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Theorem List for Intuitionistic Logic Explorer - 12801-12900   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Definitiondf-phi 12801* Define the Euler phi function (also called "Euler totient function"), which counts the number of integers less than  n and coprime to it, see definition in [ApostolNT] p. 25. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |- 
 phi  =  ( n  e.  NN  |->  ( `  { x  e.  ( 1 ... n )  |  ( x  gcd  n )  =  1 } ) )
 
Theoremphivalfi 12802* Finiteness of an expression used to define the Euler  phi function. (Contributed by Jim Kingon, 28-May-2022.)
 |-  ( N  e.  NN  ->  { x  e.  (
 1 ... N )  |  ( x  gcd  N )  =  1 }  e.  Fin )
 
Theoremphival 12803* Value of the Euler  phi function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( N  e.  NN  ->  ( phi `  N )  =  ( `  { x  e.  ( 1 ... N )  |  ( x  gcd  N )  =  1 } ) )
 
Theoremphicl2 12804 Bounds and closure for the value of the Euler  phi function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( N  e.  NN  ->  ( phi `  N )  e.  ( 1 ... N ) )
 
Theoremphicl 12805 Closure for the value of the Euler 
phi function. (Contributed by Mario Carneiro, 28-Feb-2014.)
 |-  ( N  e.  NN  ->  ( phi `  N )  e.  NN )
 
Theoremphibndlem 12806* Lemma for phibnd 12807. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( N  e.  ( ZZ>=
 `  2 )  ->  { x  e.  (
 1 ... N )  |  ( x  gcd  N )  =  1 }  C_  ( 1 ... ( N  -  1 ) ) )
 
Theoremphibnd 12807 A slightly tighter bound on the value of the Euler  phi function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( N  e.  ( ZZ>=
 `  2 )  ->  ( phi `  N )  <_  ( N  -  1
 ) )
 
Theoremphicld 12808 Closure for the value of the Euler 
phi function. (Contributed by Mario Carneiro, 29-May-2016.)
 |-  ( ph  ->  N  e.  NN )   =>    |-  ( ph  ->  ( phi `  N )  e. 
 NN )
 
Theoremphi1 12809 Value of the Euler  phi function at 1. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( phi `  1
 )  =  1
 
Theoremdfphi2 12810* Alternate definition of the Euler 
phi function. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by Mario Carneiro, 2-May-2016.)
 |-  ( N  e.  NN  ->  ( phi `  N )  =  ( `  { x  e.  ( 0..^ N )  |  ( x  gcd  N )  =  1 } ) )
 
Theoremhashdvds 12811* The number of numbers in a given residue class in a finite set of integers. (Contributed by Mario Carneiro, 12-Mar-2014.) (Proof shortened by Mario Carneiro, 7-Jun-2016.)
 |-  ( ph  ->  N  e.  NN )   &    |-  ( ph  ->  A  e.  ZZ )   &    |-  ( ph  ->  B  e.  ( ZZ>=
 `  ( A  -  1 ) ) )   &    |-  ( ph  ->  C  e.  ZZ )   =>    |-  ( ph  ->  ( ` 
 { x  e.  ( A ... B )  |  N  ||  ( x  -  C ) } )  =  ( ( |_ `  (
 ( B  -  C )  /  N ) )  -  ( |_ `  (
 ( ( A  -  1 )  -  C )  /  N ) ) ) )
 
Theoremphiprmpw 12812 Value of the Euler  phi function at a prime power. Theorem 2.5(a) in [ApostolNT] p. 28. (Contributed by Mario Carneiro, 24-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  K  e.  NN )  ->  ( phi `  ( P ^ K ) )  =  ( ( P ^ ( K  -  1 ) )  x.  ( P  -  1
 ) ) )
 
Theoremphiprm 12813 Value of the Euler  phi function at a prime. (Contributed by Mario Carneiro, 28-Feb-2014.)
 |-  ( P  e.  Prime  ->  ( phi `  P )  =  ( P  -  1
 ) )
 
Theoremcrth 12814* The Chinese Remainder Theorem: the function that maps  x to its remainder classes  mod  M and  mod  N is 1-1 and onto when  M and  N are coprime. (Contributed by Mario Carneiro, 24-Feb-2014.) (Proof shortened by Mario Carneiro, 2-May-2016.)
 |-  S  =  ( 0..^ ( M  x.  N ) )   &    |-  T  =  ( ( 0..^ M )  X.  ( 0..^ N ) )   &    |-  F  =  ( x  e.  S  |->  <.
 ( x  mod  M ) ,  ( x  mod  N ) >. )   &    |-  ( ph  ->  ( M  e.  NN  /\  N  e.  NN  /\  ( M  gcd  N )  =  1 )
 )   =>    |-  ( ph  ->  F : S -1-1-onto-> T )
 
Theoremphimullem 12815* Lemma for phimul 12816. (Contributed by Mario Carneiro, 24-Feb-2014.)
 |-  S  =  ( 0..^ ( M  x.  N ) )   &    |-  T  =  ( ( 0..^ M )  X.  ( 0..^ N ) )   &    |-  F  =  ( x  e.  S  |->  <.
 ( x  mod  M ) ,  ( x  mod  N ) >. )   &    |-  ( ph  ->  ( M  e.  NN  /\  N  e.  NN  /\  ( M  gcd  N )  =  1 )
 )   &    |-  U  =  { y  e.  ( 0..^ M )  |  ( y  gcd  M )  =  1 }   &    |-  V  =  { y  e.  ( 0..^ N )  |  ( y  gcd  N )  =  1 }   &    |-  W  =  { y  e.  S  |  ( y 
 gcd  ( M  x.  N ) )  =  1 }   =>    |-  ( ph  ->  ( phi `  ( M  x.  N ) )  =  ( ( phi `  M )  x.  ( phi `  N ) ) )
 
Theoremphimul 12816 The Euler  phi function is a multiplicative function, meaning that it distributes over multiplication at relatively prime arguments. Theorem 2.5(c) in [ApostolNT] p. 28. (Contributed by Mario Carneiro, 24-Feb-2014.)
 |-  ( ( M  e.  NN  /\  N  e.  NN  /\  ( M  gcd  N )  =  1 )  ->  ( phi `  ( M  x.  N ) )  =  ( ( phi `  M )  x.  ( phi `  N ) ) )
 
Theoremeulerthlem1 12817* Lemma for eulerth 12823. (Contributed by Mario Carneiro, 8-May-2015.)
 |-  ( ph  ->  ( N  e.  NN  /\  A  e.  ZZ  /\  ( A 
 gcd  N )  =  1 ) )   &    |-  S  =  {
 y  e.  ( 0..^ N )  |  ( y  gcd  N )  =  1 }   &    |-  T  =  ( 1 ... ( phi `  N ) )   &    |-  ( ph  ->  F : T
 -1-1-onto-> S )   &    |-  G  =  ( x  e.  T  |->  ( ( A  x.  ( F `  x ) ) 
 mod  N ) )   =>    |-  ( ph  ->  G : T --> S )
 
Theoremeulerthlemfi 12818* Lemma for eulerth 12823. The set  S is finite. (Contributed by Mario Carneiro, 28-Feb-2014.) (Revised by Jim Kingdon, 7-Sep-2024.)
 |-  ( ph  ->  ( N  e.  NN  /\  A  e.  ZZ  /\  ( A 
 gcd  N )  =  1 ) )   &    |-  S  =  {
 y  e.  ( 0..^ N )  |  ( y  gcd  N )  =  1 }   =>    |-  ( ph  ->  S  e.  Fin )
 
Theoremeulerthlemrprm 12819* Lemma for eulerth 12823. 
N and  prod_ x  e.  ( 1 ... ( phi `  N ) ) ( F `  x
) are relatively prime. (Contributed by Mario Carneiro, 28-Feb-2014.) (Revised by Jim Kingdon, 2-Sep-2024.)
 |-  ( ph  ->  ( N  e.  NN  /\  A  e.  ZZ  /\  ( A 
 gcd  N )  =  1 ) )   &    |-  S  =  {
 y  e.  ( 0..^ N )  |  ( y  gcd  N )  =  1 }   &    |-  ( ph  ->  F : ( 1 ... ( phi `  N ) ) -1-1-onto-> S )   =>    |-  ( ph  ->  ( N  gcd  prod_ x  e.  (
 1 ... ( phi `  N ) ) ( F `
  x ) )  =  1 )
 
Theoremeulerthlema 12820* Lemma for eulerth 12823. (Contributed by Mario Carneiro, 28-Feb-2014.) (Revised by Jim Kingdon, 2-Sep-2024.)
 |-  ( ph  ->  ( N  e.  NN  /\  A  e.  ZZ  /\  ( A 
 gcd  N )  =  1 ) )   &    |-  S  =  {
 y  e.  ( 0..^ N )  |  ( y  gcd  N )  =  1 }   &    |-  ( ph  ->  F : ( 1 ... ( phi `  N ) ) -1-1-onto-> S )   =>    |-  ( ph  ->  ( (
 ( A ^ ( phi `  N ) )  x.  prod_ x  e.  (
 1 ... ( phi `  N ) ) ( F `
  x ) ) 
 mod  N )  =  (
 prod_ x  e.  (
 1 ... ( phi `  N ) ) ( ( A  x.  ( F `
  x ) ) 
 mod  N )  mod  N ) )
 
Theoremeulerthlemh 12821* Lemma for eulerth 12823. A permutation of  ( 1 ... ( phi `  N ) ). (Contributed by Mario Carneiro, 28-Feb-2014.) (Revised by Jim Kingdon, 5-Sep-2024.)
 |-  ( ph  ->  ( N  e.  NN  /\  A  e.  ZZ  /\  ( A 
 gcd  N )  =  1 ) )   &    |-  S  =  {
 y  e.  ( 0..^ N )  |  ( y  gcd  N )  =  1 }   &    |-  ( ph  ->  F : ( 1 ... ( phi `  N ) ) -1-1-onto-> S )   &    |-  H  =  ( `' F  o.  ( y  e.  ( 1 ... ( phi `  N ) ) 
 |->  ( ( A  x.  ( F `  y ) )  mod  N ) ) )   =>    |-  ( ph  ->  H : ( 1 ... ( phi `  N ) ) -1-1-onto-> ( 1 ... ( phi `  N ) ) )
 
Theoremeulerthlemth 12822* Lemma for eulerth 12823. The result. (Contributed by Mario Carneiro, 28-Feb-2014.) (Revised by Jim Kingdon, 2-Sep-2024.)
 |-  ( ph  ->  ( N  e.  NN  /\  A  e.  ZZ  /\  ( A 
 gcd  N )  =  1 ) )   &    |-  S  =  {
 y  e.  ( 0..^ N )  |  ( y  gcd  N )  =  1 }   &    |-  ( ph  ->  F : ( 1 ... ( phi `  N ) ) -1-1-onto-> S )   =>    |-  ( ph  ->  ( ( A ^ ( phi `  N ) )  mod  N )  =  ( 1  mod 
 N ) )
 
Theoremeulerth 12823 Euler's theorem, a generalization of Fermat's little theorem. If  A and  N are coprime, then  A ^ phi ( N )  ==  1 (mod  N). This is Metamath 100 proof #10. Also called Euler-Fermat theorem, see theorem 5.17 in [ApostolNT] p. 113. (Contributed by Mario Carneiro, 28-Feb-2014.)
 |-  ( ( N  e.  NN  /\  A  e.  ZZ  /\  ( A  gcd  N )  =  1 )  ->  ( ( A ^
 ( phi `  N ) )  mod  N )  =  ( 1  mod 
 N ) )
 
Theoremfermltl 12824 Fermat's little theorem. When  P is prime,  A ^ P  ==  A (mod  P) for any  A, see theorem 5.19 in [ApostolNT] p. 114. (Contributed by Mario Carneiro, 28-Feb-2014.) (Proof shortened by AV, 19-Mar-2022.)
 |-  ( ( P  e.  Prime  /\  A  e.  ZZ )  ->  ( ( A ^ P )  mod  P )  =  ( A 
 mod  P ) )
 
Theoremprmdiv 12825 Show an explicit expression for the modular inverse of  A  mod  P. (Contributed by Mario Carneiro, 24-Jan-2015.)
 |-  R  =  ( ( A ^ ( P  -  2 ) ) 
 mod  P )   =>    |-  ( ( P  e.  Prime  /\  A  e.  ZZ  /\ 
 -.  P  ||  A )  ->  ( R  e.  ( 1 ... ( P  -  1 ) ) 
 /\  P  ||  (
 ( A  x.  R )  -  1 ) ) )
 
Theoremprmdiveq 12826 The modular inverse of  A  mod  P is unique. (Contributed by Mario Carneiro, 24-Jan-2015.)
 |-  R  =  ( ( A ^ ( P  -  2 ) ) 
 mod  P )   =>    |-  ( ( P  e.  Prime  /\  A  e.  ZZ  /\ 
 -.  P  ||  A )  ->  ( ( S  e.  ( 0 ... ( P  -  1
 ) )  /\  P  ||  ( ( A  x.  S )  -  1
 ) )  <->  S  =  R ) )
 
Theoremprmdivdiv 12827 The (modular) inverse of the inverse of a number is itself. (Contributed by Mario Carneiro, 24-Jan-2015.)
 |-  R  =  ( ( A ^ ( P  -  2 ) ) 
 mod  P )   =>    |-  ( ( P  e.  Prime  /\  A  e.  (
 1 ... ( P  -  1 ) ) ) 
 ->  A  =  ( ( R ^ ( P  -  2 ) ) 
 mod  P ) )
 
Theoremhashgcdlem 12828* A correspondence between elements of specific GCD and relative primes in a smaller ring. (Contributed by Stefan O'Rear, 12-Sep-2015.)
 |-  A  =  { y  e.  ( 0..^ ( M 
 /  N ) )  |  ( y  gcd  ( M  /  N ) )  =  1 }   &    |-  B  =  { z  e.  ( 0..^ M )  |  ( z  gcd  M )  =  N }   &    |-  F  =  ( x  e.  A  |->  ( x  x.  N ) )   =>    |-  ( ( M  e.  NN  /\  N  e.  NN  /\  N  ||  M )  ->  F : A -1-1-onto-> B )
 
Theoremdvdsfi 12829* A natural number has finitely many divisors. (Contributed by Jim Kingdon, 9-Oct-2025.)
 |-  ( N  e.  NN  ->  { x  e.  NN  |  x  ||  N }  e.  Fin )
 
Theoremhashgcdeq 12830* Number of initial positive integers with specified divisors. (Contributed by Stefan O'Rear, 12-Sep-2015.)
 |-  ( ( M  e.  NN  /\  N  e.  NN )  ->  ( `  { x  e.  ( 0..^ M )  |  ( x  gcd  M )  =  N }
 )  =  if ( N  ||  M ,  ( phi `  ( M  /  N ) ) ,  0 ) )
 
Theoremphisum 12831* The divisor sum identity of the totient function. Theorem 2.2 in [ApostolNT] p. 26. (Contributed by Stefan O'Rear, 12-Sep-2015.)
 |-  ( N  e.  NN  -> 
 sum_ d  e.  { x  e.  NN  |  x  ||  N }  ( phi `  d )  =  N )
 
Theoremodzval 12832* Value of the order function. This is a function of functions; the inner argument selects the base (i.e., mod  N for some  N, often prime) and the outer argument selects the integer or equivalence class (if you want to think about it that way) from the integers mod  N. In order to ensure the supremum is well-defined, we only define the expression when  A and  N are coprime. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by AV, 26-Sep-2020.)
 |-  ( ( N  e.  NN  /\  A  e.  ZZ  /\  ( A  gcd  N )  =  1 )  ->  ( ( odZ `  N ) `  A )  = inf ( { n  e.  NN  |  N  ||  ( ( A ^ n )  -  1
 ) } ,  RR ,  <  ) )
 
Theoremodzcllem 12833 - Lemma for odzcl 12834, showing existence of a recurrent point for the exponential. (Contributed by Mario Carneiro, 28-Feb-2014.) (Proof shortened by AV, 26-Sep-2020.)
 |-  ( ( N  e.  NN  /\  A  e.  ZZ  /\  ( A  gcd  N )  =  1 )  ->  ( ( ( odZ `  N ) `  A )  e.  NN  /\  N  ||  ( ( A ^ ( ( odZ `  N ) `  A ) )  -  1 ) ) )
 
Theoremodzcl 12834 The order of a group element is an integer. (Contributed by Mario Carneiro, 28-Feb-2014.)
 |-  ( ( N  e.  NN  /\  A  e.  ZZ  /\  ( A  gcd  N )  =  1 )  ->  ( ( odZ `  N ) `  A )  e.  NN )
 
Theoremodzid 12835 Any element raised to the power of its order is  1. (Contributed by Mario Carneiro, 28-Feb-2014.)
 |-  ( ( N  e.  NN  /\  A  e.  ZZ  /\  ( A  gcd  N )  =  1 )  ->  N  ||  ( ( A ^ ( ( odZ `  N ) `  A ) )  -  1 ) )
 
Theoremodzdvds 12836 The only powers of  A that are congruent to  1 are the multiples of the order of  A. (Contributed by Mario Carneiro, 28-Feb-2014.) (Proof shortened by AV, 26-Sep-2020.)
 |-  ( ( ( N  e.  NN  /\  A  e.  ZZ  /\  ( A 
 gcd  N )  =  1 )  /\  K  e.  NN0 )  ->  ( N  ||  ( ( A ^ K )  -  1
 ) 
 <->  ( ( odZ `  N ) `  A )  ||  K ) )
 
Theoremodzphi 12837 The order of any group element is a divisor of the Euler  phi function. (Contributed by Mario Carneiro, 28-Feb-2014.)
 |-  ( ( N  e.  NN  /\  A  e.  ZZ  /\  ( A  gcd  N )  =  1 )  ->  ( ( odZ `  N ) `  A )  ||  ( phi `  N ) )
 
5.2.6  Arithmetic modulo a prime number
 
Theoremmodprm1div 12838 A prime number divides an integer minus 1 iff the integer modulo the prime number is 1. (Contributed by Alexander van der Vekens, 17-May-2018.) (Proof shortened by AV, 30-May-2023.)
 |-  ( ( P  e.  Prime  /\  A  e.  ZZ )  ->  ( ( A 
 mod  P )  =  1  <->  P  ||  ( A  -  1 ) ) )
 
Theoremm1dvdsndvds 12839 If an integer minus 1 is divisible by a prime number, the integer itself is not divisible by this prime number. (Contributed by Alexander van der Vekens, 30-Aug-2018.)
 |-  ( ( P  e.  Prime  /\  A  e.  ZZ )  ->  ( P  ||  ( A  -  1
 )  ->  -.  P  ||  A ) )
 
Theoremmodprminv 12840 Show an explicit expression for the modular inverse of  A  mod  P. This is an application of prmdiv 12825. (Contributed by Alexander van der Vekens, 15-May-2018.)
 |-  R  =  ( ( A ^ ( P  -  2 ) ) 
 mod  P )   =>    |-  ( ( P  e.  Prime  /\  A  e.  ZZ  /\ 
 -.  P  ||  A )  ->  ( R  e.  ( 1 ... ( P  -  1 ) ) 
 /\  ( ( A  x.  R )  mod  P )  =  1 ) )
 
Theoremmodprminveq 12841 The modular inverse of  A  mod  P is unique. (Contributed by Alexander van der Vekens, 17-May-2018.)
 |-  R  =  ( ( A ^ ( P  -  2 ) ) 
 mod  P )   =>    |-  ( ( P  e.  Prime  /\  A  e.  ZZ  /\ 
 -.  P  ||  A )  ->  ( ( S  e.  ( 0 ... ( P  -  1
 ) )  /\  (
 ( A  x.  S )  mod  P )  =  1 )  <->  S  =  R ) )
 
Theoremvfermltl 12842 Variant of Fermat's little theorem if  A is not a multiple of  P, see theorem 5.18 in [ApostolNT] p. 113. (Contributed by AV, 21-Aug-2020.) (Proof shortened by AV, 5-Sep-2020.)
 |-  ( ( P  e.  Prime  /\  A  e.  ZZ  /\ 
 -.  P  ||  A )  ->  ( ( A ^ ( P  -  1 ) )  mod  P )  =  1 )
 
Theorempowm2modprm 12843 If an integer minus 1 is divisible by a prime number, then the integer to the power of the prime number minus 2 is 1 modulo the prime number. (Contributed by Alexander van der Vekens, 30-Aug-2018.)
 |-  ( ( P  e.  Prime  /\  A  e.  ZZ )  ->  ( P  ||  ( A  -  1
 )  ->  ( ( A ^ ( P  -  2 ) )  mod  P )  =  1 ) )
 
Theoremreumodprminv 12844* For any prime number and for any positive integer less than this prime number, there is a unique modular inverse of this positive integer. (Contributed by Alexander van der Vekens, 12-May-2018.)
 |-  ( ( P  e.  Prime  /\  N  e.  (
 1..^ P ) ) 
 ->  E! i  e.  (
 1 ... ( P  -  1 ) ) ( ( N  x.  i
 )  mod  P )  =  1 )
 
Theoremmodprm0 12845* For two positive integers less than a given prime number there is always a nonnegative integer (less than the given prime number) so that the sum of one of the two positive integers and the other of the positive integers multiplied by the nonnegative integer is 0 ( modulo the given prime number). (Contributed by Alexander van der Vekens, 17-May-2018.)
 |-  ( ( P  e.  Prime  /\  N  e.  (
 1..^ P )  /\  I  e.  ( 1..^ P ) )  ->  E. j  e.  (
 0..^ P ) ( ( I  +  (
 j  x.  N ) )  mod  P )  =  0 )
 
Theoremnnnn0modprm0 12846* For a positive integer and a nonnegative integer both less than a given prime number there is always a second nonnegative integer (less than the given prime number) so that the sum of this second nonnegative integer multiplied with the positive integer and the first nonnegative integer is 0 ( modulo the given prime number). (Contributed by Alexander van der Vekens, 8-Nov-2018.)
 |-  ( ( P  e.  Prime  /\  N  e.  (
 1..^ P )  /\  I  e.  ( 0..^ P ) )  ->  E. j  e.  (
 0..^ P ) ( ( I  +  (
 j  x.  N ) )  mod  P )  =  0 )
 
Theoremmodprmn0modprm0 12847* For an integer not being 0 modulo a given prime number and a nonnegative integer less than the prime number, there is always a second nonnegative integer (less than the given prime number) so that the sum of this second nonnegative integer multiplied with the integer and the first nonnegative integer is 0 ( modulo the given prime number). (Contributed by Alexander van der Vekens, 10-Nov-2018.)
 |-  ( ( P  e.  Prime  /\  N  e.  ZZ  /\  ( N  mod  P )  =/=  0 )  ->  ( I  e.  (
 0..^ P )  ->  E. j  e.  (
 0..^ P ) ( ( I  +  (
 j  x.  N ) )  mod  P )  =  0 ) )
 
5.2.7  Pythagorean Triples
 
Theoremcoprimeprodsq 12848 If three numbers are coprime, and the square of one is the product of the other two, then there is a formula for the other two in terms of  gcd and square. (Contributed by Scott Fenton, 2-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN0  /\  B  e.  ZZ  /\  C  e.  NN0 )  /\  ( ( A 
 gcd  B )  gcd  C )  =  1 )  ->  ( ( C ^
 2 )  =  ( A  x.  B ) 
 ->  A  =  ( ( A  gcd  C ) ^ 2 ) ) )
 
Theoremcoprimeprodsq2 12849 If three numbers are coprime, and the square of one is the product of the other two, then there is a formula for the other two in terms of  gcd and square. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  ZZ  /\  B  e.  NN0  /\  C  e.  NN0 )  /\  ( ( A  gcd  B ) 
 gcd  C )  =  1 )  ->  ( ( C ^ 2 )  =  ( A  x.  B )  ->  B  =  ( ( B  gcd  C ) ^ 2 ) ) )
 
Theoremoddprm 12850 A prime not equal to  2 is odd. (Contributed by Mario Carneiro, 4-Feb-2015.) (Proof shortened by AV, 10-Jul-2022.)
 |-  ( N  e.  ( Prime  \  { 2 } )  ->  ( ( N  -  1 )  / 
 2 )  e.  NN )
 
Theoremnnoddn2prm 12851 A prime not equal to  2 is an odd positive integer. (Contributed by AV, 28-Jun-2021.)
 |-  ( N  e.  ( Prime  \  { 2 } )  ->  ( N  e.  NN  /\  -.  2  ||  N ) )
 
Theoremoddn2prm 12852 A prime not equal to  2 is odd. (Contributed by AV, 28-Jun-2021.)
 |-  ( N  e.  ( Prime  \  { 2 } )  ->  -.  2  ||  N )
 
Theoremnnoddn2prmb 12853 A number is a prime number not equal to  2 iff it is an odd prime number. Conversion theorem for two representations of odd primes. (Contributed by AV, 14-Jul-2021.)
 |-  ( N  e.  ( Prime  \  { 2 } )  <->  ( N  e.  Prime  /\  -.  2  ||  N ) )
 
Theoremprm23lt5 12854 A prime less than 5 is either 2 or 3. (Contributed by AV, 5-Jul-2021.)
 |-  ( ( P  e.  Prime  /\  P  <  5
 )  ->  ( P  =  2  \/  P  =  3 ) )
 
Theoremprm23ge5 12855 A prime is either 2 or 3 or greater than or equal to 5. (Contributed by AV, 5-Jul-2021.)
 |-  ( P  e.  Prime  ->  ( P  =  2  \/  P  =  3  \/  P  e.  ( ZZ>= `  5 ) ) )
 
Theorempythagtriplem1 12856* Lemma for pythagtrip 12874. Prove a weaker version of one direction of the theorem. (Contributed by Scott Fenton, 28-Mar-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( E. n  e. 
 NN  E. m  e.  NN  E. k  e.  NN  ( A  =  ( k  x.  ( ( m ^
 2 )  -  ( n ^ 2 ) ) )  /\  B  =  ( k  x.  (
 2  x.  ( m  x.  n ) ) )  /\  C  =  ( k  x.  (
 ( m ^ 2
 )  +  ( n ^ 2 ) ) ) )  ->  (
 ( A ^ 2
 )  +  ( B ^ 2 ) )  =  ( C ^
 2 ) )
 
Theorempythagtriplem2 12857* Lemma for pythagtrip 12874. Prove the full version of one direction of the theorem. (Contributed by Scott Fenton, 28-Mar-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( A  e.  NN  /\  B  e.  NN )  ->  ( E. n  e.  NN  E. m  e. 
 NN  E. k  e.  NN  ( { A ,  B }  =  { (
 k  x.  ( ( m ^ 2 )  -  ( n ^
 2 ) ) ) ,  ( k  x.  ( 2  x.  ( m  x.  n ) ) ) }  /\  C  =  ( k  x.  (
 ( m ^ 2
 )  +  ( n ^ 2 ) ) ) )  ->  (
 ( A ^ 2
 )  +  ( B ^ 2 ) )  =  ( C ^
 2 ) ) )
 
Theorempythagtriplem3 12858 Lemma for pythagtrip 12874. Show that  C and 
B are relatively prime under some conditions. (Contributed by Scott Fenton, 8-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  ( B  gcd  C )  =  1 )
 
Theorempythagtriplem4 12859 Lemma for pythagtrip 12874. Show that  C  -  B and  C  +  B are relatively prime. (Contributed by Scott Fenton, 12-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  ( ( C  -  B )  gcd  ( C  +  B ) )  =  1 )
 
Theorempythagtriplem10 12860 Lemma for pythagtrip 12874. Show that  C  -  B is positive. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 ) )  ->  0  <  ( C  -  B ) )
 
Theorempythagtriplem6 12861 Lemma for pythagtrip 12874. Calculate  ( sqr `  ( C  -  B ) ). (Contributed by Scott Fenton, 18-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  ( sqr `  ( C  -  B ) )  =  ( ( C  -  B )  gcd  A ) )
 
Theorempythagtriplem7 12862 Lemma for pythagtrip 12874. Calculate  ( sqr `  ( C  +  B ) ). (Contributed by Scott Fenton, 18-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  ( sqr `  ( C  +  B ) )  =  ( ( C  +  B )  gcd  A ) )
 
Theorempythagtriplem8 12863 Lemma for pythagtrip 12874. Show that  ( sqr `  ( C  -  B ) ) is a positive integer. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  ( sqr `  ( C  -  B ) )  e. 
 NN )
 
Theorempythagtriplem9 12864 Lemma for pythagtrip 12874. Show that  ( sqr `  ( C  +  B ) ) is a positive integer. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  ( sqr `  ( C  +  B ) )  e. 
 NN )
 
Theorempythagtriplem11 12865 Lemma for pythagtrip 12874. Show that  M (which will eventually be closely related to the  m in the final statement) is a natural. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  M  =  ( ( ( sqr `  ( C  +  B )
 )  +  ( sqr `  ( C  -  B ) ) )  / 
 2 )   =>    |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  M  e.  NN )
 
Theorempythagtriplem12 12866 Lemma for pythagtrip 12874. Calculate the square of  M. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  M  =  ( ( ( sqr `  ( C  +  B )
 )  +  ( sqr `  ( C  -  B ) ) )  / 
 2 )   =>    |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  ( M ^ 2 )  =  ( ( C  +  A )  / 
 2 ) )
 
Theorempythagtriplem13 12867 Lemma for pythagtrip 12874. Show that  N (which will eventually be closely related to the  n in the final statement) is a natural. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  N  =  ( ( ( sqr `  ( C  +  B )
 )  -  ( sqr `  ( C  -  B ) ) )  / 
 2 )   =>    |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  N  e.  NN )
 
Theorempythagtriplem14 12868 Lemma for pythagtrip 12874. Calculate the square of  N. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  N  =  ( ( ( sqr `  ( C  +  B )
 )  -  ( sqr `  ( C  -  B ) ) )  / 
 2 )   =>    |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  ( N ^ 2 )  =  ( ( C  -  A )  / 
 2 ) )
 
Theorempythagtriplem15 12869 Lemma for pythagtrip 12874. Show the relationship between  M,  N, and  A. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  M  =  ( ( ( sqr `  ( C  +  B )
 )  +  ( sqr `  ( C  -  B ) ) )  / 
 2 )   &    |-  N  =  ( ( ( sqr `  ( C  +  B )
 )  -  ( sqr `  ( C  -  B ) ) )  / 
 2 )   =>    |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  A  =  ( ( M ^ 2 )  -  ( N ^ 2 ) ) )
 
Theorempythagtriplem16 12870 Lemma for pythagtrip 12874. Show the relationship between  M,  N, and  B. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  M  =  ( ( ( sqr `  ( C  +  B )
 )  +  ( sqr `  ( C  -  B ) ) )  / 
 2 )   &    |-  N  =  ( ( ( sqr `  ( C  +  B )
 )  -  ( sqr `  ( C  -  B ) ) )  / 
 2 )   =>    |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  B  =  ( 2  x.  ( M  x.  N ) ) )
 
Theorempythagtriplem17 12871 Lemma for pythagtrip 12874. Show the relationship between  M,  N, and  C. (Contributed by Scott Fenton, 17-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  M  =  ( ( ( sqr `  ( C  +  B )
 )  +  ( sqr `  ( C  -  B ) ) )  / 
 2 )   &    |-  N  =  ( ( ( sqr `  ( C  +  B )
 )  -  ( sqr `  ( C  -  B ) ) )  / 
 2 )   =>    |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  C  =  ( ( M ^ 2 )  +  ( N ^ 2 ) ) )
 
Theorempythagtriplem18 12872* Lemma for pythagtrip 12874. Wrap the previous  M and  N up in quantifiers. (Contributed by Scott Fenton, 18-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  ( ( A  gcd  B )  =  1  /\  -.  2  ||  A ) )  ->  E. n  e.  NN  E. m  e.  NN  ( A  =  ( ( m ^ 2 )  -  ( n ^ 2 ) )  /\  B  =  ( 2  x.  ( m  x.  n ) ) 
 /\  C  =  ( ( m ^ 2
 )  +  ( n ^ 2 ) ) ) )
 
Theorempythagtriplem19 12873* Lemma for pythagtrip 12874. Introduce  k and remove the relative primality requirement. (Contributed by Scott Fenton, 18-Apr-2014.) (Revised by Mario Carneiro, 19-Apr-2014.)
 |-  ( ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  /\  ( ( A ^ 2 )  +  ( B ^
 2 ) )  =  ( C ^ 2
 )  /\  -.  2  ||  ( A  /  ( A  gcd  B ) ) )  ->  E. n  e.  NN  E. m  e. 
 NN  E. k  e.  NN  ( A  =  (
 k  x.  ( ( m ^ 2 )  -  ( n ^
 2 ) ) ) 
 /\  B  =  ( k  x.  ( 2  x.  ( m  x.  n ) ) ) 
 /\  C  =  ( k  x.  ( ( m ^ 2 )  +  ( n ^
 2 ) ) ) ) )
 
Theorempythagtrip 12874* Parameterize the Pythagorean triples. If  A,  B, and  C are naturals, then they obey the Pythagorean triple formula iff they are parameterized by three naturals. This proof follows the Isabelle proof at http://afp.sourceforge.net/entries/Fermat3_4.shtml. This is Metamath 100 proof #23. (Contributed by Scott Fenton, 19-Apr-2014.)
 |-  ( ( A  e.  NN  /\  B  e.  NN  /\  C  e.  NN )  ->  ( ( ( A ^ 2 )  +  ( B ^ 2 ) )  =  ( C ^ 2 )  <->  E. n  e.  NN  E. m  e.  NN  E. k  e.  NN  ( { A ,  B }  =  { ( k  x.  ( ( m ^
 2 )  -  ( n ^ 2 ) ) ) ,  ( k  x.  ( 2  x.  ( m  x.  n ) ) ) }  /\  C  =  ( k  x.  ( ( m ^ 2 )  +  ( n ^ 2 ) ) ) ) ) )
 
5.2.8  The prime count function
 
Syntaxcpc 12875 Extend class notation with the prime count function.
 class  pCnt
 
Definitiondf-pc 12876* Define the prime count function, which returns the largest exponent of a given prime (or other positive integer) that divides the number. For rational numbers, it returns negative values according to the power of a prime in the denominator. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |- 
 pCnt  =  ( p  e.  Prime ,  r  e. 
 QQ  |->  if ( r  =  0 , +oo ,  ( iota z E. x  e.  ZZ  E. y  e. 
 NN  ( r  =  ( x  /  y
 )  /\  z  =  ( sup ( { n  e.  NN0  |  ( p ^ n )  ||  x } ,  RR ,  <  )  -  sup ( { n  e.  NN0  |  ( p ^ n ) 
 ||  y } ,  RR ,  <  ) ) ) ) ) )
 
Theorempclem0 12877* Lemma for the prime power pre-function's properties. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by Jim Kingdon, 7-Oct-2024.)
 |-  A  =  { n  e.  NN0  |  ( P ^ n )  ||  N }   =>    |-  ( ( P  e.  ( ZZ>= `  2 )  /\  ( N  e.  ZZ  /\  N  =/=  0 ) )  ->  0  e.  A )
 
Theorempclemub 12878* Lemma for the prime power pre-function's properties. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by Jim Kingdon, 7-Oct-2024.)
 |-  A  =  { n  e.  NN0  |  ( P ^ n )  ||  N }   =>    |-  ( ( P  e.  ( ZZ>= `  2 )  /\  ( N  e.  ZZ  /\  N  =/=  0 ) )  ->  E. x  e.  ZZ  A. y  e.  A  y  <_  x )
 
Theorempclemdc 12879* Lemma for the prime power pre-function's properties. (Contributed by Jim Kingdon, 8-Oct-2024.)
 |-  A  =  { n  e.  NN0  |  ( P ^ n )  ||  N }   =>    |-  ( ( P  e.  ( ZZ>= `  2 )  /\  ( N  e.  ZZ  /\  N  =/=  0 ) )  ->  A. x  e. 
 ZZ DECID  x  e.  A )
 
Theorempcprecl 12880* Closure of the prime power pre-function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  A  =  { n  e.  NN0  |  ( P ^ n )  ||  N }   &    |-  S  =  sup ( A ,  RR ,  <  )   =>    |-  ( ( P  e.  ( ZZ>= `  2 )  /\  ( N  e.  ZZ  /\  N  =/=  0 ) )  ->  ( S  e.  NN0  /\  ( P ^ S )  ||  N ) )
 
Theorempcprendvds 12881* Non-divisibility property of the prime power pre-function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  A  =  { n  e.  NN0  |  ( P ^ n )  ||  N }   &    |-  S  =  sup ( A ,  RR ,  <  )   =>    |-  ( ( P  e.  ( ZZ>= `  2 )  /\  ( N  e.  ZZ  /\  N  =/=  0 ) )  ->  -.  ( P ^ ( S  +  1 ) )  ||  N )
 
Theorempcprendvds2 12882* Non-divisibility property of the prime power pre-function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  A  =  { n  e.  NN0  |  ( P ^ n )  ||  N }   &    |-  S  =  sup ( A ,  RR ,  <  )   =>    |-  ( ( P  e.  ( ZZ>= `  2 )  /\  ( N  e.  ZZ  /\  N  =/=  0 ) )  ->  -.  P  ||  ( N  /  ( P ^ S ) ) )
 
Theorempcpre1 12883* Value of the prime power pre-function at 1. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by Mario Carneiro, 26-Apr-2016.)
 |-  A  =  { n  e.  NN0  |  ( P ^ n )  ||  N }   &    |-  S  =  sup ( A ,  RR ,  <  )   =>    |-  ( ( P  e.  ( ZZ>= `  2 )  /\  N  =  1 ) 
 ->  S  =  0 )
 
Theorempcpremul 12884* Multiplicative property of the prime count pre-function. Note that the primality of  P is essential for this property;  ( 4  pCnt  2
)  =  0 but  ( 4  pCnt 
( 2  x.  2 ) )  =  1  =/=  2  x.  (
4  pCnt  2 )  =  0. Since this is needed to show uniqueness for the real prime count function (over  QQ), we don't bother to define it off the primes. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  S  =  sup ( { n  e.  NN0  |  ( P ^ n ) 
 ||  M } ,  RR ,  <  )   &    |-  T  =  sup ( { n  e.  NN0  |  ( P ^ n )  ||  N } ,  RR ,  <  )   &    |-  U  =  sup ( { n  e.  NN0  |  ( P ^ n )  ||  ( M  x.  N ) } ,  RR ,  <  )   =>    |-  ( ( P  e.  Prime  /\  ( M  e.  ZZ  /\  M  =/=  0 )  /\  ( N  e.  ZZ  /\  N  =/=  0 ) )  ->  ( S  +  T )  =  U )
 
Theorempceulem 12885* Lemma for pceu 12886. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  S  =  sup ( { n  e.  NN0  |  ( P ^ n ) 
 ||  x } ,  RR ,  <  )   &    |-  T  =  sup ( { n  e.  NN0  |  ( P ^ n )  ||  y } ,  RR ,  <  )   &    |-  U  =  sup ( { n  e.  NN0  |  ( P ^ n )  ||  s } ,  RR ,  <  )   &    |-  V  =  sup ( { n  e.  NN0  |  ( P ^ n )  ||  t } ,  RR ,  <  )   &    |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  N  =/=  0 )   &    |-  ( ph  ->  ( x  e. 
 ZZ  /\  y  e.  NN ) )   &    |-  ( ph  ->  N  =  ( x  /  y ) )   &    |-  ( ph  ->  ( s  e. 
 ZZ  /\  t  e.  NN ) )   &    |-  ( ph  ->  N  =  ( s  /  t ) )   =>    |-  ( ph  ->  ( S  -  T )  =  ( U  -  V ) )
 
Theorempceu 12886* Uniqueness for the prime power function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  S  =  sup ( { n  e.  NN0  |  ( P ^ n ) 
 ||  x } ,  RR ,  <  )   &    |-  T  =  sup ( { n  e.  NN0  |  ( P ^ n )  ||  y } ,  RR ,  <  )   =>    |-  ( ( P  e.  Prime  /\  ( N  e.  QQ  /\  N  =/=  0
 ) )  ->  E! z E. x  e.  ZZ  E. y  e.  NN  ( N  =  ( x  /  y )  /\  z  =  ( S  -  T ) ) )
 
Theorempcval 12887* The value of the prime power function. (Contributed by Mario Carneiro, 23-Feb-2014.) (Revised by Mario Carneiro, 3-Oct-2014.)
 |-  S  =  sup ( { n  e.  NN0  |  ( P ^ n ) 
 ||  x } ,  RR ,  <  )   &    |-  T  =  sup ( { n  e.  NN0  |  ( P ^ n )  ||  y } ,  RR ,  <  )   =>    |-  ( ( P  e.  Prime  /\  ( N  e.  QQ  /\  N  =/=  0
 ) )  ->  ( P  pCnt  N )  =  ( iota z E. x  e.  ZZ  E. y  e.  NN  ( N  =  ( x  /  y
 )  /\  z  =  ( S  -  T ) ) ) )
 
Theorempczpre 12888* Connect the prime count pre-function to the actual prime count function, when restricted to the integers. (Contributed by Mario Carneiro, 23-Feb-2014.) (Proof shortened by Mario Carneiro, 24-Dec-2016.)
 |-  S  =  sup ( { n  e.  NN0  |  ( P ^ n ) 
 ||  N } ,  RR ,  <  )   =>    |-  ( ( P  e.  Prime  /\  ( N  e.  ZZ  /\  N  =/=  0 ) )  ->  ( P  pCnt  N )  =  S )
 
Theorempczcl 12889 Closure of the prime power function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  ( N  e.  ZZ  /\  N  =/=  0
 ) )  ->  ( P  pCnt  N )  e. 
 NN0 )
 
Theorempccl 12890 Closure of the prime power function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  N  e.  NN )  ->  ( P  pCnt  N )  e.  NN0 )
 
Theorempccld 12891 Closure of the prime power function. (Contributed by Mario Carneiro, 29-May-2016.)
 |-  ( ph  ->  P  e.  Prime )   &    |-  ( ph  ->  N  e.  NN )   =>    |-  ( ph  ->  ( P  pCnt  N )  e.  NN0 )
 
Theorempcmul 12892 Multiplication property of the prime power function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  ZZ  /\  A  =/=  0
 )  /\  ( B  e.  ZZ  /\  B  =/=  0 ) )  ->  ( P  pCnt  ( A  x.  B ) )  =  ( ( P 
 pCnt  A )  +  ( P  pCnt  B ) ) )
 
Theorempcdiv 12893 Division property of the prime power function. (Contributed by Mario Carneiro, 1-Mar-2014.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  ZZ  /\  A  =/=  0
 )  /\  B  e.  NN )  ->  ( P 
 pCnt  ( A  /  B ) )  =  (
 ( P  pCnt  A )  -  ( P  pCnt  B ) ) )
 
Theorempcqmul 12894 Multiplication property of the prime power function. (Contributed by Mario Carneiro, 9-Sep-2014.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  QQ  /\  A  =/=  0
 )  /\  ( B  e.  QQ  /\  B  =/=  0 ) )  ->  ( P  pCnt  ( A  x.  B ) )  =  ( ( P 
 pCnt  A )  +  ( P  pCnt  B ) ) )
 
Theorempc0 12895 The value of the prime power function at zero. (Contributed by Mario Carneiro, 3-Oct-2014.)
 |-  ( P  e.  Prime  ->  ( P  pCnt  0 )  = +oo )
 
Theorempc1 12896 Value of the prime count function at 1. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( P  e.  Prime  ->  ( P  pCnt  1 )  =  0 )
 
Theorempcqcl 12897 Closure of the general prime count function. (Contributed by Mario Carneiro, 23-Feb-2014.)
 |-  ( ( P  e.  Prime  /\  ( N  e.  QQ  /\  N  =/=  0
 ) )  ->  ( P  pCnt  N )  e. 
 ZZ )
 
Theorempcqdiv 12898 Division property of the prime power function. (Contributed by Mario Carneiro, 10-Aug-2015.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  QQ  /\  A  =/=  0
 )  /\  ( B  e.  QQ  /\  B  =/=  0 ) )  ->  ( P  pCnt  ( A 
 /  B ) )  =  ( ( P 
 pCnt  A )  -  ( P  pCnt  B ) ) )
 
Theorempcrec 12899 Prime power of a reciprocal. (Contributed by Mario Carneiro, 10-Aug-2015.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  QQ  /\  A  =/=  0
 ) )  ->  ( P  pCnt  ( 1  /  A ) )  =  -u ( P  pCnt  A ) )
 
Theorempcexp 12900 Prime power of an exponential. (Contributed by Mario Carneiro, 10-Aug-2015.)
 |-  ( ( P  e.  Prime  /\  ( A  e.  QQ  /\  A  =/=  0
 )  /\  N  e.  ZZ )  ->  ( P 
 pCnt  ( A ^ N ) )  =  ( N  x.  ( P  pCnt  A ) ) )
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