P. 130 of Theorem List - Intuitionistic Logic Explorer

Theorem List for Intuitionistic Logic Explorer - 12901-13000   *Has distinct variable group(s)

Type	Label	Description
Statement
Theorem	pcgcd 12901	The prime count of a GCD is the minimum of the prime counts of the arguments. (Contributed by Mario Carneiro, 3-Oct-2014.)
|- ( ( P e. Prime /\ A e. ZZ /\ B e. ZZ ) -> ( P pCnt ( A gcd B ) ) = if ( ( P pCnt A ) <_ ( P pCnt B ) , ( P pCnt A ) , ( P pCnt B ) ) )
Theorem	pc2dvds 12902*	A characterization of divisibility in terms of prime count. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by Mario Carneiro, 3-Oct-2014.)
|- ( ( A e. ZZ /\ B e. ZZ ) -> ( A || B <-> A. p e. Prime ( p pCnt A ) <_ ( p pCnt B ) ) )
Theorem	pc11 12903*	The prime count function, viewed as a function from NN to ( NN ^m Prime ), is one-to-one. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( ( A e. NN0 /\ B e. NN0 ) -> ( A = B <-> A. p e. Prime ( p pCnt A ) = ( p pCnt B ) ) )
Theorem	pcz 12904*	The prime count function can be used as an indicator that a given rational number is an integer. (Contributed by Mario Carneiro, 23-Feb-2014.)
|- ( A e. QQ -> ( A e. ZZ <-> A. p e. Prime 0 <_ ( p pCnt A ) ) )
Theorem	pcprmpw2 12905*	Self-referential expression for a prime power. (Contributed by Mario Carneiro, 16-Jan-2015.)
|- ( ( P e. Prime /\ A e. NN ) -> ( E. n e. NN0 A || ( P ^ n ) <-> A = ( P ^ ( P pCnt A ) ) ) )
Theorem	pcprmpw 12906*	Self-referential expression for a prime power. (Contributed by Mario Carneiro, 16-Jan-2015.)
|- ( ( P e. Prime /\ A e. NN ) -> ( E. n e. NN0 A = ( P ^ n ) <-> A = ( P ^ ( P pCnt A ) ) ) )
Theorem	dvdsprmpweq 12907*	If a positive integer divides a prime power, it is a prime power. (Contributed by AV, 25-Jul-2021.)
|- ( ( P e. Prime /\ A e. NN /\ N e. NN0 ) -> ( A || ( P ^ N ) -> E. n e. NN0 A = ( P ^ n ) ) )
Theorem	dvdsprmpweqnn 12908*	If an integer greater than 1 divides a prime power, it is a (proper) prime power. (Contributed by AV, 13-Aug-2021.)
|- ( ( P e. Prime /\ A e. ( ZZ>= ` 2 ) /\ N e. NN0 ) -> ( A || ( P ^ N ) -> E. n e. NN A = ( P ^ n ) ) )
Theorem	dvdsprmpweqle 12909*	If a positive integer divides a prime power, it is a prime power with a smaller exponent. (Contributed by AV, 25-Jul-2021.)
|- ( ( P e. Prime /\ A e. NN /\ N e. NN0 ) -> ( A || ( P ^ N ) -> E. n e. NN0 ( n <_ N /\ A = ( P ^ n ) ) ) )
Theorem	difsqpwdvds 12910	If the difference of two squares is a power of a prime, the prime divides twice the second squared number. (Contributed by AV, 13-Aug-2021.)
|- ( ( ( A e. NN0 /\ B e. NN0 /\ ( B + 1 ) < A ) /\ ( C e. Prime /\ D e. NN0 ) ) -> ( ( C ^ D ) = ( ( A ^ 2 ) - ( B ^ 2 ) ) -> C || ( 2 x. B ) ) )
Theorem	pcaddlem 12911	Lemma for pcadd 12912. The original numbers A and B have been decomposed using the prime count function as ( P ^ M ) x. ( R / S ) where R , S are both not divisible by P and M = ( P pCnt A ), and similarly for B. (Contributed by Mario Carneiro, 9-Sep-2014.)
|- ( ph -> P e. Prime )   &    |- ( ph -> A = ( ( P ^ M ) x. ( R / S ) ) )   &    |- ( ph -> B = ( ( P ^ N ) x. ( T / U ) ) )   &    |- ( ph -> N e. ( ZZ>= ` M ) )   &    |- ( ph -> ( R e. ZZ /\ -. P || R ) )   &    |- ( ph -> ( S e. NN /\ -. P || S ) )   &    |- ( ph -> ( T e. ZZ /\ -. P || T ) )   &    |- ( ph -> ( U e. NN /\ -. P || U ) )   =>    |- ( ph -> M <_ ( P pCnt ( A + B ) ) )
Theorem	pcadd 12912	An inequality for the prime count of a sum. This is the source of the ultrametric inequality for the p-adic metric. (Contributed by Mario Carneiro, 9-Sep-2014.)
|- ( ph -> P e. Prime )   &    |- ( ph -> A e. QQ )   &    |- ( ph -> B e. QQ )   &    |- ( ph -> ( P pCnt A ) <_ ( P pCnt B ) )   =>    |- ( ph -> ( P pCnt A ) <_ ( P pCnt ( A + B ) ) )
Theorem	pcadd2 12913	The inequality of pcadd 12912 becomes an equality when one of the factors has prime count strictly less than the other. (Contributed by Mario Carneiro, 16-Jan-2015.) (Revised by Mario Carneiro, 26-Jun-2015.)
|- ( ph -> P e. Prime )   &    |- ( ph -> A e. QQ )   &    |- ( ph -> B e. QQ )   &    |- ( ph -> ( P pCnt A ) < ( P pCnt B ) )   =>    |- ( ph -> ( P pCnt A ) = ( P pCnt ( A + B ) ) )
Theorem	pcmptcl 12914	Closure for the prime power map. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ A ) , 1 ) )   &    |- ( ph -> A. n e. Prime A e. NN0 )   =>    |- ( ph -> ( F : NN --> NN /\ seq 1 ( x. , F ) : NN --> NN ) )
Theorem	pcmpt 12915*	Construct a function with given prime count characteristics. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ A ) , 1 ) )   &    |- ( ph -> A. n e. Prime A e. NN0 )   &    |- ( ph -> N e. NN )   &    |- ( ph -> P e. Prime )   &    |- ( n = P -> A = B )   =>    |- ( ph -> ( P pCnt ( seq 1 ( x. , F ) ` N ) ) = if ( P <_ N , B , 0 ) )
Theorem	pcmpt2 12916*	Dividing two prime count maps yields a number with all dividing primes confined to an interval. (Contributed by Mario Carneiro, 14-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ A ) , 1 ) )   &    |- ( ph -> A. n e. Prime A e. NN0 )   &    |- ( ph -> N e. NN )   &    |- ( ph -> P e. Prime )   &    |- ( n = P -> A = B )   &    |- ( ph -> M e. ( ZZ>= ` N ) )   =>    |- ( ph -> ( P pCnt ( ( seq 1 ( x. , F ) ` M ) / ( seq 1 ( x. , F ) ` N ) ) ) = if ( ( P <_ M /\ -. P <_ N ) , B , 0 ) )
Theorem	pcmptdvds 12917	The partial products of the prime power map form a divisibility chain. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ A ) , 1 ) )   &    |- ( ph -> A. n e. Prime A e. NN0 )   &    |- ( ph -> N e. NN )   &    |- ( ph -> M e. ( ZZ>= ` N ) )   =>    |- ( ph -> ( seq 1 ( x. , F ) ` N ) || ( seq 1 ( x. , F ) ` M ) )
Theorem	pcprod 12918*	The product of the primes taken to their respective powers reconstructs the original number. (Contributed by Mario Carneiro, 12-Mar-2014.)
|- F = ( n e. NN |-> if ( n e. Prime , ( n ^ ( n pCnt N ) ) , 1 ) )   =>    |- ( N e. NN -> ( seq 1 ( x. , F ) ` N ) = N )
Theorem	sumhashdc 12919*	The sum of 1 over a set is the size of the set. (Contributed by Mario Carneiro, 8-Mar-2014.) (Revised by Mario Carneiro, 20-May-2014.)
|- ( ( B e. Fin /\ A C_ B /\ A. x e. B DECID x e. A ) -> sum_ k e. B if ( k e. A , 1 , 0 ) = (♯ ` A ) )
Theorem	fldivp1 12920	The difference between the floors of adjacent fractions is either 1 or 0. (Contributed by Mario Carneiro, 8-Mar-2014.)
|- ( ( M e. ZZ /\ N e. NN ) -> ( ( |_ ` ( ( M + 1 ) / N ) ) - ( |_ ` ( M / N ) ) ) = if ( N || ( M + 1 ) , 1 , 0 ) )
Theorem	pcfaclem 12921	Lemma for pcfac 12922. (Contributed by Mario Carneiro, 20-May-2014.)
|- ( ( N e. NN0 /\ M e. ( ZZ>= ` N ) /\ P e. Prime ) -> ( |_ ` ( N / ( P ^ M ) ) ) = 0 )
Theorem	pcfac 12922*	Calculate the prime count of a factorial. (Contributed by Mario Carneiro, 11-Mar-2014.) (Revised by Mario Carneiro, 21-May-2014.)
|- ( ( N e. NN0 /\ M e. ( ZZ>= ` N ) /\ P e. Prime ) -> ( P pCnt ( ! ` N ) ) = sum_ k e. ( 1 ... M ) ( |_ ` ( N / ( P ^ k ) ) ) )
Theorem	pcbc 12923*	Calculate the prime count of a binomial coefficient. (Contributed by Mario Carneiro, 11-Mar-2014.) (Revised by Mario Carneiro, 21-May-2014.)
|- ( ( N e. NN /\ K e. ( 0 ... N ) /\ P e. Prime ) -> ( P pCnt ( N _C K ) ) = sum_ k e. ( 1 ... N ) ( ( |_ ` ( N / ( P ^ k ) ) ) - ( ( |_ ` ( ( N - K ) / ( P ^ k ) ) ) + ( |_ ` ( K / ( P ^ k ) ) ) ) ) )
Theorem	qexpz 12924	If a power of a rational number is an integer, then the number is an integer. (Contributed by Mario Carneiro, 10-Aug-2015.)
|- ( ( A e. QQ /\ N e. NN /\ ( A ^ N ) e. ZZ ) -> A e. ZZ )
Theorem	expnprm 12925	A second or higher power of a rational number is not a prime number. Or by contraposition, the n-th root of a prime number is not rational. Suggested by Norm Megill. (Contributed by Mario Carneiro, 10-Aug-2015.)
|- ( ( A e. QQ /\ N e. ( ZZ>= ` 2 ) ) -> -. ( A ^ N ) e. Prime )
Theorem	oddprmdvds 12926*	Every positive integer which is not a power of two is divisible by an odd prime number. (Contributed by AV, 6-Aug-2021.)
|- ( ( K e. NN /\ -. E. n e. NN0 K = ( 2 ^ n ) ) -> E. p e. ( Prime \ { 2 } ) p || K )
5.2.9  Pocklington's theorem
Theorem	prmpwdvds 12927	A relation involving divisibility by a prime power. (Contributed by Mario Carneiro, 2-Mar-2014.)
|- ( ( ( K e. ZZ /\ D e. ZZ ) /\ ( P e. Prime /\ N e. NN ) /\ ( D || ( K x. ( P ^ N ) ) /\ -. D || ( K x. ( P ^ ( N - 1 ) ) ) ) ) -> ( P ^ N ) || D )
Theorem	pockthlem 12928	Lemma for pockthg 12929. (Contributed by Mario Carneiro, 2-Mar-2014.)
|- ( ph -> A e. NN )   &    |- ( ph -> B e. NN )   &    |- ( ph -> B < A )   &    |- ( ph -> N = ( ( A x. B ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> P || N )   &    |- ( ph -> Q e. Prime )   &    |- ( ph -> ( Q pCnt A ) e. NN )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> ( ( C ^ ( N - 1 ) ) mod N ) = 1 )   &    |- ( ph -> ( ( ( C ^ ( ( N - 1 ) / Q ) ) - 1 ) gcd N ) = 1 )   =>    |- ( ph -> ( Q pCnt A ) <_ ( Q pCnt ( P - 1 ) ) )
Theorem	pockthg 12929*	The generalized Pocklington's theorem. If N - 1 = A x. B where B < A, then N is prime if and only if for every prime factor p of A, there is an x such that x ^ ( N - 1 ) = 1 ( mod N ) and gcd ( x ^ ( ( N - 1 ) / p ) - 1 , N ) = 1. (Contributed by Mario Carneiro, 2-Mar-2014.)
|- ( ph -> A e. NN )   &    |- ( ph -> B e. NN )   &    |- ( ph -> B < A )   &    |- ( ph -> N = ( ( A x. B ) + 1 ) )   &    |- ( ph -> A. p e. Prime ( p || A -> E. x e. ZZ ( ( ( x ^ ( N - 1 ) ) mod N ) = 1 /\ ( ( ( x ^ ( ( N - 1 ) / p ) ) - 1 ) gcd N ) = 1 ) ) )   =>    |- ( ph -> N e. Prime )
Theorem	pockthi 12930	Pocklington's theorem, which gives a sufficient criterion for a number N to be prime. This is the preferred method for verifying large primes, being much more efficient to compute than trial division. This form has been optimized for application to specific large primes; see pockthg 12929 for a more general closed-form version. (Contributed by Mario Carneiro, 2-Mar-2014.)
|- P e. Prime   &    |- G e. NN   &    |- M = ( G x. P )   &    |- N = ( M + 1 )   &    |- D e. NN   &    |- E e. NN   &    |- A e. NN   &    |- M = ( D x. ( P ^ E ) )   &    |- D < ( P ^ E )   &    |- ( ( A ^ M ) mod N ) = ( 1 mod N )   &    |- ( ( ( A ^ G ) - 1 ) gcd N ) = 1   =>    |- N e. Prime
5.2.10  Infinite primes theorem
Theorem	infpnlem1 12931*	Lemma for infpn 12933. The smallest divisor (greater than 1) M of N ! + 1 is a prime greater than N. (Contributed by NM, 5-May-2005.)
|- K = ( ( ! ` N ) + 1 )   =>    |- ( ( N e. NN /\ M e. NN ) -> ( ( ( 1 < M /\ ( K / M ) e. NN ) /\ A. j e. NN ( ( 1 < j /\ ( K / j ) e. NN ) -> M <_ j ) ) -> ( N < M /\ A. j e. NN ( ( M / j ) e. NN -> ( j = 1 \/ j = M ) ) ) ) )
Theorem	infpnlem2 12932*	Lemma for infpn 12933. For any positive integer N, there exists a prime number j greater than N. (Contributed by NM, 5-May-2005.)
|- K = ( ( ! ` N ) + 1 )   =>    |- ( N e. NN -> E. j e. NN ( N < j /\ A. k e. NN ( ( j / k ) e. NN -> ( k = 1 \/ k = j ) ) ) )
Theorem	infpn 12933*	There exist infinitely many prime numbers: for any positive integer N, there exists a prime number j greater than N. (See infpn2 13076 for the equinumerosity version.) (Contributed by NM, 1-Jun-2006.)
|- ( N e. NN -> E. j e. NN ( N < j /\ A. k e. NN ( ( j / k ) e. NN -> ( k = 1 \/ k = j ) ) ) )
Theorem	prmunb 12934*	The primes are unbounded. (Contributed by Paul Chapman, 28-Nov-2012.)
|- ( N e. NN -> E. p e. Prime N < p )
5.2.11  Fundamental theorem of arithmetic
Theorem	1arithlem1 12935*	Lemma for 1arith 12939. (Contributed by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   =>    |- ( N e. NN -> ( M ` N ) = ( p e. Prime |-> ( p pCnt N ) ) )
Theorem	1arithlem2 12936*	Lemma for 1arith 12939. (Contributed by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   =>    |- ( ( N e. NN /\ P e. Prime ) -> ( ( M ` N ) ` P ) = ( P pCnt N ) )
Theorem	1arithlem3 12937*	Lemma for 1arith 12939. (Contributed by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   =>    |- ( N e. NN -> ( M ` N ) : Prime --> NN0 )
Theorem	1arithlem4 12938*	Lemma for 1arith 12939. (Contributed by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   &    |- G = ( y e. NN |-> if ( y e. Prime , ( y ^ ( F ` y ) ) , 1 ) )   &    |- ( ph -> F : Prime --> NN0 )   &    |- ( ph -> N e. NN )   &    |- ( ( ph /\ ( q e. Prime /\ N <_ q ) ) -> ( F ` q ) = 0 )   =>    |- ( ph -> E. x e. NN F = ( M ` x ) )
Theorem	1arith 12939*	Fundamental theorem of arithmetic, where a prime factorization is represented as a sequence of prime exponents, for which only finitely many primes have nonzero exponent. The function M maps the set of positive integers one-to-one onto the set of prime factorizations R. (Contributed by Paul Chapman, 17-Nov-2012.) (Proof shortened by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   &    |- R = { e e. ( NN0 ^m Prime ) | ( `' e " NN ) e. Fin }   =>    |- M : NN -1-1-onto-> R
Theorem	1arith2 12940*	Fundamental theorem of arithmetic, where a prime factorization is represented as a finite monotonic 1-based sequence of primes. Every positive integer has a unique prime factorization. Theorem 1.10 in [ApostolNT] p. 17. This is Metamath 100 proof #80. (Contributed by Paul Chapman, 17-Nov-2012.) (Revised by Mario Carneiro, 30-May-2014.)
|- M = ( n e. NN |-> ( p e. Prime |-> ( p pCnt n ) ) )   &    |- R = { e e. ( NN0 ^m Prime ) | ( `' e " NN ) e. Fin }   =>    |- A. z e. NN E! g e. R ( M ` z ) = g
5.2.12  Lagrange's four-square theorem
Syntax	cgz 12941	Extend class notation with the set of gaussian integers.
class ZZ[_i]
Definition	df-gz 12942	Define the set of gaussian integers, which are complex numbers whose real and imaginary parts are integers. (Note that the [ _i ] is actually part of the symbol token and has no independent meaning.) (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ZZ[_i] = { x e. CC | ( ( Re ` x ) e. ZZ /\ ( Im ` x ) e. ZZ ) }
Theorem	elgz 12943	Elementhood in the gaussian integers. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ[_i] <-> ( A e. CC /\ ( Re ` A ) e. ZZ /\ ( Im ` A ) e. ZZ ) )
Theorem	gzcn 12944	A gaussian integer is a complex number. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ[_i] -> A e. CC )
Theorem	zgz 12945	An integer is a gaussian integer. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ -> A e. ZZ[_i] )
Theorem	igz 12946	_i is a gaussian integer. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- _i e. ZZ[_i]
Theorem	gznegcl 12947	The gaussian integers are closed under negation. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ[_i] -> -u A e. ZZ[_i] )
Theorem	gzcjcl 12948	The gaussian integers are closed under conjugation. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( A e. ZZ[_i] -> ( * ` A ) e. ZZ[_i] )
Theorem	gzaddcl 12949	The gaussian integers are closed under addition. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( ( A e. ZZ[_i] /\ B e. ZZ[_i] ) -> ( A + B ) e. ZZ[_i] )
Theorem	gzmulcl 12950	The gaussian integers are closed under multiplication. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( ( A e. ZZ[_i] /\ B e. ZZ[_i] ) -> ( A x. B ) e. ZZ[_i] )
Theorem	gzreim 12951	Construct a gaussian integer from real and imaginary parts. (Contributed by Mario Carneiro, 16-Jul-2014.)
|- ( ( A e. ZZ /\ B e. ZZ ) -> ( A + ( _i x. B ) ) e. ZZ[_i] )
Theorem	gzsubcl 12952	The gaussian integers are closed under subtraction. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- ( ( A e. ZZ[_i] /\ B e. ZZ[_i] ) -> ( A - B ) e. ZZ[_i] )
Theorem	gzabssqcl 12953	The squared norm of a gaussian integer is an integer. (Contributed by Mario Carneiro, 16-Jul-2014.)
|- ( A e. ZZ[_i] -> ( ( abs ` A ) ^ 2 ) e. NN0 )
Theorem	4sqlem5 12954	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   =>    |- ( ph -> ( B e. ZZ /\ ( ( A - B ) / M ) e. ZZ ) )
Theorem	4sqlem6 12955	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   =>    |- ( ph -> ( -u ( M / 2 ) <_ B /\ B < ( M / 2 ) ) )
Theorem	4sqlem7 12956	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   =>    |- ( ph -> ( B ^ 2 ) <_ ( ( ( M ^ 2 ) / 2 ) / 2 ) )
Theorem	4sqlem8 12957	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   =>    |- ( ph -> M || ( ( A ^ 2 ) - ( B ^ 2 ) ) )
Theorem	4sqlem9 12958	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- ( ( ph /\ ps ) -> ( B ^ 2 ) = 0 )   =>    |- ( ( ph /\ ps ) -> ( M ^ 2 ) || ( A ^ 2 ) )
Theorem	4sqlem10 12959	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 16-Jul-2014.)
|- ( ph -> A e. ZZ )   &    |- ( ph -> M e. NN )   &    |- B = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- ( ( ph /\ ps ) -> ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( B ^ 2 ) ) = 0 )   =>    |- ( ( ph /\ ps ) -> ( M ^ 2 ) || ( ( A ^ 2 ) - ( ( ( M ^ 2 ) / 2 ) / 2 ) ) )
Theorem	4sqlem1 12960*	Lemma for 4sq 12982. The set S is the set of all numbers that are expressible as a sum of four squares. Our goal is to show that S = NN0; here we show one subset direction. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- S C_ NN0
Theorem	4sqlem2 12961*	Lemma for 4sq 12982. Change bound variables in S. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( A e. S <-> E. a e. ZZ E. b e. ZZ E. c e. ZZ E. d e. ZZ A = ( ( ( a ^ 2 ) + ( b ^ 2 ) ) + ( ( c ^ 2 ) + ( d ^ 2 ) ) ) )
Theorem	4sqlem3 12962*	Lemma for 4sq 12982. Sufficient condition to be in S. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( ( ( A e. ZZ /\ B e. ZZ ) /\ ( C e. ZZ /\ D e. ZZ ) ) -> ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) e. S )
Theorem	4sqlem4a 12963*	Lemma for 4sqlem4 12964. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( ( A e. ZZ[_i] /\ B e. ZZ[_i] ) -> ( ( ( abs ` A ) ^ 2 ) + ( ( abs ` B ) ^ 2 ) ) e. S )
Theorem	4sqlem4 12964*	Lemma for 4sq 12982. We can express the four-square property more compactly in terms of gaussian integers, because the norms of gaussian integers are exactly sums of two squares. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( A e. S <-> E. u e. ZZ[_i] E. v e. ZZ[_i] A = ( ( ( abs ` u ) ^ 2 ) + ( ( abs ` v ) ^ 2 ) ) )
Theorem	mul4sqlem 12965*	Lemma for mul4sq 12966: algebraic manipulations. The extra assumptions involving M would let us know not just that the product is a sum of squares, but also that it preserves divisibility by M. (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> A e. ZZ[_i] )   &    |- ( ph -> B e. ZZ[_i] )   &    |- ( ph -> C e. ZZ[_i] )   &    |- ( ph -> D e. ZZ[_i] )   &    |- X = ( ( ( abs ` A ) ^ 2 ) + ( ( abs ` B ) ^ 2 ) )   &    |- Y = ( ( ( abs ` C ) ^ 2 ) + ( ( abs ` D ) ^ 2 ) )   &    |- ( ph -> M e. NN )   &    |- ( ph -> ( ( A - C ) / M ) e. ZZ[_i] )   &    |- ( ph -> ( ( B - D ) / M ) e. ZZ[_i] )   &    |- ( ph -> ( X / M ) e. NN0 )   =>    |- ( ph -> ( ( X / M ) x. ( Y / M ) ) e. S )
Theorem	mul4sq 12966*	Euler's four-square identity: The product of two sums of four squares is also a sum of four squares. This is usually quoted as an explicit formula involving eight real variables; we save some time by working with complex numbers (gaussian integers) instead, so that we only have to work with four variables, and also hiding the actual formula for the product in the proof of mul4sqlem 12965. (For the curious, the explicit formula that is used is ( | a | ^ 2 + | b | ^ 2 ) ( | c | ^ 2 + | d | ^ 2 ) = | a * x. c + b x. d * | ^ 2 + | a * x. d - b x. c * | ^ 2.) (Contributed by Mario Carneiro, 14-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( ( A e. S /\ B e. S ) -> ( A x. B ) e. S )
Theorem	4sqlemafi 12967*	Lemma for 4sq 12982. A is finite. (Contributed by Jim Kingdon, 24-May-2025.)
|- ( ph -> N e. NN )   &    |- ( ph -> P e. NN )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   =>    |- ( ph -> A e. Fin )
Theorem	4sqlemffi 12968*	Lemma for 4sq 12982. ran F is finite. (Contributed by Jim Kingdon, 24-May-2025.)
|- ( ph -> N e. NN )   &    |- ( ph -> P e. NN )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   &    |- F = ( v e. A |-> ( ( P - 1 ) - v ) )   =>    |- ( ph -> ran F e. Fin )
Theorem	4sqleminfi 12969*	Lemma for 4sq 12982. A i^i ran F is finite. (Contributed by Jim Kingdon, 24-May-2025.)
|- ( ph -> N e. NN )   &    |- ( ph -> P e. NN )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   &    |- F = ( v e. A |-> ( ( P - 1 ) - v ) )   =>    |- ( ph -> ( A i^i ran F ) e. Fin )
Theorem	4sqexercise1 12970*	Exercise which may help in understanding the proof of 4sqlemsdc 12972. (Contributed by Jim Kingdon, 25-May-2025.)
|- S = { n | E. x e. ZZ n = ( x ^ 2 ) }   =>    |- ( A e. NN0 -> DECID A e. S )
Theorem	4sqexercise2 12971*	Exercise which may help in understanding the proof of 4sqlemsdc 12972. (Contributed by Jim Kingdon, 30-May-2025.)
|- S = { n | E. x e. ZZ E. y e. ZZ n = ( ( x ^ 2 ) + ( y ^ 2 ) ) }   =>    |- ( A e. NN0 -> DECID A e. S )
Theorem	4sqlemsdc 12972*	Lemma for 4sq 12982. The property of being the sum of four squares is decidable. The proof involves showing that (for a particular A) there are only a finite number of possible ways that it could be the sum of four squares, so checking each of those possibilities in turn decides whether the number is the sum of four squares. If this proof is hard to follow, especially because of its length, the simplified versions at 4sqexercise1 12970 and 4sqexercise2 12971 may help clarify, as they are using very much the same techniques on simplified versions of this lemma. (Contributed by Jim Kingdon, 25-May-2025.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- ( A e. NN0 -> DECID A e. S )
Theorem	4sqlem11 12973*	Lemma for 4sq 12982. Use the pigeonhole principle to show that the sets { m ^ 2 | m e. ( 0 ... N ) } and { -u 1 - n ^ 2 | n e. ( 0 ... N ) } have a common element, mod P. Note that although the conclusion is stated in terms of A i^i ran F being nonempty, it is also inhabited by 4sqleminfi 12969 and fin0 7073. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   &    |- F = ( v e. A |-> ( ( P - 1 ) - v ) )   =>    |- ( ph -> ( A i^i ran F ) =/= (/) )
Theorem	4sqlem12 12974*	Lemma for 4sq 12982. For any odd prime P, there is a k < P such that k P - 1 is a sum of two squares. (Contributed by Mario Carneiro, 15-Jul-2014.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- A = { u | E. m e. ( 0 ... N ) u = ( ( m ^ 2 ) mod P ) }   &    |- F = ( v e. A |-> ( ( P - 1 ) - v ) )   =>    |- ( ph -> E. k e. ( 1 ... ( P - 1 ) ) E. u e. ZZ[_i] ( ( ( abs ` u ) ^ 2 ) + 1 ) = ( k x. P ) )
Theorem	4sqlem13m 12975*	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   =>    |- ( ph -> ( E. j j e. T /\ M < P ) )
Theorem	4sqlem14 12976*	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   &    |- ( ph -> M e. ( ZZ>= ` 2 ) )   &    |- ( ph -> A e. ZZ )   &    |- ( ph -> B e. ZZ )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> D e. ZZ )   &    |- E = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- F = ( ( ( B + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- G = ( ( ( C + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- H = ( ( ( D + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- R = ( ( ( ( E ^ 2 ) + ( F ^ 2 ) ) + ( ( G ^ 2 ) + ( H ^ 2 ) ) ) / M )   &    |- ( ph -> ( M x. P ) = ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) )   =>    |- ( ph -> R e. NN0 )
Theorem	4sqlem15 12977*	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   &    |- ( ph -> M e. ( ZZ>= ` 2 ) )   &    |- ( ph -> A e. ZZ )   &    |- ( ph -> B e. ZZ )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> D e. ZZ )   &    |- E = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- F = ( ( ( B + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- G = ( ( ( C + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- H = ( ( ( D + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- R = ( ( ( ( E ^ 2 ) + ( F ^ 2 ) ) + ( ( G ^ 2 ) + ( H ^ 2 ) ) ) / M )   &    |- ( ph -> ( M x. P ) = ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) )   =>    |- ( ( ph /\ R = M ) -> ( ( ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( E ^ 2 ) ) = 0 /\ ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( F ^ 2 ) ) = 0 ) /\ ( ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( G ^ 2 ) ) = 0 /\ ( ( ( ( M ^ 2 ) / 2 ) / 2 ) - ( H ^ 2 ) ) = 0 ) ) )
Theorem	4sqlem16 12978*	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   &    |- ( ph -> M e. ( ZZ>= ` 2 ) )   &    |- ( ph -> A e. ZZ )   &    |- ( ph -> B e. ZZ )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> D e. ZZ )   &    |- E = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- F = ( ( ( B + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- G = ( ( ( C + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- H = ( ( ( D + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- R = ( ( ( ( E ^ 2 ) + ( F ^ 2 ) ) + ( ( G ^ 2 ) + ( H ^ 2 ) ) ) / M )   &    |- ( ph -> ( M x. P ) = ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) )   =>    |- ( ph -> ( R <_ M /\ ( ( R = 0 \/ R = M ) -> ( M ^ 2 ) || ( M x. P ) ) ) )
Theorem	4sqlem17 12979*	Lemma for 4sq 12982. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   &    |- ( ph -> M e. ( ZZ>= ` 2 ) )   &    |- ( ph -> A e. ZZ )   &    |- ( ph -> B e. ZZ )   &    |- ( ph -> C e. ZZ )   &    |- ( ph -> D e. ZZ )   &    |- E = ( ( ( A + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- F = ( ( ( B + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- G = ( ( ( C + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- H = ( ( ( D + ( M / 2 ) ) mod M ) - ( M / 2 ) )   &    |- R = ( ( ( ( E ^ 2 ) + ( F ^ 2 ) ) + ( ( G ^ 2 ) + ( H ^ 2 ) ) ) / M )   &    |- ( ph -> ( M x. P ) = ( ( ( A ^ 2 ) + ( B ^ 2 ) ) + ( ( C ^ 2 ) + ( D ^ 2 ) ) ) )   =>    |- -. ph
Theorem	4sqlem18 12980*	Lemma for 4sq 12982. Inductive step, odd prime case. (Contributed by Mario Carneiro, 16-Jul-2014.) (Revised by AV, 14-Sep-2020.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   &    |- ( ph -> N e. NN )   &    |- ( ph -> P = ( ( 2 x. N ) + 1 ) )   &    |- ( ph -> P e. Prime )   &    |- ( ph -> ( 0 ... ( 2 x. N ) ) C_ S )   &    |- T = { i e. NN | ( i x. P ) e. S }   &    |- M = inf ( T , RR , < )   =>    |- ( ph -> P e. S )
Theorem	4sqlem19 12981*	Lemma for 4sq 12982. The proof is by strong induction - we show that if all the integers less than k are in S, then k is as well. In this part of the proof we do the induction argument and dispense with all the cases except the odd prime case, which is sent to 4sqlem18 12980. If k is 0 , 1 , 2, we show k e. S directly; otherwise if k is composite, k is the product of two numbers less than it (and hence in S by assumption), so by mul4sq 12966 k e. S. (Contributed by Mario Carneiro, 14-Jul-2014.) (Revised by Mario Carneiro, 20-Jun-2015.)
|- S = { n | E. x e. ZZ E. y e. ZZ E. z e. ZZ E. w e. ZZ n = ( ( ( x ^ 2 ) + ( y ^ 2 ) ) + ( ( z ^ 2 ) + ( w ^ 2 ) ) ) }   =>    |- NN0 = S
Theorem	4sq 12982*	Lagrange's four-square theorem, or Bachet's conjecture: every nonnegative integer is expressible as a sum of four squares. This is Metamath 100 proof #19. (Contributed by Mario Carneiro, 16-Jul-2014.)
|- ( A e. NN0 <-> E. a e. ZZ E. b e. ZZ E. c e. ZZ E. d e. ZZ A = ( ( ( a ^ 2 ) + ( b ^ 2 ) ) + ( ( c ^ 2 ) + ( d ^ 2 ) ) ) )
5.2.13  Decimal arithmetic (cont.)
Theorem	dec2dvds 12983	Divisibility by two is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.)
|- A e. NN0   &    |- B e. NN0   &    |- ( B x. 2 ) = C   &    |- D = ( C + 1 )   =>    |- -. 2 || ; A D
Theorem	dec5dvds 12984	Divisibility by five is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.)
|- A e. NN0   &    |- B e. NN   &    |- B < 5   =>    |- -. 5 || ; A B
Theorem	dec5dvds2 12985	Divisibility by five is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.)
|- A e. NN0   &    |- B e. NN   &    |- B < 5   &    |- ( 5 + B ) = C   =>    |- -. 5 || ; A C
Theorem	dec5nprm 12986	A decimal number greater than 10 and ending with five is not a prime number. (Contributed by Mario Carneiro, 19-Apr-2015.)
|- A e. NN   =>    |- -. ; A 5 e. Prime
Theorem	dec2nprm 12987	A decimal number greater than 10 and ending with an even digit is not a prime number. (Contributed by Mario Carneiro, 19-Apr-2015.)
|- A e. NN   &    |- B e. NN0   &    |- ( B x. 2 ) = C   =>    |- -. ; A C e. Prime
Theorem	modxai 12988	Add exponents in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.) (Revised by Mario Carneiro, 5-Feb-2015.)
|- N e. NN   &    |- A e. NN   &    |- B e. NN0   &    |- D e. ZZ   &    |- K e. NN0   &    |- M e. NN0   &    |- C e. NN0   &    |- L e. NN0   &    |- ( ( A ^ B ) mod N ) = ( K mod N )   &    |- ( ( A ^ C ) mod N ) = ( L mod N )   &    |- ( B + C ) = E   &    |- ( ( D x. N ) + M ) = ( K x. L )   =>    |- ( ( A ^ E ) mod N ) = ( M mod N )
Theorem	mod2xi 12989	Double exponents in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.)
|- N e. NN   &    |- A e. NN   &    |- B e. NN0   &    |- D e. ZZ   &    |- K e. NN0   &    |- M e. NN0   &    |- ( ( A ^ B ) mod N ) = ( K mod N )   &    |- ( 2 x. B ) = E   &    |- ( ( D x. N ) + M ) = ( K x. K )   =>    |- ( ( A ^ E ) mod N ) = ( M mod N )
Theorem	modxp1i 12990	Add one to an exponent in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.)
|- N e. NN   &    |- A e. NN   &    |- B e. NN0   &    |- D e. ZZ   &    |- K e. NN0   &    |- M e. NN0   &    |- ( ( A ^ B ) mod N ) = ( K mod N )   &    |- ( B + 1 ) = E   &    |- ( ( D x. N ) + M ) = ( K x. A )   =>    |- ( ( A ^ E ) mod N ) = ( M mod N )
Theorem	modsubi 12991	Subtract from within a mod calculation. (Contributed by Mario Carneiro, 18-Feb-2014.)
|- N e. NN   &    |- A e. NN   &    |- B e. NN0   &    |- M e. NN0   &    |- ( A mod N ) = ( K mod N )   &    |- ( M + B ) = K   =>    |- ( ( A - B ) mod N ) = ( M mod N )
Theorem	gcdi 12992	Calculate a GCD via Euclid's algorithm. (Contributed by Mario Carneiro, 19-Feb-2014.)
|- K e. NN0   &    |- R e. NN0   &    |- N e. NN0   &    |- ( N gcd R ) = G   &    |- ( ( K x. N ) + R ) = M   =>    |- ( M gcd N ) = G
Theorem	gcdmodi 12993	Calculate a GCD via Euclid's algorithm. Theorem 5.6 in [ApostolNT] p. 109. (Contributed by Mario Carneiro, 19-Feb-2014.)
|- K e. NN0   &    |- R e. NN0   &    |- N e. NN   &    |- ( K mod N ) = ( R mod N )   &    |- ( N gcd R ) = G   =>    |- ( K gcd N ) = G
Theorem	numexp0 12994	Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.)
|- A e. NN0   =>    |- ( A ^ 0 ) = 1
Theorem	numexp1 12995	Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.)
|- A e. NN0   =>    |- ( A ^ 1 ) = A
Theorem	numexpp1 12996	Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.)
|- A e. NN0   &    |- M e. NN0   &    |- ( M + 1 ) = N   &    |- ( ( A ^ M ) x. A ) = C   =>    |- ( A ^ N ) = C
Theorem	numexp2x 12997	Double an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.)
|- A e. NN0   &    |- M e. NN0   &    |- ( 2 x. M ) = N   &    |- ( A ^ M ) = D   &    |- ( D x. D ) = C   =>    |- ( A ^ N ) = C
Theorem	decsplit0b 12998	Split a decimal number into two parts. Base case: N = 0. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.)
|- A e. NN0   =>    |- ( ( A x. (; 1 0 ^ 0 ) ) + B ) = ( A + B )
Theorem	decsplit0 12999	Split a decimal number into two parts. Base case: N = 0. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.)
|- A e. NN0   =>    |- ( ( A x. (; 1 0 ^ 0 ) ) + 0 ) = A
Theorem	decsplit1 13000	Split a decimal number into two parts. Base case: N = 1. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.)
|- A e. NN0   =>    |- ( ( A x. (; 1 0 ^ 1 ) ) + B ) = ; A B