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Theorem List for Metamath Proof Explorer - 40201-40300   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremevlsmulval 40201 Polynomial evaluation builder for multiplication. (Contributed by SN, 27-Jul-2024.)
𝑄 = ((𝐼 evalSub 𝑆)‘𝑅)    &   𝑃 = (𝐼 mPoly 𝑈)    &   𝑈 = (𝑆s 𝑅)    &   𝐾 = (Base‘𝑆)    &   𝐵 = (Base‘𝑃)    &   (𝜑𝐼𝑍)    &   (𝜑𝑆 ∈ CRing)    &   (𝜑𝑅 ∈ (SubRing‘𝑆))    &   (𝜑𝐴 ∈ (𝐾m 𝐼))    &   (𝜑 → (𝑀𝐵 ∧ ((𝑄𝑀)‘𝐴) = 𝑉))    &   (𝜑 → (𝑁𝐵 ∧ ((𝑄𝑁)‘𝐴) = 𝑊))    &    = (.r𝑃)    &    · = (.r𝑆)       (𝜑 → ((𝑀 𝑁) ∈ 𝐵 ∧ ((𝑄‘(𝑀 𝑁))‘𝐴) = (𝑉 · 𝑊)))
 
Theoremfsuppind 40202* Induction on functions 𝐹:𝐴𝐵 with finite support, or in other words the base set of the free module (see frlmelbas 20873 and frlmplusgval 20881). This theorem is structurally general for polynomial proof usage (see mplelbas 21109 and mpladd 21123). Note that hypothesis 0 is redundant when 𝐼 is nonempty. (Contributed by SN, 18-May-2024.)
𝐵 = (Base‘𝐺)    &    0 = (0g𝐺)    &    + = (+g𝐺)    &   (𝜑𝐺 ∈ Grp)    &   (𝜑𝐼𝑉)    &   (𝜑 → (𝐼 × { 0 }) ∈ 𝐻)    &   ((𝜑 ∧ (𝑎𝐼𝑏𝐵)) → (𝑥𝐼 ↦ if(𝑥 = 𝑎, 𝑏, 0 )) ∈ 𝐻)    &   ((𝜑 ∧ (𝑥𝐻𝑦𝐻)) → (𝑥f + 𝑦) ∈ 𝐻)       ((𝜑 ∧ (𝑋:𝐼𝐵𝑋 finSupp 0 )) → 𝑋𝐻)
 
Theoremfsuppssindlem1 40203* Lemma for fsuppssind 40205. Functions are zero outside of their support. (Contributed by SN, 15-Jul-2024.)
(𝜑0𝑊)    &   (𝜑𝐼𝑉)    &   (𝜑𝐹:𝐼𝐵)    &   (𝜑 → (𝐹 supp 0 ) ⊆ 𝑆)       (𝜑𝐹 = (𝑥𝐼 ↦ if(𝑥𝑆, ((𝐹𝑆)‘𝑥), 0 )))
 
Theoremfsuppssindlem2 40204* Lemma for fsuppssind 40205. Write a function as a union. (Contributed by SN, 15-Jul-2024.)
(𝜑𝐵𝑊)    &   (𝜑𝐼𝑉)    &   (𝜑𝑆𝐼)       (𝜑 → (𝐹 ∈ {𝑓 ∈ (𝐵m 𝑆) ∣ (𝑥𝐼 ↦ if(𝑥𝑆, (𝑓𝑥), 0 )) ∈ 𝐻} ↔ (𝐹:𝑆𝐵 ∧ (𝐹 ∪ ((𝐼𝑆) × { 0 })) ∈ 𝐻)))
 
Theoremfsuppssind 40205* Induction on functions 𝐹:𝐴𝐵 with finite support (see fsuppind 40202) whose supports are subsets of 𝑆. (Contributed by SN, 15-Jun-2024.)
𝐵 = (Base‘𝐺)    &    0 = (0g𝐺)    &    + = (+g𝐺)    &   (𝜑𝐺 ∈ Grp)    &   (𝜑𝐼𝑉)    &   (𝜑𝑆𝐼)    &   (𝜑 → (𝐼 × { 0 }) ∈ 𝐻)    &   ((𝜑 ∧ (𝑎𝑆𝑏𝐵)) → (𝑠𝐼 ↦ if(𝑠 = 𝑎, 𝑏, 0 )) ∈ 𝐻)    &   ((𝜑 ∧ (𝑥𝐻𝑦𝐻)) → (𝑥f + 𝑦) ∈ 𝐻)    &   (𝜑𝑋:𝐼𝐵)    &   (𝜑𝑋 finSupp 0 )    &   (𝜑 → (𝑋 supp 0 ) ⊆ 𝑆)       (𝜑𝑋𝐻)
 
Theoremmhpind 40206* The homogeneous polynomials of degree 𝑁 are generated by the terms of degree 𝑁 and addition. (Contributed by SN, 28-Jul-2024.)
𝐻 = (𝐼 mHomP 𝑅)    &   𝐵 = (Base‘𝑅)    &    0 = (0g𝑅)    &   𝑃 = (𝐼 mPoly 𝑅)    &    + = (+g𝑃)    &   𝐷 = { ∈ (ℕ0m 𝐼) ∣ ( “ ℕ) ∈ Fin}    &   𝑆 = {𝑔𝐷 ∣ ((ℂflds0) Σg 𝑔) = 𝑁}    &   (𝜑𝐼𝑉)    &   (𝜑𝑅 ∈ Grp)    &   (𝜑𝑁 ∈ ℕ0)    &   (𝜑𝑋 ∈ (𝐻𝑁))    &   (𝜑 → (𝐷 × { 0 }) ∈ 𝐺)    &   ((𝜑 ∧ (𝑎𝑆𝑏𝐵)) → (𝑠𝐷 ↦ if(𝑠 = 𝑎, 𝑏, 0 )) ∈ 𝐺)    &   ((𝜑 ∧ (𝑥 ∈ ((𝐻𝑁) ∩ 𝐺) ∧ 𝑦 ∈ ((𝐻𝑁) ∩ 𝐺))) → (𝑥 + 𝑦) ∈ 𝐺)       (𝜑𝑋𝐺)
 
Theoremmhphflem 40207* Lemma for mhphf 40208. Add several multiples of 𝐿 together, in a case where the total amount of multiplies is 𝑁. (Contributed by SN, 30-Jul-2024.)
𝐷 = { ∈ (ℕ0m 𝐼) ∣ ( “ ℕ) ∈ Fin}    &   𝐻 = {𝑔𝐷 ∣ ((ℂflds0) Σg 𝑔) = 𝑁}    &   𝐵 = (Base‘𝐺)    &    · = (.g𝐺)    &   (𝜑𝐼𝑉)    &   (𝜑𝐺 ∈ Mnd)    &   (𝜑𝐿𝐵)    &   (𝜑𝑁 ∈ ℕ0)       ((𝜑𝑎𝐻) → (𝐺 Σg (𝑣𝐼 ↦ ((𝑎𝑣) · 𝐿))) = (𝑁 · 𝐿))
 
Theoremmhphf 40208 A homogeneous polynomial defines a homogeneous function. Equivalently, an algebraic form is a homogeneous function. (An algebraic form is the function corresponding to a homogeneous polynomial, which in this case is the (𝑄𝑋) which corresponds to 𝑋). (Contributed by SN, 28-Jul-2024.)
𝑄 = ((𝐼 evalSub 𝑆)‘𝑅)    &   𝐻 = (𝐼 mHomP 𝑈)    &   𝑈 = (𝑆s 𝑅)    &   𝐾 = (Base‘𝑆)    &    · = (.r𝑆)    &    = (.g‘(mulGrp‘𝑆))    &   (𝜑𝐼𝑉)    &   (𝜑𝑆 ∈ CRing)    &   (𝜑𝑅 ∈ (SubRing‘𝑆))    &   (𝜑𝐿𝑅)    &   (𝜑𝑁 ∈ ℕ0)    &   (𝜑𝑋 ∈ (𝐻𝑁))    &   (𝜑𝐴 ∈ (𝐾m 𝐼))       (𝜑 → ((𝑄𝑋)‘((𝐼 × {𝐿}) ∘f · 𝐴)) = ((𝑁 𝐿) · ((𝑄𝑋)‘𝐴)))
 
Theoremmhphf2 40209 A homogeneous polynomial defines a homogeneous function; this is mhphf 40208 with simpler notation in the conclusion in exchange for a complex definition of , which is based on frlmvscafval 20883 but without the finite support restriction (frlmpws 20867, frlmbas 20872) on the assignments 𝐴 from variables to values.

TODO?: Polynomials (df-mpl 21024) are defined to have a finite amount of terms (of finite degree). As such, any assignment may be replaced by an assignment with finite support (as only a finite amount of variables matter in a given polynomial, even if the set of variables is infinite). So the finite support restriction can be assumed without loss of generality. (Contributed by SN, 11-Nov-2024.)

𝑄 = ((𝐼 evalSub 𝑆)‘𝑅)    &   𝐻 = (𝐼 mHomP 𝑈)    &   𝑈 = (𝑆s 𝑅)    &   𝐾 = (Base‘𝑆)    &    = ( ·𝑠 ‘((ringLMod‘𝑆) ↑s 𝐼))    &    · = (.r𝑆)    &    = (.g‘(mulGrp‘𝑆))    &   (𝜑𝐼𝑉)    &   (𝜑𝑆 ∈ CRing)    &   (𝜑𝑅 ∈ (SubRing‘𝑆))    &   (𝜑𝐿𝑅)    &   (𝜑𝑁 ∈ ℕ0)    &   (𝜑𝑋 ∈ (𝐻𝑁))    &   (𝜑𝐴 ∈ (𝐾m 𝐼))       (𝜑 → ((𝑄𝑋)‘(𝐿 𝐴)) = ((𝑁 𝐿) · ((𝑄𝑋)‘𝐴)))
 
20.26.4  Arithmetic theorems

Towards the start of this section are several proofs regarding the different complex number axioms that could be used to prove some results.

For example, ax-1rid 10872 is used in mulid1 10904 related theorems, so one could trade off the extra axioms in mulid1 10904 for the axioms needed to prove that something is a real number. Another example is avoiding complex number closure laws by using real number closure laws and then using ax-resscn 10859; in the other direction, real number closure laws can be avoided by using ax-resscn 10859 and then the complex number closure laws. (This only works if the result of (𝐴 + 𝐵) only needs to be a complex number).

The natural numbers are especially amenable to axiom reductions, as the set is the recursive set {1, (1 + 1), ((1 + 1) + 1)}, etc., i.e. the set of numbers formed by only additions of 1. The digits 2 through 9 are defined so that they expand into additions of 1. This makes adding natural numbers conveniently only require the rearrangement of parentheses, as shown with the following:

(4 + 3) = 7

((3 + 1) + (2 + 1)) = (6 + 1)

((((1 + 1) + 1) + 1) + ((1 + 1) + 1)) =

((((((1 + 1) + 1) + 1) + 1) + 1) + 1)

This only requires ax-addass 10867, ax-1cn 10860, and ax-addcl 10862. (And in practice, the expression isn't completely expanded into ones.)

Multiplication by 1 requires either mulid2i 10911 or (ax-1rid 10872 and 1re 10906) as seen in 1t1e1 12065 and 1t1e1ALT 40213. Multiplying with greater natural numbers uses ax-distr 10869. Still, this takes fewer axioms than adding zero, which is often implicit in theorems such as (9 + 1) = 10. Adding zero uses almost every complex number axiom, though notably not ax-mulcom 10866 (see readdid1 40313 and readdid2 40307).

 
Theoremc0exALT 40210 Alternate proof of c0ex 10900 using more set theory axioms but fewer complex number axioms (add ax-10 2139, ax-11 2156, ax-13 2372, ax-nul 5225, and remove ax-1cn 10860, ax-icn 10861, ax-addcl 10862, and ax-mulcl 10864). (Contributed by Steven Nguyen, 4-Dec-2022.) (Proof modification is discouraged.) (New usage is discouraged.)
0 ∈ V
 
Theorem0cnALT3 40211 Alternate proof of 0cn 10898 using ax-resscn 10859, ax-addrcl 10863, ax-rnegex 10873, ax-cnre 10875 instead of ax-icn 10861, ax-addcl 10862, ax-mulcl 10864, ax-i2m1 10870. Version of 0cnALT 11139 using ax-1cn 10860 instead of ax-icn 10861. (Contributed by Steven Nguyen, 7-Jan-2022.) (Proof modification is discouraged.) (New usage is discouraged.)
0 ∈ ℂ
 
Theoremelre0re 40212 Specialized version of 0red 10909 without using ax-1cn 10860 and ax-cnre 10875. (Contributed by Steven Nguyen, 28-Jan-2023.)
(𝐴 ∈ ℝ → 0 ∈ ℝ)
 
Theorem1t1e1ALT 40213 Alternate proof of 1t1e1 12065 using a different set of axioms (add ax-mulrcl 10865, ax-i2m1 10870, ax-1ne0 10871, ax-rrecex 10874 and remove ax-resscn 10859, ax-mulcom 10866, ax-mulass 10868, ax-distr 10869). (Contributed by Steven Nguyen, 20-Sep-2022.) (Proof modification is discouraged.) (New usage is discouraged.)
(1 · 1) = 1
 
Theoremremulcan2d 40214 mulcan2d 11539 for real numbers using fewer axioms. (Contributed by Steven Nguyen, 15-Apr-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐶 ≠ 0)       (𝜑 → ((𝐴 · 𝐶) = (𝐵 · 𝐶) ↔ 𝐴 = 𝐵))
 
Theoremreaddid1addid2d 40215 Given some real number 𝐵 where 𝐴 acts like a right additive identity, derive that 𝐴 is a left additive identity. Note that the hypothesis is weaker than proving that 𝐴 is a right additive identity (for all numbers). Although, if there is a right additive identity, then by readdcan 11079, 𝐴 is the right additive identity. (Contributed by Steven Nguyen, 14-Jan-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → (𝐵 + 𝐴) = 𝐵)       ((𝜑𝐶 ∈ ℝ) → (𝐴 + 𝐶) = 𝐶)
 
Theoremsn-1ne2 40216 A proof of 1ne2 12111 without using ax-mulcom 10866, ax-mulass 10868, ax-pre-mulgt0 10879. Based on mul02lem2 11082. (Contributed by SN, 13-Dec-2023.)
1 ≠ 2
 
Theoremnnn1suc 40217* A positive integer that is not 1 is a successor of some other positive integer. (Contributed by Steven Nguyen, 19-Aug-2023.)
((𝐴 ∈ ℕ ∧ 𝐴 ≠ 1) → ∃𝑥 ∈ ℕ (𝑥 + 1) = 𝐴)
 
Theoremnnadd1com 40218 Addition with 1 is commutative for natural numbers. (Contributed by Steven Nguyen, 9-Dec-2022.)
(𝐴 ∈ ℕ → (𝐴 + 1) = (1 + 𝐴))
 
Theoremnnaddcom 40219 Addition is commutative for natural numbers. Uses fewer axioms than addcom 11091. (Contributed by Steven Nguyen, 9-Dec-2022.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ) → (𝐴 + 𝐵) = (𝐵 + 𝐴))
 
Theoremnnaddcomli 40220 Version of addcomli 11097 for natural numbers. (Contributed by Steven Nguyen, 1-Aug-2023.)
𝐴 ∈ ℕ    &   𝐵 ∈ ℕ    &   (𝐴 + 𝐵) = 𝐶       (𝐵 + 𝐴) = 𝐶
 
Theoremnnadddir 40221 Right-distributivity for natural numbers without ax-mulcom 10866. (Contributed by SN, 5-Feb-2024.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ) → ((𝐴 + 𝐵) · 𝐶) = ((𝐴 · 𝐶) + (𝐵 · 𝐶)))
 
Theoremnnmul1com 40222 Multiplication with 1 is commutative for natural numbers, without ax-mulcom 10866. Since (𝐴 · 1) is 𝐴 by ax-1rid 10872, this is equivalent to remulid2 40336 for natural numbers, but using fewer axioms (avoiding ax-resscn 10859, ax-addass 10867, ax-mulass 10868, ax-rnegex 10873, ax-pre-lttri 10876, ax-pre-lttrn 10877, ax-pre-ltadd 10878). (Contributed by SN, 5-Feb-2024.)
(𝐴 ∈ ℕ → (1 · 𝐴) = (𝐴 · 1))
 
Theoremnnmulcom 40223 Multiplication is commutative for natural numbers. (Contributed by SN, 5-Feb-2024.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ) → (𝐴 · 𝐵) = (𝐵 · 𝐴))
 
Theoremmvrrsubd 40224 Move a subtraction in the RHS to a right-addition in the LHS. Converse of mvlraddd 11315. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐴 = (𝐵𝐶))       (𝜑 → (𝐴 + 𝐶) = 𝐵)
 
Theoremladdrotrd 40225 Rotate the variables right in an equation with addition on the left, converting it into a subtraction. Version of mvlladdd 11316 with a commuted consequent, and of mvrladdd 11318 with a commuted hypothesis. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑 → (𝐴 + 𝐵) = 𝐶)       (𝜑 → (𝐶𝐴) = 𝐵)
 
Theoremraddcom12d 40226 Swap the first two variables in an equation with addition on the right, converting it into a subtraction. Version of mvrraddd 11317 with a commuted consequent, and of mvlraddd 11315 with a commuted hypothesis. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐴 = (𝐵 + 𝐶))       (𝜑𝐵 = (𝐴𝐶))
 
Theoremlsubrotld 40227 Rotate the variables left in an equation with subtraction on the left, converting it into an addition. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑 → (𝐴𝐵) = 𝐶)       (𝜑 → (𝐵 + 𝐶) = 𝐴)
 
Theoremlsubcom23d 40228 Swap the second and third variables in an equation with subtraction on the left, converting it into an addition. (Contributed by SN, 23-Aug-2024.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑 → (𝐴𝐵) = 𝐶)       (𝜑 → (𝐴𝐶) = 𝐵)
 
Theoremaddsubeq4com 40229 Relation between sums and differences. (Contributed by Steven Nguyen, 5-Jan-2023.)
(((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → ((𝐴 + 𝐵) = (𝐶 + 𝐷) ↔ (𝐴𝐶) = (𝐷𝐵)))
 
Theoremsqsumi 40230 A sum squared. (Contributed by Steven Nguyen, 16-Sep-2022.)
𝐴 ∈ ℂ    &   𝐵 ∈ ℂ       ((𝐴 + 𝐵) · (𝐴 + 𝐵)) = (((𝐴 · 𝐴) + (𝐵 · 𝐵)) + (2 · (𝐴 · 𝐵)))
 
Theoremnegn0nposznnd 40231 Lemma for dffltz 40387. (Contributed by Steven Nguyen, 27-Feb-2023.)
(𝜑𝐴 ≠ 0)    &   (𝜑 → ¬ 0 < 𝐴)    &   (𝜑𝐴 ∈ ℤ)       (𝜑 → -𝐴 ∈ ℕ)
 
Theoremsqmid3api 40232 Value of the square of the middle term of a 3-term arithmetic progression. (Contributed by Steven Nguyen, 20-Sep-2022.)
𝐴 ∈ ℂ    &   𝑁 ∈ ℂ    &   (𝐴 + 𝑁) = 𝐵    &   (𝐵 + 𝑁) = 𝐶       (𝐵 · 𝐵) = ((𝐴 · 𝐶) + (𝑁 · 𝑁))
 
Theoremdecaddcom 40233 Commute ones place in addition. (Contributed by Steven Nguyen, 29-Jan-2023.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0    &   𝐶 ∈ ℕ0       (𝐴𝐵 + 𝐶) = (𝐴𝐶 + 𝐵)
 
Theoremsqn5i 40234 The square of a number ending in 5. This shortcut only works because 5 is half of 10. (Contributed by Steven Nguyen, 16-Sep-2022.)
𝐴 ∈ ℕ0       (𝐴5 · 𝐴5) = (𝐴 · (𝐴 + 1))25
 
Theoremsqn5ii 40235 The square of a number ending in 5. This shortcut only works because 5 is half of 10. (Contributed by Steven Nguyen, 16-Sep-2022.)
𝐴 ∈ ℕ0    &   (𝐴 + 1) = 𝐵    &   (𝐴 · 𝐵) = 𝐶       (𝐴5 · 𝐴5) = 𝐶25
 
Theoremdecpmulnc 40236 Partial products algorithm for two digit multiplication, no carry. Compare muladdi 11356. (Contributed by Steven Nguyen, 9-Dec-2022.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0    &   𝐶 ∈ ℕ0    &   𝐷 ∈ ℕ0    &   (𝐴 · 𝐶) = 𝐸    &   ((𝐴 · 𝐷) + (𝐵 · 𝐶)) = 𝐹    &   (𝐵 · 𝐷) = 𝐺       (𝐴𝐵 · 𝐶𝐷) = 𝐸𝐹𝐺
 
Theoremdecpmul 40237 Partial products algorithm for two digit multiplication. (Contributed by Steven Nguyen, 10-Dec-2022.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0    &   𝐶 ∈ ℕ0    &   𝐷 ∈ ℕ0    &   (𝐴 · 𝐶) = 𝐸    &   ((𝐴 · 𝐷) + (𝐵 · 𝐶)) = 𝐹    &   (𝐵 · 𝐷) = 𝐺𝐻    &   (𝐸𝐺 + 𝐹) = 𝐼    &   𝐺 ∈ ℕ0    &   𝐻 ∈ ℕ0       (𝐴𝐵 · 𝐶𝐷) = 𝐼𝐻
 
Theoremsqdeccom12 40238 The square of a number in terms of its digits switched. (Contributed by Steven Nguyen, 3-Jan-2023.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0       ((𝐴𝐵 · 𝐴𝐵) − (𝐵𝐴 · 𝐵𝐴)) = (99 · ((𝐴 · 𝐴) − (𝐵 · 𝐵)))
 
Theoremsq3deccom12 40239 Variant of sqdeccom12 40238 with a three digit square. (Contributed by Steven Nguyen, 3-Jan-2023.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0    &   𝐶 ∈ ℕ0    &   (𝐴 + 𝐶) = 𝐷       ((𝐴𝐵𝐶 · 𝐴𝐵𝐶) − (𝐷𝐵 · 𝐷𝐵)) = (99 · ((𝐴𝐵 · 𝐴𝐵) − (𝐶 · 𝐶)))
 
Theorem235t711 40240 Calculate a product by long multiplication as a base comparison with other multiplication algorithms.

Conveniently, 711 has two ones which greatly simplifies calculations like 235 · 1. There isn't a higher level mulcomli 10915 saving the lower level uses of mulcomli 10915 within 235 · 7 since mulcom2 doesn't exist, but if commuted versions of theorems like 7t2e14 12475 are added then this proof would benefit more than ex-decpmul 40241.

For practicality, this proof doesn't have "e167085" at the end of its name like 2p2e4 12038 or 8t7e56 12486. (Contributed by Steven Nguyen, 10-Dec-2022.) (New usage is discouraged.)

(235 · 711) = 167085
 
Theoremex-decpmul 40241 Example usage of decpmul 40237. This proof is significantly longer than 235t711 40240. There is more unnecessary carrying compared to 235t711 40240. Although saving 5 visual steps, using mulcomli 10915 early on increases the compressed proof length. (Contributed by Steven Nguyen, 10-Dec-2022.) (New usage is discouraged.) (Proof modification is discouraged.)
(235 · 711) = 167085
 
20.26.5  Exponents and divisibility
 
Theoremoexpreposd 40242 Lemma for dffltz 40387. TODO-SN?: This can be used to show exp11d 40246 holds for all integers when the exponent is odd. The more standard ¬ 2 ∥ 𝑀 should be used. (Contributed by SN, 4-Mar-2023.)
(𝜑𝑁 ∈ ℝ)    &   (𝜑𝑀 ∈ ℕ)    &   (𝜑 → ¬ (𝑀 / 2) ∈ ℕ)       (𝜑 → (0 < 𝑁 ↔ 0 < (𝑁𝑀)))
 
Theoremltexp1d 40243 ltmul1d 12742 for exponentiation of positive reals. (Contributed by Steven Nguyen, 22-Aug-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → (𝐴 < 𝐵 ↔ (𝐴𝑁) < (𝐵𝑁)))
 
Theoremltexp1dd 40244 Raising both sides of 'less than' to the same positive integer preserves ordering. (Contributed by Steven Nguyen, 24-Aug-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐴 < 𝐵)       (𝜑 → (𝐴𝑁) < (𝐵𝑁))
 
Theoremexp11nnd 40245 sq11d 13903 for positive real bases and positive integer exponents. The base cannot be generalized much further, since if 𝑁 is even then we have 𝐴𝑁 = -𝐴𝑁. (Contributed by SN, 14-Sep-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑 → (𝐴𝑁) = (𝐵𝑁))       (𝜑𝐴 = 𝐵)
 
Theoremexp11d 40246 exp11nnd 40245 for nonzero integer exponents. (Contributed by SN, 14-Sep-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℤ)    &   (𝜑𝑁 ≠ 0)    &   (𝜑 → (𝐴𝑁) = (𝐵𝑁))       (𝜑𝐴 = 𝐵)
 
Theorem0dvds0 40247 0 divides 0. (Contributed by SN, 15-Sep-2024.)
0 ∥ 0
 
Theoremabsdvdsabsb 40248 Divisibility is invariant under taking the absolute value on both sides. (Contributed by SN, 15-Sep-2024.)
((𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ) → (𝑀𝑁 ↔ (abs‘𝑀) ∥ (abs‘𝑁)))
 
Theoremdvdsexpim 40249 dvdssqim 16192 generalized to nonnegative exponents. (Contributed by Steven Nguyen, 2-Apr-2023.)
((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ∧ 𝑁 ∈ ℕ0) → (𝐴𝐵 → (𝐴𝑁) ∥ (𝐵𝑁)))
 
Theoremgcdnn0id 40250 The gcd of a nonnegative integer and itself is the integer. (Contributed by SN, 25-Aug-2024.)
(𝑁 ∈ ℕ0 → (𝑁 gcd 𝑁) = 𝑁)
 
Theoremgcdle1d 40251 The greatest common divisor of a positive integer and another integer is less than or equal to the positive integer. (Contributed by SN, 25-Aug-2024.)
(𝜑𝑀 ∈ ℕ)    &   (𝜑𝑁 ∈ ℤ)       (𝜑 → (𝑀 gcd 𝑁) ≤ 𝑀)
 
Theoremgcdle2d 40252 The greatest common divisor of a positive integer and another integer is less than or equal to the positive integer. (Contributed by SN, 25-Aug-2024.)
(𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → (𝑀 gcd 𝑁) ≤ 𝑁)
 
Theoremdvdsexpad 40253 Deduction associated with dvdsexpim 40249. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐴 ∈ ℤ)    &   (𝜑𝐵 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ0)    &   (𝜑𝐴𝐵)       (𝜑 → (𝐴𝑁) ∥ (𝐵𝑁))
 
Theoremnn0rppwr 40254 If 𝐴 and 𝐵 are relatively prime, then so are 𝐴𝑁 and 𝐵𝑁. rppwr 16197 extended to nonnegative integers. Less general than rpexp12i 16357. (Contributed by Steven Nguyen, 4-Apr-2023.)
((𝐴 ∈ ℕ0𝐵 ∈ ℕ0𝑁 ∈ ℕ0) → ((𝐴 gcd 𝐵) = 1 → ((𝐴𝑁) gcd (𝐵𝑁)) = 1))
 
Theoremexpgcd 40255 Exponentiation distributes over GCD. sqgcd 16198 extended to nonnegative exponents. (Contributed by Steven Nguyen, 4-Apr-2023.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝑁 ∈ ℕ0) → ((𝐴 gcd 𝐵)↑𝑁) = ((𝐴𝑁) gcd (𝐵𝑁)))
 
Theoremnn0expgcd 40256 Exponentiation distributes over GCD. nn0gcdsq 16384 extended to nonnegative exponents. expgcd 40255 extended to nonnegative bases. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℕ0𝐵 ∈ ℕ0𝑁 ∈ ℕ0) → ((𝐴 gcd 𝐵)↑𝑁) = ((𝐴𝑁) gcd (𝐵𝑁)))
 
Theoremzexpgcd 40257 Exponentiation distributes over GCD. zgcdsq 16385 extended to nonnegative exponents. nn0expgcd 40256 extended to integer bases by symmetry. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ∧ 𝑁 ∈ ℕ0) → ((𝐴 gcd 𝐵)↑𝑁) = ((𝐴𝑁) gcd (𝐵𝑁)))
 
Theoremnumdenexp 40258 numdensq 16386 extended to nonnegative exponents. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℚ ∧ 𝑁 ∈ ℕ0) → ((numer‘(𝐴𝑁)) = ((numer‘𝐴)↑𝑁) ∧ (denom‘(𝐴𝑁)) = ((denom‘𝐴)↑𝑁)))
 
Theoremnumexp 40259 numsq 16387 extended to nonnegative exponents. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℚ ∧ 𝑁 ∈ ℕ0) → (numer‘(𝐴𝑁)) = ((numer‘𝐴)↑𝑁))
 
Theoremdenexp 40260 densq 16388 extended to nonnegative exponents. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℚ ∧ 𝑁 ∈ ℕ0) → (denom‘(𝐴𝑁)) = ((denom‘𝐴)↑𝑁))
 
Theoremdvdsexpnn 40261 dvdssqlem 16199 generalized to positive integer exponents. (Contributed by SN, 20-Aug-2024.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝑁 ∈ ℕ) → (𝐴𝐵 ↔ (𝐴𝑁) ∥ (𝐵𝑁)))
 
Theoremdvdsexpnn0 40262 dvdsexpnn 40261 generalized to include zero bases. (Contributed by SN, 15-Sep-2024.)
((𝐴 ∈ ℕ0𝐵 ∈ ℕ0𝑁 ∈ ℕ) → (𝐴𝐵 ↔ (𝐴𝑁) ∥ (𝐵𝑁)))
 
Theoremdvdsexpb 40263 dvdssq 16200 generalized to positive integer exponents. (Contributed by SN, 15-Sep-2024.)
((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ∧ 𝑁 ∈ ℕ) → (𝐴𝐵 ↔ (𝐴𝑁) ∥ (𝐵𝑁)))
 
Theoremposqsqznn 40264 When a positive rational squared is an integer, the rational is a positive integer. zsqrtelqelz 16390 with all terms squared and positive. (Contributed by SN, 23-Aug-2024.)
(𝜑 → (𝐴↑2) ∈ ℤ)    &   (𝜑𝐴 ∈ ℚ)    &   (𝜑 → 0 < 𝐴)       (𝜑𝐴 ∈ ℕ)
 
Theoremcxpgt0d 40265 A positive real raised to a real power is positive. (Contributed by SN, 6-Apr-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℝ)       (𝜑 → 0 < (𝐴𝑐𝑁))
 
Theoremzrtelqelz 40266 zsqrtelqelz 16390 generalized to positive integer roots. (Contributed by Steven Nguyen, 6-Apr-2023.)
((𝐴 ∈ ℤ ∧ 𝑁 ∈ ℕ ∧ (𝐴𝑐(1 / 𝑁)) ∈ ℚ) → (𝐴𝑐(1 / 𝑁)) ∈ ℤ)
 
Theoremzrtdvds 40267 A positive integer root divides its integer. (Contributed by Steven Nguyen, 6-Apr-2023.)
((𝐴 ∈ ℤ ∧ 𝑁 ∈ ℕ ∧ (𝐴𝑐(1 / 𝑁)) ∈ ℕ) → (𝐴𝑐(1 / 𝑁)) ∥ 𝐴)
 
Theoremrtprmirr 40268 The root of a prime number is irrational. (Contributed by Steven Nguyen, 6-Apr-2023.)
((𝑃 ∈ ℙ ∧ 𝑁 ∈ (ℤ‘2)) → (𝑃𝑐(1 / 𝑁)) ∈ (ℝ ∖ ℚ))
 
20.26.6  Real subtraction
 
Syntaxcresub 40269 Real number subtraction.
class
 
Definitiondf-resub 40270* Define subtraction between real numbers. This operator saves a few axioms over df-sub 11137 in certain situations. Theorem resubval 40271 shows its value, resubadd 40283 relates it to addition, and rersubcl 40282 proves its closure. It is the restriction of df-sub 11137 to the reals: subresre 40333. (Contributed by Steven Nguyen, 7-Jan-2023.)
= (𝑥 ∈ ℝ, 𝑦 ∈ ℝ ↦ (𝑧 ∈ ℝ (𝑦 + 𝑧) = 𝑥))
 
Theoremresubval 40271* Value of real subtraction, which is the (unique) real 𝑥 such that 𝐵 + 𝑥 = 𝐴. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 𝐵) = (𝑥 ∈ ℝ (𝐵 + 𝑥) = 𝐴))
 
Theoremrenegeulemv 40272* Lemma for renegeu 40274 and similar. Derive existential uniqueness from existence. (Contributed by Steven Nguyen, 28-Jan-2023.)
(𝜑𝐵 ∈ ℝ)    &   (𝜑 → ∃𝑦 ∈ ℝ (𝐵 + 𝑦) = 𝐴)       (𝜑 → ∃!𝑥 ∈ ℝ (𝐵 + 𝑥) = 𝐴)
 
Theoremrenegeulem 40273* Lemma for renegeu 40274 and similar. Remove a change in bound variables from renegeulemv 40272. (Contributed by Steven Nguyen, 28-Jan-2023.)
(𝜑𝐵 ∈ ℝ)    &   (𝜑 → ∃𝑦 ∈ ℝ (𝐵 + 𝑦) = 𝐴)       (𝜑 → ∃!𝑦 ∈ ℝ (𝐵 + 𝑦) = 𝐴)
 
Theoremrenegeu 40274* Existential uniqueness of real negatives. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → ∃!𝑥 ∈ ℝ (𝐴 + 𝑥) = 0)
 
Theoremrernegcl 40275 Closure law for negative reals. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → (0 − 𝐴) ∈ ℝ)
 
Theoremrenegadd 40276 Relationship between real negation and addition. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((0 − 𝐴) = 𝐵 ↔ (𝐴 + 𝐵) = 0))
 
Theoremrenegid 40277 Addition of a real number and its negative. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → (𝐴 + (0 − 𝐴)) = 0)
 
Theoremreneg0addid2 40278 Negative zero is a left additive identity. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → ((0 − 0) + 𝐴) = 𝐴)
 
Theoremresubeulem1 40279 Lemma for resubeu 40281. A value which when added to zero, results in negative zero. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → (0 + (0 − (0 + 0))) = (0 − 0))
 
Theoremresubeulem2 40280 Lemma for resubeu 40281. A value which when added to 𝐴, results in 𝐵. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 + ((0 − 𝐴) + ((0 − (0 + 0)) + 𝐵))) = 𝐵)
 
Theoremresubeu 40281* Existential uniqueness of real differences. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ∃!𝑥 ∈ ℝ (𝐴 + 𝑥) = 𝐵)
 
Theoremrersubcl 40282 Closure for real subtraction. Based on subcl 11150. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 𝐵) ∈ ℝ)
 
Theoremresubadd 40283 Relation between real subtraction and addition. Based on subadd 11154. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐵) = 𝐶 ↔ (𝐵 + 𝐶) = 𝐴))
 
Theoremresubaddd 40284 Relationship between subtraction and addition. Based on subaddd 11280. (Contributed by Steven Nguyen, 8-Jan-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)       (𝜑 → ((𝐴 𝐵) = 𝐶 ↔ (𝐵 + 𝐶) = 𝐴))
 
Theoremresubf 40285 Real subtraction is an operation on the real numbers. Based on subf 11153. (Contributed by Steven Nguyen, 7-Jan-2023.)
:(ℝ × ℝ)⟶ℝ
 
Theoremrepncan2 40286 Addition and subtraction of equals. Compare pncan2 11158. (Contributed by Steven Nguyen, 8-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((𝐴 + 𝐵) − 𝐴) = 𝐵)
 
Theoremrepncan3 40287 Addition and subtraction of equals. Based on pncan3 11159. (Contributed by Steven Nguyen, 8-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 + (𝐵 𝐴)) = 𝐵)
 
Theoremreaddsub 40288 Law for addition and subtraction. (Contributed by Steven Nguyen, 28-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 + 𝐵) − 𝐶) = ((𝐴 𝐶) + 𝐵))
 
Theoremreladdrsub 40289 Move LHS of a sum into RHS of a (real) difference. Version of mvlladdd 11316 with real subtraction. (Contributed by Steven Nguyen, 8-Jan-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → (𝐴 + 𝐵) = 𝐶)       (𝜑𝐵 = (𝐶 𝐴))
 
Theoremreltsub1 40290 Subtraction from both sides of 'less than'. Compare ltsub1 11401. (Contributed by SN, 13-Feb-2024.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → (𝐴 < 𝐵 ↔ (𝐴 𝐶) < (𝐵 𝐶)))
 
Theoremreltsubadd2 40291 'Less than' relationship between addition and subtraction. Compare ltsubadd2 11376. (Contributed by SN, 13-Feb-2024.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐵) < 𝐶𝐴 < (𝐵 + 𝐶)))
 
Theoremresubcan2 40292 Cancellation law for real subtraction. Compare subcan2 11176. (Contributed by Steven Nguyen, 8-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐶) = (𝐵 𝐶) ↔ 𝐴 = 𝐵))
 
Theoremresubsub4 40293 Law for double subtraction. Compare subsub4 11184. (Contributed by Steven Nguyen, 14-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐵) − 𝐶) = (𝐴 (𝐵 + 𝐶)))
 
Theoremrennncan2 40294 Cancellation law for real subtraction. Compare nnncan2 11188. (Contributed by Steven Nguyen, 14-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐶) − (𝐵 𝐶)) = (𝐴 𝐵))
 
Theoremrenpncan3 40295 Cancellation law for real subtraction. Compare npncan3 11189. (Contributed by Steven Nguyen, 28-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐵) + (𝐶 𝐴)) = (𝐶 𝐵))
 
Theoremrepnpcan 40296 Cancellation law for addition and real subtraction. Compare pnpcan 11190. (Contributed by Steven Nguyen, 19-May-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 + 𝐵) − (𝐴 + 𝐶)) = (𝐵 𝐶))
 
Theoremreppncan 40297 Cancellation law for mixed addition and real subtraction. Compare ppncan 11193. (Contributed by SN, 3-Sep-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 + 𝐶) + (𝐵 𝐶)) = (𝐴 + 𝐵))
 
Theoremresubidaddid1lem 40298 Lemma for resubidaddid1 40299. A special case of npncan 11172. (Contributed by Steven Nguyen, 8-Jan-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑 → (𝐴 𝐵) = (𝐵 𝐶))       (𝜑 → ((𝐴 𝐵) + (𝐵 𝐶)) = (𝐴 𝐶))
 
Theoremresubidaddid1 40299 Any real number subtracted from itself forms a left additive identity. (Contributed by Steven Nguyen, 8-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((𝐴 𝐴) + 𝐵) = 𝐵)
 
Theoremresubdi 40300 Distribution of multiplication over real subtraction. (Contributed by Steven Nguyen, 3-Jun-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → (𝐴 · (𝐵 𝐶)) = ((𝐴 · 𝐵) − (𝐴 · 𝐶)))
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330 32901-33000 331 33001-33100 332 33101-33200 333 33201-33300 334 33301-33400 335 33401-33500 336 33501-33600 337 33601-33700 338 33701-33800 339 33801-33900 340 33901-34000 341 34001-34100 342 34101-34200 343 34201-34300 344 34301-34400 345 34401-34500 346 34501-34600 347 34601-34700 348 34701-34800 349 34801-34900 350 34901-35000 351 35001-35100 352 35101-35200 353 35201-35300 354 35301-35400 355 35401-35500 356 35501-35600 357 35601-35700 358 35701-35800 359 35801-35900 360 35901-36000 361 36001-36100 362 36101-36200 363 36201-36300 364 36301-36400 365 36401-36500 366 36501-36600 367 36601-36700 368 36701-36800 369 36801-36900 370 36901-37000 371 37001-37100 372 37101-37200 373 37201-37300 374 37301-37400 375 37401-37500 376 37501-37600 377 37601-37700 378 37701-37800 379 37801-37900 380 37901-38000 381 38001-38100 382 38101-38200 383 38201-38300 384 38301-38400 385 38401-38500 386 38501-38600 387 38601-38700 388 38701-38800 389 38801-38900 390 38901-39000 391 39001-39100 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