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Theorem List for Intuitionistic Logic Explorer - 7501-7600   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theorempr2nelem 7501 Lemma for pr2ne 7502. (Contributed by FL, 17-Aug-2008.)
 |-  ( ( A  e.  C  /\  B  e.  D  /\  A  =/=  B ) 
 ->  { A ,  B }  ~~  2o )
 
Theorempr2ne 7502 If an unordered pair has two elements they are different. (Contributed by FL, 14-Feb-2010.)
 |-  ( ( A  e.  C  /\  B  e.  D )  ->  ( { A ,  B }  ~~  2o  <->  A  =/=  B ) )
 
Theoremen2prde 7503* A set of size two is an unordered pair of two different elements. (Contributed by Alexander van der Vekens, 8-Dec-2017.) (Revised by Jim Kingdon, 11-Jan-2026.)
 |-  ( V  ~~  2o  ->  E. a E. b
 ( a  =/=  b  /\  V  =  { a ,  b } ) )
 
Theorempr1or2 7504 An unordered pair, with decidable equality for the specified elements, has either one or two elements. (Contributed by Jim Kingdon, 7-Jan-2026.)
 |-  ( ( A  e.  C  /\  B  e.  D  /\ DECID  A  =  B )  ->  ( { A ,  B }  ~~  1o  \/  { A ,  B }  ~~  2o ) )
 
Theorempr2cv1 7505 If an unordered pair is equinumerous to ordinal two, then a part is a set. (Contributed by RP, 21-Oct-2023.)
 |-  ( { A ,  B }  ~~  2o  ->  A  e.  _V )
 
Theorempr2cv2 7506 If an unordered pair is equinumerous to ordinal two, then a part is a set. (Contributed by RP, 21-Oct-2023.)
 |-  ( { A ,  B }  ~~  2o  ->  B  e.  _V )
 
Theorempr2cv 7507 If an unordered pair is equinumerous to ordinal two, then both parts are sets. (Contributed by RP, 8-Oct-2023.)
 |-  ( { A ,  B }  ~~  2o  ->  ( A  e.  _V  /\  B  e.  _V )
 )
 
Theoremsspw1or2 7508* The set of subsets of a given set with one or two elements can be expressed as elements of the power set or as inhabited elements of the power set. (Contributed by Jim Kingdon, 31-Mar-2026.)
 |- 
 { x  e.  {
 s  e.  ~P V  |  E. j  j  e.  s }  |  ( x  ~~  1o  \/  x  ~~  2o ) }  =  { x  e.  ~P V  |  ( x  ~~ 
 1o  \/  x  ~~  2o ) }
 
Theoremexmidonfinlem 7509* Lemma for exmidonfin 7510. (Contributed by Andrew W Swan and Jim Kingdon, 9-Mar-2024.)
 |-  A  =  { { x  e.  { (/) }  |  ph
 } ,  { x  e.  { (/) }  |  -.  ph
 } }   =>    |-  ( om  =  ( On  i^i  Fin )  -> DECID  ph )
 
Theoremexmidonfin 7510 If a finite ordinal is a natural number, excluded middle follows. That excluded middle implies that a finite ordinal is a natural number is proved in the Metamath Proof Explorer. That a natural number is a finite ordinal is shown at nnfi 7140 and nnon 4737. (Contributed by Andrew W Swan and Jim Kingdon, 9-Mar-2024.)
 |-  ( om  =  ( On  i^i  Fin )  -> EXMID )
 
Theoremen2eleq 7511 Express a set of pair cardinality as the unordered pair of a given element and the other element. (Contributed by Stefan O'Rear, 22-Aug-2015.)
 |-  ( ( X  e.  P  /\  P  ~~  2o )  ->  P  =  { X ,  U. ( P 
 \  { X }
 ) } )
 
Theoremen2other2 7512 Taking the other element twice in a pair gets back to the original element. (Contributed by Stefan O'Rear, 22-Aug-2015.)
 |-  ( ( X  e.  P  /\  P  ~~  2o )  ->  U. ( P  \  { U. ( P  \  { X } ) }
 )  =  X )
 
Theoremdju1p1e2 7513 Disjoint union version of one plus one equals two. (Contributed by Jim Kingdon, 1-Jul-2022.)
 |-  ( 1o 1o )  ~~  2o
 
Theoreminfpwfidom 7514 The collection of finite subsets of a set dominates the set. (We use the weaker sethood assumption 
( ~P A  i^i  Fin )  e.  _V because this theorem also implies that  A is a set if  ~P A  i^i  Fin is.) (Contributed by Mario Carneiro, 17-May-2015.)
 |-  ( ( ~P A  i^i  Fin )  e.  _V  ->  A  ~<_  ( ~P A  i^i  Fin ) )
 
Theoremexmidfodomrlemeldju 7515 Lemma for exmidfodomr 7520. A variant of djur 7373. (Contributed by Jim Kingdon, 2-Jul-2022.)
 |-  ( ph  ->  A  C_ 
 1o )   &    |-  ( ph  ->  B  e.  ( A 1o )
 )   =>    |-  ( ph  ->  ( B  =  (inl `  (/) )  \/  B  =  (inr `  (/) ) ) )
 
Theoremexmidfodomrlemreseldju 7516 Lemma for exmidfodomrlemrALT 7519. A variant of eldju 7372. (Contributed by Jim Kingdon, 9-Jul-2022.)
 |-  ( ph  ->  A  C_ 
 1o )   &    |-  ( ph  ->  B  e.  ( A 1o )
 )   =>    |-  ( ph  ->  (
 ( (/)  e.  A  /\  B  =  ( (inl  |`  A ) `  (/) ) )  \/  B  =  ( (inr  |`  1o ) `  (/) ) ) )
 
Theoremexmidfodomrlemim 7517* Excluded middle implies the existence of a mapping from any set onto any inhabited set that it dominates. Proposition 1.1 of [PradicBrown2022], p. 2. (Contributed by Jim Kingdon, 1-Jul-2022.)
 |-  (EXMID 
 ->  A. x A. y
 ( ( E. z  z  e.  y  /\  y 
 ~<_  x )  ->  E. f  f : x -onto-> y ) )
 
Theoremexmidfodomrlemr 7518* The existence of a mapping from any set onto any inhabited set that it dominates implies excluded middle. Proposition 1.2 of [PradicBrown2022], p. 2. (Contributed by Jim Kingdon, 1-Jul-2022.)
 |-  ( A. x A. y ( ( E. z  z  e.  y  /\  y  ~<_  x )  ->  E. f  f : x -onto-> y )  -> EXMID )
 
TheoremexmidfodomrlemrALT 7519* The existence of a mapping from any set onto any inhabited set that it dominates implies excluded middle. Proposition 1.2 of [PradicBrown2022], p. 2. An alternative proof of exmidfodomrlemr 7518. In particular, this proof uses eldju 7372 instead of djur 7373 and avoids djulclb 7359. (New usage is discouraged.) (Proof modification is discouraged.) (Contributed by Jim Kingdon, 9-Jul-2022.)
 |-  ( A. x A. y ( ( E. z  z  e.  y  /\  y  ~<_  x )  ->  E. f  f : x -onto-> y )  -> EXMID )
 
Theoremexmidfodomr 7520* Excluded middle is equivalent to the existence of a mapping from any set onto any inhabited set that it dominates. (Contributed by Jim Kingdon, 1-Jul-2022.)
 |-  (EXMID  <->  A. x A. y ( ( E. z  z  e.  y  /\  y  ~<_  x )  ->  E. f  f : x -onto-> y ) )
 
Theoremacnrcl 7521 Reverse closure for the choice set predicate. (Contributed by Mario Carneiro, 31-Aug-2015.)
 |-  ( X  e. AC  A  ->  A  e.  _V )
 
Theoremacneq 7522 Equality theorem for the choice set function. (Contributed by Mario Carneiro, 31-Aug-2015.)
 |-  ( A  =  C  -> AC  A  = AC  C )
 
Theoremisacnm 7523* The property of being a choice set of length  A. (Contributed by Mario Carneiro, 31-Aug-2015.)
 |-  ( ( X  e.  V  /\  A  e.  W )  ->  ( X  e. AC  A  <->  A. f  e.  ( { z  e.  ~P X  |  E. j  j  e.  z }  ^m  A ) E. g A. x  e.  A  ( g `  x )  e.  ( f `  x ) ) )
 
Theoremfinacn 7524 Every set has finite choice sequences. (Contributed by Mario Carneiro, 31-Aug-2015.)
 |-  ( A  e.  Fin  -> AC  A  =  _V )
 
2.6.45  Axiom of Choice equivalents
 
Syntaxwac 7525 Formula for an abbreviation of the axiom of choice.
 wff CHOICE
 
Definitiondf-ac 7526* The expression CHOICE will be used as a readable shorthand for any form of the axiom of choice; all concrete forms are long, cryptic, have dummy variables, or all three, making it useful to have a short name. Similar to the Axiom of Choice (first form) of [Enderton] p. 49.

There are some decisions about how to write this definition especially around whether ax-setind 4664 is needed to show equivalence to other ways of stating choice, and about whether choice functions are available for nonempty sets or inhabited sets. (Contributed by Mario Carneiro, 22-Feb-2015.)

 |-  (CHOICE  <->  A. x E. f ( f  C_  x  /\  f  Fn  dom  x )
 )
 
Theoremacfun 7527* A convenient form of choice. The goal here is to state choice as the existence of a choice function on a set of inhabited sets, while making full use of our notation around functions and function values. (Contributed by Jim Kingdon, 20-Nov-2023.)
 |-  ( ph  -> CHOICE )   &    |-  ( ph  ->  A  e.  V )   &    |-  ( ph  ->  A. x  e.  A  E. w  w  e.  x )   =>    |-  ( ph  ->  E. f
 ( f  Fn  A  /\  A. x  e.  A  ( f `  x )  e.  x )
 )
 
Theoremexmidaclem 7528* Lemma for exmidac 7529. The result, with a few hypotheses to break out commonly used expressions. (Contributed by Jim Kingdon, 21-Nov-2023.)
 |-  A  =  { x  e.  { (/) ,  { (/) } }  |  ( x  =  (/)  \/  y  =  { (/) } ) }   &    |-  B  =  { x  e.  { (/) ,  { (/) } }  |  ( x  =  { (/)
 }  \/  y  =  { (/) } ) }   &    |-  C  =  { A ,  B }   =>    |-  (CHOICE 
 -> EXMID )
 
Theoremexmidac 7529 The axiom of choice implies excluded middle. See acexmid 6057 for more discussion of this theorem and a way of stating it without using CHOICE or EXMID. (Contributed by Jim Kingdon, 21-Nov-2023.)
 |-  (CHOICE 
 -> EXMID )
 
2.6.46  Cardinal number arithmetic
 
Theoremendjudisj 7530 Equinumerosity of a disjoint union and a union of two disjoint sets. (Contributed by Jim Kingdon, 30-Jul-2023.)
 |-  ( ( A  e.  V  /\  B  e.  W  /\  ( A  i^i  B )  =  (/) )  ->  ( A B )  ~~  ( A  u.  B ) )
 
Theoremdjuen 7531 Disjoint unions of equinumerous sets are equinumerous. (Contributed by Jim Kingdon, 30-Jul-2023.)
 |-  ( ( A  ~~  B  /\  C  ~~  D )  ->  ( A C ) 
 ~~  ( B D ) )
 
Theoremdjuenun 7532 Disjoint union is equinumerous to union for disjoint sets. (Contributed by Mario Carneiro, 29-Apr-2015.) (Revised by Jim Kingdon, 19-Aug-2023.)
 |-  ( ( A  ~~  B  /\  C  ~~  D  /\  ( B  i^i  D )  =  (/) )  ->  ( A C )  ~~  ( B  u.  D ) )
 
Theoremdju1en 7533 Cardinal addition with cardinal one (which is the same as ordinal one). Used in proof of Theorem 6J of [Enderton] p. 143. (Contributed by NM, 28-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
 |-  ( ( A  e.  V  /\  -.  A  e.  A )  ->  ( A 1o )  ~~  suc  A )
 
Theoremdju0en 7534 Cardinal addition with cardinal zero (the empty set). Part (a1) of proof of Theorem 6J of [Enderton] p. 143. (Contributed by NM, 27-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
 |-  ( A  e.  V  ->  ( A (/) )  ~~  A )
 
Theoremxp2dju 7535 Two times a cardinal number. Exercise 4.56(g) of [Mendelson] p. 258. (Contributed by NM, 27-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
 |-  ( 2o  X.  A )  =  ( A A )
 
Theoremdjucomen 7536 Commutative law for cardinal addition. Exercise 4.56(c) of [Mendelson] p. 258. (Contributed by NM, 24-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
 |-  ( ( A  e.  V  /\  B  e.  W )  ->  ( A B ) 
 ~~  ( B A ) )
 
Theoremdjuassen 7537 Associative law for cardinal addition. Exercise 4.56(c) of [Mendelson] p. 258. (Contributed by NM, 26-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
 |-  ( ( A  e.  V  /\  B  e.  W  /\  C  e.  X ) 
 ->  ( ( A B ) C )  ~~  ( A ( B C ) ) )
 
Theoremxpdjuen 7538 Cardinal multiplication distributes over cardinal addition. Theorem 6I(3) of [Enderton] p. 142. (Contributed by NM, 26-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
 |-  ( ( A  e.  V  /\  B  e.  W  /\  C  e.  X ) 
 ->  ( A  X.  ( B C ) )  ~~  ( ( A  X.  B ) ( A  X.  C ) ) )
 
Theoremdjudoml 7539 A set is dominated by its disjoint union with another. (Contributed by Jim Kingdon, 11-Jul-2023.)
 |-  ( ( A  e.  V  /\  B  e.  W )  ->  A  ~<_  ( A B ) )
 
Theoremdjudomr 7540 A set is dominated by its disjoint union with another. (Contributed by Jim Kingdon, 11-Jul-2023.)
 |-  ( ( A  e.  V  /\  B  e.  W )  ->  B  ~<_  ( A B ) )
 
2.6.47  Ordinal trichotomy
 
Theoremexmidontriimlem1 7541 Lemma for exmidontriim 7545. A variation of r19.30dc 2692. (Contributed by Jim Kingdon, 12-Aug-2024.)
 |-  ( ( A. x  e.  A  ( ph  \/  ps 
 \/  ch )  /\ EXMID )  ->  ( E. x  e.  A  ph  \/  E. x  e.  A  ps  \/  A. x  e.  A  ch ) )
 
Theoremexmidontriimlem2 7542* Lemma for exmidontriim 7545. (Contributed by Jim Kingdon, 12-Aug-2024.)
 |-  ( ph  ->  B  e.  On )   &    |-  ( ph  -> EXMID )   &    |-  ( ph  ->  A. y  e.  B  ( A  e.  y  \/  A  =  y  \/  y  e.  A ) )   =>    |-  ( ph  ->  ( A  e.  B  \/  A. y  e.  B  y  e.  A ) )
 
Theoremexmidontriimlem3 7543* Lemma for exmidontriim 7545. What we get to do based on induction on both  A and  B. (Contributed by Jim Kingdon, 10-Aug-2024.)
 |-  ( ph  ->  A  e.  On )   &    |-  ( ph  ->  B  e.  On )   &    |-  ( ph  -> EXMID
 )   &    |-  ( ph  ->  A. z  e.  A  A. y  e. 
 On  ( z  e.  y  \/  z  =  y  \/  y  e.  z ) )   &    |-  ( ph  ->  A. y  e.  B  ( A  e.  y  \/  A  =  y  \/  y  e.  A ) )   =>    |-  ( ph  ->  ( A  e.  B  \/  A  =  B  \/  B  e.  A )
 )
 
Theoremexmidontriimlem4 7544* Lemma for exmidontriim 7545. The induction step for the induction on  A. (Contributed by Jim Kingdon, 10-Aug-2024.)
 |-  ( ph  ->  A  e.  On )   &    |-  ( ph  ->  B  e.  On )   &    |-  ( ph  -> EXMID
 )   &    |-  ( ph  ->  A. z  e.  A  A. y  e. 
 On  ( z  e.  y  \/  z  =  y  \/  y  e.  z ) )   =>    |-  ( ph  ->  ( A  e.  B  \/  A  =  B  \/  B  e.  A )
 )
 
Theoremexmidontriim 7545* Excluded middle implies ordinal trichotomy. Lemma 10.4.1 of [HoTT], p. (varies). The proof follows the proof from the HoTT book fairly closely. (Contributed by Jim Kingdon, 10-Aug-2024.)
 |-  (EXMID 
 ->  A. x  e.  On  A. y  e.  On  ( x  e.  y  \/  x  =  y  \/  y  e.  x )
 )
 
2.6.48  Excluded middle and the power set of a singleton
 
Theoremiftrueb01 7546 Using an  if expression to represent a truth value by  (/) or  1o. Unlike some theorems using  if,  ph does not need to be decidable. (Contributed by Jim Kingdon, 9-Jan-2026.)
 |-  ( if ( ph ,  1o ,  (/) )  =  1o  <->  ph )
 
Theorempw1m 7547* A truth value which is inhabited is equal to true. This is a variation of pwntru 4317 and pwtrufal 16897. (Contributed by Jim Kingdon, 10-Jan-2026.)
 |-  ( ( A  e.  ~P 1o  /\  E. x  x  e.  A )  ->  A  =  1o )
 
Theorempw1if 7548 Expressing a truth value in terms of an  if expression. (Contributed by Jim Kingdon, 10-Jan-2026.)
 |-  ( A  e.  ~P 1o  ->  if ( A  =  1o ,  1o ,  (/) )  =  A )
 
Theorempw1on 7549 The power set of  1o is an ordinal. (Contributed by Jim Kingdon, 29-Jul-2024.)
 |- 
 ~P 1o  e.  On
 
Theorempw1dom2 7550 The power set of  1o dominates  2o. Also see pwpw0ss 3914 which is similar. (Contributed by Jim Kingdon, 21-Sep-2022.)
 |- 
 2o  ~<_  ~P 1o
 
Theorempw1ne0 7551 The power set of  1o is not zero. (Contributed by Jim Kingdon, 30-Jul-2024.)
 |- 
 ~P 1o  =/=  (/)
 
Theorempw1ne1 7552 The power set of  1o is not one. (Contributed by Jim Kingdon, 30-Jul-2024.)
 |- 
 ~P 1o  =/=  1o
 
Theorempw1ne3 7553 The power set of  1o is not three. (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
 |- 
 ~P 1o  =/=  3o
 
Theorempw1nel3 7554 Negated excluded middle implies that the power set of  1o is not an element of  3o. (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
 |-  ( -. EXMID  ->  -.  ~P 1o  e.  3o )
 
Theoremsucpw1ne3 7555 Negated excluded middle implies that the successor of the power set of  1o is not three . (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
 |-  ( -. EXMID  ->  suc  ~P 1o  =/=  3o )
 
Theoremsucpw1nel3 7556 The successor of the power set of 
1o is not an element of  3o. (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
 |- 
 -.  suc  ~P 1o  e.  3o
 
Theorem3nelsucpw1 7557 Three is not an element of the successor of the power set of  1o. (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
 |- 
 -.  3o  e.  suc  ~P 1o
 
Theoremsucpw1nss3 7558 Negated excluded middle implies that the successor of the power set of  1o is not a subset of  3o. (Contributed by James E. Hanson and Jim Kingdon, 31-Jul-2024.)
 |-  ( -. EXMID  ->  -.  suc  ~P 1o  C_ 
 3o )
 
Theorem3nsssucpw1 7559 Negated excluded middle implies that  3o is not a subset of the successor of the power set of 
1o. (Contributed by James E. Hanson and Jim Kingdon, 31-Jul-2024.)
 |-  ( -. EXMID  ->  -.  3o  C_  suc  ~P 1o )
 
Theoremonntri35 7560* Double negated ordinal trichotomy.

There are five equivalent statements: (1)  -.  -.  A. x  e.  On A. y  e.  On ( x  e.  y  \/  x  =  y  \/  y  e.  x ), (2)  -.  -.  A. x  e.  On A. y  e.  On ( x  C_  y  \/  y  C_  x ), (3)  A. x  e.  On A. y  e.  On -.  -.  (
x  e.  y  \/  x  =  y  \/  y  e.  x ), (4)  A. x  e.  On A. y  e.  On -.  -.  (
x  C_  y  \/  y  C_  x ), and (5)  -.  -. EXMID. That these are all equivalent is expressed by (1) implies (3) (onntri13 7561), (3) implies (5) (onntri35 7560), (5) implies (1) (onntri51 7563), (2) implies (4) (onntri24 7565), (4) implies (5) (onntri45 7564), and (5) implies (2) (onntri52 7567).

Another way of stating this is that EXMID is equivalent to trichotomy, either the  x  e.  y  \/  x  =  y  \/  y  e.  x or the  x  C_  y  \/  y  C_  x form, as shown in exmidontri 7562 and exmidontri2or 7566, respectively. Thus  -.  -. EXMID is equivalent to (1) or (2). In addition, 
-.  -. EXMID is equivalent to (3) by onntri3or 7568 and (4) by onntri2or 7569.

(Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)

 |-  ( A. x  e. 
 On  A. y  e.  On  -. 
 -.  ( x  e.  y  \/  x  =  y  \/  y  e.  x )  ->  -.  -. EXMID )
 
Theoremonntri13 7561 Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
 |-  ( -.  -.  A. x  e.  On  A. y  e.  On  ( x  e.  y  \/  x  =  y  \/  y  e.  x )  ->  A. x  e.  On  A. y  e. 
 On  -.  -.  ( x  e.  y  \/  x  =  y  \/  y  e.  x )
 )
 
Theoremexmidontri 7562* Ordinal trichotomy is equivalent to excluded middle. (Contributed by Jim Kingdon, 26-Aug-2024.)
 |-  (EXMID  <->  A. x  e.  On  A. y  e.  On  ( x  e.  y  \/  x  =  y  \/  y  e.  x )
 )
 
Theoremonntri51 7563* Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
 |-  ( -.  -. EXMID  ->  -.  -.  A. x  e.  On  A. y  e.  On  ( x  e.  y  \/  x  =  y  \/  y  e.  x )
 )
 
Theoremonntri45 7564* Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
 |-  ( A. x  e. 
 On  A. y  e.  On  -. 
 -.  ( x  C_  y  \/  y  C_  x )  ->  -.  -. EXMID )
 
Theoremonntri24 7565 Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
 |-  ( -.  -.  A. x  e.  On  A. y  e.  On  ( x  C_  y  \/  y  C_  x )  ->  A. x  e.  On  A. y  e.  On  -.  -.  ( x  C_  y  \/  y  C_  x ) )
 
Theoremexmidontri2or 7566* Ordinal trichotomy is equivalent to excluded middle. (Contributed by Jim Kingdon, 26-Aug-2024.)
 |-  (EXMID  <->  A. x  e.  On  A. y  e.  On  ( x  C_  y  \/  y  C_  x ) )
 
Theoremonntri52 7567* Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
 |-  ( -.  -. EXMID  ->  -.  -.  A. x  e.  On  A. y  e.  On  ( x  C_  y  \/  y  C_  x ) )
 
Theoremonntri3or 7568* Double negated ordinal trichotomy. (Contributed by Jim Kingdon, 25-Aug-2024.)
 |-  ( -.  -. EXMID  <->  A. x  e.  On  A. y  e.  On  -.  -.  ( x  e.  y  \/  x  =  y  \/  y  e.  x ) )
 
Theoremonntri2or 7569* Double negated ordinal trichotomy. (Contributed by Jim Kingdon, 25-Aug-2024.)
 |-  ( -.  -. EXMID  <->  A. x  e.  On  A. y  e.  On  -.  -.  ( x  C_  y  \/  y  C_  x ) )
 
Theoremfmelpw1o 7570 With a formula  ph one can associate an element of 
~P 1o, which can therefore be thought of as the set of "truth values" (but recall that there are no other genuine truth values than T. and F., by nndc 859, which translate to  1o and  (/) respectively by iftrue 3631 and iffalse 3634, giving pwtrufal 16897).

As proved in if0ab 3627, the associated element of  ~P 1o is the extension, in  ~P 1o, of the formula  ph. (Contributed by BJ, 15-Aug-2024.) (Proof shortened by BJ, 5-May-2026.)

 |- 
 if ( ph ,  1o ,  (/) )  e.  ~P 1o
 
2.6.49  Apartness relations
 
Syntaxwap 7571 Apartness predicate symbol.
 wff  R Ap  A
 
Definitiondf-pap 7572* Apartness predicate. A relation  R is an apartness if it is irreflexive, symmetric, and cotransitive. (Contributed by Jim Kingdon, 14-Feb-2025.)
 |-  ( R Ap  A  <->  ( ( R 
 C_  ( A  X.  A )  /\  A. x  e.  A  -.  x R x )  /\  ( A. x  e.  A  A. y  e.  A  ( x R y  ->  y R x )  /\  A. x  e.  A  A. y  e.  A  A. z  e.  A  ( x R y  ->  ( x R z  \/  y R z ) ) ) ) )
 
Theorempapeq1 7573 Equality theorem for apartness predicate. (Contributed by Jim Kingdon, 3-Jun-2026.)
 |-  ( R  =  S  ->  ( R Ap  A  <->  S Ap  A )
 )
 
Theorempapeq2 7574 Equality theorem for apartness predicate. (Contributed by Jim Kingdon, 3-Jun-2026.)
 |-  ( A  =  B  ->  ( R Ap  A  <->  R Ap  B )
 )
 
Theorempapirr 7575 An apartness is irreflexive. (Contributed by Jim Kingdon, 27-May-2026.)
 |-  ( ( R Ap  A  /\  X  e.  A ) 
 ->  -.  X R X )
 
Theorempapsym 7576 An apartness is symmetric. (Contributed by Jim Kingdon, 27-May-2026.)
 |-  ( ph  ->  R Ap  A )   &    |-  ( ph  ->  X  e.  A )   &    |-  ( ph  ->  Y  e.  A )   &    |-  ( ph  ->  X R Y )   =>    |-  ( ph  ->  Y R X )
 
Theorempapcotr 7577 An apartness is cotransitive. (Contributed by Jim Kingdon, 28-May-2026.)
 |-  ( ph  ->  R Ap  A )   &    |-  ( ph  ->  X  e.  A )   &    |-  ( ph  ->  Y  e.  A )   &    |-  ( ph  ->  X R Y )   &    |-  ( ph  ->  Z  e.  A )   =>    |-  ( ph  ->  ( X R Z  \/  Y R Z ) )
 
Syntaxwtap 7578 Tight apartness predicate symbol.
 wff  R TAp  A
 
Definitiondf-tap 7579* Tight apartness predicate. A relation  R is a tight apartness if it is irreflexive, symmetric, cotransitive, and tight. (Contributed by Jim Kingdon, 5-Feb-2025.)
 |-  ( R TAp  A  <->  ( R Ap  A  /\  A. x  e.  A  A. y  e.  A  ( -.  x R y 
 ->  x  =  y
 ) ) )
 
Theoremtapap 7580 A tight apartness is an apartness. (Contributed by Jim Kingdon, 29-May-2026.)
 |-  ( R TAp  A  ->  R Ap 
 A )
 
Theoremdftap2 7581* Tight apartness with the apartness properties from df-pap 7572 expanded. (Contributed by Jim Kingdon, 21-Feb-2025.)
 |-  ( R TAp  A  <->  ( R  C_  ( A  X.  A ) 
 /\  ( A. x  e.  A  -.  x R x  /\  A. x  e.  A  A. y  e.  A  ( x R y  ->  y R x ) )  /\  ( A. x  e.  A  A. y  e.  A  A. z  e.  A  ( x R y  ->  ( x R z  \/  y R z ) ) 
 /\  A. x  e.  A  A. y  e.  A  ( -.  x R y 
 ->  x  =  y
 ) ) ) )
 
Theoremtapeq1 7582 Equality theorem for tight apartness predicate. (Contributed by Jim Kingdon, 8-Feb-2025.)
 |-  ( R  =  S  ->  ( R TAp  A  <->  S TAp  A )
 )
 
Theoremtapeq2 7583 Equality theorem for tight apartness predicate. (Contributed by Jim Kingdon, 15-Feb-2025.)
 |-  ( A  =  B  ->  ( R TAp  A  <->  R TAp  B )
 )
 
Theoremnetap 7584* Negated equality on a set with decidable equality is a tight apartness. (Contributed by Jim Kingdon, 5-Feb-2025.)
 |-  ( A. x  e.  A  A. y  e.  A DECID  x  =  y  ->  { <. u ,  v >.  |  ( ( u  e.  A  /\  v  e.  A )  /\  u  =/=  v ) } TAp  A )
 
Theorem2onetap 7585* Negated equality is a tight apartness on  2o. (Contributed by Jim Kingdon, 6-Feb-2025.)
 |- 
 { <. u ,  v >.  |  ( ( u  e.  2o  /\  v  e.  2o )  /\  u  =/=  v ) } TAp  2o
 
Theorem2oneel 7586*  (/) and  1o are two unequal elements of  2o. (Contributed by Jim Kingdon, 8-Feb-2025.)
 |- 
 <. (/) ,  1o >.  e. 
 { <. u ,  v >.  |  ( ( u  e.  2o  /\  v  e.  2o )  /\  u  =/=  v ) }
 
Theorem2omotaplemap 7587* Lemma for 2omotap 7589. (Contributed by Jim Kingdon, 6-Feb-2025.)
 |-  ( -.  -.  ph  ->  { <. u ,  v >.  |  ( ( u  e.  2o  /\  v  e.  2o )  /\  ( ph  /\  u  =/=  v
 ) ) } TAp  2o )
 
Theorem2omotaplemst 7588* Lemma for 2omotap 7589. (Contributed by Jim Kingdon, 6-Feb-2025.)
 |-  ( ( E* r  r TAp  2o  /\  -.  -.  ph )  ->  ph )
 
Theorem2omotap 7589 If there is at most one tight apartness on  2o, excluded middle follows. Based on online discussions by Tom de Jong, Andrew W Swan, and Martin Escardo. (Contributed by Jim Kingdon, 6-Feb-2025.)
 |-  ( E* r  r TAp 
 2o  -> EXMID
 )
 
Theoremexmidapne 7590* Excluded middle implies there is only one tight apartness on any class, namely negated equality. (Contributed by Jim Kingdon, 14-Feb-2025.)
 |-  (EXMID 
 ->  ( R TAp  A  <->  R  =  { <. u ,  v >.  |  ( ( u  e.  A  /\  v  e.  A )  /\  u  =/=  v ) } )
 )
 
Theoremexmidmotap 7591* The proposition that every class has at most one tight apartness is equivalent to excluded middle. (Contributed by Jim Kingdon, 14-Feb-2025.)
 |-  (EXMID  <->  A. x E* r  r TAp 
 x )
 
PART 3  CHOICE PRINCIPLES

We have already introduced the full Axiom of Choice df-ac 7526 but since it implies excluded middle as shown at exmidac 7529, it is not especially relevant to us. In this section we define countable choice and dependent choice, which are not as strong as thus often considered in mathematics which seeks to avoid full excluded middle.

 
3.1  Countable Choice and Dependent Choice
 
3.1.1  Introduce Countable Choice
 
Syntaxwacc 7592 Formula for an abbreviation of countable choice.
 wff CCHOICE
 
Definitiondf-cc 7593* The expression CCHOICE will be used as a readable shorthand for any form of countable choice, analogous to df-ac 7526 for full choice. (Contributed by Jim Kingdon, 27-Nov-2023.)
 |-  (CCHOICE  <->  A. x ( dom  x  ~~ 
 om  ->  E. f ( f 
 C_  x  /\  f  Fn  dom  x ) ) )
 
Theoremccfunen 7594* Existence of a choice function for a countably infinite set. (Contributed by Jim Kingdon, 28-Nov-2023.)
 |-  ( ph  -> CCHOICE )   &    |-  ( ph  ->  A 
 ~~  om )   &    |-  ( ph  ->  A. x  e.  A  E. w  w  e.  x )   =>    |-  ( ph  ->  E. f
 ( f  Fn  A  /\  A. x  e.  A  ( f `  x )  e.  x )
 )
 
Theoremcc1 7595* Countable choice in terms of a choice function on a countably infinite set of inhabited sets. (Contributed by Jim Kingdon, 27-Apr-2024.)
 |-  (CCHOICE 
 ->  A. x ( ( x  ~~  om  /\  A. z  e.  x  E. w  w  e.  z
 )  ->  E. f A. z  e.  x  ( f `  z
 )  e.  z ) )
 
Theoremcc2lem 7596* Lemma for cc2 7597. (Contributed by Jim Kingdon, 27-Apr-2024.)
 |-  ( ph  -> CCHOICE )   &    |-  ( ph  ->  F  Fn  om )   &    |-  ( ph  ->  A. x  e.  om  E. w  w  e.  ( F `  x ) )   &    |-  A  =  ( n  e.  om  |->  ( { n }  X.  ( F `  n ) ) )   &    |-  G  =  ( n  e.  om  |->  ( 2nd `  (
 f `  ( A `  n ) ) ) )   =>    |-  ( ph  ->  E. g
 ( g  Fn  om  /\ 
 A. n  e.  om  ( g `  n )  e.  ( F `  n ) ) )
 
Theoremcc2 7597* Countable choice using sequences instead of countable sets. (Contributed by Jim Kingdon, 27-Apr-2024.)
 |-  ( ph  -> CCHOICE )   &    |-  ( ph  ->  F  Fn  om )   &    |-  ( ph  ->  A. x  e.  om  E. w  w  e.  ( F `  x ) )   =>    |-  ( ph  ->  E. g
 ( g  Fn  om  /\ 
 A. n  e.  om  ( g `  n )  e.  ( F `  n ) ) )
 
Theoremcc3 7598* Countable choice using a sequence F(n) . (Contributed by Mario Carneiro, 8-Feb-2013.) (Revised by Jim Kingdon, 29-Apr-2024.)
 |-  ( ph  -> CCHOICE )   &    |-  ( ph  ->  A. n  e.  N  F  e.  _V )   &    |-  ( ph  ->  A. n  e.  N  E. w  w  e.  F )   &    |-  ( ph  ->  N  ~~ 
 om )   =>    |-  ( ph  ->  E. f
 ( f  Fn  N  /\  A. n  e.  N  ( f `  n )  e.  F )
 )
 
Theoremcc4f 7599* Countable choice by showing the existence of a function  f which can choose a value at each index 
n such that  ch holds. (Contributed by Mario Carneiro, 7-Apr-2013.) (Revised by Jim Kingdon, 3-May-2024.)
 |-  ( ph  -> CCHOICE )   &    |-  ( ph  ->  A  e.  V )   &    |-  F/_ n A   &    |-  ( ph  ->  N  ~~ 
 om )   &    |-  ( x  =  ( f `  n )  ->  ( ps  <->  ch ) )   &    |-  ( ph  ->  A. n  e.  N  E. x  e.  A  ps )   =>    |-  ( ph  ->  E. f
 ( f : N --> A  /\  A. n  e.  N  ch ) )
 
Theoremcc4 7600* Countable choice by showing the existence of a function  f which can choose a value at each index 
n such that  ch holds. (Contributed by Mario Carneiro, 7-Apr-2013.) (Revised by Jim Kingdon, 1-May-2024.)
 |-  ( ph  -> CCHOICE )   &    |-  ( ph  ->  A  e.  V )   &    |-  ( ph  ->  N  ~~  om )   &    |-  ( x  =  ( f `  n ) 
 ->  ( ps  <->  ch ) )   &    |-  ( ph  ->  A. n  e.  N  E. x  e.  A  ps )   =>    |-  ( ph  ->  E. f
 ( f : N --> A  /\  A. n  e.  N  ch ) )
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