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Theorem List for Intuitionistic Logic Explorer - 16701-16800   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremstrcollnf 16701* Version of ax-strcoll 16698 with one disjoint variable condition removed, the other disjoint variable condition replaced with a nonfreeness hypothesis, and without initial universal quantifier. Version of strcoll2 16699 with the disjoint variable condition on 𝑏, 𝜑 replaced with a nonfreeness hypothesis.

This proof aims to demonstrate a standard technique, but strcoll2 16699 will generally suffice: since the theorem asserts the existence of a set 𝑏, supposing that that setvar does not occur in the already defined 𝜑 is not a big constraint. (Contributed by BJ, 21-Oct-2019.)

𝑏𝜑       (∀𝑥𝑎𝑦𝜑 → ∃𝑏(∀𝑥𝑎𝑦𝑏 𝜑 ∧ ∀𝑦𝑏𝑥𝑎 𝜑))
 
TheoremstrcollnfALT 16702* Alternate proof of strcollnf 16701, not using strcollnft 16700. (Contributed by BJ, 5-Oct-2019.) (Proof modification is discouraged.) (New usage is discouraged.)
𝑏𝜑       (∀𝑥𝑎𝑦𝜑 → ∃𝑏(∀𝑥𝑎𝑦𝑏 𝜑 ∧ ∀𝑦𝑏𝑥𝑎 𝜑))
 
14.3.13  CZF: Subset collection

In this section, we state the axiom scheme of subset collection, which is part of CZF set theory.

 
Axiomax-sscoll 16703* Axiom scheme of subset collection. It is stated with all possible disjoint variable conditions, to show that this weak form is sufficient. The antecedent means that 𝜑 represents a multivalued function from 𝑎 to 𝑏, or equivalently a collection of nonempty subsets of 𝑏 indexed by 𝑎, and the consequent asserts the existence of a subset of 𝑐 which "collects" at least one element in the image of each 𝑥𝑎 and which is made only of such elements. The axiom asserts the existence, for any sets 𝑎, 𝑏, of a set 𝑐 such that that implication holds for any value of the parameter 𝑧 of 𝜑. (Contributed by BJ, 5-Oct-2019.)
𝑎𝑏𝑐𝑧(∀𝑥𝑎𝑦𝑏 𝜑 → ∃𝑑𝑐 (∀𝑥𝑎𝑦𝑑 𝜑 ∧ ∀𝑦𝑑𝑥𝑎 𝜑))
 
Theoremsscoll2 16704* Version of ax-sscoll 16703 with two disjoint variable conditions removed and without initial universal quantifiers. (Contributed by BJ, 5-Oct-2019.)
𝑐𝑧(∀𝑥𝑎𝑦𝑏 𝜑 → ∃𝑑𝑐 (∀𝑥𝑎𝑦𝑑 𝜑 ∧ ∀𝑦𝑑𝑥𝑎 𝜑))
 
14.3.14  Real numbers
 
Axiomax-ddkcomp 16705 Axiom of Dedekind completeness for Dedekind real numbers: every inhabited upper-bounded located set of reals has a real upper bound. Ideally, this axiom should be "proved" as "axddkcomp" for the real numbers constructed from IZF, and then Axiom ax-ddkcomp 16705 should be used in place of construction specific results. In particular, axcaucvg 8180 should be proved from it. (Contributed by BJ, 24-Oct-2021.)
(((𝐴 ⊆ ℝ ∧ ∃𝑥 𝑥𝐴) ∧ ∃𝑥 ∈ ℝ ∀𝑦𝐴 𝑦 < 𝑥 ∧ ∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦 → (∃𝑧𝐴 𝑥 < 𝑧 ∨ ∀𝑧𝐴 𝑧 < 𝑦))) → ∃𝑥 ∈ ℝ (∀𝑦𝐴 𝑦𝑥 ∧ ((𝐵𝑅 ∧ ∀𝑦𝐴 𝑦𝐵) → 𝑥𝐵)))
 
14.4  Mathbox for Jim Kingdon
 
14.4.1  Propositional and predicate logic
 
Theoremnnnotnotr 16706 Double negation of double negation elimination. Suggested by an online post by Martin Escardo. Although this statement resembles nnexmid 858, it can be proved with reference only to implication and negation (that is, without use of disjunction). (Contributed by Jim Kingdon, 21-Oct-2024.)
¬ ¬ (¬ ¬ 𝜑𝜑)
 
14.4.2  The sizes of sets
 
Theoremss1oel2o 16707 Any subset of ordinal one being an element of ordinal two is equivalent to excluded middle. A variation of exmid01 4294 which more directly illustrates the contrast with el2oss1o 6654. (Contributed by Jim Kingdon, 8-Aug-2022.)
(EXMID ↔ ∀𝑥(𝑥 ⊆ 1o𝑥 ∈ 2o))
 
Theorem3dom 16708* A set that dominates ordinal 3 has at least 3 different members. (Contributed by Jim Kingdon, 12-Feb-2026.)
(3o𝐴 → ∃𝑥𝐴𝑦𝐴𝑧𝐴 (𝑥𝑦𝑥𝑧𝑦𝑧))
 
Theorempw1ndom3lem 16709 Lemma for pw1ndom3 16710. (Contributed by Jim Kingdon, 14-Feb-2026.)
(𝜑𝑋 ∈ 𝒫 1o)    &   (𝜑𝑌 ∈ 𝒫 1o)    &   (𝜑𝑍 ∈ 𝒫 1o)    &   (𝜑𝑋𝑌)    &   (𝜑𝑋𝑍)    &   (𝜑𝑌𝑍)       (𝜑𝑋 = ∅)
 
Theorempw1ndom3 16710 The powerset of 1o does not dominate 3o. This is another way of saying that 𝒫 1o does not have three elements (like pwntru 4295). (Contributed by Steven Nguyen and Jim Kingdon, 14-Feb-2026.)
¬ 3o ≼ 𝒫 1o
 
Theorempw1ninf 16711 The powerset of 1o is not infinite. Since we cannot prove it is finite (see pw1fin 7145), this provides a concrete example of a set which we cannot show to be finite or infinite, as seen another way at inffiexmid 7141. (Contributed by Jim Kingdon, 14-Feb-2026.)
¬ ω ≼ 𝒫 1o
 
Theoremnnti 16712 Ordering on a natural number generates a tight apartness. (Contributed by Jim Kingdon, 7-Aug-2022.)
(𝜑𝐴 ∈ ω)       ((𝜑 ∧ (𝑢𝐴𝑣𝐴)) → (𝑢 = 𝑣 ↔ (¬ 𝑢 E 𝑣 ∧ ¬ 𝑣 E 𝑢)))
 
Theorem012of 16713 Mapping zero and one between 0 and ω style integers. (Contributed by Jim Kingdon, 28-Jun-2024.)
𝐺 = frec((𝑥 ∈ ℤ ↦ (𝑥 + 1)), 0)       (𝐺 ↾ {0, 1}):{0, 1}⟶2o
 
Theorem2o01f 16714 Mapping zero and one between ω and 0 style integers. (Contributed by Jim Kingdon, 28-Jun-2024.)
𝐺 = frec((𝑥 ∈ ℤ ↦ (𝑥 + 1)), 0)       (𝐺 ↾ 2o):2o⟶{0, 1}
 
Theorem2omap 16715* Mapping between (2o𝑚 𝐴) and decidable subsets of 𝐴. (Contributed by Jim Kingdon, 12-Nov-2025.)
𝐹 = (𝑠 ∈ (2o𝑚 𝐴) ↦ {𝑧𝐴 ∣ (𝑠𝑧) = 1o})       (𝐴𝑉𝐹:(2o𝑚 𝐴)–1-1-onto→{𝑥 ∈ 𝒫 𝐴 ∣ ∀𝑦𝐴 DECID 𝑦𝑥})
 
Theorem2omapen 16716* Equinumerosity of (2o𝑚 𝐴) and the set of decidable subsets of 𝐴. (Contributed by Jim Kingdon, 14-Nov-2025.)
(𝐴𝑉 → (2o𝑚 𝐴) ≈ {𝑥 ∈ 𝒫 𝐴 ∣ ∀𝑦𝐴 DECID 𝑦𝑥})
 
Theorempw1map 16717* Mapping between (𝒫 1o𝑚 𝐴) and subsets of 𝐴. (Contributed by Jim Kingdon, 9-Jan-2026.)
𝐹 = (𝑠 ∈ (𝒫 1o𝑚 𝐴) ↦ {𝑧𝐴 ∣ (𝑠𝑧) = 1o})       (𝐴𝑉𝐹:(𝒫 1o𝑚 𝐴)–1-1-onto→𝒫 𝐴)
 
Theorempw1mapen 16718 Equinumerosity of (𝒫 1o𝑚 𝐴) and the set of subsets of 𝐴. (Contributed by Jim Kingdon, 10-Jan-2026.)
(𝐴𝑉 → (𝒫 1o𝑚 𝐴) ≈ 𝒫 𝐴)
 
14.4.3  The power set of a singleton
 
Theorempwtrufal 16719 A subset of the singleton {∅} cannot be anything other than or {∅}. Removing the double negation would change the meaning, as seen at exmid01 4294. If we view a subset of a singleton as a truth value (as seen in theorems like exmidexmid 4292), then this theorem states there are no truth values other than true and false, as described in section 1.1 of [Bauer], p. 481. (Contributed by Mario Carneiro and Jim Kingdon, 11-Sep-2023.)
(𝐴 ⊆ {∅} → ¬ ¬ (𝐴 = ∅ ∨ 𝐴 = {∅}))
 
Theorempwle2 16720* An exercise related to 𝑁 copies of a singleton and the power set of a singleton (where the latter can also be thought of as representing truth values). Posed as an exercise by Martin Escardo online. (Contributed by Jim Kingdon, 3-Sep-2023.)
𝑇 = 𝑥𝑁 ({𝑥} × 1o)       ((𝑁 ∈ ω ∧ 𝐺:𝑇1-1→𝒫 1o) → 𝑁 ⊆ 2o)
 
Theorempwf1oexmid 16721* An exercise related to 𝑁 copies of a singleton and the power set of a singleton (where the latter can also be thought of as representing truth values). Posed as an exercise by Martin Escardo online. (Contributed by Jim Kingdon, 3-Sep-2023.)
𝑇 = 𝑥𝑁 ({𝑥} × 1o)       ((𝑁 ∈ ω ∧ 𝐺:𝑇1-1→𝒫 1o) → (ran 𝐺 = 𝒫 1o ↔ (𝑁 = 2oEXMID)))
 
Theoremsubctctexmid 16722* If every subcountable set is countable and Markov's principle holds, excluded middle follows. Proposition 2.6 of [BauerSwan], p. 14:4. The proof is taken from that paper. (Contributed by Jim Kingdon, 29-Nov-2023.)
(𝜑 → ∀𝑥(∃𝑠(𝑠 ⊆ ω ∧ ∃𝑓 𝑓:𝑠onto𝑥) → ∃𝑔 𝑔:ω–onto→(𝑥 ⊔ 1o)))    &   (𝜑 → ω ∈ Markov)       (𝜑EXMID)
 
Theoremdomomsubct 16723* A set dominated by ω is subcountable. (Contributed by Jim Kingdon, 11-Nov-2025.)
(𝐴 ≼ ω → ∃𝑠(𝑠 ⊆ ω ∧ ∃𝑓 𝑓:𝑠onto𝐴))
 
Theoremsssneq 16724* Any two elements of a subset of a singleton are equal. (Contributed by Jim Kingdon, 28-May-2024.)
(𝐴 ⊆ {𝐵} → ∀𝑦𝐴𝑧𝐴 𝑦 = 𝑧)
 
Theorempw1nct 16725* A condition which ensures that the powerset of a singleton is not countable. The antecedent here can be referred to as the uniformity principle. Based on Mastodon posts by Andrej Bauer and Rahul Chhabra. (Contributed by Jim Kingdon, 29-May-2024.)
(∀𝑟(𝑟 ⊆ (𝒫 1o × ω) → (∀𝑝 ∈ 𝒫 1o𝑛 ∈ ω 𝑝𝑟𝑛 → ∃𝑚 ∈ ω ∀𝑞 ∈ 𝒫 1o𝑞𝑟𝑚)) → ¬ ∃𝑓 𝑓:ω–onto→(𝒫 1o ⊔ 1o))
 
Theorempw1dceq 16726* The powerset of 1o having decidable equality is equivalent to excluded middle. (Contributed by Jim Kingdon, 12-Feb-2026.)
(EXMID ↔ ∀𝑥 ∈ 𝒫 1o𝑦 ∈ 𝒫 1oDECID 𝑥 = 𝑦)
 
Theoremexmidnotnotr 16727 Excluded middle is equivalent to double negation elimination. Read an element of 𝒫 1o as being a truth value and 𝑥 = 1o being that 𝑥 is true. For a similar theorem, but expressed in terms of formulas rather than subsets of 1o, see dcfromnotnotr 1493. (Contributed by Jim Kingdon, 22-Apr-2026.)
(EXMID ↔ ∀𝑥 ∈ 𝒫 1o(¬ ¬ 𝑥 = 1o𝑥 = 1o))
 
Theoremexmidcon 16728* Excluded middle is equivalent to the form of contraposition which removes negation. Read an element of 𝒫 1o as being a truth value and 𝑥 = 1o being that 𝑥 is true. For a similar theorem, but expressed in terms of formulas rather than subsets of 1o, see dcfromcon 1494. (Contributed by Jim Kingdon, 22-Apr-2026.)
(EXMID ↔ ∀𝑥 ∈ 𝒫 1o𝑦 ∈ 𝒫 1o((¬ 𝑦 = 1o → ¬ 𝑥 = 1o) → (𝑥 = 1o𝑦 = 1o)))
 
Theoremexmidpeirce 16729* Excluded middle is equivalent to Peirce's law. Read an element of 𝒫 1o as being a truth value and 𝑥 = 1o being that 𝑥 is true. For a similar theorem, but expressed in terms of formulas rather than subsets of 1o, see dcfrompeirce 1495. (Contributed by Jim Kingdon, 23-Apr-2026.)
(EXMID ↔ ∀𝑥 ∈ 𝒫 1o𝑦 ∈ 𝒫 1o(((𝑥 = 1o𝑦 = 1o) → 𝑥 = 1o) → 𝑥 = 1o))
 
14.4.4  Omniscience of NN+oo
 
Theorem0nninf 16730 The zero element of (the constant sequence equal to ). (Contributed by Jim Kingdon, 14-Jul-2022.)
(ω × {∅}) ∈ ℕ
 
Theoremnnsf 16731* Domain and range of 𝑆. Part of Definition 3.3 of [PradicBrown2022], p. 5. (Contributed by Jim Kingdon, 30-Jul-2022.)
𝑆 = (𝑝 ∈ ℕ ↦ (𝑖 ∈ ω ↦ if(𝑖 = ∅, 1o, (𝑝 𝑖))))       𝑆:ℕ⟶ℕ
 
Theorempeano4nninf 16732* The successor function on is one to one. Half of Lemma 3.4 of [PradicBrown2022], p. 5. (Contributed by Jim Kingdon, 31-Jul-2022.)
𝑆 = (𝑝 ∈ ℕ ↦ (𝑖 ∈ ω ↦ if(𝑖 = ∅, 1o, (𝑝 𝑖))))       𝑆:ℕ1-1→ℕ
 
Theorempeano3nninf 16733* The successor function on is never zero. Half of Lemma 3.4 of [PradicBrown2022], p. 5. (Contributed by Jim Kingdon, 1-Aug-2022.)
𝑆 = (𝑝 ∈ ℕ ↦ (𝑖 ∈ ω ↦ if(𝑖 = ∅, 1o, (𝑝 𝑖))))       (𝐴 ∈ ℕ → (𝑆𝐴) ≠ (𝑥 ∈ ω ↦ ∅))
 
Theoremnninfalllem1 16734* Lemma for nninfall 16735. (Contributed by Jim Kingdon, 1-Aug-2022.)
(𝜑𝑄 ∈ (2o𝑚))    &   (𝜑 → (𝑄‘(𝑥 ∈ ω ↦ 1o)) = 1o)    &   (𝜑 → ∀𝑛 ∈ ω (𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑛, 1o, ∅))) = 1o)    &   (𝜑𝑃 ∈ ℕ)    &   (𝜑 → (𝑄𝑃) = ∅)       (𝜑 → ∀𝑛 ∈ ω (𝑃𝑛) = 1o)
 
Theoremnninfall 16735* Given a decidable predicate on , showing it holds for natural numbers and the point at infinity suffices to show it holds everywhere. The sense in which 𝑄 is a decidable predicate is that it assigns a value of either or 1o (which can be thought of as false and true) to every element of . Lemma 3.5 of [PradicBrown2022], p. 5. (Contributed by Jim Kingdon, 1-Aug-2022.)
(𝜑𝑄 ∈ (2o𝑚))    &   (𝜑 → (𝑄‘(𝑥 ∈ ω ↦ 1o)) = 1o)    &   (𝜑 → ∀𝑛 ∈ ω (𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑛, 1o, ∅))) = 1o)       (𝜑 → ∀𝑝 ∈ ℕ (𝑄𝑝) = 1o)
 
Theoremnninfsellemdc 16736* Lemma for nninfself 16739. Showing that the selection function is well defined. (Contributed by Jim Kingdon, 8-Aug-2022.)
((𝑄 ∈ (2o𝑚) ∧ 𝑁 ∈ ω) → DECID𝑘 ∈ suc 𝑁(𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o)
 
Theoremnninfsellemcl 16737* Lemma for nninfself 16739. (Contributed by Jim Kingdon, 8-Aug-2022.)
((𝑄 ∈ (2o𝑚) ∧ 𝑁 ∈ ω) → if(∀𝑘 ∈ suc 𝑁(𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅) ∈ 2o)
 
Theoremnninfsellemsuc 16738* Lemma for nninfself 16739. (Contributed by Jim Kingdon, 6-Aug-2022.)
((𝑄 ∈ (2o𝑚) ∧ 𝐽 ∈ ω) → if(∀𝑘 ∈ suc suc 𝐽(𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅) ⊆ if(∀𝑘 ∈ suc 𝐽(𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅))
 
Theoremnninfself 16739* Domain and range of the selection function for . (Contributed by Jim Kingdon, 6-Aug-2022.)
𝐸 = (𝑞 ∈ (2o𝑚) ↦ (𝑛 ∈ ω ↦ if(∀𝑘 ∈ suc 𝑛(𝑞‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅)))       𝐸:(2o𝑚)⟶ℕ
 
Theoremnninfsellemeq 16740* Lemma for nninfsel 16743. (Contributed by Jim Kingdon, 9-Aug-2022.)
𝐸 = (𝑞 ∈ (2o𝑚) ↦ (𝑛 ∈ ω ↦ if(∀𝑘 ∈ suc 𝑛(𝑞‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅)))    &   (𝜑𝑄 ∈ (2o𝑚))    &   (𝜑 → (𝑄‘(𝐸𝑄)) = 1o)    &   (𝜑𝑁 ∈ ω)    &   (𝜑 → ∀𝑘𝑁 (𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o)    &   (𝜑 → (𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑁, 1o, ∅))) = ∅)       (𝜑 → (𝐸𝑄) = (𝑖 ∈ ω ↦ if(𝑖𝑁, 1o, ∅)))
 
Theoremnninfsellemqall 16741* Lemma for nninfsel 16743. (Contributed by Jim Kingdon, 9-Aug-2022.)
𝐸 = (𝑞 ∈ (2o𝑚) ↦ (𝑛 ∈ ω ↦ if(∀𝑘 ∈ suc 𝑛(𝑞‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅)))    &   (𝜑𝑄 ∈ (2o𝑚))    &   (𝜑 → (𝑄‘(𝐸𝑄)) = 1o)    &   (𝜑𝑁 ∈ ω)       (𝜑 → (𝑄‘(𝑖 ∈ ω ↦ if(𝑖𝑁, 1o, ∅))) = 1o)
 
Theoremnninfsellemeqinf 16742* Lemma for nninfsel 16743. (Contributed by Jim Kingdon, 9-Aug-2022.)
𝐸 = (𝑞 ∈ (2o𝑚) ↦ (𝑛 ∈ ω ↦ if(∀𝑘 ∈ suc 𝑛(𝑞‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅)))    &   (𝜑𝑄 ∈ (2o𝑚))    &   (𝜑 → (𝑄‘(𝐸𝑄)) = 1o)       (𝜑 → (𝐸𝑄) = (𝑖 ∈ ω ↦ 1o))
 
Theoremnninfsel 16743* 𝐸 is a selection function for . Theorem 3.6 of [PradicBrown2022], p. 5. (Contributed by Jim Kingdon, 9-Aug-2022.)
𝐸 = (𝑞 ∈ (2o𝑚) ↦ (𝑛 ∈ ω ↦ if(∀𝑘 ∈ suc 𝑛(𝑞‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅)))    &   (𝜑𝑄 ∈ (2o𝑚))    &   (𝜑 → (𝑄‘(𝐸𝑄)) = 1o)       (𝜑 → ∀𝑝 ∈ ℕ (𝑄𝑝) = 1o)
 
Theoremnninfomnilem 16744* Lemma for nninfomni 16745. (Contributed by Jim Kingdon, 10-Aug-2022.)
𝐸 = (𝑞 ∈ (2o𝑚) ↦ (𝑛 ∈ ω ↦ if(∀𝑘 ∈ suc 𝑛(𝑞‘(𝑖 ∈ ω ↦ if(𝑖𝑘, 1o, ∅))) = 1o, 1o, ∅)))        ∈ Omni
 
Theoremnninfomni 16745 is omniscient. Corollary 3.7 of [PradicBrown2022], p. 5. (Contributed by Jim Kingdon, 10-Aug-2022.)
∈ Omni
 
Theoremnninffeq 16746* Equality of two functions on which agree at every integer and at the point at infinity. From an online post by Martin Escardo. Remark: the last two hypotheses can be grouped into one, (𝜑 → ∀𝑛 ∈ suc ω...). (Contributed by Jim Kingdon, 4-Aug-2023.)
(𝜑𝐹:ℕ⟶ℕ0)    &   (𝜑𝐺:ℕ⟶ℕ0)    &   (𝜑 → (𝐹‘(𝑥 ∈ ω ↦ 1o)) = (𝐺‘(𝑥 ∈ ω ↦ 1o)))    &   (𝜑 → ∀𝑛 ∈ ω (𝐹‘(𝑖 ∈ ω ↦ if(𝑖𝑛, 1o, ∅))) = (𝐺‘(𝑖 ∈ ω ↦ if(𝑖𝑛, 1o, ∅))))       (𝜑𝐹 = 𝐺)
 
Theoremnnnninfen 16747 Equinumerosity of the natural numbers and is equivalent to the Limited Principle of Omniscience (LPO). Remark in Section 1.1 of [Pradic2025], p. 2. (Contributed by Jim Kingdon, 8-Jul-2025.)
(ω ≈ ℕ ↔ ω ∈ Omni)
 
Theoremnnnninfex 16748* If an element of has a value of zero somewhere, then it is the mapping of a natural number. (Contributed by Jim Kingdon, 4-Aug-2022.)
(𝜑𝑃 ∈ ℕ)    &   (𝜑𝑁 ∈ ω)    &   (𝜑 → (𝑃𝑁) = ∅)       (𝜑 → ∃𝑛 ∈ ω 𝑃 = (𝑖 ∈ ω ↦ if(𝑖𝑛, 1o, ∅)))
 
Theoremnninfnfiinf 16749* An element of which is not finite is infinite. (Contributed by Jim Kingdon, 30-Nov-2025.)
((𝐴 ∈ ℕ ∧ ¬ ∃𝑛 ∈ ω 𝐴 = (𝑖 ∈ ω ↦ if(𝑖𝑛, 1o, ∅))) → 𝐴 = (𝑖 ∈ ω ↦ 1o))
 
14.4.5  Schroeder-Bernstein Theorem
 
Theoremexmidsbthrlem 16750* Lemma for exmidsbthr 16751. (Contributed by Jim Kingdon, 11-Aug-2022.)
𝑆 = (𝑝 ∈ ℕ ↦ (𝑖 ∈ ω ↦ if(𝑖 = ∅, 1o, (𝑝 𝑖))))       (∀𝑥𝑦((𝑥𝑦𝑦𝑥) → 𝑥𝑦) → EXMID)
 
Theoremexmidsbthr 16751* The Schroeder-Bernstein Theorem implies excluded middle. Theorem 1 of [PradicBrown2022], p. 1. (Contributed by Jim Kingdon, 11-Aug-2022.)
(∀𝑥𝑦((𝑥𝑦𝑦𝑥) → 𝑥𝑦) → EXMID)
 
Theoremexmidsbth 16752* The Schroeder-Bernstein Theorem is equivalent to excluded middle. This is Metamath 100 proof #25. The forward direction (isbth 7209) is the proof of the Schroeder-Bernstein Theorem from the Metamath Proof Explorer database (in which excluded middle holds), but adapted to use EXMID as an antecedent rather than being unconditionally true, as in the non-intuitionistic proof at https://us.metamath.org/mpeuni/sbth.html 7209.

The reverse direction (exmidsbthr 16751) is the one which establishes that Schroeder-Bernstein implies excluded middle. This resolves the question of whether we will be able to prove Schroeder-Bernstein from our axioms in the negative. (Contributed by Jim Kingdon, 13-Aug-2022.)

(EXMID ↔ ∀𝑥𝑦((𝑥𝑦𝑦𝑥) → 𝑥𝑦))
 
Theoremsbthomlem 16753 Lemma for sbthom 16754. (Contributed by Mario Carneiro and Jim Kingdon, 13-Jul-2023.)
(𝜑 → ω ∈ Omni)    &   (𝜑𝑌 ⊆ {∅})    &   (𝜑𝐹:ω–1-1-onto→(𝑌 ⊔ ω))       (𝜑 → (𝑌 = ∅ ∨ 𝑌 = {∅}))
 
Theoremsbthom 16754 Schroeder-Bernstein is not possible even for ω. We know by exmidsbth 16752 that full Schroeder-Bernstein will not be provable but what about the case where one of the sets is ω? That case plus the Limited Principle of Omniscience (LPO) implies excluded middle, so we will not be able to prove it. (Contributed by Mario Carneiro and Jim Kingdon, 10-Jul-2023.)
((∀𝑥((𝑥 ≼ ω ∧ ω ≼ 𝑥) → 𝑥 ≈ ω) ∧ ω ∈ Omni) → EXMID)
 
14.4.6  Real and complex numbers
 
Theoremqdencn 16755* The set of complex numbers whose real and imaginary parts are rational is dense in the complex plane. This is a two dimensional analogue to qdenre 11842 (and also would hold for ℝ × ℝ with the usual metric; this is not about complex numbers in particular). (Contributed by Jim Kingdon, 18-Oct-2021.)
𝑄 = {𝑧 ∈ ℂ ∣ ((ℜ‘𝑧) ∈ ℚ ∧ (ℑ‘𝑧) ∈ ℚ)}       ((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℝ+) → ∃𝑥𝑄 (abs‘(𝑥𝐴)) < 𝐵)
 
Theoremrefeq 16756* Equality of two real functions which agree at negative numbers, positive numbers, and zero. This holds even without real trichotomy. From an online post by Martin Escardo. (Contributed by Jim Kingdon, 9-Jul-2023.)
(𝜑𝐹:ℝ⟶ℝ)    &   (𝜑𝐺:ℝ⟶ℝ)    &   (𝜑 → ∀𝑥 ∈ ℝ (𝑥 < 0 → (𝐹𝑥) = (𝐺𝑥)))    &   (𝜑 → ∀𝑥 ∈ ℝ (0 < 𝑥 → (𝐹𝑥) = (𝐺𝑥)))    &   (𝜑 → (𝐹‘0) = (𝐺‘0))       (𝜑𝐹 = 𝐺)
 
Theoremrepiecelem 16757* Lemma for repiecele0 16758, repiecege0 16759, and repiecef 16760. The function 𝐻 is defined everywhere. (Contributed by Jim Kingdon, 27-Apr-2026.)
(𝜑𝐹:(-∞(,]0)⟶ℝ)    &   (𝜑𝐺:(0[,)+∞)⟶ℝ)    &   (𝜑 → (𝐹‘0) = (𝐺‘0))    &   𝐻 = (𝑥 ∈ ℝ ↦ (((𝐹‘inf({𝑥, 0}, ℝ, < )) + (𝐺‘sup({𝑥, 0}, ℝ, < ))) − (𝐹‘0)))       ((𝜑𝐴 ∈ ℝ) → (((𝐹‘inf({𝐴, 0}, ℝ, < )) + (𝐺‘sup({𝐴, 0}, ℝ, < ))) − (𝐹‘0)) ∈ ℝ)
 
Theoremrepiecele0 16758* Piecewise definition on the reals agrees with the nonpositive part of the definition. See repiecef 16760 for more on this construction. (Contributed by Jim Kingdon, 27-Apr-2026.)
(𝜑𝐹:(-∞(,]0)⟶ℝ)    &   (𝜑𝐺:(0[,)+∞)⟶ℝ)    &   (𝜑 → (𝐹‘0) = (𝐺‘0))    &   𝐻 = (𝑥 ∈ ℝ ↦ (((𝐹‘inf({𝑥, 0}, ℝ, < )) + (𝐺‘sup({𝑥, 0}, ℝ, < ))) − (𝐹‘0)))       ((𝜑𝐴 ∈ ℝ ∧ 𝐴 ≤ 0) → (𝐻𝐴) = (𝐹𝐴))
 
Theoremrepiecege0 16759* Piecewise definition on the reals agrees with the nonnegative part of the definition. See repiecef 16760 for more on this construction. (Contributed by Jim Kingdon, 27-Apr-2026.)
(𝜑𝐹:(-∞(,]0)⟶ℝ)    &   (𝜑𝐺:(0[,)+∞)⟶ℝ)    &   (𝜑 → (𝐹‘0) = (𝐺‘0))    &   𝐻 = (𝑥 ∈ ℝ ↦ (((𝐹‘inf({𝑥, 0}, ℝ, < )) + (𝐺‘sup({𝑥, 0}, ℝ, < ))) − (𝐹‘0)))       ((𝜑𝐴 ∈ ℝ ∧ 0 ≤ 𝐴) → (𝐻𝐴) = (𝐺𝐴))
 
Theoremrepiecef 16760* Piecewise definition on the reals yields a function. The function agrees with 𝐹 and 𝐺 on their respective parts of the real line; see repiecele0 16758 and repiecege0 16759. From an online post by James E Hanson. The construction was published in Martín Hötzel Escardó, "Effective and sequential definition by cases on the reals via infinite signed-digit numerals", Electronic Notes in Theoretical Computer Science 10 (1998), page 2, https://martinescardo.github.io/papers/lexnew.pdf. 16759 (Contributed by Jim Kingdon, 27-Apr-2026.)
(𝜑𝐹:(-∞(,]0)⟶ℝ)    &   (𝜑𝐺:(0[,)+∞)⟶ℝ)    &   (𝜑 → (𝐹‘0) = (𝐺‘0))    &   𝐻 = (𝑥 ∈ ℝ ↦ (((𝐹‘inf({𝑥, 0}, ℝ, < )) + (𝐺‘sup({𝑥, 0}, ℝ, < ))) − (𝐹‘0)))       (𝜑𝐻:ℝ⟶ℝ)
 
Theoremtriap 16761 Two ways of stating real number trichotomy. (Contributed by Jim Kingdon, 23-Aug-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((𝐴 < 𝐵𝐴 = 𝐵𝐵 < 𝐴) ↔ DECID 𝐴 # 𝐵))
 
Theoremisomninnlem 16762* Lemma for isomninn 16763. The result, with a hypothesis to provide a convenient notation. (Contributed by Jim Kingdon, 30-Aug-2023.)
𝐺 = frec((𝑥 ∈ ℤ ↦ (𝑥 + 1)), 0)       (𝐴𝑉 → (𝐴 ∈ Omni ↔ ∀𝑓 ∈ ({0, 1} ↑𝑚 𝐴)(∃𝑥𝐴 (𝑓𝑥) = 0 ∨ ∀𝑥𝐴 (𝑓𝑥) = 1)))
 
Theoremisomninn 16763* Omniscience stated in terms of natural numbers. Similar to isomnimap 7396 but it will sometimes be more convenient to use 0 and 1 rather than and 1o. (Contributed by Jim Kingdon, 30-Aug-2023.)
(𝐴𝑉 → (𝐴 ∈ Omni ↔ ∀𝑓 ∈ ({0, 1} ↑𝑚 𝐴)(∃𝑥𝐴 (𝑓𝑥) = 0 ∨ ∀𝑥𝐴 (𝑓𝑥) = 1)))
 
Theoremcvgcmp2nlemabs 16764* Lemma for cvgcmp2n 16765. The partial sums get closer to each other as we go further out. The proof proceeds by rewriting (seq1( + , 𝐺)‘𝑁) as the sum of (seq1( + , 𝐺)‘𝑀) and a term which gets smaller as 𝑀 gets large. (Contributed by Jim Kingdon, 25-Aug-2023.)
((𝜑𝑘 ∈ ℕ) → (𝐺𝑘) ∈ ℝ)    &   ((𝜑𝑘 ∈ ℕ) → 0 ≤ (𝐺𝑘))    &   ((𝜑𝑘 ∈ ℕ) → (𝐺𝑘) ≤ (1 / (2↑𝑘)))    &   (𝜑𝑀 ∈ ℕ)    &   (𝜑𝑁 ∈ (ℤ𝑀))       (𝜑 → (abs‘((seq1( + , 𝐺)‘𝑁) − (seq1( + , 𝐺)‘𝑀))) < (2 / 𝑀))
 
Theoremcvgcmp2n 16765* A comparison test for convergence of a real infinite series. (Contributed by Jim Kingdon, 25-Aug-2023.)
((𝜑𝑘 ∈ ℕ) → (𝐺𝑘) ∈ ℝ)    &   ((𝜑𝑘 ∈ ℕ) → 0 ≤ (𝐺𝑘))    &   ((𝜑𝑘 ∈ ℕ) → (𝐺𝑘) ≤ (1 / (2↑𝑘)))       (𝜑 → seq1( + , 𝐺) ∈ dom ⇝ )
 
Theoremiooref1o 16766 A one-to-one mapping from the real numbers onto the open unit interval. (Contributed by Jim Kingdon, 27-Jun-2024.)
𝐹 = (𝑥 ∈ ℝ ↦ (1 / (1 + (exp‘𝑥))))       𝐹:ℝ–1-1-onto→(0(,)1)
 
Theoremiooreen 16767 An open interval is equinumerous to the real numbers. (Contributed by Jim Kingdon, 27-Jun-2024.)
(0(,)1) ≈ ℝ
 
14.4.7  Analytic omniscience principles

Omniscience principles refer to several propositions, most of them weaker than full excluded middle, which do not follow from the axioms of IZF set theory.

They are: (0) the Principle of Omniscience (PO), which is another name for excluded middle (see exmidomni 7401), (1) the Limited Principle of Omniscience (LPO) is ω ∈ Omni (see df-omni 7394), (2) the Weak Limited Principle of Omniscience (WLPO) is ω ∈ WOmni (see df-womni 7423), (3) Markov's Principle (MP) is ω ∈ Markov (see df-markov 7411), (4) the Lesser Limited Principle of Omniscience (LLPO) is not yet defined in iset.mm.

They also have analytic counterparts each of which follows from the corresponding omniscience principle: (1) Analytic LPO is real number trichotomy, 𝑥 ∈ ℝ∀𝑦 ∈ ℝ(𝑥 < 𝑦𝑥 = 𝑦𝑦 < 𝑥) (see trilpo 16775), (2) Analytic WLPO is decidability of real number equality, 𝑥 ∈ ℝ∀𝑦 ∈ ℝDECID 𝑥 = 𝑦 (see redcwlpo 16788), (3) Analytic MP is 𝑥 ∈ ℝ∀𝑦 ∈ ℝ(𝑥𝑦𝑥 # 𝑦) (see neapmkv 16801), (4) Analytic LLPO is real number dichotomy, 𝑥 ∈ ℝ∀𝑦 ∈ ℝ(𝑥𝑦𝑦𝑥) (most relevant current theorem is maxclpr 11862).

 
Theoremtrilpolemclim 16768* Lemma for trilpo 16775. Convergence of the series. (Contributed by Jim Kingdon, 24-Aug-2023.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐺 = (𝑛 ∈ ℕ ↦ ((1 / (2↑𝑛)) · (𝐹𝑛)))       (𝜑 → seq1( + , 𝐺) ∈ dom ⇝ )
 
Theoremtrilpolemcl 16769* Lemma for trilpo 16775. The sum exists. (Contributed by Jim Kingdon, 23-Aug-2023.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐹𝑖))       (𝜑𝐴 ∈ ℝ)
 
Theoremtrilpolemisumle 16770* Lemma for trilpo 16775. An upper bound for the sum of the digits beyond a certain point. (Contributed by Jim Kingdon, 28-Aug-2023.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐹𝑖))    &   𝑍 = (ℤ𝑀)    &   (𝜑𝑀 ∈ ℕ)       (𝜑 → Σ𝑖𝑍 ((1 / (2↑𝑖)) · (𝐹𝑖)) ≤ Σ𝑖𝑍 (1 / (2↑𝑖)))
 
Theoremtrilpolemgt1 16771* Lemma for trilpo 16775. The 1 < 𝐴 case. (Contributed by Jim Kingdon, 23-Aug-2023.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐹𝑖))       (𝜑 → ¬ 1 < 𝐴)
 
Theoremtrilpolemeq1 16772* Lemma for trilpo 16775. The 𝐴 = 1 case. This is proved by noting that if any (𝐹𝑥) is zero, then the infinite sum 𝐴 is less than one based on the term which is zero. We are using the fact that the 𝐹 sequence is decidable (in the sense that each element is either zero or one). (Contributed by Jim Kingdon, 23-Aug-2023.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐹𝑖))    &   (𝜑𝐴 = 1)       (𝜑 → ∀𝑥 ∈ ℕ (𝐹𝑥) = 1)
 
Theoremtrilpolemlt1 16773* Lemma for trilpo 16775. The 𝐴 < 1 case. We can use the distance between 𝐴 and one (that is, 1 − 𝐴) to find a position in the sequence 𝑛 where terms after that point will not add up to as much as 1 − 𝐴. By finomni 7399 we know the terms up to 𝑛 either contain a zero or are all one. But if they are all one that contradicts the way we constructed 𝑛, so we know that the sequence contains a zero. (Contributed by Jim Kingdon, 23-Aug-2023.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐹𝑖))    &   (𝜑𝐴 < 1)       (𝜑 → ∃𝑥 ∈ ℕ (𝐹𝑥) = 0)
 
Theoremtrilpolemres 16774* Lemma for trilpo 16775. The result. (Contributed by Jim Kingdon, 23-Aug-2023.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐹𝑖))    &   (𝜑 → (𝐴 < 1 ∨ 𝐴 = 1 ∨ 1 < 𝐴))       (𝜑 → (∃𝑥 ∈ ℕ (𝐹𝑥) = 0 ∨ ∀𝑥 ∈ ℕ (𝐹𝑥) = 1))
 
Theoremtrilpo 16775* Real number trichotomy implies the Limited Principle of Omniscience (LPO). We expect that we'd need some form of countable choice to prove the converse.

Here's the outline of the proof. Given an infinite sequence F of zeroes and ones, we need to show the sequence contains a zero or it is all ones. Construct a real number A whose representation in base two consists of a zero, a decimal point, and then the numbers of the sequence. Compare it with one using trichotomy. The three cases from trichotomy are trilpolemlt1 16773 (which means the sequence contains a zero), trilpolemeq1 16772 (which means the sequence is all ones), and trilpolemgt1 16771 (which is not possible).

Equivalent ways to state real number trichotomy (sometimes called "analytic LPO") include decidability of real number apartness (see triap 16761) or that the real numbers are a discrete field (see trirec0 16776).

LPO is known to not be provable in IZF (and most constructive foundations), so this theorem establishes that we will be unable to prove an analogue to qtri3or 10563 for real numbers. (Contributed by Jim Kingdon, 23-Aug-2023.)

(∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦𝑥 = 𝑦𝑦 < 𝑥) → ω ∈ Omni)
 
Theoremtrirec0 16776* Every real number having a reciprocal or equaling zero is equivalent to real number trichotomy.

This is the key part of the definition of what is known as a discrete field, so "the real numbers are a discrete field" can be taken as an equivalent way to state real trichotomy (see further discussion at trilpo 16775). (Contributed by Jim Kingdon, 10-Jun-2024.)

(∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦𝑥 = 𝑦𝑦 < 𝑥) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ∨ 𝑥 = 0))
 
Theoremtrirec0xor 16777* Version of trirec0 16776 with exclusive-or.

The definition of a discrete field is sometimes stated in terms of exclusive-or but as proved here, this is equivalent to inclusive-or because the two disjuncts cannot be simultaneously true. (Contributed by Jim Kingdon, 10-Jun-2024.)

(∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦𝑥 = 𝑦𝑦 < 𝑥) ↔ ∀𝑥 ∈ ℝ (∃𝑧 ∈ ℝ (𝑥 · 𝑧) = 1 ⊻ 𝑥 = 0))
 
Theoremapdifflemf 16778 Lemma for apdiff 16780. Being apart from the point halfway between 𝑄 and 𝑅 suffices for 𝐴 to be a different distance from 𝑄 and from 𝑅. (Contributed by Jim Kingdon, 18-May-2024.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝑄 ∈ ℚ)    &   (𝜑𝑅 ∈ ℚ)    &   (𝜑𝑄 < 𝑅)    &   (𝜑 → ((𝑄 + 𝑅) / 2) # 𝐴)       (𝜑 → (abs‘(𝐴𝑄)) # (abs‘(𝐴𝑅)))
 
Theoremapdifflemr 16779 Lemma for apdiff 16780. (Contributed by Jim Kingdon, 19-May-2024.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝑆 ∈ ℚ)    &   (𝜑 → (abs‘(𝐴 − -1)) # (abs‘(𝐴 − 1)))    &   ((𝜑𝑆 ≠ 0) → (abs‘(𝐴 − 0)) # (abs‘(𝐴 − (2 · 𝑆))))       (𝜑𝐴 # 𝑆)
 
Theoremapdiff 16780* The irrationals (reals apart from any rational) are exactly those reals that are a different distance from every rational. (Contributed by Jim Kingdon, 17-May-2024.)
(𝐴 ∈ ℝ → (∀𝑞 ∈ ℚ 𝐴 # 𝑞 ↔ ∀𝑞 ∈ ℚ ∀𝑟 ∈ ℚ (𝑞𝑟 → (abs‘(𝐴𝑞)) # (abs‘(𝐴𝑟)))))
 
Theoremqdiff 16781* The rationals are exactly those reals for which there exist two distinct rationals that are the same distance from the original number. Similar to apdiff 16780 but by stating the result positively we can completely sidestep the issue of not equal versus apart in the statement of the result. From an online post by Ingo Blechschmidt. (Contributed by Jim Kingdon, 24-Apr-2026.)
(𝐴 ∈ ℝ → (𝐴 ∈ ℚ ↔ ∃𝑞 ∈ ℚ ∃𝑟 ∈ ℚ (𝑞𝑟 ∧ (abs‘(𝐴𝑞)) = (abs‘(𝐴𝑟)))))
 
Theoremiswomninnlem 16782* Lemma for iswomnimap 7425. The result, with a hypothesis for convenience. (Contributed by Jim Kingdon, 20-Jun-2024.)
𝐺 = frec((𝑥 ∈ ℤ ↦ (𝑥 + 1)), 0)       (𝐴𝑉 → (𝐴 ∈ WOmni ↔ ∀𝑓 ∈ ({0, 1} ↑𝑚 𝐴)DECID𝑥𝐴 (𝑓𝑥) = 1))
 
Theoremiswomninn 16783* Weak omniscience stated in terms of natural numbers. Similar to iswomnimap 7425 but it will sometimes be more convenient to use 0 and 1 rather than and 1o. (Contributed by Jim Kingdon, 20-Jun-2024.)
(𝐴𝑉 → (𝐴 ∈ WOmni ↔ ∀𝑓 ∈ ({0, 1} ↑𝑚 𝐴)DECID𝑥𝐴 (𝑓𝑥) = 1))
 
Theoremiswomni0 16784* Weak omniscience stated in terms of equality with 0. Like iswomninn 16783 but with zero in place of one. (Contributed by Jim Kingdon, 24-Jul-2024.)
(𝐴𝑉 → (𝐴 ∈ WOmni ↔ ∀𝑓 ∈ ({0, 1} ↑𝑚 𝐴)DECID𝑥𝐴 (𝑓𝑥) = 0))
 
Theoremismkvnnlem 16785* Lemma for ismkvnn 16786. The result, with a hypothesis to give a name to an expression for convenience. (Contributed by Jim Kingdon, 25-Jun-2024.)
𝐺 = frec((𝑥 ∈ ℤ ↦ (𝑥 + 1)), 0)       (𝐴𝑉 → (𝐴 ∈ Markov ↔ ∀𝑓 ∈ ({0, 1} ↑𝑚 𝐴)(¬ ∀𝑥𝐴 (𝑓𝑥) = 1 → ∃𝑥𝐴 (𝑓𝑥) = 0)))
 
Theoremismkvnn 16786* The predicate of being Markov stated in terms of set exponentiation. (Contributed by Jim Kingdon, 25-Jun-2024.)
(𝐴𝑉 → (𝐴 ∈ Markov ↔ ∀𝑓 ∈ ({0, 1} ↑𝑚 𝐴)(¬ ∀𝑥𝐴 (𝑓𝑥) = 1 → ∃𝑥𝐴 (𝑓𝑥) = 0)))
 
Theoremredcwlpolemeq1 16787* Lemma for redcwlpo 16788. A biconditionalized version of trilpolemeq1 16772. (Contributed by Jim Kingdon, 21-Jun-2024.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐹𝑖))       (𝜑 → (𝐴 = 1 ↔ ∀𝑥 ∈ ℕ (𝐹𝑥) = 1))
 
Theoremredcwlpo 16788* Decidability of real number equality implies the Weak Limited Principle of Omniscience (WLPO). We expect that we'd need some form of countable choice to prove the converse.

Here's the outline of the proof. Given an infinite sequence F of zeroes and ones, we need to show the sequence is all ones or it is not. Construct a real number A whose representation in base two consists of a zero, a decimal point, and then the numbers of the sequence. This real number will equal one if and only if the sequence is all ones (redcwlpolemeq1 16787). Therefore decidability of real number equality would imply decidability of whether the sequence is all ones.

Because of this theorem, decidability of real number equality is sometimes called "analytic WLPO".

WLPO is known to not be provable in IZF (and most constructive foundations), so this theorem establishes that we will be unable to prove an analogue to qdceq 10567 for real numbers. (Contributed by Jim Kingdon, 20-Jun-2024.)

(∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ DECID 𝑥 = 𝑦 → ω ∈ WOmni)
 
Theoremtridceq 16789* Real trichotomy implies decidability of real number equality. Or in other words, analytic LPO implies analytic WLPO (see trilpo 16775 and redcwlpo 16788). Thus, this is an analytic analogue to lpowlpo 7427. (Contributed by Jim Kingdon, 24-Jul-2024.)
(∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦𝑥 = 𝑦𝑦 < 𝑥) → ∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ DECID 𝑥 = 𝑦)
 
Theoremredc0 16790* Two ways to express decidability of real number equality. (Contributed by Jim Kingdon, 23-Jul-2024.)
(∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ DECID 𝑥 = 𝑦 ↔ ∀𝑧 ∈ ℝ DECID 𝑧 = 0)
 
Theoremreap0 16791* Real number trichotomy is equivalent to decidability of apartness from zero. (Contributed by Jim Kingdon, 27-Jul-2024.)
(∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦𝑥 = 𝑦𝑦 < 𝑥) ↔ ∀𝑧 ∈ ℝ DECID 𝑧 # 0)
 
Theoremcndcap 16792* Real number trichotomy is equivalent to decidability of complex number apartness. (Contributed by Jim Kingdon, 10-Apr-2025.)
(∀𝑥 ∈ ℝ ∀𝑦 ∈ ℝ (𝑥 < 𝑦𝑥 = 𝑦𝑦 < 𝑥) ↔ ∀𝑧 ∈ ℂ ∀𝑤 ∈ ℂ DECID 𝑧 # 𝑤)
 
Theoremdceqnconst 16793* Decidability of real number equality implies the existence of a certain non-constant function from real numbers to integers. Variation of Exercise 11.6(i) of [HoTT], p. (varies). See redcwlpo 16788 for more discussion of decidability of real number equality. (Contributed by BJ and Jim Kingdon, 24-Jun-2024.) (Revised by Jim Kingdon, 23-Jul-2024.)
(∀𝑥 ∈ ℝ DECID 𝑥 = 0 → ∃𝑓(𝑓:ℝ⟶ℤ ∧ (𝑓‘0) = 0 ∧ ∀𝑥 ∈ ℝ+ (𝑓𝑥) ≠ 0))
 
Theoremdcapnconst 16794* Decidability of real number apartness implies the existence of a certain non-constant function from real numbers to integers. Variation of Exercise 11.6(i) of [HoTT], p. (varies). See trilpo 16775 for more discussion of decidability of real number apartness.

This is a weaker form of dceqnconst 16793 and in fact this theorem can be proved using dceqnconst 16793 as shown at dcapnconstALT 16795. (Contributed by BJ and Jim Kingdon, 24-Jun-2024.)

(∀𝑥 ∈ ℝ DECID 𝑥 # 0 → ∃𝑓(𝑓:ℝ⟶ℤ ∧ (𝑓‘0) = 0 ∧ ∀𝑥 ∈ ℝ+ (𝑓𝑥) ≠ 0))
 
TheoremdcapnconstALT 16795* Decidability of real number apartness implies the existence of a certain non-constant function from real numbers to integers. A proof of dcapnconst 16794 by means of dceqnconst 16793. (Contributed by Jim Kingdon, 27-Jul-2024.) (New usage is discouraged.) (Proof modification is discouraged.)
(∀𝑥 ∈ ℝ DECID 𝑥 # 0 → ∃𝑓(𝑓:ℝ⟶ℤ ∧ (𝑓‘0) = 0 ∧ ∀𝑥 ∈ ℝ+ (𝑓𝑥) ≠ 0))
 
Theoremnconstwlpolem0 16796* Lemma for nconstwlpo 16799. If all the terms of the series are zero, so is their sum. (Contributed by Jim Kingdon, 26-Jul-2024.)
(𝜑𝐺:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐺𝑖))    &   (𝜑 → ∀𝑥 ∈ ℕ (𝐺𝑥) = 0)       (𝜑𝐴 = 0)
 
Theoremnconstwlpolemgt0 16797* Lemma for nconstwlpo 16799. If one of the terms of series is positive, so is the sum. (Contributed by Jim Kingdon, 26-Jul-2024.)
(𝜑𝐺:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐺𝑖))    &   (𝜑 → ∃𝑥 ∈ ℕ (𝐺𝑥) = 1)       (𝜑 → 0 < 𝐴)
 
Theoremnconstwlpolem 16798* Lemma for nconstwlpo 16799. (Contributed by Jim Kingdon, 23-Jul-2024.)
(𝜑𝐹:ℝ⟶ℤ)    &   (𝜑 → (𝐹‘0) = 0)    &   ((𝜑𝑥 ∈ ℝ+) → (𝐹𝑥) ≠ 0)    &   (𝜑𝐺:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐺𝑖))       (𝜑 → (∀𝑦 ∈ ℕ (𝐺𝑦) = 0 ∨ ¬ ∀𝑦 ∈ ℕ (𝐺𝑦) = 0))
 
Theoremnconstwlpo 16799* Existence of a certain non-constant function from reals to integers implies ω ∈ WOmni (the Weak Limited Principle of Omniscience or WLPO). Based on Exercise 11.6(ii) of [HoTT], p. (varies). (Contributed by BJ and Jim Kingdon, 22-Jul-2024.)
(𝜑𝐹:ℝ⟶ℤ)    &   (𝜑 → (𝐹‘0) = 0)    &   ((𝜑𝑥 ∈ ℝ+) → (𝐹𝑥) ≠ 0)       (𝜑 → ω ∈ WOmni)
 
Theoremneapmkvlem 16800* Lemma for neapmkv 16801. The result, with a few hypotheses broken out for convenience. (Contributed by Jim Kingdon, 25-Jun-2024.)
(𝜑𝐹:ℕ⟶{0, 1})    &   𝐴 = Σ𝑖 ∈ ℕ ((1 / (2↑𝑖)) · (𝐹𝑖))    &   ((𝜑𝐴 ≠ 1) → 𝐴 # 1)       (𝜑 → (¬ ∀𝑥 ∈ ℕ (𝐹𝑥) = 1 → ∃𝑥 ∈ ℕ (𝐹𝑥) = 0))
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