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Theorem List for Metamath Proof Explorer - 26201-26300   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremdquart 26201 Solve a depressed quartic equation. To eliminate 𝑆, which is the square root of a solution 𝑀 to the resolvent cubic equation, apply cubic 26197 or one of its variants. (Contributed by Mario Carneiro, 6-May-2015.)
(𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝑋 ∈ ℂ)    &   (𝜑𝑆 ∈ ℂ)    &   (𝜑𝑀 = ((2 · 𝑆)↑2))    &   (𝜑𝑀 ≠ 0)    &   (𝜑𝐼 ∈ ℂ)    &   (𝜑 → (𝐼↑2) = ((-(𝑆↑2) − (𝐵 / 2)) + ((𝐶 / 4) / 𝑆)))    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑 → (((𝑀↑3) + ((2 · 𝐵) · (𝑀↑2))) + ((((𝐵↑2) − (4 · 𝐷)) · 𝑀) + -(𝐶↑2))) = 0)    &   (𝜑𝐽 ∈ ℂ)    &   (𝜑 → (𝐽↑2) = ((-(𝑆↑2) − (𝐵 / 2)) − ((𝐶 / 4) / 𝑆)))       (𝜑 → ((((𝑋↑4) + (𝐵 · (𝑋↑2))) + ((𝐶 · 𝑋) + 𝐷)) = 0 ↔ ((𝑋 = (-𝑆 + 𝐼) ∨ 𝑋 = (-𝑆𝐼)) ∨ (𝑋 = (𝑆 + 𝐽) ∨ 𝑋 = (𝑆𝐽)))))
 
Theoremquart1cl 26202 Closure lemmas for quart 26209. (Contributed by Mario Carneiro, 7-May-2015.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑𝑃 = (𝐵 − ((3 / 8) · (𝐴↑2))))    &   (𝜑𝑄 = ((𝐶 − ((𝐴 · 𝐵) / 2)) + ((𝐴↑3) / 8)))    &   (𝜑𝑅 = ((𝐷 − ((𝐶 · 𝐴) / 4)) + ((((𝐴↑2) · 𝐵) / 16) − ((3 / 256) · (𝐴↑4)))))       (𝜑 → (𝑃 ∈ ℂ ∧ 𝑄 ∈ ℂ ∧ 𝑅 ∈ ℂ))
 
Theoremquart1lem 26203 Lemma for quart1 26204. (Contributed by Mario Carneiro, 6-May-2015.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑𝑃 = (𝐵 − ((3 / 8) · (𝐴↑2))))    &   (𝜑𝑄 = ((𝐶 − ((𝐴 · 𝐵) / 2)) + ((𝐴↑3) / 8)))    &   (𝜑𝑅 = ((𝐷 − ((𝐶 · 𝐴) / 4)) + ((((𝐴↑2) · 𝐵) / 16) − ((3 / 256) · (𝐴↑4)))))    &   (𝜑𝑋 ∈ ℂ)    &   (𝜑𝑌 = (𝑋 + (𝐴 / 4)))       (𝜑𝐷 = ((((𝐴↑4) / 256) + (𝑃 · ((𝐴 / 4)↑2))) + ((𝑄 · (𝐴 / 4)) + 𝑅)))
 
Theoremquart1 26204 Depress a quartic equation. (Contributed by Mario Carneiro, 6-May-2015.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑𝑃 = (𝐵 − ((3 / 8) · (𝐴↑2))))    &   (𝜑𝑄 = ((𝐶 − ((𝐴 · 𝐵) / 2)) + ((𝐴↑3) / 8)))    &   (𝜑𝑅 = ((𝐷 − ((𝐶 · 𝐴) / 4)) + ((((𝐴↑2) · 𝐵) / 16) − ((3 / 256) · (𝐴↑4)))))    &   (𝜑𝑋 ∈ ℂ)    &   (𝜑𝑌 = (𝑋 + (𝐴 / 4)))       (𝜑 → (((𝑋↑4) + (𝐴 · (𝑋↑3))) + ((𝐵 · (𝑋↑2)) + ((𝐶 · 𝑋) + 𝐷))) = (((𝑌↑4) + (𝑃 · (𝑌↑2))) + ((𝑄 · 𝑌) + 𝑅)))
 
Theoremquartlem1 26205 Lemma for quart 26209. (Contributed by Mario Carneiro, 6-May-2015.)
(𝜑𝑃 ∈ ℂ)    &   (𝜑𝑄 ∈ ℂ)    &   (𝜑𝑅 ∈ ℂ)    &   (𝜑𝑈 = ((𝑃↑2) + (12 · 𝑅)))    &   (𝜑𝑉 = ((-(2 · (𝑃↑3)) − (27 · (𝑄↑2))) + (72 · (𝑃 · 𝑅))))       (𝜑 → (𝑈 = (((2 · 𝑃)↑2) − (3 · ((𝑃↑2) − (4 · 𝑅)))) ∧ 𝑉 = (((2 · ((2 · 𝑃)↑3)) − (9 · ((2 · 𝑃) · ((𝑃↑2) − (4 · 𝑅))))) + (27 · -(𝑄↑2)))))
 
Theoremquartlem2 26206 Closure lemmas for quart 26209. (Contributed by Mario Carneiro, 7-May-2015.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑𝑋 ∈ ℂ)    &   (𝜑𝐸 = -(𝐴 / 4))    &   (𝜑𝑃 = (𝐵 − ((3 / 8) · (𝐴↑2))))    &   (𝜑𝑄 = ((𝐶 − ((𝐴 · 𝐵) / 2)) + ((𝐴↑3) / 8)))    &   (𝜑𝑅 = ((𝐷 − ((𝐶 · 𝐴) / 4)) + ((((𝐴↑2) · 𝐵) / 16) − ((3 / 256) · (𝐴↑4)))))    &   (𝜑𝑈 = ((𝑃↑2) + (12 · 𝑅)))    &   (𝜑𝑉 = ((-(2 · (𝑃↑3)) − (27 · (𝑄↑2))) + (72 · (𝑃 · 𝑅))))    &   (𝜑𝑊 = (√‘((𝑉↑2) − (4 · (𝑈↑3)))))       (𝜑 → (𝑈 ∈ ℂ ∧ 𝑉 ∈ ℂ ∧ 𝑊 ∈ ℂ))
 
Theoremquartlem3 26207 Closure lemmas for quart 26209. (Contributed by Mario Carneiro, 7-May-2015.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑𝑋 ∈ ℂ)    &   (𝜑𝐸 = -(𝐴 / 4))    &   (𝜑𝑃 = (𝐵 − ((3 / 8) · (𝐴↑2))))    &   (𝜑𝑄 = ((𝐶 − ((𝐴 · 𝐵) / 2)) + ((𝐴↑3) / 8)))    &   (𝜑𝑅 = ((𝐷 − ((𝐶 · 𝐴) / 4)) + ((((𝐴↑2) · 𝐵) / 16) − ((3 / 256) · (𝐴↑4)))))    &   (𝜑𝑈 = ((𝑃↑2) + (12 · 𝑅)))    &   (𝜑𝑉 = ((-(2 · (𝑃↑3)) − (27 · (𝑄↑2))) + (72 · (𝑃 · 𝑅))))    &   (𝜑𝑊 = (√‘((𝑉↑2) − (4 · (𝑈↑3)))))    &   (𝜑𝑆 = ((√‘𝑀) / 2))    &   (𝜑𝑀 = -((((2 · 𝑃) + 𝑇) + (𝑈 / 𝑇)) / 3))    &   (𝜑𝑇 = (((𝑉 + 𝑊) / 2)↑𝑐(1 / 3)))    &   (𝜑𝑇 ≠ 0)       (𝜑 → (𝑆 ∈ ℂ ∧ 𝑀 ∈ ℂ ∧ 𝑇 ∈ ℂ))
 
Theoremquartlem4 26208 Closure lemmas for quart 26209. (Contributed by Mario Carneiro, 7-May-2015.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑𝑋 ∈ ℂ)    &   (𝜑𝐸 = -(𝐴 / 4))    &   (𝜑𝑃 = (𝐵 − ((3 / 8) · (𝐴↑2))))    &   (𝜑𝑄 = ((𝐶 − ((𝐴 · 𝐵) / 2)) + ((𝐴↑3) / 8)))    &   (𝜑𝑅 = ((𝐷 − ((𝐶 · 𝐴) / 4)) + ((((𝐴↑2) · 𝐵) / 16) − ((3 / 256) · (𝐴↑4)))))    &   (𝜑𝑈 = ((𝑃↑2) + (12 · 𝑅)))    &   (𝜑𝑉 = ((-(2 · (𝑃↑3)) − (27 · (𝑄↑2))) + (72 · (𝑃 · 𝑅))))    &   (𝜑𝑊 = (√‘((𝑉↑2) − (4 · (𝑈↑3)))))    &   (𝜑𝑆 = ((√‘𝑀) / 2))    &   (𝜑𝑀 = -((((2 · 𝑃) + 𝑇) + (𝑈 / 𝑇)) / 3))    &   (𝜑𝑇 = (((𝑉 + 𝑊) / 2)↑𝑐(1 / 3)))    &   (𝜑𝑇 ≠ 0)    &   (𝜑𝑀 ≠ 0)    &   (𝜑𝐼 = (√‘((-(𝑆↑2) − (𝑃 / 2)) + ((𝑄 / 4) / 𝑆))))    &   (𝜑𝐽 = (√‘((-(𝑆↑2) − (𝑃 / 2)) − ((𝑄 / 4) / 𝑆))))       (𝜑 → (𝑆 ≠ 0 ∧ 𝐼 ∈ ℂ ∧ 𝐽 ∈ ℂ))
 
Theoremquart 26209 The quartic equation, writing out all roots using square and cube root functions so that only direct substitutions remain, and we can actually claim to have a "quartic equation". Naturally, this theorem is ridiculously long (see quartfull 33699) if all the substitutions are performed. This is Metamath 100 proof #46. (Contributed by Mario Carneiro, 6-May-2015.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑𝑋 ∈ ℂ)    &   (𝜑𝐸 = -(𝐴 / 4))    &   (𝜑𝑃 = (𝐵 − ((3 / 8) · (𝐴↑2))))    &   (𝜑𝑄 = ((𝐶 − ((𝐴 · 𝐵) / 2)) + ((𝐴↑3) / 8)))    &   (𝜑𝑅 = ((𝐷 − ((𝐶 · 𝐴) / 4)) + ((((𝐴↑2) · 𝐵) / 16) − ((3 / 256) · (𝐴↑4)))))    &   (𝜑𝑈 = ((𝑃↑2) + (12 · 𝑅)))    &   (𝜑𝑉 = ((-(2 · (𝑃↑3)) − (27 · (𝑄↑2))) + (72 · (𝑃 · 𝑅))))    &   (𝜑𝑊 = (√‘((𝑉↑2) − (4 · (𝑈↑3)))))    &   (𝜑𝑆 = ((√‘𝑀) / 2))    &   (𝜑𝑀 = -((((2 · 𝑃) + 𝑇) + (𝑈 / 𝑇)) / 3))    &   (𝜑𝑇 = (((𝑉 + 𝑊) / 2)↑𝑐(1 / 3)))    &   (𝜑𝑇 ≠ 0)    &   (𝜑𝑀 ≠ 0)    &   (𝜑𝐼 = (√‘((-(𝑆↑2) − (𝑃 / 2)) + ((𝑄 / 4) / 𝑆))))    &   (𝜑𝐽 = (√‘((-(𝑆↑2) − (𝑃 / 2)) − ((𝑄 / 4) / 𝑆))))       (𝜑 → ((((𝑋↑4) + (𝐴 · (𝑋↑3))) + ((𝐵 · (𝑋↑2)) + ((𝐶 · 𝑋) + 𝐷))) = 0 ↔ ((𝑋 = ((𝐸𝑆) + 𝐼) ∨ 𝑋 = ((𝐸𝑆) − 𝐼)) ∨ (𝑋 = ((𝐸 + 𝑆) + 𝐽) ∨ 𝑋 = ((𝐸 + 𝑆) − 𝐽)))))
 
14.3.8  Inverse trigonometric functions
 
Syntaxcasin 26210 The arcsine function.
class arcsin
 
Syntaxcacos 26211 The arccosine function.
class arccos
 
Syntaxcatan 26212 The arctangent function.
class arctan
 
Definitiondf-asin 26213 Define the arcsine function. Because sin is not a one-to-one function, the literal inverse sin is not a function. Rather than attempt to find the right domain on which to restrict sin in order to get a total function, we just define it in terms of log, which we already know is total (except at 0). There are branch points at -1 and 1 (at which the function is defined), and branch cuts along the real line not between -1 and 1, which is to say (-∞, -1) ∪ (1, +∞). (Contributed by Mario Carneiro, 31-Mar-2015.)
arcsin = (𝑥 ∈ ℂ ↦ (-i · (log‘((i · 𝑥) + (√‘(1 − (𝑥↑2)))))))
 
Definitiondf-acos 26214 Define the arccosine function. See also remarks for df-asin 26213. Since we define arccos in terms of arcsin, it shares the same branch points and cuts, namely (-∞, -1) ∪ (1, +∞). (Contributed by Mario Carneiro, 31-Mar-2015.)
arccos = (𝑥 ∈ ℂ ↦ ((π / 2) − (arcsin‘𝑥)))
 
Definitiondf-atan 26215 Define the arctangent function. See also remarks for df-asin 26213. Unlike arcsin and arccos, this function is not defined everywhere, because tan(𝑧) ≠ ±i for all 𝑧 ∈ ℂ. For all other 𝑧, there is a formula for arctan(𝑧) in terms of log, and we take that as the definition. Branch points are at ±i; branch cuts are on the pure imaginary axis not between -i and i, which is to say {𝑧 ∈ ℂ ∣ (i · 𝑧) ∈ (-∞, -1) ∪ (1, +∞)}. (Contributed by Mario Carneiro, 31-Mar-2015.)
arctan = (𝑥 ∈ (ℂ ∖ {-i, i}) ↦ ((i / 2) · ((log‘(1 − (i · 𝑥))) − (log‘(1 + (i · 𝑥))))))
 
Theoremasinlem 26216 The argument to the logarithm in df-asin 26213 is always nonzero. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ ℂ → ((i · 𝐴) + (√‘(1 − (𝐴↑2)))) ≠ 0)
 
Theoremasinlem2 26217 The argument to the logarithm in df-asin 26213 has the property that replacing 𝐴 with -𝐴 in the expression gives the reciprocal. (Contributed by Mario Carneiro, 1-Apr-2015.)
(𝐴 ∈ ℂ → (((i · 𝐴) + (√‘(1 − (𝐴↑2)))) · ((i · -𝐴) + (√‘(1 − (-𝐴↑2))))) = 1)
 
Theoremasinlem3a 26218 Lemma for asinlem3 26219. (Contributed by Mario Carneiro, 1-Apr-2015.)
((𝐴 ∈ ℂ ∧ (ℑ‘𝐴) ≤ 0) → 0 ≤ (ℜ‘((i · 𝐴) + (√‘(1 − (𝐴↑2))))))
 
Theoremasinlem3 26219 The argument to the logarithm in df-asin 26213 has nonnegative real part. (Contributed by Mario Carneiro, 1-Apr-2015.)
(𝐴 ∈ ℂ → 0 ≤ (ℜ‘((i · 𝐴) + (√‘(1 − (𝐴↑2))))))
 
Theoremasinf 26220 Domain and codomain of the arcsin function. (Contributed by Mario Carneiro, 31-Mar-2015.)
arcsin:ℂ⟶ℂ
 
Theoremasincl 26221 Closure for the arcsin function. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ ℂ → (arcsin‘𝐴) ∈ ℂ)
 
Theoremacosf 26222 Domain and codoamin of the arccos function. (Contributed by Mario Carneiro, 31-Mar-2015.)
arccos:ℂ⟶ℂ
 
Theoremacoscl 26223 Closure for the arccos function. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ ℂ → (arccos‘𝐴) ∈ ℂ)
 
Theorematandm 26224 Since the property is a little lengthy, we abbreviate 𝐴 ∈ ℂ ∧ 𝐴 ≠ -i ∧ 𝐴 ≠ i as 𝐴 ∈ dom arctan. This is the necessary precondition for the definition of arctan to make sense. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ dom arctan ↔ (𝐴 ∈ ℂ ∧ 𝐴 ≠ -i ∧ 𝐴 ≠ i))
 
Theorematandm2 26225 This form of atandm 26224 is a bit more useful for showing that the logarithms in df-atan 26215 are well-defined. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ dom arctan ↔ (𝐴 ∈ ℂ ∧ (1 − (i · 𝐴)) ≠ 0 ∧ (1 + (i · 𝐴)) ≠ 0))
 
Theorematandm3 26226 A compact form of atandm 26224. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ dom arctan ↔ (𝐴 ∈ ℂ ∧ (𝐴↑2) ≠ -1))
 
Theorematandm4 26227 A compact form of atandm 26224. (Contributed by Mario Carneiro, 3-Apr-2015.)
(𝐴 ∈ dom arctan ↔ (𝐴 ∈ ℂ ∧ (1 + (𝐴↑2)) ≠ 0))
 
Theorematanf 26228 Domain and codoamin of the arctan function. (Contributed by Mario Carneiro, 31-Mar-2015.)
arctan:(ℂ ∖ {-i, i})⟶ℂ
 
Theorematancl 26229 Closure for the arctan function. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ dom arctan → (arctan‘𝐴) ∈ ℂ)
 
Theoremasinval 26230 Value of the arcsin function. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ ℂ → (arcsin‘𝐴) = (-i · (log‘((i · 𝐴) + (√‘(1 − (𝐴↑2)))))))
 
Theoremacosval 26231 Value of the arccos function. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ ℂ → (arccos‘𝐴) = ((π / 2) − (arcsin‘𝐴)))
 
Theorematanval 26232 Value of the arctan function. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ dom arctan → (arctan‘𝐴) = ((i / 2) · ((log‘(1 − (i · 𝐴))) − (log‘(1 + (i · 𝐴))))))
 
Theorematanre 26233 A real number is in the domain of the arctangent function. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ ℝ → 𝐴 ∈ dom arctan)
 
Theoremasinneg 26234 The arcsine function is odd. (Contributed by Mario Carneiro, 1-Apr-2015.)
(𝐴 ∈ ℂ → (arcsin‘-𝐴) = -(arcsin‘𝐴))
 
Theoremacosneg 26235 The negative symmetry relation of the arccosine. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ ℂ → (arccos‘-𝐴) = (π − (arccos‘𝐴)))
 
Theoremefiasin 26236 The exponential of the arcsine function. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ ℂ → (exp‘(i · (arcsin‘𝐴))) = ((i · 𝐴) + (√‘(1 − (𝐴↑2)))))
 
Theoremsinasin 26237 The arcsine function is an inverse to sin. This is the main property that justifies the notation arcsin or sin↑-1. Because sin is not an injection, the other converse identity asinsin 26240 is only true under limited circumstances. (Contributed by Mario Carneiro, 1-Apr-2015.)
(𝐴 ∈ ℂ → (sin‘(arcsin‘𝐴)) = 𝐴)
 
Theoremcosacos 26238 The arccosine function is an inverse to cos. (Contributed by Mario Carneiro, 1-Apr-2015.)
(𝐴 ∈ ℂ → (cos‘(arccos‘𝐴)) = 𝐴)
 
Theoremasinsinlem 26239 Lemma for asinsin 26240. (Contributed by Mario Carneiro, 2-Apr-2015.)
((𝐴 ∈ ℂ ∧ (ℜ‘𝐴) ∈ (-(π / 2)(,)(π / 2))) → 0 < (ℜ‘(exp‘(i · 𝐴))))
 
Theoremasinsin 26240 The arcsine function composed with sin is equal to the identity. This plus sinasin 26237 allow to view sin and arcsin as inverse operations to each other. For ease of use, we have not defined precisely the correct domain of correctness of this identity; in addition to the main region described here it is also true for some points on the branch cuts, namely when 𝐴 = (π / 2) − i𝑦 for nonnegative real 𝑦 and also symmetrically at 𝐴 = i𝑦 − (π / 2). In particular, when restricted to reals this identity extends to the closed interval [-(π / 2), (π / 2)], not just the open interval (see reasinsin 26244). (Contributed by Mario Carneiro, 2-Apr-2015.)
((𝐴 ∈ ℂ ∧ (ℜ‘𝐴) ∈ (-(π / 2)(,)(π / 2))) → (arcsin‘(sin‘𝐴)) = 𝐴)
 
Theoremacoscos 26241 The arccosine function is an inverse to cos. (Contributed by Mario Carneiro, 2-Apr-2015.)
((𝐴 ∈ ℂ ∧ (ℜ‘𝐴) ∈ (0(,)π)) → (arccos‘(cos‘𝐴)) = 𝐴)
 
Theoremasin1 26242 The arcsine of 1 is π / 2. (Contributed by Mario Carneiro, 2-Apr-2015.)
(arcsin‘1) = (π / 2)
 
Theoremacos1 26243 The arccosine of 1 is 0. (Contributed by Mario Carneiro, 2-Apr-2015.)
(arccos‘1) = 0
 
Theoremreasinsin 26244 The arcsine function composed with sin is equal to the identity. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ (-(π / 2)[,](π / 2)) → (arcsin‘(sin‘𝐴)) = 𝐴)
 
Theoremasinsinb 26245 Relationship between sine and arcsine. (Contributed by Mario Carneiro, 2-Apr-2015.)
((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ (ℜ‘𝐵) ∈ (-(π / 2)(,)(π / 2))) → ((arcsin‘𝐴) = 𝐵 ↔ (sin‘𝐵) = 𝐴))
 
Theoremacoscosb 26246 Relationship between cosine and arccosine. (Contributed by Mario Carneiro, 2-Apr-2015.)
((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ (ℜ‘𝐵) ∈ (0(,)π)) → ((arccos‘𝐴) = 𝐵 ↔ (cos‘𝐵) = 𝐴))
 
Theoremasinbnd 26247 The arcsine function has range within a vertical strip of the complex plane with real part between -π / 2 and π / 2. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ ℂ → (ℜ‘(arcsin‘𝐴)) ∈ (-(π / 2)[,](π / 2)))
 
Theoremacosbnd 26248 The arccosine function has range within a vertical strip of the complex plane with real part between 0 and π. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ ℂ → (ℜ‘(arccos‘𝐴)) ∈ (0[,]π))
 
Theoremasinrebnd 26249 Bounds on the arcsine function. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ (-1[,]1) → (arcsin‘𝐴) ∈ (-(π / 2)[,](π / 2)))
 
Theoremasinrecl 26250 The arcsine function is real in its principal domain. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ (-1[,]1) → (arcsin‘𝐴) ∈ ℝ)
 
Theoremacosrecl 26251 The arccosine function is real in its principal domain. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ (-1[,]1) → (arccos‘𝐴) ∈ ℝ)
 
Theoremcosasin 26252 The cosine of the arcsine of 𝐴 is √(1 − 𝐴↑2). (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ ℂ → (cos‘(arcsin‘𝐴)) = (√‘(1 − (𝐴↑2))))
 
Theoremsinacos 26253 The sine of the arccosine of 𝐴 is √(1 − 𝐴↑2). (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ ℂ → (sin‘(arccos‘𝐴)) = (√‘(1 − (𝐴↑2))))
 
Theorematandmneg 26254 The domain of the arctangent function is closed under negatives. (Contributed by Mario Carneiro, 3-Apr-2015.)
(𝐴 ∈ dom arctan → -𝐴 ∈ dom arctan)
 
Theorematanneg 26255 The arctangent function is odd. (Contributed by Mario Carneiro, 3-Apr-2015.)
(𝐴 ∈ dom arctan → (arctan‘-𝐴) = -(arctan‘𝐴))
 
Theorematan0 26256 The arctangent of zero is zero. (Contributed by Mario Carneiro, 31-Mar-2015.)
(arctan‘0) = 0
 
Theorematandmcj 26257 The arctangent function distributes under conjugation. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ dom arctan → (∗‘𝐴) ∈ dom arctan)
 
Theorematancj 26258 The arctangent function distributes under conjugation. (The condition that ℜ(𝐴) ≠ 0 is necessary because the branch cuts are chosen so that the negative imaginary line "agrees with" neighboring values with negative real part, while the positive imaginary line agrees with values with positive real part. This makes atanneg 26255 true unconditionally but messes up conjugation symmetry, and it is impossible to have both in a single-valued function. The claim is true on the imaginary line between -1 and 1, though.) (Contributed by Mario Carneiro, 31-Mar-2015.)
((𝐴 ∈ ℂ ∧ (ℜ‘𝐴) ≠ 0) → (𝐴 ∈ dom arctan ∧ (∗‘(arctan‘𝐴)) = (arctan‘(∗‘𝐴))))
 
Theorematanrecl 26259 The arctangent function is real for all real inputs. (Contributed by Mario Carneiro, 31-Mar-2015.)
(𝐴 ∈ ℝ → (arctan‘𝐴) ∈ ℝ)
 
Theoremefiatan 26260 Value of the exponential of an artcangent. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ dom arctan → (exp‘(i · (arctan‘𝐴))) = ((√‘(1 + (i · 𝐴))) / (√‘(1 − (i · 𝐴)))))
 
Theorematanlogaddlem 26261 Lemma for atanlogadd 26262. (Contributed by Mario Carneiro, 3-Apr-2015.)
((𝐴 ∈ dom arctan ∧ 0 ≤ (ℜ‘𝐴)) → ((log‘(1 + (i · 𝐴))) + (log‘(1 − (i · 𝐴)))) ∈ ran log)
 
Theorematanlogadd 26262 The rule √(𝑧𝑤) = (√𝑧)(√𝑤) is not always true on the complex numbers, but it is true when the arguments of 𝑧 and 𝑤 sum to within the interval (-π, π], so there are some cases such as this one with 𝑧 = 1 + i𝐴 and 𝑤 = 1 − i𝐴 which are true unconditionally. This result can also be stated as "√(1 + 𝑧) + √(1 − 𝑧) is analytic". (Contributed by Mario Carneiro, 3-Apr-2015.)
(𝐴 ∈ dom arctan → ((log‘(1 + (i · 𝐴))) + (log‘(1 − (i · 𝐴)))) ∈ ran log)
 
Theorematanlogsublem 26263 Lemma for atanlogsub 26264. (Contributed by Mario Carneiro, 4-Apr-2015.)
((𝐴 ∈ dom arctan ∧ 0 < (ℜ‘𝐴)) → (ℑ‘((log‘(1 + (i · 𝐴))) − (log‘(1 − (i · 𝐴))))) ∈ (-π(,)π))
 
Theorematanlogsub 26264 A variation on atanlogadd 26262, to show that √(1 + i𝑧) / √(1 − i𝑧) = √((1 + i𝑧) / (1 − i𝑧)) under more limited conditions. (Contributed by Mario Carneiro, 4-Apr-2015.)
((𝐴 ∈ dom arctan ∧ (ℜ‘𝐴) ≠ 0) → ((log‘(1 + (i · 𝐴))) − (log‘(1 − (i · 𝐴)))) ∈ ran log)
 
Theoremefiatan2 26265 Value of the exponential of an artcangent. (Contributed by Mario Carneiro, 3-Apr-2015.)
(𝐴 ∈ dom arctan → (exp‘(i · (arctan‘𝐴))) = ((1 + (i · 𝐴)) / (√‘(1 + (𝐴↑2)))))
 
Theorem2efiatan 26266 Value of the exponential of an artcangent. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ dom arctan → (exp‘(2 · (i · (arctan‘𝐴)))) = (((2 · i) / (𝐴 + i)) − 1))
 
Theoremtanatan 26267 The arctangent function is an inverse to tan. (Contributed by Mario Carneiro, 2-Apr-2015.)
(𝐴 ∈ dom arctan → (tan‘(arctan‘𝐴)) = 𝐴)
 
Theorematandmtan 26268 The tangent function has range contained in the domain of the arctangent. (Contributed by Mario Carneiro, 31-Mar-2015.)
((𝐴 ∈ ℂ ∧ (cos‘𝐴) ≠ 0) → (tan‘𝐴) ∈ dom arctan)
 
Theoremcosatan 26269 The cosine of an arctangent. (Contributed by Mario Carneiro, 3-Apr-2015.)
(𝐴 ∈ dom arctan → (cos‘(arctan‘𝐴)) = (1 / (√‘(1 + (𝐴↑2)))))
 
Theoremcosatanne0 26270 The arctangent function has range contained in the domain of the tangent. (Contributed by Mario Carneiro, 3-Apr-2015.)
(𝐴 ∈ dom arctan → (cos‘(arctan‘𝐴)) ≠ 0)
 
Theorematantan 26271 The arctangent function is an inverse to tan. (Contributed by Mario Carneiro, 5-Apr-2015.)
((𝐴 ∈ ℂ ∧ (ℜ‘𝐴) ∈ (-(π / 2)(,)(π / 2))) → (arctan‘(tan‘𝐴)) = 𝐴)
 
Theorematantanb 26272 Relationship between tangent and arctangent. (Contributed by Mario Carneiro, 5-Apr-2015.)
((𝐴 ∈ dom arctan ∧ 𝐵 ∈ ℂ ∧ (ℜ‘𝐵) ∈ (-(π / 2)(,)(π / 2))) → ((arctan‘𝐴) = 𝐵 ↔ (tan‘𝐵) = 𝐴))
 
Theorematanbndlem 26273 Lemma for atanbnd 26274. (Contributed by Mario Carneiro, 5-Apr-2015.)
(𝐴 ∈ ℝ+ → (arctan‘𝐴) ∈ (-(π / 2)(,)(π / 2)))
 
Theorematanbnd 26274 The arctangent function is bounded by π / 2 on the reals. (Contributed by Mario Carneiro, 5-Apr-2015.)
(𝐴 ∈ ℝ → (arctan‘𝐴) ∈ (-(π / 2)(,)(π / 2)))
 
Theorematanord 26275 The arctangent function is strictly increasing. (Contributed by Mario Carneiro, 5-Apr-2015.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 < 𝐵 ↔ (arctan‘𝐴) < (arctan‘𝐵)))
 
Theorematan1 26276 The arctangent of 1 is π / 4. (Contributed by Mario Carneiro, 2-Apr-2015.)
(arctan‘1) = (π / 4)
 
Theorembndatandm 26277 A point in the open unit disk is in the domain of the arctangent. (Contributed by Mario Carneiro, 5-Apr-2015.)
((𝐴 ∈ ℂ ∧ (abs‘𝐴) < 1) → 𝐴 ∈ dom arctan)
 
Theorematans 26278* The "domain of continuity" of the arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐷 = (ℂ ∖ (-∞(,]0))    &   𝑆 = {𝑦 ∈ ℂ ∣ (1 + (𝑦↑2)) ∈ 𝐷}       (𝐴𝑆 ↔ (𝐴 ∈ ℂ ∧ (1 + (𝐴↑2)) ∈ 𝐷))
 
Theorematans2 26279* It suffices to show that 1 − i𝐴 and 1 + i𝐴 are in the continuity domain of log to show that 𝐴 is in the continuity domain of arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐷 = (ℂ ∖ (-∞(,]0))    &   𝑆 = {𝑦 ∈ ℂ ∣ (1 + (𝑦↑2)) ∈ 𝐷}       (𝐴𝑆 ↔ (𝐴 ∈ ℂ ∧ (1 − (i · 𝐴)) ∈ 𝐷 ∧ (1 + (i · 𝐴)) ∈ 𝐷))
 
Theorematansopn 26280* The domain of continuity of the arctangent is an open set. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐷 = (ℂ ∖ (-∞(,]0))    &   𝑆 = {𝑦 ∈ ℂ ∣ (1 + (𝑦↑2)) ∈ 𝐷}       𝑆 ∈ (TopOpen‘ℂfld)
 
Theorematansssdm 26281* The domain of continuity of the arctangent is a subset of the actual domain of the arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐷 = (ℂ ∖ (-∞(,]0))    &   𝑆 = {𝑦 ∈ ℂ ∣ (1 + (𝑦↑2)) ∈ 𝐷}       𝑆 ⊆ dom arctan
 
Theoremressatans 26282* The real number line is a subset of the domain of continuity of the arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐷 = (ℂ ∖ (-∞(,]0))    &   𝑆 = {𝑦 ∈ ℂ ∣ (1 + (𝑦↑2)) ∈ 𝐷}       ℝ ⊆ 𝑆
 
Theoremdvatan 26283* The derivative of the arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐷 = (ℂ ∖ (-∞(,]0))    &   𝑆 = {𝑦 ∈ ℂ ∣ (1 + (𝑦↑2)) ∈ 𝐷}       (ℂ D (arctan ↾ 𝑆)) = (𝑥𝑆 ↦ (1 / (1 + (𝑥↑2))))
 
Theorematancn 26284* The arctangent is a continuous function. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐷 = (ℂ ∖ (-∞(,]0))    &   𝑆 = {𝑦 ∈ ℂ ∣ (1 + (𝑦↑2)) ∈ 𝐷}       (arctan ↾ 𝑆) ∈ (𝑆cn→ℂ)
 
Theorematantayl 26285* The Taylor series for arctan(𝐴). (Contributed by Mario Carneiro, 1-Apr-2015.)
𝐹 = (𝑛 ∈ ℕ ↦ (((i · ((-i↑𝑛) − (i↑𝑛))) / 2) · ((𝐴𝑛) / 𝑛)))       ((𝐴 ∈ ℂ ∧ (abs‘𝐴) < 1) → seq1( + , 𝐹) ⇝ (arctan‘𝐴))
 
Theorematantayl2 26286* The Taylor series for arctan(𝐴). (Contributed by Mario Carneiro, 1-Apr-2015.)
𝐹 = (𝑛 ∈ ℕ ↦ if(2 ∥ 𝑛, 0, ((-1↑((𝑛 − 1) / 2)) · ((𝐴𝑛) / 𝑛))))       ((𝐴 ∈ ℂ ∧ (abs‘𝐴) < 1) → seq1( + , 𝐹) ⇝ (arctan‘𝐴))
 
Theorematantayl3 26287* The Taylor series for arctan(𝐴). (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐹 = (𝑛 ∈ ℕ0 ↦ ((-1↑𝑛) · ((𝐴↑((2 · 𝑛) + 1)) / ((2 · 𝑛) + 1))))       ((𝐴 ∈ ℂ ∧ (abs‘𝐴) < 1) → seq0( + , 𝐹) ⇝ (arctan‘𝐴))
 
Theoremleibpilem1 26288 Lemma for leibpi 26290. (Contributed by Mario Carneiro, 7-Apr-2015.) (Proof shortened by Steven Nguyen, 23-Mar-2023.)
((𝑁 ∈ ℕ0 ∧ (¬ 𝑁 = 0 ∧ ¬ 2 ∥ 𝑁)) → (𝑁 ∈ ℕ ∧ ((𝑁 − 1) / 2) ∈ ℕ0))
 
Theoremleibpilem2 26289* The Leibniz formula for π. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐹 = (𝑛 ∈ ℕ0 ↦ ((-1↑𝑛) / ((2 · 𝑛) + 1)))    &   𝐺 = (𝑘 ∈ ℕ0 ↦ if((𝑘 = 0 ∨ 2 ∥ 𝑘), 0, ((-1↑((𝑘 − 1) / 2)) / 𝑘)))    &   𝐴 ∈ V       (seq0( + , 𝐹) ⇝ 𝐴 ↔ seq0( + , 𝐺) ⇝ 𝐴)
 
Theoremleibpi 26290 The Leibniz formula for π. This proof depends on three main facts: (1) the series 𝐹 is convergent, because it is an alternating series (iseralt 15568). (2) Using leibpilem2 26289 to rewrite the series as a power series, it is the 𝑥 = 1 special case of the Taylor series for arctan (atantayl2 26286). (3) Although we cannot directly plug 𝑥 = 1 into atantayl2 26286, Abel's theorem (abelth2 25799) says that the limit along any sequence converging to 1, such as 1 − 1 / 𝑛, of the power series converges to the power series extended to 1, and then since arctan is continuous at 1 (atancn 26284) we get the desired result. This is Metamath 100 proof #26. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐹 = (𝑛 ∈ ℕ0 ↦ ((-1↑𝑛) / ((2 · 𝑛) + 1)))       seq0( + , 𝐹) ⇝ (π / 4)
 
Theoremleibpisum 26291 The Leibniz formula for π. This version of leibpi 26290 looks nicer but does not assert that the series is convergent so is not as practically useful. (Contributed by Mario Carneiro, 7-Apr-2015.)
Σ𝑛 ∈ ℕ0 ((-1↑𝑛) / ((2 · 𝑛) + 1)) = (π / 4)
 
Theoremlog2cnv 26292 Using the Taylor series for arctan(i / 3), produce a rapidly convergent series for log2. (Contributed by Mario Carneiro, 7-Apr-2015.)
𝐹 = (𝑛 ∈ ℕ0 ↦ (2 / ((3 · ((2 · 𝑛) + 1)) · (9↑𝑛))))       seq0( + , 𝐹) ⇝ (log‘2)
 
Theoremlog2tlbnd 26293* Bound the error term in the series of log2cnv 26292. (Contributed by Mario Carneiro, 7-Apr-2015.)
(𝑁 ∈ ℕ0 → ((log‘2) − Σ𝑛 ∈ (0...(𝑁 − 1))(2 / ((3 · ((2 · 𝑛) + 1)) · (9↑𝑛)))) ∈ (0[,](3 / ((4 · ((2 · 𝑁) + 1)) · (9↑𝑁)))))
 
14.3.9  The Birthday Problem
 
Theoremlog2ublem1 26294 Lemma for log2ub 26297. The proof of log2ub 26297, which is simply the evaluation of log2tlbnd 26293 for 𝑁 = 4, takes the form of the addition of five fractions and showing this is less than another fraction. We could just perform exact arithmetic on these fractions, get a large rational number, and just multiply everything to verify the claim, but as anyone who uses decimal numbers for this task knows, it is often better to pick a common denominator 𝑑 (usually a large power of 10) and work with the closest approximations of the form 𝑛 / 𝑑 for some integer 𝑛 instead. It turns out that for our purposes it is sufficient to take 𝑑 = (3↑7) · 5 · 7, which is also nice because it shares many factors in common with the fractions in question. (Contributed by Mario Carneiro, 17-Apr-2015.)
(((3↑7) · (5 · 7)) · 𝐴) ≤ 𝐵    &   𝐴 ∈ ℝ    &   𝐷 ∈ ℕ0    &   𝐸 ∈ ℕ    &   𝐵 ∈ ℕ0    &   𝐹 ∈ ℕ0    &   𝐶 = (𝐴 + (𝐷 / 𝐸))    &   (𝐵 + 𝐹) = 𝐺    &   (((3↑7) · (5 · 7)) · 𝐷) ≤ (𝐸 · 𝐹)       (((3↑7) · (5 · 7)) · 𝐶) ≤ 𝐺
 
Theoremlog2ublem2 26295* Lemma for log2ub 26297. (Contributed by Mario Carneiro, 17-Apr-2015.)
(((3↑7) · (5 · 7)) · Σ𝑛 ∈ (0...𝐾)(2 / ((3 · ((2 · 𝑛) + 1)) · (9↑𝑛)))) ≤ (2 · 𝐵)    &   𝐵 ∈ ℕ0    &   𝐹 ∈ ℕ0    &   𝑁 ∈ ℕ0    &   (𝑁 − 1) = 𝐾    &   (𝐵 + 𝐹) = 𝐺    &   𝑀 ∈ ℕ0    &   (𝑀 + 𝑁) = 3    &   ((5 · 7) · (9↑𝑀)) = (((2 · 𝑁) + 1) · 𝐹)       (((3↑7) · (5 · 7)) · Σ𝑛 ∈ (0...𝑁)(2 / ((3 · ((2 · 𝑛) + 1)) · (9↑𝑛)))) ≤ (2 · 𝐺)
 
Theoremlog2ublem3 26296 Lemma for log2ub 26297. In decimal, this is a proof that the first four terms of the series for log2 is less than 53056 / 76545. (Contributed by Mario Carneiro, 17-Apr-2015.) (Proof shortened by AV, 15-Sep-2021.)
(((3↑7) · (5 · 7)) · Σ𝑛 ∈ (0...3)(2 / ((3 · ((2 · 𝑛) + 1)) · (9↑𝑛)))) ≤ 53056
 
Theoremlog2ub 26297 log2 is less than 253 / 365. If written in decimal, this is because log2 = 0.693147... is less than 253/365 = 0.693151... , so this is a very tight bound, at five decimal places. (Contributed by Mario Carneiro, 7-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.)
(log‘2) < (253 / 365)
 
Theoremlog2le1 26298 log2 is less than 1. This is just a weaker form of log2ub 26297 when no tight upper bound is required. (Contributed by Thierry Arnoux, 27-Sep-2017.)
(log‘2) < 1
 
Theorembirthdaylem1 26299* Lemma for birthday 26302. (Contributed by Mario Carneiro, 17-Apr-2015.)
𝑆 = {𝑓𝑓:(1...𝐾)⟶(1...𝑁)}    &   𝑇 = {𝑓𝑓:(1...𝐾)–1-1→(1...𝑁)}       (𝑇𝑆𝑆 ∈ Fin ∧ (𝑁 ∈ ℕ → 𝑆 ≠ ∅))
 
Theorembirthdaylem2 26300* For general 𝑁 and 𝐾, count the fraction of injective functions from 1...𝐾 to 1...𝑁. (Contributed by Mario Carneiro, 7-May-2015.)
𝑆 = {𝑓𝑓:(1...𝐾)⟶(1...𝑁)}    &   𝑇 = {𝑓𝑓:(1...𝐾)–1-1→(1...𝑁)}       ((𝑁 ∈ ℕ ∧ 𝐾 ∈ (0...𝑁)) → ((♯‘𝑇) / (♯‘𝑆)) = (exp‘Σ𝑘 ∈ (0...(𝐾 − 1))(log‘(1 − (𝑘 / 𝑁)))))
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268 26701-26800 269 26801-26900 270 26901-27000 271 27001-27100 272 27101-27200 273 27201-27300 274 27301-27400 275 27401-27500 276 27501-27600 277 27601-27700 278 27701-27800 279 27801-27900 280 27901-28000 281 28001-28100 282 28101-28200 283 28201-28300 284 28301-28400 285 28401-28500 286 28501-28600 287 28601-28700 288 28701-28800 289 28801-28900 290 28901-29000 291 29001-29100 292 29101-29200 293 29201-29300 294 29301-29400 295 29401-29500 296 29501-29600 297 29601-29700 298 29701-29800 299 29801-29900 300 29901-30000 301 30001-30100 302 30101-30200 303 30201-30300 304 30301-30400 305 30401-30500 306 30501-30600 307 30601-30700 308 30701-30800 309 30801-30900 310 30901-31000 311 31001-31100 312 31101-31200 313 31201-31300 314 31301-31400 315 31401-31500 316 31501-31600 317 31601-31700 318 31701-31800 319 31801-31900 320 31901-32000 321 32001-32100 322 32101-32200 323 32201-32300 324 32301-32400 325 32401-32500 326 32501-32600 327 32601-32700 328 32701-32800 329 32801-32900 330 32901-33000 331 33001-33100 332 33101-33200 333 33201-33300 334 33301-33400 335 33401-33500 336 33501-33600 337 33601-33700 338 33701-33800 339 33801-33900 340 33901-34000 341 34001-34100 342 34101-34200 343 34201-34300 344 34301-34400 345 34401-34500 346 34501-34600 347 34601-34700 348 34701-34800 349 34801-34900 350 34901-35000 351 35001-35100 352 35101-35200 353 35201-35300 354 35301-35400 355 35401-35500 356 35501-35600 357 35601-35700 358 35701-35800 359 35801-35900 360 35901-36000 361 36001-36100 362 36101-36200 363 36201-36300 364 36301-36400 365 36401-36500 366 36501-36600 367 36601-36700 368 36701-36800 369 36801-36900 370 36901-37000 371 37001-37100 372 37101-37200 373 37201-37300 374 37301-37400 375 37401-37500 376 37501-37600 377 37601-37700 378 37701-37800 379 37801-37900 380 37901-38000 381 38001-38100 382 38101-38200 383 38201-38300 384 38301-38400 385 38401-38500 386 38501-38600 387 38601-38700 388 38701-38800 389 38801-38900 390 38901-39000 391 39001-39100 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454 45301-45400 455 45401-45500 456 45501-45600 457 45601-45700 458 45701-45800 459 45801-45900 460 45901-46000 461 46001-46100 462 46101-46200 463 46201-46300 464 46301-46400 465 46401-46500 466 46501-46600 467 46601-46700 468 46701-46800 469 46801-46900 470 46901-47000 471 47001-47100 472 47101-47200 473 47201-47223
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