HomeHome Intuitionistic Logic Explorer
Theorem List (p. 133 of 173)
< Previous  Next >
Browser slow? Try the
Unicode version.

Mirrors  >  Metamath Home Page  >  ILE Home Page  >  Theorem List Contents  >  Recent Proofs       This page: Page List

Theorem List for Intuitionistic Logic Explorer - 13201-13300   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theorem4sqlem12 13201* Lemma for 4sq 13209. For any odd prime  P, there is a  k  <  P such that  k P  -  1 is a sum of two squares. (Contributed by Mario Carneiro, 15-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  A  =  { u  |  E. m  e.  ( 0 ... N ) u  =  (
 ( m ^ 2
 )  mod  P ) }   &    |-  F  =  ( v  e.  A  |->  ( ( P  -  1 )  -  v ) )   =>    |-  ( ph  ->  E. k  e.  ( 1 ... ( P  -  1 ) ) E. u  e.  ZZ[_i]  ( ( ( abs `  u ) ^ 2 )  +  1 )  =  (
 k  x.  P ) )
 
Theorem4sqlem13m 13202* Lemma for 4sq 13209. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  ( 0 ... ( 2  x.  N ) ) 
 C_  S )   &    |-  T  =  { i  e.  NN  |  ( i  x.  P )  e.  S }   &    |-  M  = inf ( T ,  RR ,  <  )   =>    |-  ( ph  ->  ( E. j  j  e.  T  /\  M  <  P ) )
 
Theorem4sqlem14 13203* Lemma for 4sq 13209. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  ( 0 ... ( 2  x.  N ) ) 
 C_  S )   &    |-  T  =  { i  e.  NN  |  ( i  x.  P )  e.  S }   &    |-  M  = inf ( T ,  RR ,  <  )   &    |-  ( ph  ->  M  e.  ( ZZ>= `  2
 ) )   &    |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  B  e.  ZZ )   &    |-  ( ph  ->  C  e.  ZZ )   &    |-  ( ph  ->  D  e.  ZZ )   &    |-  E  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   &    |-  F  =  ( (
 ( B  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  G  =  ( (
 ( C  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  H  =  ( (
 ( D  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  R  =  ( (
 ( ( E ^
 2 )  +  ( F ^ 2 ) )  +  ( ( G ^ 2 )  +  ( H ^ 2 ) ) )  /  M )   &    |-  ( ph  ->  ( M  x.  P )  =  ( ( ( A ^ 2 )  +  ( B ^ 2 ) )  +  ( ( C ^ 2 )  +  ( D ^
 2 ) ) ) )   =>    |-  ( ph  ->  R  e.  NN0 )
 
Theorem4sqlem15 13204* Lemma for 4sq 13209. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  ( 0 ... ( 2  x.  N ) ) 
 C_  S )   &    |-  T  =  { i  e.  NN  |  ( i  x.  P )  e.  S }   &    |-  M  = inf ( T ,  RR ,  <  )   &    |-  ( ph  ->  M  e.  ( ZZ>= `  2
 ) )   &    |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  B  e.  ZZ )   &    |-  ( ph  ->  C  e.  ZZ )   &    |-  ( ph  ->  D  e.  ZZ )   &    |-  E  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   &    |-  F  =  ( (
 ( B  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  G  =  ( (
 ( C  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  H  =  ( (
 ( D  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  R  =  ( (
 ( ( E ^
 2 )  +  ( F ^ 2 ) )  +  ( ( G ^ 2 )  +  ( H ^ 2 ) ) )  /  M )   &    |-  ( ph  ->  ( M  x.  P )  =  ( ( ( A ^ 2 )  +  ( B ^ 2 ) )  +  ( ( C ^ 2 )  +  ( D ^
 2 ) ) ) )   =>    |-  ( ( ph  /\  R  =  M )  ->  (
 ( ( ( ( ( M ^ 2
 )  /  2 )  /  2 )  -  ( E ^ 2 ) )  =  0  /\  ( ( ( ( M ^ 2 ) 
 /  2 )  / 
 2 )  -  ( F ^ 2 ) )  =  0 )  /\  ( ( ( ( ( M ^ 2
 )  /  2 )  /  2 )  -  ( G ^ 2 ) )  =  0  /\  ( ( ( ( M ^ 2 ) 
 /  2 )  / 
 2 )  -  ( H ^ 2 ) )  =  0 ) ) )
 
Theorem4sqlem16 13205* Lemma for 4sq 13209. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  ( 0 ... ( 2  x.  N ) ) 
 C_  S )   &    |-  T  =  { i  e.  NN  |  ( i  x.  P )  e.  S }   &    |-  M  = inf ( T ,  RR ,  <  )   &    |-  ( ph  ->  M  e.  ( ZZ>= `  2
 ) )   &    |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  B  e.  ZZ )   &    |-  ( ph  ->  C  e.  ZZ )   &    |-  ( ph  ->  D  e.  ZZ )   &    |-  E  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   &    |-  F  =  ( (
 ( B  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  G  =  ( (
 ( C  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  H  =  ( (
 ( D  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  R  =  ( (
 ( ( E ^
 2 )  +  ( F ^ 2 ) )  +  ( ( G ^ 2 )  +  ( H ^ 2 ) ) )  /  M )   &    |-  ( ph  ->  ( M  x.  P )  =  ( ( ( A ^ 2 )  +  ( B ^ 2 ) )  +  ( ( C ^ 2 )  +  ( D ^
 2 ) ) ) )   =>    |-  ( ph  ->  ( R  <_  M  /\  (
 ( R  =  0  \/  R  =  M )  ->  ( M ^
 2 )  ||  ( M  x.  P ) ) ) )
 
Theorem4sqlem17 13206* Lemma for 4sq 13209. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  ( 0 ... ( 2  x.  N ) ) 
 C_  S )   &    |-  T  =  { i  e.  NN  |  ( i  x.  P )  e.  S }   &    |-  M  = inf ( T ,  RR ,  <  )   &    |-  ( ph  ->  M  e.  ( ZZ>= `  2
 ) )   &    |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  B  e.  ZZ )   &    |-  ( ph  ->  C  e.  ZZ )   &    |-  ( ph  ->  D  e.  ZZ )   &    |-  E  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   &    |-  F  =  ( (
 ( B  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  G  =  ( (
 ( C  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  H  =  ( (
 ( D  +  ( M  /  2 ) ) 
 mod  M )  -  ( M  /  2 ) )   &    |-  R  =  ( (
 ( ( E ^
 2 )  +  ( F ^ 2 ) )  +  ( ( G ^ 2 )  +  ( H ^ 2 ) ) )  /  M )   &    |-  ( ph  ->  ( M  x.  P )  =  ( ( ( A ^ 2 )  +  ( B ^ 2 ) )  +  ( ( C ^ 2 )  +  ( D ^
 2 ) ) ) )   =>    |- 
 -.  ph
 
Theorem4sqlem18 13207* Lemma for 4sq 13209. Inductive step, odd prime case. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  ( 0 ... ( 2  x.  N ) ) 
 C_  S )   &    |-  T  =  { i  e.  NN  |  ( i  x.  P )  e.  S }   &    |-  M  = inf ( T ,  RR ,  <  )   =>    |-  ( ph  ->  P  e.  S )
 
Theorem4sqlem19 13208* Lemma for 4sq 13209. The proof is by strong induction - we show that if all the integers less than  k are in  S, then  k is as well. In this part of the proof we do the induction argument and dispense with all the cases except the odd prime case, which is sent to 4sqlem18 13207. If  k is  0 ,  1 ,  2, we show  k  e.  S directly; otherwise if  k is composite,  k is the product of two numbers less than it (and hence in  S by assumption), so by mul4sq 13193  k  e.  S. (Contributed by Mario Carneiro, 14-Jul-2014.) (Revised by Mario Carneiro, 20-Jun-2015.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   =>    |- 
 NN0  =  S
 
Theorem4sq 13209* Lagrange's four-square theorem, or Bachet's conjecture: every nonnegative integer is expressible as a sum of four squares. This is Metamath 100 proof #19. (Contributed by Mario Carneiro, 16-Jul-2014.)
 |-  ( A  e.  NN0  <->  E. a  e.  ZZ  E. b  e.  ZZ  E. c  e. 
 ZZ  E. d  e.  ZZ  A  =  ( (
 ( a ^ 2
 )  +  ( b ^ 2 ) )  +  ( ( c ^ 2 )  +  ( d ^ 2
 ) ) ) )
 
5.2.13  Decimal arithmetic (cont.)
 
Theoremdec2dvds 13210 Divisibility by two is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.)
 |-  A  e.  NN0   &    |-  B  e.  NN0   &    |-  ( B  x.  2
 )  =  C   &    |-  D  =  ( C  +  1 )   =>    |- 
 -.  2  || ; A D
 
Theoremdec5dvds 13211 Divisibility by five is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.)
 |-  A  e.  NN0   &    |-  B  e.  NN   &    |-  B  <  5   =>    |- 
 -.  5  || ; A B
 
Theoremdec5dvds2 13212 Divisibility by five is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.)
 |-  A  e.  NN0   &    |-  B  e.  NN   &    |-  B  <  5   &    |-  ( 5  +  B )  =  C   =>    |-  -.  5  || ; A C
 
Theoremdec5nprm 13213 A decimal number greater than 10 and ending with five is not a prime number. (Contributed by Mario Carneiro, 19-Apr-2015.)
 |-  A  e.  NN   =>    |-  -. ; A 5  e.  Prime
 
Theoremdec2nprm 13214 A decimal number greater than 10 and ending with an even digit is not a prime number. (Contributed by Mario Carneiro, 19-Apr-2015.)
 |-  A  e.  NN   &    |-  B  e.  NN0   &    |-  ( B  x.  2
 )  =  C   =>    |-  -. ; A C  e.  Prime
 
Theoremmodxai 13215 Add exponents in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.) (Revised by Mario Carneiro, 5-Feb-2015.)
 |-  N  e.  NN   &    |-  A  e.  NN   &    |-  B  e.  NN0   &    |-  D  e.  ZZ   &    |-  K  e.  NN0   &    |-  M  e.  NN0   &    |-  C  e.  NN0   &    |-  L  e.  NN0   &    |-  ( ( A ^ B )  mod  N )  =  ( K  mod  N )   &    |-  ( ( A ^ C )  mod  N )  =  ( L 
 mod  N )   &    |-  ( B  +  C )  =  E   &    |-  (
 ( D  x.  N )  +  M )  =  ( K  x.  L )   =>    |-  ( ( A ^ E )  mod  N )  =  ( M  mod  N )
 
Theoremmod2xi 13216 Double exponents in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.)
 |-  N  e.  NN   &    |-  A  e.  NN   &    |-  B  e.  NN0   &    |-  D  e.  ZZ   &    |-  K  e.  NN0   &    |-  M  e.  NN0   &    |-  ( ( A ^ B )  mod  N )  =  ( K  mod  N )   &    |-  ( 2  x.  B )  =  E   &    |-  (
 ( D  x.  N )  +  M )  =  ( K  x.  K )   =>    |-  ( ( A ^ E )  mod  N )  =  ( M  mod  N )
 
Theoremmodxp1i 13217 Add one to an exponent in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.)
 |-  N  e.  NN   &    |-  A  e.  NN   &    |-  B  e.  NN0   &    |-  D  e.  ZZ   &    |-  K  e.  NN0   &    |-  M  e.  NN0   &    |-  ( ( A ^ B )  mod  N )  =  ( K  mod  N )   &    |-  ( B  +  1 )  =  E   &    |-  (
 ( D  x.  N )  +  M )  =  ( K  x.  A )   =>    |-  ( ( A ^ E )  mod  N )  =  ( M  mod  N )
 
Theoremmod2xnegi 13218 Version of mod2xi 13216 where  A ^ B does not equal  K (mod  N) but instead the negative of 
K (mod  N). (Contributed by Mario Carneiro, 21-Feb-2014.)
 |-  A  e.  NN   &    |-  B  e.  NN0   &    |-  D  e.  ZZ   &    |-  K  e.  NN   &    |-  M  e.  NN0   &    |-  L  e.  NN0   &    |-  ( ( A ^ B )  mod  N )  =  ( L  mod  N )   &    |-  ( 2  x.  B )  =  E   &    |-  ( L  +  K )  =  N   &    |-  ( ( D  x.  N )  +  M )  =  ( K  x.  K )   =>    |-  ( ( A ^ E )  mod  N )  =  ( M 
 mod  N )
 
Theoremmodsubi 13219 Subtract from within a mod calculation. (Contributed by Mario Carneiro, 18-Feb-2014.)
 |-  N  e.  NN   &    |-  A  e.  NN   &    |-  B  e.  NN0   &    |-  M  e.  NN0   &    |-  ( A  mod  N )  =  ( K  mod  N )   &    |-  ( M  +  B )  =  K   =>    |-  (
 ( A  -  B )  mod  N )  =  ( M  mod  N )
 
Theoremgcdi 13220 Calculate a GCD via Euclid's algorithm. (Contributed by Mario Carneiro, 19-Feb-2014.)
 |-  K  e.  NN0   &    |-  R  e.  NN0   &    |-  N  e.  NN0   &    |-  ( N  gcd  R )  =  G   &    |-  ( ( K  x.  N )  +  R )  =  M   =>    |-  ( M  gcd  N )  =  G
 
Theoremgcdmodi 13221 Calculate a GCD via Euclid's algorithm. Theorem 5.6 in [ApostolNT] p. 109. (Contributed by Mario Carneiro, 19-Feb-2014.)
 |-  K  e.  NN0   &    |-  R  e.  NN0   &    |-  N  e.  NN   &    |-  ( K  mod  N )  =  ( R  mod  N )   &    |-  ( N  gcd  R )  =  G   =>    |-  ( K  gcd  N )  =  G
 
Theoremnumexp0 13222 Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.)
 |-  A  e.  NN0   =>    |-  ( A ^ 0
 )  =  1
 
Theoremnumexp1 13223 Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.)
 |-  A  e.  NN0   =>    |-  ( A ^ 1
 )  =  A
 
Theoremnumexpp1 13224 Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.)
 |-  A  e.  NN0   &    |-  M  e.  NN0   &    |-  ( M  +  1 )  =  N   &    |-  (
 ( A ^ M )  x.  A )  =  C   =>    |-  ( A ^ N )  =  C
 
Theoremnumexp2x 13225 Double an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.)
 |-  A  e.  NN0   &    |-  M  e.  NN0   &    |-  ( 2  x.  M )  =  N   &    |-  ( A ^ M )  =  D   &    |-  ( D  x.  D )  =  C   =>    |-  ( A ^ N )  =  C
 
Theoremdecsplit0b 13226 Split a decimal number into two parts. Base case:  N  =  0. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.)
 |-  A  e.  NN0   =>    |-  ( ( A  x.  (; 1 0 ^ 0 ) )  +  B )  =  ( A  +  B )
 
Theoremdecsplit0 13227 Split a decimal number into two parts. Base case:  N  =  0. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.)
 |-  A  e.  NN0   =>    |-  ( ( A  x.  (; 1 0 ^ 0 ) )  +  0 )  =  A
 
Theoremdecsplit1 13228 Split a decimal number into two parts. Base case:  N  =  1. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.)
 |-  A  e.  NN0   =>    |-  ( ( A  x.  (; 1 0 ^ 1 ) )  +  B )  = ; A B
 
Theoremdecsplit 13229 Split a decimal number into two parts. Inductive step. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.)
 |-  A  e.  NN0   &    |-  B  e.  NN0   &    |-  D  e.  NN0   &    |-  M  e.  NN0   &    |-  ( M  +  1 )  =  N   &    |-  (
 ( A  x.  (; 1 0 ^ M ) )  +  B )  =  C   =>    |-  ( ( A  x.  (; 1 0 ^ N ) )  + ; B D )  = ; C D
 
Theoremkaratsuba 13230 The Karatsuba multiplication algorithm. If  X and 
Y are decomposed into two groups of digits of length  M (only the lower group is known to be this size but the algorithm is most efficient when the partition is chosen near the middle of the digit string), then  X Y can be written in three groups of digits, where each group needs only one multiplication. Thus, we can halve both inputs with only three multiplications on the smaller operands, yielding an asymptotic improvement of n^(log2 3) instead of n^2 for the "naive" algorithm decmul1c 9850. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 9-Sep-2021.)
 |-  A  e.  NN0   &    |-  B  e.  NN0   &    |-  C  e.  NN0   &    |-  D  e.  NN0   &    |-  S  e.  NN0   &    |-  M  e.  NN0   &    |-  ( A  x.  C )  =  R   &    |-  ( B  x.  D )  =  T   &    |-  (
 ( A  +  B )  x.  ( C  +  D ) )  =  ( ( R  +  S )  +  T )   &    |-  ( ( A  x.  (; 1 0 ^ M ) )  +  B )  =  X   &    |-  ( ( C  x.  (; 1 0 ^ M ) )  +  D )  =  Y   &    |-  ( ( R  x.  (; 1 0 ^ M ) )  +  S )  =  W   &    |-  ( ( W  x.  (; 1 0 ^ M ) )  +  T )  =  Z   =>    |-  ( X  x.  Y )  =  Z
 
Theorem2exp4 13231 Two to the fourth power is 16. (Contributed by Mario Carneiro, 20-Apr-2015.)
 |-  ( 2 ^ 4
 )  = ; 1 6
 
Theorem2exp5 13232 Two to the fifth power is 32. (Contributed by AV, 16-Aug-2021.)
 |-  ( 2 ^ 5
 )  = ; 3 2
 
Theorem2exp6 13233 Two to the sixth power is 64. (Contributed by Mario Carneiro, 20-Apr-2015.) (Proof shortened by OpenAI, 25-Mar-2020.)
 |-  ( 2 ^ 6
 )  = ; 6 4
 
Theorem2exp7 13234 Two to the seventh power is 128. (Contributed by AV, 16-Aug-2021.)
 |-  ( 2 ^ 7
 )  = ;; 1 2 8
 
Theorem2exp8 13235 Two to the eighth power is 256. (Contributed by Mario Carneiro, 20-Apr-2015.)
 |-  ( 2 ^ 8
 )  = ;; 2 5 6
 
Theorem2exp11 13236 Two to the eleventh power is 2048. (Contributed by AV, 16-Aug-2021.)
 |-  ( 2 ^; 1 1 )  = ;;; 2 0 4 8
 
Theorem2exp16 13237 Two to the sixteenth power is 65536. (Contributed by Mario Carneiro, 20-Apr-2015.)
 |-  ( 2 ^; 1 6 )  = ;;;; 6 5 5 3 6
 
Theorem3exp3 13238 Three to the third power is 27. (Contributed by Mario Carneiro, 20-Apr-2015.)
 |-  ( 3 ^ 3
 )  = ; 2 7
 
Theorem2expltfac 13239 The factorial grows faster than two to the power  N. (Contributed by Mario Carneiro, 15-Sep-2016.)
 |-  ( N  e.  ( ZZ>=
 `  4 )  ->  ( 2 ^ N )  <  ( ! `  N ) )
 
5.2.14  Specific prime numbers
 
Theoremprmlem0 13240* Lemma for prmlem1a 13241 and prmlem2 13254. (Contributed by Mario Carneiro, 18-Feb-2014.)
 |-  ( ( -.  2  ||  M  /\  x  e.  ( ZZ>= `  M )
 )  ->  ( ( x  e.  ( Prime  \  { 2 } )  /\  ( x ^ 2
 )  <_  N )  ->  -.  x  ||  N ) )   &    |-  ( K  e.  Prime  ->  -.  K  ||  N )   &    |-  ( K  +  2 )  =  M   =>    |-  ( ( -.  2  ||  K  /\  x  e.  ( ZZ>= `  K ) )  ->  ( ( x  e.  ( Prime  \  { 2 } )  /\  ( x ^ 2 )  <_  N )  ->  -.  x  ||  N ) )
 
Theoremprmlem1a 13241* Lemma for prmlem1 13242 and prmlem2 13254. (Contributed by Mario Carneiro, 18-Feb-2014.)
 |-  N  e.  NN   &    |-  1  <  N   &    |-  -.  2  ||  N   &    |- 
 -.  3  ||  N   &    |-  (
 ( -.  2  ||  5  /\  x  e.  ( ZZ>=
 `  5 ) ) 
 ->  ( ( x  e.  ( Prime  \  { 2 } )  /\  ( x ^ 2 )  <_  N )  ->  -.  x  ||  N ) )   =>    |-  N  e.  Prime
 
Theoremprmlem1 13242 A quick proof skeleton to show that the numbers less than 25 are prime, by trial division. (Contributed by Mario Carneiro, 18-Feb-2014.)
 |-  N  e.  NN   &    |-  1  <  N   &    |-  -.  2  ||  N   &    |- 
 -.  3  ||  N   &    |-  N  < ; 2
 5   =>    |-  N  e.  Prime
 
Theorem5prm 13243 5 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.)
 |-  5  e.  Prime
 
Theorem6nprm 13244 6 is not a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.)
 |- 
 -.  6  e.  Prime
 
Theorem7prm 13245 7 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.)
 |-  7  e.  Prime
 
Theorem8nprm 13246 8 is not a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.)
 |- 
 -.  8  e.  Prime
 
Theorem9nprm 13247 9 is not a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.)
 |- 
 -.  9  e.  Prime
 
Theorem10nprm 13248 10 is not a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by AV, 6-Sep-2021.) (Proof shortened by Umit Teoman Dogan, 10-Jun-2026.)
 |- 
 -. ; 1 0  e.  Prime
 
Theorem11prm 13249 11 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.)
 |- ; 1
 1  e.  Prime
 
Theorem13prm 13250 13 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.)
 |- ; 1
 3  e.  Prime
 
Theorem17prm 13251 17 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.)
 |- ; 1
 7  e.  Prime
 
Theorem19prm 13252 19 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.)
 |- ; 1
 9  e.  Prime
 
Theorem23prm 13253 23 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.)
 |- ; 2
 3  e.  Prime
 
Theoremprmlem2 13254 Our last proving session got as far as 25 because we started with the two "bootstrap" primes 2 and 3, and the next prime is 5, so knowing that 2 and 3 are prime and 4 is not allows to cover the numbers less than  5 ^ 2  =  2 5. Additionally, nonprimes are "easy", so we can extend this range of known prime/nonprimes all the way until 29, which is the first prime larger than 25. Thus, in this lemma we extend another blanket out to  2 9 ^ 2  =  8 4 1, from which we can prove even more primes. If we wanted, we could keep doing this, but the goal is Bertrand's postulate, and for that we only need a few large primes - we don't need to find them all, as we have been doing thus far. So after this blanket runs out, we'll have to switch to another method (see 1259prm 13267).

As a side note, you can see the pattern of the primes in the indentation pattern of this lemma! (Contributed by Mario Carneiro, 18-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)

 |-  N  e.  NN   &    |-  N  < ;; 8 4 1   &    |-  1  <  N   &    |-  -.  2  ||  N   &    |- 
 -.  3  ||  N   &    |-  -.  5  ||  N   &    |-  -.  7  ||  N   &    |- 
 -. ; 1 1  ||  N   &    |-  -. ; 1 3  ||  N   &    |-  -. ; 1 7 
 ||  N   &    |-  -. ; 1 9  ||  N   &    |-  -. ; 2 3 
 ||  N   =>    |-  N  e.  Prime
 
Theorem37prm 13255 37 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)
 |- ; 3
 7  e.  Prime
 
Theorem43prm 13256 43 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)
 |- ; 4
 3  e.  Prime
 
Theorem83prm 13257 83 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)
 |- ; 8
 3  e.  Prime
 
Theorem139prm 13258 139 is a prime number. (Contributed by Mario Carneiro, 19-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)
 |- ;; 1 3 9  e. 
 Prime
 
Theorem163prm 13259 163 is a prime number. (Contributed by Mario Carneiro, 19-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)
 |- ;; 1 6 3  e. 
 Prime
 
Theorem317prm 13260 317 is a prime number. (Contributed by Mario Carneiro, 19-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)
 |- ;; 3 1 7  e. 
 Prime
 
Theorem631prm 13261 631 is a prime number. (Contributed by Mario Carneiro, 1-Mar-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)
 |- ;; 6 3 1  e. 
 Prime
 
5.2.15  Very large primes
 
Theorem1259lem1 13262 Lemma for 1259prm 13267. Calculate a power mod. In decimal, we calculate  2 ^ 1 6  =  5 2 N  +  6 8  ==  6 8 and  2 ^ 1 7  ==  6 8  x.  2  =  1 3 6 in this lemma. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.)
 |-  N  = ;;; 1 2 5 9   =>    |-  ( ( 2 ^; 1 7 )  mod  N )  =  (;; 1 3 6  mod  N )
 
Theorem1259lem2 13263 Lemma for 1259prm 13267. Calculate a power mod. In decimal, we calculate  2 ^ 3 4  =  ( 2 ^ 1 7 ) ^ 2  ==  1
3 6 ^ 2  ==  1 4 N  +  8 7 0. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 15-Sep-2021.)
 |-  N  = ;;; 1 2 5 9   =>    |-  ( ( 2 ^; 3 4 )  mod  N )  =  (;; 8 7 0  mod  N )
 
Theorem1259lem3 13264 Lemma for 1259prm 13267. Calculate a power mod. In decimal, we calculate  2 ^ 3 8  =  2 ^ 3 4  x.  2 ^ 4  ==  8
7 0  x.  1 6  =  1 1 N  +  7 1 and  2 ^ 7 6  =  ( 2 ^ 3 4 ) ^ 2  ==  7
1 ^ 2  =  4 N  +  5  ==  5. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.)
 |-  N  = ;;; 1 2 5 9   =>    |-  ( ( 2 ^; 7 6 )  mod  N )  =  ( 5  mod 
 N )
 
Theorem1259lem4 13265 Lemma for 1259prm 13267. Calculate a power mod. In decimal, we calculate  2 ^ 3 0 6  =  ( 2 ^ 7 6 ) ^ 4  x.  4  ==  5 ^ 4  x.  4  =  2 N  -  1 8,  2 ^ 6 1 2  =  ( 2 ^ 3 0 6 ) ^ 2  ==  1 8 ^ 2  =  3 2 4,  2 ^ 6 2 9  =  2 ^ 6 1 2  x.  2 ^ 1 7  ==  3 2 4  x.  1 3 6  =  3 5 N  -  1 and finally  2 ^ ( N  -  1 )  =  ( 2 ^ 6 2 9 ) ^ 2  ==  1 ^ 2  =  1. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.)
 |-  N  = ;;; 1 2 5 9   =>    |-  ( ( 2 ^
 ( N  -  1
 ) )  mod  N )  =  ( 1  mod  N )
 
Theorem1259lem5 13266 Lemma for 1259prm 13267. Calculate the GCD of  2 ^ 3 4  -  1  ==  8 6 9 with  N  =  1 2 5 9. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.)
 |-  N  = ;;; 1 2 5 9   =>    |-  ( ( ( 2 ^; 3 4 )  -  1 )  gcd  N )  =  1
 
Theorem1259prm 13267 1259 is a prime number. (Contributed by Mario Carneiro, 22-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.)
 |-  N  = ;;; 1 2 5 9   =>    |-  N  e.  Prime
 
5.2.16  Bertrand's Ballot Problem
 
Theoremballotfilemofi 13268*  O is finite. (Contributed by Jim Kingdon, 20-May-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   =>    |-  O  e.  Fin
 
Theoremballotfilem1 13269* The size of the universe is a binomial coefficient. (Contributed by Thierry Arnoux, 23-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   =>    |-  ( `  O )  =  ( ( M  +  N )  _C  M )
 
Theoremballotfilemonn 13270* The size of the universe is at least one. (Contributed by Jim Kingdon, 4-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   =>    |-  ( `  O )  e.  NN
 
Theoremballotfilemelo 13271* Elementhood in  O. (Contributed by Thierry Arnoux, 17-Apr-2017.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   =>    |-  ( C  e.  O  <->  ( C  C_  ( 1 ... ( M  +  N ) )  /\  C  e.  Fin  /\  ( `  C )  =  M ) )
 
Theoremballotfilemcdc 13272* Lemma for ballotfi . It is decidable whether a given integer is an element of a particular element of  O. (Contributed by Jim Kingdon, 7-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  K  e.  ZZ )   =>    |-  ( ph  -> DECID  K  e.  C )
 
Theoremballotfilemcinfi 13273* Lemma for ballotfi . The portion of a counting representing votes for A up to a specified integer is finite. (Contributed by Jim Kingdon, 8-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  ZZ )   =>    |-  ( ph  ->  (
 ( 1 ... J )  i^i  C )  e. 
 Fin )
 
Theoremballotfilemdifcfi 13274* Lemma for ballotfi . The portion of a counting representing votes for B up to a specified integer is finite. (Contributed by Jim Kingdon, 8-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  ZZ )   =>    |-  ( ph  ->  (
 ( 1 ... J )  \  C )  e. 
 Fin )
 
Theoremballotfilemcinfz 13275* Lemma for ballotfi . The portion of a counting representing votes for A within a specified integer range is finite. (Contributed by Jim Kingdon, 15-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  ZZ )   &    |-  ( ph  ->  K  e.  ZZ )   =>    |-  ( ph  ->  (
 ( J ... K )  i^i  C )  e. 
 Fin )
 
Theoremballotfilemdifcfz 13276* Lemma for ballotfi . The portion of a counting representing votes for B within a specified integer range is finite. (Contributed by Jim Kingdon, 15-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  ZZ )   &    |-  ( ph  ->  K  e.  ZZ )   =>    |-  ( ph  ->  (
 ( J ... K )  \  C )  e. 
 Fin )
 
Theoremballotfilem2 13277* The probability that the first vote picked in a count is a B. (Contributed by Thierry Arnoux, 23-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   =>    |-  ( P `  { c  e.  O  |  -.  1  e.  c } )  =  ( N  /  ( M  +  N ) )
 
Theoremballotfilemfval 13278* The value of  F. (Contributed by Thierry Arnoux, 23-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  ZZ )   =>    |-  ( ph  ->  (
 ( F `  C ) `  J )  =  ( ( `  (
 ( 1 ... J )  i^i  C ) )  -  ( `  (
 ( 1 ... J )  \  C ) ) ) )
 
Theoremballotfilemfelz 13279*  ( F `  C ) has values in  ZZ. (Contributed by Thierry Arnoux, 23-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  ZZ )   =>    |-  ( ph  ->  (
 ( F `  C ) `  J )  e. 
 ZZ )
 
Theoremballotfilemfp1 13280* If the  J th ballot is for A,  ( F `  C ) goes up 1. If the  J th ballot is for B,  ( F `  C ) goes down 1. (Contributed by Thierry Arnoux, 24-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  NN )   =>    |-  ( ph  ->  (
 ( -.  J  e.  C  ->  ( ( F `
  C ) `  J )  =  (
 ( ( F `  C ) `  ( J  -  1 ) )  -  1 ) ) 
 /\  ( J  e.  C  ->  ( ( F `
  C ) `  J )  =  (
 ( ( F `  C ) `  ( J  -  1 ) )  +  1 ) ) ) )
 
Theoremballotfilemfc0 13281*  F takes value 0 between negative and positive values. (Contributed by Thierry Arnoux, 24-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  NN )   &    |-  ( ph  ->  E. i  e.  ( 1 ... J ) ( ( F `
  C ) `  i )  <_  0 )   &    |-  ( ph  ->  0  <  ( ( F `  C ) `  J ) )   =>    |-  ( ph  ->  E. k  e.  ( 1 ... J ) ( ( F `
  C ) `  k )  =  0
 )
 
Theoremballotfilemfcc 13282*  F takes value 0 between positive and negative values. (Contributed by Thierry Arnoux, 2-Apr-2017.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  ( ph  ->  C  e.  O )   &    |-  ( ph  ->  J  e.  NN )   &    |-  ( ph  ->  E. i  e.  ( 1 ... J ) 0  <_  (
 ( F `  C ) `  i ) )   &    |-  ( ph  ->  ( ( F `  C ) `  J )  <  0 )   =>    |-  ( ph  ->  E. k  e.  ( 1 ... J ) ( ( F `
  C ) `  k )  =  0
 )
 
Theoremballotfilemfmpn 13283*  ( F `  C ) finishes counting at  ( M  -  N ). (Contributed by Thierry Arnoux, 25-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   =>    |-  ( C  e.  O  ->  ( ( F `  C ) `  ( M  +  N )
 )  =  ( M  -  N ) )
 
Theoremballotfilemfval0 13284*  ( F `  C ) always starts counting at 0 . (Contributed by Thierry Arnoux, 25-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   =>    |-  ( C  e.  O  ->  ( ( F `  C ) `  0
 )  =  0 )
 
Theoremballotfileme 13285* Elements of  E. (Contributed by Thierry Arnoux, 14-Dec-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   =>    |-  ( C  e.  E 
 <->  ( C  e.  O  /\  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  C ) `  i ) ) )
 
Theoremballotfilemefi 13286*  E is finite. (Contributed by Jim Kingdon, 17-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   =>    |-  E  e.  Fin
 
Theoremballotfilemafi 13287* The set of countings where A got the first vote, but does not stay strictly ahead throughout, is finite. (Contributed by Jim Kingdon, 17-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   =>    |-  { c  e.  ( O  \  E )  |  1  e.  c }  e.  Fin
 
Theoremballotfilembfi 13288* The set of countings where B got the first vote is finite. (Contributed by Jim Kingdon, 17-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   =>    |-  { c  e.  ( O  \  E )  |  -.  1  e.  c }  e.  Fin
 
Theoremballotfilemodife 13289* Elements of  ( O  \  E ). (Contributed by Thierry Arnoux, 7-Dec-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   =>    |-  ( C  e.  ( O  \  E )  <-> 
 ( C  e.  O  /\  E. i  e.  (
 1 ... ( M  +  N ) ) ( ( F `  C ) `  i )  <_ 
 0 ) )
 
Theoremballotfilem4 13290* If the first pick is a vote for B, A is not ahead throughout the count. (Contributed by Thierry Arnoux, 25-Nov-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   =>    |-  ( C  e.  O  ->  ( -.  1  e.  C  ->  -.  C  e.  E ) )
 
Theoremballotfilem5 13291* If A is not ahead throughout, there is a  k where votes are tied. (Contributed by Thierry Arnoux, 1-Dec-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   =>    |-  ( C  e.  ( O  \  E )  ->  E. k  e.  (
 1 ... ( M  +  N ) ) ( ( F `  C ) `  k )  =  0 )
 
Theoremballotfilemi 13292* Value of  I for a given counting  C. (Contributed by Thierry Arnoux, 1-Dec-2016.) (Revised by AV, 6-Oct-2020.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   =>    |-  ( C  e.  ( O  \  E )  ->  ( I `  C )  = inf ( { k  e.  ( 1 ... ( M  +  N )
 )  |  ( ( F `  C ) `
  k )  =  0 } ,  RR ,  <  ) )
 
Theoremballotfilemiex 13293* Properties of  ( I `  C ). (Contributed by Thierry Arnoux, 12-Dec-2016.) (Revised by AV, 6-Oct-2020.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   =>    |-  ( C  e.  ( O  \  E )  ->  ( ( I `  C )  e.  (
 1 ... ( M  +  N ) )  /\  ( ( F `  C ) `  ( I `  C ) )  =  0 ) )
 
Theoremballotfilemi1 13294* The first tie cannot be reached at the first pick. (Contributed by Thierry Arnoux, 12-Mar-2017.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   =>    |-  ( ( C  e.  ( O  \  E ) 
 /\  -.  1  e.  C )  ->  ( I `
  C )  =/=  1 )
 
Theoremballotfilemii 13295* The first tie cannot be reached at the first pick. (Contributed by Thierry Arnoux, 4-Apr-2017.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   =>    |-  ( ( C  e.  ( O  \  E ) 
 /\  1  e.  C )  ->  ( I `  C )  =/=  1
 )
 
Theoremballotfilemscl 13296* The set of zeroes of  F has an infimum. (Contributed by Jim Kingdon, 12-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   &    |-  S  =  {
 k  e.  ( 1
 ... ( M  +  N ) )  |  ( ( F `  C ) `  k
 )  =  0 }   =>    |-  ( C  e.  ( O  \  E )  -> inf ( S ,  RR ,  <  )  e.  S )
 
Theoremballotfilemsle 13297* The infimum of the set of zeroes of 
F is a lower bound. (Contributed by Jim Kingdon, 12-Jun-2026.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   &    |-  S  =  {
 k  e.  ( 1
 ... ( M  +  N ) )  |  ( ( F `  C ) `  k
 )  =  0 }   =>    |-  ( ( C  e.  ( O  \  E ) 
 /\  X  e.  S )  -> inf ( S ,  RR ,  <  )  <_  X )
 
Theoremballotfilemimin 13298*  ( I `  C ) is the first tie. (Contributed by Thierry Arnoux, 1-Dec-2016.) (Revised by AV, 6-Oct-2020.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   =>    |-  ( C  e.  ( O  \  E )  ->  -.  E. k  e.  (
 1 ... ( ( I `
  C )  -  1 ) ) ( ( F `  C ) `  k )  =  0 )
 
Theoremballotfilemic 13299* If the first vote is for B, the vote on the first tie is for A. (Contributed by Thierry Arnoux, 1-Dec-2016.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   =>    |-  ( ( C  e.  ( O  \  E ) 
 /\  -.  1  e.  C )  ->  ( I `
  C )  e.  C )
 
Theoremballotfilem1c 13300* If the first vote is for A, the vote on the first tie is for B. (Contributed by Thierry Arnoux, 4-Apr-2017.)
 |-  M  e.  NN   &    |-  N  e.  NN   &    |-  O  =  {
 c  e.  ( ~P ( 1 ... ( M  +  N )
 )  i^i  Fin )  |  ( `  c )  =  M }   &    |-  P  =  ( x  e.  ( ~P O  i^i  Fin )  |->  ( ( `  x )  /  ( `  O ) ) )   &    |-  F  =  ( c  e.  O  |->  ( i  e.  ZZ  |->  ( ( `  ( (
 1 ... i )  i^i  c ) )  -  ( `  ( ( 1
 ... i )  \  c ) ) ) ) )   &    |-  E  =  {
 c  e.  O  |  A. i  e.  (
 1 ... ( M  +  N ) ) 0  <  ( ( F `
  c ) `  i ) }   &    |-  N  <  M   &    |-  I  =  ( c  e.  ( O 
 \  E )  |-> inf ( { k  e.  (
 1 ... ( M  +  N ) )  |  ( ( F `  c ) `  k
 )  =  0 } ,  RR ,  <  ) )   =>    |-  ( ( C  e.  ( O  \  E ) 
 /\  1  e.  C )  ->  -.  ( I `  C )  e.  C )
    < Previous  Next >

Page List
Jump to page: Contents  1 1-100 2 101-200 3 201-300 4 301-400 5 401-500 6 501-600 7 601-700 8 701-800 9 801-900 10 901-1000 11 1001-1100 12 1101-1200 13 1201-1300 14 1301-1400 15 1401-1500 16 1501-1600 17 1601-1700 18 1701-1800 19 1801-1900 20 1901-2000 21 2001-2100 22 2101-2200 23 2201-2300 24 2301-2400 25 2401-2500 26 2501-2600 27 2601-2700 28 2701-2800 29 2801-2900 30 2901-3000 31 3001-3100 32 3101-3200 33 3201-3300 34 3301-3400 35 3401-3500 36 3501-3600 37 3601-3700 38 3701-3800 39 3801-3900 40 3901-4000 41 4001-4100 42 4101-4200 43 4201-4300 44 4301-4400 45 4401-4500 46 4501-4600 47 4601-4700 48 4701-4800 49 4801-4900 50 4901-5000 51 5001-5100 52 5101-5200 53 5201-5300 54 5301-5400 55 5401-5500 56 5501-5600 57 5601-5700 58 5701-5800 59 5801-5900 60 5901-6000 61 6001-6100 62 6101-6200 63 6201-6300 64 6301-6400 65 6401-6500 66 6501-6600 67 6601-6700 68 6701-6800 69 6801-6900 70 6901-7000 71 7001-7100 72 7101-7200 73 7201-7300 74 7301-7400 75 7401-7500 76 7501-7600 77 7601-7700 78 7701-7800 79 7801-7900 80 7901-8000 81 8001-8100 82 8101-8200 83 8201-8300 84 8301-8400 85 8401-8500 86 8501-8600 87 8601-8700 88 8701-8800 89 8801-8900 90 8901-9000 91 9001-9100 92 9101-9200 93 9201-9300 94 9301-9400 95 9401-9500 96 9501-9600 97 9601-9700 98 9701-9800 99 9801-9900 100 9901-10000 101 10001-10100 102 10101-10200 103 10201-10300 104 10301-10400 105 10401-10500 106 10501-10600 107 10601-10700 108 10701-10800 109 10801-10900 110 10901-11000 111 11001-11100 112 11101-11200 113 11201-11300 114 11301-11400 115 11401-11500 116 11501-11600 117 11601-11700 118 11701-11800 119 11801-11900 120 11901-12000 121 12001-12100 122 12101-12200 123 12201-12300 124 12301-12400 125 12401-12500 126 12501-12600 127 12601-12700 128 12701-12800 129 12801-12900 130 12901-13000 131 13001-13100 132 13101-13200 133 13201-13300 134 13301-13400 135 13401-13500 136 13501-13600 137 13601-13700 138 13701-13800 139 13801-13900 140 13901-14000 141 14001-14100 142 14101-14200 143 14201-14300 144 14301-14400 145 14401-14500 146 14501-14600 147 14601-14700 148 14701-14800 149 14801-14900 150 14901-15000 151 15001-15100 152 15101-15200 153 15201-15300 154 15301-15400 155 15401-15500 156 15501-15600 157 15601-15700 158 15701-15800 159 15801-15900 160 15901-16000 161 16001-16100 162 16101-16200 163 16201-16300 164 16301-16400 165 16401-16500 166 16501-16600 167 16601-16700 168 16701-16800 169 16801-16900 170 16901-17000 171 17001-17100 172 17101-17200 173 17201-17277
  Copyright terms: Public domain < Previous  Next >