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Theorem List for Metamath Proof Explorer - 29301-29400   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
16.2.22  Parallel lines
 
Syntaxcprlng 29301 Extend class notation for the parallel lines relation.
class parlnG
 
Definitiondf-prlng 29302* Define the parallel relation for lines. Definition 12.2 of [Schwabhauser] p. 121. Note that the textbook first defines a "strict" parallelism where equal lines are not considered parallel in the strict sense: here we jump directly to the more common definition which allows equality. (Contributed by Thierry Arnoux, 17-Jun-2026.)
parlnG = (𝑔 ∈ V ↦ {⟨𝑎, 𝑏⟩ ∣ ((𝑎 ∈ ran (LineG‘𝑔) ∧ 𝑏 ∈ ran (LineG‘𝑔)) ∧ (𝑎 = 𝑏 ∨ (∃ ∈ ran (hlG‘𝑔)(𝑎𝑏) ∧ (𝑎𝑏) = ∅)))})
 
Theorembrprlng 29303* Property of two lines 𝐴 and 𝐵 to be parallel. (Contributed by Thierry Arnoux, 18-Jun-2026.)
𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺𝑉)       (𝜑 → (𝐴 𝐵 ↔ ((𝐴 ∈ ran 𝐿𝐵 ∈ ran 𝐿) ∧ (𝐴 = 𝐵 ∨ (∃ ∈ ran 𝐸(𝐴𝐵) ∧ (𝐴𝐵) = ∅)))))
 
Theoremprlngd 29304 Deduce parallelism between two lines 𝐴 and 𝐵. (Contributed by Thierry Arnoux, 18-Jun-2026.)
𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺𝑉)    &   (𝜑𝐴 ∈ ran 𝐿)    &   (𝜑𝐵 ∈ ran 𝐿)    &   (𝜑𝐻 ∈ ran 𝐸)    &   (𝜑𝐴𝐻)    &   (𝜑𝐵𝐻)    &   (𝜑 → (𝐴𝐵) = ∅)       (𝜑𝐴 𝐵)
 
Theoremprlngref 29305 Parallelism is reflexive. Theorem 12.4 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 18-Jun-2026.)
𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺𝑉)    &   (𝜑𝐴 ∈ ran 𝐿)       (𝜑𝐴 𝐴)
 
Theoremprlngsym 29306 Parallelism is symmetric. Theorem 12.5 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 18-Jun-2026.)
𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺𝑉)    &   (𝜑𝐴 𝐵)       (𝜑𝐵 𝐴)
 
Theoremprlngrcl1 29307 Reverse closure for parallelism. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺𝑉)    &   (𝜑𝐴 𝐵)       (𝜑𝐴 ∈ ran 𝐿)
 
Theoremprlngrcl2 29308 Reverse closure for parallelism. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺𝑉)    &   (𝜑𝐴 𝐵)       (𝜑𝐵 ∈ ran 𝐿)
 
Theoremprlngin0 29309 Two parallel lines do not intersect. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺𝑉)    &   (𝜑𝐴 𝐵)    &   (𝜑𝐴𝐵)       (𝜑 → (𝐴𝐵) = ∅)
 
Theoremprlngpln 29310* Two parallel lines are on a common plane. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺𝑉)    &   (𝜑𝐴 𝐵)    &   (𝜑𝐴𝐵)       (𝜑 → ∃ ∈ ran 𝐸(𝐴𝐵))
 
Theoremprlnghpg 29311 If two lines 𝐴 and 𝐵 are parallel, then any two points 𝑋 and 𝑌 of 𝐵 lie on the same half-plane limited by 𝐴. Theorem 12.6 of [Schwabhauser] p. 122. . (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐴 𝐵)    &   (𝜑𝐴𝐵)    &   (𝜑𝑋𝐵)    &   (𝜑𝑌𝐵)       (𝜑𝑋((hpG‘𝐺)‘𝐴)𝑌)
 
Theoremdfprlng2 29312 Alternate definition of (strict) parallelism. Theorem 12.7 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 13-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌 ∈ (𝑃 ∖ {𝑋}))    &   (𝜑𝑍𝑃)    &   (𝜑𝑊 ∈ (𝑃 ∖ {𝑍}))    &   (𝜑 → (𝑋𝐿𝑌) ≠ (𝑍𝐿𝑊))       (𝜑 → ((𝑋𝐿𝑌) (𝑍𝐿𝑊) ↔ (𝑍((hpG‘𝐺)‘(𝑋𝐿𝑌))𝑊 ∧ ((𝑋𝐿𝑌) ∩ (𝑍𝐿𝑊)) = ∅)))
 
Theoremdfprlng3 29313 Alternate definition of (strict) parallelism. Theorem 12.7 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 13-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌 ∈ (𝑃 ∖ {𝑋}))    &   (𝜑𝐴 ∈ ran 𝐿)    &   (𝜑𝐴 ≠ (𝑋𝐿𝑌))       (𝜑 → (𝐴 (𝑋𝐿𝑌) ↔ (𝑋((hpG‘𝐺)‘𝐴)𝑌 ∧ (𝐴 ∩ (𝑋𝐿𝑌)) = ∅)))
 
Theoremprlngpln3 29314 Two parallel lines are on a common plane. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐴 𝐵)    &   (𝜑𝐴𝐵)    &   (𝜑𝑋𝐵)       (𝜑𝐵 ⊆ (𝐴𝐸𝑋))
 
Theoremperpprlng 29315 If two lines 𝐴 and 𝐵 have a common perpendicular 𝐶 and lie in the same plane 𝐻, then they are parallel. Theorem 12.9 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐻 ∈ ran 𝐸)    &   (𝜑𝐴𝐻)    &   (𝜑𝐵𝐻)    &   (𝜑𝐶𝐻)    &   (𝜑𝐴(⟂G‘𝐺)𝐶)    &   (𝜑𝐵(⟂G‘𝐺)𝐶)       (𝜑𝐴 𝐵)
 
Theoremprlngex 29316* There exists at least one parallel line 𝑏 to a given line 𝐴 through a given point 𝑋. Theorem 12.10 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐴 ∈ ran 𝐿)    &   (𝜑𝑋𝑃)       (𝜑 → ∃𝑏 ∈ ran 𝐿(𝐴 𝑏𝑋𝑏))
 
Theoremprlngmolem1 29317* Lemma for prlngmo 29319: Contradiction: Assuming two different parallels 𝐵 and 𝐶 having a common point 𝑋 exist to a line 𝐴, the geometry cannot be Euclidean (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐴 ∈ ran 𝐿)    &   (𝜑𝑋 ∈ (𝑃𝐴))    &   𝑂 = {⟨𝑎, 𝑏⟩ ∣ ((𝑎 ∈ (𝑃𝐵) ∧ 𝑏 ∈ (𝑃𝐵)) ∧ ∃𝑦𝐵 𝑦 ∈ (𝑎𝐼𝑏))}    &   𝑄 = {⟨𝑎, 𝑏⟩ ∣ ((𝑎 ∈ (𝑃𝐴) ∧ 𝑏 ∈ (𝑃𝐴)) ∧ ∃𝑤𝐴 𝑤 ∈ (𝑎𝐼𝑏))}    &   𝐼 = (Itv‘𝐺)    &   (𝜑𝐵 ∈ ran 𝐿)    &   (𝜑𝐶 ∈ ran 𝐿)    &   (𝜑𝐴 𝐵)    &   (𝜑𝐴 𝐶)    &   (𝜑𝑋𝐵)    &   (𝜑𝑋𝐶)    &   (𝜑𝑇𝐴)    &   (𝜑𝑊 ∈ (𝐶𝐵))    &   (𝜑𝐵𝐶)    &   (𝜑𝑊𝑂𝑇)       (𝜑 → ¬ 𝐺 ∈ TarskiGE)
 
Theoremprlngmolem2 29318* Lemma for prlngmo 29319. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐴 ∈ ran 𝐿)    &   (𝜑𝑋 ∈ (𝑃𝐴))    &   (𝜑𝐺 ∈ TarskiGE)    &   𝑂 = {⟨𝑥, 𝑦⟩ ∣ ((𝑥 ∈ (𝑃𝑏) ∧ 𝑦 ∈ (𝑃𝑏)) ∧ ∃𝑟𝑏 𝑟 ∈ (𝑥(Itv‘𝐺)𝑦))}    &   𝑄 = {⟨𝑥, 𝑦⟩ ∣ ((𝑥 ∈ (𝑃𝐴) ∧ 𝑦 ∈ (𝑃𝐴)) ∧ ∃𝑠𝐴 𝑠 ∈ (𝑥(Itv‘𝐺)𝑦))}       (𝜑 → ∃*𝑏 ∈ ran 𝐿(𝐴 𝑏𝑋𝑏))
 
Theoremprlngmo 29319* Playfair's axiom. Given a line 𝐴 and a point 𝑋 not on 𝐴, at most one line parallel to 𝐴 can be drawn through 𝑋. Theorem 12.11 of [Schwabhauser] p. 123. Note that this is the first instance of a theorem where the geometry is required to be Euclidean, as expressed by 𝐺 ∈ TarskiGE. Theorem A10 of [Schwabhauser] p. 24 is used, in the form of axtgeucl 28821, in the proof of prlngmolem1 29317. See prlngex 29316 for the corresponding existence theorem. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐴 ∈ ran 𝐿)    &   (𝜑𝑋 ∈ (𝑃𝐴))    &   (𝜑𝐺 ∈ TarskiGE)       (𝜑 → ∃*𝑏 ∈ ran 𝐿(𝐴 𝑏𝑋𝑏))
 
Theoremprlngeu 29320* Given a line 𝐴 and a point 𝑋 not on 𝐴, a unique line parallel to 𝐴 can be drawn through 𝑋. Theorem 12.13 of [Schwabhauser] p. 124. (Contributed by Thierry Arnoux, 5-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐴 ∈ ran 𝐿)    &   (𝜑𝑋 ∈ (𝑃𝐴))    &   (𝜑𝐺 ∈ TarskiGE)       (𝜑 → ∃!𝑏 ∈ ran 𝐿(𝐴 𝑏𝑋𝑏))
 
Theoremprlngmo2 29321* Playfair's axiom, without the restriction that the point 𝑋 is outside of the line 𝐴. Theorem 12.11 of [Schwabhauser] p. 123. (Contributed by Thierry Arnoux, 13-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐴 ∈ ran 𝐿)    &   (𝜑𝑋𝑃)    &   (𝜑𝐺 ∈ TarskiGE)       (𝜑 → ∃*𝑏 ∈ ran 𝐿(𝐴 𝑏𝑋𝑏))
 
Theoremprlngeq 29322 Playfair's axiom, written as an equality: if two different lines are parallel to a given line at a given point, they are equal. (Contributed by Thierry Arnoux, 20-Jul-2026.)
𝑃 = (Base‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝐴 𝐵)    &   (𝜑𝐴 𝐶)    &   (𝜑𝑋𝐵)    &   (𝜑𝑋𝐶)       (𝜑𝐵 = 𝐶)
 
Theoremprlngpln4 29323 Building a parallel line conserves planes, i.e. given a line 𝐴 and a point 𝑋 not on 𝐴, the (unique) parallel 𝐵 to 𝐴 through 𝑋 lies completely within the plane defined by 𝐴 and 𝑋. Theorem 12.14 of [Schwabhauser] p. 124. (Contributed by Thierry Arnoux, 13-Jul-2026.)
𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐻 ∈ ran 𝐸)    &   (𝜑𝐴𝐻)    &   (𝜑𝐴 𝐵)    &   (𝜑𝑋𝐻)    &   (𝜑𝑋𝐵)       (𝜑𝐵𝐻)
 
Theoremprlngplngtr 29324 Transitivity of parallelism, for lines in the same plane 𝐻. This is case 1 of Theorem 12.15 of [Schwabhauser] p. 124. (Contributed by Thierry Arnoux, 13-Jul-2026.)
𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐻 ∈ ran 𝐸)    &   (𝜑𝐴𝐻)    &   (𝜑𝐴 𝐵)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝐶𝐻)    &   (𝜑𝐵 𝐶)       (𝜑𝐴 𝐶)
 
Theoremprlnginn0 29325 A line 𝐶 intersecting another line 𝐴 also intersects any line 𝐵 parallel to 𝐴. Theorem 12.16 of [Schwabhauser] p. 125. (Contributed by Thierry Arnoux, 13-Jul-2026.)
𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝐻 ∈ ran 𝐸)    &   (𝜑𝐶 ∈ ran 𝐿)    &   (𝜑 → (𝐴𝐶) ≠ ∅)    &   (𝜑𝐴𝐶)    &   (𝜑𝐴 𝐵)    &   (𝜑𝐴𝐻)    &   (𝜑𝐵𝐻)    &   (𝜑𝐶𝐻)       (𝜑 → (𝐵𝐶) ≠ ∅)
 
Theoremprlngmid2 29326 If the midpoints of two segments (𝑋𝐼𝑍) and (𝑌𝐼𝑊) coincide, the points 𝑋, 𝑌, 𝑍 and 𝑊 form a parallelogram, i.e. the lines (𝑋𝐿𝑌) and (𝑍𝐿𝑊) are parallel. Theorem 12.17 of [Schwabhauser] p. 125. (Contributed by Thierry Arnoux, 13-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐿 = (LineG‘𝐺)    &   𝐸 = (hlG‘𝐺)    &    = (parlnG‘𝐺)    &   𝑀 = (midG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   (𝜑𝑍 ∈ (𝑃 ∖ (𝑋𝐿𝑌)))    &   (𝜑𝑊𝑃)    &   (𝜑 → (𝑋𝑀𝑍) = (𝑌𝑀𝑊))    &   (𝜑𝑋𝑌)       (𝜑 → (𝑋𝐿𝑌) (𝑍𝐿𝑊))
 
Theoremsymquadprlng 29327 Symmetrical quadrilaterals are parallelograms. Theorem 12.18 of [Schwabhauser] p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026.)
𝑃 = (Base‘𝐺)    &    = (dist‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   (𝜑𝑍𝑃)    &   (𝜑𝑊𝑃)    &   (𝜑 → (𝑋 𝑌) = (𝑍 𝑊))    &   (𝜑 → (𝑌 𝑍) = (𝑊 𝑋))    &   (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍))    &   (𝜑𝑌𝑊)    &   (𝜑𝑇 ∈ (𝑋𝐿𝑍))    &   (𝜑𝑇 ∈ (𝑌𝐿𝑊))       (𝜑 → ((𝑋𝐿𝑌) (𝑍𝐿𝑊) ∧ (𝑌𝐿𝑍) (𝑊𝐿𝑋)))
 
Theoremprlngsymquadlem 29328 Lemma for prlngsymquad 29329. (Contributed by Thierry Arnoux, 20-Jul-2026.)
𝑃 = (Base‘𝐺)    &    = (dist‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   (𝜑𝑍𝑃)    &   (𝜑𝑊𝑃)    &   (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍))    &   (𝜑 → (𝑋𝐿𝑌) (𝑍𝐿𝑊))    &   (𝜑 → (𝑌𝐿𝑍) (𝑊𝐿𝑋))    &   𝑇 = (((pInvG‘𝐺)‘(𝑋(midG‘𝐺)𝑍))‘𝑌)       (𝜑𝑇 = 𝑊)
 
Theoremprlngsymquad 29329 All parallelograms are symmetric quadrilaterals. First part of Theorem 12.19 of [Schwabhauser] p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026.)
𝑃 = (Base‘𝐺)    &    = (dist‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   (𝜑𝑍𝑃)    &   (𝜑𝑊𝑃)    &   (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍))    &   (𝜑 → (𝑋𝐿𝑌) (𝑍𝐿𝑊))    &   (𝜑 → (𝑌𝐿𝑍) (𝑊𝐿𝑋))       (𝜑 → ((𝑋 𝑌) = (𝑍 𝑊) ∧ (𝑌 𝑍) = (𝑊 𝑋)))
 
Theoremprlngsymquadopp 29330* In parallelograms, opposing vertices are on opposite sides of the diagonal. Second part of Theorem 12.19 of [Schwabhauser] p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026.)
𝑃 = (Base‘𝐺)    &    = (dist‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   (𝜑𝑍𝑃)    &   (𝜑𝑊𝑃)    &   (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍))    &   (𝜑 → (𝑋𝐿𝑌) (𝑍𝐿𝑊))    &   (𝜑 → (𝑌𝐿𝑍) (𝑊𝐿𝑋))    &   𝑂 = {⟨𝑎, 𝑏⟩ ∣ ((𝑎 ∈ (𝑃 ∖ (𝑋𝐿𝑍)) ∧ 𝑏 ∈ (𝑃 ∖ (𝑋𝐿𝑍))) ∧ ∃𝑡 ∈ (𝑋𝐿𝑍)𝑡 ∈ (𝑎𝐼𝑏))}    &   𝐼 = (Itv‘𝐺)       (𝜑𝑊𝑂𝑌)
 
Theoremquadcgrprlng 29331* Nontrivial quadrilaterals with congruent and parallel opposite sides are parallelograms. Theorem 12.20 of [Schwabhauser] p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026.)
𝑃 = (Base‘𝐺)    &    = (dist‘𝐺)    &   𝐼 = (Itv‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   𝑂 = {⟨𝑎, 𝑏⟩ ∣ ((𝑎 ∈ (𝑃 ∖ (𝑋𝐿𝑍)) ∧ 𝑏 ∈ (𝑃 ∖ (𝑋𝐿𝑍))) ∧ ∃𝑡 ∈ (𝑋𝐿𝑍)𝑡 ∈ (𝑎𝐼𝑏))}    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   (𝜑𝑍𝑃)    &   (𝜑𝑊𝑃)    &   (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍))    &   (𝜑 → (𝑋𝐿𝑌) (𝑍𝐿𝑊))    &   (𝜑 → (𝑋 𝑌) = (𝑍 𝑊))    &   (𝜑𝑌𝑂𝑊)       (𝜑 → ((𝑌𝐿𝑍) (𝑊𝐿𝑋) ∧ (𝑌 𝑍) = (𝑊 𝑋)))
 
Theoremtgaltai 29332* Parallelism implies alternate angles congruence: if a line (𝑋𝐿𝑍) crosses two parallel lines (𝑋𝐿𝑌) and (𝑍𝐿𝑊), then the alternate angles are congruent. First direction of Theorem 12.21 of [Schwabhauser] p. 126. This is also Proposition 1.29 of Euclid's Elements . (Contributed by Thierry Arnoux, 20-Jul-2026.)
𝑃 = (Base‘𝐺)    &   𝐼 = (Itv‘𝐺)    &   𝐿 = (LineG‘𝐺)    &    = (parlnG‘𝐺)    &   𝑂 = {⟨𝑎, 𝑏⟩ ∣ ((𝑎 ∈ (𝑃 ∖ (𝑋𝐿𝑍)) ∧ 𝑏 ∈ (𝑃 ∖ (𝑋𝐿𝑍))) ∧ ∃𝑡 ∈ (𝑋𝐿𝑍)𝑡 ∈ (𝑎𝐼𝑏))}    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑𝐺 ∈ TarskiGE)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   (𝜑𝑍𝑃)    &   (𝜑𝑊𝑃)    &   (𝜑 → (𝑋𝐿𝑌) (𝑍𝐿𝑊))    &   (𝜑𝑌𝑂𝑊)    &   (𝜑𝑋𝑍)       (𝜑 → ⟨“𝑌𝑋𝑍”⟩(cgrA‘𝐺)⟨“𝑊𝑍𝑋”⟩)
 
16.3  Properties of geometries
 
16.3.1  Isomorphisms between geometries
 
Theoremf1otrgds 29333* Convenient lemma for f1otrg 29335. (Contributed by Thierry Arnoux, 19-Mar-2019.)
𝑃 = (Base‘𝐺)    &   𝐷 = (dist‘𝐺)    &   𝐼 = (Itv‘𝐺)    &   𝐵 = (Base‘𝐻)    &   𝐸 = (dist‘𝐻)    &   𝐽 = (Itv‘𝐻)    &   (𝜑𝐹:𝐵1-1-onto𝑃)    &   ((𝜑 ∧ (𝑒𝐵𝑓𝐵)) → (𝑒𝐸𝑓) = ((𝐹𝑒)𝐷(𝐹𝑓)))    &   ((𝜑 ∧ (𝑒𝐵𝑓𝐵𝑔𝐵)) → (𝑔 ∈ (𝑒𝐽𝑓) ↔ (𝐹𝑔) ∈ ((𝐹𝑒)𝐼(𝐹𝑓))))    &   (𝜑𝑋𝐵)    &   (𝜑𝑌𝐵)       (𝜑 → (𝑋𝐸𝑌) = ((𝐹𝑋)𝐷(𝐹𝑌)))
 
Theoremf1otrgitv 29334* Convenient lemma for f1otrg 29335. (Contributed by Thierry Arnoux, 19-Mar-2019.)
𝑃 = (Base‘𝐺)    &   𝐷 = (dist‘𝐺)    &   𝐼 = (Itv‘𝐺)    &   𝐵 = (Base‘𝐻)    &   𝐸 = (dist‘𝐻)    &   𝐽 = (Itv‘𝐻)    &   (𝜑𝐹:𝐵1-1-onto𝑃)    &   ((𝜑 ∧ (𝑒𝐵𝑓𝐵)) → (𝑒𝐸𝑓) = ((𝐹𝑒)𝐷(𝐹𝑓)))    &   ((𝜑 ∧ (𝑒𝐵𝑓𝐵𝑔𝐵)) → (𝑔 ∈ (𝑒𝐽𝑓) ↔ (𝐹𝑔) ∈ ((𝐹𝑒)𝐼(𝐹𝑓))))    &   (𝜑𝑋𝐵)    &   (𝜑𝑌𝐵)    &   (𝜑𝑍𝐵)       (𝜑 → (𝑍 ∈ (𝑋𝐽𝑌) ↔ (𝐹𝑍) ∈ ((𝐹𝑋)𝐼(𝐹𝑌))))
 
Theoremf1otrg 29335* A bijection between bases which conserves distances and intervals conserves also geometries. (Contributed by Thierry Arnoux, 23-Mar-2019.)
𝑃 = (Base‘𝐺)    &   𝐷 = (dist‘𝐺)    &   𝐼 = (Itv‘𝐺)    &   𝐵 = (Base‘𝐻)    &   𝐸 = (dist‘𝐻)    &   𝐽 = (Itv‘𝐻)    &   (𝜑𝐹:𝐵1-1-onto𝑃)    &   ((𝜑 ∧ (𝑒𝐵𝑓𝐵)) → (𝑒𝐸𝑓) = ((𝐹𝑒)𝐷(𝐹𝑓)))    &   ((𝜑 ∧ (𝑒𝐵𝑓𝐵𝑔𝐵)) → (𝑔 ∈ (𝑒𝐽𝑓) ↔ (𝐹𝑔) ∈ ((𝐹𝑒)𝐼(𝐹𝑓))))    &   (𝜑𝐻𝑉)    &   (𝜑𝐺 ∈ TarskiG)    &   (𝜑 → (LineG‘𝐻) = (𝑥𝐵, 𝑦 ∈ (𝐵 ∖ {𝑥}) ↦ {𝑧𝐵 ∣ (𝑧 ∈ (𝑥𝐽𝑦) ∨ 𝑥 ∈ (𝑧𝐽𝑦) ∨ 𝑦 ∈ (𝑥𝐽𝑧))}))       (𝜑𝐻 ∈ TarskiG)
 
Theoremf1otrge 29336* A bijection between bases which conserves distances and intervals conserves also the property of being a Euclidean geometry. (Contributed by Thierry Arnoux, 23-Mar-2019.)
𝑃 = (Base‘𝐺)    &   𝐷 = (dist‘𝐺)    &   𝐼 = (Itv‘𝐺)    &   𝐵 = (Base‘𝐻)    &   𝐸 = (dist‘𝐻)    &   𝐽 = (Itv‘𝐻)    &   (𝜑𝐹:𝐵1-1-onto𝑃)    &   ((𝜑 ∧ (𝑒𝐵𝑓𝐵)) → (𝑒𝐸𝑓) = ((𝐹𝑒)𝐷(𝐹𝑓)))    &   ((𝜑 ∧ (𝑒𝐵𝑓𝐵𝑔𝐵)) → (𝑔 ∈ (𝑒𝐽𝑓) ↔ (𝐹𝑔) ∈ ((𝐹𝑒)𝐼(𝐹𝑓))))    &   (𝜑𝐻𝑉)    &   (𝜑𝐺 ∈ TarskiGE)       (𝜑𝐻 ∈ TarskiGE)
 
16.4  Geometry in Hilbert spaces
 
Syntaxcttg 29337 Function to convert an algebraic structure to a Tarski geometry.
class toTG
 
Definitiondf-ttg 29338* Define a function converting a subcomplex Hilbert space to a Tarski Geometry. It does so by equipping the structure with a betweenness operation. Note that because the scalar product is applied over the interval (0[,]1), only spaces whose scalar field is a superset of that interval can be considered. (Contributed by Thierry Arnoux, 24-Mar-2019.)
toTG = (𝑤 ∈ V ↦ (𝑥 ∈ (Base‘𝑤), 𝑦 ∈ (Base‘𝑤) ↦ {𝑧 ∈ (Base‘𝑤) ∣ ∃𝑘 ∈ (0[,]1)(𝑧(-g𝑤)𝑥) = (𝑘( ·𝑠𝑤)(𝑦(-g𝑤)𝑥))}) / 𝑖((𝑤 sSet ⟨(Itv‘ndx), 𝑖⟩) sSet ⟨(LineG‘ndx), (𝑥 ∈ (Base‘𝑤), 𝑦 ∈ (Base‘𝑤) ↦ {𝑧 ∈ (Base‘𝑤) ∣ (𝑧 ∈ (𝑥𝑖𝑦) ∨ 𝑥 ∈ (𝑧𝑖𝑦) ∨ 𝑦 ∈ (𝑥𝑖𝑧))})⟩))
 
Theoremttgval 29339* Define a function to augment a subcomplex Hilbert space with betweenness and a line definition. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Proof shortened by AV, 9-Nov-2024.)
𝐺 = (toTG‘𝐻)    &   𝐵 = (Base‘𝐻)    &    = (-g𝐻)    &    · = ( ·𝑠𝐻)    &   𝐼 = (Itv‘𝐺)       (𝐻𝑉 → (𝐺 = ((𝐻 sSet ⟨(Itv‘ndx), (𝑥𝐵, 𝑦𝐵 ↦ {𝑧𝐵 ∣ ∃𝑘 ∈ (0[,]1)(𝑧 𝑥) = (𝑘 · (𝑦 𝑥))})⟩) sSet ⟨(LineG‘ndx), (𝑥𝐵, 𝑦𝐵 ↦ {𝑧𝐵 ∣ (𝑧 ∈ (𝑥𝐼𝑦) ∨ 𝑥 ∈ (𝑧𝐼𝑦) ∨ 𝑦 ∈ (𝑥𝐼𝑧))})⟩) ∧ 𝐼 = (𝑥𝐵, 𝑦𝐵 ↦ {𝑧𝐵 ∣ ∃𝑘 ∈ (0[,]1)(𝑧 𝑥) = (𝑘 · (𝑦 𝑥))})))
 
Theoremttglem 29340 Lemma for ttgbas 29341, ttgvsca 29344 etc. (Contributed by Thierry Arnoux, 15-Apr-2019.) (Revised by AV, 29-Oct-2024.)
𝐺 = (toTG‘𝐻)    &   𝐸 = Slot (𝐸‘ndx)    &   (𝐸‘ndx) ≠ (LineG‘ndx)    &   (𝐸‘ndx) ≠ (Itv‘ndx)       (𝐸𝐻) = (𝐸𝐺)
 
Theoremttgbas 29341 The base set of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Revised by AV, 29-Oct-2024.)
𝐺 = (toTG‘𝐻)    &   𝐵 = (Base‘𝐻)       𝐵 = (Base‘𝐺)
 
Theoremttgplusg 29342 The addition operation of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Revised by AV, 29-Oct-2024.)
𝐺 = (toTG‘𝐻)    &    + = (+g𝐻)        + = (+g𝐺)
 
Theoremttgsub 29343 The subtraction operation of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.)
𝐺 = (toTG‘𝐻)    &    = (-g𝐻)        = (-g𝐺)
 
Theoremttgvsca 29344 The scalar product of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Revised by AV, 29-Oct-2024.)
𝐺 = (toTG‘𝐻)    &    · = ( ·𝑠𝐻)        · = ( ·𝑠𝐺)
 
Theoremttgds 29345 The metric of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Revised by AV, 29-Oct-2024.)
𝐺 = (toTG‘𝐻)    &   𝐷 = (dist‘𝐻)       𝐷 = (dist‘𝐺)
 
Theoremttgitvval 29346* Betweenness for a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.)
𝐺 = (toTG‘𝐻)    &   𝐼 = (Itv‘𝐺)    &   𝑃 = (Base‘𝐻)    &    = (-g𝐻)    &    · = ( ·𝑠𝐻)       ((𝐻𝑉𝑋𝑃𝑌𝑃) → (𝑋𝐼𝑌) = {𝑧𝑃 ∣ ∃𝑘 ∈ (0[,]1)(𝑧 𝑋) = (𝑘 · (𝑌 𝑋))})
 
Theoremttgelitv 29347* Betweenness for a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.)
𝐺 = (toTG‘𝐻)    &   𝐼 = (Itv‘𝐺)    &   𝑃 = (Base‘𝐻)    &    = (-g𝐻)    &    · = ( ·𝑠𝐻)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   (𝜑𝐻𝑉)    &   (𝜑𝑍𝑃)       (𝜑 → (𝑍 ∈ (𝑋𝐼𝑌) ↔ ∃𝑘 ∈ (0[,]1)(𝑍 𝑋) = (𝑘 · (𝑌 𝑋))))
 
Theoremttgbtwnid 29348 Any subcomplex module equipped with the betweenness operation fulfills the identity of betweenness (Axiom A6). (Contributed by Thierry Arnoux, 26-Mar-2019.)
𝐺 = (toTG‘𝐻)    &   𝐼 = (Itv‘𝐺)    &   𝑃 = (Base‘𝐻)    &    = (-g𝐻)    &    · = ( ·𝑠𝐻)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   𝑅 = (Base‘(Scalar‘𝐻))    &   (𝜑 → (0[,]1) ⊆ 𝑅)    &   (𝜑𝐻 ∈ ℂMod)    &   (𝜑𝑌 ∈ (𝑋𝐼𝑋))       (𝜑𝑋 = 𝑌)
 
Theoremttgcontlem1 29349 Lemma for % ttgcont . (Contributed by Thierry Arnoux, 24-May-2019.)
𝐺 = (toTG‘𝐻)    &   𝐼 = (Itv‘𝐺)    &   𝑃 = (Base‘𝐻)    &    = (-g𝐻)    &    · = ( ·𝑠𝐻)    &   (𝜑𝑋𝑃)    &   (𝜑𝑌𝑃)    &   𝑅 = (Base‘(Scalar‘𝐻))    &   (𝜑 → (0[,]1) ⊆ 𝑅)    &    + = (+g𝐻)    &   (𝜑𝐻 ∈ ℂVec)    &   (𝜑𝐴𝑃)    &   (𝜑𝑁𝑃)    &   (𝜑𝑀 ≠ 0)    &   (𝜑𝐾 ≠ 0)    &   (𝜑𝐾 ≠ 1)    &   (𝜑𝐿𝑀)    &   (𝜑𝐿 ≤ (𝑀 / 𝐾))    &   (𝜑𝐿 ∈ (0[,]1))    &   (𝜑𝐾 ∈ (0[,]1))    &   (𝜑𝑀 ∈ (0[,]𝐿))    &   (𝜑 → (𝑋 𝐴) = (𝐾 · (𝑌 𝐴)))    &   (𝜑 → (𝑋 𝐴) = (𝑀 · (𝑁 𝐴)))    &   (𝜑𝐵 = (𝐴 + (𝐿 · (𝑁 𝐴))))       (𝜑𝐵 ∈ (𝑋𝐼𝑌))
 
Theoremxmstrkgc 29350 Any metric space fulfills Tarski's geometry axioms of congruence. (Contributed by Thierry Arnoux, 13-Mar-2019.)
(𝐺 ∈ ∞MetSp → 𝐺 ∈ TarskiGC)
 
16.4.1  Geometry in the complex plane
 
Theoremcchhllem 29351* Lemma for chlbas and chlvsca . (Contributed by Thierry Arnoux, 15-Apr-2019.) (Revised by AV, 29-Oct-2024.)
𝐶 = (((subringAlg ‘ℂfld)‘ℝ) sSet ⟨(·𝑖‘ndx), (𝑥 ∈ ℂ, 𝑦 ∈ ℂ ↦ (𝑥 · (∗‘𝑦)))⟩)    &   𝐸 = Slot (𝐸‘ndx)    &   (Scalar‘ndx) ≠ (𝐸‘ndx)    &   ( ·𝑠 ‘ndx) ≠ (𝐸‘ndx)    &   (·𝑖‘ndx) ≠ (𝐸‘ndx)       (𝐸‘ℂfld) = (𝐸𝐶)
 
16.4.2  Geometry in Euclidean spaces
 
16.4.2.1  Definition of the Euclidean space
 
Syntaxcee 29352 Declare the syntax for the Euclidean space generator.
class 𝔼
 
Syntaxcbtwn 29353 Declare the syntax for the Euclidean betweenness predicate.
class Btwn
 
Syntaxccgr 29354 Declare the syntax for the Euclidean congruence predicate.
class Cgr
 
Definitiondf-ee 29355 Define the Euclidean space generator. For details, see elee 29358. (Contributed by Scott Fenton, 3-Jun-2013.)
𝔼 = (𝑛 ∈ ℕ ↦ (ℝ ↑m (1...𝑛)))
 
Definitiondf-btwn 29356* Define the Euclidean betweenness predicate. For details, see brbtwn 29364. (Contributed by Scott Fenton, 3-Jun-2013.)
Btwn = {⟨⟨𝑥, 𝑧⟩, 𝑦⟩ ∣ ∃𝑛 ∈ ℕ ((𝑥 ∈ (𝔼‘𝑛) ∧ 𝑧 ∈ (𝔼‘𝑛) ∧ 𝑦 ∈ (𝔼‘𝑛)) ∧ ∃𝑡 ∈ (0[,]1)∀𝑖 ∈ (1...𝑛)(𝑦𝑖) = (((1 − 𝑡) · (𝑥𝑖)) + (𝑡 · (𝑧𝑖))))}
 
Definitiondf-cgr 29357* Define the Euclidean congruence predicate. For details, see brcgr 29365. (Contributed by Scott Fenton, 3-Jun-2013.)
Cgr = {⟨𝑥, 𝑦⟩ ∣ ∃𝑛 ∈ ℕ ((𝑥 ∈ ((𝔼‘𝑛) × (𝔼‘𝑛)) ∧ 𝑦 ∈ ((𝔼‘𝑛) × (𝔼‘𝑛))) ∧ Σ𝑖 ∈ (1...𝑛)((((1st𝑥)‘𝑖) − ((2nd𝑥)‘𝑖))↑2) = Σ𝑖 ∈ (1...𝑛)((((1st𝑦)‘𝑖) − ((2nd𝑦)‘𝑖))↑2))}
 
Theoremelee 29358 Membership in a Euclidean space. We define Euclidean space here using Cartesian coordinates over 𝑁 space. We later abstract away from this using Tarski's geometry axioms, so this exact definition is unimportant. (Contributed by Scott Fenton, 3-Jun-2013.)
(𝑁 ∈ ℕ → (𝐴 ∈ (𝔼‘𝑁) ↔ 𝐴:(1...𝑁)⟶ℝ))
 
Theoremmptelee 29359* A condition for a mapping to be an element of a Euclidean space. (Contributed by Scott Fenton, 7-Jun-2013.) (Proof shortened by SN, 2-Feb-2026.)
(𝑁 ∈ ℕ → ((𝑘 ∈ (1...𝑁) ↦ (𝐴𝐹𝐵)) ∈ (𝔼‘𝑁) ↔ ∀𝑘 ∈ (1...𝑁)(𝐴𝐹𝐵) ∈ ℝ))
 
TheoremmpteleeOLD 29360* Obsolete version of mptelee 29359 as of 2-Feb-2026. (Contributed by Scott Fenton, 7-Jun-2013.) (Proof modification is discouraged.) (New usage is discouraged.)
(𝑁 ∈ ℕ → ((𝑘 ∈ (1...𝑁) ↦ (𝐴𝐹𝐵)) ∈ (𝔼‘𝑁) ↔ ∀𝑘 ∈ (1...𝑁)(𝐴𝐹𝐵) ∈ ℝ))
 
Theoremeleenn 29361 If 𝐴 is in (𝔼‘𝑁), then 𝑁 is a natural. (Contributed by Scott Fenton, 1-Jul-2013.)
(𝐴 ∈ (𝔼‘𝑁) → 𝑁 ∈ ℕ)
 
Theoremeleei 29362 The forward direction of elee 29358. (Contributed by Scott Fenton, 1-Jul-2013.)
(𝐴 ∈ (𝔼‘𝑁) → 𝐴:(1...𝑁)⟶ℝ)
 
Theoremeedimeq 29363 A point belongs to at most one Euclidean space. (Contributed by Scott Fenton, 1-Jul-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐴 ∈ (𝔼‘𝑀)) → 𝑁 = 𝑀)
 
Theorembrbtwn 29364* The binary relation form of the betweenness predicate. The statement 𝐴 Btwn ⟨𝐵, 𝐶 should be informally read as "𝐴 lies on a line segment between 𝐵 and 𝐶. This exact definition is abstracted away by Tarski's geometry axioms later on. (Contributed by Scott Fenton, 3-Jun-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → (𝐴 Btwn ⟨𝐵, 𝐶⟩ ↔ ∃𝑡 ∈ (0[,]1)∀𝑖 ∈ (1...𝑁)(𝐴𝑖) = (((1 − 𝑡) · (𝐵𝑖)) + (𝑡 · (𝐶𝑖)))))
 
Theorembrcgr 29365* The binary relation form of the congruence predicate. The statement 𝐴, 𝐵⟩Cgr⟨𝐶, 𝐷 should be read informally as "the 𝑁 dimensional point 𝐴 is as far from 𝐵 as 𝐶 is from 𝐷, or "the line segment 𝐴𝐵 is congruent to the line segment 𝐶𝐷. This particular definition is encapsulated by Tarski's axioms later on. (Contributed by Scott Fenton, 3-Jun-2013.)
(((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → (⟨𝐴, 𝐵⟩Cgr⟨𝐶, 𝐷⟩ ↔ Σ𝑖 ∈ (1...𝑁)(((𝐴𝑖) − (𝐵𝑖))↑2) = Σ𝑖 ∈ (1...𝑁)(((𝐶𝑖) − (𝐷𝑖))↑2)))
 
Theoremfveere 29366 The function value of a point is a real. (Contributed by Scott Fenton, 10-Jun-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐼 ∈ (1...𝑁)) → (𝐴𝐼) ∈ ℝ)
 
Theoremfveecn 29367 The function value of a point is a complex. (Contributed by Scott Fenton, 10-Jun-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐼 ∈ (1...𝑁)) → (𝐴𝐼) ∈ ℂ)
 
Theoremeqeefv 29368* Two points are equal iff they agree in all dimensions. (Contributed by Scott Fenton, 10-Jun-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → (𝐴 = 𝐵 ↔ ∀𝑖 ∈ (1...𝑁)(𝐴𝑖) = (𝐵𝑖)))
 
Theoremeqeelen 29369* Two points are equal iff the square of the distance between them is zero. (Contributed by Scott Fenton, 10-Jun-2013.) (Revised by Mario Carneiro, 22-May-2014.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → (𝐴 = 𝐵 ↔ Σ𝑖 ∈ (1...𝑁)(((𝐴𝑖) − (𝐵𝑖))↑2) = 0))
 
Theorembrbtwn2 29370* Alternate characterization of betweenness, with no existential quantifiers. (Contributed by Scott Fenton, 24-Jun-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → (𝐴 Btwn ⟨𝐵, 𝐶⟩ ↔ (∀𝑖 ∈ (1...𝑁)(((𝐵𝑖) − (𝐴𝑖)) · ((𝐶𝑖) − (𝐴𝑖))) ≤ 0 ∧ ∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐵𝑖) − (𝐴𝑖)) · ((𝐶𝑗) − (𝐴𝑗))) = (((𝐵𝑗) − (𝐴𝑗)) · ((𝐶𝑖) − (𝐴𝑖))))))
 
Theoremcolinearalglem1 29371 Lemma for colinearalg 29375. Expand out a multiplication. (Contributed by Scott Fenton, 24-Jun-2013.)
(((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ) ∧ (𝐷 ∈ ℂ ∧ 𝐸 ∈ ℂ ∧ 𝐹 ∈ ℂ)) → (((𝐵𝐴) · (𝐹𝐷)) = ((𝐸𝐷) · (𝐶𝐴)) ↔ ((𝐵 · 𝐹) − ((𝐴 · 𝐹) + (𝐵 · 𝐷))) = ((𝐶 · 𝐸) − ((𝐴 · 𝐸) + (𝐶 · 𝐷)))))
 
Theoremcolinearalglem2 29372* Lemma for colinearalg 29375. Translate between two forms of the colinearity condition. (Contributed by Scott Fenton, 24-Jun-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → (∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐵𝑖) − (𝐴𝑖)) · ((𝐶𝑗) − (𝐴𝑗))) = (((𝐵𝑗) − (𝐴𝑗)) · ((𝐶𝑖) − (𝐴𝑖))) ↔ ∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐶𝑖) − (𝐵𝑖)) · ((𝐴𝑗) − (𝐵𝑗))) = (((𝐶𝑗) − (𝐵𝑗)) · ((𝐴𝑖) − (𝐵𝑖)))))
 
Theoremcolinearalglem3 29373* Lemma for colinearalg 29375. Translate between two forms of the colinearity condition. (Contributed by Scott Fenton, 24-Jun-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → (∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐵𝑖) − (𝐴𝑖)) · ((𝐶𝑗) − (𝐴𝑗))) = (((𝐵𝑗) − (𝐴𝑗)) · ((𝐶𝑖) − (𝐴𝑖))) ↔ ∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐴𝑖) − (𝐶𝑖)) · ((𝐵𝑗) − (𝐶𝑗))) = (((𝐴𝑗) − (𝐶𝑗)) · ((𝐵𝑖) − (𝐶𝑖)))))
 
Theoremcolinearalglem4 29374* Lemma for colinearalg 29375. Prove a disjunction that will be needed in the final proof. (Contributed by Scott Fenton, 27-Jun-2013.)
(((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ 𝐾 ∈ ℝ) → (∀𝑖 ∈ (1...𝑁)((((𝐾 · ((𝐶𝑖) − (𝐴𝑖))) + (𝐴𝑖)) − (𝐴𝑖)) · ((𝐶𝑖) − (𝐴𝑖))) ≤ 0 ∨ ∀𝑖 ∈ (1...𝑁)(((𝐶𝑖) − ((𝐾 · ((𝐶𝑖) − (𝐴𝑖))) + (𝐴𝑖))) · ((𝐴𝑖) − ((𝐾 · ((𝐶𝑖) − (𝐴𝑖))) + (𝐴𝑖)))) ≤ 0 ∨ ∀𝑖 ∈ (1...𝑁)(((𝐴𝑖) − (𝐶𝑖)) · (((𝐾 · ((𝐶𝑖) − (𝐴𝑖))) + (𝐴𝑖)) − (𝐶𝑖))) ≤ 0))
 
Theoremcolinearalg 29375* An algebraic characterization of colinearity. Note the similarity to brbtwn2 29370. (Contributed by Scott Fenton, 24-Jun-2013.)
((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → ((𝐴 Btwn ⟨𝐵, 𝐶⟩ ∨ 𝐵 Btwn ⟨𝐶, 𝐴⟩ ∨ 𝐶 Btwn ⟨𝐴, 𝐵⟩) ↔ ∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐵𝑖) − (𝐴𝑖)) · ((𝐶𝑗) − (𝐴𝑗))) = (((𝐵𝑗) − (𝐴𝑗)) · ((𝐶𝑖) − (𝐴𝑖)))))
 
Theoremeleesub 29376* Membership of a subtraction mapping in a Euclidean space. (Contributed by Scott Fenton, 17-Jul-2013.)
𝐶 = (𝑖 ∈ (1...𝑁) ↦ ((𝐴𝑖) − (𝐵𝑖)))       ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 𝐶 ∈ (𝔼‘𝑁))
 
Theoremeleesubd 29377* Membership of a subtraction mapping in a Euclidean space. Deduction form of eleesub 29376. (Contributed by Scott Fenton, 17-Jul-2013.)
(𝜑𝐶 = (𝑖 ∈ (1...𝑁) ↦ ((𝐴𝑖) − (𝐵𝑖))))       ((𝜑𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 𝐶 ∈ (𝔼‘𝑁))
 
16.4.2.2  Tarski's axioms for geometry for the Euclidean space
 
Theoremaxdimuniq 29378 The unique dimension axiom. If a point is in 𝑁 dimensional space and in 𝑀 dimensional space, then 𝑁 = 𝑀. This axiom is not traditionally presented with Tarski's axioms, but we require it here as we are considering spaces in arbitrary dimensions. (Contributed by Scott Fenton, 24-Sep-2013.)
(((𝑁 ∈ ℕ ∧ 𝐴 ∈ (𝔼‘𝑁)) ∧ (𝑀 ∈ ℕ ∧ 𝐴 ∈ (𝔼‘𝑀))) → 𝑁 = 𝑀)
 
Theoremaxcgrrflx 29379 𝐴 is as far from 𝐵 as 𝐵 is from 𝐴. Axiom A1 of [Schwabhauser] p. 10. (Contributed by Scott Fenton, 3-Jun-2013.)
((𝑁 ∈ ℕ ∧ 𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → ⟨𝐴, 𝐵⟩Cgr⟨𝐵, 𝐴⟩)
 
Theoremaxcgrtr 29380 Congruence is transitive. Axiom A2 of [Schwabhauser] p. 10. (Contributed by Scott Fenton, 3-Jun-2013.)
((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝐷 ∈ (𝔼‘𝑁) ∧ 𝐸 ∈ (𝔼‘𝑁) ∧ 𝐹 ∈ (𝔼‘𝑁))) → ((⟨𝐴, 𝐵⟩Cgr⟨𝐶, 𝐷⟩ ∧ ⟨𝐴, 𝐵⟩Cgr⟨𝐸, 𝐹⟩) → ⟨𝐶, 𝐷⟩Cgr⟨𝐸, 𝐹⟩))
 
Theoremaxcgrid 29381 If there is no distance between 𝐴 and 𝐵, then 𝐴 = 𝐵. Axiom A3 of [Schwabhauser] p. 10. (Contributed by Scott Fenton, 3-Jun-2013.)
((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁))) → (⟨𝐴, 𝐵⟩Cgr⟨𝐶, 𝐶⟩ → 𝐴 = 𝐵))
 
Theoremaxsegconlem1 29382* Lemma for axsegcon 29392. Handle the degenerate case. (Contributed by Scott Fenton, 7-Jun-2013.)
((𝐴 = 𝐵 ∧ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁)))) → ∃𝑥 ∈ (𝔼‘𝑁)∃𝑡 ∈ (0[,]1)(∀𝑖 ∈ (1...𝑁)(𝐵𝑖) = (((1 − 𝑡) · (𝐴𝑖)) + (𝑡 · (𝑥𝑖))) ∧ Σ𝑖 ∈ (1...𝑁)(((𝐵𝑖) − (𝑥𝑖))↑2) = Σ𝑖 ∈ (1...𝑁)(((𝐶𝑖) − (𝐷𝑖))↑2)))
 
Theoremaxsegconlem2 29383* Lemma for axsegcon 29392. Show that the square of the distance between two points is a real number. (Contributed by Scott Fenton, 17-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)       ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 𝑆 ∈ ℝ)
 
Theoremaxsegconlem3 29384* Lemma for axsegcon 29392. Show that the square of the distance between two points is nonnegative. (Contributed by Scott Fenton, 17-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)       ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 0 ≤ 𝑆)
 
Theoremaxsegconlem4 29385* Lemma for axsegcon 29392. Show that the distance between two points is a real number. (Contributed by Scott Fenton, 17-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)       ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → (√‘𝑆) ∈ ℝ)
 
Theoremaxsegconlem5 29386* Lemma for axsegcon 29392. Show that the distance between two points is nonnegative. (Contributed by Scott Fenton, 17-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)       ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 0 ≤ (√‘𝑆))
 
Theoremaxsegconlem6 29387* Lemma for axsegcon 29392. Show that the distance between two distinct points is positive. (Contributed by Scott Fenton, 17-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)       ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴𝐵) → 0 < (√‘𝑆))
 
Theoremaxsegconlem7 29388* Lemma for axsegcon 29392. Show that a particular ratio of distances is in the closed unit interval. (Contributed by Scott Fenton, 18-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)    &   𝑇 = Σ𝑝 ∈ (1...𝑁)(((𝐶𝑝) − (𝐷𝑝))↑2)       (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴𝐵) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → ((√‘𝑆) / ((√‘𝑆) + (√‘𝑇))) ∈ (0[,]1))
 
Theoremaxsegconlem8 29389* Lemma for axsegcon 29392. Show that a particular mapping generates a point. (Contributed by Scott Fenton, 18-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)    &   𝑇 = Σ𝑝 ∈ (1...𝑁)(((𝐶𝑝) − (𝐷𝑝))↑2)    &   𝐹 = (𝑘 ∈ (1...𝑁) ↦ (((((√‘𝑆) + (√‘𝑇)) · (𝐵𝑘)) − ((√‘𝑇) · (𝐴𝑘))) / (√‘𝑆)))       (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴𝐵) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → 𝐹 ∈ (𝔼‘𝑁))
 
Theoremaxsegconlem9 29390* Lemma for axsegcon 29392. Show that 𝐵𝐹 is congruent to 𝐶𝐷. (Contributed by Scott Fenton, 19-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)    &   𝑇 = Σ𝑝 ∈ (1...𝑁)(((𝐶𝑝) − (𝐷𝑝))↑2)    &   𝐹 = (𝑘 ∈ (1...𝑁) ↦ (((((√‘𝑆) + (√‘𝑇)) · (𝐵𝑘)) − ((√‘𝑇) · (𝐴𝑘))) / (√‘𝑆)))       (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴𝐵) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → Σ𝑖 ∈ (1...𝑁)(((𝐵𝑖) − (𝐹𝑖))↑2) = Σ𝑖 ∈ (1...𝑁)(((𝐶𝑖) − (𝐷𝑖))↑2))
 
Theoremaxsegconlem10 29391* Lemma for axsegcon 29392. Show that the scaling constant from axsegconlem7 29388 produces the betweenness condition for 𝐴, 𝐵 and 𝐹. (Contributed by Scott Fenton, 21-Sep-2013.)
𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴𝑝) − (𝐵𝑝))↑2)    &   𝑇 = Σ𝑝 ∈ (1...𝑁)(((𝐶𝑝) − (𝐷𝑝))↑2)    &   𝐹 = (𝑘 ∈ (1...𝑁) ↦ (((((√‘𝑆) + (√‘𝑇)) · (𝐵𝑘)) − ((√‘𝑇) · (𝐴𝑘))) / (√‘𝑆)))       (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴𝐵) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → ∀𝑖 ∈ (1...𝑁)(𝐵𝑖) = (((1 − ((√‘𝑆) / ((√‘𝑆) + (√‘𝑇)))) · (𝐴𝑖)) + (((√‘𝑆) / ((√‘𝑆) + (√‘𝑇))) · (𝐹𝑖))))
 
Theoremaxsegcon 29392* Any segment 𝐴𝐵 can be extended to a point 𝑥 such that 𝐵𝑥 is congruent to 𝐶𝐷. Axiom A4 of [Schwabhauser] p. 11. (Contributed by Scott Fenton, 4-Jun-2013.)
((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → ∃𝑥 ∈ (𝔼‘𝑁)(𝐵 Btwn ⟨𝐴, 𝑥⟩ ∧ ⟨𝐵, 𝑥⟩Cgr⟨𝐶, 𝐷⟩))
 
Theoremax5seglem1 29393* Lemma for ax5seg 29403. Rexpress a one congruence sum given betweenness. (Contributed by Scott Fenton, 11-Jun-2013.)
((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝑇 ∈ (0[,]1) ∧ ∀𝑖 ∈ (1...𝑁)(𝐵𝑖) = (((1 − 𝑇) · (𝐴𝑖)) + (𝑇 · (𝐶𝑖))))) → Σ𝑗 ∈ (1...𝑁)(((𝐴𝑗) − (𝐵𝑗))↑2) = ((𝑇↑2) · Σ𝑗 ∈ (1...𝑁)(((𝐴𝑗) − (𝐶𝑗))↑2)))
 
Theoremax5seglem2 29394* Lemma for ax5seg 29403. Rexpress another congruence sum given betweenness. (Contributed by Scott Fenton, 11-Jun-2013.)
((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝑇 ∈ (0[,]1) ∧ ∀𝑖 ∈ (1...𝑁)(𝐵𝑖) = (((1 − 𝑇) · (𝐴𝑖)) + (𝑇 · (𝐶𝑖))))) → Σ𝑗 ∈ (1...𝑁)(((𝐵𝑗) − (𝐶𝑗))↑2) = (((1 − 𝑇)↑2) · Σ𝑗 ∈ (1...𝑁)(((𝐴𝑗) − (𝐶𝑗))↑2)))
 
Theoremax5seglem3a 29395 Lemma for ax5seg 29403. (Contributed by Scott Fenton, 7-May-2015.)
(((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝐷 ∈ (𝔼‘𝑁) ∧ 𝐸 ∈ (𝔼‘𝑁) ∧ 𝐹 ∈ (𝔼‘𝑁))) ∧ 𝑗 ∈ (1...𝑁)) → (((𝐴𝑗) − (𝐶𝑗)) ∈ ℝ ∧ ((𝐷𝑗) − (𝐹𝑗)) ∈ ℝ))
 
Theoremax5seglem3 29396* Lemma for ax5seg 29403. Combine congruences for points on a line. (Contributed by Scott Fenton, 11-Jun-2013.)
(((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝐷 ∈ (𝔼‘𝑁) ∧ 𝐸 ∈ (𝔼‘𝑁) ∧ 𝐹 ∈ (𝔼‘𝑁))) ∧ ((𝑇 ∈ (0[,]1) ∧ 𝑆 ∈ (0[,]1)) ∧ (∀𝑖 ∈ (1...𝑁)(𝐵𝑖) = (((1 − 𝑇) · (𝐴𝑖)) + (𝑇 · (𝐶𝑖))) ∧ ∀𝑖 ∈ (1...𝑁)(𝐸𝑖) = (((1 − 𝑆) · (𝐷𝑖)) + (𝑆 · (𝐹𝑖))))) ∧ (⟨𝐴, 𝐵⟩Cgr⟨𝐷, 𝐸⟩ ∧ ⟨𝐵, 𝐶⟩Cgr⟨𝐸, 𝐹⟩)) → Σ𝑗 ∈ (1...𝑁)(((𝐴𝑗) − (𝐶𝑗))↑2) = Σ𝑗 ∈ (1...𝑁)(((𝐷𝑗) − (𝐹𝑗))↑2))
 
Theoremax5seglem4 29397* Lemma for ax5seg 29403. Given two distinct points, the scaling constant in a betweenness statement is nonzero. (Contributed by Scott Fenton, 11-Jun-2013.)
(((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁))) ∧ ∀𝑖 ∈ (1...𝑁)(𝐵𝑖) = (((1 − 𝑇) · (𝐴𝑖)) + (𝑇 · (𝐶𝑖))) ∧ 𝐴𝐵) → 𝑇 ≠ 0)
 
Theoremax5seglem5 29398* Lemma for ax5seg 29403. If 𝐵 is between 𝐴 and 𝐶, and 𝐴 is distinct from 𝐵, then 𝐴 is distinct from 𝐶. (Contributed by Scott Fenton, 11-Jun-2013.)
(((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁))) ∧ (𝐴𝐵𝑇 ∈ (0[,]1) ∧ ∀𝑖 ∈ (1...𝑁)(𝐵𝑖) = (((1 − 𝑇) · (𝐴𝑖)) + (𝑇 · (𝐶𝑖))))) → Σ𝑗 ∈ (1...𝑁)(((𝐴𝑗) − (𝐶𝑗))↑2) ≠ 0)
 
Theoremax5seglem6 29399* Lemma for ax5seg 29403. Given two line segments that are divided into pieces, if the pieces are congruent, then the scaling constant is the same. (Contributed by Scott Fenton, 12-Jun-2013.)
(((𝑁 ∈ ℕ ∧ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝐷 ∈ (𝔼‘𝑁) ∧ 𝐸 ∈ (𝔼‘𝑁) ∧ 𝐹 ∈ (𝔼‘𝑁)))) ∧ (𝐴𝐵 ∧ (𝑇 ∈ (0[,]1) ∧ 𝑆 ∈ (0[,]1)) ∧ (∀𝑖 ∈ (1...𝑁)(𝐵𝑖) = (((1 − 𝑇) · (𝐴𝑖)) + (𝑇 · (𝐶𝑖))) ∧ ∀𝑖 ∈ (1...𝑁)(𝐸𝑖) = (((1 − 𝑆) · (𝐷𝑖)) + (𝑆 · (𝐹𝑖))))) ∧ (⟨𝐴, 𝐵⟩Cgr⟨𝐷, 𝐸⟩ ∧ ⟨𝐵, 𝐶⟩Cgr⟨𝐸, 𝐹⟩)) → 𝑇 = 𝑆)
 
Theoremax5seglem7 29400 Lemma for ax5seg 29403. An algebraic calculation needed further down the line. (Contributed by Scott Fenton, 12-Jun-2013.)
𝐴 ∈ ℂ    &   𝑇 ∈ ℂ    &   𝐶 ∈ ℂ    &   𝐷 ∈ ℂ       (𝑇 · ((𝐶𝐷)↑2)) = ((((((1 − 𝑇) · 𝐴) + (𝑇 · 𝐶)) − 𝐷)↑2) + ((1 − 𝑇) · ((𝑇 · ((𝐴𝐶)↑2)) − ((𝐴𝐷)↑2))))
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