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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | prmo2 17101 | The primorial of 2. (Contributed by AV, 28-Aug-2020.) |
| ⊢ (#p‘2) = 2 | ||
| Theorem | prmo3 17102 | The primorial of 3. (Contributed by AV, 28-Aug-2020.) |
| ⊢ (#p‘3) = 6 | ||
| Theorem | prmdvdsprmo 17103* | The primorial of a number is divisible by each prime less than or equal to the number. (Contributed by AV, 15-Aug-2020.) (Revised by AV, 28-Aug-2020.) |
| ⊢ (𝑁 ∈ ℕ → ∀𝑝 ∈ ℙ (𝑝 ≤ 𝑁 → 𝑝 ∥ (#p‘𝑁))) | ||
| Theorem | prmdvdsprmop 17104* | The primorial of a number plus an integer greater than 1 and less than or equal to the number is divisible by a prime less than or equal to the number. (Contributed by AV, 15-Aug-2020.) (Revised by AV, 28-Aug-2020.) |
| ⊢ ((𝑁 ∈ ℕ ∧ 𝐼 ∈ (2...𝑁)) → ∃𝑝 ∈ ℙ (𝑝 ≤ 𝑁 ∧ 𝑝 ∥ 𝐼 ∧ 𝑝 ∥ ((#p‘𝑁) + 𝐼))) | ||
| Theorem | fvprmselelfz 17105* | The value of the prime selection function is in a finite sequence of integers if the argument is in this finite sequence of integers. (Contributed by AV, 19-Aug-2020.) |
| ⊢ 𝐹 = (𝑚 ∈ ℕ ↦ if(𝑚 ∈ ℙ, 𝑚, 1)) ⇒ ⊢ ((𝑁 ∈ ℕ ∧ 𝑋 ∈ (1...𝑁)) → (𝐹‘𝑋) ∈ (1...𝑁)) | ||
| Theorem | fvprmselgcd1 17106* | The greatest common divisor of two values of the prime selection function for different arguments is 1. (Contributed by AV, 19-Aug-2020.) |
| ⊢ 𝐹 = (𝑚 ∈ ℕ ↦ if(𝑚 ∈ ℙ, 𝑚, 1)) ⇒ ⊢ ((𝑋 ∈ (1...𝑁) ∧ 𝑌 ∈ (1...𝑁) ∧ 𝑋 ≠ 𝑌) → ((𝐹‘𝑋) gcd (𝐹‘𝑌)) = 1) | ||
| Theorem | prmolefac 17107 | The primorial of a positive integer is less than or equal to the factorial of the integer. (Contributed by AV, 15-Aug-2020.) (Revised by AV, 29-Aug-2020.) |
| ⊢ (𝑁 ∈ ℕ0 → (#p‘𝑁) ≤ (!‘𝑁)) | ||
| Theorem | prmodvdslcmf 17108 | The primorial of a nonnegative integer divides the least common multiple of all positive integers less than or equal to the integer. (Contributed by AV, 19-Aug-2020.) (Revised by AV, 29-Aug-2020.) |
| ⊢ (𝑁 ∈ ℕ0 → (#p‘𝑁) ∥ (lcm‘(1...𝑁))) | ||
| Theorem | prmolelcmf 17109 | The primorial of a positive integer is less than or equal to the least common multiple of all positive integers less than or equal to the integer. (Contributed by AV, 19-Aug-2020.) (Revised by AV, 29-Aug-2020.) |
| ⊢ (𝑁 ∈ ℕ0 → (#p‘𝑁) ≤ (lcm‘(1...𝑁))) | ||
According to Wikipedia "Prime gap", https://en.wikipedia.org/wiki/Prime_gap (16-Aug-2020): "A prime gap is the difference between two successive prime numbers. The n-th prime gap, denoted gn or g(pn) is the difference between the (n+1)-th and the n-th prime numbers, i.e. gn = pn+1 - pn . We have g1 = 1, g2 = g3 = 2, and g4 = 4." It can be proven that there are arbitrary large gaps, usually by showing that "in the sequence n!+2, n!+3, ..., n!+n the first term is divisible by 2, the second term is divisible by 3, and so on. Thus, this is a sequence of n-1 consecutive composite integers, and it must belong to a gap between primes having length at least n.", see prmgap 17120. Instead of using the factorial of n (see df-fac 14312), any function can be chosen for which f(n) is not relatively prime to the integers 2, 3, ..., n. For example, the least common multiple of the integers 2, 3, ..., n, see prmgaplcm 17121, or the primorial n# (the product of all prime numbers less than or equal to n), see prmgapprmo 17123, are such functions, which provide smaller values than the factorial function (see lcmflefac 16707 and prmolefac 17107 resp. prmolelcmf 17109): "For instance, the first prime gap of size larger than 14 occurs between the primes 523 and 541, while 15! is the vastly larger number 1307674368000." But the least common multiple of the integers 2, 3, ..., 15 is 360360, and 15# is 30030 (p3248 = 30029 and P3249 = 30047, so g3248 = 18). | ||
| Theorem | prmgaplem1 17110 | Lemma for prmgap 17120: The factorial of a number plus an integer greater than 1 and less than or equal to the number is divisible by that integer. (Contributed by AV, 13-Aug-2020.) |
| ⊢ ((𝑁 ∈ ℕ ∧ 𝐼 ∈ (2...𝑁)) → 𝐼 ∥ ((!‘𝑁) + 𝐼)) | ||
| Theorem | prmgaplem2 17111 | Lemma for prmgap 17120: The factorial of a number plus an integer greater than 1 and less than or equal to the number are not coprime. (Contributed by AV, 13-Aug-2020.) |
| ⊢ ((𝑁 ∈ ℕ ∧ 𝐼 ∈ (2...𝑁)) → 1 < (((!‘𝑁) + 𝐼) gcd 𝐼)) | ||
| Theorem | prmgaplcmlem1 17112 | Lemma for prmgaplcm 17121: The least common multiple of all positive integers less than or equal to a number plus an integer greater than 1 and less than or equal to the number is divisible by that integer. (Contributed by AV, 14-Aug-2020.) (Revised by AV, 27-Aug-2020.) |
| ⊢ ((𝑁 ∈ ℕ ∧ 𝐼 ∈ (2...𝑁)) → 𝐼 ∥ ((lcm‘(1...𝑁)) + 𝐼)) | ||
| Theorem | prmgaplcmlem2 17113 | Lemma for prmgaplcm 17121: The least common multiple of all positive integers less than or equal to a number plus an integer greater than 1 and less than or equal to the number are not coprime. (Contributed by AV, 14-Aug-2020.) (Revised by AV, 27-Aug-2020.) |
| ⊢ ((𝑁 ∈ ℕ ∧ 𝐼 ∈ (2...𝑁)) → 1 < (((lcm‘(1...𝑁)) + 𝐼) gcd 𝐼)) | ||
| Theorem | prmgaplem3 17114* | Lemma for prmgap 17120. (Contributed by AV, 9-Aug-2020.) |
| ⊢ 𝐴 = {𝑝 ∈ ℙ ∣ 𝑝 < 𝑁} ⇒ ⊢ (𝑁 ∈ (ℤ≥‘3) → ∃𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 𝑦 ≤ 𝑥) | ||
| Theorem | prmgaplem4 17115* | Lemma for prmgap 17120. (Contributed by AV, 10-Aug-2020.) |
| ⊢ 𝐴 = {𝑝 ∈ ℙ ∣ (𝑁 < 𝑝 ∧ 𝑝 ≤ 𝑃)} ⇒ ⊢ ((𝑁 ∈ ℕ ∧ 𝑃 ∈ ℙ ∧ 𝑁 < 𝑃) → ∃𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐴 𝑥 ≤ 𝑦) | ||
| Theorem | prmgaplem5 17116* | Lemma for prmgap 17120: for each integer greater than 2 there is a smaller prime closest to this integer, i.e. there is a smaller prime and no other prime is between this prime and the integer. (Contributed by AV, 9-Aug-2020.) |
| ⊢ (𝑁 ∈ (ℤ≥‘3) → ∃𝑝 ∈ ℙ (𝑝 < 𝑁 ∧ ∀𝑧 ∈ ((𝑝 + 1)..^𝑁)𝑧 ∉ ℙ)) | ||
| Theorem | prmgaplem6 17117* | Lemma for prmgap 17120: for each positive integer there is a greater prime closest to this integer, i.e. there is a greater prime and no other prime is between this prime and the integer. (Contributed by AV, 10-Aug-2020.) |
| ⊢ (𝑁 ∈ ℕ → ∃𝑝 ∈ ℙ (𝑁 < 𝑝 ∧ ∀𝑧 ∈ ((𝑁 + 1)..^𝑝)𝑧 ∉ ℙ)) | ||
| Theorem | prmgaplem7 17118* | Lemma for prmgap 17120. (Contributed by AV, 12-Aug-2020.) (Proof shortened by AV, 10-Jul-2022.) |
| ⊢ (𝜑 → 𝑁 ∈ ℕ) & ⊢ (𝜑 → 𝐹 ∈ (ℕ ↑m ℕ)) & ⊢ (𝜑 → ∀𝑖 ∈ (2...𝑁)1 < (((𝐹‘𝑁) + 𝑖) gcd 𝑖)) ⇒ ⊢ (𝜑 → ∃𝑝 ∈ ℙ ∃𝑞 ∈ ℙ (𝑝 < ((𝐹‘𝑁) + 2) ∧ ((𝐹‘𝑁) + 𝑁) < 𝑞 ∧ ∀𝑧 ∈ ((𝑝 + 1)..^𝑞)𝑧 ∉ ℙ)) | ||
| Theorem | prmgaplem8 17119* | Lemma for prmgap 17120. (Contributed by AV, 13-Aug-2020.) |
| ⊢ (𝜑 → 𝑁 ∈ ℕ) & ⊢ (𝜑 → 𝐹 ∈ (ℕ ↑m ℕ)) & ⊢ (𝜑 → ∀𝑖 ∈ (2...𝑁)1 < (((𝐹‘𝑁) + 𝑖) gcd 𝑖)) ⇒ ⊢ (𝜑 → ∃𝑝 ∈ ℙ ∃𝑞 ∈ ℙ (𝑁 ≤ (𝑞 − 𝑝) ∧ ∀𝑧 ∈ ((𝑝 + 1)..^𝑞)𝑧 ∉ ℙ)) | ||
| Theorem | prmgap 17120* | The prime gap theorem: for each positive integer there are (at least) two successive primes with a difference ("gap") at least as big as the given integer. (Contributed by AV, 13-Aug-2020.) |
| ⊢ ∀𝑛 ∈ ℕ ∃𝑝 ∈ ℙ ∃𝑞 ∈ ℙ (𝑛 ≤ (𝑞 − 𝑝) ∧ ∀𝑧 ∈ ((𝑝 + 1)..^𝑞)𝑧 ∉ ℙ) | ||
| Theorem | prmgaplcm 17121* | Alternate proof of prmgap 17120: in contrast to prmgap 17120, where the gap starts at n! , the factorial of n, the gap starts at the least common multiple of all positive integers less than or equal to n. (Contributed by AV, 13-Aug-2020.) (Revised by AV, 27-Aug-2020.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ ∀𝑛 ∈ ℕ ∃𝑝 ∈ ℙ ∃𝑞 ∈ ℙ (𝑛 ≤ (𝑞 − 𝑝) ∧ ∀𝑧 ∈ ((𝑝 + 1)..^𝑞)𝑧 ∉ ℙ) | ||
| Theorem | prmgapprmolem 17122 | Lemma for prmgapprmo 17123: The primorial of a number plus an integer greater than 1 and less than or equal to the number are not coprime. (Contributed by AV, 15-Aug-2020.) (Revised by AV, 29-Aug-2020.) |
| ⊢ ((𝑁 ∈ ℕ ∧ 𝐼 ∈ (2...𝑁)) → 1 < (((#p‘𝑁) + 𝐼) gcd 𝐼)) | ||
| Theorem | prmgapprmo 17123* | Alternate proof of prmgap 17120: in contrast to prmgap 17120, where the gap starts at n! , the factorial of n, the gap starts at n#, the primorial of n. (Contributed by AV, 15-Aug-2020.) (Revised by AV, 29-Aug-2020.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ ∀𝑛 ∈ ℕ ∃𝑝 ∈ ℙ ∃𝑞 ∈ ℙ (𝑛 ≤ (𝑞 − 𝑝) ∧ ∀𝑧 ∈ ((𝑝 + 1)..^𝑞)𝑧 ∉ ℙ) | ||
| Theorem | dec2dvds 17124 | Divisibility by two is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ0 & ⊢ (𝐵 · 2) = 𝐶 & ⊢ 𝐷 = (𝐶 + 1) ⇒ ⊢ ¬ 2 ∥ ;𝐴𝐷 | ||
| Theorem | dec5dvds 17125 | Divisibility by five is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ & ⊢ 𝐵 < 5 ⇒ ⊢ ¬ 5 ∥ ;𝐴𝐵 | ||
| Theorem | dec5dvds2 17126 | Divisibility by five is obvious in base 10. (Contributed by Mario Carneiro, 19-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ & ⊢ 𝐵 < 5 & ⊢ (5 + 𝐵) = 𝐶 ⇒ ⊢ ¬ 5 ∥ ;𝐴𝐶 | ||
| Theorem | dec5nprm 17127 | A decimal number greater than 10 and ending with five is not a prime number. (Contributed by Mario Carneiro, 19-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ ⇒ ⊢ ¬ ;𝐴5 ∈ ℙ | ||
| Theorem | dec2nprm 17128 | A decimal number greater than 10 and ending with an even digit is not a prime number. (Contributed by Mario Carneiro, 19-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ & ⊢ 𝐵 ∈ ℕ0 & ⊢ (𝐵 · 2) = 𝐶 ⇒ ⊢ ¬ ;𝐴𝐶 ∈ ℙ | ||
| Theorem | modxai 17129 | Add exponents in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.) (Revised by Mario Carneiro, 5-Feb-2015.) |
| ⊢ 𝑁 ∈ ℕ & ⊢ 𝐴 ∈ ℕ & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐷 ∈ ℤ & ⊢ 𝐾 ∈ ℕ0 & ⊢ 𝑀 ∈ ℕ0 & ⊢ 𝐶 ∈ ℕ0 & ⊢ 𝐿 ∈ ℕ0 & ⊢ ((𝐴↑𝐵) mod 𝑁) = (𝐾 mod 𝑁) & ⊢ ((𝐴↑𝐶) mod 𝑁) = (𝐿 mod 𝑁) & ⊢ (𝐵 + 𝐶) = 𝐸 & ⊢ ((𝐷 · 𝑁) + 𝑀) = (𝐾 · 𝐿) ⇒ ⊢ ((𝐴↑𝐸) mod 𝑁) = (𝑀 mod 𝑁) | ||
| Theorem | mod2xi 17130 | Double exponents in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.) |
| ⊢ 𝑁 ∈ ℕ & ⊢ 𝐴 ∈ ℕ & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐷 ∈ ℤ & ⊢ 𝐾 ∈ ℕ0 & ⊢ 𝑀 ∈ ℕ0 & ⊢ ((𝐴↑𝐵) mod 𝑁) = (𝐾 mod 𝑁) & ⊢ (2 · 𝐵) = 𝐸 & ⊢ ((𝐷 · 𝑁) + 𝑀) = (𝐾 · 𝐾) ⇒ ⊢ ((𝐴↑𝐸) mod 𝑁) = (𝑀 mod 𝑁) | ||
| Theorem | modxp1i 17131 | Add one to an exponent in a power mod calculation. (Contributed by Mario Carneiro, 21-Feb-2014.) |
| ⊢ 𝑁 ∈ ℕ & ⊢ 𝐴 ∈ ℕ & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐷 ∈ ℤ & ⊢ 𝐾 ∈ ℕ0 & ⊢ 𝑀 ∈ ℕ0 & ⊢ ((𝐴↑𝐵) mod 𝑁) = (𝐾 mod 𝑁) & ⊢ (𝐵 + 1) = 𝐸 & ⊢ ((𝐷 · 𝑁) + 𝑀) = (𝐾 · 𝐴) ⇒ ⊢ ((𝐴↑𝐸) mod 𝑁) = (𝑀 mod 𝑁) | ||
| Theorem | mod2xnegi 17132 | Version of mod2xi 17130 with a negative mod value. (Contributed by Mario Carneiro, 21-Feb-2014.) |
| ⊢ 𝐴 ∈ ℕ & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐷 ∈ ℤ & ⊢ 𝐾 ∈ ℕ & ⊢ 𝑀 ∈ ℕ0 & ⊢ 𝐿 ∈ ℕ0 & ⊢ ((𝐴↑𝐵) mod 𝑁) = (𝐿 mod 𝑁) & ⊢ (2 · 𝐵) = 𝐸 & ⊢ (𝐿 + 𝐾) = 𝑁 & ⊢ ((𝐷 · 𝑁) + 𝑀) = (𝐾 · 𝐾) ⇒ ⊢ ((𝐴↑𝐸) mod 𝑁) = (𝑀 mod 𝑁) | ||
| Theorem | modsubi 17133 | Subtract from within a mod calculation. (Contributed by Mario Carneiro, 18-Feb-2014.) |
| ⊢ 𝑁 ∈ ℕ & ⊢ 𝐴 ∈ ℕ & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝑀 ∈ ℕ0 & ⊢ (𝐴 mod 𝑁) = (𝐾 mod 𝑁) & ⊢ (𝑀 + 𝐵) = 𝐾 ⇒ ⊢ ((𝐴 − 𝐵) mod 𝑁) = (𝑀 mod 𝑁) | ||
| Theorem | gcdi 17134 | Calculate a GCD via Euclid's algorithm. (Contributed by Mario Carneiro, 19-Feb-2014.) |
| ⊢ 𝐾 ∈ ℕ0 & ⊢ 𝑅 ∈ ℕ0 & ⊢ 𝑁 ∈ ℕ0 & ⊢ (𝑁 gcd 𝑅) = 𝐺 & ⊢ ((𝐾 · 𝑁) + 𝑅) = 𝑀 ⇒ ⊢ (𝑀 gcd 𝑁) = 𝐺 | ||
| Theorem | gcdmodi 17135 | Calculate a GCD via Euclid's algorithm. Theorem 5.6 in [ApostolNT] p. 109. (Contributed by Mario Carneiro, 19-Feb-2014.) |
| ⊢ 𝐾 ∈ ℕ0 & ⊢ 𝑅 ∈ ℕ0 & ⊢ 𝑁 ∈ ℕ & ⊢ (𝐾 mod 𝑁) = (𝑅 mod 𝑁) & ⊢ (𝑁 gcd 𝑅) = 𝐺 ⇒ ⊢ (𝐾 gcd 𝑁) = 𝐺 | ||
| Theorem | numexp0 17136 | Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ0 ⇒ ⊢ (𝐴↑0) = 1 | ||
| Theorem | numexp1 17137 | Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ0 ⇒ ⊢ (𝐴↑1) = 𝐴 | ||
| Theorem | numexpp1 17138 | Calculate an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝑀 ∈ ℕ0 & ⊢ (𝑀 + 1) = 𝑁 & ⊢ ((𝐴↑𝑀) · 𝐴) = 𝐶 ⇒ ⊢ (𝐴↑𝑁) = 𝐶 | ||
| Theorem | numexp2x 17139 | Double an integer power. (Contributed by Mario Carneiro, 17-Apr-2015.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝑀 ∈ ℕ0 & ⊢ (2 · 𝑀) = 𝑁 & ⊢ (𝐴↑𝑀) = 𝐷 & ⊢ (𝐷 · 𝐷) = 𝐶 ⇒ ⊢ (𝐴↑𝑁) = 𝐶 | ||
| Theorem | decsplit0b 17140 | Split a decimal number into two parts. Base case: 𝑁 = 0. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.) |
| ⊢ 𝐴 ∈ ℕ0 ⇒ ⊢ ((𝐴 · (;10↑0)) + 𝐵) = (𝐴 + 𝐵) | ||
| Theorem | decsplit0 17141 | Split a decimal number into two parts. Base case: 𝑁 = 0. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.) |
| ⊢ 𝐴 ∈ ℕ0 ⇒ ⊢ ((𝐴 · (;10↑0)) + 0) = 𝐴 | ||
| Theorem | decsplit1 17142 | Split a decimal number into two parts. Base case: 𝑁 = 1. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.) |
| ⊢ 𝐴 ∈ ℕ0 ⇒ ⊢ ((𝐴 · (;10↑1)) + 𝐵) = ;𝐴𝐵 | ||
| Theorem | decsplit 17143 | Split a decimal number into two parts. Inductive step. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 8-Sep-2021.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐷 ∈ ℕ0 & ⊢ 𝑀 ∈ ℕ0 & ⊢ (𝑀 + 1) = 𝑁 & ⊢ ((𝐴 · (;10↑𝑀)) + 𝐵) = 𝐶 ⇒ ⊢ ((𝐴 · (;10↑𝑁)) + ;𝐵𝐷) = ;𝐶𝐷 | ||
| Theorem | karatsuba 17144 | The Karatsuba multiplication algorithm. If 𝑋 and 𝑌 are decomposed into two groups of digits of length 𝑀 (only the lower group is known to be this size but the algorithm is most efficient when the partition is chosen near the middle of the digit string), then 𝑋𝑌 can be written in three groups of digits, where each group needs only one multiplication. Thus, we can halve both inputs with only three multiplications on the smaller operands, yielding an asymptotic improvement of n^(log2 3) instead of n^2 for the "naive" algorithm decmul1c 12782. (Contributed by Mario Carneiro, 16-Jul-2015.) (Revised by AV, 9-Sep-2021.) |
| ⊢ 𝐴 ∈ ℕ0 & ⊢ 𝐵 ∈ ℕ0 & ⊢ 𝐶 ∈ ℕ0 & ⊢ 𝐷 ∈ ℕ0 & ⊢ 𝑆 ∈ ℕ0 & ⊢ 𝑀 ∈ ℕ0 & ⊢ (𝐴 · 𝐶) = 𝑅 & ⊢ (𝐵 · 𝐷) = 𝑇 & ⊢ ((𝐴 + 𝐵) · (𝐶 + 𝐷)) = ((𝑅 + 𝑆) + 𝑇) & ⊢ ((𝐴 · (;10↑𝑀)) + 𝐵) = 𝑋 & ⊢ ((𝐶 · (;10↑𝑀)) + 𝐷) = 𝑌 & ⊢ ((𝑅 · (;10↑𝑀)) + 𝑆) = 𝑊 & ⊢ ((𝑊 · (;10↑𝑀)) + 𝑇) = 𝑍 ⇒ ⊢ (𝑋 · 𝑌) = 𝑍 | ||
| Theorem | 2exp4 17145 | Two to the fourth power is 16. (Contributed by Mario Carneiro, 20-Apr-2015.) |
| ⊢ (2↑4) = ;16 | ||
| Theorem | 2exp5 17146 | Two to the fifth power is 32. (Contributed by AV, 16-Aug-2021.) |
| ⊢ (2↑5) = ;32 | ||
| Theorem | 2exp6 17147 | Two to the sixth power is 64. (Contributed by Mario Carneiro, 20-Apr-2015.) (Proof shortened by OpenAI, 25-Mar-2020.) |
| ⊢ (2↑6) = ;64 | ||
| Theorem | 2exp7 17148 | Two to the seventh power is 128. (Contributed by AV, 16-Aug-2021.) |
| ⊢ (2↑7) = ;;128 | ||
| Theorem | 2exp8 17149 | Two to the eighth power is 256. (Contributed by Mario Carneiro, 20-Apr-2015.) |
| ⊢ (2↑8) = ;;256 | ||
| Theorem | 2exp11 17150 | Two to the eleventh power is 2048. (Contributed by AV, 16-Aug-2021.) |
| ⊢ (2↑;11) = ;;;2048 | ||
| Theorem | 2exp16 17151 | Two to the sixteenth power is 65536. (Contributed by Mario Carneiro, 20-Apr-2015.) |
| ⊢ (2↑;16) = ;;;;65536 | ||
| Theorem | 3exp3 17152 | Three to the third power is 27. (Contributed by Mario Carneiro, 20-Apr-2015.) |
| ⊢ (3↑3) = ;27 | ||
| Theorem | 2expltfac 17153 | The factorial grows faster than two to the power 𝑁. (Contributed by Mario Carneiro, 15-Sep-2016.) |
| ⊢ (𝑁 ∈ (ℤ≥‘4) → (2↑𝑁) < (!‘𝑁)) | ||
| Theorem | cshwsidrepsw 17154 | If cyclically shifting a word of length being a prime number by a number of positions which is not divisible by the prime number results in the word itself, the word is a "repeated symbol word". (Contributed by AV, 18-May-2018.) (Revised by AV, 10-Nov-2018.) |
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) ∈ ℙ) → ((𝐿 ∈ ℤ ∧ (𝐿 mod (♯‘𝑊)) ≠ 0 ∧ (𝑊 cyclShift 𝐿) = 𝑊) → 𝑊 = ((𝑊‘0) repeatS (♯‘𝑊)))) | ||
| Theorem | cshwsidrepswmod0 17155 | If cyclically shifting a word of length being a prime number results in the word itself, the shift must be either by 0 (modulo the length of the word) or the word must be a "repeated symbol word". (Contributed by AV, 18-May-2018.) (Revised by AV, 10-Nov-2018.) |
| ⊢ ((𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) ∈ ℙ ∧ 𝐿 ∈ ℤ) → ((𝑊 cyclShift 𝐿) = 𝑊 → ((𝐿 mod (♯‘𝑊)) = 0 ∨ 𝑊 = ((𝑊‘0) repeatS (♯‘𝑊))))) | ||
| Theorem | cshwshashlem1 17156* | If cyclically shifting a word of length being a prime number not consisting of identical symbols by at least one position (and not by as many positions as the length of the word), the result will not be the word itself. (Contributed by AV, 19-May-2018.) (Revised by AV, 8-Jun-2018.) (Revised by AV, 10-Nov-2018.) |
| ⊢ (𝜑 → (𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) ∈ ℙ)) ⇒ ⊢ ((𝜑 ∧ ∃𝑖 ∈ (0..^(♯‘𝑊))(𝑊‘𝑖) ≠ (𝑊‘0) ∧ 𝐿 ∈ (1..^(♯‘𝑊))) → (𝑊 cyclShift 𝐿) ≠ 𝑊) | ||
| Theorem | cshwshashlem2 17157* | If cyclically shifting a word of length being a prime number and not of identical symbols by different numbers of positions, the resulting words are different. (Contributed by Alexander van der Vekens, 19-May-2018.) (Revised by Alexander van der Vekens, 8-Jun-2018.) |
| ⊢ (𝜑 → (𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) ∈ ℙ)) ⇒ ⊢ ((𝜑 ∧ ∃𝑖 ∈ (0..^(♯‘𝑊))(𝑊‘𝑖) ≠ (𝑊‘0)) → ((𝐿 ∈ (0..^(♯‘𝑊)) ∧ 𝐾 ∈ (0..^(♯‘𝑊)) ∧ 𝐾 < 𝐿) → (𝑊 cyclShift 𝐿) ≠ (𝑊 cyclShift 𝐾))) | ||
| Theorem | cshwshashlem3 17158* | If cyclically shifting a word of length being a prime number and not of identical symbols by different numbers of positions, the resulting words are different. (Contributed by Alexander van der Vekens, 19-May-2018.) (Revised by Alexander van der Vekens, 8-Jun-2018.) |
| ⊢ (𝜑 → (𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) ∈ ℙ)) ⇒ ⊢ ((𝜑 ∧ ∃𝑖 ∈ (0..^(♯‘𝑊))(𝑊‘𝑖) ≠ (𝑊‘0)) → ((𝐿 ∈ (0..^(♯‘𝑊)) ∧ 𝐾 ∈ (0..^(♯‘𝑊)) ∧ 𝐾 ≠ 𝐿) → (𝑊 cyclShift 𝐿) ≠ (𝑊 cyclShift 𝐾))) | ||
| Theorem | cshwsdisj 17159* | The singletons resulting by cyclically shifting a given word of length being a prime number and not consisting of identical symbols is a disjoint collection. (Contributed by Alexander van der Vekens, 19-May-2018.) (Revised by Alexander van der Vekens, 8-Jun-2018.) |
| ⊢ (𝜑 → (𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) ∈ ℙ)) ⇒ ⊢ ((𝜑 ∧ ∃𝑖 ∈ (0..^(♯‘𝑊))(𝑊‘𝑖) ≠ (𝑊‘0)) → Disj 𝑛 ∈ (0..^(♯‘𝑊)){(𝑊 cyclShift 𝑛)}) | ||
| Theorem | cshwsiun 17160* | The set of (different!) words resulting by cyclically shifting a given word is an indexed union. (Contributed by AV, 19-May-2018.) (Revised by AV, 8-Jun-2018.) (Proof shortened by AV, 8-Nov-2018.) |
| ⊢ 𝑀 = {𝑤 ∈ Word 𝑉 ∣ ∃𝑛 ∈ (0..^(♯‘𝑊))(𝑊 cyclShift 𝑛) = 𝑤} ⇒ ⊢ (𝑊 ∈ Word 𝑉 → 𝑀 = ∪ 𝑛 ∈ (0..^(♯‘𝑊)){(𝑊 cyclShift 𝑛)}) | ||
| Theorem | cshwsex 17161* | The class of (different!) words resulting by cyclically shifting a given word is a set. (Contributed by AV, 8-Jun-2018.) (Revised by AV, 8-Nov-2018.) |
| ⊢ 𝑀 = {𝑤 ∈ Word 𝑉 ∣ ∃𝑛 ∈ (0..^(♯‘𝑊))(𝑊 cyclShift 𝑛) = 𝑤} ⇒ ⊢ (𝑊 ∈ Word 𝑉 → 𝑀 ∈ V) | ||
| Theorem | cshws0 17162* | The size of the set of (different!) words resulting by cyclically shifting an empty word is 0. (Contributed by AV, 8-Nov-2018.) |
| ⊢ 𝑀 = {𝑤 ∈ Word 𝑉 ∣ ∃𝑛 ∈ (0..^(♯‘𝑊))(𝑊 cyclShift 𝑛) = 𝑤} ⇒ ⊢ (𝑊 = ∅ → (♯‘𝑀) = 0) | ||
| Theorem | cshwrepswhash1 17163* | The size of the set of (different!) words resulting by cyclically shifting a nonempty "repeated symbol word" is 1. (Contributed by AV, 18-May-2018.) (Revised by AV, 8-Nov-2018.) |
| ⊢ 𝑀 = {𝑤 ∈ Word 𝑉 ∣ ∃𝑛 ∈ (0..^(♯‘𝑊))(𝑊 cyclShift 𝑛) = 𝑤} ⇒ ⊢ ((𝐴 ∈ 𝑉 ∧ 𝑁 ∈ ℕ ∧ 𝑊 = (𝐴 repeatS 𝑁)) → (♯‘𝑀) = 1) | ||
| Theorem | cshwshashnsame 17164* | If a word (not consisting of identical symbols) has a length being a prime number, the size of the set of (different!) words resulting by cyclically shifting the original word equals the length of the original word. (Contributed by AV, 19-May-2018.) (Revised by AV, 10-Nov-2018.) |
| ⊢ 𝑀 = {𝑤 ∈ Word 𝑉 ∣ ∃𝑛 ∈ (0..^(♯‘𝑊))(𝑊 cyclShift 𝑛) = 𝑤} ⇒ ⊢ ((𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) ∈ ℙ) → (∃𝑖 ∈ (0..^(♯‘𝑊))(𝑊‘𝑖) ≠ (𝑊‘0) → (♯‘𝑀) = (♯‘𝑊))) | ||
| Theorem | cshwshash 17165* | If a word has a length being a prime number, the size of the set of (different!) words resulting by cyclically shifting the original word equals the length of the original word or 1. (Contributed by AV, 19-May-2018.) (Revised by AV, 10-Nov-2018.) |
| ⊢ 𝑀 = {𝑤 ∈ Word 𝑉 ∣ ∃𝑛 ∈ (0..^(♯‘𝑊))(𝑊 cyclShift 𝑛) = 𝑤} ⇒ ⊢ ((𝑊 ∈ Word 𝑉 ∧ (♯‘𝑊) ∈ ℙ) → ((♯‘𝑀) = (♯‘𝑊) ∨ (♯‘𝑀) = 1)) | ||
| Theorem | prmlem0 17166* | Lemma for prmlem1 17168 and prmlem2 17181. (Contributed by Mario Carneiro, 18-Feb-2014.) |
| ⊢ ((¬ 2 ∥ 𝑀 ∧ 𝑥 ∈ (ℤ≥‘𝑀)) → ((𝑥 ∈ (ℙ ∖ {2}) ∧ (𝑥↑2) ≤ 𝑁) → ¬ 𝑥 ∥ 𝑁)) & ⊢ (𝐾 ∈ ℙ → ¬ 𝐾 ∥ 𝑁) & ⊢ (𝐾 + 2) = 𝑀 ⇒ ⊢ ((¬ 2 ∥ 𝐾 ∧ 𝑥 ∈ (ℤ≥‘𝐾)) → ((𝑥 ∈ (ℙ ∖ {2}) ∧ (𝑥↑2) ≤ 𝑁) → ¬ 𝑥 ∥ 𝑁)) | ||
| Theorem | prmlem1a 17167* | A quick proof skeleton to show that the numbers less than 25 are prime, by trial division. (Contributed by Mario Carneiro, 18-Feb-2014.) |
| ⊢ 𝑁 ∈ ℕ & ⊢ 1 < 𝑁 & ⊢ ¬ 2 ∥ 𝑁 & ⊢ ¬ 3 ∥ 𝑁 & ⊢ ((¬ 2 ∥ 5 ∧ 𝑥 ∈ (ℤ≥‘5)) → ((𝑥 ∈ (ℙ ∖ {2}) ∧ (𝑥↑2) ≤ 𝑁) → ¬ 𝑥 ∥ 𝑁)) ⇒ ⊢ 𝑁 ∈ ℙ | ||
| Theorem | prmlem1 17168 | A quick proof skeleton to show that the numbers less than 25 are prime, by trial division. (Contributed by Mario Carneiro, 18-Feb-2014.) |
| ⊢ 𝑁 ∈ ℕ & ⊢ 1 < 𝑁 & ⊢ ¬ 2 ∥ 𝑁 & ⊢ ¬ 3 ∥ 𝑁 & ⊢ 𝑁 < ;25 ⇒ ⊢ 𝑁 ∈ ℙ | ||
| Theorem | 5prm 17169 | 5 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) |
| ⊢ 5 ∈ ℙ | ||
| Theorem | 6nprm 17170 | 6 is not a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) |
| ⊢ ¬ 6 ∈ ℙ | ||
| Theorem | 7prm 17171 | 7 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) |
| ⊢ 7 ∈ ℙ | ||
| Theorem | 8nprm 17172 | 8 is not a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) |
| ⊢ ¬ 8 ∈ ℙ | ||
| Theorem | 9nprm 17173 | 9 is not a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) |
| ⊢ ¬ 9 ∈ ℙ | ||
| Theorem | 10nprm 17174 | 10 is not a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by AV, 6-Sep-2021.) (Proof shortened by Umit Teoman Dogan, 10-Jun-2026.) |
| ⊢ ¬ ;10 ∈ ℙ | ||
| Theorem | 10nprmOLD 17175 | Obsolete version of 10nprm 17174 as of 10-Jun-2026. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by AV, 6-Sep-2021.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ ¬ ;10 ∈ ℙ | ||
| Theorem | 11prm 17176 | 11 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;11 ∈ ℙ | ||
| Theorem | 13prm 17177 | 13 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;13 ∈ ℙ | ||
| Theorem | 17prm 17178 | 17 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;17 ∈ ℙ | ||
| Theorem | 19prm 17179 | 19 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;19 ∈ ℙ | ||
| Theorem | 23prm 17180 | 23 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;23 ∈ ℙ | ||
| Theorem | prmlem2 17181 |
Our last proving session got as far as 25 because we started with the
two "bootstrap" primes 2 and 3, and the next prime is 5, so
knowing that
2 and 3 are prime and 4 is not allows to cover the numbers less than
5↑2 = 25. Additionally, nonprimes are
"easy", so we can extend
this range of known prime/nonprimes all the way until 29, which is the
first prime larger than 25. Thus, in this lemma we extend another
blanket out to 29↑2 = 841, from which we
can prove even more
primes. If we wanted, we could keep doing this, but the goal is
Bertrand's postulate, and for that we only need a few large primes - we
don't need to find them all, as we have been doing thus far. So after
this blanket runs out, we'll have to switch to another method (see
1259prm 17197).
As a side note, you can see the pattern of the primes in the indentation pattern of this lemma! (Contributed by Mario Carneiro, 18-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ 𝑁 ∈ ℕ & ⊢ 𝑁 < ;;841 & ⊢ 1 < 𝑁 & ⊢ ¬ 2 ∥ 𝑁 & ⊢ ¬ 3 ∥ 𝑁 & ⊢ ¬ 5 ∥ 𝑁 & ⊢ ¬ 7 ∥ 𝑁 & ⊢ ¬ ;11 ∥ 𝑁 & ⊢ ¬ ;13 ∥ 𝑁 & ⊢ ¬ ;17 ∥ 𝑁 & ⊢ ¬ ;19 ∥ 𝑁 & ⊢ ¬ ;23 ∥ 𝑁 ⇒ ⊢ 𝑁 ∈ ℙ | ||
| Theorem | 37prm 17182 | 37 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;37 ∈ ℙ | ||
| Theorem | 43prm 17183 | 43 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;43 ∈ ℙ | ||
| Theorem | 83prm 17184 | 83 is a prime number. (Contributed by Mario Carneiro, 18-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;83 ∈ ℙ | ||
| Theorem | 139prm 17185 | 139 is a prime number. (Contributed by Mario Carneiro, 19-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;;139 ∈ ℙ | ||
| Theorem | 163prm 17186 | 163 is a prime number. (Contributed by Mario Carneiro, 19-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;;163 ∈ ℙ | ||
| Theorem | 317prm 17187 | 317 is a prime number. (Contributed by Mario Carneiro, 19-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;;317 ∈ ℙ | ||
| Theorem | 631prm 17188 | 631 is a prime number. (Contributed by Mario Carneiro, 1-Mar-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ ;;631 ∈ ℙ | ||
| Theorem | prmo4 17189 | The primorial of 4. (Contributed by AV, 28-Aug-2020.) |
| ⊢ (#p‘4) = 6 | ||
| Theorem | prmo5 17190 | The primorial of 5. (Contributed by AV, 28-Aug-2020.) |
| ⊢ (#p‘5) = ;30 | ||
| Theorem | prmo6 17191 | The primorial of 6. (Contributed by AV, 28-Aug-2020.) |
| ⊢ (#p‘6) = ;30 | ||
| Theorem | 1259lem1 17192 | Lemma for 1259prm 17197. Calculate a power mod. In decimal, we calculate 2↑16 = 52𝑁 + 68≡68 and 2↑17≡68 · 2 = 136 in this lemma. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.) |
| ⊢ 𝑁 = ;;;1259 ⇒ ⊢ ((2↑;17) mod 𝑁) = (;;136 mod 𝑁) | ||
| Theorem | 1259lem2 17193 | Lemma for 1259prm 17197. Calculate a power mod. In decimal, we calculate 2↑34 = (2↑17)↑2≡136↑2≡14𝑁 + 870. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 15-Sep-2021.) |
| ⊢ 𝑁 = ;;;1259 ⇒ ⊢ ((2↑;34) mod 𝑁) = (;;870 mod 𝑁) | ||
| Theorem | 1259lem3 17194 | Lemma for 1259prm 17197. Calculate a power mod. In decimal, we calculate 2↑38 = 2↑34 · 2↑4≡870 · 16 = 11𝑁 + 71 and 2↑76 = (2↑34)↑2≡71↑2 = 4𝑁 + 5≡5. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.) |
| ⊢ 𝑁 = ;;;1259 ⇒ ⊢ ((2↑;76) mod 𝑁) = (5 mod 𝑁) | ||
| Theorem | 1259lem4 17195 | Lemma for 1259prm 17197. Calculate a power mod. In decimal, we calculate 2↑306 = (2↑76)↑4 · 4≡5↑4 · 4 = 2𝑁 − 18, 2↑612 = (2↑306)↑2≡18↑2 = 324, 2↑629 = 2↑612 · 2↑17≡324 · 136 = 35𝑁 − 1 and finally 2↑(𝑁 − 1) = (2↑629)↑2≡1↑2 = 1. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.) |
| ⊢ 𝑁 = ;;;1259 ⇒ ⊢ ((2↑(𝑁 − 1)) mod 𝑁) = (1 mod 𝑁) | ||
| Theorem | 1259lem5 17196 | Lemma for 1259prm 17197. Calculate the GCD of 2↑34 − 1≡869 with 𝑁 = 1259. (Contributed by Mario Carneiro, 22-Feb-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) |
| ⊢ 𝑁 = ;;;1259 ⇒ ⊢ (((2↑;34) − 1) gcd 𝑁) = 1 | ||
| Theorem | 1259prm 17197 | 1259 is a prime number. (Contributed by Mario Carneiro, 22-Feb-2014.) (Proof shortened by Mario Carneiro, 20-Apr-2015.) |
| ⊢ 𝑁 = ;;;1259 ⇒ ⊢ 𝑁 ∈ ℙ | ||
| Theorem | 2503lem1 17198 | Lemma for 2503prm 17201. Calculate a power mod. In decimal, we calculate 2↑18 = 512↑2 = 104𝑁 + 1832≡1832. (Contributed by Mario Carneiro, 3-Mar-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.) |
| ⊢ 𝑁 = ;;;2503 ⇒ ⊢ ((2↑;18) mod 𝑁) = (;;;1832 mod 𝑁) | ||
| Theorem | 2503lem2 17199 | Lemma for 2503prm 17201. Calculate a power mod. We calculate 2↑19 = 2↑18 · 2≡1832 · 2 = 𝑁 + 1161, 2↑38 = (2↑19)↑2≡1161↑2 = 538𝑁 + 1307, 2↑39 = 2↑38 · 2≡1307 · 2 = 𝑁 + 111, 2↑78 = (2↑39)↑2≡111↑2 = 5𝑁 − 194, 2↑156 = (2↑78)↑2≡194↑2 = 15𝑁 + 91, 2↑312 = (2↑156)↑2≡91↑2 = 3𝑁 + 772, 2↑624 = (2↑312)↑2≡772↑2 = 238𝑁 + 270, 2↑1248 = (2↑624)↑2≡270↑2 = 29𝑁 + 313, 2↑1251 = 2↑1248 · 8≡313 · 8 = 𝑁 + 1 and finally 2↑(𝑁 − 1) = (2↑1251)↑2≡1↑2 = 1. (Contributed by Mario Carneiro, 3-Mar-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.) |
| ⊢ 𝑁 = ;;;2503 ⇒ ⊢ ((2↑(𝑁 − 1)) mod 𝑁) = (1 mod 𝑁) | ||
| Theorem | 2503lem3 17200 | Lemma for 2503prm 17201. Calculate the GCD of 2↑18 − 1≡1831 with 𝑁 = 2503. (Contributed by Mario Carneiro, 3-Mar-2014.) (Revised by Mario Carneiro, 20-Apr-2015.) (Proof shortened by AV, 15-Sep-2021.) |
| ⊢ 𝑁 = ;;;2503 ⇒ ⊢ (((2↑;18) − 1) gcd 𝑁) = 1 | ||
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