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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Syntax | cprlng 29301 | Extend class notation for the parallel lines relation. |
| class parlnG | ||
| Definition | df-prlng 29302* | Define the parallel relation for lines. Definition 12.2 of [Schwabhauser] p. 121. Note that the textbook first defines a "strict" parallelism where equal lines are not considered parallel in the strict sense: here we jump directly to the more common definition which allows equality. (Contributed by Thierry Arnoux, 17-Jun-2026.) |
| ⊢ parlnG = (𝑔 ∈ V ↦ {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ ran (LineG‘𝑔) ∧ 𝑏 ∈ ran (LineG‘𝑔)) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran (hlG‘𝑔)(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))}) | ||
| Theorem | brprlng 29303* | Property of two lines 𝐴 and 𝐵 to be parallel. (Contributed by Thierry Arnoux, 18-Jun-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ 𝑉) ⇒ ⊢ (𝜑 → (𝐴 ∥ 𝐵 ↔ ((𝐴 ∈ ran 𝐿 ∧ 𝐵 ∈ ran 𝐿) ∧ (𝐴 = 𝐵 ∨ (∃ℎ ∈ ran 𝐸(𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ) ∧ (𝐴 ∩ 𝐵) = ∅))))) | ||
| Theorem | prlngd 29304 | Deduce parallelism between two lines 𝐴 and 𝐵. (Contributed by Thierry Arnoux, 18-Jun-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ 𝑉) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) & ⊢ (𝜑 → 𝐵 ∈ ran 𝐿) & ⊢ (𝜑 → 𝐻 ∈ ran 𝐸) & ⊢ (𝜑 → 𝐴 ⊆ 𝐻) & ⊢ (𝜑 → 𝐵 ⊆ 𝐻) & ⊢ (𝜑 → (𝐴 ∩ 𝐵) = ∅) ⇒ ⊢ (𝜑 → 𝐴 ∥ 𝐵) | ||
| Theorem | prlngref 29305 | Parallelism is reflexive. Theorem 12.4 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 18-Jun-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ 𝑉) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) ⇒ ⊢ (𝜑 → 𝐴 ∥ 𝐴) | ||
| Theorem | prlngsym 29306 | Parallelism is symmetric. Theorem 12.5 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 18-Jun-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ 𝑉) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) ⇒ ⊢ (𝜑 → 𝐵 ∥ 𝐴) | ||
| Theorem | prlngrcl1 29307 | Reverse closure for parallelism. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ 𝑉) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) ⇒ ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) | ||
| Theorem | prlngrcl2 29308 | Reverse closure for parallelism. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ 𝑉) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) ⇒ ⊢ (𝜑 → 𝐵 ∈ ran 𝐿) | ||
| Theorem | prlngin0 29309 | Two parallel lines do not intersect. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ 𝑉) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝐴 ≠ 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐵) = ∅) | ||
| Theorem | prlngpln 29310* | Two parallel lines are on a common plane. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ 𝑉) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝐴 ≠ 𝐵) ⇒ ⊢ (𝜑 → ∃ℎ ∈ ran 𝐸(𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ)) | ||
| Theorem | prlnghpg 29311 | If two lines 𝐴 and 𝐵 are parallel, then any two points 𝑋 and 𝑌 of 𝐵 lie on the same half-plane limited by 𝐴. Theorem 12.6 of [Schwabhauser] p. 122. . (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝐴 ≠ 𝐵) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) & ⊢ (𝜑 → 𝑌 ∈ 𝐵) ⇒ ⊢ (𝜑 → 𝑋((hpG‘𝐺)‘𝐴)𝑌) | ||
| Theorem | dfprlng2 29312 | Alternate definition of (strict) parallelism. Theorem 12.7 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 13-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ (𝑃 ∖ {𝑋})) & ⊢ (𝜑 → 𝑍 ∈ 𝑃) & ⊢ (𝜑 → 𝑊 ∈ (𝑃 ∖ {𝑍})) & ⊢ (𝜑 → (𝑋𝐿𝑌) ≠ (𝑍𝐿𝑊)) ⇒ ⊢ (𝜑 → ((𝑋𝐿𝑌) ∥ (𝑍𝐿𝑊) ↔ (𝑍((hpG‘𝐺)‘(𝑋𝐿𝑌))𝑊 ∧ ((𝑋𝐿𝑌) ∩ (𝑍𝐿𝑊)) = ∅))) | ||
| Theorem | dfprlng3 29313 | Alternate definition of (strict) parallelism. Theorem 12.7 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 13-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ (𝑃 ∖ {𝑋})) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) & ⊢ (𝜑 → 𝐴 ≠ (𝑋𝐿𝑌)) ⇒ ⊢ (𝜑 → (𝐴 ∥ (𝑋𝐿𝑌) ↔ (𝑋((hpG‘𝐺)‘𝐴)𝑌 ∧ (𝐴 ∩ (𝑋𝐿𝑌)) = ∅))) | ||
| Theorem | prlngpln3 29314 | Two parallel lines are on a common plane. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝐴 ≠ 𝐵) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) ⇒ ⊢ (𝜑 → 𝐵 ⊆ (𝐴𝐸𝑋)) | ||
| Theorem | perpprlng 29315 | If two lines 𝐴 and 𝐵 have a common perpendicular 𝐶 and lie in the same plane 𝐻, then they are parallel. Theorem 12.9 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐻 ∈ ran 𝐸) & ⊢ (𝜑 → 𝐴 ⊆ 𝐻) & ⊢ (𝜑 → 𝐵 ⊆ 𝐻) & ⊢ (𝜑 → 𝐶 ⊆ 𝐻) & ⊢ (𝜑 → 𝐴(⟂G‘𝐺)𝐶) & ⊢ (𝜑 → 𝐵(⟂G‘𝐺)𝐶) ⇒ ⊢ (𝜑 → 𝐴 ∥ 𝐵) | ||
| Theorem | prlngex 29316* | There exists at least one parallel line 𝑏 to a given line 𝐴 through a given point 𝑋. Theorem 12.10 of [Schwabhauser] p. 122. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) ⇒ ⊢ (𝜑 → ∃𝑏 ∈ ran 𝐿(𝐴 ∥ 𝑏 ∧ 𝑋 ∈ 𝑏)) | ||
| Theorem | prlngmolem1 29317* | Lemma for prlngmo 29319: Contradiction: Assuming two different parallels 𝐵 and 𝐶 having a common point 𝑋 exist to a line 𝐴, the geometry cannot be Euclidean (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) & ⊢ (𝜑 → 𝑋 ∈ (𝑃 ∖ 𝐴)) & ⊢ 𝑂 = {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ (𝑃 ∖ 𝐵) ∧ 𝑏 ∈ (𝑃 ∖ 𝐵)) ∧ ∃𝑦 ∈ 𝐵 𝑦 ∈ (𝑎𝐼𝑏))} & ⊢ 𝑄 = {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ (𝑃 ∖ 𝐴) ∧ 𝑏 ∈ (𝑃 ∖ 𝐴)) ∧ ∃𝑤 ∈ 𝐴 𝑤 ∈ (𝑎𝐼𝑏))} & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ (𝜑 → 𝐵 ∈ ran 𝐿) & ⊢ (𝜑 → 𝐶 ∈ ran 𝐿) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝐴 ∥ 𝐶) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) & ⊢ (𝜑 → 𝑋 ∈ 𝐶) & ⊢ (𝜑 → 𝑇 ∈ 𝐴) & ⊢ (𝜑 → 𝑊 ∈ (𝐶 ∖ 𝐵)) & ⊢ (𝜑 → 𝐵 ≠ 𝐶) & ⊢ (𝜑 → 𝑊𝑂𝑇) ⇒ ⊢ (𝜑 → ¬ 𝐺 ∈ TarskiGE) | ||
| Theorem | prlngmolem2 29318* | Lemma for prlngmo 29319. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) & ⊢ (𝜑 → 𝑋 ∈ (𝑃 ∖ 𝐴)) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ 𝑂 = {〈𝑥, 𝑦〉 ∣ ((𝑥 ∈ (𝑃 ∖ 𝑏) ∧ 𝑦 ∈ (𝑃 ∖ 𝑏)) ∧ ∃𝑟 ∈ 𝑏 𝑟 ∈ (𝑥(Itv‘𝐺)𝑦))} & ⊢ 𝑄 = {〈𝑥, 𝑦〉 ∣ ((𝑥 ∈ (𝑃 ∖ 𝐴) ∧ 𝑦 ∈ (𝑃 ∖ 𝐴)) ∧ ∃𝑠 ∈ 𝐴 𝑠 ∈ (𝑥(Itv‘𝐺)𝑦))} ⇒ ⊢ (𝜑 → ∃*𝑏 ∈ ran 𝐿(𝐴 ∥ 𝑏 ∧ 𝑋 ∈ 𝑏)) | ||
| Theorem | prlngmo 29319* | Playfair's axiom. Given a line 𝐴 and a point 𝑋 not on 𝐴, at most one line parallel to 𝐴 can be drawn through 𝑋. Theorem 12.11 of [Schwabhauser] p. 123. Note that this is the first instance of a theorem where the geometry is required to be Euclidean, as expressed by 𝐺 ∈ TarskiGE. Theorem A10 of [Schwabhauser] p. 24 is used, in the form of axtgeucl 28821, in the proof of prlngmolem1 29317. See prlngex 29316 for the corresponding existence theorem. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) & ⊢ (𝜑 → 𝑋 ∈ (𝑃 ∖ 𝐴)) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) ⇒ ⊢ (𝜑 → ∃*𝑏 ∈ ran 𝐿(𝐴 ∥ 𝑏 ∧ 𝑋 ∈ 𝑏)) | ||
| Theorem | prlngeu 29320* | Given a line 𝐴 and a point 𝑋 not on 𝐴, a unique line parallel to 𝐴 can be drawn through 𝑋. Theorem 12.13 of [Schwabhauser] p. 124. (Contributed by Thierry Arnoux, 5-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) & ⊢ (𝜑 → 𝑋 ∈ (𝑃 ∖ 𝐴)) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) ⇒ ⊢ (𝜑 → ∃!𝑏 ∈ ran 𝐿(𝐴 ∥ 𝑏 ∧ 𝑋 ∈ 𝑏)) | ||
| Theorem | prlngmo2 29321* | Playfair's axiom, without the restriction that the point 𝑋 is outside of the line 𝐴. Theorem 12.11 of [Schwabhauser] p. 123. (Contributed by Thierry Arnoux, 13-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐴 ∈ ran 𝐿) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) ⇒ ⊢ (𝜑 → ∃*𝑏 ∈ ran 𝐿(𝐴 ∥ 𝑏 ∧ 𝑋 ∈ 𝑏)) | ||
| Theorem | prlngeq 29322 | Playfair's axiom, written as an equality: if two different lines are parallel to a given line at a given point, they are equal. (Contributed by Thierry Arnoux, 20-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝐴 ∥ 𝐶) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) & ⊢ (𝜑 → 𝑋 ∈ 𝐶) ⇒ ⊢ (𝜑 → 𝐵 = 𝐶) | ||
| Theorem | prlngpln4 29323 | Building a parallel line conserves planes, i.e. given a line 𝐴 and a point 𝑋 not on 𝐴, the (unique) parallel 𝐵 to 𝐴 through 𝑋 lies completely within the plane defined by 𝐴 and 𝑋. Theorem 12.14 of [Schwabhauser] p. 124. (Contributed by Thierry Arnoux, 13-Jul-2026.) |
| ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐻 ∈ ran 𝐸) & ⊢ (𝜑 → 𝐴 ⊆ 𝐻) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝑋 ∈ 𝐻) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) ⇒ ⊢ (𝜑 → 𝐵 ⊆ 𝐻) | ||
| Theorem | prlngplngtr 29324 | Transitivity of parallelism, for lines in the same plane 𝐻. This is case 1 of Theorem 12.15 of [Schwabhauser] p. 124. (Contributed by Thierry Arnoux, 13-Jul-2026.) |
| ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐻 ∈ ran 𝐸) & ⊢ (𝜑 → 𝐴 ⊆ 𝐻) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝐶 ⊆ 𝐻) & ⊢ (𝜑 → 𝐵 ∥ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ∥ 𝐶) | ||
| Theorem | prlnginn0 29325 | A line 𝐶 intersecting another line 𝐴 also intersects any line 𝐵 parallel to 𝐴. Theorem 12.16 of [Schwabhauser] p. 125. (Contributed by Thierry Arnoux, 13-Jul-2026.) |
| ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝐻 ∈ ran 𝐸) & ⊢ (𝜑 → 𝐶 ∈ ran 𝐿) & ⊢ (𝜑 → (𝐴 ∩ 𝐶) ≠ ∅) & ⊢ (𝜑 → 𝐴 ≠ 𝐶) & ⊢ (𝜑 → 𝐴 ∥ 𝐵) & ⊢ (𝜑 → 𝐴 ⊆ 𝐻) & ⊢ (𝜑 → 𝐵 ⊆ 𝐻) & ⊢ (𝜑 → 𝐶 ⊆ 𝐻) ⇒ ⊢ (𝜑 → (𝐵 ∩ 𝐶) ≠ ∅) | ||
| Theorem | prlngmid2 29326 | If the midpoints of two segments (𝑋𝐼𝑍) and (𝑌𝐼𝑊) coincide, the points 𝑋, 𝑌, 𝑍 and 𝑊 form a parallelogram, i.e. the lines (𝑋𝐿𝑌) and (𝑍𝐿𝑊) are parallel. Theorem 12.17 of [Schwabhauser] p. 125. (Contributed by Thierry Arnoux, 13-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ 𝐸 = (hlG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ 𝑀 = (midG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ (𝜑 → 𝑍 ∈ (𝑃 ∖ (𝑋𝐿𝑌))) & ⊢ (𝜑 → 𝑊 ∈ 𝑃) & ⊢ (𝜑 → (𝑋𝑀𝑍) = (𝑌𝑀𝑊)) & ⊢ (𝜑 → 𝑋 ≠ 𝑌) ⇒ ⊢ (𝜑 → (𝑋𝐿𝑌) ∥ (𝑍𝐿𝑊)) | ||
| Theorem | symquadprlng 29327 | Symmetrical quadrilaterals are parallelograms. Theorem 12.18 of [Schwabhauser] p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ − = (dist‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ (𝜑 → 𝑍 ∈ 𝑃) & ⊢ (𝜑 → 𝑊 ∈ 𝑃) & ⊢ (𝜑 → (𝑋 − 𝑌) = (𝑍 − 𝑊)) & ⊢ (𝜑 → (𝑌 − 𝑍) = (𝑊 − 𝑋)) & ⊢ (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍)) & ⊢ (𝜑 → 𝑌 ≠ 𝑊) & ⊢ (𝜑 → 𝑇 ∈ (𝑋𝐿𝑍)) & ⊢ (𝜑 → 𝑇 ∈ (𝑌𝐿𝑊)) ⇒ ⊢ (𝜑 → ((𝑋𝐿𝑌) ∥ (𝑍𝐿𝑊) ∧ (𝑌𝐿𝑍) ∥ (𝑊𝐿𝑋))) | ||
| Theorem | prlngsymquadlem 29328 | Lemma for prlngsymquad 29329. (Contributed by Thierry Arnoux, 20-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ − = (dist‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ (𝜑 → 𝑍 ∈ 𝑃) & ⊢ (𝜑 → 𝑊 ∈ 𝑃) & ⊢ (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍)) & ⊢ (𝜑 → (𝑋𝐿𝑌) ∥ (𝑍𝐿𝑊)) & ⊢ (𝜑 → (𝑌𝐿𝑍) ∥ (𝑊𝐿𝑋)) & ⊢ 𝑇 = (((pInvG‘𝐺)‘(𝑋(midG‘𝐺)𝑍))‘𝑌) ⇒ ⊢ (𝜑 → 𝑇 = 𝑊) | ||
| Theorem | prlngsymquad 29329 | All parallelograms are symmetric quadrilaterals. First part of Theorem 12.19 of [Schwabhauser] p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ − = (dist‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ (𝜑 → 𝑍 ∈ 𝑃) & ⊢ (𝜑 → 𝑊 ∈ 𝑃) & ⊢ (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍)) & ⊢ (𝜑 → (𝑋𝐿𝑌) ∥ (𝑍𝐿𝑊)) & ⊢ (𝜑 → (𝑌𝐿𝑍) ∥ (𝑊𝐿𝑋)) ⇒ ⊢ (𝜑 → ((𝑋 − 𝑌) = (𝑍 − 𝑊) ∧ (𝑌 − 𝑍) = (𝑊 − 𝑋))) | ||
| Theorem | prlngsymquadopp 29330* | In parallelograms, opposing vertices are on opposite sides of the diagonal. Second part of Theorem 12.19 of [Schwabhauser] p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ − = (dist‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ (𝜑 → 𝑍 ∈ 𝑃) & ⊢ (𝜑 → 𝑊 ∈ 𝑃) & ⊢ (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍)) & ⊢ (𝜑 → (𝑋𝐿𝑌) ∥ (𝑍𝐿𝑊)) & ⊢ (𝜑 → (𝑌𝐿𝑍) ∥ (𝑊𝐿𝑋)) & ⊢ 𝑂 = {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ (𝑃 ∖ (𝑋𝐿𝑍)) ∧ 𝑏 ∈ (𝑃 ∖ (𝑋𝐿𝑍))) ∧ ∃𝑡 ∈ (𝑋𝐿𝑍)𝑡 ∈ (𝑎𝐼𝑏))} & ⊢ 𝐼 = (Itv‘𝐺) ⇒ ⊢ (𝜑 → 𝑊𝑂𝑌) | ||
| Theorem | quadcgrprlng 29331* | Nontrivial quadrilaterals with congruent and parallel opposite sides are parallelograms. Theorem 12.20 of [Schwabhauser] p. 126. (Contributed by Thierry Arnoux, 20-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ − = (dist‘𝐺) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ 𝑂 = {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ (𝑃 ∖ (𝑋𝐿𝑍)) ∧ 𝑏 ∈ (𝑃 ∖ (𝑋𝐿𝑍))) ∧ ∃𝑡 ∈ (𝑋𝐿𝑍)𝑡 ∈ (𝑎𝐼𝑏))} & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ (𝜑 → 𝑍 ∈ 𝑃) & ⊢ (𝜑 → 𝑊 ∈ 𝑃) & ⊢ (𝜑 → ¬ (𝑋 ∈ (𝑌𝐿𝑍) ∨ 𝑌 = 𝑍)) & ⊢ (𝜑 → (𝑋𝐿𝑌) ∥ (𝑍𝐿𝑊)) & ⊢ (𝜑 → (𝑋 − 𝑌) = (𝑍 − 𝑊)) & ⊢ (𝜑 → 𝑌𝑂𝑊) ⇒ ⊢ (𝜑 → ((𝑌𝐿𝑍) ∥ (𝑊𝐿𝑋) ∧ (𝑌 − 𝑍) = (𝑊 − 𝑋))) | ||
| Theorem | tgaltai 29332* | Parallelism implies alternate angles congruence: if a line (𝑋𝐿𝑍) crosses two parallel lines (𝑋𝐿𝑌) and (𝑍𝐿𝑊), then the alternate angles are congruent. First direction of Theorem 12.21 of [Schwabhauser] p. 126. This is also Proposition 1.29 of Euclid's Elements . (Contributed by Thierry Arnoux, 20-Jul-2026.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝐿 = (LineG‘𝐺) & ⊢ ∥ = (parlnG‘𝐺) & ⊢ 𝑂 = {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ (𝑃 ∖ (𝑋𝐿𝑍)) ∧ 𝑏 ∈ (𝑃 ∖ (𝑋𝐿𝑍))) ∧ ∃𝑡 ∈ (𝑋𝐿𝑍)𝑡 ∈ (𝑎𝐼𝑏))} & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ (𝜑 → 𝑍 ∈ 𝑃) & ⊢ (𝜑 → 𝑊 ∈ 𝑃) & ⊢ (𝜑 → (𝑋𝐿𝑌) ∥ (𝑍𝐿𝑊)) & ⊢ (𝜑 → 𝑌𝑂𝑊) & ⊢ (𝜑 → 𝑋 ≠ 𝑍) ⇒ ⊢ (𝜑 → 〈“𝑌𝑋𝑍”〉(cgrA‘𝐺)〈“𝑊𝑍𝑋”〉) | ||
| Theorem | f1otrgds 29333* | Convenient lemma for f1otrg 29335. (Contributed by Thierry Arnoux, 19-Mar-2019.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐷 = (dist‘𝐺) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝐵 = (Base‘𝐻) & ⊢ 𝐸 = (dist‘𝐻) & ⊢ 𝐽 = (Itv‘𝐻) & ⊢ (𝜑 → 𝐹:𝐵–1-1-onto→𝑃) & ⊢ ((𝜑 ∧ (𝑒 ∈ 𝐵 ∧ 𝑓 ∈ 𝐵)) → (𝑒𝐸𝑓) = ((𝐹‘𝑒)𝐷(𝐹‘𝑓))) & ⊢ ((𝜑 ∧ (𝑒 ∈ 𝐵 ∧ 𝑓 ∈ 𝐵 ∧ 𝑔 ∈ 𝐵)) → (𝑔 ∈ (𝑒𝐽𝑓) ↔ (𝐹‘𝑔) ∈ ((𝐹‘𝑒)𝐼(𝐹‘𝑓)))) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) & ⊢ (𝜑 → 𝑌 ∈ 𝐵) ⇒ ⊢ (𝜑 → (𝑋𝐸𝑌) = ((𝐹‘𝑋)𝐷(𝐹‘𝑌))) | ||
| Theorem | f1otrgitv 29334* | Convenient lemma for f1otrg 29335. (Contributed by Thierry Arnoux, 19-Mar-2019.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐷 = (dist‘𝐺) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝐵 = (Base‘𝐻) & ⊢ 𝐸 = (dist‘𝐻) & ⊢ 𝐽 = (Itv‘𝐻) & ⊢ (𝜑 → 𝐹:𝐵–1-1-onto→𝑃) & ⊢ ((𝜑 ∧ (𝑒 ∈ 𝐵 ∧ 𝑓 ∈ 𝐵)) → (𝑒𝐸𝑓) = ((𝐹‘𝑒)𝐷(𝐹‘𝑓))) & ⊢ ((𝜑 ∧ (𝑒 ∈ 𝐵 ∧ 𝑓 ∈ 𝐵 ∧ 𝑔 ∈ 𝐵)) → (𝑔 ∈ (𝑒𝐽𝑓) ↔ (𝐹‘𝑔) ∈ ((𝐹‘𝑒)𝐼(𝐹‘𝑓)))) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) & ⊢ (𝜑 → 𝑌 ∈ 𝐵) & ⊢ (𝜑 → 𝑍 ∈ 𝐵) ⇒ ⊢ (𝜑 → (𝑍 ∈ (𝑋𝐽𝑌) ↔ (𝐹‘𝑍) ∈ ((𝐹‘𝑋)𝐼(𝐹‘𝑌)))) | ||
| Theorem | f1otrg 29335* | A bijection between bases which conserves distances and intervals conserves also geometries. (Contributed by Thierry Arnoux, 23-Mar-2019.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐷 = (dist‘𝐺) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝐵 = (Base‘𝐻) & ⊢ 𝐸 = (dist‘𝐻) & ⊢ 𝐽 = (Itv‘𝐻) & ⊢ (𝜑 → 𝐹:𝐵–1-1-onto→𝑃) & ⊢ ((𝜑 ∧ (𝑒 ∈ 𝐵 ∧ 𝑓 ∈ 𝐵)) → (𝑒𝐸𝑓) = ((𝐹‘𝑒)𝐷(𝐹‘𝑓))) & ⊢ ((𝜑 ∧ (𝑒 ∈ 𝐵 ∧ 𝑓 ∈ 𝐵 ∧ 𝑔 ∈ 𝐵)) → (𝑔 ∈ (𝑒𝐽𝑓) ↔ (𝐹‘𝑔) ∈ ((𝐹‘𝑒)𝐼(𝐹‘𝑓)))) & ⊢ (𝜑 → 𝐻 ∈ 𝑉) & ⊢ (𝜑 → 𝐺 ∈ TarskiG) & ⊢ (𝜑 → (LineG‘𝐻) = (𝑥 ∈ 𝐵, 𝑦 ∈ (𝐵 ∖ {𝑥}) ↦ {𝑧 ∈ 𝐵 ∣ (𝑧 ∈ (𝑥𝐽𝑦) ∨ 𝑥 ∈ (𝑧𝐽𝑦) ∨ 𝑦 ∈ (𝑥𝐽𝑧))})) ⇒ ⊢ (𝜑 → 𝐻 ∈ TarskiG) | ||
| Theorem | f1otrge 29336* | A bijection between bases which conserves distances and intervals conserves also the property of being a Euclidean geometry. (Contributed by Thierry Arnoux, 23-Mar-2019.) |
| ⊢ 𝑃 = (Base‘𝐺) & ⊢ 𝐷 = (dist‘𝐺) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝐵 = (Base‘𝐻) & ⊢ 𝐸 = (dist‘𝐻) & ⊢ 𝐽 = (Itv‘𝐻) & ⊢ (𝜑 → 𝐹:𝐵–1-1-onto→𝑃) & ⊢ ((𝜑 ∧ (𝑒 ∈ 𝐵 ∧ 𝑓 ∈ 𝐵)) → (𝑒𝐸𝑓) = ((𝐹‘𝑒)𝐷(𝐹‘𝑓))) & ⊢ ((𝜑 ∧ (𝑒 ∈ 𝐵 ∧ 𝑓 ∈ 𝐵 ∧ 𝑔 ∈ 𝐵)) → (𝑔 ∈ (𝑒𝐽𝑓) ↔ (𝐹‘𝑔) ∈ ((𝐹‘𝑒)𝐼(𝐹‘𝑓)))) & ⊢ (𝜑 → 𝐻 ∈ 𝑉) & ⊢ (𝜑 → 𝐺 ∈ TarskiGE) ⇒ ⊢ (𝜑 → 𝐻 ∈ TarskiGE) | ||
| Syntax | cttg 29337 | Function to convert an algebraic structure to a Tarski geometry. |
| class toTG | ||
| Definition | df-ttg 29338* | Define a function converting a subcomplex Hilbert space to a Tarski Geometry. It does so by equipping the structure with a betweenness operation. Note that because the scalar product is applied over the interval (0[,]1), only spaces whose scalar field is a superset of that interval can be considered. (Contributed by Thierry Arnoux, 24-Mar-2019.) |
| ⊢ toTG = (𝑤 ∈ V ↦ ⦋(𝑥 ∈ (Base‘𝑤), 𝑦 ∈ (Base‘𝑤) ↦ {𝑧 ∈ (Base‘𝑤) ∣ ∃𝑘 ∈ (0[,]1)(𝑧(-g‘𝑤)𝑥) = (𝑘( ·𝑠 ‘𝑤)(𝑦(-g‘𝑤)𝑥))}) / 𝑖⦌((𝑤 sSet 〈(Itv‘ndx), 𝑖〉) sSet 〈(LineG‘ndx), (𝑥 ∈ (Base‘𝑤), 𝑦 ∈ (Base‘𝑤) ↦ {𝑧 ∈ (Base‘𝑤) ∣ (𝑧 ∈ (𝑥𝑖𝑦) ∨ 𝑥 ∈ (𝑧𝑖𝑦) ∨ 𝑦 ∈ (𝑥𝑖𝑧))})〉)) | ||
| Theorem | ttgval 29339* | Define a function to augment a subcomplex Hilbert space with betweenness and a line definition. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Proof shortened by AV, 9-Nov-2024.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ 𝐵 = (Base‘𝐻) & ⊢ − = (-g‘𝐻) & ⊢ · = ( ·𝑠 ‘𝐻) & ⊢ 𝐼 = (Itv‘𝐺) ⇒ ⊢ (𝐻 ∈ 𝑉 → (𝐺 = ((𝐻 sSet 〈(Itv‘ndx), (𝑥 ∈ 𝐵, 𝑦 ∈ 𝐵 ↦ {𝑧 ∈ 𝐵 ∣ ∃𝑘 ∈ (0[,]1)(𝑧 − 𝑥) = (𝑘 · (𝑦 − 𝑥))})〉) sSet 〈(LineG‘ndx), (𝑥 ∈ 𝐵, 𝑦 ∈ 𝐵 ↦ {𝑧 ∈ 𝐵 ∣ (𝑧 ∈ (𝑥𝐼𝑦) ∨ 𝑥 ∈ (𝑧𝐼𝑦) ∨ 𝑦 ∈ (𝑥𝐼𝑧))})〉) ∧ 𝐼 = (𝑥 ∈ 𝐵, 𝑦 ∈ 𝐵 ↦ {𝑧 ∈ 𝐵 ∣ ∃𝑘 ∈ (0[,]1)(𝑧 − 𝑥) = (𝑘 · (𝑦 − 𝑥))}))) | ||
| Theorem | ttglem 29340 | Lemma for ttgbas 29341, ttgvsca 29344 etc. (Contributed by Thierry Arnoux, 15-Apr-2019.) (Revised by AV, 29-Oct-2024.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ 𝐸 = Slot (𝐸‘ndx) & ⊢ (𝐸‘ndx) ≠ (LineG‘ndx) & ⊢ (𝐸‘ndx) ≠ (Itv‘ndx) ⇒ ⊢ (𝐸‘𝐻) = (𝐸‘𝐺) | ||
| Theorem | ttgbas 29341 | The base set of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Revised by AV, 29-Oct-2024.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ 𝐵 = (Base‘𝐻) ⇒ ⊢ 𝐵 = (Base‘𝐺) | ||
| Theorem | ttgplusg 29342 | The addition operation of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Revised by AV, 29-Oct-2024.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ + = (+g‘𝐻) ⇒ ⊢ + = (+g‘𝐺) | ||
| Theorem | ttgsub 29343 | The subtraction operation of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ − = (-g‘𝐻) ⇒ ⊢ − = (-g‘𝐺) | ||
| Theorem | ttgvsca 29344 | The scalar product of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Revised by AV, 29-Oct-2024.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ · = ( ·𝑠 ‘𝐻) ⇒ ⊢ · = ( ·𝑠 ‘𝐺) | ||
| Theorem | ttgds 29345 | The metric of a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) (Revised by AV, 29-Oct-2024.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ 𝐷 = (dist‘𝐻) ⇒ ⊢ 𝐷 = (dist‘𝐺) | ||
| Theorem | ttgitvval 29346* | Betweenness for a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝑃 = (Base‘𝐻) & ⊢ − = (-g‘𝐻) & ⊢ · = ( ·𝑠 ‘𝐻) ⇒ ⊢ ((𝐻 ∈ 𝑉 ∧ 𝑋 ∈ 𝑃 ∧ 𝑌 ∈ 𝑃) → (𝑋𝐼𝑌) = {𝑧 ∈ 𝑃 ∣ ∃𝑘 ∈ (0[,]1)(𝑧 − 𝑋) = (𝑘 · (𝑌 − 𝑋))}) | ||
| Theorem | ttgelitv 29347* | Betweenness for a subcomplex Hilbert space augmented with betweenness. (Contributed by Thierry Arnoux, 25-Mar-2019.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝑃 = (Base‘𝐻) & ⊢ − = (-g‘𝐻) & ⊢ · = ( ·𝑠 ‘𝐻) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ (𝜑 → 𝐻 ∈ 𝑉) & ⊢ (𝜑 → 𝑍 ∈ 𝑃) ⇒ ⊢ (𝜑 → (𝑍 ∈ (𝑋𝐼𝑌) ↔ ∃𝑘 ∈ (0[,]1)(𝑍 − 𝑋) = (𝑘 · (𝑌 − 𝑋)))) | ||
| Theorem | ttgbtwnid 29348 | Any subcomplex module equipped with the betweenness operation fulfills the identity of betweenness (Axiom A6). (Contributed by Thierry Arnoux, 26-Mar-2019.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝑃 = (Base‘𝐻) & ⊢ − = (-g‘𝐻) & ⊢ · = ( ·𝑠 ‘𝐻) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ 𝑅 = (Base‘(Scalar‘𝐻)) & ⊢ (𝜑 → (0[,]1) ⊆ 𝑅) & ⊢ (𝜑 → 𝐻 ∈ ℂMod) & ⊢ (𝜑 → 𝑌 ∈ (𝑋𝐼𝑋)) ⇒ ⊢ (𝜑 → 𝑋 = 𝑌) | ||
| Theorem | ttgcontlem1 29349 | Lemma for % ttgcont . (Contributed by Thierry Arnoux, 24-May-2019.) |
| ⊢ 𝐺 = (toTG‘𝐻) & ⊢ 𝐼 = (Itv‘𝐺) & ⊢ 𝑃 = (Base‘𝐻) & ⊢ − = (-g‘𝐻) & ⊢ · = ( ·𝑠 ‘𝐻) & ⊢ (𝜑 → 𝑋 ∈ 𝑃) & ⊢ (𝜑 → 𝑌 ∈ 𝑃) & ⊢ 𝑅 = (Base‘(Scalar‘𝐻)) & ⊢ (𝜑 → (0[,]1) ⊆ 𝑅) & ⊢ + = (+g‘𝐻) & ⊢ (𝜑 → 𝐻 ∈ ℂVec) & ⊢ (𝜑 → 𝐴 ∈ 𝑃) & ⊢ (𝜑 → 𝑁 ∈ 𝑃) & ⊢ (𝜑 → 𝑀 ≠ 0) & ⊢ (𝜑 → 𝐾 ≠ 0) & ⊢ (𝜑 → 𝐾 ≠ 1) & ⊢ (𝜑 → 𝐿 ≠ 𝑀) & ⊢ (𝜑 → 𝐿 ≤ (𝑀 / 𝐾)) & ⊢ (𝜑 → 𝐿 ∈ (0[,]1)) & ⊢ (𝜑 → 𝐾 ∈ (0[,]1)) & ⊢ (𝜑 → 𝑀 ∈ (0[,]𝐿)) & ⊢ (𝜑 → (𝑋 − 𝐴) = (𝐾 · (𝑌 − 𝐴))) & ⊢ (𝜑 → (𝑋 − 𝐴) = (𝑀 · (𝑁 − 𝐴))) & ⊢ (𝜑 → 𝐵 = (𝐴 + (𝐿 · (𝑁 − 𝐴)))) ⇒ ⊢ (𝜑 → 𝐵 ∈ (𝑋𝐼𝑌)) | ||
| Theorem | xmstrkgc 29350 | Any metric space fulfills Tarski's geometry axioms of congruence. (Contributed by Thierry Arnoux, 13-Mar-2019.) |
| ⊢ (𝐺 ∈ ∞MetSp → 𝐺 ∈ TarskiGC) | ||
| Theorem | cchhllem 29351* | Lemma for chlbas and chlvsca . (Contributed by Thierry Arnoux, 15-Apr-2019.) (Revised by AV, 29-Oct-2024.) |
| ⊢ 𝐶 = (((subringAlg ‘ℂfld)‘ℝ) sSet 〈(·𝑖‘ndx), (𝑥 ∈ ℂ, 𝑦 ∈ ℂ ↦ (𝑥 · (∗‘𝑦)))〉) & ⊢ 𝐸 = Slot (𝐸‘ndx) & ⊢ (Scalar‘ndx) ≠ (𝐸‘ndx) & ⊢ ( ·𝑠 ‘ndx) ≠ (𝐸‘ndx) & ⊢ (·𝑖‘ndx) ≠ (𝐸‘ndx) ⇒ ⊢ (𝐸‘ℂfld) = (𝐸‘𝐶) | ||
| Syntax | cee 29352 | Declare the syntax for the Euclidean space generator. |
| class 𝔼 | ||
| Syntax | cbtwn 29353 | Declare the syntax for the Euclidean betweenness predicate. |
| class Btwn | ||
| Syntax | ccgr 29354 | Declare the syntax for the Euclidean congruence predicate. |
| class Cgr | ||
| Definition | df-ee 29355 | Define the Euclidean space generator. For details, see elee 29358. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ 𝔼 = (𝑛 ∈ ℕ ↦ (ℝ ↑m (1...𝑛))) | ||
| Definition | df-btwn 29356* | Define the Euclidean betweenness predicate. For details, see brbtwn 29364. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ Btwn = ◡{〈〈𝑥, 𝑧〉, 𝑦〉 ∣ ∃𝑛 ∈ ℕ ((𝑥 ∈ (𝔼‘𝑛) ∧ 𝑧 ∈ (𝔼‘𝑛) ∧ 𝑦 ∈ (𝔼‘𝑛)) ∧ ∃𝑡 ∈ (0[,]1)∀𝑖 ∈ (1...𝑛)(𝑦‘𝑖) = (((1 − 𝑡) · (𝑥‘𝑖)) + (𝑡 · (𝑧‘𝑖))))} | ||
| Definition | df-cgr 29357* | Define the Euclidean congruence predicate. For details, see brcgr 29365. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ Cgr = {〈𝑥, 𝑦〉 ∣ ∃𝑛 ∈ ℕ ((𝑥 ∈ ((𝔼‘𝑛) × (𝔼‘𝑛)) ∧ 𝑦 ∈ ((𝔼‘𝑛) × (𝔼‘𝑛))) ∧ Σ𝑖 ∈ (1...𝑛)((((1st ‘𝑥)‘𝑖) − ((2nd ‘𝑥)‘𝑖))↑2) = Σ𝑖 ∈ (1...𝑛)((((1st ‘𝑦)‘𝑖) − ((2nd ‘𝑦)‘𝑖))↑2))} | ||
| Theorem | elee 29358 | Membership in a Euclidean space. We define Euclidean space here using Cartesian coordinates over 𝑁 space. We later abstract away from this using Tarski's geometry axioms, so this exact definition is unimportant. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ (𝑁 ∈ ℕ → (𝐴 ∈ (𝔼‘𝑁) ↔ 𝐴:(1...𝑁)⟶ℝ)) | ||
| Theorem | mptelee 29359* | A condition for a mapping to be an element of a Euclidean space. (Contributed by Scott Fenton, 7-Jun-2013.) (Proof shortened by SN, 2-Feb-2026.) |
| ⊢ (𝑁 ∈ ℕ → ((𝑘 ∈ (1...𝑁) ↦ (𝐴𝐹𝐵)) ∈ (𝔼‘𝑁) ↔ ∀𝑘 ∈ (1...𝑁)(𝐴𝐹𝐵) ∈ ℝ)) | ||
| Theorem | mpteleeOLD 29360* | Obsolete version of mptelee 29359 as of 2-Feb-2026. (Contributed by Scott Fenton, 7-Jun-2013.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ (𝑁 ∈ ℕ → ((𝑘 ∈ (1...𝑁) ↦ (𝐴𝐹𝐵)) ∈ (𝔼‘𝑁) ↔ ∀𝑘 ∈ (1...𝑁)(𝐴𝐹𝐵) ∈ ℝ)) | ||
| Theorem | eleenn 29361 | If 𝐴 is in (𝔼‘𝑁), then 𝑁 is a natural. (Contributed by Scott Fenton, 1-Jul-2013.) |
| ⊢ (𝐴 ∈ (𝔼‘𝑁) → 𝑁 ∈ ℕ) | ||
| Theorem | eleei 29362 | The forward direction of elee 29358. (Contributed by Scott Fenton, 1-Jul-2013.) |
| ⊢ (𝐴 ∈ (𝔼‘𝑁) → 𝐴:(1...𝑁)⟶ℝ) | ||
| Theorem | eedimeq 29363 | A point belongs to at most one Euclidean space. (Contributed by Scott Fenton, 1-Jul-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐴 ∈ (𝔼‘𝑀)) → 𝑁 = 𝑀) | ||
| Theorem | brbtwn 29364* | The binary relation form of the betweenness predicate. The statement 𝐴 Btwn 〈𝐵, 𝐶〉 should be informally read as "𝐴 lies on a line segment between 𝐵 and 𝐶. This exact definition is abstracted away by Tarski's geometry axioms later on. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → (𝐴 Btwn 〈𝐵, 𝐶〉 ↔ ∃𝑡 ∈ (0[,]1)∀𝑖 ∈ (1...𝑁)(𝐴‘𝑖) = (((1 − 𝑡) · (𝐵‘𝑖)) + (𝑡 · (𝐶‘𝑖))))) | ||
| Theorem | brcgr 29365* | The binary relation form of the congruence predicate. The statement 〈𝐴, 𝐵〉Cgr〈𝐶, 𝐷〉 should be read informally as "the 𝑁 dimensional point 𝐴 is as far from 𝐵 as 𝐶 is from 𝐷, or "the line segment 𝐴𝐵 is congruent to the line segment 𝐶𝐷. This particular definition is encapsulated by Tarski's axioms later on. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → (〈𝐴, 𝐵〉Cgr〈𝐶, 𝐷〉 ↔ Σ𝑖 ∈ (1...𝑁)(((𝐴‘𝑖) − (𝐵‘𝑖))↑2) = Σ𝑖 ∈ (1...𝑁)(((𝐶‘𝑖) − (𝐷‘𝑖))↑2))) | ||
| Theorem | fveere 29366 | The function value of a point is a real. (Contributed by Scott Fenton, 10-Jun-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐼 ∈ (1...𝑁)) → (𝐴‘𝐼) ∈ ℝ) | ||
| Theorem | fveecn 29367 | The function value of a point is a complex. (Contributed by Scott Fenton, 10-Jun-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐼 ∈ (1...𝑁)) → (𝐴‘𝐼) ∈ ℂ) | ||
| Theorem | eqeefv 29368* | Two points are equal iff they agree in all dimensions. (Contributed by Scott Fenton, 10-Jun-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → (𝐴 = 𝐵 ↔ ∀𝑖 ∈ (1...𝑁)(𝐴‘𝑖) = (𝐵‘𝑖))) | ||
| Theorem | eqeelen 29369* | Two points are equal iff the square of the distance between them is zero. (Contributed by Scott Fenton, 10-Jun-2013.) (Revised by Mario Carneiro, 22-May-2014.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → (𝐴 = 𝐵 ↔ Σ𝑖 ∈ (1...𝑁)(((𝐴‘𝑖) − (𝐵‘𝑖))↑2) = 0)) | ||
| Theorem | brbtwn2 29370* | Alternate characterization of betweenness, with no existential quantifiers. (Contributed by Scott Fenton, 24-Jun-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → (𝐴 Btwn 〈𝐵, 𝐶〉 ↔ (∀𝑖 ∈ (1...𝑁)(((𝐵‘𝑖) − (𝐴‘𝑖)) · ((𝐶‘𝑖) − (𝐴‘𝑖))) ≤ 0 ∧ ∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐵‘𝑖) − (𝐴‘𝑖)) · ((𝐶‘𝑗) − (𝐴‘𝑗))) = (((𝐵‘𝑗) − (𝐴‘𝑗)) · ((𝐶‘𝑖) − (𝐴‘𝑖)))))) | ||
| Theorem | colinearalglem1 29371 | Lemma for colinearalg 29375. Expand out a multiplication. (Contributed by Scott Fenton, 24-Jun-2013.) |
| ⊢ (((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ) ∧ (𝐷 ∈ ℂ ∧ 𝐸 ∈ ℂ ∧ 𝐹 ∈ ℂ)) → (((𝐵 − 𝐴) · (𝐹 − 𝐷)) = ((𝐸 − 𝐷) · (𝐶 − 𝐴)) ↔ ((𝐵 · 𝐹) − ((𝐴 · 𝐹) + (𝐵 · 𝐷))) = ((𝐶 · 𝐸) − ((𝐴 · 𝐸) + (𝐶 · 𝐷))))) | ||
| Theorem | colinearalglem2 29372* | Lemma for colinearalg 29375. Translate between two forms of the colinearity condition. (Contributed by Scott Fenton, 24-Jun-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → (∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐵‘𝑖) − (𝐴‘𝑖)) · ((𝐶‘𝑗) − (𝐴‘𝑗))) = (((𝐵‘𝑗) − (𝐴‘𝑗)) · ((𝐶‘𝑖) − (𝐴‘𝑖))) ↔ ∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐶‘𝑖) − (𝐵‘𝑖)) · ((𝐴‘𝑗) − (𝐵‘𝑗))) = (((𝐶‘𝑗) − (𝐵‘𝑗)) · ((𝐴‘𝑖) − (𝐵‘𝑖))))) | ||
| Theorem | colinearalglem3 29373* | Lemma for colinearalg 29375. Translate between two forms of the colinearity condition. (Contributed by Scott Fenton, 24-Jun-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → (∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐵‘𝑖) − (𝐴‘𝑖)) · ((𝐶‘𝑗) − (𝐴‘𝑗))) = (((𝐵‘𝑗) − (𝐴‘𝑗)) · ((𝐶‘𝑖) − (𝐴‘𝑖))) ↔ ∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐴‘𝑖) − (𝐶‘𝑖)) · ((𝐵‘𝑗) − (𝐶‘𝑗))) = (((𝐴‘𝑗) − (𝐶‘𝑗)) · ((𝐵‘𝑖) − (𝐶‘𝑖))))) | ||
| Theorem | colinearalglem4 29374* | Lemma for colinearalg 29375. Prove a disjunction that will be needed in the final proof. (Contributed by Scott Fenton, 27-Jun-2013.) |
| ⊢ (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ 𝐾 ∈ ℝ) → (∀𝑖 ∈ (1...𝑁)((((𝐾 · ((𝐶‘𝑖) − (𝐴‘𝑖))) + (𝐴‘𝑖)) − (𝐴‘𝑖)) · ((𝐶‘𝑖) − (𝐴‘𝑖))) ≤ 0 ∨ ∀𝑖 ∈ (1...𝑁)(((𝐶‘𝑖) − ((𝐾 · ((𝐶‘𝑖) − (𝐴‘𝑖))) + (𝐴‘𝑖))) · ((𝐴‘𝑖) − ((𝐾 · ((𝐶‘𝑖) − (𝐴‘𝑖))) + (𝐴‘𝑖)))) ≤ 0 ∨ ∀𝑖 ∈ (1...𝑁)(((𝐴‘𝑖) − (𝐶‘𝑖)) · (((𝐾 · ((𝐶‘𝑖) − (𝐴‘𝑖))) + (𝐴‘𝑖)) − (𝐶‘𝑖))) ≤ 0)) | ||
| Theorem | colinearalg 29375* | An algebraic characterization of colinearity. Note the similarity to brbtwn2 29370. (Contributed by Scott Fenton, 24-Jun-2013.) |
| ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) → ((𝐴 Btwn 〈𝐵, 𝐶〉 ∨ 𝐵 Btwn 〈𝐶, 𝐴〉 ∨ 𝐶 Btwn 〈𝐴, 𝐵〉) ↔ ∀𝑖 ∈ (1...𝑁)∀𝑗 ∈ (1...𝑁)(((𝐵‘𝑖) − (𝐴‘𝑖)) · ((𝐶‘𝑗) − (𝐴‘𝑗))) = (((𝐵‘𝑗) − (𝐴‘𝑗)) · ((𝐶‘𝑖) − (𝐴‘𝑖))))) | ||
| Theorem | eleesub 29376* | Membership of a subtraction mapping in a Euclidean space. (Contributed by Scott Fenton, 17-Jul-2013.) |
| ⊢ 𝐶 = (𝑖 ∈ (1...𝑁) ↦ ((𝐴‘𝑖) − (𝐵‘𝑖))) ⇒ ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 𝐶 ∈ (𝔼‘𝑁)) | ||
| Theorem | eleesubd 29377* | Membership of a subtraction mapping in a Euclidean space. Deduction form of eleesub 29376. (Contributed by Scott Fenton, 17-Jul-2013.) |
| ⊢ (𝜑 → 𝐶 = (𝑖 ∈ (1...𝑁) ↦ ((𝐴‘𝑖) − (𝐵‘𝑖)))) ⇒ ⊢ ((𝜑 ∧ 𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 𝐶 ∈ (𝔼‘𝑁)) | ||
| Theorem | axdimuniq 29378 | The unique dimension axiom. If a point is in 𝑁 dimensional space and in 𝑀 dimensional space, then 𝑁 = 𝑀. This axiom is not traditionally presented with Tarski's axioms, but we require it here as we are considering spaces in arbitrary dimensions. (Contributed by Scott Fenton, 24-Sep-2013.) |
| ⊢ (((𝑁 ∈ ℕ ∧ 𝐴 ∈ (𝔼‘𝑁)) ∧ (𝑀 ∈ ℕ ∧ 𝐴 ∈ (𝔼‘𝑀))) → 𝑁 = 𝑀) | ||
| Theorem | axcgrrflx 29379 | 𝐴 is as far from 𝐵 as 𝐵 is from 𝐴. Axiom A1 of [Schwabhauser] p. 10. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ ((𝑁 ∈ ℕ ∧ 𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 〈𝐴, 𝐵〉Cgr〈𝐵, 𝐴〉) | ||
| Theorem | axcgrtr 29380 | Congruence is transitive. Axiom A2 of [Schwabhauser] p. 10. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ ((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝐷 ∈ (𝔼‘𝑁) ∧ 𝐸 ∈ (𝔼‘𝑁) ∧ 𝐹 ∈ (𝔼‘𝑁))) → ((〈𝐴, 𝐵〉Cgr〈𝐶, 𝐷〉 ∧ 〈𝐴, 𝐵〉Cgr〈𝐸, 𝐹〉) → 〈𝐶, 𝐷〉Cgr〈𝐸, 𝐹〉)) | ||
| Theorem | axcgrid 29381 | If there is no distance between 𝐴 and 𝐵, then 𝐴 = 𝐵. Axiom A3 of [Schwabhauser] p. 10. (Contributed by Scott Fenton, 3-Jun-2013.) |
| ⊢ ((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁))) → (〈𝐴, 𝐵〉Cgr〈𝐶, 𝐶〉 → 𝐴 = 𝐵)) | ||
| Theorem | axsegconlem1 29382* | Lemma for axsegcon 29392. Handle the degenerate case. (Contributed by Scott Fenton, 7-Jun-2013.) |
| ⊢ ((𝐴 = 𝐵 ∧ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁)))) → ∃𝑥 ∈ (𝔼‘𝑁)∃𝑡 ∈ (0[,]1)(∀𝑖 ∈ (1...𝑁)(𝐵‘𝑖) = (((1 − 𝑡) · (𝐴‘𝑖)) + (𝑡 · (𝑥‘𝑖))) ∧ Σ𝑖 ∈ (1...𝑁)(((𝐵‘𝑖) − (𝑥‘𝑖))↑2) = Σ𝑖 ∈ (1...𝑁)(((𝐶‘𝑖) − (𝐷‘𝑖))↑2))) | ||
| Theorem | axsegconlem2 29383* | Lemma for axsegcon 29392. Show that the square of the distance between two points is a real number. (Contributed by Scott Fenton, 17-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) ⇒ ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 𝑆 ∈ ℝ) | ||
| Theorem | axsegconlem3 29384* | Lemma for axsegcon 29392. Show that the square of the distance between two points is nonnegative. (Contributed by Scott Fenton, 17-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) ⇒ ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 0 ≤ 𝑆) | ||
| Theorem | axsegconlem4 29385* | Lemma for axsegcon 29392. Show that the distance between two points is a real number. (Contributed by Scott Fenton, 17-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) ⇒ ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → (√‘𝑆) ∈ ℝ) | ||
| Theorem | axsegconlem5 29386* | Lemma for axsegcon 29392. Show that the distance between two points is nonnegative. (Contributed by Scott Fenton, 17-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) ⇒ ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) → 0 ≤ (√‘𝑆)) | ||
| Theorem | axsegconlem6 29387* | Lemma for axsegcon 29392. Show that the distance between two distinct points is positive. (Contributed by Scott Fenton, 17-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) ⇒ ⊢ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴 ≠ 𝐵) → 0 < (√‘𝑆)) | ||
| Theorem | axsegconlem7 29388* | Lemma for axsegcon 29392. Show that a particular ratio of distances is in the closed unit interval. (Contributed by Scott Fenton, 18-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) & ⊢ 𝑇 = Σ𝑝 ∈ (1...𝑁)(((𝐶‘𝑝) − (𝐷‘𝑝))↑2) ⇒ ⊢ (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴 ≠ 𝐵) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → ((√‘𝑆) / ((√‘𝑆) + (√‘𝑇))) ∈ (0[,]1)) | ||
| Theorem | axsegconlem8 29389* | Lemma for axsegcon 29392. Show that a particular mapping generates a point. (Contributed by Scott Fenton, 18-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) & ⊢ 𝑇 = Σ𝑝 ∈ (1...𝑁)(((𝐶‘𝑝) − (𝐷‘𝑝))↑2) & ⊢ 𝐹 = (𝑘 ∈ (1...𝑁) ↦ (((((√‘𝑆) + (√‘𝑇)) · (𝐵‘𝑘)) − ((√‘𝑇) · (𝐴‘𝑘))) / (√‘𝑆))) ⇒ ⊢ (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴 ≠ 𝐵) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → 𝐹 ∈ (𝔼‘𝑁)) | ||
| Theorem | axsegconlem9 29390* | Lemma for axsegcon 29392. Show that 𝐵𝐹 is congruent to 𝐶𝐷. (Contributed by Scott Fenton, 19-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) & ⊢ 𝑇 = Σ𝑝 ∈ (1...𝑁)(((𝐶‘𝑝) − (𝐷‘𝑝))↑2) & ⊢ 𝐹 = (𝑘 ∈ (1...𝑁) ↦ (((((√‘𝑆) + (√‘𝑇)) · (𝐵‘𝑘)) − ((√‘𝑇) · (𝐴‘𝑘))) / (√‘𝑆))) ⇒ ⊢ (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴 ≠ 𝐵) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → Σ𝑖 ∈ (1...𝑁)(((𝐵‘𝑖) − (𝐹‘𝑖))↑2) = Σ𝑖 ∈ (1...𝑁)(((𝐶‘𝑖) − (𝐷‘𝑖))↑2)) | ||
| Theorem | axsegconlem10 29391* | Lemma for axsegcon 29392. Show that the scaling constant from axsegconlem7 29388 produces the betweenness condition for 𝐴, 𝐵 and 𝐹. (Contributed by Scott Fenton, 21-Sep-2013.) |
| ⊢ 𝑆 = Σ𝑝 ∈ (1...𝑁)(((𝐴‘𝑝) − (𝐵‘𝑝))↑2) & ⊢ 𝑇 = Σ𝑝 ∈ (1...𝑁)(((𝐶‘𝑝) − (𝐷‘𝑝))↑2) & ⊢ 𝐹 = (𝑘 ∈ (1...𝑁) ↦ (((((√‘𝑆) + (√‘𝑇)) · (𝐵‘𝑘)) − ((√‘𝑇) · (𝐴‘𝑘))) / (√‘𝑆))) ⇒ ⊢ (((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐴 ≠ 𝐵) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → ∀𝑖 ∈ (1...𝑁)(𝐵‘𝑖) = (((1 − ((√‘𝑆) / ((√‘𝑆) + (√‘𝑇)))) · (𝐴‘𝑖)) + (((√‘𝑆) / ((√‘𝑆) + (√‘𝑇))) · (𝐹‘𝑖)))) | ||
| Theorem | axsegcon 29392* | Any segment 𝐴𝐵 can be extended to a point 𝑥 such that 𝐵𝑥 is congruent to 𝐶𝐷. Axiom A4 of [Schwabhauser] p. 11. (Contributed by Scott Fenton, 4-Jun-2013.) |
| ⊢ ((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁)) ∧ (𝐶 ∈ (𝔼‘𝑁) ∧ 𝐷 ∈ (𝔼‘𝑁))) → ∃𝑥 ∈ (𝔼‘𝑁)(𝐵 Btwn 〈𝐴, 𝑥〉 ∧ 〈𝐵, 𝑥〉Cgr〈𝐶, 𝐷〉)) | ||
| Theorem | ax5seglem1 29393* | Lemma for ax5seg 29403. Rexpress a one congruence sum given betweenness. (Contributed by Scott Fenton, 11-Jun-2013.) |
| ⊢ ((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝑇 ∈ (0[,]1) ∧ ∀𝑖 ∈ (1...𝑁)(𝐵‘𝑖) = (((1 − 𝑇) · (𝐴‘𝑖)) + (𝑇 · (𝐶‘𝑖))))) → Σ𝑗 ∈ (1...𝑁)(((𝐴‘𝑗) − (𝐵‘𝑗))↑2) = ((𝑇↑2) · Σ𝑗 ∈ (1...𝑁)(((𝐴‘𝑗) − (𝐶‘𝑗))↑2))) | ||
| Theorem | ax5seglem2 29394* | Lemma for ax5seg 29403. Rexpress another congruence sum given betweenness. (Contributed by Scott Fenton, 11-Jun-2013.) |
| ⊢ ((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝑇 ∈ (0[,]1) ∧ ∀𝑖 ∈ (1...𝑁)(𝐵‘𝑖) = (((1 − 𝑇) · (𝐴‘𝑖)) + (𝑇 · (𝐶‘𝑖))))) → Σ𝑗 ∈ (1...𝑁)(((𝐵‘𝑗) − (𝐶‘𝑗))↑2) = (((1 − 𝑇)↑2) · Σ𝑗 ∈ (1...𝑁)(((𝐴‘𝑗) − (𝐶‘𝑗))↑2))) | ||
| Theorem | ax5seglem3a 29395 | Lemma for ax5seg 29403. (Contributed by Scott Fenton, 7-May-2015.) |
| ⊢ (((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝐷 ∈ (𝔼‘𝑁) ∧ 𝐸 ∈ (𝔼‘𝑁) ∧ 𝐹 ∈ (𝔼‘𝑁))) ∧ 𝑗 ∈ (1...𝑁)) → (((𝐴‘𝑗) − (𝐶‘𝑗)) ∈ ℝ ∧ ((𝐷‘𝑗) − (𝐹‘𝑗)) ∈ ℝ)) | ||
| Theorem | ax5seglem3 29396* | Lemma for ax5seg 29403. Combine congruences for points on a line. (Contributed by Scott Fenton, 11-Jun-2013.) |
| ⊢ (((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝐷 ∈ (𝔼‘𝑁) ∧ 𝐸 ∈ (𝔼‘𝑁) ∧ 𝐹 ∈ (𝔼‘𝑁))) ∧ ((𝑇 ∈ (0[,]1) ∧ 𝑆 ∈ (0[,]1)) ∧ (∀𝑖 ∈ (1...𝑁)(𝐵‘𝑖) = (((1 − 𝑇) · (𝐴‘𝑖)) + (𝑇 · (𝐶‘𝑖))) ∧ ∀𝑖 ∈ (1...𝑁)(𝐸‘𝑖) = (((1 − 𝑆) · (𝐷‘𝑖)) + (𝑆 · (𝐹‘𝑖))))) ∧ (〈𝐴, 𝐵〉Cgr〈𝐷, 𝐸〉 ∧ 〈𝐵, 𝐶〉Cgr〈𝐸, 𝐹〉)) → Σ𝑗 ∈ (1...𝑁)(((𝐴‘𝑗) − (𝐶‘𝑗))↑2) = Σ𝑗 ∈ (1...𝑁)(((𝐷‘𝑗) − (𝐹‘𝑗))↑2)) | ||
| Theorem | ax5seglem4 29397* | Lemma for ax5seg 29403. Given two distinct points, the scaling constant in a betweenness statement is nonzero. (Contributed by Scott Fenton, 11-Jun-2013.) |
| ⊢ (((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁))) ∧ ∀𝑖 ∈ (1...𝑁)(𝐵‘𝑖) = (((1 − 𝑇) · (𝐴‘𝑖)) + (𝑇 · (𝐶‘𝑖))) ∧ 𝐴 ≠ 𝐵) → 𝑇 ≠ 0) | ||
| Theorem | ax5seglem5 29398* | Lemma for ax5seg 29403. If 𝐵 is between 𝐴 and 𝐶, and 𝐴 is distinct from 𝐵, then 𝐴 is distinct from 𝐶. (Contributed by Scott Fenton, 11-Jun-2013.) |
| ⊢ (((𝑁 ∈ ℕ ∧ (𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁))) ∧ (𝐴 ≠ 𝐵 ∧ 𝑇 ∈ (0[,]1) ∧ ∀𝑖 ∈ (1...𝑁)(𝐵‘𝑖) = (((1 − 𝑇) · (𝐴‘𝑖)) + (𝑇 · (𝐶‘𝑖))))) → Σ𝑗 ∈ (1...𝑁)(((𝐴‘𝑗) − (𝐶‘𝑗))↑2) ≠ 0) | ||
| Theorem | ax5seglem6 29399* | Lemma for ax5seg 29403. Given two line segments that are divided into pieces, if the pieces are congruent, then the scaling constant is the same. (Contributed by Scott Fenton, 12-Jun-2013.) |
| ⊢ (((𝑁 ∈ ℕ ∧ ((𝐴 ∈ (𝔼‘𝑁) ∧ 𝐵 ∈ (𝔼‘𝑁) ∧ 𝐶 ∈ (𝔼‘𝑁)) ∧ (𝐷 ∈ (𝔼‘𝑁) ∧ 𝐸 ∈ (𝔼‘𝑁) ∧ 𝐹 ∈ (𝔼‘𝑁)))) ∧ (𝐴 ≠ 𝐵 ∧ (𝑇 ∈ (0[,]1) ∧ 𝑆 ∈ (0[,]1)) ∧ (∀𝑖 ∈ (1...𝑁)(𝐵‘𝑖) = (((1 − 𝑇) · (𝐴‘𝑖)) + (𝑇 · (𝐶‘𝑖))) ∧ ∀𝑖 ∈ (1...𝑁)(𝐸‘𝑖) = (((1 − 𝑆) · (𝐷‘𝑖)) + (𝑆 · (𝐹‘𝑖))))) ∧ (〈𝐴, 𝐵〉Cgr〈𝐷, 𝐸〉 ∧ 〈𝐵, 𝐶〉Cgr〈𝐸, 𝐹〉)) → 𝑇 = 𝑆) | ||
| Theorem | ax5seglem7 29400 | Lemma for ax5seg 29403. An algebraic calculation needed further down the line. (Contributed by Scott Fenton, 12-Jun-2013.) |
| ⊢ 𝐴 ∈ ℂ & ⊢ 𝑇 ∈ ℂ & ⊢ 𝐶 ∈ ℂ & ⊢ 𝐷 ∈ ℂ ⇒ ⊢ (𝑇 · ((𝐶 − 𝐷)↑2)) = ((((((1 − 𝑇) · 𝐴) + (𝑇 · 𝐶)) − 𝐷)↑2) + ((1 − 𝑇) · ((𝑇 · ((𝐴 − 𝐶)↑2)) − ((𝐴 − 𝐷)↑2)))) | ||
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