Theorem List for Intuitionistic Logic Explorer - 6801-6900   *Has distinct variable
 group(s)
| Type | Label | Description | 
| Statement | 
|   | 
| Definition | df-dom 6801* | 
Define the dominance relation.  Compare Definition of [Enderton] p. 145.
       Typical textbook definitions are derived as brdom 6809 and domen 6810.
       (Contributed by NM, 28-Mar-1998.)
 | 
                          | 
|   | 
| Definition | df-fin 6802* | 
Define the (proper) class of all finite sets.  Similar to Definition
       10.29 of [TakeutiZaring] p. 91,
whose "Fin(a)" corresponds to
       our "     ".  This definition is
meaningful whether or not we
       accept the Axiom of Infinity ax-inf2 15622.  (Contributed by NM,
       22-Aug-2008.)
 | 
     
                    | 
|   | 
| Theorem | relen 6803 | 
Equinumerosity is a relation.  (Contributed by NM, 28-Mar-1998.)
 | 
      | 
|   | 
| Theorem | reldom 6804 | 
Dominance is a relation.  (Contributed by NM, 28-Mar-1998.)
 | 
      | 
|   | 
| Theorem | encv 6805 | 
If two classes are equinumerous, both classes are sets.  (Contributed by
     AV, 21-Mar-2019.)
 | 
                            | 
|   | 
| Theorem | bren 6806* | 
Equinumerosity relation.  (Contributed by NM, 15-Jun-1998.)
 | 
                     | 
|   | 
| Theorem | brdomg 6807* | 
Dominance relation.  (Contributed by NM, 15-Jun-1998.)
 | 
                               | 
|   | 
| Theorem | brdomi 6808* | 
Dominance relation.  (Contributed by Mario Carneiro, 26-Apr-2015.)
 | 
                     | 
|   | 
| Theorem | brdom 6809* | 
Dominance relation.  (Contributed by NM, 15-Jun-1998.)
 | 
                                   | 
|   | 
| Theorem | domen 6810* | 
Dominance in terms of equinumerosity.  Example 1 of [Enderton] p. 146.
       (Contributed by NM, 15-Jun-1998.)
 | 
                                            | 
|   | 
| Theorem | domeng 6811* | 
Dominance in terms of equinumerosity, with the sethood requirement
       expressed as an antecedent.  Example 1 of [Enderton] p. 146.
       (Contributed by NM, 24-Apr-2004.)
 | 
                                        | 
|   | 
| Theorem | ctex 6812 | 
A class dominated by   is a set.  See also ctfoex 7184 which says that
     a countable class is a set.  (Contributed by Thierry Arnoux, 29-Dec-2016.)
     (Proof shortened by Jim Kingdon, 13-Mar-2023.)
 | 
                  | 
|   | 
| Theorem | f1oen3g 6813 | 
The domain and range of a one-to-one, onto function are equinumerous.
       This variation of f1oeng 6816 does not require the Axiom of Replacement.
       (Contributed by NM, 13-Jan-2007.)  (Revised by Mario Carneiro,
       10-Sep-2015.)
 | 
                            | 
|   | 
| Theorem | f1oen2g 6814 | 
The domain and range of a one-to-one, onto function are equinumerous.
       This variation of f1oeng 6816 does not require the Axiom of Replacement.
       (Contributed by Mario Carneiro, 10-Sep-2015.)
 | 
                                    | 
|   | 
| Theorem | f1dom2g 6815 | 
The domain of a one-to-one function is dominated by its codomain.  This
       variation of f1domg 6817 does not require the Axiom of Replacement.
       (Contributed by Mario Carneiro, 24-Jun-2015.)
 | 
                                    | 
|   | 
| Theorem | f1oeng 6816 | 
The domain and range of a one-to-one, onto function are equinumerous.
       (Contributed by NM, 19-Jun-1998.)
 | 
                            | 
|   | 
| Theorem | f1domg 6817 | 
The domain of a one-to-one function is dominated by its codomain.
       (Contributed by NM, 4-Sep-2004.)
 | 
                            | 
|   | 
| Theorem | f1oen 6818 | 
The domain and range of a one-to-one, onto function are equinumerous.
       (Contributed by NM, 19-Jun-1998.)
 | 
                                | 
|   | 
| Theorem | f1dom 6819 | 
The domain of a one-to-one function is dominated by its codomain.
       (Contributed by NM, 19-Jun-1998.)
 | 
                      
          | 
|   | 
| Theorem | isfi 6820* | 
Express "  is
finite".  Definition 10.29 of [TakeutiZaring] p. 91
       (whose "  " is a predicate instead of a class).  (Contributed by
       NM, 22-Aug-2008.)
 | 
               
          | 
|   | 
| Theorem | enssdom 6821 | 
Equinumerosity implies dominance.  (Contributed by NM, 31-Mar-1998.)
 | 
        | 
|   | 
| Theorem | endom 6822 | 
Equinumerosity implies dominance.  Theorem 15 of [Suppes] p. 94.
     (Contributed by NM, 28-May-1998.)
 | 
                  | 
|   | 
| Theorem | enrefg 6823 | 
Equinumerosity is reflexive.  Theorem 1 of [Suppes] p. 92.  (Contributed
     by NM, 18-Jun-1998.)  (Revised by Mario Carneiro, 26-Apr-2015.)
 | 
                  | 
|   | 
| Theorem | enref 6824 | 
Equinumerosity is reflexive.  Theorem 1 of [Suppes] p. 92.  (Contributed
       by NM, 25-Sep-2004.)
 | 
                      | 
|   | 
| Theorem | eqeng 6825 | 
Equality implies equinumerosity.  (Contributed by NM, 26-Oct-2003.)
 | 
                            | 
|   | 
| Theorem | domrefg 6826 | 
Dominance is reflexive.  (Contributed by NM, 18-Jun-1998.)
 | 
                  | 
|   | 
| Theorem | en2d 6827* | 
Equinumerosity inference from an implicit one-to-one onto function.
       (Contributed by NM, 27-Jul-2004.)  (Revised by Mario Carneiro,
       12-May-2014.)
 | 
                                                       
                                                   
      
        
                  
                          | 
|   | 
| Theorem | en3d 6828* | 
Equinumerosity inference from an implicit one-to-one onto function.
       (Contributed by NM, 27-Jul-2004.)  (Revised by Mario Carneiro,
       12-May-2014.)
 | 
                                                       
                              
                                             
      
                            | 
|   | 
| Theorem | en2i 6829* | 
Equinumerosity inference from an implicit one-to-one onto function.
       (Contributed by NM, 4-Jan-2004.)
 | 
                                      
                        
                                                                  | 
|   | 
| Theorem | en3i 6830* | 
Equinumerosity inference from an implicit one-to-one onto function.
       (Contributed by NM, 19-Jul-2004.)
 | 
                                      
                        
                                       
      
                     | 
|   | 
| Theorem | dom2lem 6831* | 
A mapping (first hypothesis) that is one-to-one (second hypothesis)
       implies its domain is dominated by its codomain.  (Contributed by NM,
       24-Jul-2004.)
 | 
           
                         
      
        
                                         
             | 
|   | 
| Theorem | dom2d 6832* | 
A mapping (first hypothesis) that is one-to-one (second hypothesis)
       implies its domain is dominated by its codomain.  (Contributed by NM,
       24-Jul-2004.)  (Revised by Mario Carneiro, 20-May-2013.)
 | 
           
                         
      
        
                                         
             | 
|   | 
| Theorem | dom3d 6833* | 
A mapping (first hypothesis) that is one-to-one (second hypothesis)
       implies its domain is dominated by its codomain.  (Contributed by Mario
       Carneiro, 20-May-2013.)
 | 
           
                         
      
        
                                                                                    | 
|   | 
| Theorem | dom2 6834* | 
A mapping (first hypothesis) that is one-to-one (second hypothesis)
       implies its domain is dominated by its codomain.   and   can be
       read      and     , as can be inferred from their
       distinct variable conditions.  (Contributed by NM, 26-Oct-2003.)
 | 
                                                 
      
                               | 
|   | 
| Theorem | dom3 6835* | 
A mapping (first hypothesis) that is one-to-one (second hypothesis)
       implies its domain is dominated by its codomain.   and   can be
       read      and     , as can be inferred from their
       distinct variable conditions.  (Contributed by Mario Carneiro,
       20-May-2013.)
 | 
                                                 
      
                                         | 
|   | 
| Theorem | idssen 6836 | 
Equality implies equinumerosity.  (Contributed by NM, 30-Apr-1998.)
       (Revised by Mario Carneiro, 15-Nov-2014.)
 | 
        | 
|   | 
| Theorem | ssdomg 6837 | 
A set dominates its subsets.  Theorem 16 of [Suppes] p. 94.  (Contributed
     by NM, 19-Jun-1998.)  (Revised by Mario Carneiro, 24-Jun-2015.)
 | 
                            | 
|   | 
| Theorem | ener 6838 | 
Equinumerosity is an equivalence relation.  (Contributed by NM,
       19-Mar-1998.)  (Revised by Mario Carneiro, 15-Nov-2014.)
 | 
     
   | 
|   | 
| Theorem | ensymb 6839 | 
Symmetry of equinumerosity.  Theorem 2 of [Suppes] p. 92.  (Contributed by
     Mario Carneiro, 26-Apr-2015.)
 | 
                  | 
|   | 
| Theorem | ensym 6840 | 
Symmetry of equinumerosity.  Theorem 2 of [Suppes] p. 92.  (Contributed by
     NM, 26-Oct-2003.)  (Revised by Mario Carneiro, 26-Apr-2015.)
 | 
                  | 
|   | 
| Theorem | ensymi 6841 | 
Symmetry of equinumerosity.  Theorem 2 of [Suppes] p. 92.  (Contributed
       by NM, 25-Sep-2004.)
 | 
                      | 
|   | 
| Theorem | ensymd 6842 | 
Symmetry of equinumerosity.  Deduction form of ensym 6840.  (Contributed
       by David Moews, 1-May-2017.)
 | 
                                  | 
|   | 
| Theorem | entr 6843 | 
Transitivity of equinumerosity.  Theorem 3 of [Suppes] p. 92.
       (Contributed by NM, 9-Jun-1998.)
 | 
                            | 
|   | 
| Theorem | domtr 6844 | 
Transitivity of dominance relation.  Theorem 17 of [Suppes] p. 94.
       (Contributed by NM, 4-Jun-1998.)  (Revised by Mario Carneiro,
       15-Nov-2014.)
 | 
                            | 
|   | 
| Theorem | entri 6845 | 
A chained equinumerosity inference.  (Contributed by NM,
       25-Sep-2004.)
 | 
                                    | 
|   | 
| Theorem | entr2i 6846 | 
A chained equinumerosity inference.  (Contributed by NM,
       25-Sep-2004.)
 | 
                                    | 
|   | 
| Theorem | entr3i 6847 | 
A chained equinumerosity inference.  (Contributed by NM,
       25-Sep-2004.)
 | 
                                    | 
|   | 
| Theorem | entr4i 6848 | 
A chained equinumerosity inference.  (Contributed by NM,
       25-Sep-2004.)
 | 
                                    | 
|   | 
| Theorem | endomtr 6849 | 
Transitivity of equinumerosity and dominance.  (Contributed by NM,
     7-Jun-1998.)
 | 
                            | 
|   | 
| Theorem | domentr 6850 | 
Transitivity of dominance and equinumerosity.  (Contributed by NM,
     7-Jun-1998.)
 | 
                            | 
|   | 
| Theorem | f1imaeng 6851 | 
A one-to-one function's image under a subset of its domain is equinumerous
     to the subset.  (Contributed by Mario Carneiro, 15-May-2015.)
 | 
         
                         
      | 
|   | 
| Theorem | f1imaen2g 6852 | 
A one-to-one function's image under a subset of its domain is equinumerous
     to the subset.  (This version of f1imaen 6853 does not need ax-setind 4573.)
     (Contributed by Mario Carneiro, 16-Nov-2014.)  (Revised by Mario Carneiro,
     25-Jun-2015.)
 | 
                
                        
            | 
|   | 
| Theorem | f1imaen 6853 | 
A one-to-one function's image under a subset of its domain is
       equinumerous to the subset.  (Contributed by NM, 30-Sep-2004.)
 | 
                                              | 
|   | 
| Theorem | en0 6854 | 
The empty set is equinumerous only to itself.  Exercise 1 of
       [TakeutiZaring] p. 88. 
(Contributed by NM, 27-May-1998.)
 | 
            
      | 
|   | 
| Theorem | ensn1 6855 | 
A singleton is equinumerous to ordinal one.  (Contributed by NM,
       4-Nov-2002.)
 | 
                        | 
|   | 
| Theorem | ensn1g 6856 | 
A singleton is equinumerous to ordinal one.  (Contributed by NM,
       23-Apr-2004.)
 | 
                    | 
|   | 
| Theorem | enpr1g 6857 | 
       has only
one element.  (Contributed by FL, 15-Feb-2010.)
 | 
                       | 
|   | 
| Theorem | en1 6858* | 
A set is equinumerous to ordinal one iff it is a singleton.
       (Contributed by NM, 25-Jul-2004.)
 | 
               
        | 
|   | 
| Theorem | en1bg 6859 | 
A set is equinumerous to ordinal one iff it is a singleton.
       (Contributed by Jim Kingdon, 13-Apr-2020.)
 | 
                               | 
|   | 
| Theorem | reuen1 6860* | 
Two ways to express "exactly one".  (Contributed by Stefan O'Rear,
       28-Oct-2014.)
 | 
           
                    | 
|   | 
| Theorem | euen1 6861 | 
Two ways to express "exactly one".  (Contributed by Stefan O'Rear,
       28-Oct-2014.)
 | 
             
         | 
|   | 
| Theorem | euen1b 6862* | 
Two ways to express "  has a unique element".  (Contributed by
       Mario Carneiro, 9-Apr-2015.)
 | 
               
      | 
|   | 
| Theorem | en1uniel 6863 | 
A singleton contains its sole element.  (Contributed by Stefan O'Rear,
     16-Aug-2015.)
 | 
                   | 
|   | 
| Theorem | 2dom 6864* | 
A set that dominates ordinal 2 has at least 2 different members.
       (Contributed by NM, 25-Jul-2004.)
 | 
                      
        
    | 
|   | 
| Theorem | fundmen 6865 | 
A function is equinumerous to its domain.  Exercise 4 of [Suppes] p. 98.
       (Contributed by NM, 28-Jul-2004.)  (Revised by Mario Carneiro,
       15-Nov-2014.)
 | 
                                | 
|   | 
| Theorem | fundmeng 6866 | 
A function is equinumerous to its domain.  Exercise 4 of [Suppes] p. 98.
       (Contributed by NM, 17-Sep-2013.)
 | 
             
               | 
|   | 
| Theorem | cnven 6867 | 
A relational set is equinumerous to its converse.  (Contributed by Mario
       Carneiro, 28-Dec-2014.)
 | 
                           | 
|   | 
| Theorem | cnvct 6868 | 
If a set is dominated by  , so is its converse.  (Contributed by
     Thierry Arnoux, 29-Dec-2016.)
 | 
                   | 
|   | 
| Theorem | fndmeng 6869 | 
A function is equinumerate to its domain.  (Contributed by Paul Chapman,
     22-Jun-2011.)
 | 
                            | 
|   | 
| Theorem | mapsnen 6870 | 
Set exponentiation to a singleton exponent is equinumerous to its base.
       Exercise 4.43 of [Mendelson] p. 255. 
(Contributed by NM, 17-Dec-2003.)
       (Revised by Mario Carneiro, 15-Nov-2014.)
 | 
                                            | 
|   | 
| Theorem | map1 6871 | 
Set exponentiation: ordinal 1 to any set is equinumerous to ordinal 1.
       Exercise 4.42(b) of [Mendelson] p.
255.  (Contributed by NM,
       17-Dec-2003.)
 | 
                        | 
|   | 
| Theorem | en2sn 6872 | 
Two singletons are equinumerous.  (Contributed by NM, 9-Nov-2003.)
 | 
                                | 
|   | 
| Theorem | snfig 6873 | 
A singleton is finite.  For the proper class case, see snprc 3687.
       (Contributed by Jim Kingdon, 13-Apr-2020.)
 | 
                    | 
|   | 
| Theorem | fiprc 6874 | 
The class of finite sets is a proper class.  (Contributed by Jeff
       Hankins, 3-Oct-2008.)
 | 
        | 
|   | 
| Theorem | unen 6875 | 
Equinumerosity of union of disjoint sets.  Theorem 4 of [Suppes] p. 92.
       (Contributed by NM, 11-Jun-1998.)  (Revised by Mario Carneiro,
       26-Apr-2015.)
 | 
                                
                                 
       | 
|   | 
| Theorem | enpr2d 6876 | 
A pair with distinct elements is equinumerous to ordinal two.
       (Contributed by Rohan Ridenour, 3-Aug-2023.)
 | 
                                                
                                 | 
|   | 
| Theorem | ssct 6877 | 
A subset of a set dominated by   is dominated by  .
     (Contributed by Thierry Arnoux, 31-Jan-2017.)
 | 
                            | 
|   | 
| Theorem | 1domsn 6878 | 
A singleton (whether of a set or a proper class) is dominated by one.
       (Contributed by Jim Kingdon, 1-Mar-2022.)
 | 
          | 
|   | 
| Theorem | enm 6879* | 
A set equinumerous to an inhabited set is inhabited.  (Contributed by
       Jim Kingdon, 19-May-2020.)
 | 
                          
        | 
|   | 
| Theorem | xpsnen 6880 | 
A set is equinumerous to its Cartesian product with a singleton.
       Proposition 4.22(c) of [Mendelson] p.
254.  (Contributed by NM,
       4-Jan-2004.)  (Revised by Mario Carneiro, 15-Nov-2014.)
 | 
                                            | 
|   | 
| Theorem | xpsneng 6881 | 
A set is equinumerous to its Cartesian product with a singleton.
       Proposition 4.22(c) of [Mendelson] p.
254.  (Contributed by NM,
       22-Oct-2004.)
 | 
                                    | 
|   | 
| Theorem | xp1en 6882 | 
One times a cardinal number.  (Contributed by NM, 27-Sep-2004.)  (Revised
     by Mario Carneiro, 29-Apr-2015.)
 | 
                        | 
|   | 
| Theorem | endisj 6883* | 
Any two sets are equinumerous to disjoint sets.  Exercise 4.39 of
       [Mendelson] p. 255.  (Contributed by
NM, 16-Apr-2004.)
 | 
                                                            
      | 
|   | 
| Theorem | xpcomf1o 6884* | 
The canonical bijection from         to        .
       (Contributed by Mario Carneiro, 23-Apr-2014.)
 | 
                  
                                    | 
|   | 
| Theorem | xpcomco 6885* | 
Composition with the bijection of xpcomf1o 6884 swaps the arguments to a
       mapping.  (Contributed by Mario Carneiro, 30-May-2015.)
 | 
                  
                               
                           
                    | 
|   | 
| Theorem | xpcomen 6886 | 
Commutative law for equinumerosity of Cartesian product.  Proposition
       4.22(d) of [Mendelson] p. 254. 
(Contributed by NM, 5-Jan-2004.)
       (Revised by Mario Carneiro, 15-Nov-2014.)
 | 
                                                | 
|   | 
| Theorem | xpcomeng 6887 | 
Commutative law for equinumerosity of Cartesian product.  Proposition
       4.22(d) of [Mendelson] p. 254. 
(Contributed by NM, 27-Mar-2006.)
 | 
                            
            | 
|   | 
| Theorem | xpsnen2g 6888 | 
A set is equinumerous to its Cartesian product with a singleton on the
     left.  (Contributed by Stefan O'Rear, 21-Nov-2014.)
 | 
                                    | 
|   | 
| Theorem | xpassen 6889 | 
Associative law for equinumerosity of Cartesian product.  Proposition
       4.22(e) of [Mendelson] p. 254. 
(Contributed by NM, 22-Jan-2004.)
       (Revised by Mario Carneiro, 15-Nov-2014.)
 | 
                                                              
            | 
|   | 
| Theorem | xpdom2 6890 | 
Dominance law for Cartesian product.  Proposition 10.33(2) of
       [TakeutiZaring] p. 92. 
(Contributed by NM, 24-Jul-2004.)  (Revised by
       Mario Carneiro, 15-Nov-2014.)
 | 
                                            | 
|   | 
| Theorem | xpdom2g 6891 | 
Dominance law for Cartesian product.  Theorem 6L(c) of [Enderton]
       p. 149.  (Contributed by Mario Carneiro, 26-Apr-2015.)
 | 
                                        | 
|   | 
| Theorem | xpdom1g 6892 | 
Dominance law for Cartesian product.  Theorem 6L(c) of [Enderton]
       p. 149.  (Contributed by NM, 25-Mar-2006.)  (Revised by Mario Carneiro,
       26-Apr-2015.)
 | 
                                        | 
|   | 
| Theorem | xpdom3m 6893* | 
A set is dominated by its Cartesian product with an inhabited set.
       Exercise 6 of [Suppes] p. 98. 
(Contributed by Jim Kingdon,
       15-Apr-2020.)
 | 
                                      
       | 
|   | 
| Theorem | xpdom1 6894 | 
Dominance law for Cartesian product.  Theorem 6L(c) of [Enderton]
       p. 149.  (Contributed by NM, 28-Sep-2004.)  (Revised by NM,
       29-Mar-2006.)  (Revised by Mario Carneiro, 7-May-2015.)
 | 
                                            | 
|   | 
| Theorem | pw2f1odclem 6895* | 
Lemma for pw2f1odc 6896.  (Contributed by Mario Carneiro,
6-Oct-2014.)
 | 
                                                                                                  
    DECID                                                                                       
             | 
|   | 
| Theorem | pw2f1odc 6896* | 
The power set of a set is equinumerous to set exponentiation with an
       unordered pair base of ordinal 2.  Generalized from Proposition 10.44 of
       [TakeutiZaring] p. 96. 
(Contributed by Mario Carneiro, 6-Oct-2014.)
 | 
                                                                                                  
    DECID                                
                                                 
       | 
|   | 
| Theorem | fopwdom 6897 | 
Covering implies injection on power sets.  (Contributed by Stefan
       O'Rear, 6-Nov-2014.)  (Revised by Mario Carneiro, 24-Jun-2015.)
 | 
                  
            | 
|   | 
| Theorem | 0domg 6898 | 
Any set dominates the empty set.  (Contributed by NM, 26-Oct-2003.)
     (Revised by Mario Carneiro, 26-Apr-2015.)
 | 
                  | 
|   | 
| Theorem | dom0 6899 | 
A set dominated by the empty set is empty.  (Contributed by NM,
       22-Nov-2004.)
 | 
            
      | 
|   | 
| Theorem | 0dom 6900 | 
Any set dominates the empty set.  (Contributed by NM, 26-Oct-2003.)
       (Revised by Mario Carneiro, 26-Apr-2015.)
 | 
                      |