Theorem List for Intuitionistic Logic Explorer - 6901-7000 *Has distinct variable
group(s)
| Type | Label | Description |
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| Theorem | mapsnf1o 6901* |
A bijection between a set and single-point functions to it.
(Contributed by Stefan O'Rear, 24-Jan-2015.)
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| 2.6.28 Equinumerosity
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| Syntax | cen 6902 |
Extend class definition to include the equinumerosity relation
("approximately equals" symbol)
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| Syntax | cdom 6903 |
Extend class definition to include the dominance relation (curly
less-than-or-equal)
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| Syntax | cfn 6904 |
Extend class definition to include the class of all finite sets.
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| Definition | df-en 6905* |
Define the equinumerosity relation. Definition of [Enderton] p. 129.
We define
to be a binary relation rather than a connective, so
its arguments must be sets to be meaningful. This is acceptable because
we do not consider equinumerosity for proper classes. We derive the
usual definition as bren 6912. (Contributed by NM, 28-Mar-1998.)
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| Definition | df-dom 6906* |
Define the dominance relation. Compare Definition of [Enderton] p. 145.
Typical textbook definitions are derived as brdom 6916 and domen 6917.
(Contributed by NM, 28-Mar-1998.)
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| Definition | df-fin 6907* |
Define the (proper) class of all finite sets. Similar to Definition
10.29 of [TakeutiZaring] p. 91,
whose "Fin(a)" corresponds to
our " ". This definition is
meaningful whether or not we
accept the Axiom of Infinity ax-inf2 16507. (Contributed by NM,
22-Aug-2008.)
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| Theorem | relen 6908 |
Equinumerosity is a relation. (Contributed by NM, 28-Mar-1998.)
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| Theorem | reldom 6909 |
Dominance is a relation. (Contributed by NM, 28-Mar-1998.)
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| Theorem | encv 6910 |
If two classes are equinumerous, both classes are sets. (Contributed by
AV, 21-Mar-2019.)
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| Theorem | breng 6911* |
Equinumerosity relation. This variation of bren 6912
does not require the
Axiom of Union. (Contributed by NM, 15-Jun-1998.) Extract from a
subproof of bren 6912. (Revised by BTernaryTau, 23-Sep-2024.)
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| Theorem | bren 6912* |
Equinumerosity relation. (Contributed by NM, 15-Jun-1998.)
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| Theorem | brdom2g 6913* |
Dominance relation. This variation of brdomg 6914 does not require the
Axiom of Union. (Contributed by NM, 15-Jun-1998.) Extract from a
subproof of brdomg 6914. (Revised by BTernaryTau, 29-Nov-2024.)
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| Theorem | brdomg 6914* |
Dominance relation. (Contributed by NM, 15-Jun-1998.)
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| Theorem | brdomi 6915* |
Dominance relation. (Contributed by Mario Carneiro, 26-Apr-2015.)
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| Theorem | brdom 6916* |
Dominance relation. (Contributed by NM, 15-Jun-1998.)
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| Theorem | domen 6917* |
Dominance in terms of equinumerosity. Example 1 of [Enderton] p. 146.
(Contributed by NM, 15-Jun-1998.)
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| Theorem | domeng 6918* |
Dominance in terms of equinumerosity, with the sethood requirement
expressed as an antecedent. Example 1 of [Enderton] p. 146.
(Contributed by NM, 24-Apr-2004.)
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| Theorem | ctex 6919 |
A class dominated by is a set. See also ctfoex 7308 which says that
a countable class is a set. (Contributed by Thierry Arnoux, 29-Dec-2016.)
(Proof shortened by Jim Kingdon, 13-Mar-2023.)
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| Theorem | f1oen4g 6920 |
The domain and range of a one-to-one, onto set function are
equinumerous. This variation of f1oeng 6925 does not require the Axiom of
Collection nor the Axiom of Union. (Contributed by BTernaryTau,
7-Dec-2024.)
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| Theorem | f1dom4g 6921 |
The domain of a one-to-one set function is dominated by its codomain
when the latter is a set. This variation of f1domg 6926 does not require
the Axiom of Collection nor the Axiom of Union. (Contributed by
BTernaryTau, 7-Dec-2024.)
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| Theorem | f1oen3g 6922 |
The domain and range of a one-to-one, onto function are equinumerous.
This variation of f1oeng 6925 does not require the Axiom of Replacement.
(Contributed by NM, 13-Jan-2007.) (Revised by Mario Carneiro,
10-Sep-2015.)
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| Theorem | f1oen2g 6923 |
The domain and range of a one-to-one, onto function are equinumerous.
This variation of f1oeng 6925 does not require the Axiom of Replacement.
(Contributed by Mario Carneiro, 10-Sep-2015.)
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| Theorem | f1dom2g 6924 |
The domain of a one-to-one function is dominated by its codomain. This
variation of f1domg 6926 does not require the Axiom of Replacement.
(Contributed by Mario Carneiro, 24-Jun-2015.)
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| Theorem | f1oeng 6925 |
The domain and range of a one-to-one, onto function are equinumerous.
(Contributed by NM, 19-Jun-1998.)
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| Theorem | f1domg 6926 |
The domain of a one-to-one function is dominated by its codomain.
(Contributed by NM, 4-Sep-2004.)
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| Theorem | f1oen 6927 |
The domain and range of a one-to-one, onto function are equinumerous.
(Contributed by NM, 19-Jun-1998.)
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| Theorem | f1dom 6928 |
The domain of a one-to-one function is dominated by its codomain.
(Contributed by NM, 19-Jun-1998.)
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| Theorem | isfi 6929* |
Express " is
finite". Definition 10.29 of [TakeutiZaring] p. 91
(whose " " is a predicate instead of a class). (Contributed by
NM, 22-Aug-2008.)
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| Theorem | enssdom 6930 |
Equinumerosity implies dominance. (Contributed by NM, 31-Mar-1998.)
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| Theorem | endom 6931 |
Equinumerosity implies dominance. Theorem 15 of [Suppes] p. 94.
(Contributed by NM, 28-May-1998.)
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| Theorem | enrefg 6932 |
Equinumerosity is reflexive. Theorem 1 of [Suppes] p. 92. (Contributed
by NM, 18-Jun-1998.) (Revised by Mario Carneiro, 26-Apr-2015.)
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| Theorem | enref 6933 |
Equinumerosity is reflexive. Theorem 1 of [Suppes] p. 92. (Contributed
by NM, 25-Sep-2004.)
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| Theorem | eqeng 6934 |
Equality implies equinumerosity. (Contributed by NM, 26-Oct-2003.)
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| Theorem | domrefg 6935 |
Dominance is reflexive. (Contributed by NM, 18-Jun-1998.)
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| Theorem | en2d 6936* |
Equinumerosity inference from an implicit one-to-one onto function.
(Contributed by NM, 27-Jul-2004.) (Revised by Mario Carneiro,
12-May-2014.)
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| Theorem | en3d 6937* |
Equinumerosity inference from an implicit one-to-one onto function.
(Contributed by NM, 27-Jul-2004.) (Revised by Mario Carneiro,
12-May-2014.)
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| Theorem | en2i 6938* |
Equinumerosity inference from an implicit one-to-one onto function.
(Contributed by NM, 4-Jan-2004.)
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| Theorem | en3i 6939* |
Equinumerosity inference from an implicit one-to-one onto function.
(Contributed by NM, 19-Jul-2004.)
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| Theorem | dom2lem 6940* |
A mapping (first hypothesis) that is one-to-one (second hypothesis)
implies its domain is dominated by its codomain. (Contributed by NM,
24-Jul-2004.)
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| Theorem | dom2d 6941* |
A mapping (first hypothesis) that is one-to-one (second hypothesis)
implies its domain is dominated by its codomain. (Contributed by NM,
24-Jul-2004.) (Revised by Mario Carneiro, 20-May-2013.)
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| Theorem | dom3d 6942* |
A mapping (first hypothesis) that is one-to-one (second hypothesis)
implies its domain is dominated by its codomain. (Contributed by Mario
Carneiro, 20-May-2013.)
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| Theorem | dom2 6943* |
A mapping (first hypothesis) that is one-to-one (second hypothesis)
implies its domain is dominated by its codomain. and can be
read    and    , as can be inferred from their
distinct variable conditions. (Contributed by NM, 26-Oct-2003.)
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| Theorem | dom3 6944* |
A mapping (first hypothesis) that is one-to-one (second hypothesis)
implies its domain is dominated by its codomain. and can be
read    and    , as can be inferred from their
distinct variable conditions. (Contributed by Mario Carneiro,
20-May-2013.)
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| Theorem | idssen 6945 |
Equality implies equinumerosity. (Contributed by NM, 30-Apr-1998.)
(Revised by Mario Carneiro, 15-Nov-2014.)
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| Theorem | domssr 6946 |
If is a superset of
and dominates , then
also dominates . (Contributed by BTernaryTau, 7-Dec-2024.)
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| Theorem | ssdomg 6947 |
A set dominates its subsets. Theorem 16 of [Suppes] p. 94. (Contributed
by NM, 19-Jun-1998.) (Revised by Mario Carneiro, 24-Jun-2015.)
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| Theorem | ener 6948 |
Equinumerosity is an equivalence relation. (Contributed by NM,
19-Mar-1998.) (Revised by Mario Carneiro, 15-Nov-2014.)
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| Theorem | ensymb 6949 |
Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92. (Contributed by
Mario Carneiro, 26-Apr-2015.)
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| Theorem | ensym 6950 |
Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92. (Contributed by
NM, 26-Oct-2003.) (Revised by Mario Carneiro, 26-Apr-2015.)
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| Theorem | ensymi 6951 |
Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92. (Contributed
by NM, 25-Sep-2004.)
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| Theorem | ensymd 6952 |
Symmetry of equinumerosity. Deduction form of ensym 6950. (Contributed
by David Moews, 1-May-2017.)
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| Theorem | entr 6953 |
Transitivity of equinumerosity. Theorem 3 of [Suppes] p. 92.
(Contributed by NM, 9-Jun-1998.)
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| Theorem | domtr 6954 |
Transitivity of dominance relation. Theorem 17 of [Suppes] p. 94.
(Contributed by NM, 4-Jun-1998.) (Revised by Mario Carneiro,
15-Nov-2014.)
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| Theorem | entri 6955 |
A chained equinumerosity inference. (Contributed by NM,
25-Sep-2004.)
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| Theorem | entr2i 6956 |
A chained equinumerosity inference. (Contributed by NM,
25-Sep-2004.)
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| Theorem | entr3i 6957 |
A chained equinumerosity inference. (Contributed by NM,
25-Sep-2004.)
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| Theorem | entr4i 6958 |
A chained equinumerosity inference. (Contributed by NM,
25-Sep-2004.)
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| Theorem | endomtr 6959 |
Transitivity of equinumerosity and dominance. (Contributed by NM,
7-Jun-1998.)
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| Theorem | domentr 6960 |
Transitivity of dominance and equinumerosity. (Contributed by NM,
7-Jun-1998.)
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| Theorem | f1imaeng 6961 |
A one-to-one function's image under a subset of its domain is equinumerous
to the subset. (Contributed by Mario Carneiro, 15-May-2015.)
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| Theorem | f1imaen2g 6962 |
A one-to-one function's image under a subset of its domain is equinumerous
to the subset. (This version of f1imaen 6963 does not need ax-setind 4633.)
(Contributed by Mario Carneiro, 16-Nov-2014.) (Revised by Mario Carneiro,
25-Jun-2015.)
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| Theorem | f1imaen 6963 |
A one-to-one function's image under a subset of its domain is
equinumerous to the subset. (Contributed by NM, 30-Sep-2004.)
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| Theorem | en0 6964 |
The empty set is equinumerous only to itself. Exercise 1 of
[TakeutiZaring] p. 88.
(Contributed by NM, 27-May-1998.)
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| Theorem | ensn1 6965 |
A singleton is equinumerous to ordinal one. (Contributed by NM,
4-Nov-2002.)
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| Theorem | ensn1g 6966 |
A singleton is equinumerous to ordinal one. (Contributed by NM,
23-Apr-2004.)
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| Theorem | enpr1g 6967 |
   has only
one element. (Contributed by FL, 15-Feb-2010.)
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| Theorem | en1 6968* |
A set is equinumerous to ordinal one iff it is a singleton.
(Contributed by NM, 25-Jul-2004.)
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| Theorem | en1bg 6969 |
A set is equinumerous to ordinal one iff it is a singleton.
(Contributed by Jim Kingdon, 13-Apr-2020.)
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| Theorem | reuen1 6970* |
Two ways to express "exactly one". (Contributed by Stefan O'Rear,
28-Oct-2014.)
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| Theorem | euen1 6971 |
Two ways to express "exactly one". (Contributed by Stefan O'Rear,
28-Oct-2014.)
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| Theorem | euen1b 6972* |
Two ways to express " has a unique element". (Contributed by
Mario Carneiro, 9-Apr-2015.)
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| Theorem | en1uniel 6973 |
A singleton contains its sole element. (Contributed by Stefan O'Rear,
16-Aug-2015.)
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| Theorem | en1m 6974* |
A set with one element is inhabited. (Contributed by Jim Kingdon,
3-Jan-2026.)
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| Theorem | 2dom 6975* |
A set that dominates ordinal 2 has at least 2 different members.
(Contributed by NM, 25-Jul-2004.)
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| Theorem | fundmen 6976 |
A function is equinumerous to its domain. Exercise 4 of [Suppes] p. 98.
(Contributed by NM, 28-Jul-2004.) (Revised by Mario Carneiro,
15-Nov-2014.)
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| Theorem | fundmeng 6977 |
A function is equinumerous to its domain. Exercise 4 of [Suppes] p. 98.
(Contributed by NM, 17-Sep-2013.)
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| Theorem | cnven 6978 |
A relational set is equinumerous to its converse. (Contributed by Mario
Carneiro, 28-Dec-2014.)
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| Theorem | cnvct 6979 |
If a set is dominated by , so is its converse. (Contributed by
Thierry Arnoux, 29-Dec-2016.)
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| Theorem | fndmeng 6980 |
A function is equinumerate to its domain. (Contributed by Paul Chapman,
22-Jun-2011.)
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| Theorem | mapsnen 6981 |
Set exponentiation to a singleton exponent is equinumerous to its base.
Exercise 4.43 of [Mendelson] p. 255.
(Contributed by NM, 17-Dec-2003.)
(Revised by Mario Carneiro, 15-Nov-2014.)
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| Theorem | map1 6982 |
Set exponentiation: ordinal 1 to any set is equinumerous to ordinal 1.
Exercise 4.42(b) of [Mendelson] p.
255. (Contributed by NM,
17-Dec-2003.)
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| Theorem | en2sn 6983 |
Two singletons are equinumerous. (Contributed by NM, 9-Nov-2003.)
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| Theorem | snfig 6984 |
A singleton is finite. For the proper class case, see snprc 3732.
(Contributed by Jim Kingdon, 13-Apr-2020.)
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| Theorem | fiprc 6985 |
The class of finite sets is a proper class. (Contributed by Jeff
Hankins, 3-Oct-2008.)
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| Theorem | unen 6986 |
Equinumerosity of union of disjoint sets. Theorem 4 of [Suppes] p. 92.
(Contributed by NM, 11-Jun-1998.) (Revised by Mario Carneiro,
26-Apr-2015.)
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| Theorem | en2prd 6987 |
Two proper unordered pairs are equinumerous. (Contributed by
BTernaryTau, 23-Dec-2024.)
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| Theorem | 1dom1el 6988 |
If a set is dominated by one, then any two of its elements are equal.
(Contributed by Jim Kingdon, 23-Apr-2025.)
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| Theorem | modom 6989 |
Two ways to express "at most one". (Contributed by Stefan O'Rear,
28-Oct-2014.)
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| Theorem | modom2 6990* |
Two ways to express "at most one". (Contributed by Mario Carneiro,
24-Dec-2016.)
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| Theorem | rex2dom 6991* |
A set that has at least 2 different members dominates ordinal 2.
(Contributed by BTernaryTau, 30-Dec-2024.)
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| Theorem | enpr2d 6992 |
A pair with distinct elements is equinumerous to ordinal two.
(Contributed by Rohan Ridenour, 3-Aug-2023.)
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| Theorem | en2 6993* |
A set equinumerous to ordinal 2 is an unordered pair. (Contributed by
Mario Carneiro, 5-Jan-2016.)
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| Theorem | en2m 6994* |
A set with two elements is inhabited. (Contributed by Jim Kingdon,
3-Jan-2026.)
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| Theorem | ssct 6995 |
A subset of a set dominated by is dominated by .
(Contributed by Thierry Arnoux, 31-Jan-2017.)
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| Theorem | 1domsn 6996 |
A singleton (whether of a set or a proper class) is dominated by one.
(Contributed by Jim Kingdon, 1-Mar-2022.)
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| Theorem | dom1o 6997* |
Two ways of saying that a set is inhabited. (Contributed by Jim
Kingdon, 3-Jan-2026.)
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| Theorem | dom1oi 6998 |
A set with an element dominates one. (Contributed by Jim Kingdon,
3-Feb-2026.)
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| Theorem | enm 6999* |
A set equinumerous to an inhabited set is inhabited. (Contributed by
Jim Kingdon, 19-May-2020.)
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| Theorem | xpsnen 7000 |
A set is equinumerous to its Cartesian product with a singleton.
Proposition 4.22(c) of [Mendelson] p.
254. (Contributed by NM,
4-Jan-2004.) (Revised by Mario Carneiro, 15-Nov-2014.)
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