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Theorem List for Metamath Proof Explorer - 38901-39000   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremcdlemk19-2N 38901* Part of proof of Lemma K of [Crawley] p. 118. Line 22 on p. 119. 𝑁, 𝑉, 𝑄, 𝐶 are k, sigma2 (p), k2, f2. (Contributed by NM, 2-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑄 = (𝑆𝐶)    &   𝑉 = (𝑑𝑇 ↦ (𝑘𝑇 (𝑘𝑃) = ((𝑃 (𝑅𝑑)) ((𝑄𝑃) (𝑅‘(𝑑𝐶))))))       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐹𝑇𝐶𝑇𝑁𝑇) ∧ ((𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → (𝑉𝐹) = 𝑁)
 
Theoremcdlemk7u-2N 38902* Part of proof of Lemma K of [Crawley] p. 118. Line 5, p. 119 for the sigma2 case. (Contributed by NM, 5-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑄 = (𝑆𝐶)    &   𝑉 = (𝑑𝑇 ↦ (𝑘𝑇 (𝑘𝑃) = ((𝑃 (𝑅𝑑)) ((𝑄𝑃) (𝑅‘(𝑑𝐶))))))    &   𝑍 = (((𝐺𝑃) (𝑋𝑃)) ((𝑅‘(𝐺𝐶)) (𝑅‘(𝑋𝐶))))       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐶𝑇𝑁𝑇) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝑋𝑇𝑋 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝑋) ≠ (𝑅𝐶)) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑉𝐺)‘𝑃) (((𝑉𝑋)‘𝑃) 𝑍))
 
Theoremcdlemk11u-2N 38903* Part of proof of Lemma K of [Crawley] p. 118. Line 17, p. 119, showing Eq. 3 (line 8, p. 119) for the sigma2 (𝑍) case. (Contributed by NM, 5-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑄 = (𝑆𝐶)    &   𝑉 = (𝑑𝑇 ↦ (𝑘𝑇 (𝑘𝑃) = ((𝑃 (𝑅𝑑)) ((𝑄𝑃) (𝑅‘(𝑑𝐶))))))    &   𝑍 = (((𝐺𝑃) (𝑋𝑃)) ((𝑅‘(𝐺𝐶)) (𝑅‘(𝑋𝐶))))       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐶𝑇𝑁𝑇) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝑋𝑇𝑋 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝑋) ≠ (𝑅𝐶)) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑉𝐺)‘𝑃) (((𝑉𝑋)‘𝑃) (𝑅‘(𝑋𝐺))))
 
Theoremcdlemk12u-2N 38904* Part of proof of Lemma K of [Crawley] p. 118. Line 18, p. 119, showing Eq. 4 (line 10, p. 119) for the sigma2 (𝑉) case. (Contributed by NM, 5-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑄 = (𝑆𝐶)    &   𝑉 = (𝑑𝑇 ↦ (𝑘𝑇 (𝑘𝑃) = ((𝑃 (𝑅𝑑)) ((𝑄𝑃) (𝑅‘(𝑑𝐶))))))       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐶𝑇𝑁𝑇) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝑋𝑇𝑋 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝑋) ≠ (𝑅𝐶)) ∧ ((𝑅𝐺) ≠ (𝑅𝑋) ∧ 𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑉𝐺)‘𝑃) = ((𝑃 (𝐺𝑃)) (((𝑉𝑋)‘𝑃) (𝑅‘(𝑋𝐺)))))
 
Theoremcdlemk21-2N 38905* Part of proof of Lemma K of [Crawley] p. 118. Lines 26-27, p. 119 for i=0 and j=2. (Contributed by NM, 5-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑄 = (𝑆𝐶)    &   𝑉 = (𝑑𝑇 ↦ (𝑘𝑇 (𝑘𝑃) = ((𝑃 (𝑅𝑑)) ((𝑄𝑃) (𝑅‘(𝑑𝐶))))))       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐶𝑇𝑁𝑇) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝐶)) ∧ ((𝑅𝐺) ≠ (𝑅𝐹) ∧ 𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑆𝐺)‘𝑃) = ((𝑉𝐺)‘𝑃))
 
Theoremcdlemk20-2N 38906* Part of proof of Lemma K of [Crawley] p. 118. Line 22, p. 119 for the i=2, j=1 case. Note typo on line 22: f should be fi. Our 𝐷, 𝐶, 𝑂, 𝑄, 𝑈, 𝑉 represent their f1, f2, k1, k2, sigma1, sigma2. (Contributed by NM, 5-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑄 = (𝑆𝐶)    &   𝑉 = (𝑑𝑇 ↦ (𝑘𝑇 (𝑘𝑃) = ((𝑃 (𝑅𝑑)) ((𝑄𝑃) (𝑅‘(𝑑𝐶))))))    &   𝑂 = (𝑆𝐷)       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐶𝑇𝑁𝑇) ∧ (𝐷𝑇𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝐶𝑇𝐶 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐶)) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑉𝐷)‘𝑃) = (𝑂𝑃))
 
Theoremcdlemk22 38907* Part of proof of Lemma K of [Crawley] p. 118. Lines 26-27, p. 119 for i=1 and j=2. (Contributed by NM, 5-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑄 = (𝑆𝐶)    &   𝑉 = (𝑑𝑇 ↦ (𝑘𝑇 (𝑘𝑃) = ((𝑃 (𝑅𝑑)) ((𝑄𝑃) (𝑅‘(𝑑𝐶))))))    &   𝑂 = (𝑆𝐷)    &   𝑈 = (𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) ((𝑂𝑃) (𝑅‘(𝑒𝐷))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇𝐷𝑇) ∧ ((𝑁𝑇𝐺𝑇𝐶𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵) ∧ 𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝐶 ≠ ( I ↾ 𝐵) ∧ (𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝐶) ≠ (𝑅𝐹)) ∧ ((𝑅𝐷) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝐷) ∧ (𝑅𝐶) ≠ (𝑅𝐷)))) → ((𝑈𝐺)‘𝑃) = ((𝑉𝐺)‘𝑃))
 
Theoremcdlemk30 38908* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. Part of attempt to simplify hypotheses. (Contributed by NM, 17-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐹𝑇𝑏𝑇𝑁𝑇) ∧ ((𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑏 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑆𝑏)‘𝑃) = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹)))))
 
Theoremcdlemkuu 38909* Convert between function and operation forms of 𝑌. TODO: Use operation form everywhere. (Contributed by NM, 6-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))    &   𝑄 = (𝑆𝐷)    &   𝑍 = (𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) ((𝑄𝑃) (𝑅‘(𝑒𝐷))))))       ((𝐷𝑇𝐺𝑇) → (𝐷𝑌𝐺) = (𝑍𝐺))
 
Theoremcdlemk31 38910* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. Part of attempt to simplify hypotheses. (Contributed by NM, 17-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝑏𝑇𝑁𝑇) ∧ 𝐺𝑇) ∧ (((𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑏 ≠ ( I ↾ 𝐵) ∧ 𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑏𝑌𝐺)‘𝑃) = ((𝑃 (𝑅𝐺)) (((𝑆𝑏)‘𝑃) (𝑅‘(𝐺𝑏)))))
 
Theoremcdlemk32 38911* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. Part of attempt to simplify hypotheses. (Contributed by NM, 17-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝑏𝑇𝑁𝑇) ∧ 𝐺𝑇) ∧ (((𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑏 ≠ ( I ↾ 𝐵) ∧ 𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑏𝑌𝐺)‘𝑃) = ((𝑃 (𝑅𝐺)) (((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹)))) (𝑅‘(𝐺𝑏)))))
 
Theoremcdlemkuel-3 38912* Part of proof of Lemma K of [Crawley] p. 118. Conditions for the sigma2 (p) function to be a translation. TODO: combine cdlemkj 38877? (Contributed by NM, 11-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁) ∧ 𝐺𝑇) ∧ (𝐹𝑇𝐷𝑇𝑁𝑇) ∧ (((𝑅𝐷) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐺)) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐺 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → (𝐷𝑌𝐺) ∈ 𝑇)
 
Theoremcdlemkuv2-3N 38913* Part of proof of Lemma K of [Crawley] p. 118. Line 16 on p. 119 for i = 1, where sigma2 (p) is 𝑌, f1 is 𝐷, and k1 is 𝑂. (Contributed by NM, 6-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁) ∧ 𝐺𝑇) ∧ (𝐹𝑇𝐷𝑇𝑁𝑇) ∧ (((𝑅𝐷) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐺)) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐺 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝐷𝑌𝐺)‘𝑃) = ((𝑃 (𝑅𝐺)) (((𝑆𝐷)‘𝑃) (𝑅‘(𝐺𝐷)))))
 
Theoremcdlemk18-3N 38914* Part of proof of Lemma K of [Crawley] p. 118. Line 22 on p. 119. 𝑁, 𝑌, 𝑂, 𝐷 are k, sigma2 (p), k1, f1. (Contributed by NM, 7-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐹𝑇𝐷𝑇𝑁𝑇) ∧ ((𝑅𝐷) ≠ (𝑅𝐹) ∧ (𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝐷𝑌𝐹)‘𝑃) = (𝑁𝑃))
 
Theoremcdlemk22-3 38915* Part of proof of Lemma K of [Crawley] p. 118. Lines 26-27, p. 119 for i=1 and j=2. (Contributed by NM, 7-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇𝐷𝑇) ∧ ((𝑁𝑇𝐺𝑇𝐶𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵) ∧ 𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝐶 ≠ ( I ↾ 𝐵) ∧ (𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝐶) ≠ (𝑅𝐹)) ∧ ((𝑅𝐷) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝐷) ∧ (𝑅𝐶) ≠ (𝑅𝐷)))) → ((𝐷𝑌𝐺)‘𝑃) = ((𝐶𝑌𝐺)‘𝑃))
 
Theoremcdlemk23-3 38916* Part of proof of Lemma K of [Crawley] p. 118. Eliminate the (𝑅𝐶) ≠ (𝑅𝐷) requirement from cdlemk22-3 38915. (Contributed by NM, 7-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐷𝑇𝑁𝑇) ∧ (𝐺𝑇𝐶𝑇𝑥𝑇)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ ((𝑅𝐹) = (𝑅𝑁) ∧ 𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝐺 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵) ∧ 𝑥 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐹)) ∧ ((𝑅𝐺) ≠ (𝑅𝐷) ∧ (𝑅𝑥) ≠ (𝑅𝐶)) ∧ ((𝑅𝑥) ≠ (𝑅𝐷) ∧ (𝑅𝑥) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝑥)))) → ((𝐷𝑌𝐺)‘𝑃) = ((𝐶𝑌𝐺)‘𝑃))
 
Theoremcdlemk24-3 38917* Part of proof of Lemma K of [Crawley] p. 118. Eliminate the (𝑅𝑥) ≠ (𝑅𝐶) requirement from cdlemk23-3 38916 using (𝑅𝐶) = (𝑅𝐷). (Contributed by NM, 7-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐷𝑇𝑁𝑇) ∧ (𝐺𝑇𝐶𝑇𝑥𝑇)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ ((𝑅𝐹) = (𝑅𝑁) ∧ 𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝐺 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵) ∧ 𝑥 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐹)) ∧ ((𝑅𝐺) ≠ (𝑅𝐷) ∧ (𝑅𝐶) = (𝑅𝐷)) ∧ ((𝑅𝑥) ≠ (𝑅𝐷) ∧ (𝑅𝑥) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝑥)))) → ((𝐷𝑌𝐺)‘𝑃) = ((𝐶𝑌𝐺)‘𝑃))
 
Theoremcdlemk25-3 38918* Part of proof of Lemma K of [Crawley] p. 118. Eliminate the (𝑅𝐶) = (𝑅𝐷) requirement from cdlemk24-3 38917. (Contributed by NM, 7-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐷𝑇𝑁𝑇) ∧ (𝐺𝑇𝐶𝑇𝑥𝑇)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ ((𝑅𝐹) = (𝑅𝑁) ∧ 𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝐺 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵) ∧ 𝑥 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐹)) ∧ (𝑅𝐺) ≠ (𝑅𝐷) ∧ ((𝑅𝑥) ≠ (𝑅𝐷) ∧ (𝑅𝑥) ≠ (𝑅𝐹) ∧ (𝑅𝐺) ≠ (𝑅𝑥)))) → ((𝐷𝑌𝐺)‘𝑃) = ((𝐶𝑌𝐺)‘𝑃))
 
Theoremcdlemk26b-3 38919* Part of proof of Lemma K of [Crawley] p. 118. (Contributed by NM, 14-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵) ∧ (𝑅𝐹) = (𝑅𝑁))) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → ∃𝑥𝑇 ((𝑥 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑥) ≠ (𝑅𝐹) ∧ (𝑅𝑥) ≠ (𝑅𝐺)) ∧ (𝑥𝑌𝐺) ∈ 𝑇))
 
Theoremcdlemk26-3 38920* Part of proof of Lemma K of [Crawley] p. 118. Eliminate the 𝑥 requirements from cdlemk25-3 38918. (Contributed by NM, 10-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐷𝑇𝑁𝑇) ∧ (𝐺𝑇𝐶𝑇)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ ((𝑅𝐹) = (𝑅𝑁) ∧ 𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝐺 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐹)) ∧ (𝑅𝐺) ≠ (𝑅𝐷))) → ((𝐷𝑌𝐺)‘𝑃) = ((𝐶𝑌𝐺)‘𝑃))
 
Theoremcdlemk27-3 38921* Part of proof of Lemma K of [Crawley] p. 118. Eliminate the 𝑃 from the conclusion of cdlemk25-3 38918. (Contributed by NM, 10-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐷𝑇𝑁𝑇) ∧ (𝐺𝑇𝐶𝑇)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ ((𝑅𝐹) = (𝑅𝑁) ∧ 𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐷 ≠ ( I ↾ 𝐵)) ∧ (𝐺 ≠ ( I ↾ 𝐵) ∧ 𝐶 ≠ ( I ↾ 𝐵))) ∧ (((𝑅𝐺) ≠ (𝑅𝐶) ∧ (𝑅𝐶) ≠ (𝑅𝐹) ∧ (𝑅𝐷) ≠ (𝑅𝐹)) ∧ (𝑅𝐺) ≠ (𝑅𝐷))) → (𝐷𝑌𝐺) = (𝐶𝑌𝐺))
 
Theoremcdlemk28-3 38922* Part of proof of Lemma K of [Crawley] p. 118. (Contributed by NM, 14-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ 𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → ∃𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → 𝑧 = (𝑏𝑌𝐺)))
 
Theoremcdlemk33N 38923* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. Part of attempt to simplify hypotheses. TODO: not needed, is embodied in cdlemk34 38924. (Contributed by NM, 18-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → 𝑧 = (𝑏𝑌𝐺)))       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → 𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → (𝑧𝑃) = ((𝑏𝑌𝐺)‘𝑃))))
 
Theoremcdlemk34 38924* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. Part of attempt to simplify hypotheses. (Contributed by NM, 18-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → 𝑧 = (𝑏𝑌𝐺)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ 𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → 𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → (𝑧𝑃) = ((𝑃 (𝑅𝐺)) (((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹)))) (𝑅‘(𝐺𝑏)))))))
 
Theoremcdlemk29-3 38925* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. (Contributed by NM, 14-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑌 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → 𝑧 = (𝑏𝑌𝐺)))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ 𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → 𝑋𝑇)
 
Theoremcdlemk35 38926* Part of proof of Lemma K of [Crawley] p. 118. cdlemk29-3 38925 with shorter hypotheses. (Contributed by NM, 18-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝐺)) (𝑍 (𝑅‘(𝐺𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ 𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → 𝑋𝑇)
 
Theoremcdlemk36 38927* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. (Contributed by NM, 18-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝐺)) (𝑍 (𝑅‘(𝐺𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → (𝑋𝑃) = 𝑌)
 
Theoremcdlemk37 38928* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. (Contributed by NM, 18-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝐺)) (𝑍 (𝑅‘(𝐺𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → (𝑋𝑃) (𝑃 (𝑅𝐺)))
 
Theoremcdlemk38 38929* Part of proof of Lemma K of [Crawley] p. 118. Line 31, p. 119. TODO: derive more directly with r19.23 3247? (Contributed by NM, 19-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝐺)) (𝑍 (𝑅‘(𝐺𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ 𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → (𝑋𝑃) (𝑃 (𝑅𝐺)))
 
Theoremcdlemk39 38930* Part of proof of Lemma K of [Crawley] p. 118. Line 31, p. 119. Trace-preserving property of tau, represented by 𝑋. (Contributed by NM, 19-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝐺)) (𝑍 (𝑅‘(𝐺𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ 𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → (𝑅𝑋) (𝑅𝐺))
 
Theoremcdlemk40 38931* TODO: fix comment. (Contributed by NM, 31-Jul-2013.)
𝑋 = (𝑧𝑇 𝜑)    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       (𝐺𝑇 → (𝑈𝐺) = if(𝐹 = 𝑁, 𝐺, 𝐺 / 𝑔𝑋))
 
Theoremcdlemk40t 38932* TODO: fix comment. (Contributed by NM, 31-Jul-2013.)
𝑋 = (𝑧𝑇 𝜑)    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((𝐹 = 𝑁𝐺𝑇) → (𝑈𝐺) = 𝐺)
 
Theoremcdlemk40f 38933* TODO: fix comment. (Contributed by NM, 31-Jul-2013.)
𝑋 = (𝑧𝑇 𝜑)    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((𝐹𝑁𝐺𝑇) → (𝑈𝐺) = 𝐺 / 𝑔𝑋)
 
Theoremcdlemk41 38934* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. (Contributed by NM, 19-Jul-2013.)
𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))       (𝐺𝑇𝐺 / 𝑔𝑌 = ((𝑃 (𝑅𝐺)) (𝑍 (𝑅‘(𝐺𝑏)))))
 
Theoremcdlemkfid1N 38935 Lemma for cdlemkfid3N 38939. (Contributed by NM, 29-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝐺𝑇) ∧ ((𝑅𝐺) ≠ (𝑅𝐹) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → ((𝑃 (𝑅𝐺)) ((𝐹𝑃) (𝑅‘(𝐺𝐹)))) = (𝐺𝑃))
 
Theoremcdlemkid1 38936 Lemma for cdlemkid 38950. (Contributed by NM, 24-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑏𝑇𝑏 ≠ ( I ↾ 𝐵)))) → (𝑍 (𝑅𝑏)) = (𝑃 (𝑅𝑏)))
 
Theoremcdlemkfid2N 38937 Lemma for cdlemkfid3N 38939. (Contributed by NM, 29-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹 = 𝑁) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑏𝑇) ∧ ((𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → 𝑍 = (𝑏𝑃))
 
Theoremcdlemkid2 38938* Lemma for cdlemkid 38950. (Contributed by NM, 24-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝐺 = ( I ↾ 𝐵) ∧ (𝑏𝑇𝑏 ≠ ( I ↾ 𝐵)))) → 𝐺 / 𝑔𝑌 = 𝑃)
 
Theoremcdlemkfid3N 38939* TODO: is this useful or should it be deleted? (Contributed by NM, 29-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹 = 𝑁) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ 𝐺𝑇 ∧ (𝑏𝑇𝑏 ≠ ( I ↾ 𝐵))) ∧ ((𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊))) → 𝐺 / 𝑔𝑌 = (𝐺𝑃))
 
Theoremcdlemky 38940* Part of proof of Lemma K of [Crawley] p. 118. TODO: clean up (𝑏𝑌𝐺) stuff. 𝑉 represents 𝑌 in cdlemk31 38910. (Contributed by NM, 21-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑉 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → 𝐺 / 𝑔𝑌 = ((𝑏𝑉𝐺)‘𝑃))
 
Theoremcdlemkyu 38941* Convert between function and explicit forms. 𝐶 represents 𝑍 in cdlemkuu 38909. TODO: Clean all this up. (Contributed by NM, 21-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑉 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))    &   𝑄 = (𝑆𝑏)    &   𝐶 = (𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) ((𝑄𝑃) (𝑅‘(𝑒𝑏))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → 𝐺 / 𝑔𝑌 = ((𝐶𝐺)‘𝑃))
 
Theoremcdlemkyuu 38942* cdlemkyu 38941 with some hypotheses eliminated. TODO: Clean all this up. (Contributed by NM, 21-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝐶 = (𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑏)‘𝑃) (𝑅‘(𝑒𝑏))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → 𝐺 / 𝑔𝑌 = ((𝐶𝐺)‘𝑃))
 
Theoremcdlemk11ta 38943* Part of proof of Lemma K of [Crawley] p. 118. Lemma for Eq. 5, p. 119. 𝐺, 𝐼 stand for g, h. TODO: fix comment. (Contributed by NM, 21-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝐶 = (𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑏)‘𝑃) (𝑅‘(𝑒𝑏))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐼)))) → 𝐺 / 𝑔𝑌 (𝐼 / 𝑔𝑌 (𝑅‘(𝐼𝐺))))
 
Theoremcdlemk19ylem 38944* Lemma for cdlemk19y 38946. (Contributed by NM, 30-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝐶 = (𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑏)‘𝑃) (𝑅‘(𝑒𝑏))))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹)))) → 𝐹 / 𝑔𝑌 = (𝑁𝑃))
 
Theoremcdlemk11tb 38945* Part of proof of Lemma K of [Crawley] p. 118. Lemma for Eq. 5, p. 119. 𝐺, 𝐼 stand for g, h. cdlemk11ta 38943 with hypotheses removed. TODO: Can this be proved directly with no quantification? (Contributed by NM, 21-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐼)))) → 𝐺 / 𝑔𝑌 (𝐼 / 𝑔𝑌 (𝑅‘(𝐼𝐺))))
 
Theoremcdlemk19y 38946* cdlemk19 38883 with simpler hypotheses. TODO: Clean all this up. (Contributed by NM, 30-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹)))) → 𝐹 / 𝑔𝑌 = (𝑁𝑃))
 
Theoremcdlemkid3N 38947* Lemma for cdlemkid 38950. (Contributed by NM, 25-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝐺 = ( I ↾ 𝐵))) → 𝐺 / 𝑔𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → (𝑧𝑃) = 𝑃)))
 
Theoremcdlemkid4 38948* Lemma for cdlemkid 38950. (Contributed by NM, 25-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝐺 = ( I ↾ 𝐵))) → 𝐺 / 𝑔𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) → 𝑧 = ( I ↾ 𝐵))))
 
Theoremcdlemkid5 38949* Lemma for cdlemkid 38950. (Contributed by NM, 25-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝐺 = ( I ↾ 𝐵))) → 𝐺 / 𝑔𝑋𝑇)
 
Theoremcdlemkid 38950* The value of the tau function (in Lemma K of [Crawley] p. 118) on the identity relation. (Contributed by NM, 25-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ 𝐺 = ( I ↾ 𝐵))) → 𝐺 / 𝑔𝑋 = ( I ↾ 𝐵))
 
Theoremcdlemk35s 38951* Substitution version of cdlemk35 38926. (Contributed by NM, 22-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ 𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → 𝐺 / 𝑔𝑋𝑇)
 
Theoremcdlemk35s-id 38952* Substitution version of cdlemk35 38926. (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ 𝐺𝑇𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → 𝐺 / 𝑔𝑋𝑇)
 
Theoremcdlemk39s 38953* Substitution version of cdlemk39 38930. TODO: Can any commonality with cdlemk35s 38951 be exploited? (Contributed by NM, 23-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ 𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → (𝑅𝐺 / 𝑔𝑋) (𝑅𝐺))
 
Theoremcdlemk39s-id 38954* Substitution version of cdlemk39 38930 with non-identity requirement on 𝐺 removed. TODO: Can any commonality with cdlemk35s 38951 be exploited? (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ 𝐺𝑇𝑁𝑇) ∧ ((𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁))) → (𝑅𝐺 / 𝑔𝑋) (𝑅𝐺))
 
Theoremcdlemk42 38955* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. (Contributed by NM, 20-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → (𝐺 / 𝑔𝑋𝑃) = 𝐺 / 𝑔𝑌)
 
Theoremcdlemk19xlem 38956* Lemma for cdlemk19x 38957. (Contributed by NM, 30-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹)))) → (𝐹 / 𝑔𝑋𝑃) = (𝑁𝑃))
 
Theoremcdlemk19x 38957* cdlemk19 38883 with simpler hypotheses. TODO: Clean all this up. (Contributed by NM, 30-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → (𝐹 / 𝑔𝑋𝑃) = (𝑁𝑃))
 
Theoremcdlemk42yN 38958* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. (Contributed by NM, 20-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → (𝐺 / 𝑔𝑋𝑃) = ((𝑃 (𝑅𝐺)) (𝑍 (𝑅‘(𝐺𝑏)))))
 
Theoremcdlemk11tc 38959* Part of proof of Lemma K of [Crawley] p. 118. Lemma for Eq. 5, p. 119. 𝐺, 𝐼 stand for g, h. TODO: fix comment. (Contributed by NM, 21-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐼)))) → (𝐺 / 𝑔𝑋𝑃) ((𝐼 / 𝑔𝑋𝑃) (𝑅‘(𝐼𝐺))))
 
Theoremcdlemk11t 38960* Part of proof of Lemma K of [Crawley] p. 118. Eq. 5, line 36, p. 119. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 21-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵))) → (𝐺 / 𝑔𝑋𝑃) ((𝐼 / 𝑔𝑋𝑃) (𝑅‘(𝐼𝐺))))
 
Theoremcdlemk45 38961* Part of proof of Lemma K of [Crawley] p. 118. Line 37, p. 119. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. They do not explicitly mention the requirement (𝐺𝐼) ≠ ( I ↾ 𝐵). (Contributed by NM, 22-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝐺𝐼) ≠ ( I ↾ 𝐵))) → ((𝐺𝐼) / 𝑔𝑋𝑃) ((𝐼 / 𝑔𝑋𝑃) (𝑅𝐺)))
 
Theoremcdlemk46 38962* Part of proof of Lemma K of [Crawley] p. 118. Line 38 (last line), p. 119. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 22-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝐺𝐼) ≠ ( I ↾ 𝐵))) → ((𝐺𝐼) / 𝑔𝑋𝑃) ((𝐺 / 𝑔𝑋𝑃) (𝑅𝐼)))
 
Theoremcdlemk47 38963* Part of proof of Lemma K of [Crawley] p. 118. Line 2, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 22-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝑅𝐺) ≠ (𝑅𝐼))) → ((𝐺𝐼) / 𝑔𝑋𝑃) = (((𝐺 / 𝑔𝑋𝑃) (𝑅𝐼)) ((𝐼 / 𝑔𝑋𝑃) (𝑅𝐺))))
 
Theoremcdlemk48 38964* Part of proof of Lemma K of [Crawley] p. 118. Line 4, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 22-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵))) → ((𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋)‘𝑃) ((𝐼 / 𝑔𝑋𝑃) (𝑅𝐺 / 𝑔𝑋)))
 
Theoremcdlemk49 38965* Part of proof of Lemma K of [Crawley] p. 118. Line 5, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 23-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵))) → ((𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋)‘𝑃) ((𝐺 / 𝑔𝑋𝑃) (𝑅𝐼 / 𝑔𝑋)))
 
Theoremcdlemk50 38966* Part of proof of Lemma K of [Crawley] p. 118. Line 6, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. TODO: Combine into cdlemk52 38968? (Contributed by NM, 23-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵))) → ((𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋)‘𝑃) (((𝐺 / 𝑔𝑋𝑃) (𝑅𝐼 / 𝑔𝑋)) ((𝐼 / 𝑔𝑋𝑃) (𝑅𝐺 / 𝑔𝑋))))
 
Theoremcdlemk51 38967* Part of proof of Lemma K of [Crawley] p. 118. Line 6, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. TODO: Combine into cdlemk52 38968? (Contributed by NM, 23-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵))) → (((𝐺 / 𝑔𝑋𝑃) (𝑅𝐼 / 𝑔𝑋)) ((𝐼 / 𝑔𝑋𝑃) (𝑅𝐺 / 𝑔𝑋))) (((𝐺 / 𝑔𝑋𝑃) (𝑅𝐼)) ((𝐼 / 𝑔𝑋𝑃) (𝑅𝐺))))
 
Theoremcdlemk52 38968* Part of proof of Lemma K of [Crawley] p. 118. Line 6, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 23-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝑅𝐺) ≠ (𝑅𝐼))) → ((𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋)‘𝑃) = ((𝐺𝐼) / 𝑔𝑋𝑃))
 
Theoremcdlemk53a 38969* Lemma for cdlemk53 38971. (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝐹 ≠ ( I ↾ 𝐵)) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵))) ∧ (𝑁𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝑅𝐺) ≠ (𝑅𝐼))) → (𝐺𝐼) / 𝑔𝑋 = (𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋))
 
Theoremcdlemk53b 38970* Lemma for cdlemk53 38971. (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ 𝐺𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ (𝐼𝑇𝐼 ≠ ( I ↾ 𝐵) ∧ (𝑅𝐺) ≠ (𝑅𝐼))) → (𝐺𝐼) / 𝑔𝑋 = (𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋))
 
Theoremcdlemk53 38971* Part of proof of Lemma K of [Crawley] p. 118. Line 7, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ 𝐺𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ (𝐼𝑇 ∧ (𝑅𝐺) ≠ (𝑅𝐼))) → (𝐺𝐼) / 𝑔𝑋 = (𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋))
 
Theoremcdlemk54 38972* Part of proof of Lemma K of [Crawley] p. 118. Line 10, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ 𝐺𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ ((𝐼𝑇 ∧ (𝑅𝐺) = (𝑅𝐼)) ∧ 𝑗𝑇 ∧ (𝑗 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑗) ≠ (𝑅𝐺) ∧ (𝑅𝑗) ≠ (𝑅‘(𝐺𝐼))))) → ((𝐺𝐼) / 𝑔𝑋𝑗 / 𝑔𝑋) = ((𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋) ∘ 𝑗 / 𝑔𝑋))
 
Theoremcdlemk55a 38973* Lemma for cdlemk55 38975. (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ 𝐺𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ ((𝐼𝑇 ∧ (𝑅𝐺) = (𝑅𝐼)) ∧ 𝑗𝑇 ∧ (𝑗 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑗) ≠ (𝑅𝐺) ∧ (𝑅𝑗) ≠ (𝑅‘(𝐺𝐼))))) → (𝐺𝐼) / 𝑔𝑋 = (𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋))
 
Theoremcdlemk55b 38974* Lemma for cdlemk55 38975. (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ 𝐺𝑇 ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ (𝐼𝑇 ∧ (𝑅𝐺) = (𝑅𝐼))) → (𝐺𝐼) / 𝑔𝑋 = (𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋))
 
Theoremcdlemk55 38975* Part of proof of Lemma K of [Crawley] p. 118. Line 11, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 26-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ 𝐺𝑇𝐼𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → (𝐺𝐼) / 𝑔𝑋 = (𝐺 / 𝑔𝑋𝐼 / 𝑔𝑋))
 
TheoremcdlemkyyN 38976* Part of proof of Lemma K of [Crawley] p. 118. TODO: clean up (𝑏𝑌𝐺) stuff. (Contributed by NM, 21-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑆 = (𝑓𝑇 ↦ (𝑖𝑇 (𝑖𝑃) = ((𝑃 (𝑅𝑓)) ((𝑁𝑃) (𝑅‘(𝑓𝐹))))))    &   𝑉 = (𝑑𝑇, 𝑒𝑇 ↦ (𝑗𝑇 (𝑗𝑃) = ((𝑃 (𝑅𝑒)) (((𝑆𝑑)‘𝑃) (𝑅‘(𝑒𝑑))))))       (((𝐾 ∈ HL ∧ 𝑊𝐻 ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝐹 ≠ ( I ↾ 𝐵) ∧ 𝑁𝑇) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → (𝐺 / 𝑔𝑋𝑃) = ((𝑏𝑉𝐺)‘𝑃))
 
Theoremcdlemk43N 38977* Part of proof of Lemma K of [Crawley] p. 118. TODO: fix comment. (Contributed by NM, 31-Jul-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ ((𝐹𝑇𝑁𝑇𝐹𝑁) ∧ (𝐺𝑇𝐺 ≠ ( I ↾ 𝐵)) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) ∧ (𝑏𝑇 ∧ (𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝐺)))) → ((𝑈𝐺)‘𝑃) = 𝐺 / 𝑔𝑌)
 
Theoremcdlemk35u 38978* Substitution version of cdlemk35 38926. (Contributed by NM, 31-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐹𝑇𝑁𝑇𝐺𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → (𝑈𝐺) ∈ 𝑇)
 
Theoremcdlemk55u1 38979* Lemma for cdlemk55u 38980. (Contributed by NM, 31-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇𝑁𝑇) ∧ (((𝑅𝐹) = (𝑅𝑁) ∧ 𝐹𝑁) ∧ 𝐺𝑇𝐼𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → (𝑈‘(𝐺𝐼)) = ((𝑈𝐺) ∘ (𝑈𝐼)))
 
Theoremcdlemk55u 38980* Part of proof of Lemma K of [Crawley] p. 118. Line 11, p. 120. 𝐺, 𝐼 stand for g, h. 𝑋 represents tau. (Contributed by NM, 31-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇𝑁𝑇) ∧ ((𝑅𝐹) = (𝑅𝑁) ∧ 𝐺𝑇𝐼𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → (𝑈‘(𝐺𝐼)) = ((𝑈𝐺) ∘ (𝑈𝐼)))
 
Theoremcdlemk39u1 38981* Lemma for cdlemk39u 38982. (Contributed by NM, 31-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇𝑁𝑇) ∧ ((𝑅𝐹) = (𝑅𝑁) ∧ 𝐹𝑁𝐺𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → (𝑅‘(𝑈𝐺)) (𝑅𝐺))
 
Theoremcdlemk39u 38982* Part of proof of Lemma K of [Crawley] p. 118. Line 31, p. 119. Trace-preserving property of the value of tau, represented by (𝑈𝐺). (Contributed by NM, 31-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇𝑁𝑇) ∧ ((𝑅𝐹) = (𝑅𝑁) ∧ 𝐺𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → (𝑅‘(𝑈𝐺)) (𝑅𝐺))
 
Theoremcdlemk19u1 38983* cdlemk19 38883 with simpler hypotheses. TODO: Clean all this up. (Contributed by NM, 31-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐹𝑇𝐹𝑁𝑁𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → ((𝑈𝐹)‘𝑃) = (𝑁𝑃))
 
Theoremcdlemk19u 38984* Part of Lemma K of [Crawley] p. 118. Line 12, p. 120, "f (exponent) tau = k". We represent f, k, tau with 𝐹, 𝑁, 𝑈. (Contributed by NM, 31-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑅𝐹) = (𝑅𝑁)) ∧ (𝐹𝑇𝑁𝑇) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → (𝑈𝐹) = 𝑁)
 
Theoremcdlemk56 38985* Part of Lemma K of [Crawley] p. 118. Line 11, p. 120, "tau is in Delta" i.e. 𝑈 is a trace-preserving endormorphism. (Contributed by NM, 31-Jul-2013.)
𝐵 = (Base‘𝐾)    &    = (le‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))    &   𝐸 = ((TEndo‘𝐾)‘𝑊)       ((((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇𝑁𝑇) ∧ (𝑅𝐹) = (𝑅𝑁) ∧ (𝑃𝐴 ∧ ¬ 𝑃 𝑊)) → 𝑈𝐸)
 
Theoremcdlemk19w 38986* Use a fixed element to eliminate 𝑃 in cdlemk19u 38984. (Contributed by NM, 1-Aug-2013.)
𝐵 = (Base‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &    = (oc‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑃 = ( 𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇) ∧ (𝑅𝐹) = (𝑅𝑁)) → (𝑈𝐹) = 𝑁)
 
Theoremcdlemk56w 38987* Use a fixed element to eliminate 𝑃 in cdlemk56 38985. (Contributed by NM, 1-Aug-2013.)
𝐵 = (Base‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &    = (oc‘𝐾)    &   𝐴 = (Atoms‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑃 = ( 𝑊)    &   𝑍 = ((𝑃 (𝑅𝑏)) ((𝑁𝑃) (𝑅‘(𝑏𝐹))))    &   𝑌 = ((𝑃 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅𝐹) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑃) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if(𝐹 = 𝑁, 𝑔, 𝑋))    &   𝐸 = ((TEndo‘𝐾)‘𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇) ∧ (𝑅𝐹) = (𝑅𝑁)) → (𝑈𝐸 ∧ (𝑈𝐹) = 𝑁))
 
Theoremcdlemk 38988* Lemma K of [Crawley] p. 118. Final result, lines 11 and 12 on p. 120: given two translations f and k with the same trace, there exists a trace-preserving endomorphism tau whose value at f is k. We use 𝐹, 𝑁, and 𝑢 to represent f, k, and tau. (Contributed by NM, 1-Aug-2013.)
𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇) ∧ (𝑅𝐹) = (𝑅𝑁)) → ∃𝑢𝐸 (𝑢𝐹) = 𝑁)
 
Theoremtendoex 38989* Generalization of Lemma K of [Crawley] p. 118, cdlemk 38988. TODO: can this be used to shorten uses of cdlemk 38988? (Contributed by NM, 15-Oct-2013.)
= (le‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝐹𝑇𝑁𝑇) ∧ (𝑅𝑁) (𝑅𝐹)) → ∃𝑢𝐸 (𝑢𝐹) = 𝑁)
 
Theoremcdleml1N 38990 Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 1-Aug-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑈𝐸𝑉𝐸𝑓𝑇) ∧ (𝑓 ≠ ( I ↾ 𝐵) ∧ (𝑈𝑓) ≠ ( I ↾ 𝐵) ∧ (𝑉𝑓) ≠ ( I ↾ 𝐵))) → (𝑅‘(𝑈𝑓)) = (𝑅‘(𝑉𝑓)))
 
Theoremcdleml2N 38991* Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 1-Aug-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑈𝐸𝑉𝐸𝑓𝑇) ∧ (𝑓 ≠ ( I ↾ 𝐵) ∧ (𝑈𝑓) ≠ ( I ↾ 𝐵) ∧ (𝑉𝑓) ≠ ( I ↾ 𝐵))) → ∃𝑠𝐸 (𝑠‘(𝑈𝑓)) = (𝑉𝑓))
 
Theoremcdleml3N 38992* Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 1-Aug-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)    &    0 = (𝑔𝑇 ↦ ( I ↾ 𝐵))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑈𝐸𝑉𝐸𝑓𝑇) ∧ (𝑓 ≠ ( I ↾ 𝐵) ∧ 𝑈0𝑉0 )) → ∃𝑠𝐸 (𝑠𝑈) = 𝑉)
 
Theoremcdleml4N 38993* Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 1-Aug-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)    &    0 = (𝑔𝑇 ↦ ( I ↾ 𝐵))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑈𝐸𝑉𝐸) ∧ (𝑈0𝑉0 )) → ∃𝑠𝐸 (𝑠𝑈) = 𝑉)
 
Theoremcdleml5N 38994* Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 1-Aug-2013.) (New usage is discouraged.)
𝐵 = (Base‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)    &    0 = (𝑔𝑇 ↦ ( I ↾ 𝐵))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑈𝐸𝑉𝐸) ∧ 𝑈0 ) → ∃𝑠𝐸 (𝑠𝑈) = 𝑉)
 
Theoremcdleml6 38995* Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 11-Aug-2013.)
𝐵 = (Base‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑄 = ((oc‘𝐾)‘𝑊)    &   𝑍 = ((𝑄 (𝑅𝑏)) ((𝑄) (𝑅‘(𝑏(𝑠)))))    &   𝑌 = ((𝑄 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅‘(𝑠)) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑄) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if((𝑠) = , 𝑔, 𝑋))    &   𝐸 = ((TEndo‘𝐾)‘𝑊)    &    0 = (𝑓𝑇 ↦ ( I ↾ 𝐵))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝑇 ∧ (𝑠𝐸𝑠0 )) → (𝑈𝐸 ∧ (𝑈‘(𝑠)) = ))
 
Theoremcdleml7 38996* Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 11-Aug-2013.)
𝐵 = (Base‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑄 = ((oc‘𝐾)‘𝑊)    &   𝑍 = ((𝑄 (𝑅𝑏)) ((𝑄) (𝑅‘(𝑏(𝑠)))))    &   𝑌 = ((𝑄 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅‘(𝑠)) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑄) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if((𝑠) = , 𝑔, 𝑋))    &   𝐸 = ((TEndo‘𝐾)‘𝑊)    &    0 = (𝑓𝑇 ↦ ( I ↾ 𝐵))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝑇 ∧ (𝑠𝐸𝑠0 )) → ((𝑈𝑠)‘) = (( I ↾ 𝑇)‘))
 
Theoremcdleml8 38997* Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 11-Aug-2013.)
𝐵 = (Base‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑄 = ((oc‘𝐾)‘𝑊)    &   𝑍 = ((𝑄 (𝑅𝑏)) ((𝑄) (𝑅‘(𝑏(𝑠)))))    &   𝑌 = ((𝑄 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅‘(𝑠)) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑄) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if((𝑠) = , 𝑔, 𝑋))    &   𝐸 = ((TEndo‘𝐾)‘𝑊)    &    0 = (𝑓𝑇 ↦ ( I ↾ 𝐵))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑇 ≠ ( I ↾ 𝐵)) ∧ (𝑠𝐸𝑠0 )) → (𝑈𝑠) = ( I ↾ 𝑇))
 
Theoremcdleml9 38998* Part of proof of Lemma L of [Crawley] p. 120. TODO: fix comment. (Contributed by NM, 11-Aug-2013.)
𝐵 = (Base‘𝐾)    &    = (join‘𝐾)    &    = (meet‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝑄 = ((oc‘𝐾)‘𝑊)    &   𝑍 = ((𝑄 (𝑅𝑏)) ((𝑄) (𝑅‘(𝑏(𝑠)))))    &   𝑌 = ((𝑄 (𝑅𝑔)) (𝑍 (𝑅‘(𝑔𝑏))))    &   𝑋 = (𝑧𝑇𝑏𝑇 ((𝑏 ≠ ( I ↾ 𝐵) ∧ (𝑅𝑏) ≠ (𝑅‘(𝑠)) ∧ (𝑅𝑏) ≠ (𝑅𝑔)) → (𝑧𝑄) = 𝑌))    &   𝑈 = (𝑔𝑇 ↦ if((𝑠) = , 𝑔, 𝑋))    &   𝐸 = ((TEndo‘𝐾)‘𝑊)    &    0 = (𝑓𝑇 ↦ ( I ↾ 𝐵))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ (𝑇 ≠ ( I ↾ 𝐵)) ∧ (𝑠𝐸𝑠0 )) → 𝑈0 )
 
Theoremdva1dim 38999* Two expressions for the 1-dimensional subspaces of partial vector space A. Remark in [Crawley] p. 120 line 21, but using a non-identity translation (nonzero vector) 𝐹 whose trace is 𝑃 rather than 𝑃 itself; 𝐹 exists by cdlemf 38577. 𝐸 is the division ring base by erngdv 39007, and 𝑠𝐹 is the scalar product by dvavsca 39031. 𝐹 must be a non-identity translation for the expression to be a 1-dimensional subspace, although the theorem doesn't require it. (Contributed by NM, 14-Oct-2013.)
= (le‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇) → {𝑔 ∣ ∃𝑠𝐸 𝑔 = (𝑠𝐹)} = {𝑔𝑇 ∣ (𝑅𝑔) (𝑅𝐹)})
 
Theoremdvhb1dimN 39000* Two expressions for the 1-dimensional subspaces of vector space H, in the isomorphism B case where the 2nd vector component is zero. (Contributed by NM, 23-Feb-2014.) (New usage is discouraged.)
= (le‘𝐾)    &   𝐻 = (LHyp‘𝐾)    &   𝑇 = ((LTrn‘𝐾)‘𝑊)    &   𝑅 = ((trL‘𝐾)‘𝑊)    &   𝐸 = ((TEndo‘𝐾)‘𝑊)    &    0 = (𝑇 ↦ ( I ↾ 𝐵))       (((𝐾 ∈ HL ∧ 𝑊𝐻) ∧ 𝐹𝑇) → {𝑔 ∈ (𝑇 × 𝐸) ∣ ∃𝑠𝐸 𝑔 = ⟨(𝑠𝐹), 0 ⟩} = {𝑔 ∈ (𝑇 × 𝐸) ∣ ((𝑅‘(1st𝑔)) (𝑅𝐹) ∧ (2nd𝑔) = 0 )})
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268 26701-26800 269 26801-26900 270 26901-27000 271 27001-27100 272 27101-27200 273 27201-27300 274 27301-27400 275 27401-27500 276 27501-27600 277 27601-27700 278 27701-27800 279 27801-27900 280 27901-28000 281 28001-28100 282 28101-28200 283 28201-28300 284 28301-28400 285 28401-28500 286 28501-28600 287 28601-28700 288 28701-28800 289 28801-28900 290 28901-29000 291 29001-29100 292 29101-29200 293 29201-29300 294 29301-29400 295 29401-29500 296 29501-29600 297 29601-29700 298 29701-29800 299 29801-29900 300 29901-30000 301 30001-30100 302 30101-30200 303 30201-30300 304 30301-30400 305 30401-30500 306 30501-30600 307 30601-30700 308 30701-30800 309 30801-30900 310 30901-31000 311 31001-31100 312 31101-31200 313 31201-31300 314 31301-31400 315 31401-31500 316 31501-31600 317 31601-31700 318 31701-31800 319 31801-31900 320 31901-32000 321 32001-32100 322 32101-32200 323 32201-32300 324 32301-32400 325 32401-32500 326 32501-32600 327 32601-32700 328 32701-32800 329 32801-32900 330 32901-33000 331 33001-33100 332 33101-33200 333 33201-33300 334 33301-33400 335 33401-33500 336 33501-33600 337 33601-33700 338 33701-33800 339 33801-33900 340 33901-34000 341 34001-34100 342 34101-34200 343 34201-34300 344 34301-34400 345 34401-34500 346 34501-34600 347 34601-34700 348 34701-34800 349 34801-34900 350 34901-35000 351 35001-35100 352 35101-35200 353 35201-35300 354 35301-35400 355 35401-35500 356 35501-35600 357 35601-35700 358 35701-35800 359 35801-35900 360 35901-36000 361 36001-36100 362 36101-36200 363 36201-36300 364 36301-36400 365 36401-36500 366 36501-36600 367 36601-36700 368 36701-36800 369 36801-36900 370 36901-37000 371 37001-37100 372 37101-37200 373 37201-37300 374 37301-37400 375 37401-37500 376 37501-37600 377 37601-37700 378 37701-37800 379 37801-37900 380 37901-38000 381 38001-38100 382 38101-38200 383 38201-38300 384 38301-38400 385 38401-38500 386 38501-38600 387 38601-38700 388 38701-38800 389 38801-38900 390 38901-39000 391 39001-39100 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