempty word is an element of the alphabet for the
word. (Contributed by Alexander van der Vekens, 1-Oct-2018.) (Proof
shortened by AV, 29-Apr-2020.)
|
   Word ♯    lastS    |
| |
| 4.7.3 Concatenations of words
|
| |
| Syntax | cconcat 11216 |
Syntax for the concatenation operator.
|
++ |
| |
| Definition | df-concat 11217* |
Define the concatenation operator which combines two words. Definition
in Section 9.1 of [AhoHopUll] p. 318.
(Contributed by FL, 14-Jan-2014.)
(Revised by Stefan O'Rear, 15-Aug-2015.)
|
++     ..^ ♯  ♯       ..^ ♯             ♯        |
| |
| Theorem | ccatfvalfi 11218* |
Value of the concatenation operator. (Contributed by Stefan O'Rear,
15-Aug-2015.)
|
    ++    ..^ ♯  ♯       ..^ ♯             ♯        |
| |
| Theorem | ccatcl 11219 |
The concatenation of two words is a word. (Contributed by FL,
2-Feb-2014.) (Proof shortened by Stefan O'Rear, 15-Aug-2015.) (Proof
shortened by AV, 29-Apr-2020.)
|
  Word Word   ++ 
Word   |
| |
| Theorem | ccatclab 11220 |
The concatenation of words over two sets is a word over the union of
those sets. (Contributed by Jim Kingdon, 19-Dec-2025.)
|
  Word Word   ++ 
Word     |
| |
| Theorem | ccatlen 11221 |
The length of a concatenated word. (Contributed by Stefan O'Rear,
15-Aug-2015.) (Revised by JJ, 1-Jan-2024.)
|
  Word Word  ♯  ++    ♯  ♯     |
| |
| Theorem | ccat0 11222 |
The concatenation of two words is empty iff the two words are empty.
(Contributed by AV, 4-Mar-2022.) (Revised by JJ, 18-Jan-2024.)
|
  Word Word    ++  
    |
| |
| Theorem | ccatval1 11223 |
Value of a symbol in the left half of a concatenated word. (Contributed
by Stefan O'Rear, 15-Aug-2015.) (Revised by Mario Carneiro,
22-Sep-2015.) (Proof shortened by AV, 30-Apr-2020.) (Revised by JJ,
18-Jan-2024.)
|
  Word Word
 ..^ ♯      ++           |
| |
| Theorem | ccatval2 11224 |
Value of a symbol in the right half of a concatenated word.
(Contributed by Stefan O'Rear, 15-Aug-2015.) (Revised by Mario
Carneiro, 22-Sep-2015.)
|
  Word Word
 ♯  ..^ ♯  ♯       ++         ♯      |
| |
| Theorem | ccatval3 11225 |
Value of a symbol in the right half of a concatenated word, using an
index relative to the subword. (Contributed by Stefan O'Rear,
16-Aug-2015.) (Proof shortened by AV, 30-Apr-2020.)
|
  Word Word
 ..^ ♯      ++     ♯          |
| |
| Theorem | elfzelfzccat 11226 |
An element of a finite set of sequential integers up to the length of a
word is an element of an extended finite set of sequential integers up to
the length of a concatenation of this word with another word.
(Contributed by Alexander van der Vekens, 28-Mar-2018.)
|
  Word Word      ♯  
   ♯  ++       |
| |
| Theorem | ccatvalfn 11227 |
The concatenation of two words is a function over the half-open integer
range having the sum of the lengths of the word as length. (Contributed
by Alexander van der Vekens, 30-Mar-2018.)
|
  Word Word   ++   ..^ ♯  ♯      |
| |
| Theorem | ccatsymb 11228 |
The symbol at a given position in a concatenated word. (Contributed by
AV, 26-May-2018.) (Proof shortened by AV, 24-Nov-2018.)
|
  Word Word
   ++       ♯            ♯       |
| |
| Theorem | ccatfv0 11229 |
The first symbol of a concatenation of two words is the first symbol of
the first word if the first word is not empty. (Contributed by Alexander
van der Vekens, 22-Sep-2018.)
|
  Word Word
♯  
  ++    
      |
| |
| Theorem | ccatval1lsw 11230 |
The last symbol of the left (nonempty) half of a concatenated word.
(Contributed by Alexander van der Vekens, 3-Oct-2018.) (Proof shortened
by AV, 1-May-2020.)
|
  Word Word    ++     ♯    lastS    |
| |
| Theorem | ccatval21sw 11231 |
The first symbol of the right (nonempty) half of a concatenated word.
(Contributed by AV, 23-Apr-2022.)
|
  Word Word    ++    ♯  
      |
| |
| Theorem | ccatlid 11232 |
Concatenation of a word by the empty word on the left. (Contributed by
Stefan O'Rear, 15-Aug-2015.) (Proof shortened by AV, 1-May-2020.)
|
 Word 
++    |
| |
| Theorem | ccatrid 11233 |
Concatenation of a word by the empty word on the right. (Contributed by
Stefan O'Rear, 15-Aug-2015.) (Proof shortened by AV, 1-May-2020.)
|
 Word  ++    |
| |
| Theorem | ccatass 11234 |
Associative law for concatenation of words. (Contributed by Stefan
O'Rear, 15-Aug-2015.)
|
  Word Word Word
   ++  ++   ++  ++     |
| |
| Theorem | ccatrn 11235 |
The range of a concatenated word. (Contributed by Stefan O'Rear,
15-Aug-2015.)
|
  Word Word 
 ++      |
| |
| Theorem | ccatidid 11236 |
Concatenation of the empty word by the empty word. (Contributed by AV,
26-Mar-2022.)
|

++   |
| |
| Theorem | lswccatn0lsw 11237 |
The last symbol of a word concatenated with a nonempty word is the last
symbol of the nonempty word. (Contributed by AV, 22-Oct-2018.) (Proof
shortened by AV, 1-May-2020.)
|
  Word Word  lastS  ++  
lastS    |
| |
| Theorem | lswccat0lsw 11238 |
The last symbol of a word concatenated with the empty word is the last
symbol of the word. (Contributed by AV, 22-Oct-2018.) (Proof shortened
by AV, 1-May-2020.)
|
 Word lastS  ++   lastS    |
| |
| Theorem | ccatalpha 11239 |
A concatenation of two arbitrary words is a word over an alphabet iff
the symbols of both words belong to the alphabet. (Contributed by AV,
28-Feb-2021.)
|
  Word Word    ++  Word  Word
Word     |
| |
| Theorem | ccatrcl1 11240 |
Reverse closure of a concatenation: If the concatenation of two arbitrary
words is a word over an alphabet then the symbols of the first word belong
to the alphabet. (Contributed by AV, 3-Mar-2021.)
|
  Word Word   ++ 
Word   Word
  |
| |
| 4.7.4 Singleton words
|
| |
| Syntax | cs1 11241 |
Syntax for the singleton word constructor.
|
     |
| |
| Definition | df-s1 11242 |
Define the canonical injection from symbols to words. Although not
required, should
usually be a set. Otherwise, the singleton word
    would be the singleton word consisting of the empty set, see
s1prc 11249, and not, as maybe expected, the empty word.
(Contributed by
Stefan O'Rear, 15-Aug-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
|
            |
| |
| Theorem | s1val 11243 |
Value of a singleton word. (Contributed by Stefan O'Rear, 15-Aug-2015.)
(Revised by Mario Carneiro, 26-Feb-2016.)
|
            |
| |
| Theorem | s1rn 11244 |
The range of a singleton word. (Contributed by Mario Carneiro,
18-Jul-2016.)
|
         |
| |
| Theorem | s1eq 11245 |
Equality theorem for a singleton word. (Contributed by Mario Carneiro,
26-Feb-2016.)
|
           |
| |
| Theorem | s1eqd 11246 |
Equality theorem for a singleton word. (Contributed by Mario Carneiro,
26-Feb-2016.)
|
             |
| |
| Theorem | s1cl 11247 |
A singleton word is a word. (Contributed by Stefan O'Rear, 15-Aug-2015.)
(Revised by Mario Carneiro, 26-Feb-2016.) (Proof shortened by AV,
23-Nov-2018.)
|
     Word   |
| |
| Theorem | s1cld 11248 |
A singleton word is a word. (Contributed by Mario Carneiro,
26-Feb-2016.)
|
       Word
  |
| |
| Theorem | s1prc 11249 |
Value of a singleton word if the symbol is a proper class. (Contributed
by AV, 26-Mar-2022.)
|
           |
| |
| Theorem | s1leng 11250 |
Length of a singleton word. (Contributed by Stefan O'Rear, 15-Aug-2015.)
(Revised by Mario Carneiro, 26-Feb-2016.)
|
 ♯        |
| |
| Theorem | s1dmg 11251 |
The domain of a singleton word is a singleton. (Contributed by AV,
9-Jan-2020.)
|
         |
| |
| Theorem | s1fv 11252 |
Sole symbol of a singleton word. (Contributed by Stefan O'Rear,
15-Aug-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
|
           |
| |
| Theorem | lsws1 11253 |
The last symbol of a singleton word is its symbol. (Contributed by AV,
22-Oct-2018.)
|
 lastS        |
| |
| Theorem | eqs1 11254 |
A word of length 1 is a singleton word. (Contributed by Stefan O'Rear,
23-Aug-2015.) (Proof shortened by AV, 1-May-2020.)
|
  Word ♯  
          |
| |
| Theorem | wrdl1exs1 11255* |
A word of length 1 is a singleton word. (Contributed by AV,
24-Jan-2021.)
|
  Word ♯   
      |
| |
| Theorem | wrdl1s1 11256 |
A word of length 1 is a singleton word consisting of the first symbol of
the word. (Contributed by AV, 22-Jul-2018.) (Proof shortened by AV,
14-Oct-2018.)
|
       Word ♯ 
        |
| |
| Theorem | s111 11257 |
The singleton word function is injective. (Contributed by Mario Carneiro,
1-Oct-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
|
               |
| |
| 4.7.5 Concatenations with singleton
words
|
| |
| Theorem | ccatws1cl 11258 |
The concatenation of a word with a singleton word is a word. (Contributed
by Alexander van der Vekens, 22-Sep-2018.)
|
  Word   ++      Word   |
| |
| Theorem | ccat2s1cl 11259 |
The concatenation of two singleton words is a word. (Contributed by
Alexander van der Vekens, 22-Sep-2018.)
|
        ++      Word
  |
| |
| Theorem | ccatws1leng 11260 |
The length of the concatenation of a word with a singleton word.
(Contributed by Alexander van der Vekens, 22-Sep-2018.) (Revised by AV,
4-Mar-2022.)
|
  Word  ♯  ++        ♯     |
| |
| Theorem | ccatws1lenp1bg 11261 |
The length of a word is iff the length of the concatenation of the
word with a singleton word is . (Contributed by AV,
4-Mar-2022.)
|
  Word   ♯  ++         ♯     |
| |
| Theorem | wrdlenccats1lenm1g 11262 |
The length of a word is the length of the word concatenated with a
singleton word minus 1. (Contributed by AV, 28-Jun-2018.) (Revised by
AV, 5-Mar-2022.)
|
  Word   ♯  ++        ♯    |
| |
| Theorem | ccatw2s1cl 11263 |
The concatenation of a word with two singleton words is a word.
(Contributed by Alexander van der Vekens, 22-Sep-2018.)
|
  Word    ++      ++      Word   |
| |
| Theorem | ccatw2s1leng 11264 |
The length of the concatenation of a word with two singleton words.
(Contributed by Alexander van der Vekens, 22-Sep-2018.) (Revised by AV,
5-Mar-2022.)
|
  Word  ♯   ++      ++        ♯     |
| |
| Theorem | ccats1val1g 11265 |
Value of a symbol in the left half of a word concatenated with a single
symbol. (Contributed by Alexander van der Vekens, 5-Aug-2018.) (Revised
by JJ, 20-Jan-2024.)
|
  Word
 ..^ ♯      ++               |
| |
| Theorem | ccats1val2 11266 |
Value of the symbol concatenated with a word. (Contributed by Alexander
van der Vekens, 5-Aug-2018.) (Proof shortened by Alexander van der
Vekens, 14-Oct-2018.)
|
  Word
♯     ++           |
| |
| Theorem | ccat1st1st 11267 |
The first symbol of a word concatenated with its first symbol is the first
symbol of the word. This theorem holds even if is the empty word.
(Contributed by AV, 26-Mar-2022.)
|
 Word   ++                   |
| |
| Theorem | ccatws1ls 11268 |
The last symbol of the concatenation of a word with a singleton word is
the symbol of the singleton word. (Contributed by AV, 29-Sep-2018.)
(Proof shortened by AV, 14-Oct-2018.)
|
  Word    ++        ♯  
  |
| |
| Theorem | lswccats1 11269 |
The last symbol of a word concatenated with a singleton word is the symbol
of the singleton word. (Contributed by AV, 6-Aug-2018.)
|
  Word  lastS  ++         |
| |
| Theorem | lswccats1fst 11270 |
The last symbol of a nonempty word concatenated with its first symbol is
the first symbol. (Contributed by AV, 28-Jun-2018.) (Proof shortened by
AV, 1-May-2020.)
|
  Word ♯   lastS  ++             ++               |
| |
| Theorem | ccatw2s1p1g 11271 |
Extract the symbol of the first singleton word of a word concatenated with
this singleton word and another singleton word. (Contributed by Alexander
van der Vekens, 22-Sep-2018.) (Proof shortened by AV, 1-May-2020.)
(Revised by AV, 1-May-2020.) (Revised by AV, 29-Jan-2024.)
|
   Word
♯ 
   
   ++      ++        
  |
| |
| Theorem | ccatw2s1p2 11272 |
Extract the second of two single symbols concatenated with a word.
(Contributed by Alexander van der Vekens, 22-Sep-2018.) (Proof shortened
by AV, 1-May-2020.)
|
   Word
♯ 
   
   ++      ++        
    |
| |
| Theorem | ccat2s1fvwd 11273 |
Extract a symbol of a word from the concatenation of the word with two
single symbols. (Contributed by AV, 22-Sep-2018.) (Revised by AV,
13-Jan-2020.) (Proof shortened by AV, 1-May-2020.) (Revised by AV,
28-Jan-2024.)
|
 Word     ♯           ++      ++               |
| |
| Theorem | ccat2s1fstg 11274 |
The first symbol of the concatenation of a word with two single symbols.
(Contributed by Alexander van der Vekens, 22-Sep-2018.) (Revised by AV,
28-Jan-2024.)
|
   Word
♯  
      ++      ++               |
| |
| 4.7.6 Subwords/substrings
|
| |
| Syntax | csubstr 11275 |
Syntax for the subword operator.
|
substr |
| |
| Definition | df-substr 11276* |
Define an operation which extracts portions (called subwords or
substrings) of words. Definition in Section 9.1 of [AhoHopUll]
p. 318. (Contributed by Stefan O'Rear, 15-Aug-2015.)
|
substr  
         ..^        ..^              
           |
| |
| Theorem | fzowrddc 11277 |
Decidability of whether a range of integers is a subset of a word's
domain. (Contributed by Jim Kingdon, 23-Dec-2025.)
|
  Word  DECID  ..^   |
| |
| Theorem | swrdval 11278* |
Value of a subword. (Contributed by Stefan O'Rear, 15-Aug-2015.)
|
    substr
       ..^
 
 ..^              |
| |
| Theorem | swrd00g 11279 |
A zero length substring. (Contributed by Stefan O'Rear,
27-Aug-2015.)
|
    substr       |
| |
| Theorem | swrdclg 11280 |
Closure of the subword extractor. (Contributed by Stefan O'Rear,
16-Aug-2015.) (Revised by Mario Carneiro, 26-Feb-2016.)
|
  Word   substr
    Word   |
| |
| Theorem | swrdval2 11281* |
Value of the subword extractor in its intended domain. (Contributed by
Stefan O'Rear, 15-Aug-2015.) (Proof shortened by AV, 2-May-2020.)
|
  Word    
   ♯     substr       ..^      
     |
| |
| Theorem | swrdlen 11282 |
Length of an extracted subword. (Contributed by Stefan O'Rear,
16-Aug-2015.)
|
  Word    
   ♯    ♯  substr
         |
| |
| Theorem | swrdfv 11283 |
A symbol in an extracted subword, indexed using the subword's indices.
(Contributed by Stefan O'Rear, 16-Aug-2015.)
|
   Word
       ♯   
 ..^
     substr       
        |
| |
| Theorem | swrdfv0 11284 |
The first symbol in an extracted subword. (Contributed by AV,
27-Apr-2022.)
|
  Word  ..^
   ♯      substr
             |
| |
| Theorem | swrdf 11285 |
A subword of a word is a function from a half-open range of nonnegative
integers of the same length as the subword to the set of symbols for the
original word. (Contributed by AV, 13-Nov-2018.)
|
  Word    
   ♯     substr        ..^       |
| |
| Theorem | swrdvalfn 11286 |
Value of the subword extractor as function with domain. (Contributed by
Alexander van der Vekens, 28-Mar-2018.) (Proof shortened by AV,
2-May-2020.)
|
  Word    
   ♯     substr      ..^     |
| |
| Theorem | swrdrn 11287 |
The range of a subword of a word is a subset of the set of symbols for the
word. (Contributed by AV, 13-Nov-2018.)
|
  Word    
   ♯     substr       |
| |
| Theorem | swrdlend 11288 |
The value of the subword extractor is the empty set (undefined) if the
range is not valid. (Contributed by Alexander van der Vekens,
16-Mar-2018.) (Proof shortened by AV, 2-May-2020.)
|
  Word    substr
       |
| |
| Theorem | swrdnd 11289 |
The value of the subword extractor is the empty set (undefined) if the
range is not valid. (Contributed by Alexander van der Vekens,
16-Mar-2018.) (Proof shortened by AV, 2-May-2020.)
|
  Word    ♯    substr        |
| |
| Theorem | swrd0g 11290 |
A subword of an empty set is always the empty set. (Contributed by AV,
31-Mar-2018.) (Revised by AV, 20-Oct-2018.) (Proof shortened by AV,
2-May-2020.)
|
    substr       |
| |
| Theorem | swrdrlen 11291 |
Length of a right-anchored subword. (Contributed by Alexander van der
Vekens, 5-Apr-2018.)
|
  Word    ♯    ♯  substr   ♯      ♯     |
| |
| Theorem | swrdlen2 11292 |
Length of an extracted subword. (Contributed by AV, 5-May-2020.)
|
  Word       ♯  
♯  substr          |
| |
| Theorem | swrdfv2 11293 |
A symbol in an extracted subword, indexed using the word's indices.
(Contributed by AV, 5-May-2020.)
|
   Word

    
♯  
 ..^    substr                |
| |
| Theorem | swrdwrdsymbg 11294 |
A subword is a word over the symbols it consists of. (Contributed by
AV, 2-Dec-2022.)
|
  Word    
   ♯     substr     Word     ..^    |
| |
| Theorem | swrdsb0eq 11295 |
Two subwords with the same bounds are equal if the range is not valid.
(Contributed by AV, 4-May-2020.)
|
   Word
Word  
 
 substr  
   substr       |
| |
| Theorem | swrdsbslen 11296 |
Two subwords with the same bounds have the same length. (Contributed by
AV, 4-May-2020.)
|
   Word
Word  
  ♯ 
♯    ♯  substr      ♯  substr  
     |
| |
| Theorem | swrdspsleq 11297* |
Two words have a common subword (starting at the same position with the
same length) iff they have the same symbols at each position.
(Contributed by Alexander van der Vekens, 7-Aug-2018.) (Proof shortened
by AV, 7-May-2020.)
|
   Word
Word  
  ♯ 
♯      substr      substr       ..^             |
| |
| Theorem | swrds1 11298 |
Extract a single symbol from a word. (Contributed by Stefan O'Rear,
23-Aug-2015.)
|
  Word  ..^ ♯     substr                 |
| |
| Theorem | swrdlsw 11299 |
Extract the last single symbol from a word. (Contributed by Alexander van
der Vekens, 23-Sep-2018.)
|
  Word  
substr   ♯    ♯      lastS      |
| |
| Theorem | ccatswrd 11300 |
Joining two adjacent subwords makes a longer subword. (Contributed by
Stefan O'Rear, 20-Aug-2015.)
|
  Word         
   ♯       substr     ++  substr       substr       |