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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | 4ne0 12301 | The number 4 is nonzero. (Contributed by David A. Wheeler, 5-Dec-2018.) |
| ⊢ 4 ≠ 0 | ||
| Theorem | 5pos 12302 | The number 5 is positive. (Contributed by NM, 27-May-1999.) |
| ⊢ 0 < 5 | ||
| Theorem | 6pos 12303 | The number 6 is positive. (Contributed by NM, 27-May-1999.) |
| ⊢ 0 < 6 | ||
| Theorem | 7pos 12304 | The number 7 is positive. (Contributed by NM, 27-May-1999.) |
| ⊢ 0 < 7 | ||
| Theorem | 8pos 12305 | The number 8 is positive. (Contributed by NM, 27-May-1999.) |
| ⊢ 0 < 8 | ||
| Theorem | 9pos 12306 | The number 9 is positive. (Contributed by NM, 27-May-1999.) |
| ⊢ 0 < 9 | ||
This section includes specific theorems about one-digit natural numbers (membership, addition, subtraction, multiplication, division, ordering). | ||
| Theorem | 1pneg1e0 12307 | 1 + -1 is 0. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ (1 + -1) = 0 | ||
| Theorem | 0m0e0 12308 | 0 minus 0 equals 0. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ (0 − 0) = 0 | ||
| Theorem | 1m0e1 12309 | 1 - 0 = 1. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ (1 − 0) = 1 | ||
| Theorem | 0p1e1 12310 | 0 + 1 = 1. (Contributed by David A. Wheeler, 7-Jul-2016.) |
| ⊢ (0 + 1) = 1 | ||
| Theorem | fv0p1e1 12311 | Function value at 𝑁 + 1 with 𝑁 replaced by 0. Technical theorem to be used to reduce the size of a significant number of proofs. (Contributed by AV, 13-Aug-2022.) |
| ⊢ (𝑁 = 0 → (𝐹‘(𝑁 + 1)) = (𝐹‘1)) | ||
| Theorem | 1p0e1 12312 | 1 + 0 = 1. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ (1 + 0) = 1 | ||
| Theorem | 1p1e2 12313 | 1 + 1 = 2. (Contributed by NM, 1-Apr-2008.) |
| ⊢ (1 + 1) = 2 | ||
| Theorem | 2m1e1 12314 | 2 - 1 = 1. The result is on the right-hand-side to be consistent with similar proofs like 4p4e8 12343. (Contributed by David A. Wheeler, 4-Jan-2017.) |
| ⊢ (2 − 1) = 1 | ||
| Theorem | 1e2m1 12315 | 1 = 2 - 1. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ 1 = (2 − 1) | ||
| Theorem | 3m1e2 12316 | 3 - 1 = 2. (Contributed by FL, 17-Oct-2010.) (Revised by NM, 10-Dec-2017.) (Proof shortened by AV, 6-Sep-2021.) |
| ⊢ (3 − 1) = 2 | ||
| Theorem | 4m1e3 12317 | 4 - 1 = 3. (Contributed by AV, 8-Feb-2021.) (Proof shortened by AV, 6-Sep-2021.) |
| ⊢ (4 − 1) = 3 | ||
| Theorem | 5m1e4 12318 | 5 - 1 = 4. (Contributed by AV, 6-Sep-2021.) |
| ⊢ (5 − 1) = 4 | ||
| Theorem | 6m1e5 12319 | 6 - 1 = 5. (Contributed by AV, 6-Sep-2021.) |
| ⊢ (6 − 1) = 5 | ||
| Theorem | 7m1e6 12320 | 7 - 1 = 6. (Contributed by AV, 6-Sep-2021.) |
| ⊢ (7 − 1) = 6 | ||
| Theorem | 8m1e7 12321 | 8 - 1 = 7. (Contributed by AV, 6-Sep-2021.) |
| ⊢ (8 − 1) = 7 | ||
| Theorem | 9m1e8 12322 | 9 - 1 = 8. (Contributed by AV, 6-Sep-2021.) |
| ⊢ (9 − 1) = 8 | ||
| Theorem | 2p2e4 12323 | Two plus two equals four. For more information, see "2+2=4 Trivia" on the Metamath Proof Explorer Home Page: mmset.html#trivia. This proof is simple, but it depends on many other proof steps because 2 and 4 are complex numbers and thus it depends on our construction of complex numbers. The proof o2p2e4 8508 is similar but proves 2 + 2 = 4 using ordinal natural numbers (finite integers starting at 0), so that proof depends on fewer intermediate steps. (Contributed by NM, 27-May-1999.) |
| ⊢ (2 + 2) = 4 | ||
| Theorem | 2times 12324 | Two times a number. (Contributed by NM, 10-Oct-2004.) (Revised by Mario Carneiro, 27-May-2016.) (Proof shortened by AV, 26-Feb-2020.) |
| ⊢ (𝐴 ∈ ℂ → (2 · 𝐴) = (𝐴 + 𝐴)) | ||
| Theorem | times2 12325 | A number times 2. (Contributed by NM, 16-Oct-2007.) |
| ⊢ (𝐴 ∈ ℂ → (𝐴 · 2) = (𝐴 + 𝐴)) | ||
| Theorem | 2timesi 12326 | Two times a number. (Contributed by NM, 1-Aug-1999.) |
| ⊢ 𝐴 ∈ ℂ ⇒ ⊢ (2 · 𝐴) = (𝐴 + 𝐴) | ||
| Theorem | times2i 12327 | A number times 2. (Contributed by NM, 11-May-2004.) |
| ⊢ 𝐴 ∈ ℂ ⇒ ⊢ (𝐴 · 2) = (𝐴 + 𝐴) | ||
| Theorem | 2txmxeqx 12328 | Two times a complex number minus the number itself results in the number itself. (Contributed by Alexander van der Vekens, 8-Jun-2018.) |
| ⊢ (𝑋 ∈ ℂ → ((2 · 𝑋) − 𝑋) = 𝑋) | ||
| Theorem | 2div2e1 12329 | 2 divided by 2 is 1. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ (2 / 2) = 1 | ||
| Theorem | 2p1e3 12330 | 2 + 1 = 3. (Contributed by Mario Carneiro, 18-Apr-2015.) |
| ⊢ (2 + 1) = 3 | ||
| Theorem | 1p2e3 12331 | 1 + 2 = 3. For a shorter proof using addcomli 11373, see 1p2e3ALT 12332. (Contributed by David A. Wheeler, 8-Dec-2018.) Reduce dependencies on axioms. (Revised by Steven Nguyen, 12-Dec-2022.) |
| ⊢ (1 + 2) = 3 | ||
| Theorem | 1p2e3ALT 12332 | Alternate proof of 1p2e3 12331, shorter but using more axioms. (Contributed by David A. Wheeler, 8-Dec-2018.) (New usage is discouraged.) (Proof modification is discouraged.) |
| ⊢ (1 + 2) = 3 | ||
| Theorem | 3p1e4 12333 | 3 + 1 = 4. (Contributed by Mario Carneiro, 18-Apr-2015.) |
| ⊢ (3 + 1) = 4 | ||
| Theorem | 4p1e5 12334 | 4 + 1 = 5. (Contributed by Mario Carneiro, 18-Apr-2015.) |
| ⊢ (4 + 1) = 5 | ||
| Theorem | 5p1e6 12335 | 5 + 1 = 6. (Contributed by Mario Carneiro, 18-Apr-2015.) |
| ⊢ (5 + 1) = 6 | ||
| Theorem | 6p1e7 12336 | 6 + 1 = 7. (Contributed by Mario Carneiro, 18-Apr-2015.) |
| ⊢ (6 + 1) = 7 | ||
| Theorem | 7p1e8 12337 | 7 + 1 = 8. (Contributed by Mario Carneiro, 18-Apr-2015.) |
| ⊢ (7 + 1) = 8 | ||
| Theorem | 8p1e9 12338 | 8 + 1 = 9. (Contributed by Mario Carneiro, 18-Apr-2015.) |
| ⊢ (8 + 1) = 9 | ||
| Theorem | 3p2e5 12339 | 3 + 2 = 5. (Contributed by NM, 11-May-2004.) |
| ⊢ (3 + 2) = 5 | ||
| Theorem | 3p3e6 12340 | 3 + 3 = 6. (Contributed by NM, 11-May-2004.) |
| ⊢ (3 + 3) = 6 | ||
| Theorem | 4p2e6 12341 | 4 + 2 = 6. (Contributed by NM, 11-May-2004.) |
| ⊢ (4 + 2) = 6 | ||
| Theorem | 4p3e7 12342 | 4 + 3 = 7. (Contributed by NM, 11-May-2004.) |
| ⊢ (4 + 3) = 7 | ||
| Theorem | 4p4e8 12343 | 4 + 4 = 8. (Contributed by NM, 11-May-2004.) |
| ⊢ (4 + 4) = 8 | ||
| Theorem | 5p2e7 12344 | 5 + 2 = 7. (Contributed by NM, 11-May-2004.) |
| ⊢ (5 + 2) = 7 | ||
| Theorem | 5p3e8 12345 | 5 + 3 = 8. (Contributed by NM, 11-May-2004.) |
| ⊢ (5 + 3) = 8 | ||
| Theorem | 5p4e9 12346 | 5 + 4 = 9. (Contributed by NM, 11-May-2004.) |
| ⊢ (5 + 4) = 9 | ||
| Theorem | 6p2e8 12347 | 6 + 2 = 8. (Contributed by NM, 11-May-2004.) |
| ⊢ (6 + 2) = 8 | ||
| Theorem | 6p3e9 12348 | 6 + 3 = 9. (Contributed by NM, 11-May-2004.) |
| ⊢ (6 + 3) = 9 | ||
| Theorem | 7p2e9 12349 | 7 + 2 = 9. (Contributed by NM, 11-May-2004.) |
| ⊢ (7 + 2) = 9 | ||
| Theorem | 1t1e1 12350 | 1 times 1 equals 1. (Contributed by David A. Wheeler, 7-Jul-2016.) |
| ⊢ (1 · 1) = 1 | ||
| Theorem | 2t1e2 12351 | 2 times 1 equals 2. (Contributed by David A. Wheeler, 6-Dec-2018.) |
| ⊢ (2 · 1) = 2 | ||
| Theorem | 2t2e4 12352 | 2 times 2 equals 4. (Contributed by NM, 1-Aug-1999.) |
| ⊢ (2 · 2) = 4 | ||
| Theorem | 3t1e3 12353 | 3 times 1 equals 3. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ (3 · 1) = 3 | ||
| Theorem | 3t2e6 12354 | 3 times 2 equals 6. (Contributed by NM, 2-Aug-2004.) |
| ⊢ (3 · 2) = 6 | ||
| Theorem | 3t3e9 12355 | 3 times 3 equals 9. (Contributed by NM, 11-May-2004.) |
| ⊢ (3 · 3) = 9 | ||
| Theorem | 4t2e8 12356 | 4 times 2 equals 8. (Contributed by NM, 2-Aug-2004.) |
| ⊢ (4 · 2) = 8 | ||
| Theorem | 2t0e0 12357 | 2 times 0 equals 0. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ (2 · 0) = 0 | ||
| Theorem | 4d2e2 12358 | One half of four is two. (Contributed by NM, 3-Sep-1999.) |
| ⊢ (4 / 2) = 2 | ||
| Theorem | 1lt2 12359 | 1 is less than 2. (Contributed by NM, 24-Feb-2005.) |
| ⊢ 1 < 2 | ||
| Theorem | 2lt3 12360 | 2 is less than 3. (Contributed by NM, 26-Sep-2010.) |
| ⊢ 2 < 3 | ||
| Theorem | 1lt3 12361 | 1 is less than 3. (Contributed by NM, 26-Sep-2010.) |
| ⊢ 1 < 3 | ||
| Theorem | 3lt4 12362 | 3 is less than 4. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 3 < 4 | ||
| Theorem | 2lt4 12363 | 2 is less than 4. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 2 < 4 | ||
| Theorem | 1lt4 12364 | 1 is less than 4. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 1 < 4 | ||
| Theorem | 4lt5 12365 | 4 is less than 5. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 4 < 5 | ||
| Theorem | 3lt5 12366 | 3 is less than 5. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 3 < 5 | ||
| Theorem | 2lt5 12367 | 2 is less than 5. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 2 < 5 | ||
| Theorem | 1lt5 12368 | 1 is less than 5. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 1 < 5 | ||
| Theorem | 5lt6 12369 | 5 is less than 6. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 5 < 6 | ||
| Theorem | 4lt6 12370 | 4 is less than 6. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 4 < 6 | ||
| Theorem | 3lt6 12371 | 3 is less than 6. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 3 < 6 | ||
| Theorem | 2lt6 12372 | 2 is less than 6. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 2 < 6 | ||
| Theorem | 1lt6 12373 | 1 is less than 6. (Contributed by NM, 19-Oct-2012.) |
| ⊢ 1 < 6 | ||
| Theorem | 6lt7 12374 | 6 is less than 7. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 6 < 7 | ||
| Theorem | 5lt7 12375 | 5 is less than 7. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 5 < 7 | ||
| Theorem | 4lt7 12376 | 4 is less than 7. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 4 < 7 | ||
| Theorem | 3lt7 12377 | 3 is less than 7. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 3 < 7 | ||
| Theorem | 2lt7 12378 | 2 is less than 7. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 2 < 7 | ||
| Theorem | 1lt7 12379 | 1 is less than 7. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 1 < 7 | ||
| Theorem | 7lt8 12380 | 7 is less than 8. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 7 < 8 | ||
| Theorem | 6lt8 12381 | 6 is less than 8. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 6 < 8 | ||
| Theorem | 5lt8 12382 | 5 is less than 8. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 5 < 8 | ||
| Theorem | 4lt8 12383 | 4 is less than 8. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 4 < 8 | ||
| Theorem | 3lt8 12384 | 3 is less than 8. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 3 < 8 | ||
| Theorem | 2lt8 12385 | 2 is less than 8. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 2 < 8 | ||
| Theorem | 1lt8 12386 | 1 is less than 8. (Contributed by Mario Carneiro, 15-Sep-2013.) |
| ⊢ 1 < 8 | ||
| Theorem | 8lt9 12387 | 8 is less than 9. (Contributed by Mario Carneiro, 19-Feb-2014.) |
| ⊢ 8 < 9 | ||
| Theorem | 7lt9 12388 | 7 is less than 9. (Contributed by Mario Carneiro, 9-Mar-2015.) |
| ⊢ 7 < 9 | ||
| Theorem | 6lt9 12389 | 6 is less than 9. (Contributed by Mario Carneiro, 9-Mar-2015.) |
| ⊢ 6 < 9 | ||
| Theorem | 5lt9 12390 | 5 is less than 9. (Contributed by Mario Carneiro, 9-Mar-2015.) |
| ⊢ 5 < 9 | ||
| Theorem | 4lt9 12391 | 4 is less than 9. (Contributed by Mario Carneiro, 9-Mar-2015.) |
| ⊢ 4 < 9 | ||
| Theorem | 3lt9 12392 | 3 is less than 9. (Contributed by Mario Carneiro, 9-Mar-2015.) |
| ⊢ 3 < 9 | ||
| Theorem | 2lt9 12393 | 2 is less than 9. (Contributed by Mario Carneiro, 9-Mar-2015.) |
| ⊢ 2 < 9 | ||
| Theorem | 1lt9 12394 | 1 is less than 9. (Contributed by NM, 19-Oct-2012.) (Revised by Mario Carneiro, 9-Mar-2015.) |
| ⊢ 1 < 9 | ||
| Theorem | 0ne2 12395 | 0 is not equal to 2. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ 0 ≠ 2 | ||
| Theorem | 1ne2 12396 | 1 is not equal to 2. (Contributed by NM, 19-Oct-2012.) |
| ⊢ 1 ≠ 2 | ||
| Theorem | 1le2 12397 | 1 is less than or equal to 2. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ 1 ≤ 2 | ||
| Theorem | 2cnne0 12398 | 2 is a nonzero complex number. (Contributed by David A. Wheeler, 7-Dec-2018.) |
| ⊢ (2 ∈ ℂ ∧ 2 ≠ 0) | ||
| Theorem | 2rene0 12399 | 2 is a nonzero real number. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ (2 ∈ ℝ ∧ 2 ≠ 0) | ||
| Theorem | 1le3 12400 | 1 is less than or equal to 3. (Contributed by David A. Wheeler, 8-Dec-2018.) |
| ⊢ 1 ≤ 3 | ||
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