P. 130 of Theorem List - Intuitionistic Logic Explorer

Theorem List for Intuitionistic Logic Explorer - 12901-13000   *Has distinct variable group(s)

Type	Label	Description
Statement
Theorem	pcxnn0cl 12901	Extended nonnegative integer closure of the general prime count function. (Contributed by Jim Kingdon, 13-Oct-2024.)
|- ( ( P e. Prime /\ N e. ZZ ) -> ( P pCnt N ) e. NN0* )
Theorem	pcxcl 12902	Extended real closure of the general prime count function. (Contributed by Mario Carneiro, 3-Oct-2014.)
|- ( ( P e. Prime /\ N e. QQ ) -> ( P pCnt N ) e. RR* )
Theorem	pcxqcl 12903	The general prime count function is an integer or infinite. (Contributed by Jim Kingdon, 6-Jun-2025.)
|- ( ( P e. Prime /\ N e. QQ ) -> ( ( P pCnt N ) e. ZZ \/ ( P pCnt N ) = +oo ) )
Theorem	pcge0 12904	The prime count of an integer is greater than or equal to zero. (Contributed by Mario Carneiro, 3-Oct-2014.)
|- ( ( P e. Prime /\ N e. ZZ ) -> 0 <_ ( P pCnt N ) )
Theorem	pczdvds 12905	Defining property of the prime count function. (Contributed by Mario Carneiro, 9-Sep-2014.)
|- ( ( P e. Prime /\ ( N e. ZZ /\ N =/= 0 ) ) -> ( P ^ ( P pCnt N ) ) || N )
Theorem	pcdvds 12906	Defining property of the prime count function. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( ( P e. Prime /\ N e. NN ) -> ( P ^ ( P pCnt N ) ) || N )
Theorem	pczndvds 12907	Defining property of the prime count function. (Contributed by Mario Carneiro, 3-Oct-2014.)
|- ( ( P e. Prime /\ ( N e. ZZ /\ N =/= 0 ) ) -> -. ( P ^ ( ( P pCnt N ) + 1 ) ) || N )
Theorem	pcndvds 12908	Defining property of the prime count function. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( ( P e. Prime /\ N e. NN ) -> -. ( P ^ ( ( P pCnt N ) + 1 ) ) || N )
Theorem	pczndvds2 12909	The remainder after dividing out all factors of P is not divisible by P. (Contributed by Mario Carneiro, 9-Sep-2014.)
|- ( ( P e. Prime /\ ( N e. ZZ /\ N =/= 0 ) ) -> -. P || ( N / ( P ^ ( P pCnt N ) ) ) )
Theorem	pcndvds2 12910	The remainder after dividing out all factors of P is not divisible by P. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( ( P e. Prime /\ N e. NN ) -> -. P || ( N / ( P ^ ( P pCnt N ) ) ) )
Theorem	pcdvdsb 12911	P ^ A divides N if and only if A is at most the count of P. (Contributed by Mario Carneiro, 3-Oct-2014.)
|- ( ( P e. Prime /\ N e. ZZ /\ A e. NN0 ) -> ( A <_ ( P pCnt N ) <-> ( P ^ A ) || N ) )
Theorem	pcelnn 12912	There are a positive number of powers of a prime P in N iff P divides N. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( ( P e. Prime /\ N e. NN ) -> ( ( P pCnt N ) e. NN <-> P || N ) )
Theorem	pceq0 12913	There are zero powers of a prime P in N iff P does not divide N. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( ( P e. Prime /\ N e. NN ) -> ( ( P pCnt N ) = 0 <-> -. P || N ) )
Theorem	pcidlem 12914	The prime count of a prime power. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- ( ( P e. Prime /\ A e. NN0 ) -> ( P pCnt ( P ^ A ) ) = A )
Theorem	pcid 12915	The prime count of a prime power. (Contributed by Mario Carneiro, 9-Sep-2014.)
|- ( ( P e. Prime /\ A e. ZZ ) -> ( P pCnt ( P ^ A ) ) = A )
Theorem	pcneg 12916	The prime count of a negative number. (Contributed by Mario Carneiro, 13-Mar-2014.)
|- ( ( P e. Prime /\ A e. QQ ) -> ( P pCnt -u A ) = ( P pCnt A ) )
Theorem	pcabs 12917	The prime count of an absolute value. (Contributed by Mario Carneiro, 13-Mar-2014.)
|- ( ( P e. Prime /\ A e. QQ ) -> ( P pCnt ( abs ` A ) ) = ( P pCnt A ) )
Theorem	pcdvdstr 12918	The prime count increases under the divisibility relation. (Contributed by Mario Carneiro, 13-Mar-2014.)
|- ( ( P e. Prime /\ ( A e. ZZ /\ B e. ZZ /\ A || B ) ) -> ( P pCnt A ) <_ ( P pCnt B ) )
Theorem	pcgcd1 12919	The prime count of a GCD is the minimum of the prime counts of the arguments. (Contributed by Mario Carneiro, 3-Oct-2014.)
|- ( ( ( P e. Prime /\ A e. ZZ /\ B e. ZZ ) /\ ( P pCnt A ) <_ ( P pCnt B ) ) -> ( P pCnt ( A gcd B ) ) = ( P pCnt A ) )
Theorem	pcgcd 12920	The prime count of a GCD is the minimum of the prime counts of the arguments. (Contributed by Mario Carneiro, 3-Oct-2014.)
|- ( ( P e. Prime /\ A e. ZZ /\ B e. ZZ ) -> ( P pCnt ( A gcd B ) ) = if ( ( P pCnt A ) <_ ( P pCnt B ) , ( P pCnt A ) , ( P pCnt B ) ) )
Theorem	pc2dvds 12921*	A characterization of divisibility in terms of prime count. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by Mario Carneiro, 3-Oct-2014.)
|- ( ( A e. ZZ /\ B e. ZZ ) -> ( A || B <-> A. p e. Prime ( p pCnt A ) <_ ( p pCnt B ) ) )
Theorem	pc11 12922*	The prime count function, viewed as a function from NN to ( NN ^m Prime ), is one-to-one. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( ( A e. NN0 /\ B e. NN0 ) -> ( A = B <-> A. p e. Prime ( p pCnt A ) = ( p pCnt B ) ) )
Theorem	pcz 12923*	The prime count function can be used as an indicator that a given rational number is an integer. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( A e. QQ -> ( A e. ZZ <-> A. p e. Prime 0 <_ ( p pCnt A ) ) )
Theorem	pcprmpw2 12924*	Self-referential expression for a prime power. (Contributed by Mario Carneiro, 16-Jan-2015.)
|- ( ( P e. Prime /\ A e. NN ) -> ( E. n e. NN0 A || ( P ^ n ) <-> A = ( P ^ ( P pCnt A ) ) ) )
Theorem	pcprmpw 12925*	Self-referential expression for a prime power. (Contributed by Mario Carneiro, 16-Jan-2015.)
|- ( ( P e. Prime /\ A e. NN ) -> ( E. n e. NN0 A = ( P ^ n ) <-> A = ( P ^ ( P pCnt A ) ) ) )
Theorem	dvdsprmpweq 12926*	If a positive integer divides a prime power, it is a prime power. (Contributed by AV, 25-Jul-2021.)
|- ( ( P e. Prime /\ A e. NN /\ N e. NN0 ) -> ( A || ( P ^ N ) -> E. n e. NN0 A = ( P ^ n ) ) )
Theorem	dvdsprmpweqnn 12927*	If an integer greater than 1 divides a prime power, it is a (proper) prime power. (Contributed by AV, 13-Aug-2021.)
|- ( ( P e. Prime /\ A e. ( ZZ>= ` 2 ) /\ N e. NN0 ) -> ( A || ( P ^ N ) -> E. n e. NN A = ( P ^ n ) ) )
Theorem	dvdsprmpweqle 12928*	If a positive integer divides a prime power, it is a prime power with a smaller exponent. (Contributed by AV, 25-Jul-2021.)
|- ( ( P e. Prime /\ A e. NN /\ N e. NN0 ) -> ( A || ( P ^ N ) -> E. n e. NN0 ( n <_ N /\ A = ( P ^ n ) ) ) )
Theorem	difsqpwdvds 12929	If the difference of two squares is a power of a prime, the prime divides twice the second squared number. (Contributed by AV, 13-Aug-2021.)
|- ( ( ( A e. NN0 /\ B e. NN0 /\ ( B + 1 ) < A ) /\ ( C e. Prime /\ D e. NN0 ) ) -> ( ( C ^ D ) = ( ( A ^ 2 ) - ( B ^ 2 ) ) -> C || ( 2 x. B ) ) )
Theorem	pcaddlem 12930	Lemma for pcadd 12931. The original numbers A and B have been decomposed using the prime count function as ( P ^ M ) x. ( R / S ) where R , S are both not divisible by P and M = ( P pCnt A ), and similarly for B. (Contributed by Mario Carneiro, 9-Sep-2014.)
|- ( ph -> P e. Prime )   &    |- ( ph -> A = ( ( P ^ M ) x. ( R / S ) ) )   &    |- ( ph -> B = ( ( P ^ N ) x. ( T / U ) ) )   &    |- ( ph -> N e. ( ZZ>= ` M ) )   &    |- ( ph -> ( R e. ZZ /\ -. P || R ) )   &    |- ( ph -> ( S e. NN /\ -. P || S ) )   &    |- ( ph -> ( T e. ZZ /\ -. P || T ) )   &    |- ( ph -> ( U e. NN /\ -. P || U ) )   =>    |- ( ph -> M <_ ( P pCnt ( A + B ) ) )
Theorem	pcadd 12931	An inequality for the prime count of a sum. This is the source of the ultrametric inequality for the p-adic metric. (Contributed by Mario Carneiro, 9-Sep-2014.)
|- ( ph -> P e. Prime )   &    |- ( ph -> A e. QQ )   &    |- ( ph -> B e. QQ )   &    |- ( ph -> ( P pCnt A ) <_ ( P pCnt B ) )   =>    |- ( ph -> ( P pCnt A ) <_ ( P pCnt ( A + B ) ) )
Theorem	pcadd2 12932	The inequality of pcadd 12931 becomes an equality when one of the factors has prime count strictly less than the other. (Contributed by Mario Carneiro, 16-Jan-2015.) (Revised by Mario Carneiro, 26-Jun-2015.)
|- ( ph -> P e. Prime )   &    |- ( ph -> A e. QQ )   &    |- ( ph -> B e. QQ )   &    |- ( ph -> ( P pCnt A ) < ( P pCnt B ) )   =>    |- ( ph -> ( P pCnt A ) = ( P pCnt ( A + B ) ) )
Theorem	pcmptcl 12933	Closure for the prime power map. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ A ) , 1 ) )   &    |- ( ph -> A. n e. Prime A e. NN0 )   =>    |- ( ph -> ( F : NN --> NN /\ seq 1 ( x. , F ) : NN --> NN ) )
Theorem	pcmpt 12934*	Construct a function with given prime count characteristics. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ A ) , 1 ) )   &    |- ( ph -> A. n e. Prime A e. NN0 )   &    |- ( ph -> N e. NN )   &    |- ( ph -> P e. Prime )   &    |- ( n = P -> A = B )   =>    |- ( ph -> ( P pCnt ( seq 1 ( x. , F ) ` N ) ) = if ( P <_ N , B , 0 ) )
Theorem	pcmpt2 12935*	Dividing two prime count maps yields a number with all dividing primes confined to an interval. (Contributed by Mario Carneiro, 14-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ A ) , 1 ) )   &    |- ( ph -> A. n e. Prime A e. NN0 )   &    |- ( ph -> N e. NN )   &    |- ( ph -> P e. Prime )   &    |- ( n = P -> A = B )   &    |- ( ph -> M e. ( ZZ>= ` N ) )   =>    |- ( ph -> ( P pCnt ( ( seq 1 ( x. , F ) ` M ) / ( seq 1 ( x. , F ) ` N ) ) ) = if ( ( P <_ M /\ -. P <_ N ) , B , 0 ) )
Theorem	pcmptdvds 12936	The partial products of the prime power map form a divisibility chain. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ A ) , 1 ) )   &    |- ( ph -> A. n e. Prime A e. NN0 )   &    |- ( ph -> N e. NN )   &    |- ( ph -> M e. ( ZZ>= ` N ) )   =>    |- ( ph -> ( seq 1 ( x. , F ) ` N ) || ( seq 1 ( x. , F ) ` M ) )
Theorem	pcprod 12937*	The product of the primes taken to their respective powers reconstructs the original number. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ ( n pCnt N ) ) , 1 ) )   =>    |- ( N e. NN -> ( seq 1 ( x. , F ) ` N ) = N )
Theorem	sumhashdc 12938*	The sum of 1 over a set is the size of the set. (Contributed by Mario Carneiro, 8-Mar-2014.) (Revised by Mario Carneiro, 20-May-2014.)
|- ( ( B e. Fin /\ A C_ B /\ A. x e. B DECID x e. A ) -> sum_ k e. B if ( k e. A , 1 , 0 ) = (♯ ` A ) )
Theorem	fldivp1 12939	The difference between the floors of adjacent fractions is either 1 or 0. (Contributed by Mario Carneiro, 8-Mar-2014.)
|- ( ( M e. ZZ /\ N e. NN ) -> ( ( |_ ` ( ( M + 1 ) / N ) ) - ( |_ ` ( M / N ) ) ) = if ( N || ( M + 1 ) , 1 , 0 ) )
Theorem	pcfaclem 12940	Lemma for pcfac 12941. (Contributed by Mario Carneiro, 20-May-2014.)
|- ( ( N e. NN0 /\ M e. ( ZZ>= ` N ) /\ P e. Prime ) -> ( |_ ` ( N / ( P ^ M ) ) ) = 0 )
Theorem	pcfac 12941*	Calculate the prime count of a factorial. (Contributed by Mario Carneiro, 11-Mar-2014.) (Revised by Mario Carneiro, 21-May-2014.)
|- ( ( N e. NN0 /\ M e. ( ZZ>= ` N ) /\ P e. Prime ) -> ( P pCnt ( ! ` N ) ) = sum_ k e. ( 1 ... M ) ( |_ ` ( N / ( P ^ k ) ) ) )
Theorem	pcbc 12942*	Calculate the prime count of a binomial coefficient. (Contributed by Mario Carneiro, 11-Mar-2014.) (Revised by Mario Carneiro, 21-May-2014.)
|- ( ( N e. NN /\ K e. ( 0 ... N ) /\ P e. Prime ) -> ( P pCnt ( N _C K ) ) = sum_ k e. ( 1 ... N ) ( ( |_ ` ( N / ( P ^ k ) ) ) - ( ( |_ ` ( ( N - K ) / ( P ^ k ) ) ) + ( |_ ` ( K / ( P ^ k ) ) ) ) ) )
Theorem	qexpz 12943	If a power of a rational number is an integer, then the number is an integer. (Contributed by Mario Carneiro, 10-Aug-2015.)
|- ( ( A e. QQ /\ N e. NN /\ ( A ^ N ) e. ZZ ) -> A e. ZZ )
Theorem	expnprm 12944	A second or higher power of a rational number is not a prime number. Or by contraposition, the n-th root of a prime number is not rational. Suggested by Norm Megill. (Contributed by Mario Carneiro, 10-Aug-2015.)
|- ( ( A e. QQ /\ N e. ( ZZ>= ` 2 ) ) -> -. ( A ^ N ) e. Prime )
Theorem	oddprmdvds 12945*	Every positive integer which is not a power of two is divisible by an odd prime number. (Contributed by AV, 6-Aug-2021.)
|- ( ( K e. NN /\ -. E. n e. NN0 K = ( 2 ^ n ) ) -> E. p e. ( Prime \ { 2 } ) p || K )
5.2.9  Pocklington's theorem
Theorem	prmpwdvds 12946	A relation involving divisibility by a prime power. (Contributed by Mario Carneiro, 2-Mar-2014.)
|- ( ( ( K e. ZZ /\ D e. ZZ ) /\ ( P e. Prime /\ N e. NN ) /\ ( D || ( K x. ( P ^ N ) ) /\ -. D || ( K x. ( P ^ ( N - 1 ) ) ) ) ) -> ( P ^ N ) || D )
Theorem	pockthlem 12947	Lemma for pockthg 12948. (Contributed by Mario Carneiro, 2-Mar-2014.)
|- ( ph -> A e. NN )   &    |- ( ph -> B e. NN )   &    |- ( ph -> B < A )   &    |- ( ph -> N = ( ( A x. B ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> P || N )   &    |- ( ph -> Q e. Prime )   &    |- ( ph -> ( Q pCnt A ) e. NN )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> ( ( C ^ ( N - 1 ) ) mod N ) = 1 )   &    |- ( ph -> ( ( ( C ^ ( ( N - 1 ) / Q ) ) - 1 ) gcd N ) = 1 )   =>    |- ( ph -> ( Q pCnt A ) <_ ( Q pCnt ( P - 1 ) ) )
Theorem	pockthg 12948*	The generalized Pocklington's theorem. If N - 1 = A x. B where B < A, then N is prime if and only if for every prime factor p of A, there is an x such that x ^ ( N - 1 ) = 1 ( mod N ) and gcd ( x ^ ( ( N - 1 ) / p ) - 1 , N ) = 1. (Contributed by Mario Carneiro, 2-Mar-2014.)
|- ( ph -> A e. NN )   &    |- ( ph -> B e. NN )   &    |- ( ph -> B < A )   &    |- ( ph -> N = ( ( A x. B ) + 1 ) )   &    |- ( ph -> A. p e. Prime ( p || A -> E. x e. ZZ ( ( ( x ^ ( N - 1 ) ) mod N ) = 1 /\ ( ( ( x ^ ( ( N - 1 ) / p ) ) - 1 ) gcd N ) = 1 ) ) )   =>    |- ( ph -> N e. Prime )
Theorem	pockthi 12949	Pocklington's theorem, which gives a sufficient criterion for a number N to be prime. This is the preferred method for verifying large primes, being much more efficient to compute than trial division. This form has been optimized for application to specific large primes; see pockthg 12948 for a more general closed-form version. (Contributed by Mario Carneiro, 2-Mar-2014.)
|- P e. Prime   &    |- G e. NN   &    |- M = ( G x. P )   &    |- N = ( M + 1 )   &    |- D e. NN   &    |- E e. NN   &    |- A e. NN   &    |- M = ( D x. ( P ^ E ) )   &    |- D < ( P ^ E )   &    |- ( ( A ^ M ) mod N ) = ( 1 mod N )   &    |- ( ( ( A ^ G ) - 1 ) gcd N ) = 1   =>    |- N e. Prime
5.2.10  Infinite primes theorem
Theorem	infpnlem1 12950*	Lemma for infpn 12952. The smallest divisor (greater than 1) M of N ! + 1 is a prime greater than N. (Contributed by NM, 5-May-2005.)
|- K = ( ( ! ` N ) + 1 )   =>    |- ( ( N e. NN /\ M e. NN ) -> ( ( ( 1 < M /\ ( K / M ) e. NN ) /\ A. j e. NN ( ( 1 < j /\ ( K / j ) e. NN ) -> M <_ j ) ) -> ( N < M /\ A. j e. NN ( ( M / j ) e. NN -> ( j = 1 \/ j = M ) ) ) ) )
Theorem	infpnlem2 12951*	Lemma for infpn 12952. For any positive integer N, there exists a prime number j greater than N. (Contributed by NM, 5-May-2005.)
|- K = ( ( ! ` N ) + 1 )   =>    |- ( N e. NN -> E. j e. NN ( N < j /\ A. k e. NN ( ( j / k ) e. NN -> ( k = 1 \/ k = j ) ) ) )
Theorem	infpn 12952*	There exist infinitely many prime numbers: for any positive integer N, there exists a prime number j greater than N. (See infpn2 13095 for the equinumerosity version.) (Contributed by NM, 1-Jun-2006.)
|- ( N e. NN -> E. j e. NN ( N < j /\ A. k e. NN ( ( j / k ) e. NN -> ( k = 1 \/ k = j ) ) ) )
Theorem	prmunb 12953*	The primes are unbounded. (Contributed by Paul Chapman, 28-Nov-2012.)
|- ( N e. NN -> E. p e. Prime N < p )
5.2.11  Fundamental theorem of arithmetic
Theorem	1arithlem1 12954*	Lemma for 1arith 12958. (Contributed by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   =>    |- ( N e. NN -> ( M ` N ) = ( p e. Prime |-> ( p pCnt N ) ) )
Theorem	1arithlem2 12955*	Lemma for 1arith 12958. (Contributed by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   =>    |- ( ( N e. NN /\ P e. Prime ) -> ( ( M ` N ) ` P ) = ( P pCnt N ) )
Theorem	1arithlem3 12956*	Lemma for 1arith 12958. (Contributed by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   =>    |- ( N e. NN -> ( M ` N ) : Prime --> NN0 )
Theorem	1arithlem4 12957*	Lemma for 1arith 12958. (Contributed by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   &    |- G = ( y e. NN |-> if ( y e. Prime , ( y ^ ( F ` y ) ) , 1 ) )   &    |- ( ph -> F : Prime --> NN0 )   &    |- ( ph -> N e. NN )   &    |- ( ( ph /\ ( q e. Prime /\ N <_ q ) ) -> ( F ` q ) = 0 )   =>    |- ( ph -> E. x e. NN F = ( M ` x ) )
Theorem	1arith 12958*	Fundamental theorem of arithmetic, where a prime factorization is represented as a sequence of prime exponents, for which only finitely many primes have nonzero exponent. The function M maps the set of positive integers one-to-one onto the set of prime factorizations R. (Contributed by Paul Chapman, 17-Nov-2012.) (Proof shortened by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   &    |- R = { e e. ( NN0 ^m Prime ) | ( `' e " NN ) e. Fin }   =>    |- M : NN -1-1-onto-> R
Theorem	1arith2 12959*	Fundamental theorem of arithmetic, where a prime factorization is represented as a finite monotonic 1-based sequence of primes. Every positive integer has a unique prime factorization. Theorem 1.10 in [ApostolNT] p. 17. This is Metamath 100 proof #80. (Contributed by Paul Chapman, 17-Nov-2012.) (Revised by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   &    |- R = { e e. ( NN0 ^m Prime ) | ( `' e " NN ) e. Fin }   =>    |- A. z e. NN E! g e. R ( M ` z ) = g
5.2.12  Lagrange's four-square theorem
Syntax	cgz 12960	Extend class notation with the set of gaussian integers.
class ZZ[_i]
Definition	df-gz 12961	Define the set of gaussian integers, which are complex numbers whose real and imaginary parts are integers. (Note that the [ _i ] is actually part of the symbol token and has no independent meaning.) (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ZZ[_i] = { x e. CC | ( ( Re ` x ) e. ZZ /\ ( Im ` x ) e. ZZ ) }
Theorem	elgz 12962	Elementhood in the gaussian integers. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ[_i] <-> ( A e. CC /\ ( Re ` A ) e. ZZ /\ ( Im ` A ) e. ZZ ) )
Theorem	gzcn 12963	A gaussian integer is a complex number. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ[_i] -> A e. CC )
Theorem	zgz 12964	An integer is a gaussian integer. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ -> A e. ZZ[_i] )
Theorem	igz 12965	_i is a gaussian integer. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- _i e. ZZ[_i]
Theorem	gznegcl 12966	The gaussian integers are closed under negation. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ[_i] -> -u A e. ZZ[_i] )
Theorem	gzcjcl 12967	The gaussian integers are closed under conjugation. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ[_i] -> ( * ` A ) e. ZZ[_i] )
Theorem	gzaddcl 12968	The gaussian integers are closed under addition. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( ( A e. ZZ[_i] /\ B e. ZZ[_i] ) -> ( A + B ) e. ZZ[_i] )
Theorem	gzmulcl 12969	The gaussian integers are closed under multiplication. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( ( A e. ZZ[_i] /\ B e. ZZ[_i] ) -> ( A x. B ) e. ZZ[_i] )
Theorem	gzreim 12970	Construct a gaussian integer from real and imaginary parts. (Contributed by Mario Carneiro, 16-Jul-2014.)
|- ( ( A e. ZZ /\ B e. ZZ ) -> ( A + ( _i x. B ) ) e. ZZ[_i] )
Theorem	gzsubcl 12971	The gaussian integers are closed under subtraction. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( ( A e. ZZ[_i] /\ B e. ZZ[_i] ) -> ( A - B ) e. ZZ[_i] )
Theorem	gzabssqcl 12972	The squared norm of a gaussian integer is an integer. (Contributed by Mario Carneiro, 16-Jul-2014.)
|- ( A e. ZZ[_i] -> ( ( abs ` A ) ^ 2 ) e. NN0 )
Theorem	4sqlem5 12973	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   =>    |- ( ph -> ( B e. ZZ /\ ( ( A - B ) / M ) e. ZZ ) )
Theorem	4sqlem6 12974	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   =>    |- ( ph -> ( -u ( M / 2 ) <_ B /\ B < ( M / 2 ) ) )
Theorem	4sqlem7 12975	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   =>    |- ( ph -> ( B ^ 2 ) <_ ( ( ( M ^ 2 ) / 2 ) / 2 ) )
Theorem	4sqlem8 12976	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   =>    |- ( ph -> M || ( ( A ^ 2 ) - ( B ^ 2 ) ) )
Theorem	4sqlem9 12977	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- ( ( ph /\ ps ) -> ( B ^ 2 ) = 0 )   =>    |- ( ( ph /\ ps ) -> ( M ^ 2 ) || ( A ^ 2 ) )
Theorem	4sqlem10 12978	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 16-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- ( ( ph /\ ps ) -> ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( B ^ 2 ) ) = 0 )   =>    |- ( ( ph /\ ps ) -> ( M ^ 2 ) || ( ( A ^ 2 ) - ( ( ( M ^ 2 ) / 2 ) / 2 ) ) )
Theorem	4sqlem1 12979*	Lemma for 4sq 13001. The set S is the set of all numbers that are expressible as a sum of four squares. Our goal is to show that S = NN0; here we show one subset direction. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- S C_ NN0
Theorem	4sqlem2 12980*	Lemma for 4sq 13001. Change bound variables in S. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( A e. S <-> E. a e. ZZ E. b e. ZZ E. c e. ZZ E. d e. ZZ A = ( ( ( a ^ 2 ) + ( b ^ 2 ) ) + ( ( c ^ 2 ) + ( d ^ 2 ) ) ) )
Theorem	4sqlem3 12981*	Lemma for 4sq 13001. Sufficient condition to be in S. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( ( ( A e. ZZ /\ B e. ZZ ) /\ ( C e. ZZ /\ D e. ZZ ) ) -> ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) e. S )
Theorem	4sqlem4a 12982*	Lemma for 4sqlem4 12983. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( ( A e. ZZ[_i] /\ B e. ZZ[_i] ) -> ( ( ( abs ` A ) ^ 2 ) + ( ( abs ` B ) ^ 2 ) ) e. S )
Theorem	4sqlem4 12983*	Lemma for 4sq 13001. We can express the four-square property more compactly in terms of gaussian integers, because the norms of gaussian integers are exactly sums of two squares. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( A e. S <-> E. u e. ZZ[_i] E. v e. ZZ[_i] A = ( ( ( abs ` u ) ^ 2 ) + ( ( abs ` v ) ^ 2 ) ) )
Theorem	mul4sqlem 12984*	Lemma for mul4sq 12985: algebraic manipulations. The extra assumptions involving M would let us know not just that the product is a sum of squares, but also that it preserves divisibility by M. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> A e. ZZ[_i] )   &    |- ( ph -> B e. ZZ[_i] )   &    |- ( ph -> C e. ZZ[_i] )   &    |- ( ph -> D e. ZZ[_i] )   &    |- X = ( ( ( abs ` A ) ^ 2 ) + ( ( abs ` B ) ^ 2 ) )   &    |- Y = ( ( ( abs ` C ) ^ 2 ) + ( ( abs ` D ) ^ 2 ) )   &    |- ( ph -> M e. NN )   &    |- ( ph -> ( ( A - C ) / M ) e. ZZ[_i] )   &    |- ( ph -> ( ( B - D ) / M ) e. ZZ[_i] )   &    |- ( ph -> ( X / M ) e. NN0 )   =>    |- ( ph -> ( ( X / M ) x. ( Y / M ) ) e. S )
Theorem	mul4sq 12985*	Euler's four-square identity: The product of two sums of four squares is also a sum of four squares. This is usually quoted as an explicit formula involving eight real variables; we save some time by working with complex numbers (gaussian integers) instead, so that we only have to work with four variables, and also hiding the actual formula for the product in the proof of mul4sqlem 12984. (For the curious, the explicit formula that is used is ( | a | ^ 2 + | b | ^ 2 ) ( | c | ^ 2 + | d | ^ 2 ) = | a * x. c + b x. d * | ^ 2 + | a * x. d - b x. c * | ^ 2.) (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( ( A e. S /\ B e. S ) -> ( A x. B ) e. S )
Theorem	4sqlemafi 12986*	Lemma for 4sq 13001. A is finite. (Contributed by Jim Kingdon, 24-May-2025.)
|- ( ph -> N e. NN )   &    |- ( ph -> P e. NN )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   =>    |- ( ph -> A e. Fin )
Theorem	4sqlemffi 12987*	Lemma for 4sq 13001. ran F is finite. (Contributed by Jim Kingdon, 24-May-2025.)
|- ( ph -> N e. NN )   &    |- ( ph -> P e. NN )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   &    |- F = ( v e. A |-> ( ( P - 1 ) - v ) )   =>    |- ( ph -> ran F e. Fin )
Theorem	4sqleminfi 12988*	Lemma for 4sq 13001. A i^i ran F is finite. (Contributed by Jim Kingdon, 24-May-2025.)
|- ( ph -> N e. NN )   &    |- ( ph -> P e. NN )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   &    |- F = ( v e. A |-> ( ( P - 1 ) - v ) )   =>    |- ( ph -> ( A i^i ran F ) e. Fin )
Theorem	4sqexercise1 12989*	Exercise which may help in understanding the proof of 4sqlemsdc 12991. (Contributed by Jim Kingdon, 25-May-2025.)
|- S = { n | E. x e. ZZ n = ( x ^ 2 ) }   =>    |- ( A e. NN0 -> DECID A e. S )
Theorem	4sqexercise2 12990*	Exercise which may help in understanding the proof of 4sqlemsdc 12991. (Contributed by Jim Kingdon, 30-May-2025.)
|- S = { n | E. x e. ZZ E. y e. ZZ n = ( ( x ^ 2 ) + ( y ^ 2 ) ) }   =>    |- ( A e. NN0 -> DECID A e. S )
Theorem	4sqlemsdc 12991*	Lemma for 4sq 13001. The property of being the sum of four squares is decidable. The proof involves showing that (for a particular A) there are only a finite number of possible ways that it could be the sum of four squares, so checking each of those possibilities in turn decides whether the number is the sum of four squares. If this proof is hard to follow, especially because of its length, the simplified versions at 4sqexercise1 12989 and 4sqexercise2 12990 may help clarify, as they are using very much the same techniques on simplified versions of this lemma. (Contributed by Jim Kingdon, 25-May-2025.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( A e. NN0 -> DECID A e. S )
Theorem	4sqlem11 12992*	Lemma for 4sq 13001. Use the pigeonhole principle to show that the sets { m ^ 2 | m e. ( 0 ... N ) } and { -u 1 - n ^ 2 | n e. ( 0 ... N ) } have a common element, mod P. Note that although the conclusion is stated in terms of A i^i ran F being nonempty, it is also inhabited by 4sqleminfi 12988 and fin0 7074. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   &    |- F = ( v e. A |-> ( ( P - 1 ) - v ) )   =>    |- ( ph -> ( A i^i ran F ) =/= (/) )
Theorem	4sqlem12 12993*	Lemma for 4sq 13001. For any odd prime P, there is a k < P such that k P - 1 is a sum of two squares. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   &    |- F = ( v e. A |-> ( ( P - 1 ) - v ) )   =>    |- ( ph -> E. k e. ( 1 ... ( P - 1 ) ) E. u e. ZZ[_i] ( ( ( abs ` u ) ^ 2 ) + 1 ) = ( k x. P ) )
Theorem	4sqlem13m 12994*	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   =>    |- ( ph -> ( E. j j e. T /\ M < P ) )
Theorem	4sqlem14 12995*	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   &    |- ( ph -> M e. ( ZZ>= ` 2 ) )   &    |- ( ph -> A e. ZZ )   &    |- ( ph -> B e. ZZ )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> D e. ZZ )   &    |- E = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- F = ( ( ( B + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- G = ( ( ( C + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- H = ( ( ( D + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- R = ( ( ( ( E ^ 2 ) + ( F ^ 2 ) ) + ( ( G ^ 2 ) + ( H ^ 2 ) ) ) / M )   &    |- ( ph -> ( M x. P ) = ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) )   =>    |- ( ph -> R e. NN0 )
Theorem	4sqlem15 12996*	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   &    |- ( ph -> M e. ( ZZ>= ` 2 ) )   &    |- ( ph -> A e. ZZ )   &    |- ( ph -> B e. ZZ )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> D e. ZZ )   &    |- E = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- F = ( ( ( B + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- G = ( ( ( C + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- H = ( ( ( D + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- R = ( ( ( ( E ^ 2 ) + ( F ^ 2 ) ) + ( ( G ^ 2 ) + ( H ^ 2 ) ) ) / M )   &    |- ( ph -> ( M x. P ) = ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) )   =>    |- ( ( ph /\ R = M ) -> ( ( ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( E ^ 2 ) ) = 0 /\ ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( F ^ 2 ) ) = 0 ) /\ ( ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( G ^ 2 ) ) = 0 /\ ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( H ^ 2 ) ) = 0 ) ) )
Theorem	4sqlem16 12997*	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   &    |- ( ph -> M e. ( ZZ>= ` 2 ) )   &    |- ( ph -> A e. ZZ )   &    |- ( ph -> B e. ZZ )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> D e. ZZ )   &    |- E = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- F = ( ( ( B + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- G = ( ( ( C + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- H = ( ( ( D + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- R = ( ( ( ( E ^ 2 ) + ( F ^ 2 ) ) + ( ( G ^ 2 ) + ( H ^ 2 ) ) ) / M )   &    |- ( ph -> ( M x. P ) = ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) )   =>    |- ( ph -> ( R <_ M /\ ( ( R = 0 \/ R = M ) -> ( M ^ 2 ) || ( M x. P ) ) ) )
Theorem	4sqlem17 12998*	Lemma for 4sq 13001. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   &    |- ( ph -> M e. ( ZZ>= ` 2 ) )   &    |- ( ph -> A e. ZZ )   &    |- ( ph -> B e. ZZ )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> D e. ZZ )   &    |- E = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- F = ( ( ( B + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- G = ( ( ( C + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- H = ( ( ( D + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- R = ( ( ( ( E ^ 2 ) + ( F ^ 2 ) ) + ( ( G ^ 2 ) + ( H ^ 2 ) ) ) / M )   &    |- ( ph -> ( M x. P ) = ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) )   =>    |- -. ph
Theorem	4sqlem18 12999*	Lemma for 4sq 13001. Inductive step, odd prime case. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   =>    |- ( ph -> P e. S )
Theorem	4sqlem19 13000*	Lemma for 4sq 13001. The proof is by strong induction - we show that if all the integers less than k are in S, then k is as well. In this part of the proof we do the induction argument and dispense with all the cases except the odd prime case, which is sent to 4sqlem18 12999. If k is 0 , 1 , 2, we show k e. S directly; otherwise if k is composite, k is the product of two numbers less than it (and hence in S by assumption), so by mul4sq 12985 k e. S. (Contributed by Mario Carneiro, 14-Jul-2014.) (Revised by Mario Carneiro, 20-Jun-2015.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- NN0 = S