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Type | Label | Description |
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Statement | ||
Theorem | xpdom1 6801 | Dominance law for Cartesian product. Theorem 6L(c) of [Enderton] p. 149. (Contributed by NM, 28-Sep-2004.) (Revised by NM, 29-Mar-2006.) (Revised by Mario Carneiro, 7-May-2015.) |
Theorem | fopwdom 6802 | Covering implies injection on power sets. (Contributed by Stefan O'Rear, 6-Nov-2014.) (Revised by Mario Carneiro, 24-Jun-2015.) |
Theorem | 0domg 6803 | Any set dominates the empty set. (Contributed by NM, 26-Oct-2003.) (Revised by Mario Carneiro, 26-Apr-2015.) |
Theorem | dom0 6804 | A set dominated by the empty set is empty. (Contributed by NM, 22-Nov-2004.) |
Theorem | 0dom 6805 | Any set dominates the empty set. (Contributed by NM, 26-Oct-2003.) (Revised by Mario Carneiro, 26-Apr-2015.) |
Theorem | enen1 6806 | Equality-like theorem for equinumerosity. (Contributed by NM, 18-Dec-2003.) |
Theorem | enen2 6807 | Equality-like theorem for equinumerosity. (Contributed by NM, 18-Dec-2003.) |
Theorem | domen1 6808 | Equality-like theorem for equinumerosity and dominance. (Contributed by NM, 8-Nov-2003.) |
Theorem | domen2 6809 | Equality-like theorem for equinumerosity and dominance. (Contributed by NM, 8-Nov-2003.) |
Theorem | xpf1o 6810* | Construct a bijection on a Cartesian product given bijections on the factors. (Contributed by Mario Carneiro, 30-May-2015.) |
Theorem | xpen 6811 | Equinumerosity law for Cartesian product. Proposition 4.22(b) of [Mendelson] p. 254. (Contributed by NM, 24-Jul-2004.) |
Theorem | mapen 6812 | Two set exponentiations are equinumerous when their bases and exponents are equinumerous. Theorem 6H(c) of [Enderton] p. 139. (Contributed by NM, 16-Dec-2003.) (Proof shortened by Mario Carneiro, 26-Apr-2015.) |
Theorem | mapdom1g 6813 | Order-preserving property of set exponentiation. (Contributed by Jim Kingdon, 15-Jul-2022.) |
Theorem | mapxpen 6814 | Equinumerosity law for double set exponentiation. Proposition 10.45 of [TakeutiZaring] p. 96. (Contributed by NM, 21-Feb-2004.) (Revised by Mario Carneiro, 24-Jun-2015.) |
Theorem | xpmapenlem 6815* | Lemma for xpmapen 6816. (Contributed by NM, 1-May-2004.) (Revised by Mario Carneiro, 16-Nov-2014.) |
Theorem | xpmapen 6816 | Equinumerosity law for set exponentiation of a Cartesian product. Exercise 4.47 of [Mendelson] p. 255. (Contributed by NM, 23-Feb-2004.) (Proof shortened by Mario Carneiro, 16-Nov-2014.) |
Theorem | ssenen 6817* | Equinumerosity of equinumerous subsets of a set. (Contributed by NM, 30-Sep-2004.) (Revised by Mario Carneiro, 16-Nov-2014.) |
Theorem | phplem1 6818 | Lemma for Pigeonhole Principle. If we join a natural number to itself minus an element, we end up with its successor minus the same element. (Contributed by NM, 25-May-1998.) |
Theorem | phplem2 6819 | Lemma for Pigeonhole Principle. A natural number is equinumerous to its successor minus one of its elements. (Contributed by NM, 11-Jun-1998.) (Revised by Mario Carneiro, 16-Nov-2014.) |
Theorem | phplem3 6820 | Lemma for Pigeonhole Principle. A natural number is equinumerous to its successor minus any element of the successor. For a version without the redundant hypotheses, see phplem3g 6822. (Contributed by NM, 26-May-1998.) |
Theorem | phplem4 6821 | Lemma for Pigeonhole Principle. Equinumerosity of successors implies equinumerosity of the original natural numbers. (Contributed by NM, 28-May-1998.) (Revised by Mario Carneiro, 24-Jun-2015.) |
Theorem | phplem3g 6822 | A natural number is equinumerous to its successor minus any element of the successor. Version of phplem3 6820 with unnecessary hypotheses removed. (Contributed by Jim Kingdon, 1-Sep-2021.) |
Theorem | nneneq 6823 | Two equinumerous natural numbers are equal. Proposition 10.20 of [TakeutiZaring] p. 90 and its converse. Also compare Corollary 6E of [Enderton] p. 136. (Contributed by NM, 28-May-1998.) |
Theorem | php5 6824 | A natural number is not equinumerous to its successor. Corollary 10.21(1) of [TakeutiZaring] p. 90. (Contributed by NM, 26-Jul-2004.) |
Theorem | snnen2og 6825 | A singleton is never equinumerous with the ordinal number 2. If is a proper class, see snnen2oprc 6826. (Contributed by Jim Kingdon, 1-Sep-2021.) |
Theorem | snnen2oprc 6826 | A singleton is never equinumerous with the ordinal number 2. If is a set, see snnen2og 6825. (Contributed by Jim Kingdon, 1-Sep-2021.) |
Theorem | 1nen2 6827 | One and two are not equinumerous. (Contributed by Jim Kingdon, 25-Jan-2022.) |
Theorem | phplem4dom 6828 | Dominance of successors implies dominance of the original natural numbers. (Contributed by Jim Kingdon, 1-Sep-2021.) |
Theorem | php5dom 6829 | A natural number does not dominate its successor. (Contributed by Jim Kingdon, 1-Sep-2021.) |
Theorem | nndomo 6830 | Cardinal ordering agrees with natural number ordering. Example 3 of [Enderton] p. 146. (Contributed by NM, 17-Jun-1998.) |
Theorem | phpm 6831* | Pigeonhole Principle. A natural number is not equinumerous to a proper subset of itself. By "proper subset" here we mean that there is an element which is in the natural number and not in the subset, or in symbols (which is stronger than not being equal in the absence of excluded middle). Theorem (Pigeonhole Principle) of [Enderton] p. 134. The theorem is so-called because you can't put n + 1 pigeons into n holes (if each hole holds only one pigeon). The proof consists of lemmas phplem1 6818 through phplem4 6821, nneneq 6823, and this final piece of the proof. (Contributed by NM, 29-May-1998.) |
Theorem | phpelm 6832 | Pigeonhole Principle. A natural number is not equinumerous to an element of itself. (Contributed by Jim Kingdon, 6-Sep-2021.) |
Theorem | phplem4on 6833 | Equinumerosity of successors of an ordinal and a natural number implies equinumerosity of the originals. (Contributed by Jim Kingdon, 5-Sep-2021.) |
Theorem | fict 6834 | A finite set is dominated by . Also see finct 7081. (Contributed by Thierry Arnoux, 27-Mar-2018.) |
Theorem | fidceq 6835 | Equality of members of a finite set is decidable. This may be counterintuitive: cannot any two sets be elements of a finite set? Well, to show, for example, that is finite would require showing it is equinumerous to or to but to show that you'd need to know or , respectively. (Contributed by Jim Kingdon, 5-Sep-2021.) |
DECID | ||
Theorem | fidifsnen 6836 | All decrements of a finite set are equinumerous. (Contributed by Jim Kingdon, 9-Sep-2021.) |
Theorem | fidifsnid 6837 | If we remove a single element from a finite set then put it back in, we end up with the original finite set. This strengthens difsnss 3719 from subset to equality when the set is finite. (Contributed by Jim Kingdon, 9-Sep-2021.) |
Theorem | nnfi 6838 | Natural numbers are finite sets. (Contributed by Stefan O'Rear, 21-Mar-2015.) |
Theorem | enfi 6839 | Equinumerous sets have the same finiteness. (Contributed by NM, 22-Aug-2008.) |
Theorem | enfii 6840 | A set equinumerous to a finite set is finite. (Contributed by Mario Carneiro, 12-Mar-2015.) |
Theorem | ssfilem 6841* | Lemma for ssfiexmid 6842. (Contributed by Jim Kingdon, 3-Feb-2022.) |
Theorem | ssfiexmid 6842* | If any subset of a finite set is finite, excluded middle follows. One direction of Theorem 2.1 of [Bauer], p. 485. (Contributed by Jim Kingdon, 19-May-2020.) |
Theorem | infiexmid 6843* | If the intersection of any finite set and any other set is finite, excluded middle follows. (Contributed by Jim Kingdon, 5-Feb-2022.) |
Theorem | domfiexmid 6844* | If any set dominated by a finite set is finite, excluded middle follows. (Contributed by Jim Kingdon, 3-Feb-2022.) |
Theorem | dif1en 6845 | If a set is equinumerous to the successor of a natural number , then with an element removed is equinumerous to . (Contributed by Jeff Madsen, 2-Sep-2009.) (Revised by Stefan O'Rear, 16-Aug-2015.) |
Theorem | dif1enen 6846 | Subtracting one element from each of two equinumerous finite sets. (Contributed by Jim Kingdon, 5-Jun-2022.) |
Theorem | fiunsnnn 6847 | Adding one element to a finite set which is equinumerous to a natural number. (Contributed by Jim Kingdon, 13-Sep-2021.) |
Theorem | php5fin 6848 | A finite set is not equinumerous to a set which adds one element. (Contributed by Jim Kingdon, 13-Sep-2021.) |
Theorem | fisbth 6849 | Schroeder-Bernstein Theorem for finite sets. (Contributed by Jim Kingdon, 12-Sep-2021.) |
Theorem | 0fin 6850 | The empty set is finite. (Contributed by FL, 14-Jul-2008.) |
Theorem | fin0 6851* | A nonempty finite set has at least one element. (Contributed by Jim Kingdon, 10-Sep-2021.) |
Theorem | fin0or 6852* | A finite set is either empty or inhabited. (Contributed by Jim Kingdon, 30-Sep-2021.) |
Theorem | diffitest 6853* | If subtracting any set from a finite set gives a finite set, any proposition of the form is decidable. This is not a proof of full excluded middle, but it is close enough to show we won't be able to prove . (Contributed by Jim Kingdon, 8-Sep-2021.) |
Theorem | findcard 6854* | Schema for induction on the cardinality of a finite set. The inductive hypothesis is that the result is true on the given set with any one element removed. The result is then proven to be true for all finite sets. (Contributed by Jeff Madsen, 2-Sep-2009.) |
Theorem | findcard2 6855* | Schema for induction on the cardinality of a finite set. The inductive step shows that the result is true if one more element is added to the set. The result is then proven to be true for all finite sets. (Contributed by Jeff Madsen, 8-Jul-2010.) |
Theorem | findcard2s 6856* | Variation of findcard2 6855 requiring that the element added in the induction step not be a member of the original set. (Contributed by Paul Chapman, 30-Nov-2012.) |
Theorem | findcard2d 6857* | Deduction version of findcard2 6855. If you also need (which doesn't come for free due to ssfiexmid 6842), use findcard2sd 6858 instead. (Contributed by SO, 16-Jul-2018.) |
Theorem | findcard2sd 6858* | Deduction form of finite set induction . (Contributed by Jim Kingdon, 14-Sep-2021.) |
Theorem | diffisn 6859 | Subtracting a singleton from a finite set produces a finite set. (Contributed by Jim Kingdon, 11-Sep-2021.) |
Theorem | diffifi 6860 | Subtracting one finite set from another produces a finite set. (Contributed by Jim Kingdon, 8-Sep-2021.) |
Theorem | infnfi 6861 | An infinite set is not finite. (Contributed by Jim Kingdon, 20-Feb-2022.) |
Theorem | ominf 6862 | The set of natural numbers is not finite. Although we supply this theorem because we can, the more natural way to express " is infinite" is which is an instance of domrefg 6733. (Contributed by NM, 2-Jun-1998.) |
Theorem | isinfinf 6863* | An infinite set contains subsets of arbitrarily large finite cardinality. (Contributed by Jim Kingdon, 15-Jun-2022.) |
Theorem | ac6sfi 6864* | Existence of a choice function for finite sets. (Contributed by Jeff Hankins, 26-Jun-2009.) (Proof shortened by Mario Carneiro, 29-Jan-2014.) |
Theorem | tridc 6865* | A trichotomous order is decidable. (Contributed by Jim Kingdon, 5-Sep-2022.) |
DECID | ||
Theorem | fimax2gtrilemstep 6866* | Lemma for fimax2gtri 6867. The induction step. (Contributed by Jim Kingdon, 5-Sep-2022.) |
Theorem | fimax2gtri 6867* | A finite set has a maximum under a trichotomous order. (Contributed by Jim Kingdon, 5-Sep-2022.) |
Theorem | finexdc 6868* | Decidability of existence, over a finite set and defined by a decidable proposition. (Contributed by Jim Kingdon, 12-Jul-2022.) |
DECID DECID | ||
Theorem | dfrex2fin 6869* | Relationship between universal and existential quantifiers over a finite set. Remark in Section 2.2.1 of [Pierik], p. 8. Although Pierik does not mention the decidability condition explicitly, it does say "only finitely many x to check" which means there must be some way of checking each value of x. (Contributed by Jim Kingdon, 11-Jul-2022.) |
DECID | ||
Theorem | infm 6870* | An infinite set is inhabited. (Contributed by Jim Kingdon, 18-Feb-2022.) |
Theorem | infn0 6871 | An infinite set is not empty. (Contributed by NM, 23-Oct-2004.) |
Theorem | inffiexmid 6872* | If any given set is either finite or infinite, excluded middle follows. (Contributed by Jim Kingdon, 15-Jun-2022.) |
Theorem | en2eqpr 6873 | Building a set with two elements. (Contributed by FL, 11-Aug-2008.) (Revised by Mario Carneiro, 10-Sep-2015.) |
Theorem | exmidpw 6874 | Excluded middle is equivalent to the power set of having two elements. Remark of [PradicBrown2022], p. 2. (Contributed by Jim Kingdon, 30-Jun-2022.) |
EXMID | ||
Theorem | exmidpweq 6875 | Excluded middle is equivalent to the power set of being . (Contributed by Jim Kingdon, 28-Jul-2024.) |
EXMID | ||
Theorem | pw1fin 6876 | Excluded middle is equivalent to the power set of being finite. (Contributed by SN and Jim Kingdon, 7-Aug-2024.) |
EXMID | ||
Theorem | pw1dc0el 6877 | Another equivalent of excluded middle, which is a mere reformulation of the definition. (Contributed by BJ, 9-Aug-2024.) |
EXMID DECID | ||
Theorem | ss1o0el1o 6878 | Reformulation of ss1o0el1 4176 using instead of . (Contributed by BJ, 9-Aug-2024.) |
Theorem | pw1dc1 6879 | If, in the set of truth values (the powerset of 1o), equality to 1o is decidable, then excluded middle holds (and conversely). (Contributed by BJ and Jim Kingdon, 8-Aug-2024.) |
EXMID DECID | ||
Theorem | fientri3 6880 | Trichotomy of dominance for finite sets. (Contributed by Jim Kingdon, 15-Sep-2021.) |
Theorem | nnwetri 6881* | A natural number is well-ordered by . More specifically, this order both satisfies and is trichotomous. (Contributed by Jim Kingdon, 25-Sep-2021.) |
Theorem | onunsnss 6882 | Adding a singleton to create an ordinal. (Contributed by Jim Kingdon, 20-Oct-2021.) |
Theorem | unfiexmid 6883* | If the union of any two finite sets is finite, excluded middle follows. Remark 8.1.17 of [AczelRathjen], p. 74. (Contributed by Mario Carneiro and Jim Kingdon, 5-Mar-2022.) |
Theorem | unsnfi 6884 | Adding a singleton to a finite set yields a finite set. (Contributed by Jim Kingdon, 3-Feb-2022.) |
Theorem | unsnfidcex 6885 | The condition in unsnfi 6884. This is intended to show that unsnfi 6884 without that condition would not be provable but it probably would need to be strengthened (for example, to imply included middle) to fully show that. (Contributed by Jim Kingdon, 6-Feb-2022.) |
DECID | ||
Theorem | unsnfidcel 6886 | The condition in unsnfi 6884. This is intended to show that unsnfi 6884 without that condition would not be provable but it probably would need to be strengthened (for example, to imply included middle) to fully show that. (Contributed by Jim Kingdon, 6-Feb-2022.) |
DECID | ||
Theorem | unfidisj 6887 | The union of two disjoint finite sets is finite. (Contributed by Jim Kingdon, 25-Feb-2022.) |
Theorem | undifdcss 6888* | Union of complementary parts into whole and decidability. (Contributed by Jim Kingdon, 17-Jun-2022.) |
DECID | ||
Theorem | undifdc 6889* | Union of complementary parts into whole. This is a case where we can strengthen undifss 3489 from subset to equality. (Contributed by Jim Kingdon, 17-Jun-2022.) |
DECID | ||
Theorem | undiffi 6890 | Union of complementary parts into whole. This is a case where we can strengthen undifss 3489 from subset to equality. (Contributed by Jim Kingdon, 2-Mar-2022.) |
Theorem | unfiin 6891 | The union of two finite sets is finite if their intersection is. (Contributed by Jim Kingdon, 2-Mar-2022.) |
Theorem | prfidisj 6892 | A pair is finite if it consists of two unequal sets. For the case where , see snfig 6780. For the cases where one or both is a proper class, see prprc1 3684, prprc2 3685, or prprc 3686. (Contributed by Jim Kingdon, 31-May-2022.) |
Theorem | tpfidisj 6893 | A triple is finite if it consists of three unequal sets. (Contributed by Jim Kingdon, 1-Oct-2022.) |
Theorem | fiintim 6894* |
If a class is closed under pairwise intersections, then it is closed
under nonempty finite intersections. The converse would appear to
require an additional condition, such as and not being
equal, or
having decidable equality.
This theorem is applicable to a topology, which (among other axioms) is closed under finite intersections. Some texts use a pairwise intersection and some texts use a finite intersection, but most topology texts assume excluded middle (in which case the two intersection properties would be equivalent). (Contributed by NM, 22-Sep-2002.) (Revised by Jim Kingdon, 14-Jan-2023.) |
Theorem | xpfi 6895 | The Cartesian product of two finite sets is finite. Lemma 8.1.16 of [AczelRathjen], p. 74. (Contributed by Jeff Madsen, 2-Sep-2009.) (Revised by Mario Carneiro, 12-Mar-2015.) |
Theorem | 3xpfi 6896 | The Cartesian product of three finite sets is a finite set. (Contributed by Alexander van der Vekens, 11-Mar-2018.) |
Theorem | fisseneq 6897 | A finite set is equal to its subset if they are equinumerous. (Contributed by FL, 11-Aug-2008.) |
Theorem | phpeqd 6898 | Corollary of the Pigeonhole Principle using equality. Strengthening of phpm 6831 expressed without negation. (Contributed by Rohan Ridenour, 3-Aug-2023.) |
Theorem | ssfirab 6899* | A subset of a finite set is finite if it is defined by a decidable property. (Contributed by Jim Kingdon, 27-May-2022.) |
DECID | ||
Theorem | ssfidc 6900* | A subset of a finite set is finite if membership in the subset is decidable. (Contributed by Jim Kingdon, 27-May-2022.) |
DECID |
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