P. 335 of Theorem List - Metamath Proof Explorer

Theorem List for Metamath Proof Explorer - 33401-33500   *Has distinct variable group(s)

Type	Label	Description
Statement
Theorem	cringm4 33401	Commutative/associative law for commutative ring. (Contributed by Thierry Arnoux, 14-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ · = (.r‘𝑅)    ⇒   ⊢ ((𝑅 ∈ CRing ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵) ∧ (𝑍 ∈ 𝐵 ∧ 𝑊 ∈ 𝐵)) → ((𝑋 · 𝑌) · (𝑍 · 𝑊)) = ((𝑋 · 𝑍) · (𝑌 · 𝑊)))
Theorem	isprmidlc 33402*	The predicate "is prime ideal" for commutative rings. Alternate definition for commutative rings. See definition in [Lang] p. 92. (Contributed by Jeff Madsen, 19-Jun-2010.) (Revised by Thierry Arnoux, 12-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ · = (.r‘𝑅)    ⇒   ⊢ (𝑅 ∈ CRing → (𝑃 ∈ (PrmIdeal‘𝑅) ↔ (𝑃 ∈ (LIdeal‘𝑅) ∧ 𝑃 ≠ 𝐵 ∧ ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐵 ((𝑥 · 𝑦) ∈ 𝑃 → (𝑥 ∈ 𝑃 ∨ 𝑦 ∈ 𝑃)))))
Theorem	prmidlc 33403	Property of a prime ideal in a commutative ring. (Contributed by Jeff Madsen, 17-Jun-2011.) (Revised by Thierry Arnoux, 12-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ · = (.r‘𝑅)    ⇒   ⊢ (((𝑅 ∈ CRing ∧ 𝑃 ∈ (PrmIdeal‘𝑅)) ∧ (𝐼 ∈ 𝐵 ∧ 𝐽 ∈ 𝐵 ∧ (𝐼 · 𝐽) ∈ 𝑃)) → (𝐼 ∈ 𝑃 ∨ 𝐽 ∈ 𝑃))
Theorem	0ringprmidl 33404	The trivial ring does not have any prime ideal. (Contributed by Thierry Arnoux, 30-Jun-2024.)
⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ ((𝑅 ∈ Ring ∧ (♯‘𝐵) = 1) → (PrmIdeal‘𝑅) = ∅)
Theorem	prmidl0 33405	The zero ideal of a commutative ring 𝑅 is a prime ideal if and only if 𝑅 is an integral domain. (Contributed by Thierry Arnoux, 30-Jun-2024.)
⊢ 0 = (0g‘𝑅)    ⇒   ⊢ ((𝑅 ∈ CRing ∧ { 0 } ∈ (PrmIdeal‘𝑅)) ↔ 𝑅 ∈ IDomn)
Theorem	rhmpreimaprmidl 33406	The preimage of a prime ideal by a ring homomorphism is a prime ideal. (Contributed by Thierry Arnoux, 29-Jun-2024.)
⊢ 𝑃 = (PrmIdeal‘𝑅)    ⇒   ⊢ (((𝑆 ∈ CRing ∧ 𝐹 ∈ (𝑅 RingHom 𝑆)) ∧ 𝐽 ∈ (PrmIdeal‘𝑆)) → (◡𝐹 “ 𝐽) ∈ 𝑃)
Theorem	qsidomlem1 33407	If the quotient ring of a commutative ring relative to an ideal is an integral domain, that ideal must be prime. (Contributed by Thierry Arnoux, 16-Jan-2024.)
⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    ⇒   ⊢ (((𝑅 ∈ CRing ∧ 𝐼 ∈ (LIdeal‘𝑅)) ∧ 𝑄 ∈ IDomn) → 𝐼 ∈ (PrmIdeal‘𝑅))
Theorem	qsidomlem2 33408	A quotient by a prime ideal is an integral domain. (Contributed by Thierry Arnoux, 16-Jan-2024.)
⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    ⇒   ⊢ ((𝑅 ∈ CRing ∧ 𝐼 ∈ (PrmIdeal‘𝑅)) → 𝑄 ∈ IDomn)
Theorem	qsidom 33409	An ideal 𝐼 in the commutative ring 𝑅 is prime if and only if the factor ring 𝑄 is an integral domain. (Contributed by Thierry Arnoux, 16-Jan-2024.)
⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    ⇒   ⊢ ((𝑅 ∈ CRing ∧ 𝐼 ∈ (LIdeal‘𝑅)) → (𝑄 ∈ IDomn ↔ 𝐼 ∈ (PrmIdeal‘𝑅)))
Theorem	qsnzr 33410	A quotient of a non-zero ring by a proper ideal is a non-zero ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    &   ⊢ (𝜑 → 𝐼 ∈ (2Ideal‘𝑅))    &   ⊢ (𝜑 → 𝐼 ≠ 𝐵)    ⇒   ⊢ (𝜑 → 𝑄 ∈ NzRing)
Theorem	ssdifidllem 33411*	Lemma for ssdifidl 33412: The set 𝑃 used in the proof of ssdifidl 33412 satisfies the condition of Zorn's Lemma. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝐼 ∈ (LIdeal‘𝑅))    &   ⊢ (𝜑 → 𝑆 ⊆ 𝐵)    &   ⊢ (𝜑 → (𝑆 ∩ 𝐼) = ∅)    &   ⊢ 𝑃 = {𝑝 ∈ (LIdeal‘𝑅) ∣ ((𝑆 ∩ 𝑝) = ∅ ∧ 𝐼 ⊆ 𝑝)}    &   ⊢ (𝜑 → 𝑍 ⊆ 𝑃)    &   ⊢ (𝜑 → 𝑍 ≠ ∅)    &   ⊢ (𝜑 → [⊊] Or 𝑍)    ⇒   ⊢ (𝜑 → ∪ 𝑍 ∈ 𝑃)
Theorem	ssdifidl 33412*	Let 𝑅 be a ring, and let 𝐼 be an ideal of 𝑅 disjoint with a set 𝑆. Then there exists an ideal 𝑖, maximal among the set 𝑃 of ideals containing 𝐼 and disjoint with 𝑆. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝐼 ∈ (LIdeal‘𝑅))    &   ⊢ (𝜑 → 𝑆 ⊆ 𝐵)    &   ⊢ (𝜑 → (𝑆 ∩ 𝐼) = ∅)    &   ⊢ 𝑃 = {𝑝 ∈ (LIdeal‘𝑅) ∣ ((𝑆 ∩ 𝑝) = ∅ ∧ 𝐼 ⊆ 𝑝)}    ⇒   ⊢ (𝜑 → ∃𝑖 ∈ 𝑃 ∀𝑗 ∈ 𝑃 ¬ 𝑖 ⊊ 𝑗)
Theorem	ssdifidlprm 33413*	If the set 𝑆 of ssdifidl 33412 is multiplicatively closed, then the ideal 𝑖 is prime. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝐼 ∈ (LIdeal‘𝑅))    &   ⊢ (𝜑 → 𝑆 ∈ (SubMnd‘𝑀))    &   ⊢ 𝑀 = (mulGrp‘𝑅)    &   ⊢ (𝜑 → (𝑆 ∩ 𝐼) = ∅)    &   ⊢ 𝑃 = {𝑝 ∈ (LIdeal‘𝑅) ∣ ((𝑆 ∩ 𝑝) = ∅ ∧ 𝐼 ⊆ 𝑝)}    ⇒   ⊢ (𝜑 → ∃𝑖 ∈ 𝑃 (𝑖 ∈ (PrmIdeal‘𝑅) ∧ ∀𝑗 ∈ 𝑃 ¬ 𝑖 ⊊ 𝑗))
21.3.10.40  Maximal Ideals
Syntax	cmxidl 33414	Extend class notation with the class of maximal ideals.
class MaxIdeal
Definition	df-mxidl 33415*	Define the class of maximal ideals of a ring 𝑅. A proper ideal is called maximal if it is maximal with respect to inclusion among proper ideals. (Contributed by Jeff Madsen, 5-Jan-2011.) (Revised by Thierry Arnoux, 19-Jan-2024.)
⊢ MaxIdeal = (𝑟 ∈ Ring ↦ {𝑖 ∈ (LIdeal‘𝑟) ∣ (𝑖 ≠ (Base‘𝑟) ∧ ∀𝑗 ∈ (LIdeal‘𝑟)(𝑖 ⊆ 𝑗 → (𝑗 = 𝑖 ∨ 𝑗 = (Base‘𝑟))))})
Theorem	mxidlval 33416*	The set of maximal ideals of a ring. (Contributed by Jeff Madsen, 5-Jan-2011.) (Revised by Thierry Arnoux, 19-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ (𝑅 ∈ Ring → (MaxIdeal‘𝑅) = {𝑖 ∈ (LIdeal‘𝑅) ∣ (𝑖 ≠ 𝐵 ∧ ∀𝑗 ∈ (LIdeal‘𝑅)(𝑖 ⊆ 𝑗 → (𝑗 = 𝑖 ∨ 𝑗 = 𝐵)))})
Theorem	ismxidl 33417*	The predicate "is a maximal ideal". (Contributed by Jeff Madsen, 5-Jan-2011.) (Revised by Thierry Arnoux, 19-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ (𝑅 ∈ Ring → (𝑀 ∈ (MaxIdeal‘𝑅) ↔ (𝑀 ∈ (LIdeal‘𝑅) ∧ 𝑀 ≠ 𝐵 ∧ ∀𝑗 ∈ (LIdeal‘𝑅)(𝑀 ⊆ 𝑗 → (𝑗 = 𝑀 ∨ 𝑗 = 𝐵)))))
Theorem	mxidlidl 33418	A maximal ideal is an ideal. (Contributed by Jeff Madsen, 5-Jan-2011.) (Revised by Thierry Arnoux, 19-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ ((𝑅 ∈ Ring ∧ 𝑀 ∈ (MaxIdeal‘𝑅)) → 𝑀 ∈ (LIdeal‘𝑅))
Theorem	mxidlnr 33419	A maximal ideal is proper. (Contributed by Jeff Madsen, 16-Jun-2011.) (Revised by Thierry Arnoux, 19-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ ((𝑅 ∈ Ring ∧ 𝑀 ∈ (MaxIdeal‘𝑅)) → 𝑀 ≠ 𝐵)
Theorem	mxidlmax 33420	A maximal ideal is a maximal proper ideal. (Contributed by Jeff Madsen, 16-Jun-2011.) (Revised by Thierry Arnoux, 19-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ (((𝑅 ∈ Ring ∧ 𝑀 ∈ (MaxIdeal‘𝑅)) ∧ (𝐼 ∈ (LIdeal‘𝑅) ∧ 𝑀 ⊆ 𝐼)) → (𝐼 = 𝑀 ∨ 𝐼 = 𝐵))
Theorem	mxidln1 33421	One is not contained in any maximal ideal. (Contributed by Jeff Madsen, 17-Jun-2011.) (Revised by Thierry Arnoux, 19-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 1 = (1r‘𝑅)    ⇒   ⊢ ((𝑅 ∈ Ring ∧ 𝑀 ∈ (MaxIdeal‘𝑅)) → ¬ 1 ∈ 𝑀)
Theorem	mxidlnzr 33422	A ring with a maximal ideal is a nonzero ring. (Contributed by Jeff Madsen, 17-Jun-2011.) (Revised by Thierry Arnoux, 19-Jan-2024.)
⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ ((𝑅 ∈ Ring ∧ 𝑀 ∈ (MaxIdeal‘𝑅)) → 𝑅 ∈ NzRing)
Theorem	mxidlmaxv 33423	An ideal 𝐼 strictly containing a maximal ideal 𝑀 is the whole ring 𝐵. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘𝑅))    &   ⊢ (𝜑 → 𝐼 ∈ (LIdeal‘𝑅))    &   ⊢ (𝜑 → 𝑀 ⊆ 𝐼)    &   ⊢ (𝜑 → 𝑋 ∈ (𝐼 ∖ 𝑀))    ⇒   ⊢ (𝜑 → 𝐼 = 𝐵)
Theorem	crngmxidl 33424	In a commutative ring, maximal ideals of the opposite ring coincide with maximal ideals. (Contributed by Thierry Arnoux, 13-Mar-2025.)
⊢ 𝑀 = (MaxIdeal‘𝑅)    &   ⊢ 𝑂 = (oppr‘𝑅)    ⇒   ⊢ (𝑅 ∈ CRing → 𝑀 = (MaxIdeal‘𝑂))
Theorem	mxidlprm 33425	Every maximal ideal is prime. Statement in [Lang] p. 92. (Contributed by Thierry Arnoux, 21-Jan-2024.)
⊢ × = (LSSum‘(mulGrp‘𝑅))    ⇒   ⊢ ((𝑅 ∈ CRing ∧ 𝑀 ∈ (MaxIdeal‘𝑅)) → 𝑀 ∈ (PrmIdeal‘𝑅))
Theorem	mxidlirredi 33426	In an integral domain, the generator of a maximal ideal is irreducible. (Contributed by Thierry Arnoux, 22-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝐾 = (RSpan‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ 𝑀 = (𝐾‘{𝑋})    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐵)    &   ⊢ (𝜑 → 𝑋 ≠ 0 )    &   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘𝑅))    ⇒   ⊢ (𝜑 → 𝑋 ∈ (Irred‘𝑅))
Theorem	mxidlirred 33427	In a principal ideal domain, maximal ideals are exactly the ideals generated by irreducible elements. (Contributed by Thierry Arnoux, 22-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝐾 = (RSpan‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ 𝑀 = (𝐾‘{𝑋})    &   ⊢ (𝜑 → 𝑅 ∈ PID)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐵)    &   ⊢ (𝜑 → 𝑋 ≠ 0 )    &   ⊢ (𝜑 → 𝑀 ∈ (LIdeal‘𝑅))    ⇒   ⊢ (𝜑 → (𝑀 ∈ (MaxIdeal‘𝑅) ↔ 𝑋 ∈ (Irred‘𝑅)))
Theorem	ssmxidllem 33428*	The set 𝑃 used in the proof of ssmxidl 33429 satisfies the condition of Zorn's Lemma. (Contributed by Thierry Arnoux, 10-Apr-2024.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = {𝑝 ∈ (LIdeal‘𝑅) ∣ (𝑝 ≠ 𝐵 ∧ 𝐼 ⊆ 𝑝)}    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝐼 ∈ (LIdeal‘𝑅))    &   ⊢ (𝜑 → 𝐼 ≠ 𝐵)    &   ⊢ (𝜑 → 𝑍 ⊆ 𝑃)    &   ⊢ (𝜑 → 𝑍 ≠ ∅)    &   ⊢ (𝜑 → [⊊] Or 𝑍)    ⇒   ⊢ (𝜑 → ∪ 𝑍 ∈ 𝑃)
Theorem	ssmxidl 33429*	Let 𝑅 be a ring, and let 𝐼 be a proper ideal of 𝑅. Then there is a maximal ideal of 𝑅 containing 𝐼. (Contributed by Thierry Arnoux, 10-Apr-2024.)
⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ ((𝑅 ∈ Ring ∧ 𝐼 ∈ (LIdeal‘𝑅) ∧ 𝐼 ≠ 𝐵) → ∃𝑚 ∈ (MaxIdeal‘𝑅)𝐼 ⊆ 𝑚)
Theorem	drnglidl1ne0 33430	In a nonzero ring, the zero ideal is different of the unit ideal. (Contributed by Thierry Arnoux, 16-Mar-2025.)
⊢ 0 = (0g‘𝑅)    &   ⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ (𝑅 ∈ NzRing → 𝐵 ≠ { 0 })
Theorem	drng0mxidl 33431	In a division ring, the zero ideal is a maximal ideal. (Contributed by Thierry Arnoux, 16-Mar-2025.)
⊢ 0 = (0g‘𝑅)    ⇒   ⊢ (𝑅 ∈ DivRing → { 0 } ∈ (MaxIdeal‘𝑅))
Theorem	drngmxidl 33432	The zero ideal is the only ideal of a division ring. (Contributed by Thierry Arnoux, 16-Mar-2025.)
⊢ 0 = (0g‘𝑅)    ⇒   ⊢ (𝑅 ∈ DivRing → (MaxIdeal‘𝑅) = {{ 0 }})
Theorem	drngmxidlr 33433	If a ring's only maximal ideal is the zero ideal, it is a division ring. See also drngmxidl 33432. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ 𝑀 = (MaxIdeal‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    &   ⊢ (𝜑 → 𝑀 = {{ 0 }})    ⇒   ⊢ (𝜑 → 𝑅 ∈ DivRing)
Theorem	krull 33434*	Krull's theorem: Any nonzero ring has at least one maximal ideal. (Contributed by Thierry Arnoux, 10-Apr-2024.)
⊢ (𝑅 ∈ NzRing → ∃𝑚 𝑚 ∈ (MaxIdeal‘𝑅))
Theorem	mxidlnzrb 33435*	A ring is nonzero if and only if it has maximal ideals. (Contributed by Thierry Arnoux, 10-Apr-2024.)
⊢ (𝑅 ∈ Ring → (𝑅 ∈ NzRing ↔ ∃𝑚 𝑚 ∈ (MaxIdeal‘𝑅)))
Theorem	krullndrng 33436*	Krull's theorem for non-division-rings: Existence of a nonzero maximal ideal. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 0 = (0g‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    &   ⊢ (𝜑 → ¬ 𝑅 ∈ DivRing)    ⇒   ⊢ (𝜑 → ∃𝑚 ∈ (MaxIdeal‘𝑅)𝑚 ≠ { 0 })
Theorem	opprabs 33437	The opposite ring of the opposite ring is the original ring. Note the conditions on this theorem, which makes it unpractical in case we only have e.g. 𝑅 ∈ Ring as a premise. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ · = (.r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ 𝑉)    &   ⊢ (𝜑 → Fun 𝑅)    &   ⊢ (𝜑 → (.r‘ndx) ∈ dom 𝑅)    &   ⊢ (𝜑 → · Fn (𝐵 × 𝐵))    ⇒   ⊢ (𝜑 → 𝑅 = (oppr‘𝑂))
Theorem	oppreqg 33438	Group coset equivalence relation for the opposite ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝐵 = (Base‘𝑅)    ⇒   ⊢ ((𝑅 ∈ 𝑉 ∧ 𝐼 ⊆ 𝐵) → (𝑅 ~QG 𝐼) = (𝑂 ~QG 𝐼))
Theorem	opprnsg 33439	Normal subgroups of the opposite ring are the same as the original normal subgroups. (Contributed by Thierry Arnoux, 13-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    ⇒   ⊢ (NrmSGrp‘𝑅) = (NrmSGrp‘𝑂)
Theorem	opprlidlabs 33440	The ideals of the opposite ring's opposite ring are the ideals of the original ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    ⇒   ⊢ (𝜑 → (LIdeal‘𝑅) = (LIdeal‘(oppr‘𝑂)))
Theorem	oppr2idl 33441	Two sided ideal of the opposite ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    ⇒   ⊢ (𝜑 → (2Ideal‘𝑅) = (2Ideal‘𝑂))
Theorem	opprmxidlabs 33442	The maximal ideal of the opposite ring's opposite ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘𝑅))    ⇒   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘(oppr‘𝑂)))
Theorem	opprqusbas 33443	The base of the quotient of the opposite ring is the same as the base of the opposite of the quotient ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    &   ⊢ (𝜑 → 𝑅 ∈ 𝑉)    &   ⊢ (𝜑 → 𝐼 ⊆ 𝐵)    ⇒   ⊢ (𝜑 → (Base‘(oppr‘𝑄)) = (Base‘(𝑂 /s (𝑂 ~QG 𝐼))))
Theorem	opprqusplusg 33444	The group operation of the quotient of the opposite ring is the same as the group operation of the opposite of the quotient ring. (Contributed by Thierry Arnoux, 13-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    &   ⊢ (𝜑 → 𝐼 ∈ (NrmSGrp‘𝑅))    &   ⊢ 𝐸 = (Base‘𝑄)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐸)    &   ⊢ (𝜑 → 𝑌 ∈ 𝐸)    ⇒   ⊢ (𝜑 → (𝑋(+g‘(oppr‘𝑄))𝑌) = (𝑋(+g‘(𝑂 /s (𝑂 ~QG 𝐼)))𝑌))
Theorem	opprqus0g 33445	The group identity element of the quotient of the opposite ring is the same as the group identity element of the opposite of the quotient ring. (Contributed by Thierry Arnoux, 13-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    &   ⊢ (𝜑 → 𝐼 ∈ (NrmSGrp‘𝑅))    ⇒   ⊢ (𝜑 → (0g‘(oppr‘𝑄)) = (0g‘(𝑂 /s (𝑂 ~QG 𝐼))))
Theorem	opprqusmulr 33446	The multiplication operation of the quotient of the opposite ring is the same as the multiplication operation of the opposite of the quotient ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝐼 ∈ (2Ideal‘𝑅))    &   ⊢ 𝐸 = (Base‘𝑄)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐸)    &   ⊢ (𝜑 → 𝑌 ∈ 𝐸)    ⇒   ⊢ (𝜑 → (𝑋(.r‘(oppr‘𝑄))𝑌) = (𝑋(.r‘(𝑂 /s (𝑂 ~QG 𝐼)))𝑌))
Theorem	opprqus1r 33447	The ring unity of the quotient of the opposite ring is the same as the ring unity of the opposite of the quotient ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝐼 ∈ (2Ideal‘𝑅))    ⇒   ⊢ (𝜑 → (1r‘(oppr‘𝑄)) = (1r‘(𝑂 /s (𝑂 ~QG 𝐼))))
Theorem	opprqusdrng 33448	The quotient of the opposite ring is a division ring iff the opposite of the quotient ring is. (Contributed by Thierry Arnoux, 13-Mar-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝐼))    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝐼 ∈ (2Ideal‘𝑅))    ⇒   ⊢ (𝜑 → ((oppr‘𝑄) ∈ DivRing ↔ (𝑂 /s (𝑂 ~QG 𝐼)) ∈ DivRing))
Theorem	qsdrngilem 33449*	Lemma for qsdrngi 33450. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝑀))    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    &   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘𝑅))    &   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘𝑂))    &   ⊢ (𝜑 → 𝑋 ∈ (Base‘𝑅))    &   ⊢ (𝜑 → ¬ 𝑋 ∈ 𝑀)    ⇒   ⊢ (𝜑 → ∃𝑣 ∈ (Base‘𝑄)(𝑣(.r‘𝑄)[𝑋](𝑅 ~QG 𝑀)) = (1r‘𝑄))
Theorem	qsdrngi 33450	A quotient by a maximal left and maximal right ideal is a division ring. (Contributed by Thierry Arnoux, 9-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝑀))    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    &   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘𝑅))    &   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘𝑂))    ⇒   ⊢ (𝜑 → 𝑄 ∈ DivRing)
Theorem	qsdrnglem2 33451	Lemma for qsdrng 33452. (Contributed by Thierry Arnoux, 13-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝑀))    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    &   ⊢ (𝜑 → 𝑀 ∈ (2Ideal‘𝑅))    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ (𝜑 → 𝑄 ∈ DivRing)    &   ⊢ (𝜑 → 𝐽 ∈ (LIdeal‘𝑅))    &   ⊢ (𝜑 → 𝑀 ⊆ 𝐽)    &   ⊢ (𝜑 → 𝑋 ∈ (𝐽 ∖ 𝑀))    ⇒   ⊢ (𝜑 → 𝐽 = 𝐵)
Theorem	qsdrng 33452	An ideal 𝑀 is both left and right maximal if and only if the factor ring 𝑄 is a division ring. (Contributed by Thierry Arnoux, 13-Mar-2025.)
⊢ 𝑂 = (oppr‘𝑅)    &   ⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝑀))    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    &   ⊢ (𝜑 → 𝑀 ∈ (2Ideal‘𝑅))    ⇒   ⊢ (𝜑 → (𝑄 ∈ DivRing ↔ (𝑀 ∈ (MaxIdeal‘𝑅) ∧ 𝑀 ∈ (MaxIdeal‘𝑂))))
Theorem	qsfld 33453	An ideal 𝑀 in the commutative ring 𝑅 is maximal if and only if the factor ring 𝑄 is a field. (Contributed by Thierry Arnoux, 13-Mar-2025.)
⊢ 𝑄 = (𝑅 /s (𝑅 ~QG 𝑀))    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    &   ⊢ (𝜑 → 𝑀 ∈ (LIdeal‘𝑅))    ⇒   ⊢ (𝜑 → (𝑄 ∈ Field ↔ 𝑀 ∈ (MaxIdeal‘𝑅)))
Theorem	mxidlprmALT 33454	Every maximal ideal is prime - alternative proof. (Contributed by Thierry Arnoux, 15-Mar-2025.) (Proof modification is discouraged.) (New usage is discouraged.)
⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑀 ∈ (MaxIdeal‘𝑅))    ⇒   ⊢ (𝜑 → 𝑀 ∈ (PrmIdeal‘𝑅))
21.3.10.41  The semiring of ideals of a ring
Syntax	cidlsrg 33455	Extend class notation with the semiring of ideals of a ring.
class IDLsrg
Definition	df-idlsrg 33456*	Define a structure for the ideals of a ring. (Contributed by Thierry Arnoux, 21-Jan-2024.)
⊢ IDLsrg = (𝑟 ∈ V ↦ ⦋(LIdeal‘𝑟) / 𝑏⦌({⟨(Base‘ndx), 𝑏⟩, ⟨(+g‘ndx), (LSSum‘𝑟)⟩, ⟨(.r‘ndx), (𝑖 ∈ 𝑏, 𝑗 ∈ 𝑏 ↦ ((RSpan‘𝑟)‘(𝑖(LSSum‘(mulGrp‘𝑟))𝑗)))⟩} ∪ {⟨(TopSet‘ndx), ran (𝑖 ∈ 𝑏 ↦ {𝑗 ∈ 𝑏 ∣ ¬ 𝑖 ⊆ 𝑗})⟩, ⟨(le‘ndx), {⟨𝑖, 𝑗⟩ ∣ ({𝑖, 𝑗} ⊆ 𝑏 ∧ 𝑖 ⊆ 𝑗)}⟩}))
Theorem	idlsrgstr 33457	A constructed semiring of ideals is a structure. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑊 = ({⟨(Base‘ndx), 𝐵⟩, ⟨(+g‘ndx), + ⟩, ⟨(.r‘ndx), · ⟩} ∪ {⟨(TopSet‘ndx), 𝐽⟩, ⟨(le‘ndx), ≤ ⟩})    ⇒   ⊢ 𝑊 Struct ⟨1, ;10⟩
Theorem	idlsrgval 33458*	Lemma for idlsrgbas 33459 through idlsrgtset 33463. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝐼 = (LIdeal‘𝑅)    &   ⊢ ⊕ = (LSSum‘𝑅)    &   ⊢ 𝐺 = (mulGrp‘𝑅)    &   ⊢ ⊗ = (LSSum‘𝐺)    ⇒   ⊢ (𝑅 ∈ 𝑉 → (IDLsrg‘𝑅) = ({⟨(Base‘ndx), 𝐼⟩, ⟨(+g‘ndx), ⊕ ⟩, ⟨(.r‘ndx), (𝑖 ∈ 𝐼, 𝑗 ∈ 𝐼 ↦ ((RSpan‘𝑅)‘(𝑖 ⊗ 𝑗)))⟩} ∪ {⟨(TopSet‘ndx), ran (𝑖 ∈ 𝐼 ↦ {𝑗 ∈ 𝐼 ∣ ¬ 𝑖 ⊆ 𝑗})⟩, ⟨(le‘ndx), {⟨𝑖, 𝑗⟩ ∣ ({𝑖, 𝑗} ⊆ 𝐼 ∧ 𝑖 ⊆ 𝑗)}⟩}))
Theorem	idlsrgbas 33459	Base of the ideals of a ring. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 𝐼 = (LIdeal‘𝑅)    ⇒   ⊢ (𝑅 ∈ 𝑉 → 𝐼 = (Base‘𝑆))
Theorem	idlsrgplusg 33460	Additive operation of the ideals of a ring. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ ⊕ = (LSSum‘𝑅)    ⇒   ⊢ (𝑅 ∈ 𝑉 → ⊕ = (+g‘𝑆))
Theorem	idlsrg0g 33461	The zero ideal is the additive identity of the semiring of ideals. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    ⇒   ⊢ (𝑅 ∈ Ring → { 0 } = (0g‘𝑆))
Theorem	idlsrgmulr 33462*	Multiplicative operation of the ideals of a ring. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 𝐵 = (LIdeal‘𝑅)    &   ⊢ 𝐺 = (mulGrp‘𝑅)    &   ⊢ ⊗ = (LSSum‘𝐺)    ⇒   ⊢ (𝑅 ∈ 𝑉 → (𝑖 ∈ 𝐵, 𝑗 ∈ 𝐵 ↦ ((RSpan‘𝑅)‘(𝑖 ⊗ 𝑗))) = (.r‘𝑆))
Theorem	idlsrgtset 33463*	Topology component of the ideals of a ring. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 𝐼 = (LIdeal‘𝑅)    &   ⊢ 𝐽 = ran (𝑖 ∈ 𝐼 ↦ {𝑗 ∈ 𝐼 ∣ ¬ 𝑖 ⊆ 𝑗})    ⇒   ⊢ (𝑅 ∈ 𝑉 → 𝐽 = (TopSet‘𝑆))
Theorem	idlsrgmulrval 33464	Value of the ring multiplication for the ideals of a ring 𝑅. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 𝐵 = (LIdeal‘𝑅)    &   ⊢ ⊗ = (.r‘𝑆)    &   ⊢ 𝐺 = (mulGrp‘𝑅)    &   ⊢ · = (LSSum‘𝐺)    &   ⊢ (𝜑 → 𝑅 ∈ 𝑉)    &   ⊢ (𝜑 → 𝐼 ∈ 𝐵)    &   ⊢ (𝜑 → 𝐽 ∈ 𝐵)    ⇒   ⊢ (𝜑 → (𝐼 ⊗ 𝐽) = ((RSpan‘𝑅)‘(𝐼 · 𝐽)))
Theorem	idlsrgmulrcl 33465	Ideals of a ring 𝑅 are closed under multiplication. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 𝐵 = (LIdeal‘𝑅)    &   ⊢ ⊗ = (.r‘𝑆)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝐼 ∈ 𝐵)    &   ⊢ (𝜑 → 𝐽 ∈ 𝐵)    ⇒   ⊢ (𝜑 → (𝐼 ⊗ 𝐽) ∈ 𝐵)
Theorem	idlsrgmulrss1 33466	In a commutative ring, the product of two ideals is a subset of the first one. (Contributed by Thierry Arnoux, 16-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 𝐵 = (LIdeal‘𝑅)    &   ⊢ ⊗ = (.r‘𝑆)    &   ⊢ · = (.r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝐼 ∈ 𝐵)    &   ⊢ (𝜑 → 𝐽 ∈ 𝐵)    ⇒   ⊢ (𝜑 → (𝐼 ⊗ 𝐽) ⊆ 𝐼)
Theorem	idlsrgmulrss2 33467	The product of two ideals is a subset of the second one. (Contributed by Thierry Arnoux, 2-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 𝐵 = (LIdeal‘𝑅)    &   ⊢ ⊗ = (.r‘𝑆)    &   ⊢ · = (.r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝐼 ∈ 𝐵)    &   ⊢ (𝜑 → 𝐽 ∈ 𝐵)    ⇒   ⊢ (𝜑 → (𝐼 ⊗ 𝐽) ⊆ 𝐽)
Theorem	idlsrgmulrssin 33468	In a commutative ring, the product of two ideals is a subset of their intersection. (Contributed by Thierry Arnoux, 17-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    &   ⊢ 𝐵 = (LIdeal‘𝑅)    &   ⊢ ⊗ = (.r‘𝑆)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝐼 ∈ 𝐵)    &   ⊢ (𝜑 → 𝐽 ∈ 𝐵)    ⇒   ⊢ (𝜑 → (𝐼 ⊗ 𝐽) ⊆ (𝐼 ∩ 𝐽))
Theorem	idlsrgmnd 33469	The ideals of a ring form a monoid. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    ⇒   ⊢ (𝑅 ∈ Ring → 𝑆 ∈ Mnd)
Theorem	idlsrgcmnd 33470	The ideals of a ring form a commutative monoid. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝑆 = (IDLsrg‘𝑅)    ⇒   ⊢ (𝑅 ∈ Ring → 𝑆 ∈ CMnd)
21.3.10.42  Prime Elements
Theorem	rprmval 33471*	The prime elements of a ring 𝑅. (Contributed by Thierry Arnoux, 1-Jul-2024.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ · = (.r‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    ⇒   ⊢ (𝑅 ∈ 𝑉 → (RPrime‘𝑅) = {𝑝 ∈ (𝐵 ∖ (𝑈 ∪ { 0 })) ∣ ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐵 (𝑝 ∥ (𝑥 · 𝑦) → (𝑝 ∥ 𝑥 ∨ 𝑝 ∥ 𝑦))})
Theorem	isrprm 33472*	Property for 𝑃 to be a prime element in the ring 𝑅. (Contributed by Thierry Arnoux, 1-Jul-2024.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ · = (.r‘𝑅)    ⇒   ⊢ (𝑅 ∈ 𝑉 → (𝑃 ∈ (RPrime‘𝑅) ↔ (𝑃 ∈ (𝐵 ∖ (𝑈 ∪ { 0 })) ∧ ∀𝑥 ∈ 𝐵 ∀𝑦 ∈ 𝐵 (𝑃 ∥ (𝑥 · 𝑦) → (𝑃 ∥ 𝑥 ∨ 𝑃 ∥ 𝑦)))))
Theorem	rprmcl 33473	A ring prime is an element of the base set. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ 𝑉)    &   ⊢ (𝜑 → 𝑋 ∈ 𝑃)    ⇒   ⊢ (𝜑 → 𝑋 ∈ 𝐵)
Theorem	rprmdvds 33474	If a ring prime 𝑄 divides a product 𝑋 · 𝑌, then it divides either 𝑋 or 𝑌. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ · = (.r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ 𝑉)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐵)    &   ⊢ (𝜑 → 𝑌 ∈ 𝐵)    &   ⊢ (𝜑 → 𝑄 ∥ (𝑋 · 𝑌))    ⇒   ⊢ (𝜑 → (𝑄 ∥ 𝑋 ∨ 𝑄 ∥ 𝑌))
Theorem	rprmnz 33475	A ring prime is nonzero. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ 𝑉)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    ⇒   ⊢ (𝜑 → 𝑄 ≠ 0 )
Theorem	rprmnunit 33476	A ring prime is not a unit. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ 𝑉)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    ⇒   ⊢ (𝜑 → ¬ 𝑄 ∈ 𝑈)
Theorem	rsprprmprmidl 33477	In a commutative ring, ideals generated by prime elements are prime ideals. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝐾 = (RSpan‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑃 ∈ (RPrime‘𝑅))    ⇒   ⊢ (𝜑 → (𝐾‘{𝑃}) ∈ (PrmIdeal‘𝑅))
Theorem	rsprprmprmidlb 33478	In an integral domain, an ideal generated by a single element is a prime iff that element is prime. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 0 = (0g‘𝑅)    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝐾 = (RSpan‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐵)    &   ⊢ (𝜑 → 𝑋 ≠ 0 )    ⇒   ⊢ (𝜑 → (𝑋 ∈ 𝑃 ↔ (𝐾‘{𝑋}) ∈ (PrmIdeal‘𝑅)))
Theorem	rprmndvdsr1 33479	A ring prime element does not divide the ring multiplicative identity. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 1 = (1r‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    ⇒   ⊢ (𝜑 → ¬ 𝑄 ∥ 1 )
Theorem	rprmasso 33480	In an integral domain, the associate of a prime is a prime. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝑋 ∈ 𝑃)    &   ⊢ (𝜑 → 𝑋 ∥ 𝑌)    &   ⊢ (𝜑 → 𝑌 ∥ 𝑋)    ⇒   ⊢ (𝜑 → 𝑌 ∈ 𝑃)
Theorem	rprmasso2 33481	In an integral domain, if a prime element divides another, they are associates. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝑋 ∈ 𝑃)    &   ⊢ (𝜑 → 𝑋 ∥ 𝑌)    &   ⊢ (𝜑 → 𝑌 ∈ 𝑃)    ⇒   ⊢ (𝜑 → 𝑌 ∥ 𝑋)
Theorem	rprmasso3 33482*	In an integral domain, if a prime element divides another, they are associates. (Contributed by Thierry Arnoux, 27-May-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝑋 ∈ 𝑃)    &   ⊢ (𝜑 → 𝑋 ∥ 𝑌)    &   ⊢ (𝜑 → 𝑌 ∈ 𝑃)    &   ⊢ · = (.r‘𝑅)    &   ⊢ 𝑈 = (Unit‘𝑅)    ⇒   ⊢ (𝜑 → ∃𝑡 ∈ 𝑈 (𝑡 · 𝑋) = 𝑌)
Theorem	unitmulrprm 33483	A ring unit multiplied by a ring prime is a ring prime. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ · = (.r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝐼 ∈ 𝑈)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    ⇒   ⊢ (𝜑 → (𝐼 · 𝑄) ∈ 𝑃)
Theorem	rprmndvdsru 33484	A ring prime element does not divide any ring unit. (Contributed by Thierry Arnoux, 27-May-2025.)
⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    &   ⊢ (𝜑 → 𝑇 ∈ 𝑈)    ⇒   ⊢ (𝜑 → ¬ 𝑄 ∥ 𝑇)
Theorem	rprmirredlem 33485	Lemma for rprmirred 33486. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ · = (.r‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝑄 ≠ 0 )    &   ⊢ (𝜑 → 𝑋 ∈ (𝐵 ∖ 𝑈))    &   ⊢ (𝜑 → 𝑌 ∈ 𝐵)    &   ⊢ (𝜑 → 𝑄 = (𝑋 · 𝑌))    &   ⊢ (𝜑 → 𝑄 ∥ 𝑋)    ⇒   ⊢ (𝜑 → 𝑌 ∈ 𝑈)
Theorem	rprmirred 33486	In an integral domain, ring primes are irreducible. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝐼 = (Irred‘𝑅)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    ⇒   ⊢ (𝜑 → 𝑄 ∈ 𝐼)
Theorem	rprmirredb 33487	In a principal ideal domain, the converse of rprmirred 33486 holds, i.e. irreducible elements are prime. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝐼 = (Irred‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ PID)    ⇒   ⊢ (𝜑 → 𝐼 = 𝑃)
Theorem	rprmdvdspow 33488	If a prime element divides a ring "power", it divides the term. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ 𝑀 = (mulGrp‘𝑅)    &   ⊢ ↑ = (.g‘𝑀)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐵)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    &   ⊢ (𝜑 → 𝑁 ∈ ℕ0)    &   ⊢ (𝜑 → 𝑄 ∥ (𝑁 ↑ 𝑋))    ⇒   ⊢ (𝜑 → 𝑄 ∥ 𝑋)
Theorem	rprmdvdsprod 33489*	If a prime element 𝑄 divides a product, then it divides one term. (Contributed by Thierry Arnoux, 18-May-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ ∥ = (∥r‘𝑅)    &   ⊢ 1 = (1r‘𝑅)    &   ⊢ 𝑀 = (mulGrp‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    &   ⊢ (𝜑 → 𝐼 ∈ 𝑉)    &   ⊢ (𝜑 → 𝐹 finSupp 1 )    &   ⊢ (𝜑 → 𝐹:𝐼⟶𝐵)    &   ⊢ (𝜑 → 𝑄 ∥ (𝑀 Σg 𝐹))    ⇒   ⊢ (𝜑 → ∃𝑥 ∈ (𝐹 supp 1 )𝑄 ∥ (𝐹‘𝑥))
Theorem	1arithidomlem1 33490*	Lemma for 1arithidom 33492. (Contributed by Thierry Arnoux, 30-May-2025.)
⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝑀 = (mulGrp‘𝑅)    &   ⊢ · = (.r‘𝑅)    &   ⊢ 𝐽 = (0..^(♯‘𝐹))    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝐹 ∈ Word 𝑃)    &   ⊢ (𝜑 → 𝐺 ∈ Word 𝑃)    &   ⊢ (𝜑 → (𝑀 Σg 𝐹) = (𝑀 Σg 𝐺))    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    &   ⊢ (𝜑 → ∀𝑔 ∈ Word 𝑃(∃𝑘 ∈ 𝑈 (𝑀 Σg 𝐹) = (𝑘 · (𝑀 Σg 𝑔)) → ∃𝑤∃𝑢 ∈ (𝑈 ↑m (0..^(♯‘𝐹)))(𝑤:(0..^(♯‘𝐹))–1-1-onto→(0..^(♯‘𝐹)) ∧ 𝑔 = (𝑢 ∘f · (𝐹 ∘ 𝑤)))))    &   ⊢ (𝜑 → 𝐻 ∈ Word 𝑃)    &   ⊢ (𝜑 → ∃𝑘 ∈ 𝑈 (𝑀 Σg (𝐹 ++ ⟨“𝑄”⟩)) = (𝑘 · (𝑀 Σg 𝐻)))    &   ⊢ (𝜑 → 𝐾 ∈ (0..^(♯‘𝐻)))    &   ⊢ (𝜑 → 𝑄(∥r‘𝑅)(𝐻‘𝐾))    &   ⊢ (𝜑 → 𝑇 ∈ 𝑈)    &   ⊢ (𝜑 → (𝑇 · 𝑄) = (𝐻‘𝐾))    &   ⊢ (𝜑 → 𝑆:(0..^(♯‘𝐻))–1-1-onto→(0..^(♯‘𝐻)))    &   ⊢ (𝜑 → (𝐻 ∘ 𝑆) = (((𝐻 ∘ 𝑆) prefix ((♯‘𝐻) − 1)) ++ ⟨“(𝐻‘𝐾)”⟩))    &   ⊢ (𝜑 → 𝑁 ∈ 𝑈)    &   ⊢ (𝜑 → (𝑀 Σg (𝐹 ++ ⟨“𝑄”⟩)) = (𝑁 · (𝑀 Σg 𝐻)))    ⇒   ⊢ (𝜑 → ∃𝑐∃𝑑 ∈ (𝑈 ↑m (0..^(♯‘𝐹)))(𝑐:(0..^(♯‘𝐹))–1-1-onto→(0..^(♯‘𝐹)) ∧ ((𝐻 ∘ 𝑆) prefix ((♯‘𝐻) − 1)) = (𝑑 ∘f · (𝐹 ∘ 𝑐))))
Theorem	1arithidomlem2 33491*	Lemma for 1arithidom 33492: induction step. (Contributed by Thierry Arnoux, 27-May-2025.)
⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝑀 = (mulGrp‘𝑅)    &   ⊢ · = (.r‘𝑅)    &   ⊢ 𝐽 = (0..^(♯‘𝐹))    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝐹 ∈ Word 𝑃)    &   ⊢ (𝜑 → 𝐺 ∈ Word 𝑃)    &   ⊢ (𝜑 → (𝑀 Σg 𝐹) = (𝑀 Σg 𝐺))    &   ⊢ (𝜑 → 𝑄 ∈ 𝑃)    &   ⊢ (𝜑 → ∀𝑔 ∈ Word 𝑃(∃𝑘 ∈ 𝑈 (𝑀 Σg 𝐹) = (𝑘 · (𝑀 Σg 𝑔)) → ∃𝑤∃𝑢 ∈ (𝑈 ↑m (0..^(♯‘𝐹)))(𝑤:(0..^(♯‘𝐹))–1-1-onto→(0..^(♯‘𝐹)) ∧ 𝑔 = (𝑢 ∘f · (𝐹 ∘ 𝑤)))))    &   ⊢ (𝜑 → 𝐻 ∈ Word 𝑃)    &   ⊢ (𝜑 → ∃𝑘 ∈ 𝑈 (𝑀 Σg (𝐹 ++ ⟨“𝑄”⟩)) = (𝑘 · (𝑀 Σg 𝐻)))    &   ⊢ (𝜑 → 𝐾 ∈ (0..^(♯‘𝐻)))    &   ⊢ (𝜑 → 𝑄(∥r‘𝑅)(𝐻‘𝐾))    &   ⊢ (𝜑 → 𝑇 ∈ 𝑈)    &   ⊢ (𝜑 → (𝑇 · 𝑄) = (𝐻‘𝐾))    &   ⊢ (𝜑 → 𝑆:(0..^(♯‘𝐻))–1-1-onto→(0..^(♯‘𝐻)))    &   ⊢ (𝜑 → (𝐻 ∘ 𝑆) = (((𝐻 ∘ 𝑆) prefix ((♯‘𝐻) − 1)) ++ ⟨“(𝐻‘𝐾)”⟩))    &   ⊢ (𝜑 → 𝑁 ∈ 𝑈)    &   ⊢ (𝜑 → (𝑀 Σg (𝐹 ++ ⟨“𝑄”⟩)) = (𝑁 · (𝑀 Σg 𝐻)))    &   ⊢ (𝜑 → 𝐷 ∈ (𝑈 ↑m (0..^(♯‘𝐹))))    &   ⊢ (𝜑 → 𝐶:(0..^(♯‘𝐹))–1-1-onto→(0..^(♯‘𝐹)))    &   ⊢ (𝜑 → ((𝐻 ∘ 𝑆) prefix ((♯‘𝐻) − 1)) = (𝐷 ∘f · (𝐹 ∘ 𝐶)))    ⇒   ⊢ (𝜑 → (((𝐶 ++ ⟨“(♯‘𝐹)”⟩) ∘ ◡𝑆):(0..^(♯‘(𝐹 ++ ⟨“𝑄”⟩)))–1-1-onto→(0..^(♯‘(𝐹 ++ ⟨“𝑄”⟩))) ∧ 𝐻 = (((𝐷 ++ ⟨“𝑇”⟩) ∘ ◡𝑆) ∘f · ((𝐹 ++ ⟨“𝑄”⟩) ∘ ((𝐶 ++ ⟨“(♯‘𝐹)”⟩) ∘ ◡𝑆)))))
Theorem	1arithidom 33492*	Uniqueness of prime factorizations in an integral domain 𝑅. Given two equal products 𝐹 and 𝐺 of prime elements, 𝐹 and 𝐺 are equal up to a renumbering 𝑤 and a multiplication by units 𝑢. See also 1arith 16831. Chapter VII, Paragraph 3, Section 3, Proposition 2 of [BourbakiCAlg2], p. 228. (Contributed by Thierry Arnoux, 27-May-2025.)
⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝑀 = (mulGrp‘𝑅)    &   ⊢ · = (.r‘𝑅)    &   ⊢ 𝐽 = (0..^(♯‘𝐹))    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝐹 ∈ Word 𝑃)    &   ⊢ (𝜑 → 𝐺 ∈ Word 𝑃)    &   ⊢ (𝜑 → (𝑀 Σg 𝐹) = (𝑀 Σg 𝐺))    ⇒   ⊢ (𝜑 → ∃𝑤∃𝑢 ∈ (𝑈 ↑m 𝐽)(𝑤:𝐽–1-1-onto→𝐽 ∧ 𝐺 = (𝑢 ∘f · (𝐹 ∘ 𝑤))))
21.3.10.43  Unique factorization domains
Syntax	cufd 33493	Class of unique factorization domains.
class UFD
Definition	df-ufd 33494*	Define the class of unique factorization domains. A unique factorization domain (UFD for short), is an integral domain such that every nonzero prime ideal contains a prime element (this is a characterization due to Irving Kaplansky). A UFD is sometimes also called a "factorial ring" following the terminology of Bourbaki. (Contributed by Mario Carneiro, 17-Feb-2015.) Exclude the 0 prime ideal. (Revised by Thierry Arnoux, 9-May-2025.) Exclude the 0 ring. (Revised by Thierry Arnoux, 14-Jun-2025.)
⊢ UFD = {𝑟 ∈ IDomn ∣ ∀𝑖 ∈ ((PrmIdeal‘𝑟) ∖ {{(0g‘𝑟)}})(𝑖 ∩ (RPrime‘𝑟)) ≠ ∅}
Theorem	isufd 33495*	The property of being a Unique Factorization Domain. (Contributed by Thierry Arnoux, 1-Jun-2024.)
⊢ 𝐼 = (PrmIdeal‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    ⇒   ⊢ (𝑅 ∈ UFD ↔ (𝑅 ∈ IDomn ∧ ∀𝑖 ∈ (𝐼 ∖ {{ 0 }})(𝑖 ∩ 𝑃) ≠ ∅))
Theorem	ufdprmidl 33496*	In a unique factorization domain 𝑅, a nonzero prime ideal 𝐽 contains a prime element 𝑝. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 𝐼 = (PrmIdeal‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ UFD)    &   ⊢ (𝜑 → 𝐽 ∈ 𝐼)    &   ⊢ (𝜑 → 𝐽 ≠ { 0 })    ⇒   ⊢ (𝜑 → ∃𝑝 ∈ 𝑃 𝑝 ∈ 𝐽)
Theorem	ufdidom 33497	A nonzero unique factorization domain is an integral domain. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ (𝜑 → 𝑅 ∈ UFD)    ⇒   ⊢ (𝜑 → 𝑅 ∈ IDomn)
Theorem	pidufd 33498	Every principal ideal domain is a unique factorization domain. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ (𝜑 → 𝑅 ∈ PID)    ⇒   ⊢ (𝜑 → 𝑅 ∈ UFD)
Theorem	1arithufdlem1 33499*	Lemma for 1arithufd 33503. The set 𝑆 of elements which can be written as a product of primes is not empty. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝑀 = (mulGrp‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ UFD)    &   ⊢ (𝜑 → ¬ 𝑅 ∈ DivRing)    &   ⊢ 𝑆 = {𝑥 ∈ 𝐵 ∣ ∃𝑓 ∈ Word 𝑃𝑥 = (𝑀 Σg 𝑓)}    ⇒   ⊢ (𝜑 → 𝑆 ≠ ∅)
Theorem	1arithufdlem2 33500*	Lemma for 1arithufd 33503. The set 𝑆 of elements which can be written as a product of primes is multiplicatively closed. (Contributed by Thierry Arnoux, 3-Jun-2025.)
⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ 𝑈 = (Unit‘𝑅)    &   ⊢ 𝑃 = (RPrime‘𝑅)    &   ⊢ 𝑀 = (mulGrp‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ UFD)    &   ⊢ (𝜑 → ¬ 𝑅 ∈ DivRing)    &   ⊢ 𝑆 = {𝑥 ∈ 𝐵 ∣ ∃𝑓 ∈ Word 𝑃𝑥 = (𝑀 Σg 𝑓)}    &   ⊢ · = (.r‘𝑅)    &   ⊢ (𝜑 → 𝑋 ∈ 𝑆)    &   ⊢ (𝜑 → 𝑌 ∈ 𝑆)    ⇒   ⊢ (𝜑 → (𝑋 · 𝑌) ∈ 𝑆)