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Theorem List for Intuitionistic Logic Explorer - 13001-13100   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theorempcqmul 13001 Multiplication property of the prime power function. (Contributed by Mario Carneiro, 9-Sep-2014.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  QQ  /\  A  =/=  0
 )  /\  ( B  e.  QQ  /\  B  =/=  0 ) )  ->  ( P  pCnt  ( A  x.  B ) )  =  ( ( P 
 pCnt  A )  +  ( P  pCnt  B ) ) )
 
Theorempc0 13002 The value of the prime power function at zero. (Contributed by Mario Carneiro, 3-Oct-2014.)
 |-  ( P  e.  Prime  ->  ( P  pCnt  0 )  = +oo )
 
Theorempc1 13003 Value of the prime count function at 1. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( P  e.  Prime  ->  ( P  pCnt  1 )  =  0 )
 
Theorempcqcl 13004 Closure of the general prime count function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  ( N  e.  QQ  /\  N  =/=  0
 ) )  ->  ( P  pCnt  N )  e. 
 ZZ )
 
Theorempcqdiv 13005 Division property of the prime power function. (Contributed by Mario Carneiro, 10-Aug-2015.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  QQ  /\  A  =/=  0
 )  /\  ( B  e.  QQ  /\  B  =/=  0 ) )  ->  ( P  pCnt  ( A 
 /  B ) )  =  ( ( P 
 pCnt  A )  -  ( P  pCnt  B ) ) )
 
Theorempcrec 13006 Prime power of a reciprocal. (Contributed by Mario Carneiro, 10-Aug-2015.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  QQ  /\  A  =/=  0
 ) )  ->  ( P  pCnt  ( 1  /  A ) )  =  -u ( P  pCnt  A ) )
 
Theorempcexp 13007 Prime power of an exponential. (Contributed by Mario Carneiro, 10-Aug-2015.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  QQ  /\  A  =/=  0
 )  /\  N  e.  ZZ )  ->  ( P 
 pCnt  ( A ^ N ) )  =  ( N  x.  ( P  pCnt  A ) ) )
 
Theorempcxnn0cl 13008 Extended nonnegative integer closure of the general prime count function. (Contributed by Jim Kingdon, 13-Oct-2024.)
 |-  ( ( P  e.  Prime  /\  N  e.  ZZ )  ->  ( P  pCnt  N )  e. NN0* )
 
Theorempcxcl 13009 Extended real closure of the general prime count function. (Contributed by Mario Carneiro, 3-Oct-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  QQ )  ->  ( P  pCnt  N )  e.  RR* )
 
Theorempcxqcl 13010 The general prime count function is an integer or infinite. (Contributed by Jim Kingdon, 6-Jun-2025.)
 |-  ( ( P  e.  Prime  /\  N  e.  QQ )  ->  ( ( P 
 pCnt  N )  e.  ZZ  \/  ( P  pCnt  N )  = +oo ) )
 
Theorempcge0 13011 The prime count of an integer is greater than or equal to zero. (Contributed by Mario Carneiro, 3-Oct-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  ZZ )  ->  0  <_  ( P  pCnt  N ) )
 
Theorempczdvds 13012 Defining property of the prime count function. (Contributed by Mario Carneiro, 9-Sep-2014.)
 |-  ( ( P  e.  Prime  /\  ( N  e.  ZZ  /\  N  =/=  0
 ) )  ->  ( P ^ ( P  pCnt  N ) )  ||  N )
 
Theorempcdvds 13013 Defining property of the prime count function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  NN )  ->  ( P ^
 ( P  pCnt  N ) )  ||  N )
 
Theorempczndvds 13014 Defining property of the prime count function. (Contributed by Mario Carneiro, 3-Oct-2014.)
 |-  ( ( P  e.  Prime  /\  ( N  e.  ZZ  /\  N  =/=  0
 ) )  ->  -.  ( P ^ ( ( P 
 pCnt  N )  +  1 ) )  ||  N )
 
Theorempcndvds 13015 Defining property of the prime count function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  NN )  ->  -.  ( P ^ ( ( P 
 pCnt  N )  +  1 ) )  ||  N )
 
Theorempczndvds2 13016 The remainder after dividing out all factors of  P is not divisible by  P. (Contributed by Mario Carneiro, 9-Sep-2014.)
 |-  ( ( P  e.  Prime  /\  ( N  e.  ZZ  /\  N  =/=  0
 ) )  ->  -.  P  ||  ( N  /  ( P ^ ( P  pCnt  N ) ) ) )
 
Theorempcndvds2 13017 The remainder after dividing out all factors of  P is not divisible by  P. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  NN )  ->  -.  P  ||  ( N  /  ( P ^
 ( P  pCnt  N ) ) ) )
 
Theorempcdvdsb 13018  P ^ A divides  N if and only if  A is at most the count of  P. (Contributed by Mario Carneiro, 3-Oct-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  ZZ  /\  A  e.  NN0 )  ->  ( A  <_  ( P  pCnt  N )  <->  ( P ^ A )  ||  N ) )
 
Theorempcelnn 13019 There are a positive number of powers of a prime  P in  N iff  P divides  N. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  NN )  ->  ( ( P 
 pCnt  N )  e.  NN  <->  P  ||  N ) )
 
Theorempceq0 13020 There are zero powers of a prime  P in  N iff  P does not divide  N. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  NN )  ->  ( ( P 
 pCnt  N )  =  0  <->  -.  P  ||  N )
 )
 
Theorempcidlem 13021 The prime count of a prime power. (Contributed by Mario Carneiro, 12-Mar-2014.)
 |-  ( ( P  e.  Prime  /\  A  e.  NN0 )  ->  ( P  pCnt  ( P ^ A ) )  =  A )
 
Theorempcid 13022 The prime count of a prime power. (Contributed by Mario Carneiro, 9-Sep-2014.)
 |-  ( ( P  e.  Prime  /\  A  e.  ZZ )  ->  ( P  pCnt  ( P ^ A ) )  =  A )
 
Theorempcneg 13023 The prime count of a negative number. (Contributed by Mario Carneiro, 13-Mar-2014.)
 |-  ( ( P  e.  Prime  /\  A  e.  QQ )  ->  ( P  pCnt  -u A )  =  ( P  pCnt  A )
 )
 
Theorempcabs 13024 The prime count of an absolute value. (Contributed by Mario Carneiro, 13-Mar-2014.)
 |-  ( ( P  e.  Prime  /\  A  e.  QQ )  ->  ( P  pCnt  ( abs `  A )
 )  =  ( P 
 pCnt  A ) )
 
Theorempcdvdstr 13025 The prime count increases under the divisibility relation. (Contributed by Mario Carneiro, 13-Mar-2014.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  ZZ  /\  B  e.  ZZ  /\  A  ||  B )
 )  ->  ( P  pCnt  A )  <_  ( P  pCnt  B ) )
 
Theorempcgcd1 13026 The prime count of a GCD is the minimum of the prime counts of the arguments. (Contributed by Mario Carneiro, 3-Oct-2014.)
 |-  ( ( ( P  e.  Prime  /\  A  e.  ZZ  /\  B  e.  ZZ )  /\  ( P  pCnt  A )  <_  ( P  pCnt  B ) )  ->  ( P  pCnt  ( A 
 gcd  B ) )  =  ( P  pCnt  A ) )
 
Theorempcgcd 13027 The prime count of a GCD is the minimum of the prime counts of the arguments. (Contributed by Mario Carneiro, 3-Oct-2014.)
 |-  ( ( P  e.  Prime  /\  A  e.  ZZ  /\  B  e.  ZZ )  ->  ( P  pCnt  ( A  gcd  B ) )  =  if ( ( P  pCnt  A )  <_  ( P  pCnt  B ) ,  ( P  pCnt  A ) ,  ( P 
 pCnt  B ) ) )
 
Theorempc2dvds 13028* A characterization of divisibility in terms of prime count. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by Mario Carneiro, 3-Oct-2014.)
 |-  ( ( A  e.  ZZ  /\  B  e.  ZZ )  ->  ( A  ||  B 
 <-> 
 A. p  e.  Prime  ( p  pCnt  A )  <_  ( p  pCnt  B ) ) )
 
Theorempc11 13029* The prime count function, viewed as a function from  NN to  ( NN  ^m  Prime ), is one-to-one. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( A  e.  NN0  /\  B  e.  NN0 )  ->  ( A  =  B  <->  A. p  e.  Prime  ( p  pCnt  A )  =  ( p  pCnt  B ) ) )
 
Theorempcz 13030* The prime count function can be used as an indicator that a given rational number is an integer. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( A  e.  QQ  ->  ( A  e.  ZZ  <->  A. p  e.  Prime  0  <_  ( p  pCnt  A ) ) )
 
Theorempcprmpw2 13031* Self-referential expression for a prime power. (Contributed by Mario Carneiro, 16-Jan-2015.)
 |-  ( ( P  e.  Prime  /\  A  e.  NN )  ->  ( E. n  e.  NN0  A  ||  ( P ^ n )  <->  A  =  ( P ^ ( P  pCnt  A ) ) ) )
 
Theorempcprmpw 13032* Self-referential expression for a prime power. (Contributed by Mario Carneiro, 16-Jan-2015.)
 |-  ( ( P  e.  Prime  /\  A  e.  NN )  ->  ( E. n  e.  NN0  A  =  ( P ^ n )  <->  A  =  ( P ^ ( P  pCnt  A ) ) ) )
 
Theoremdvdsprmpweq 13033* If a positive integer divides a prime power, it is a prime power. (Contributed by AV, 25-Jul-2021.)
 |-  ( ( P  e.  Prime  /\  A  e.  NN  /\  N  e.  NN0 )  ->  ( A  ||  ( P ^ N )  ->  E. n  e.  NN0  A  =  ( P ^ n ) ) )
 
Theoremdvdsprmpweqnn 13034* If an integer greater than 1 divides a prime power, it is a (proper) prime power. (Contributed by AV, 13-Aug-2021.)
 |-  ( ( P  e.  Prime  /\  A  e.  ( ZZ>=
 `  2 )  /\  N  e.  NN0 )  ->  ( A  ||  ( P ^ N )  ->  E. n  e.  NN  A  =  ( P ^ n ) ) )
 
Theoremdvdsprmpweqle 13035* If a positive integer divides a prime power, it is a prime power with a smaller exponent. (Contributed by AV, 25-Jul-2021.)
 |-  ( ( P  e.  Prime  /\  A  e.  NN  /\  N  e.  NN0 )  ->  ( A  ||  ( P ^ N )  ->  E. n  e.  NN0  ( n  <_  N  /\  A  =  ( P ^ n ) ) ) )
 
Theoremdifsqpwdvds 13036 If the difference of two squares is a power of a prime, the prime divides twice the second squared number. (Contributed by AV, 13-Aug-2021.)
 |-  ( ( ( A  e.  NN0  /\  B  e.  NN0  /\  ( B  +  1 )  <  A ) 
 /\  ( C  e.  Prime  /\  D  e.  NN0 ) )  ->  ( ( C ^ D )  =  ( ( A ^ 2 )  -  ( B ^ 2 ) )  ->  C  ||  (
 2  x.  B ) ) )
 
Theorempcaddlem 13037 Lemma for pcadd 13038. The original numbers  A and  B have been decomposed using the prime count function as  ( P ^ M )  x.  ( R  /  S ) where  R ,  S are both not divisible by  P and  M  =  ( P  pCnt  A ), and similarly for  B. (Contributed by Mario Carneiro, 9-Sep-2014.)
 |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  A  =  ( ( P ^ M )  x.  ( R  /  S ) ) )   &    |-  ( ph  ->  B  =  ( ( P ^ N )  x.  ( T  /  U ) ) )   &    |-  ( ph  ->  N  e.  ( ZZ>= `  M )
 )   &    |-  ( ph  ->  ( R  e.  ZZ  /\  -.  P  ||  R ) )   &    |-  ( ph  ->  ( S  e.  NN  /\  -.  P  ||  S ) )   &    |-  ( ph  ->  ( T  e.  ZZ  /\  -.  P  ||  T ) )   &    |-  ( ph  ->  ( U  e.  NN  /\  -.  P  ||  U ) )   =>    |-  ( ph  ->  M 
 <_  ( P  pCnt  ( A  +  B )
 ) )
 
Theorempcadd 13038 An inequality for the prime count of a sum. This is the source of the ultrametric inequality for the p-adic metric. (Contributed by Mario Carneiro, 9-Sep-2014.)
 |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  A  e.  QQ )   &    |-  ( ph  ->  B  e.  QQ )   &    |-  ( ph  ->  ( P  pCnt  A )  <_  ( P  pCnt  B ) )   =>    |-  ( ph  ->  ( P  pCnt  A )  <_  ( P  pCnt  ( A  +  B ) ) )
 
Theorempcadd2 13039 The inequality of pcadd 13038 becomes an equality when one of the factors has prime count strictly less than the other. (Contributed by Mario Carneiro, 16-Jan-2015.) (Revised by Mario Carneiro, 26-Jun-2015.)
 |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  A  e.  QQ )   &    |-  ( ph  ->  B  e.  QQ )   &    |-  ( ph  ->  ( P  pCnt  A )  < 
 ( P  pCnt  B ) )   =>    |-  ( ph  ->  ( P  pCnt  A )  =  ( P  pCnt  ( A  +  B )
 ) )
 
Theorempcmptcl 13040 Closure for the prime power map. (Contributed by Mario Carneiro, 12-Mar-2014.)
 |-  F  =  ( n  e.  NN  |->  if ( n  e.  Prime ,  ( n ^ A ) ,  1 ) )   &    |-  ( ph  ->  A. n  e.  Prime  A  e.  NN0 )   =>    |-  ( ph  ->  ( F : NN --> NN  /\  seq 1 (  x.  ,  F ) : NN --> NN ) )
 
Theorempcmpt 13041* Construct a function with given prime count characteristics. (Contributed by Mario Carneiro, 12-Mar-2014.)
 |-  F  =  ( n  e.  NN  |->  if ( n  e.  Prime ,  ( n ^ A ) ,  1 ) )   &    |-  ( ph  ->  A. n  e.  Prime  A  e.  NN0 )   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( n  =  P  ->  A  =  B )   =>    |-  ( ph  ->  ( P  pCnt  (  seq 1 (  x.  ,  F ) `
  N ) )  =  if ( P 
 <_  N ,  B , 
 0 ) )
 
Theorempcmpt2 13042* Dividing two prime count maps yields a number with all dividing primes confined to an interval. (Contributed by Mario Carneiro, 14-Mar-2014.)
 |-  F  =  ( n  e.  NN  |->  if ( n  e.  Prime ,  ( n ^ A ) ,  1 ) )   &    |-  ( ph  ->  A. n  e.  Prime  A  e.  NN0 )   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( n  =  P  ->  A  =  B )   &    |-  ( ph  ->  M  e.  ( ZZ>= `  N )
 )   =>    |-  ( ph  ->  ( P  pCnt  ( (  seq 1 (  x.  ,  F ) `  M )  /  (  seq 1 (  x. 
 ,  F ) `  N ) ) )  =  if ( ( P  <_  M  /\  -.  P  <_  N ) ,  B ,  0 ) )
 
Theorempcmptdvds 13043 The partial products of the prime power map form a divisibility chain. (Contributed by Mario Carneiro, 12-Mar-2014.)
 |-  F  =  ( n  e.  NN  |->  if ( n  e.  Prime ,  ( n ^ A ) ,  1 ) )   &    |-  ( ph  ->  A. n  e.  Prime  A  e.  NN0 )   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  M  e.  ( ZZ>=
 `  N ) )   =>    |-  ( ph  ->  (  seq 1 (  x.  ,  F ) `  N )  ||  (  seq 1 (  x. 
 ,  F ) `  M ) )
 
Theorempcprod 13044* The product of the primes taken to their respective powers reconstructs the original number. (Contributed by Mario Carneiro, 12-Mar-2014.)
 |-  F  =  ( n  e.  NN  |->  if ( n  e.  Prime ,  ( n ^ ( n  pCnt  N ) ) ,  1 ) )   =>    |-  ( N  e.  NN  ->  (  seq 1 (  x.  ,  F ) `
  N )  =  N )
 
Theoremsumhashdc 13045* The sum of 1 over a set is the size of the set. (Contributed by Mario Carneiro, 8-Mar-2014.) (Revised by Mario Carneiro, 20-May-2014.)
 |-  ( ( B  e.  Fin  /\  A  C_  B  /\  A. x  e.  B DECID  x  e.  A )  ->  sum_ k  e.  B  if ( k  e.  A ,  1 ,  0 )  =  ( `  A )
 )
 
Theoremfldivp1 13046 The difference between the floors of adjacent fractions is either 1 or 0. (Contributed by Mario Carneiro, 8-Mar-2014.)
 |-  ( ( M  e.  ZZ  /\  N  e.  NN )  ->  ( ( |_ `  ( ( M  +  1 )  /  N ) )  -  ( |_ `  ( M  /  N ) ) )  =  if ( N  ||  ( M  +  1
 ) ,  1 ,  0 ) )
 
Theorempcfaclem 13047 Lemma for pcfac 13048. (Contributed by Mario Carneiro, 20-May-2014.)
 |-  ( ( N  e.  NN0  /\  M  e.  ( ZZ>= `  N )  /\  P  e.  Prime )  ->  ( |_ `  ( N  /  ( P ^ M ) ) )  =  0 )
 
Theorempcfac 13048* Calculate the prime count of a factorial. (Contributed by Mario Carneiro, 11-Mar-2014.) (Revised by Mario Carneiro, 21-May-2014.)
 |-  ( ( N  e.  NN0  /\  M  e.  ( ZZ>= `  N )  /\  P  e.  Prime )  ->  ( P  pCnt  ( ! `  N ) )  =  sum_ k  e.  ( 1 ...
 M ) ( |_ `  ( N  /  ( P ^ k ) ) ) )
 
Theorempcbc 13049* Calculate the prime count of a binomial coefficient. (Contributed by Mario Carneiro, 11-Mar-2014.) (Revised by Mario Carneiro, 21-May-2014.)
 |-  ( ( N  e.  NN  /\  K  e.  (
 0 ... N )  /\  P  e.  Prime )  ->  ( P  pCnt  ( N  _C  K ) )  =  sum_ k  e.  (
 1 ... N ) ( ( |_ `  ( N  /  ( P ^
 k ) ) )  -  ( ( |_ `  ( ( N  -  K )  /  ( P ^ k ) ) )  +  ( |_ `  ( K  /  ( P ^ k ) ) ) ) ) )
 
Theoremqexpz 13050 If a power of a rational number is an integer, then the number is an integer. (Contributed by Mario Carneiro, 10-Aug-2015.)
 |-  ( ( A  e.  QQ  /\  N  e.  NN  /\  ( A ^ N )  e.  ZZ )  ->  A  e.  ZZ )
 
Theoremexpnprm 13051 A second or higher power of a rational number is not a prime number. Or by contraposition, the n-th root of a prime number is not rational. Suggested by Norm Megill. (Contributed by Mario Carneiro, 10-Aug-2015.)
 |-  ( ( A  e.  QQ  /\  N  e.  ( ZZ>=
 `  2 ) ) 
 ->  -.  ( A ^ N )  e.  Prime )
 
Theoremoddprmdvds 13052* Every positive integer which is not a power of two is divisible by an odd prime number. (Contributed by AV, 6-Aug-2021.)
 |-  ( ( K  e.  NN  /\  -.  E. n  e.  NN0  K  =  ( 2 ^ n ) )  ->  E. p  e.  ( Prime  \  { 2 } ) p  ||  K )
 
5.2.9  Pocklington's theorem
 
Theoremprmpwdvds 13053 A relation involving divisibility by a prime power. (Contributed by Mario Carneiro, 2-Mar-2014.)
 |-  ( ( ( K  e.  ZZ  /\  D  e.  ZZ )  /\  ( P  e.  Prime  /\  N  e.  NN )  /\  ( D  ||  ( K  x.  ( P ^ N ) )  /\  -.  D  ||  ( K  x.  ( P ^ ( N  -  1 ) ) ) ) )  ->  ( P ^ N )  ||  D )
 
Theorempockthlem 13054 Lemma for pockthg 13055. (Contributed by Mario Carneiro, 2-Mar-2014.)
 |-  ( ph  ->  A  e.  NN )   &    |-  ( ph  ->  B  e.  NN )   &    |-  ( ph  ->  B  <  A )   &    |-  ( ph  ->  N  =  ( ( A  x.  B )  +  1
 ) )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  P 
 ||  N )   &    |-  ( ph  ->  Q  e.  Prime )   &    |-  ( ph  ->  ( Q  pCnt  A )  e.  NN )   &    |-  ( ph  ->  C  e.  ZZ )   &    |-  ( ph  ->  ( ( C ^ ( N  -  1 ) ) 
 mod  N )  =  1 )   &    |-  ( ph  ->  ( ( ( C ^
 ( ( N  -  1 )  /  Q ) )  -  1 ) 
 gcd  N )  =  1 )   =>    |-  ( ph  ->  ( Q  pCnt  A )  <_  ( Q  pCnt  ( P  -  1 ) ) )
 
Theorempockthg 13055* The generalized Pocklington's theorem. If  N  -  1  =  A  x.  B where  B  <  A, then  N is prime if and only if for every prime factor  p of  A, there is an  x such that  x ^ ( N  -  1 )  =  1 (  mod 
N ) and  gcd  ( x ^ ( ( N  -  1 )  /  p )  -  1 ,  N )  =  1. (Contributed by Mario Carneiro, 2-Mar-2014.)
 |-  ( ph  ->  A  e.  NN )   &    |-  ( ph  ->  B  e.  NN )   &    |-  ( ph  ->  B  <  A )   &    |-  ( ph  ->  N  =  ( ( A  x.  B )  +  1
 ) )   &    |-  ( ph  ->  A. p  e.  Prime  ( p  ||  A  ->  E. x  e.  ZZ  ( ( ( x ^ ( N  -  1 ) ) 
 mod  N )  =  1 
 /\  ( ( ( x ^ ( ( N  -  1 ) 
 /  p ) )  -  1 )  gcd  N )  =  1 ) ) )   =>    |-  ( ph  ->  N  e.  Prime )
 
Theorempockthi 13056 Pocklington's theorem, which gives a sufficient criterion for a number  N to be prime. This is the preferred method for verifying large primes, being much more efficient to compute than trial division. This form has been optimized for application to specific large primes; see pockthg 13055 for a more general closed-form version. (Contributed by Mario Carneiro, 2-Mar-2014.)
 |-  P  e.  Prime   &    |-  G  e.  NN   &    |-  M  =  ( G  x.  P )   &    |-  N  =  ( M  +  1 )   &    |-  D  e.  NN   &    |-  E  e.  NN   &    |-  A  e.  NN   &    |-  M  =  ( D  x.  ( P ^ E ) )   &    |-  D  <  ( P ^ E )   &    |-  ( ( A ^ M )  mod  N )  =  ( 1 
 mod  N )   &    |-  ( ( ( A ^ G )  -  1 )  gcd  N )  =  1   =>    |-  N  e.  Prime
 
5.2.10  Infinite primes theorem
 
Theoreminfpnlem1 13057* Lemma for infpn 13059. The smallest divisor (greater than 1)  M of  N !  + 
1 is a prime greater than  N. (Contributed by NM, 5-May-2005.)
 |-  K  =  ( ( ! `  N )  +  1 )   =>    |-  ( ( N  e.  NN  /\  M  e.  NN )  ->  (
 ( ( 1  <  M  /\  ( K  /  M )  e.  NN )  /\  A. j  e. 
 NN  ( ( 1  <  j  /\  ( K  /  j )  e. 
 NN )  ->  M  <_  j ) )  ->  ( N  <  M  /\  A. j  e.  NN  (
 ( M  /  j
 )  e.  NN  ->  ( j  =  1  \/  j  =  M ) ) ) ) )
 
Theoreminfpnlem2 13058* Lemma for infpn 13059. For any positive integer  N, there exists a prime number  j greater than  N. (Contributed by NM, 5-May-2005.)
 |-  K  =  ( ( ! `  N )  +  1 )   =>    |-  ( N  e.  NN  ->  E. j  e.  NN  ( N  <  j  /\  A. k  e.  NN  (
 ( j  /  k
 )  e.  NN  ->  ( k  =  1  \/  k  =  j ) ) ) )
 
Theoreminfpn 13059* There exist infinitely many prime numbers: for any positive integer  N, there exists a prime number  j greater than  N. (See infpn2 13207 for the equinumerosity version.) (Contributed by NM, 1-Jun-2006.)
 |-  ( N  e.  NN  ->  E. j  e.  NN  ( N  <  j  /\  A. k  e.  NN  (
 ( j  /  k
 )  e.  NN  ->  ( k  =  1  \/  k  =  j ) ) ) )
 
Theoremprmunb 13060* The primes are unbounded. (Contributed by Paul Chapman, 28-Nov-2012.)
 |-  ( N  e.  NN  ->  E. p  e.  Prime  N  <  p )
 
5.2.11  Fundamental theorem of arithmetic
 
Theorem1arithlem1 13061* Lemma for 1arith 13065. (Contributed by Mario Carneiro, 30-May-2014.)
 |-  M  =  ( n  e.  NN  |->  ( p  e.  Prime  |->  ( p 
 pCnt  n ) ) )   =>    |-  ( N  e.  NN  ->  ( M `  N )  =  ( p  e.  Prime  |->  ( p  pCnt  N ) ) )
 
Theorem1arithlem2 13062* Lemma for 1arith 13065. (Contributed by Mario Carneiro, 30-May-2014.)
 |-  M  =  ( n  e.  NN  |->  ( p  e.  Prime  |->  ( p 
 pCnt  n ) ) )   =>    |-  ( ( N  e.  NN  /\  P  e.  Prime ) 
 ->  ( ( M `  N ) `  P )  =  ( P  pCnt  N ) )
 
Theorem1arithlem3 13063* Lemma for 1arith 13065. (Contributed by Mario Carneiro, 30-May-2014.)
 |-  M  =  ( n  e.  NN  |->  ( p  e.  Prime  |->  ( p 
 pCnt  n ) ) )   =>    |-  ( N  e.  NN  ->  ( M `  N ) : Prime --> NN0 )
 
Theorem1arithlem4 13064* Lemma for 1arith 13065. (Contributed by Mario Carneiro, 30-May-2014.)
 |-  M  =  ( n  e.  NN  |->  ( p  e.  Prime  |->  ( p 
 pCnt  n ) ) )   &    |-  G  =  ( y  e.  NN  |->  if ( y  e. 
 Prime ,  ( y ^
 ( F `  y
 ) ) ,  1 ) )   &    |-  ( ph  ->  F : Prime --> NN0 )   &    |-  ( ph  ->  N  e.  NN )   &    |-  (
 ( ph  /\  ( q  e.  Prime  /\  N  <_  q ) )  ->  ( F `  q )  =  0 )   =>    |-  ( ph  ->  E. x  e.  NN  F  =  ( M `  x ) )
 
Theorem1arith 13065* Fundamental theorem of arithmetic, where a prime factorization is represented as a sequence of prime exponents, for which only finitely many primes have nonzero exponent. The function  M maps the set of positive integers one-to-one onto the set of prime factorizations  R. (Contributed by Paul Chapman, 17-Nov-2012.) (Proof shortened by Mario Carneiro, 30-May-2014.)
 |-  M  =  ( n  e.  NN  |->  ( p  e.  Prime  |->  ( p 
 pCnt  n ) ) )   &    |-  R  =  { e  e.  ( NN0  ^m  Prime )  |  ( `' e " NN )  e.  Fin }   =>    |-  M : NN -1-1-onto-> R
 
Theorem1arith2 13066* Fundamental theorem of arithmetic, where a prime factorization is represented as a finite monotonic 1-based sequence of primes. Every positive integer has a unique prime factorization. Theorem 1.10 in [ApostolNT] p. 17. This is Metamath 100 proof #80. (Contributed by Paul Chapman, 17-Nov-2012.) (Revised by Mario Carneiro, 30-May-2014.)
 |-  M  =  ( n  e.  NN  |->  ( p  e.  Prime  |->  ( p 
 pCnt  n ) ) )   &    |-  R  =  { e  e.  ( NN0  ^m  Prime )  |  ( `' e " NN )  e.  Fin }   =>    |-  A. z  e.  NN  E! g  e.  R  ( M `  z )  =  g
 
5.2.12  Lagrange's four-square theorem
 
Syntaxcgz 13067 Extend class notation with the set of gaussian integers.
 class  ZZ[_i]
 
Definitiondf-gz 13068 Define the set of gaussian integers, which are complex numbers whose real and imaginary parts are integers. (Note that the  [
_i ] is actually part of the symbol token and has no independent meaning.) (Contributed by Mario Carneiro, 14-Jul-2014.)
 |- 
 ZZ[_i]  =  { x  e.  CC  |  ( ( Re `  x )  e.  ZZ  /\  ( Im `  x )  e.  ZZ ) }
 
Theoremelgz 13069 Elementhood in the gaussian integers. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  ( A  e.  ZZ[_i]  <->  ( A  e.  CC  /\  ( Re `  A )  e.  ZZ  /\  ( Im `  A )  e.  ZZ )
 )
 
Theoremgzcn 13070 A gaussian integer is a complex number. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  ( A  e.  ZZ[_i]  ->  A  e.  CC )
 
Theoremzgz 13071 An integer is a gaussian integer. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  ( A  e.  ZZ  ->  A  e.  ZZ[_i] )
 
Theoremigz 13072  _i is a gaussian integer. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  _i  e.  ZZ[_i]
 
Theoremgznegcl 13073 The gaussian integers are closed under negation. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  ( A  e.  ZZ[_i]  ->  -u A  e.  ZZ[_i]
 )
 
Theoremgzcjcl 13074 The gaussian integers are closed under conjugation. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  ( A  e.  ZZ[_i]  ->  ( * `  A )  e. 
 ZZ[_i]
 )
 
Theoremgzaddcl 13075 The gaussian integers are closed under addition. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  ( ( A  e.  ZZ[_i]  /\  B  e.  ZZ[_i] )  ->  ( A  +  B )  e.  ZZ[_i]
 )
 
Theoremgzmulcl 13076 The gaussian integers are closed under multiplication. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  ( ( A  e.  ZZ[_i]  /\  B  e.  ZZ[_i] )  ->  ( A  x.  B )  e. 
 ZZ[_i]
 )
 
Theoremgzreim 13077 Construct a gaussian integer from real and imaginary parts. (Contributed by Mario Carneiro, 16-Jul-2014.)
 |-  ( ( A  e.  ZZ  /\  B  e.  ZZ )  ->  ( A  +  ( _i  x.  B ) )  e.  ZZ[_i] )
 
Theoremgzsubcl 13078 The gaussian integers are closed under subtraction. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  ( ( A  e.  ZZ[_i]  /\  B  e.  ZZ[_i] )  ->  ( A  -  B )  e. 
 ZZ[_i]
 )
 
Theoremgzabssqcl 13079 The squared norm of a gaussian integer is an integer. (Contributed by Mario Carneiro, 16-Jul-2014.)
 |-  ( A  e.  ZZ[_i]  ->  (
 ( abs `  A ) ^ 2 )  e. 
 NN0 )
 
Theorem4sqlem5 13080 Lemma for 4sq 13108. (Contributed by Mario Carneiro, 15-Jul-2014.)
 |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  M  e.  NN )   &    |-  B  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   =>    |-  ( ph  ->  ( B  e.  ZZ  /\  ( ( A  -  B ) 
 /  M )  e. 
 ZZ ) )
 
Theorem4sqlem6 13081 Lemma for 4sq 13108. (Contributed by Mario Carneiro, 15-Jul-2014.)
 |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  M  e.  NN )   &    |-  B  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   =>    |-  ( ph  ->  ( -u ( M  /  2 )  <_  B  /\  B  <  ( M  /  2 ) ) )
 
Theorem4sqlem7 13082 Lemma for 4sq 13108. (Contributed by Mario Carneiro, 15-Jul-2014.)
 |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  M  e.  NN )   &    |-  B  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   =>    |-  ( ph  ->  ( B ^ 2 )  <_  ( ( ( M ^ 2 )  / 
 2 )  /  2
 ) )
 
Theorem4sqlem8 13083 Lemma for 4sq 13108. (Contributed by Mario Carneiro, 15-Jul-2014.)
 |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  M  e.  NN )   &    |-  B  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   =>    |-  ( ph  ->  M  ||  (
 ( A ^ 2
 )  -  ( B ^ 2 ) ) )
 
Theorem4sqlem9 13084 Lemma for 4sq 13108. (Contributed by Mario Carneiro, 15-Jul-2014.)
 |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  M  e.  NN )   &    |-  B  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   &    |-  ( ( ph  /\  ps )  ->  ( B ^
 2 )  =  0 )   =>    |-  ( ( ph  /\  ps )  ->  ( M ^
 2 )  ||  ( A ^ 2 ) )
 
Theorem4sqlem10 13085 Lemma for 4sq 13108. (Contributed by Mario Carneiro, 16-Jul-2014.)
 |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  M  e.  NN )   &    |-  B  =  ( ( ( A  +  ( M  / 
 2 ) )  mod  M )  -  ( M 
 /  2 ) )   &    |-  ( ( ph  /\  ps )  ->  ( ( ( ( M ^ 2
 )  /  2 )  /  2 )  -  ( B ^ 2 ) )  =  0 )   =>    |-  ( ( ph  /\  ps )  ->  ( M ^
 2 )  ||  (
 ( A ^ 2
 )  -  ( ( ( M ^ 2
 )  /  2 )  /  2 ) ) )
 
Theorem4sqlem1 13086* Lemma for 4sq 13108. The set  S is the set of all numbers that are expressible as a sum of four squares. Our goal is to show that  S  =  NN0; here we show one subset direction. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   =>    |-  S  C_  NN0
 
Theorem4sqlem2 13087* Lemma for 4sq 13108. Change bound variables in  S. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   =>    |-  ( A  e.  S  <->  E. a  e.  ZZ  E. b  e.  ZZ  E. c  e.  ZZ  E. d  e. 
 ZZ  A  =  ( ( ( a ^
 2 )  +  (
 b ^ 2 ) )  +  ( ( c ^ 2 )  +  ( d ^
 2 ) ) ) )
 
Theorem4sqlem3 13088* Lemma for 4sq 13108. Sufficient condition to be in  S. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   =>    |-  ( ( ( A  e.  ZZ  /\  B  e.  ZZ )  /\  ( C  e.  ZZ  /\  D  e.  ZZ ) )  ->  ( ( ( A ^ 2 )  +  ( B ^ 2 ) )  +  ( ( C ^ 2 )  +  ( D ^
 2 ) ) )  e.  S )
 
Theorem4sqlem4a 13089* Lemma for 4sqlem4 13090. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   =>    |-  ( ( A  e.  ZZ[_i]  /\  B  e.  ZZ[_i] )  ->  (
 ( ( abs `  A ) ^ 2 )  +  ( ( abs `  B ) ^ 2 ) )  e.  S )
 
Theorem4sqlem4 13090* Lemma for 4sq 13108. We can express the four-square property more compactly in terms of gaussian integers, because the norms of gaussian integers are exactly sums of two squares. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   =>    |-  ( A  e.  S  <->  E. u  e.  ZZ[_i]  E. v  e.  ZZ[_i]  A  =  ( (
 ( abs `  u ) ^ 2 )  +  ( ( abs `  v
 ) ^ 2 ) ) )
 
Theoremmul4sqlem 13091* Lemma for mul4sq 13092: algebraic manipulations. The extra assumptions involving  M would let us know not just that the product is a sum of squares, but also that it preserves divisibility by  M. (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  A  e.  ZZ[_i] )   &    |-  ( ph  ->  B  e.  ZZ[_i] )   &    |-  ( ph  ->  C  e.  ZZ[_i] )   &    |-  ( ph  ->  D  e.  ZZ[_i] )   &    |-  X  =  ( ( ( abs `  A ) ^ 2 )  +  ( ( abs `  B ) ^ 2 ) )   &    |-  Y  =  ( (
 ( abs `  C ) ^ 2 )  +  ( ( abs `  D ) ^ 2 ) )   &    |-  ( ph  ->  M  e.  NN )   &    |-  ( ph  ->  ( ( A  -  C )  /  M )  e. 
 ZZ[_i]
 )   &    |-  ( ph  ->  (
 ( B  -  D )  /  M )  e. 
 ZZ[_i]
 )   &    |-  ( ph  ->  ( X  /  M )  e. 
 NN0 )   =>    |-  ( ph  ->  (
 ( X  /  M )  x.  ( Y  /  M ) )  e.  S )
 
Theoremmul4sq 13092* Euler's four-square identity: The product of two sums of four squares is also a sum of four squares. This is usually quoted as an explicit formula involving eight real variables; we save some time by working with complex numbers (gaussian integers) instead, so that we only have to work with four variables, and also hiding the actual formula for the product in the proof of mul4sqlem 13091. (For the curious, the explicit formula that is used is  (  |  a  |  ^ 2  +  |  b  |  ^
2 ) (  |  c  |  ^ 2  +  |  d  |  ^ 2 )  =  |  a *  x.  c  +  b  x.  d *  |  ^ 2  +  | 
a *  x.  d  -  b  x.  c
*  |  ^ 2.) (Contributed by Mario Carneiro, 14-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   =>    |-  ( ( A  e.  S  /\  B  e.  S )  ->  ( A  x.  B )  e.  S )
 
Theorem4sqlemafi 13093* Lemma for 4sq 13108. 
A is finite. (Contributed by Jim Kingdon, 24-May-2025.)
 |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  e.  NN )   &    |-  A  =  { u  |  E. m  e.  ( 0 ... N ) u  =  ( ( m ^
 2 )  mod  P ) }   =>    |-  ( ph  ->  A  e.  Fin )
 
Theorem4sqlemffi 13094* Lemma for 4sq 13108.  ran  F is finite. (Contributed by Jim Kingdon, 24-May-2025.)
 |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  e.  NN )   &    |-  A  =  { u  |  E. m  e.  ( 0 ... N ) u  =  ( ( m ^
 2 )  mod  P ) }   &    |-  F  =  ( v  e.  A  |->  ( ( P  -  1
 )  -  v ) )   =>    |-  ( ph  ->  ran  F  e.  Fin )
 
Theorem4sqleminfi 13095* Lemma for 4sq 13108. 
A  i^i  ran  F is finite. (Contributed by Jim Kingdon, 24-May-2025.)
 |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  e.  NN )   &    |-  A  =  { u  |  E. m  e.  ( 0 ... N ) u  =  ( ( m ^
 2 )  mod  P ) }   &    |-  F  =  ( v  e.  A  |->  ( ( P  -  1
 )  -  v ) )   =>    |-  ( ph  ->  ( A  i^i  ran  F )  e.  Fin )
 
Theorem4sqexercise1 13096* Exercise which may help in understanding the proof of 4sqlemsdc 13098. (Contributed by Jim Kingdon, 25-May-2025.)
 |-  S  =  { n  |  E. x  e.  ZZ  n  =  ( x ^ 2 ) }   =>    |-  ( A  e.  NN0  -> DECID  A  e.  S )
 
Theorem4sqexercise2 13097* Exercise which may help in understanding the proof of 4sqlemsdc 13098. (Contributed by Jim Kingdon, 30-May-2025.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  n  =  ( ( x ^
 2 )  +  (
 y ^ 2 ) ) }   =>    |-  ( A  e.  NN0  -> DECID  A  e.  S )
 
Theorem4sqlemsdc 13098* Lemma for 4sq 13108. The property of being the sum of four squares is decidable.

The proof involves showing that (for a particular  A) there are only a finite number of possible ways that it could be the sum of four squares, so checking each of those possibilities in turn decides whether the number is the sum of four squares. If this proof is hard to follow, especially because of its length, the simplified versions at 4sqexercise1 13096 and 4sqexercise2 13097 may help clarify, as they are using very much the same techniques on simplified versions of this lemma. (Contributed by Jim Kingdon, 25-May-2025.)

 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   =>    |-  ( A  e.  NN0  -> DECID  A  e.  S )
 
Theorem4sqlem11 13099* Lemma for 4sq 13108. Use the pigeonhole principle to show that the sets  { m ^
2  |  m  e.  ( 0 ... N
) } and  { -u 1  -  n ^ 2  |  n  e.  ( 0 ... N ) } have a common element,  mod  P. Note that although the conclusion is stated in terms of  A  i^i  ran  F being nonempty, it is also inhabited by 4sqleminfi 13095 and fin0 7142. (Contributed by Mario Carneiro, 15-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  A  =  { u  |  E. m  e.  ( 0 ... N ) u  =  (
 ( m ^ 2
 )  mod  P ) }   &    |-  F  =  ( v  e.  A  |->  ( ( P  -  1 )  -  v ) )   =>    |-  ( ph  ->  ( A  i^i  ran  F )  =/=  (/) )
 
Theorem4sqlem12 13100* Lemma for 4sq 13108. For any odd prime  P, there is a  k  <  P such that  k P  -  1 is a sum of two squares. (Contributed by Mario Carneiro, 15-Jul-2014.)
 |-  S  =  { n  |  E. x  e.  ZZ  E. y  e.  ZZ  E. z  e.  ZZ  E. w  e.  ZZ  n  =  ( ( ( x ^
 2 )  +  (
 y ^ 2 ) )  +  ( ( z ^ 2 )  +  ( w ^
 2 ) ) ) }   &    |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  P  =  ( ( 2  x.  N )  +  1 )
 )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  A  =  { u  |  E. m  e.  ( 0 ... N ) u  =  (
 ( m ^ 2
 )  mod  P ) }   &    |-  F  =  ( v  e.  A  |->  ( ( P  -  1 )  -  v ) )   =>    |-  ( ph  ->  E. k  e.  ( 1 ... ( P  -  1 ) ) E. u  e.  ZZ[_i]  ( ( ( abs `  u ) ^ 2 )  +  1 )  =  (
 k  x.  P ) )
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